An object is dropped from a 15 m ledge. How fast it is moving just before it hits the ground?

Answers

Answer 1
By v^2 = u^2 + 2gh 
v^2 = 0 + 2 x 9.8 x 15
v = √294
v = 17.15 m/s 
Answer 2

Answer:

[tex]v_f = 17.15 m/s[/tex]

Explanation:

Since the ball is dropped from the height

h = 15 m

so here initial speed of the ball is

[tex]u = 0[/tex]

acceleration of the ball due to gravity is given as

[tex]a = 9.8 m/s^2[/tex]

now the final speed of the ball is given as

[tex]v_f^2 - v_i^2 = 2 a d[/tex]

[tex]v_f^2 - 0 = 2(9.8)(15)[/tex]

[tex]v_f = 17.15 m/s[/tex]


Related Questions

What is the distance from the earth and the sun? Please explain

Answers

The distance is 92.96 million miles. This is called an astronomical unit (AU), which is used to measure distance in the solar system.
Here is your answer:

Based on what scientists research the the Earth and the sun is
=148.56miles

Because of technology scientist were able to find the exact distance of the Earth and the Sun.

:))))

Jesse is swinging Miguel in a circle at a tangential speed of 3.50 m/s. If the radius of the circle is 0.600 m and Miguel has a mass of 11.0 kg, what is the centripetal force on Miguel? Round to the nearest whole number.

Answers

225 N is the answer. Glad I could help

Answer:

Explanation:

When an object is moving around a circular path with a uniform speed the motion os said to be uniform cicular motion. It is the example of accelerated motion as the direction of motion keeps on changing every instant.

When a body is in uniform circular motion, it experiences a force towards the centre of circular path, this force is called centripetal force.

The formula of centripetal force is given by

F = mv^2 / r

Where m is the mass of body, V be the speed of body and R be the radius of circular path

F = 11 × 3.5 × 3.5 / 0.6

F = 224.58 N

The process of estimating values between measured data points is called

Answers

the answer to this question is interpolation
Interpolation is often required in a certain research in order to estimate the value of a certain function for an intermediate value of the independent variable.in order to ensure the validity of the data and the results made during the experiment.

Answer:

The process of estimating values between measured data points is called. interpolation.

Explanation:

Seagulls are often observed dropping clams and other shellfish from a height to the rocks below, as a mean of opening the shells. If a seagull drops a shell from rest at a height of 14.0m, how fast is the shell moving when it hits the rocks?

Answers

This is free fall with initial speed zero under the acceleration of gravity [tex]g[/tex]
We apply the equation 
[tex]v^2=v_0^2+2a*s[/tex]
rewritten as
[tex]v^2=2gh[/tex]
From this we find the sspeed of the shell as
[tex]v= \sqrt{2*9.81*14}=16.57 (m/s) [/tex]

Final answer:

The shell dropped by the seagull would be moving at a speed of approximately 16.7 m/s when it hits the ground. This calculation is based on the physics concept of final velocity in a free-fall motion.

Explanation:

In this scenario, the concept of kinematics, an aspect of Physics, will be employed. Particularly, we'll be focusing on free fall motion. The speed of the shell just before hitting the ground can be calculated using the equation for the final velocity in free fall: v = √(2gs) where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s² on Earth), and s is the height from which the object is dropped.

Substituting the given values (s = 14.0m, g = 9.81m/s²) into the equation, the calculation should look like this:

v = √(2*9.81*14.0) ≈ 16.7 m/s

So, the shell should be moving at approximately 16.7 m/s when it hits the rocks below.

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The summer season is closely linked to which of the following?
An equinox because the Earth is very close to the Sun
An equinox because the Earth is very far away from the Sun
A solstice because the Earth is very close to the Sun
A solstice because the Earth is very far away from the Sun

Answers

The summer season begins with a solstice and ends with an equinox, in both hemispheres.
Equinoxes and solstices have no connection to the Earth's distance from the sun.
In the northern hemisphere, the Earth is FARTHEST from the sun early in summer, around the first week of July.

