An insulated lunch bag keeps food warm by

Answers

Answer 1
trapping warm air in and keeping cold air out
Answer 2

An insulated lunch bag uses materials that slow down heat transfer.

Importance of Features in Insulated Containers

An insulated lunch bag keeps food warm by utilizing materials that slow down heat transfer, complying with the principles of thermodynamics. To understand which features are most important in minimizing the rate of a hot beverage cooling, we need to consider the mechanisms of heat transfer: conduction, convection, and radiation. A metal lining might conduct heat, leading to quicker heat loss, unless it's part of a vacuum layer such as in a thermos. Insulating cup material, on the other hand, is crucial as materials like polystyrene or foam are poor conductors of heat and therefore reduce heat loss through conduction. The importance of a lid can't be overstated because it traps hot air and reduces heat loss through convection.


Related Questions

How do mass and speed affect kinetic energy?

Answers

The mass affects the kinetic energy because the more the mass the more energy is given to the object and the speed affects by making it go faster and longer, so whenever speed goes up so does energy.
Here is your answer:

Kinetic energy is when an object or person is moving.

Ex: A car going down the street.

Mass effects kinetic energy because mass is weight and weight will make an object go slower which lowers the kinetic energy and rises the potential energy (that's when a object is at rest or not moving)

How has access to the source code of proprietary software?

Answers

Proprietary software is the software that is owned by an individual or the company that developed it.
Source code is the basic component of a computer program and it is the only component where a programmer can read and modify a computer program.
The source code for proprietary software is closed. Only the programmers who have made the software have access to the source code.

Answer:

Explanation:

It's a software publisher

A net force f is required to give an object with mass m an acceleration
a. if a net force 6f is applied to an object with mass 2m. what is the acceleration in this object

Answers

net force = mass × acceleration
F= ma
a = F/M
a = 6f/2m
a= {3f/m} ms-²

Answer:

net force = mass × acceleration

F= ma

a = F/M

a = 6f/2m

a= {3f/m} ms-²

Explanation:

A motorist drives 200 km from one city to another in 2.50 h but makes the return trip in only 1.60 h. what is the average speed for the total trip?

Answers

Average speed = (total distance) divided by (total time).

Total distance = 400 km
Total time = (2.5 + 1.6) = 4.1 hr

Average speed = 400/4.1 = 97.56 km/hr

Which of the following is the best definition of energy?

A) The ability to produce fusion.

B) the ability to do work

C) the ability to generate heat

D) the ability to generate electricity


Is it B?

Answers

Yeah I would think B) is the best answer

What makes the north star, polaris, special?

Answers

It's the only star in the sky (visible from the northern hemisphere) that never seems to move. It stays at almost exactly the same point in the sky, while the other stars all circle around it once a day.

A physician has a patient that he believes has had foul play. What type of autopsy would the physician request?

Question 15 options:

Medical- legal autopsy


Investigation Autopsy


Medical Autopsy


Evidence Autopsy

Answers

Medical- legal autopsy would help determine the cause of death and confirm or reject the doctors suspicions. This is also more broadly defined as a forensic autopsy as well. This type covers death by suspicion, death without a doctor present, and also death while in surgery.
Final answer:

If a physician believes that foul play may have been involved in a patient's death, they would typically request a medical-legal autopsy.

Explanation:

If a physician believes that foul play may have been involved in a patient's death, they would typically request a medical-legal autopsy. This type of autopsy is performed to investigate the cause and manner of death, with a focus on documenting any forensic evidence that could be relevant to a legal investigation. Medical-legal autopsies differ from regular medical autopsies because they involve more detailed examination and documentation to determine if any crimes were committed.

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What are the activities involved in scientific method?

Answers

 Ask a Question Do Background Research Construct a Hypothesis Test Your Hypothesis by Doing an Experiment Analyze Your Dat…a and Draw a Conclusion Communicate Your Results
.
Final answer:

The scientific method is a structured approach that scientists use to answer questions and solve problems, involving steps such as making observations, asking questions, researching, formulating hypotheses, and conducting experiments.

Explanation:

In the pursuit of understanding the natural world, scientists engage in a sequence of activities known as the scientific method. This method is foundational to experimenting, observing, and learning in science. The scientific method often includes the following steps:

Making initial observations to identify a phenomenon of interest.Asking a question that seeks to explain the observation.Conducting research to gather existing knowledge on the topic.Formulating a testable hypothesis as a potential answer.Executing experiments to test the validity of the hypothesis.

