An object has a mass of 785 g and a volume of 15 cm³. What is its density? (Give your answer in g/cm³ to 2 decimal places).

Answer:

The velocity of the package before hitting the floor is 35.28 m/s.

Explanation:

Given:

The package is dropped, so initial velocity is, [tex]u=0\ m/s[/tex]

Time taken to reach the floor is, [tex]t=3.60\ s[/tex]

The motion is a complete free fall motion.

When the body is in free fall, the only acceleration acting on the body is due to gravity.

Therefore, the acceleration of the package is, [tex]a=g=9.8\ m/s^2[/tex]

Now, final velocity of the package is, [tex]v=?[/tex]

In order to find the final velocity, we need to use the Newton's equation of motion that relates initial velocity, final velocity, acceleration and time taken.

So, the equation of motion used is given as:

[tex]v=u+at[/tex]

Plug in the given values and solve for 'v'. This gives,

[tex]v=0+9.8\times 3.60\\v=35.28\ m/s[/tex]

Therefore, the velocity of the package before hitting the floor is 35.28 m/s.

Answer:

35.316 [tex]m/s[/tex]

Explanation:

Given: [tex]t=3.60\ sec[/tex]

In free fall velocity does not depend upon height of fall.

Now, we will use the relation between final velocity (v) and initial velocity (u) and time (t) under free fall.

That is [tex]v=u+gt[/tex]

Where 'g' is acceleration due to gravity which is [tex]9.81 m/s^2[/tex]

Here initial velocity (u) is zero as package was dropped from rest.

Plugging the values in the equation, we get.

[tex]v=u+gt\\\\v=0+9.81(t)\\\\v=9.81(3.60)\\\\v=35.316\ m/s[/tex]

Hence, the velocity with which the ball will hit the ground will be [tex]v=35.316\ m/s[/tex].

Answer:

Electromagnetic waves do not require a medium to propagate means they  can travel through air and solid material and the vacuum of space too.

they move the fastest through gases mostly because particles in gases are spread out more than the particles in solids or in liquids so they move quickly through gases.

Explanation:

322.5 joules

Data given;

We are supposed to determine the amount of heat required.

In this case, specific heat, c of gold is 0.129 J/g/°C

Mass of gold in grams is 100 g

Therefore;

Q = 100 g × 0.129 J/g/°C × 25°C

   = 322.5 joules

Thus, the amount of heat required is 322.5 Joules

Answer:

You now this question state why a person standing at point Y hears an echo

Explanation:

Density is mass divided by volume.  For example, Block A:

ρ = m / V

ρ = 60 g / 125 cm³

ρ = 0.48 g/cm³

I assume each block is a cube, so the length of block underwater divided by the side length of the block is the percent underwater.

% = 1.8 / 3.9

% = 46%

Repeat for Blocks B through E.

2.38Ω

We are given;

We are required to calculate the resistance of the iPhone battery;

R = V/I

Therefore;

R = 5.0 V ÷ 2.1 A

  = 2.38 Ω

Thus, the resistance of the iPhone battery is 2.38Ω

For the resistance of an iPhone battery connected to a 5.0V charger at 2.1A, you can use Ohm's Law to calculate the resistance as approximately 2.38 ohms.

The resistance of a battery is determined using Ohm's Law, where resistance (R) equals voltage (V) divided by current (I). In this case, a 5.0V charger at 2.1A results in a resistance of 2.38 ohms.

Answer:

false

Explanation:

its a trick question. not all evidence should be collected from the crime scene due to not all the evidence be useful.

Answer:

Its C waxing gibbous

Explanation:

1) It means that the ratio [tex]\frac{\Delta L}{L}[/tex], where [tex]\Delta L[/tex] is the change in length of the material and L is the original length, change by 0.000017 units for an increase in temperature of 1 Kelvin.

2) The safety gap between two successive bars is 0.33 mm

Explanation:

1)

When a solid material is heated and its temperature increases, the material expands. The linear expansivity of the material gives a measure of how much the length of the material increases per unit temperature change.

For instance, the linear expansivity of copper is

[tex]\alpha = 0.000017/K[/tex]

which means that the ratio [tex]\frac{\Delta L}{L}[/tex], where [tex]\Delta L[/tex] is the change in length of the material and L is the original length, change by 0.000017 units for an increase in temperature of 1 Kelvin.

In formula, this can be rewritten as

[tex]\frac{\Delta L}{L} = \alpha \Delta T[/tex]

where [tex]\Delta T[/tex] is the change in temperature of the material.