Answer:

The correct statement is “A solstice because the Earth is very close to the Sun”

Explanation:

The solstice occurs when the sun is closer or further from one of the Earth's hemispheres, increasing the duration of the day in one part of the world, and decreasing its duration in the other. That is, during the solstice, the sun is closer to one of the hemispheres, causing the day to have a longer duration, while the night is longer in the other hemisphere.

In the case of the equinox, the sun is on the equator line, so the day and night in both hemispheres have the same duration. At that time the part of the Earth closest to the Sun is the equator.

The solstice is caused because the axis on which our planet rotates on itself is slightly inclined with respect to the translation plane, this is its trajectory around the Sun.

That implies that different regions of the globe receive more or less light at different times of the year.

The equinox like the solstice is presented twice a year, marking the entrance of the seasons. The sunny days are longer during the summer solstice, while the nights are longer during the winter solstice. The equinox occurs at the beginning of autumn and spring, when the sun is closer to the equator.

So the correct statement is “A solstice because the Earth is very close to the Sun”

How is active transport possible since it contradicts the second law of thermodynamics?

Answers

The second law of thermodynamics states that the total entropy of a system increases. The key thing to remember is "total entropy of a system". It's perfectly reasonable for the local entropy of part of a system to decrease as long as the total entropy of the entire system increases. In the case of active transport, energy is consumed in the form of ATP molecules.

Why are all tides greatest at the time of a full moon or new moon?

Answers

Great question. Tides are caused by tidal forces, and the answer to your question lies in the definition of a tidal force. A tidal force is related to gravity, but it isnt the same thing. Its really the difference between the strength of gravity at two locations.

Do changes in speed and mass have the same effect on the kinetic energy of an object? Explain.

Answers

Yes, it does because depending on its speed and mass, it will either move faster than another object or move slower. This shows a demonstration of kinetic energy increasing or decreasing.

When we make our memories consistent with our current beliefs or attitudes, we are experiencing?

Answers

selfishness.. I'm not sure honestly

A worker pushes horizontally on a 34 kg crate with a force of magnitude 110 n . the coefficient of static friction between the crate and the floor is 0.37. (a) what is the frictional force on the crate from the floor?

Answers

Static frictional force = 126.91 N 
1st worker force = 110 N 
2nd worker = 126.91 – 110 = 16.91 Nelectron1 · 7 years ago.

A runner achieves a velocity of 11.1m/s nine seconds after he begins running. What is his acceleration?

Answers

Using this kinematics formula: Vf=vi+at, we get: 11.1=0+a*9, solving for a we get 1.233 m/s^2. That's his acceleration.

A bird sitting high in a tree is an example of an object with what type of energy? (2 points)

potential energy because it has the ability to do work

kinetic energy because it has the ability to do work

potential energy because it is doing work

kinetic energy because it is doing work
16.
A cook preparing a meal for a group of people is an example of (2 points)

kinetic energy because he has the ability to make a meal.

potential energy because he has the ability to make a meal.

kinetic energy because he is making the meal.

potential energy because he is making the meal.
17.
When a bow is stretched back and an arrow is shot, what type of energy conversion has occurred? (2 points)

chemical to mechanical

elastic to mechanical

mechanical to thermal

mechanical to elastic

Answers

15)Potential energy because it has the ability to do work.

16) Kinetic energy because he is making the meal.

17) Elastic to Mechanical

Answer:

1) the bird sitting on the tree is not moving, hence he has not kinetic energy. By the fact that the bird is high in the tree you can see that it has some potential energy (wich in this case depends on the height) and the bird has potential energy because has the ability  of doing work (lije jumping down for example)

2) the cook is moving, because he needs to do it in order to prepare the meal, then he has kinetic energy and is doing work (because he puts the energy in order to move himself) the answer is "kinetic energy because he is making the meal.