These steps enable a structured approach to inquiry, ensuring that conclusions are well-supported by empirical evidence. Notably, the scientific method is flexible and can vary to accommodate different scientific disciplines and types of inquiries.

The National Ambient Air Quality Standards (NAAQS) are maximum allowable levels for _____ harmful pollutants. sixteen six sixty ten

Answers

6

I hope this helps (:

Answer;

-Six

The National Ambient Air Quality Standards (NAAQS) are maximum allowable levels for six harmful pollutants. sixteen six sixty ten.

Explanation;

-The Clean Air Act requires EPA to set National Ambient Air Quality Standards (NAAQS)  for six common air pollutants (also known as "criteria air pollutants.  These pollutants are found all over the U.S. They can harm your health and the environment, and cause property damage.

-These pollutants are particulate matter, photochemical oxidants, carbon monoxide, sulfur oxides, nitrogen oxides and lead. They are called criteria air pollutants because its sets NAAQS for them based on the criteria, which are characterizations of the latest scientific information regarding their effects on health or welfare.

An old truck compresses a spring scale at the junkyard by 25 cm. The spring constant for the industrial scale at the junkyard is 39,200 N/m.
N=?

Answers

F = Ke
F = 39200×(25÷100)
F= 9800 N

Answer : F = 9800 N

Explanation :

It is given that,

The spring constant  for the industrial scale at the junkyard, k = 39,200 N/m

Displacement of spring, x = 25 cm = 0.25 m

According to Hooke's law, the force applied on spring is given by the following relation :

F = -k x

Negative sign shows the force is applied in opposite direction.

[tex]F = -39,200\ N/m\times 0.25\ m[/tex]

So, [tex]F=-9800\ N[/tex]

[tex]|F|=9800\ N[/tex]

Hence, this is the required solution.

"find the ratio of the gravitational force between two planets if the masses of both planets are tripled but the distance between them stays the same."

Answers

The gravitational force between two planets would increase by a factor of nine if the masses of both planets are tripled, while the distance between them stays the same.

The student is asking about the effect on gravitational force when the masses of two planets are tripled but the distance between them remains constant. According to Newton's law of gravity, the gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

If both masses are tripled, the gravitational force becomes 3  imes 3 times larger because the force depends on the product of the two masses. Since the distance does not change, the ratio of the gravitational force after tripling the masses would be 9:1 when compared to the initial force (3 imes 3 = 9). Therefore, the gravitational force increases by a factor of nine

Randy observed that cooked onions in his food taste very differently from the raw onions that he had on his salad. He wondered why that was so. He thinks that he has an idea, but he is not sure.

What has he developed in his mind?

Answers

It's called a hypothesis :D

Answer:

Hypothesis.

Explanation:

Hypothesis is defined as the assumption or can be say that an idea that is proposed for the sake of an argument so that it can be tested or might be occur in future.

A hypothesis is basically tentative. It is usually made an assumption for the experiment to be tested.

Basically Randy made a hypothesis by which he thinks that he has an idea but he is not sure about that.

How are the frequency and wavelength of light related?

Answers

The relationship between frequency and wavelength of light is given by:

[tex]f=\frac{c}{\lambda}[/tex]

where

f is the frequency

c is the speed of the light

[tex]\lambda[/tex] is the wavelength

Therefore, from this equation we see that frequency is inversely proportional to wavelength: the longer the wavelength, the smaller the frequency, and the shorter the wavelength, the higher the frequency.

Final answer:

The wavelength and frequency of light are inversely proportional to each other. The higher the frequency of light, the shorter its wavelength. Also, high-frequency waves carry more energy than lower-frequency waves.

Explanation:

The wavelength and frequency of light are inversely proportional to each other. This means if the wavelength of light increases, its frequency decreases, and vice versa. This relationship can be expressed as λf = c, where λ represents wavelength, f represents frequency, and c is the speed of light. For instance, the different colors of visible light have specific frequencies and wavelengths associated with them. Radio waves, which have longer wavelengths, have lower frequencies, while visible light with shorter wavelengths have higher frequencies. This relationship remains constant irrespective of the moving source or observer.

In a given medium under fixed conditions, the higher the frequency, the smaller the wavelength. Also, waves with higher frequencies carry more energy than lower-frequency waves. This energy is delivered as elementary particles called photons. Therefore, higher-frequency waves deliver more energetic photons compared to lower-frequency waves.

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Filling in the blanks
A) moments are measured of the --------- effect of a force.
B) the moment is increased if the size of the force -----------
C) the moment is also increased if the force acts at a ----------- distance
D) moments are calculated using:
Moment= ------------- multiplied by -----------
E) moments are measured in -------------

Answers

a) turning
b)greater 
c) greater
d) force*distance
e)Nm

When an electron falls from a higher energy level to a lower energy level how is the energy released?