2)

To solve this part of the problem, we can use the formula given in the previous part:

[tex]\frac{\Delta L}{L} = \alpha \Delta T[/tex]

Which can be rewritten as

[tex]\Delta L =L \alpha \Delta T[/tex]

where in this case, we have:

L = 3 m is the original length of the steel bar

[tex]\alpha = 1.0\cdot 10^{-5} /K[/tex] is the linear expansivity of steel

[tex]\Delta T = 40^{\circ}C-29^{\circ}C=11^{\circ}C[/tex] is the increase in temperature of the steel bar

Therefore, by solving the formula for [tex]\Delta L[/tex], we find the increase in length of the steel bars when the temperature increases to 40 degrees:

[tex]\Delta L = (3)(1.0\cdot 10^{-5})(11)=3.3\cdot 10^{-4} m = 0.33 mm[/tex]

This means that the safety gap between two successive bars must be 0.33 mm.

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Answer:

B. A line angled upward

Explanation:

velocity is plotted along y- axis and time is plotted along x- axis so we get a line angled upward

1) The acceleration of the plane is 1.89 times the acceleration of gravity

2) The force acting on the airplane is [tex]2.22\cdot 10^5 N[/tex]

Explanation:

1)

The acceleration of the plane is given by

[tex]a=\frac{v-u}{t}[/tex]

where

v is the final velocity of the plane

u is the initial velocity

t is the time elapsed

For the airplane in this problem, we have:

[tex]u=0[/tex] (it starts from rest)

[tex]v=200 km/h \cdot \frac{1000 m/km}{3600 s/h}=55.6 m/s[/tex] is the final velocity

[tex]t=3 s[/tex] is the time

Substituting, we find

[tex]a=\frac{55.6-0}{3}=18.5 m/s^2[/tex]

The acceleration of gravity is

[tex]g=9.8 m/s^2[/tex]

So, the acceleration of the plane relative to [tex]g[/tex] is

[tex]\frac{a}{g}=\frac{18.5}{9.8}=1.89[/tex]

2)

The average force exerted on the plane is given by Newton's second law:

[tex]F=ma[/tex]

where

F is the force

m is the mass of the airplane

a is the acceleration

In this problem, we have

[tex]m=12000 kg[/tex] is the mass of the plane

[tex]a=18.5 m/s^2[/tex] is the acceleration

Substituting, we find:

[tex]F=(12000)(18.5)=2.22\cdot 10^5 N[/tex]

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Answer:

0. 1226495726kg

Explanation:

Force is the product of mass and acceleration.

Mathematically,

Force(F) = mass (m)×acceleration(a)

Substituting the values into the equation

2. 87=m×23. 4

2. 87=m (23. 4)

2. 87/23. 4=m (23. 4)/23. 4

2. 87/23. 4=m

0. 1226495726=m

Answer:

Answer:

0. 1226495726kg

Explanation:

Force is the product of mass and acceleration.

Mathematically,

Force(F) = mass (m)×acceleration(a)

Substituting the values into the equation

2. 87=m×23. 4

2. 87=m (23. 4)

2. 87/23. 4=m (23. 4)/23. 4

2. 87/23. 4=m

0. 1226495726=m

Explanation:

Answer:

The mass of the block is 0.025 kg

Explanation:

Mass-Spring Harmonic Motion

When a mass m is attached to a spring of constant k, they produce a simple harmonic motion which angular frequency is

[tex]\displaystyle w=\sqrt{\frac{k}{m}}[/tex]

We also know

[tex]w=2\pi f[/tex]

which means

[tex]\displaystyle \sqrt{\frac{k}{m}}=2\pi f[/tex]

Squaring

[tex]\displaystyle \frac{k}{m}=4\pi^2 f^2[/tex]

Solving for m

[tex]\displaystyle m=\frac{k}{4\pi^2 f^2}[/tex]

We have

[tex]k=10 N/m, f=10/\pi Hz[/tex]

[tex]\displaystyle m=\frac{10}{4\pi^2 \left (\frac{10}{\pi}\right )^2}[/tex]

Operating

[tex]\displaystyle m=\frac{10}{4\pi^2 \frac{100}{\pi^2}}[/tex]

Simplifying and computing

[tex]\displaystyle m=\frac{1}{40}=0.025\ kg[/tex]

The mass of the block is 0.025 kg

The velocity of sound in at 300C is 511.3 m/s.