3) Ok, when you stretch the bow, it wants to return to his original shape, then you are creating elastical energy in the bow, and you are using mechanical energy to stretch the bow.  Then when the bow releases his elastical energy (also you can think that when the string is pushing the arrow, it is applying mechanical energy on the arrow), it propulsates the arrow, creating now kinetic energy into the arrow.

The correct answer is mechanical to elastic, because you need to first use mechanical energy in order to stretch the bow and create the elastic energy, and then mechanical again when the string starts to impulse the arrow.

Find the emitted power per square meter of peak intensity for a 2600 k object that emits thermal radiation.

Answers

Hotter Sun: Suppose the surface temperature of the Sun were about 12,000K, rather than 6000K. a. How much more thermal radiation would the Sun emit? b. What would happen to the Sun’s wavelength of peak emission? c. Do you think it would still be possible to have life on Earth? Explain. Answer: a) To calculate the emitted power per square meter we need to use Stefan-Boltzmann’s Law, that is, 𝸠= 𝜍𝑇 4 đť‘Šđť‘•đť‘’đť‘źđť‘’, 𝸠= đť¸đť‘šđť‘–𝑡𝑡𝑒𝑑 đť‘𝑜𝑤𝑒𝑟 đť‘ťđť‘’đť‘ź 𝑠𝑞𝑎𝑢𝑟𝑒 𝑚𝑒𝑡𝑒𝑟 đť‘śđť‘“ 𝑠𝑢𝑟𝑓𝑎đť‘đť‘’ 𝑇 = 𝑡𝑒𝑚𝑝𝑒𝑟𝑎𝑡𝑢𝑟𝑒 đť‘–đť‘› đťľđť‘’𝑙𝑣𝑖𝑛 𝑎𝑛𝑑 𝜍 = 𝑆𝑡𝑒𝑓𝑎𝑛 â’ đťµđť‘śđť‘™đť‘ˇđť‘§đť‘šđť‘Žđť‘›đť‘› đť¶đť‘śđť‘›đť‘ 𝑡𝑎𝑛𝑡 = 5.7 Ă— 10â’8 𝑤𝑎𝑡𝑡 đť‘š2 Ă— đťľ4 At 6000K, Emitted Power = 𝜍 Ă— (6,000) 4 At 12000K, Emitted Power = 𝜍 Ă— (12,000) 4 Now calculate the ratio of thermal radiation at the two temperatures to find out how much more thermal radiation would the Sun emit, đť¸12000𝾠𝸠6000đťľ = 𝜍 Ă— (12,000) 4 𝜍 Ă— (6,000) 4 = 12,000 4 6,000 4 = 12,000 6,000 4 = 2 4 = 16 â´ đť¸12000𝾠𝸠6000đťľ = 16 Therefore, emitted power at 12000K is 16 times the emitted power at 60000K. b) To calculate the wavelength of maximum intensity we need to use Wien’s Law, that is, 𝜆𝑚𝑎𝑥 = đť‘Ź 𝑇 đť‘Šđť‘•đť‘’đť‘źđť‘’, 𝜆𝑚𝑎𝑥 = 𝑤𝑎𝑣𝑒𝑙𝑒𝑛𝑔𝑡𝑕 đť‘śđť‘“ 𝑚𝑎𝑥𝑖𝑚𝑢𝑚 𝑖𝑛𝑡𝑒𝑛𝑠𝑖𝑡𝑦 đť‘Ź = đť‘Šđť‘–đť‘’đť‘› ′ đť‘ đť‘𝑜𝑛𝑠𝑡𝑎𝑛𝑡 = 2,900,000 𝑛𝑚.𝾠𝑇 = 𝑡𝑒𝑚𝑝𝑒𝑟𝑎𝑡𝑢𝑟𝑒 đť‘–đť‘› đťľđť‘’𝑙𝑣𝑖𝑛 𝜆𝑚𝑎𝑥 = 2,900,000 𝑇 = 2,900,000 6,000 đť‘śđť‘ź 483.33 𝑛𝑚 𝜆𝑚𝑎𝑥 = 2,900,000 𝑇 = 2,900,000 12,000 đť‘śđť‘ź 241.67 𝑛𝑚 𝑅𝑎𝑡𝑖𝑜 = 𝜆max 𝑎𝑡 12,000𝾠𝜆max 𝑎𝑡 6,000đťľ = 2,900,000 12,000 Ă— 6,000 2,900,000 ⴠ𝜆max 𝑎𝑡 12,000𝾠𝜆max 𝑎𝑡 6,000đťľ = 1 2 Therefore, wavelength of maximum intensity at 12,000K is half the wavelength of maximum intensity at 6,000K. c) We know that the intensity of light emitted by a given object depends on its wavelength or frequency. Here, the wavelength at 12,000K is reduced by half which means its frequency has increased by half. In the EM spectrum, UV rays have shorter wavelengths. Therefore, at this temperature, the Sun would emit copious ultraviolet light which cannot be suitable for supporting life. Chapter 5: #52 Doppler Calculations II. In hydrogen, the transition from level 2 to level 1 has a rest wavelength of 121.6 nm. Suppose you see this line at wavelength ay 121.9 nm in Star C and at 122.9 nm in Star D. Calculate each star’s speed, and be sure to state whether it is moving toward or away from us.