Answers

When a valence electron absorbs energy in the form of heat or light it uses that energy to jump to an excited state (outer level)

A projectile is launched horizontally from a height of 8.0 m. The projectile travels 6.5 m before hitting the ground.

Answers

You can find

1) time to hit the ground
2) initial velocity
3) speed when it hits the ground

Equations

Vx = Vxo

x = Vx * t

Vy = Vyo + gt

Vyo = 0

Vy = gt

y = yo - Vyo - gt^2 / 2

=> yo - y = gt^2 / 2

1) time to hit the ground

=> 8.0 = g t^2 / 2 => t^2 = 8.0m * 2 / 9.81 m/s^2 = 1.631 s^2

=> t = √1.631 s^2 = 1.28 s

2) initial velocity

Vxo = x / t = 6.5m / 1.28s = 5.08 m/s

3) speed when it  hits the ground

Vy = g*t = 9.81 m/s * 1.28s = 12.56 m/s

V^2 = Vy^2 + Vx^2 = (12.56 m/s)^2 + (5.08 m/s)^2 = 183.56 m^2 / s^2

=> V = √ (183.56 m^2 / s^2) = 13.55 m/s

Answer:

5.09 m/s

Explanation:

The velocity of the projectile the moment it was launched, rounded to the nearest hundredth, is

5.09 m/s.

Correct On EDG

If the rock has a mass of 1 kg which is the speed of the rock after it has fallen for two seconds

Answers

If the rock has a mass of 1 kg then the speed of the rock would have been 19.6 m / s after it has fallen for two seconds.

What are the three equations of motion?

There are three equations of motion given by  Newton ,

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

As given in the problem If the rock has a mass of 1 kg , we have to find out  which is the speed of the rock after it has fallen for two seconds

By using the second equation of the motion for the vertical direction,

v = u + gt

v = 0 + 9.8 × 2

v = 19.6 m / s

Thus , If the rock has a mass of 1 kg then the speed of the rock would have been 19.6 m / s after it has fallen for two seconds.

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What would be a good reason to increase friction between surfaces?

Answers

A good reason would be to keep something stationary and from sliding.

Answer:

Explanation: Increasing friction between surface have so many good reasons such as - generating more heat between surfaces, avoiding slippage from smooth surfaces, reducing speed of vehicles. Friction force is the force automatically acting in opposite direction of motion. Friction can be dry friction force and fluid friction force depending upon the medium of motion of object.

A block of metal has a width of 3.2 cm, a length of 17.1 cm, and height of 3.8 cm . its mass is 1.3 kg . calculate the density of the metal.express your answer to two significant figures and include the appropriate units.

Answers

density(rho) = m/v
(1.3)/((3.2)(17.1)(3.8))
since density is given in kg/m^3 you should convert the blocks dimensions to meters

1.3/(0.032*0.038*0.171)

plugging in these numbers would give you the density

1.3/0.000208
6250
with sigfigs= 6300kg/m^3

Adam EvilKeynevil is a daredevil. As part of his act, Adam gets into his cannon and shoots himself at a 25.0 degrees angle at an initial velocity of 30.0 m/s. How far away from his initial position does he land?

Answers

The delta “x” is 29.8 meters.
Final answer:

Using the principles of projectile motion, we calculate the horizontal distance travelled by Adam using his initial velocity, launch angle, and the constant for gravitational acceleration.

Explanation:

To calculate the distance Adam lands from his initial position, we need to use the principles of physics, specifically those of projectile motion. The horizontal distance (range) in a projectile motion can be calculated using the formula R = (v²sin(2θ))/g, where v is the initial velocity, θ is the launch angle, and g is the gravitational acceleration (9.8 m/s²).

Substituting the given values, we get R = ((30 m/sec)²sin(2*25))/9.8 m/s². This should give you the horizontal distance Adam travels in meters.

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a gas exerts less pressure when it has a a. smaller volume b. lower temperature c. higher temperature d. two of the above

Answers

The combined gas law is 
[tex] \frac{Pressure_{1} *Volume_{1}}{Temperature_{1}} = \frac{Pressure_{2} *Volume_{2}}{Temperature_{2}} [/tex] with 1 and 2 both being anything with pressure, volume, and temperature. Since pressure is on the top and temperature is on the bottom, they are inversely related, meaning that when the temperature gets high the pressure goes low. In addition, since pressure and volume are both on the top, when volume goes down pressure goes down too. Therefore, since A and C are right, D is the correct answer

A plane is flying east at 135 m/s. The wind accelerates it at 2.18 m/s squared directly north east. After 18.0s, what is the displacement (magnitude and direction) of the plane?