Explanation:

The equation that gives the speed of sound in ar as a function of the air temperature is the following:

[tex]v=(331.3+0.6T) m/s[/tex]

where

T is the temperature of the air, measured in Celsius degrees

In this problem, we want to find the speed of sound in ar for a temperature of

[tex]T=300^{\circ}C[/tex]

Substituting into the equation, we find:

[tex]v=331.3 + 0.6(300)=511.3 m/s[/tex]

So, the velocity of sound in at 300C is 511.3 m/s.

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Final answer:

The velocity of sound in air at 30°C is approximately 349 m/s, calculated using the temperature-dependent formula v = 331.4 m/s + 0.6T.

Explanation:

The velocity of sound in air increases with the rise in temperature. At 0°C, sound travels at 331 m/s, and this velocity increases by about 0.6 m/s for each degree Celsius increase in temperature. Given that the temperature is 30°C, we can calculate the speed of sound using the formula v = 331.4 m/s + 0.6T, where T is the temperature in Celsius. Plugging the value of 30°C into the formula gives us v = 331.4 m/s + (0.6 × 30), which equals approximately 349 m/s as the velocity of sound in air at 30°C.

Answer:

C. The procedure scientist use to gain knowledge about the ohysical world

Explanation:

The correct answer is C. The procedure scientists use to gain knowledge about the physical universe.

Explanation:

The scientific method is a non-linear procedure used to answer questions about specific phenomena or understand the world. This method includes a set of steps that are used to create a hypothesis and then tested it successfully. Besides this, the scientific method is applied in most areas related to science because through this scientist can explain or understand the physical universe. According to this, the scientific method can be best described as "The procedure scientists use to gain knowledge about the physical universe".

Answer:

These 5 principles can be better understood from the past events as well as from formation of the sedimentary rocks

Explanation:

Principle of original horizontal- the sedimentary rocks are found to be horizontal during the initial deposits phase. If  tilted this is due to the subsequent geological event.

Principle of original lateral continuity- The sedimentary beds are originally laterally continuous into their environment of deposition. Faulting in the severe folding and also erosion may leads to the separation of the originally lateral continuous beds which in later becomes separate units.

Principle of cross cutting- The younger features can get cuts across the older features. That's why faults,  erosion, volcanoes etc can be seen. The above mentioned are younger than those materials that is faulted intruded, or eroded.

Principle of inclusion- Inclusion itself means (a rock fragment another rock fragment) they must be older than the materials in.

Principle of uniformity-  Those are the physical process that are been seen today, were also worked in the same way in the geologic past, thus modern methods helps us to understand the ancient events.

Answer:

Permanent Charging. When you take a temporarily charged object and ground it, the charged object retains its charge. This is called permanent charging by induction.

Answer:

When light is reflected, the "outgoing" ray is also called the reflected ray.

Explanation:

when an light ray is incident on a boundary of two mediums it an reflect or refract.

reflected ray is the part of the ray that gets back with same mediu that it was coming from. angle of reflection and incident are equal . angle of reflection and incident are the angle made by the reflected and incident ray with the normal.

total internal reflection occurs when the incident angle is greater than the critical angle of pair of given medium and when light travels from denser to rarer medium . in total internal reflection ray gets reflected with no loss at all.

in refracted ray the the light ray passes to the other medium angle of incidence and refraction are not same.

The arguments for and against the theory that animals have the capacity for language, like humans, revolve around communication abilities and linguistic complexity. Some argue that animals can communicate using complex systems of signs, sounds, and gestures, while others claim that their communication lacks the complexity and structure of human language.

There are arguments both for and against the theory that animals have the capacity for language, like humans. Some argue that animals do have the capacity for language based on their ability to communicate with each other and with humans using complex systems of signs, sounds, and gestures. For example, dolphins use a system of clicks and whistles to communicate with each other. Some primates have been taught sign language and can use it to communicate with humans.

On the other hand, some argue that animals do not have the same capacity for language as humans. They point out that while animals can communicate, their communication lacks the complexity and structure found in human language. Animal communication is often limited to simple signals or gestures, rather than the complex syntax and grammar of human language.

Additionally, animals do not exhibit the same level of linguistic creativity and symbolic thought as humans. For example, humans can use language to discuss abstract concepts, tell stories, and express emotions, whereas animals typically use communication for more practical purposes such as signaling danger or finding food.