Final answer:

To calculate the emitted power per square meter for an object at 2600 K, we use the Stefan-Boltzmann law with a value of 5.67 × 10^-8 W/m^2/K^4 for the Stefan-Boltzmann constant. The result for the given object is approximately 1.53 × 10^7 W/m^2.

Explanation:

Finding the Emitted Power Per Square Meter for a Blackbody

To find the emitted power per square meter (intensity) of peak intensity for an object with a temperature of 2600 K, we will use the Stefan-Boltzmann law, which expresses the power radiated per unit area from a blackbody in terms of the Stefan-Boltzmann constant (σ) and the absolute temperature (T) to the fourth power. The Stefan-Boltzmann law can be written as:

dP/dA = σ T^4,

where σ (Stefan-Boltzmann constant) is approximately 5.67 × 10^-8 W/m^2/K^4. We can calculate the power per square meter by plugging the given temperature into this equation:

dP/dA = (5.67 × 10^-8 W/m^2/K^4) × (2600 K)^4,

After calculating, we find that the power emitted per square meter at peak intensity is:

dP/dA = about 1.53 × 10^7 W/m^2.

Therefore, an object at 2600 K emits approximately 1.53 × 10^7 watts per square meter.

Which statement accurately describes radiation?

Radiation needs matter to transfer thermal energy.
Thermal energy is transferred by electromagnetic waves.
Ironing a shirt to take out wrinkles is an example of radiation.

Answers

I believe it is Thermal energy is transferred by electromagnetic waves.

Answer:

Option 2.) Thermal energy is transferred by electromagnetic waves.

Explanation:

just answered it on e2020

Select three standard units of the metric system.
centimeter
meter
liter
cubic
centimeter
gram
kilogram

Answers

centimeter, meter, liter

Answer:

Meter

Liter

Kilogram

Even though the Sun has a greater mass than Earth, the Moon orbits Earth because it's ___________________ to Earth than to the Sun.

Answers

Even though the Sun has a greater mass than Earth, the Moon orbits Earth because it's closer to the Earth than to the Sun. Because of this proximity between the Earth and the Moon, the Earth has a stronger gravitational pull than the Sun does. Furthermore, the Earth's mass is 81 times that of the Moon, and so at this proximity, it is more than able to overpower what pull the Sun exerts on the Moon.

Final answer:

The Moon orbits Earth instead of the Sun because it is closer to Earth. The strength of gravitational attraction is greater with proximity, despite the Sun's larger mass. The close distance to Earth thus ensures the Moon's stable orbit around it.