Answers

2.18/18.0 should be your answer

Approximately 4271.9 m is the magnitude of the displacement, and its direction is approximately [tex]\( 56.14^\circ \)[/tex] north of east.

To find the displacement of the plane, we need to consider both the initial velocity of the plane and the acceleration due to the wind. Let's break down the problem into horizontal (east) and vertical (north) components:

1. Horizontal Motion (East):

  - Initial velocity [tex](\(v_{\text{initial}}\))[/tex] = 135 m/s (east)

  - Time (t) = 18.0 s

  - There is no acceleration in the east direction.

2. Vertical Motion (North):

  - Initial velocity [tex](\(v_{\text{initial}}\))[/tex] = 0 m/s (since the wind accelerates the plane only horizontally)

  - Acceleration (a) = 2.18 m/s² (north)

  - Time (t) = 18.0 s

Horizontal Motion (East):

For the horizontal motion, since there is no acceleration, the displacement [tex](\(d_{\text{east}}\))[/tex] is simply:

[tex]\[ d_{\text{east}} = v_{\text{initial}} \times t \][/tex]

[tex]\[ d_{\text{east}} = 135 \, \text{m/s} \times 18.0 \, \text{s} \][/tex]

[tex]\[ d_{\text{east}} = 2430 \, \text{m} \][/tex]

Vertical Motion (North):

For the vertical motion, we can use the equation of motion:

[tex]\[ d_{\text{north}} = v_{\text{initial}} \times t + \frac{1}{2} a t^2 \][/tex]

[tex]\[ d_{\text{north}} = 0 \times 18.0 \, \text{s} + \frac{1}{2} (2.18 \, \text{m/s}^2) \times (18.0 \, \text{s})^2 \][/tex]

[tex]\[ d_{\text{north}} = 0 + \frac{1}{2} \times 2.18 \times 18^2 \][/tex]

[tex]\[ d_{\text{north}} = \frac{1}{2} \times 2.18 \times 324 \][/tex]

[tex]\[ d_{\text{north}} = 3513.6 \, \text{m} \][/tex]

Resultant Displacement:

To find the resultant displacement, we'll use the Pythagorean theorem since the displacement vectors form a right triangle:

[tex]\[ \text{Resultant Displacement} = \sqrt{(d_{\text{east}})^2 + (d_{\text{north}})^2} \][/tex]

[tex]\[ \text{Resultant Displacement} = \sqrt{(2430 \, \text{m})^2 + (3513.6 \, \text{m})^2} \][/tex]

[tex]\[ \text{Resultant Displacement} \approx \sqrt{5904900 \, \text{m}^2 + 12346627.36 \, \text{m}^2} \][/tex]

[tex]\[ \text{Resultant Displacement} \approx \sqrt{18251527.36 \, \text{m}^2} \][/tex]

[tex]\[ \text{Resultant Displacement} \approx 4271.9 \, \text{m} \][/tex]

Direction:

To find the direction, we'll use trigonometry:

[tex]\[ \text{Direction} = \arctan \left( \frac{d_{\text{north}}}{d_{\text{east}}} \right) \][/tex]

[tex]\[ \text{Direction} = \arctan \left( \frac{3513.6 \, \text{m}}{2430 \, \text{m}} \right) \][/tex]

[tex]\[ \text{Direction} = \arctan \left( 1.445 \right) \][/tex]

[tex]\[ \text{Direction} \approx 56.14^\circ \][/tex]

The magnitude of the displacement of the plane is approximately 4271.9 m, and its direction is approximately [tex]\( 56.14^\circ \)[/tex] north of east.

A conversion factor is a ratio with a value of

A: one

B: two

C: five

D: ten

Answers

The answer would be
B

Answer:

A) one

Explanation:

for anyone else who looks for this question, the answer is one. stated in the book itself, "a conversion factor is a ratio that has a value of one."

An 18.0 kg box is released on a 34.0° incline and accelerates down the incline at 0.270 m/s2. find the friction force impeding its motion. how large is the coefficient of friction?

Answers

Final answer:

The friction force impeding the box's motion is 4.24 N. The coefficient of friction is 0.106.

Explanation:

To find the friction force impeding the motion of the box, we need to use the equation:

Ffriction = μmgcosθ

Where Ffriction is the friction force, μ is the coefficient of friction, m is the mass of the box, g is the acceleration due to gravity, and θ is the angle of the incline.