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Answer:

[tex]0.01132 g/mm^{3}[/tex]

Explanation:

Density, [tex]\rho=\frac {m}{v}[/tex]

Where m is the mass of the object and v is the volume of the same object

Given the dimensions, we can make them in mm hence 45 mm by 52 mm by 60 mm

Volume=45*52*60= 140400 mm^{3}

Density, [tex]\rho=\frac {1590}{140400}=0.011324786 g/mm^{3}\approx 0.01132 g/mm^{3}[/tex]

The actual volume of the liquid is [tex]50 cm^2[/tex]

Explanation:

When doing a measurement, there are two types of errors that we can define:

In this problem we have:

[tex]E_a=0.6 cm^2[/tex] (absolute error)

[tex]E_r = 1.2\%[/tex] (relative error)

Using the formula for the relative error, we can find the actual value of the volume of the liquid:

[tex]V=\frac{E_a}{E_r}\cdot 100 = \frac{0.6}{1.2}\cdot 100 =50 cm^3[/tex]

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Answer:

c. Velocity

Explanation:

Velocity is a measure of change of position of the body with time. Change of position means the distance traveled by the object in a given interval of time but in a particular direction.

We know that speed is given as the distance traveled over a given time interval without taking into account the direction of motion. So, the magnitude of velocity is same as its speed. Velocity, being a vector quantity, has both magnitude and direction.

Therefore, the velocity of an object consists of its speed and direction.

Answer: 13.6 N

Explanation:

The equation of motion for the rabbit is:

[tex]\Delta x=V_{ox}t+\frac{1}{2}a_{x}t^{2}[/tex] (1)

Where:

[tex]\Delta x=0.85 m[/tex] is the distance traveled by the rabbit

[tex]V_{ox}=0 m/s[/tex] is the rabbit's initial velocity, assuming it started from rest

[tex]t=0.5 s[/tex] is the time

[tex]a_{x}[/tex] is the acceleration

Isolating [tex]a_{x}[/tex]:

[tex]a_{x}=\frac{2 \Delta x}{t^{2}}[/tex] (2)

[tex]a_{x}=\frac{2 (0.85 m)}{(0.5)^{2}}[/tex] (3)

[tex]a_{x}=6.8 m/s^{2}[/tex] (4)

On the other hand, the force [tex]F_{x}[/tex] is given by:

[tex]F_{x}=m.a_{x}[/tex] (5)

Where [tex]m=2 kg[/tex] is the mass of the rabbit

Substituting (4) in (5):

[tex]F_{x}=(2 kg)(6.8 m/s^{2})[/tex] (6)

Finally:

[tex]F_{x}=13.6 N[/tex]

Answer:

non linear square relationship

Explanation:

formula for centripetal force is given as

a = mv^2/r

here a ic centripetal acceleration , m is mass of body moving in circle of radius r and v is velocity of body . If m ,and r are constant we have

a = constant × v^2

a α v^2

hence non linear square relationship

The relationship between velocity and centripetal force is a nonlinear square relationship.

The centripetal force is given by;

F = mv^2/r

The centripetal force is the force required to keep an object moving in a circular path.

If we take the relationship between the centripetal force and velocity as we can see in the equation above, we realize that it is a nonlinear square relationship. Therefore, the relationship between velocity and centripetal force is a nonlinear square relationship.

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Answer:

A) Shape of Continental coastlines matching up together

Explanation:

It helped provide evidence for how the plates moved. Answer B could be right, but the moving of the plates helped provide evidence as to why we were finding similar fossils on different countries so it's almost opposite

Answer:

4 kWh or 4 units

Explanation:

energy = power × time

            = 400 W×  10 h

            = 4000 Wh

           =( 4000/ 1000 )  kWh

            = 4 kWh

             = 4 commercial units

Answer:

volume = 0.47 [tex]m^{3}[/tex].

Explanation:

Density:

[tex]d = \frac{m}{v}[/tex]

We have that d = 2700 kg/[tex]m^{3}[/tex] and that we have 1280 kg of Al.

[tex]2700 = \frac{1280}{V}[/tex]

V = 0.47 [tex]m^{3}[/tex]

Answer:

The correct answer is 0.47 m³

Explanation:

The formula for density (d) is

Mass (m) ÷ volume (v)

Hence

d = m ÷ v

The density of aluminium (as provided in the question) is 2700  kg/m³ and the mass of aluminium is 1280 kg, the volume is however unknown.

Thus, from the formula earlier

2700 = 1280 ÷ v

v = 1280 ÷ 2700

v = 0.47 m³

The volume of aluminium when the density is 2700  kg/m³ and the mass is 1280 kg is 0.47 m³

Answer:

The frequency should increase.

Explanation:

The wavelength of a wave varies inversely to frequency of the wave.