Explanation:

Even though the Sun has a greater mass than Earth, the Moon orbits Earth because it's closer to Earth than to the Sun. The gravitational force that an object experiences from another object is not just dependent on the mass but also on the distance between the two objects. In the Earth-Moon system, despite the Moon and the Sun both exerting gravitational forces on each other, the Moon remains in orbit around the Earth because it is much closer to Earth than it is to the Sun.

While the Sun is 27 million times more massive than the Moon, its gravitational pull on the Moon is lesser because it is 387 times farther away from the Earth than the Moon is. The gravitational force decreases with the square of the distance, which means that even a massive object like the Sun exerts a weaker force on the Moon compared to Earth, which is much closer.

Therefore, the Moon's orbit around Earth is stable because the Earth's gravitational pull on the Moon is significantly stronger than that of the Sun's due to the close proximity of the Moon to Earth. In the context of gravitational interactions, this proximity is the key factor in the Moon being Earth's natural satellite.

The table shows data for the planet Uranus.

To the nearest whole number, how much would a 25.0 kg rock weigh on Uranus?

170 N
218 N
430 N
532 N

Answers

Answer:

weight of the rock on Uranus is 218 Newton.

Explanation:

Weight of the object is given by,

Weight = mass × gravitational acceleration

For Uranus,

gravitational acceleration = 8.7 [tex]\frac{m}{s^{2} }[/tex]

thus,

Weight of rock on Uranus is,

Weight = mass × gravitational acceleration

Weight = 25 × 8.7

Weight = 217.5 Newton

Thus, weight of the rock on Uranus is 218 Newton.

Answer:

B

Explanation:

Edge 2021

The Black Hills of South Dakota is an example of an eroded _____.
laccolith dlke batholith sill

Answers

 batholith
 
i hope this is right, if not then correct me lol

The Black Hills of South Dakota is an example of an eroded "batholith".


Magma does not generally achieve the surface. In the event that gas weights are not sufficiently extraordinary to constrain the magma to the surface, or if overlying rocks can't be infiltrated by it, the magma may gradually cool and frame an extensive pool of stone. Stone is effortlessly unmistakable by its extensive gem structure and blend of minerals, including light-hued quartzes and darker feldspars and micas. An expansive district of intru-sive molten shake, found profound inside the outside, is known as a batholith. Batholiths can frame the center of a mountain run. This batholith, once framed profound inside Earth's outside layer, is presently uncovered at an elevation surpassing 3300 meters (10,000 ft) above ocean level. The Black Hills of South Dakota are another exemplary case of this sort of geologic development.

A car with a mass of 2500 kg accelerates when the traffic light turns green. If the net force on the car is 5000 Newton’s, what is the car’s acceleration?

Answers

a=Fnet/m
a=5000N/2500kg
a= 2 m/s^2 (meters per second squared)

Final answer:

The car's acceleration can be calculated using Newton's second law of motion, which states that force is equal to mass multiplied by acceleration. By rearranging the formula, we can find the car's acceleration to be 2 m/s².

Explanation:

The acceleration of a car can be calculated using Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = ma). In this case, the net force acting on the car is 5000 N and the mass of the car is 2500 kg. Using the formula, we can rearrange it to solve for acceleration:

a = F / m

Substituting the given values, we have:
a = 5000 N / 2500 kg

Simplifying the equation gives:
a = 2 m/s²

Therefore, the car's acceleration is 2 m/s².

What is the value of work done on an object when a 10–newton force moves it 30 meters and the angle between the force and the displacement is 25°?


Answers

The component of force which is parallel to the path of the motion is 10N * cos25 = 9.06 N 
This component is the only "effective" force, and it is the one doing work. 

Work = force * distance

Work = 9.06 N * 30 m

Work = 2.7×10^2 J

Answer:

2.7×10^2 Joules

Explanation:

A 25 n box is pulled across a frictionless surface by an applied force of 22 n. the coefficient of kinetic friction between the box and the surface is 0.3. find the acceleration of the box. use g = 10 m/s2 .