Using the given values, we can substitute them into the equation:

Ffriction = (0.0300)(18.0 kg)(9.8 m/s²)cos(34.0°) = 4.24 N

So, the friction force impeding the motion of the box is 4.24 N. To find the coefficient of friction, we need to rearrange the equation:

μ = Ffriction / (mgcosθ)

Substituting the known values:

μ = 4.24 N / (18.0 kg)(9.8 m/s²)cos(34.0°) = 0.106

Therefore, the coefficient of friction is 0.106.

What prevents geologists from exploring earth's interior?

Answers

Maybe the Earth's core.
As it has high energy......

What's the difference between inplicit and explicit solvent?

Answers

hi 

Explicit- and implicit-solvent molecular dynamics simulations are performed to study complexation in two polyelectrolyte systems: poly(styrene sulfonate)/poly(allylamine hydrochloride) (PSS/PAH) and poly(acrylic acid)/poly(allylamine hydrochloride) (PAA/PAH). Both these systems have been used in layer-by-layer assembly of polyelectrolyte films, with the first of these typically yielding linear growth in film thickness with increasing numbers of layers and the second yielding exponential growth. In both the systems, the polyelectrolytes have the same number of monomers and are present in stoichiometric proportion, and water is used as solvent. Simulations give important insights into the structure and composition of the complexes. We found that the PSS/PAH complex is more compact and has a smaller fraction of water than the PAA/PAH complex due to the presence of phenyl rings in the PSS chain and the hydrophilic nature of the charged group in the PAA chain. Either an increase in salt concentration or a decrease in partial charge fraction increases swelling and the water content in the complex. To overcome the computational limitations associated with the explicit-solvent simulation, a simple strategy to develop the force field for an implicit-solvent simulation is proposed. In the absence of salt and for fully charged polyelectrolytes, the radius-of-gyration and the various radial distribution functions predicted by the implicit-solvent simulation match well with those predicted by the explicit-solvent simulation, while reasonable agreement is obtained in the other cases. The implicit-solvent simulation was performed for bigger system sizes, and we observed trends similar to those observed for smaller system sizes, suggesting that the simulation results are independent of system size.

hope it helps..

If an object weighs 40 n on earth what would it weigh on the moon

Answers

it would weigh 1/6 (weight on the earth )
= 1/6×40 = 6.67N

How do rocks along the central valley of the mid oceanic ridges provide evidence of seafloor spreading?

Answers

These rocks allow you to know the ages of the rocks. If the rocks are farther from the ridge, they are considered old. The rocks near the ridges are considered the young rocks. Aside from the rock ages, it also helps determine the Earth's magnetic field. Scientists can determine this one with the help of the iron substances in the sea floor. It also helps determine the movements of active volcanoes and heat flow of the lave with the use of MOR

Rank them from fastest to slowest in how quickly each warms up: (a) steel, 450 j/kgââc ; (b) aluminum, 910 j/kgââc ; (c) copper, 390 j/kgââc .

Answers

The rate of conductivity is different among different substances, like aluminum, steel, and copper. Aluminum conducts heat the fastest at 910 j/kgaac. Steel is next and conducts heat at 450 j/kgaac. Copper conducts heat the slowest at 390 j/kgaac.

What is the maximum altitude of Denman Orchard?

Answers

Essentially, denman is an island.  11,000 feet is the maximum altitude of Denman Orchard.

What is orchard?

An orchard is indeed a planned planting of shrubs or trees that is kept up for the purpose of producing food. Trees that produce fruit or nuts are often cultivated in orchards for commercial purposes.

Large gardens may include orchards as a feature, where they serve both a decorative and functional function. Although it is situated on a smaller, non-commercial scale or may emphasis berry bushes rather than fruit trees, a fruit garden and an orchard are typically interchangeable terms. Essentially, Denman is an island. 11,000 feet is the maximum altitude of Denman Orchard.

Therefore, 11,000 feet is the maximum altitude of Denman Orchard.

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Denman Orchard reaches an altitude of about 200 yards in a fictional context, while the tallest real tree in Canada mentioned is 314 feet tall.

The maximum altitude of the fictional location known as Denman Orchard, described in a fantastical passage, is approximately 200 yards above the level plateau mentioned. This is part of an imaginative narrative and not a real-world geographical feature.

In contrast, a real-world example is provided by Randy's search for a tall tree on Vancouver Island. The tree's reported height is 314 feet, which, if accurate, would make it the tallest tree in Canada.

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