The relation between the frequency and wavelength of a wave is given as:

[tex]f\lambda=v[/tex]

Here, [tex]f\to frequency\\\lambda\to wavelength\\v\to velocity\ of\ wave[/tex]

Therefore, as the wavelength increases then the frequency will decrease.

Similarly, as the wavelength of the wave decreases, then the frequency will increase.

So, the frequency should increase if you decrease the wavelength of a wave.

Answer:

9.05 W

Explanation:

The given formula is [tex]r=\sqrt {\frac {P}{0.02\pi}}[/tex] where r is in centimeters and P is in Watts

Making Power, P the subject from the above formula

[tex]P=0.02\pi r^{2}[/tex]

Substituting r with 12 cm then

[tex]P=0.02\pi 12^{2}= 9.047786842  W\approx 9.05 W[/tex]

Final answer:

A cell with a radius of 12 cm produces approximately 2.88π watts of power.

Explanation:

The given equation relates the power P produced by a circular solar cell to the radius r of the cell. To find the power produced by a cell with a radius of 12 cm, you can substitute this radius value into the equation.

Using the equation r = √(p / (0.02π)), we have r = √(p / (0.02π)). Plugging in r = 12 cm, we can solve for P.

12 = √(p / (0.02π)) ⇒ [tex]12^2[/tex] = p / (0.02π),

or 144 = p / (0.02π).

Multiplying both sides of the equation by (0.02π), we get:

2.88π = p.

Therefore, a cell with a radius of 12 cm produces approximately 2.88π watts of power.

It travels faster at higher temperature. Longitudinal wave is a wave in which the vibration of the particles travels in the parallel direction to the propagation of wave. Therefore, the common characteristic between transverse wave and longitudinal is both move faster at higher temperature.

Transverse waves and longitudinal waves are both types of mechanical waves that propagate through a medium.

Wavelength is a fundamental property of waves, including electromagnetic waves like light and radio waves, as well as other types of waves, such as sound waves or water waves.

One commonality between transverse and longitudinal waves is that they both involve the transfer of energy through a wave. In both cases, the energy is carried by the disturbance of the medium, whether it is a series of crests and troughs in a transverse wave or a series of compressions and rarefactions in a longitudinal wave.

Another commonality is that both types of waves can exhibit properties such as reflection, refraction, diffraction, and interference. These phenomena occur as the wave interacts with boundaries, obstacles, or other waves, and they can affect the behavior and properties of the wave.

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The characteristic that changes in each isotope of calcium is the number of neutrons in the nucleus. The atomic number remains the same for all the isotopes.

The characteristic that differs in each isotope of an element, in this case, Calcium (Ca), is D. the number of neutrons in the nucleus. An isotope is a variant of a particular chemical element, and what distinguishes one isotope from another is the number of neutrons. For instance, Ca-40, Ca-42, Ca-43, and Ca-44 hold 20, 22, 23, and 24 neutrons, respectively. The atomic number, which represents the number of protons in an atom, remains the same for all isotopes of an element. Therefore, the number of neutrons in the nucleus is the only characteristic that changes within isotopes of the same element.

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The correct answer is D. The only characteristic that varies among the listed calcium isotopes is the number of neutrons in the nucleus.

Since the atomic number of calcium (Ca) is 20, each isotope of calcium has 20 protons. The isotopes listed in the question, Ca-40, Ca-42, Ca-43, and Ca-44, have atomic masses of 40, 42, 43, and 44, respectively.

To find the number of neutrons in each isotope, we subtract the number of protons (which is constant for calcium) from the atomic mass:

- For Ca-40: 40 (atomic mass) - 20 (protons) = 20 neutrons

- For Ca-42: 42 (atomic mass) - 20 (protons) = 22 neutrons

- For Ca-43: 43 (atomic mass) - 20 (protons) = 23 neutrons

- For Ca-44: 44 (atomic mass) - 20 (protons) = 24 neutrons

As we can see, the number of neutrons varies in each isotope, which is the characteristic that is different for each isotope listed.

The other options provided in the question can be ruled out based on the following reasons:

 A. the position in the periodic table of the elements - All calcium isotopes have the same position in the periodic table because they all have 20 protons, which defines their atomic number and thus their position in the periodic table.

B. the net charge of the nucleus - The net charge of the nucleus is determined by the number of protons, which is the same (20) for all calcium isotopes. Therefore, the net charge of the nucleus does not vary among these isotopes.

C. the mass of the protons in the nucleus - The mass of a proton is constant and does not vary from one isotope to another. All calcium isotopes have the same number of protons, so the mass of the protons is not the characteristic that differs among these isotopes.