Answers

Final answer:

The acceleration of the box is -2.12 m/s^2.

Explanation:

To find the acceleration of the box, we need to calculate the net force acting on it. The net force is the difference between the applied force and the force of kinetic friction. The force of kinetic friction can be calculated by multiplying the coefficient of kinetic friction by the normal force, which is the weight of the box. The weight of the box is mass multiplied by the acceleration due to gravity. With this information, we can plug in the given values and calculate the acceleration.



Calculate the weight of the box. Weight = mass x acceleration due to gravity. Given that the mass of the box is 25 N, and acceleration due to gravity is 10 m/s2, the weight of the box is 25 N x 10 m/s2 = 250 N.Calculate the force of kinetic friction. Force of kinetic friction = coefficient of kinetic friction x weight of the box. Given that the coefficient of kinetic friction is 0.3 and the weight of the box is 250 N, the force of kinetic friction is 0.3 x 250 N = 75 N.Calculate the net force. Net force = applied force - force of kinetic friction. Given that the applied force is 22 N and the force of kinetic friction is 75 N, the net force is 22 N - 75 N = -53 N (negative because the force of kinetic friction opposes the motion).Calculate the acceleration. Acceleration = net force / mass. Given that the net force is -53 N and the mass is 25 N, the acceleration is -53 N / 25 N = -2.12 m/s2. Since the acceleration is negative, it means that the box is slowing down.

Therefore, the acceleration of the box is -2.12 m/s2.

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Final answer:

To find the acceleration of the box, you subtract the frictional force from the applied force, then divide by the box's mass. In this case, the acceleration is found to be 5.8 m/s².

Explanation:

To find the acceleration of the box, we need to apply Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. In this case, the net force is the applied force minus the force of friction. Given the normal force (created by the box's weight) is 25 N, the force of friction would be the coefficient of kinetic friction (0.3) multiplied by the normal force. That equals 0.3 * 25 = 7.5N.

Then, the net force is the applied force (22 N) minus this frictional force: 22 - 7.5 = 14.5 N. Since force equals mass times acceleration (F = ma), you can find the acceleration (a) by dividing the net force by the mass. Remember that the mass should be calculated by dividing the weight by gravitational acceleration (m = N/g). The mass is 2.5 kg. Therefore, the acceleration (a) would be F/m = 14.5 N divided by 2.5 kg= 5.8 m/s².

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3. Ohm's law is represented by the equation, I = V/R. Explain how the current would change if the amount of resistance decreased and the voltage stayed the same.

Answers

In accordance with the law, if r became smaller, and V stayed the same, the current would increase. The increases would be inversely proportional to the resistance, if the resistance was halved, the current would double.

Explain how to identify a starting position on a line.

Answers

a fully shaded bubble with a line going right.

Sample Response: Pick a reference point on the line to be the zero position. Determine the direction and measure the distance from zero in standard units.

-The reference point is set on the line.

-The distance from that reference point can be used to describe movement.

-Standard units of measurement can be used to identify the distance from the reference point.

A source of sound is kept in a jar in a vacuum. Air is slowly introduced in to the jar. What happens to the sound coming out of the jar? A The loudness of the sound increases gradually. B The loudness of the source decreases gradually. C The sound remains unchanged. D The pitch of the sound increases gradually. E
The pitch of the sound decreases gradually.

Answers

The loudness of the sound increases gradually as the air is slowly introduced in to the jar. This is because sound needs a physical medium and in a vacuum there is none. The air provides that medium and as it is introduced, the transfer of sound energy increases

A source of sound is kept in a jar in a vacuum. Air is slowly introduced in to the jar. The loudness of the sound increases gradually  because the air is slowly introduced in to the jar as sound needs a physical medium and in a vacuum there is none.

what are the properties of a sound ?

The pitch of the sound is an important property where the perception of frequency of sound occur by human ear within the range of human hearing, higher the frequency of the sound the higher is its pitch and a lower frequency means a lower pitch.

The loudness of sound can be determined by amplitude of the sound which  is a measure of the magnitude of the maximum disturbance of sound.

The speed of the sound can be detrained as  the sound waves travel through the medium is called the speed of sound and it is different for different mediums, travels fastest in solids.

When sound waves hit the surface of a solid  it reflects back to the same medium as it follows laws of reflection, Timbre is the another  property of sound which is used to differentiate sounds of the same frequency.

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Potential energy
a. transfers motion to matter.
b. is stored energy unavailable to do work.
c. is kinetic energy that has not yet been turned to heat.
d. contains less energy than kinetic energy.
e. is contained in matter placed in certain positions or arrangements.

Answers

the answer would be B.

How does speed affect the friction between a road and a skidding tire?

Answers

speed does not affect friction, friction affects force

in 1650, an individual calculated that the earth was about 6,000 years old. since then what has happened to scientists of the earths age?

A. scientists now beleive the earth is much younger.
B. scientists are now less sure of the earths age
C. scientsts now believe the earth is much older
D. scientists agree with the estimate from 1650

Answers

C is the correct answer to your question.
The answer is c scientists now believe the earth is much older
 

The refractive index of medium A is 1.54 and that of medium B is 2.12. Which statement is correct about this information?

Answers

the statement that is correct about this information is a ray of light passing from medium A to B will bend toward the normal.

Answer:

A ray of light passing from medium A to B will bend toward the normal.

Explanation: Plato user

On his fishing trip Justin rides in a boat 12 km south The fish aren’t biting so they go 4 km west. They then follow a school of fish 1 km north. What distance did they cover? What was their displacement?

Answers

In finding the distance that covers we simply add the three km which is 
12 + 4 + 1 = 17km

17 km is the distance they cover.

We are going to use the displacement formula which is
d = vt + 1/2 at^2
d = 11.7 km

11.7 is the displacement

The distance is 17 km

The displacement of the boat is about 12 km at 70° S of W

[tex]\texttt{ }[/tex]

Further explanation

Vector is quantity that has magnitude and direction.

One example of a vector is displacement.

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

This problem is about Vector Diagram.

On his fishing trip Justin rides in a boat 12 km south.

[tex]d_1 = -12 \widehat{j}[/tex]

[tex]\texttt{ }[/tex]

The fish aren’t biting so they go 4 km west.

[tex]d_2 = -4 \widehat{i}[/tex]

[tex]\texttt{ }[/tex]

They then follow a school of fish 1 km north.

[tex]d_3 = 1 \widehat{j}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{Total Distance} = 12 + 4 + 1 = 17 \texttt{ km}[/tex]

[tex]\texttt{ }[/tex]

[tex]d = d_1 + d_2 + d_3[/tex]

[tex]d = -12 \widehat{j} - 4 \widehat{i} + 1 \widehat{j}[/tex]

[tex]d = -4 \widehat{i} - 11 \widehat{j}[/tex]

[tex]\texttt{Total Displacement} = \sqrt{4^2 + 11^2} = \sqrt{137} \approx 12 \texttt{ km}[/tex]

[tex]\texttt{Direction of Displacement} = \theta = \tan^{-1} \frac{11}{4} \approx 70^o \texttt{ south of west}[/tex]

[tex]\texttt{ }[/tex]

Learn moreDirection of Displacement : https://brainly.ph/question/1746541Scalar and Vector : https://brainly.ph/question/274572Weight : https://brainly.ph/question/545327Orientation of Vectors : https://brainly.ph/question/2121753

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Answer details

Grade: High School

Subject: Physics

Chapter: Vectors

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Keywords: Local , Race , Driver , Road , Finish , Line , Displacement , Vector , Degree , North , West , South , Kilometres

How much work is required to move a box 5 meters across the floor with a force of 15N?

20 J
25 J
75 J
100 J

Answers

75 J. All I did was multiply the 2 numbers to get 75
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