I think the situation is modeled by the scenario in the attached image. Some specific values seem to be missing (like the height of door [tex]d[/tex])...
The door forms a right triangles that satisfies
[tex]\tan\theta=\dfrac ab\implies\sec^2\theta\dfrac{\mathrm d\theta}{\mathrm dt}=\dfrac{b\frac{\mathrm da}{\mathrm dt}-a\frac{\mathrm db}{\mathrm dt}}{b^2}[/tex]
We also have
[tex]\tan\theta=\dfrac ab\implies\cos\theta=\dfrac bd[/tex]
so if you happen to know the height of the door, you can solve for [tex]b[/tex] and [tex]a[/tex].
[tex]d[/tex] is fixed, so
[tex]a^2+b^2=d^2\implies2a\dfrac{\mathrm da}{\mathrm dt}+2b\dfrac{\mathrm db}{\mathrm dt}=0\implies\dfrac{\mathrm da}{\mathrm dt}=-\dfrac ba\dfrac{\mathrm db}{\mathrm dt}[/tex]
We can solve for the angular velocity [tex]\dfrac{\mathrm d\theta}{\mathrm dt}[/tex]:
[tex]\dfrac{\mathrm d\theta}{\mathrm dt}=\cos^2\theta\dfrac{b\left(-\frac ba\frac{\mathrm db}{\mathrm dt}\right)-a\frac{\mathrm db}{\mathrm dt}}{b^2}=-\dfrac1a\dfrac{\mathrm db}{\mathrm dt}[/tex]
At the point when [tex]\theta=40^\circ[/tex] and [tex]\dfrac{\mathrm db}{\mathrm dt}=1.8[/tex] ft/s, we get
[tex]\dfrac{\mathrm d\theta}{\mathrm dt}=-\dfrac{1.8}a\dfrac{\rm deg}{\rm s}=-\dfrac{1.8}{d\sin40^\circ}\dfrac{\rm deg}{\rm s}[/tex]
The angular velocity of the door is [tex]\rm \( 0.744 \, \text{rad/s} \)[/tex], and the velocity of end D is approximately [tex]\rm \( 3.6 \, \text{ft/s} \)[/tex] in the horizontal direction and [tex]\rm \( 2.6964 \, \text{ft/s} \)[/tex] in the upward direction.
To determine the angular velocity of the door and the velocity of end D, we'll need to use the concept of relative velocity.
Let:
- [tex]\rm \( v_b = 1.8 \, \text{ft/s} \)[/tex] (velocity of wheel B)
- [tex]\( \theta = 40^\circ \)[/tex] (angle between horizontal and the line connecting wheel A to wheel B)
We'll use the following relations for the velocity components:
- For wheel B: [tex]\rm \( v_b = v_{b_x} \hat{i} + v_{b_y} \hat{j} \)[/tex]
- For end D: [tex]\rm \( v_d = v_{d_x} \hat{i} + v_{d_y} \hat{j} \)[/tex]
Since the door's velocity at point B is vertical [tex]\rm (\( v_{b_x} = 0 \))[/tex] and directed upward [tex]\rm (\( v_{b_y} = 1.8 \, \text{ft/s} \))[/tex], we can calculate the angular velocity [tex]\rm (\( \omega \))[/tex] of the door using the relative velocity formula:
[tex]\rm \[ \omega = \frac{{v_b}}{{R}} \][/tex]
Where [tex]\rm \( R \)[/tex] is the distance from point B to the axis of rotation.
Next, to calculate the velocity of end D, we use the following relationship:
[tex]\rm \[ v_d = v_b + \omega \times \vec{r} \][/tex]
Where [tex]\rm \( \vec{r} \)[/tex] is the position vector from point B to point D.
Since [tex]\rm \( \theta = 40^\circ \)[/tex], we can express [tex]\rm \( \vec{r} \)[/tex] as:
[tex]\rm \[ \vec{r} = r \cos(\theta) \hat{i} + r \sin(\theta) \hat{j} \][/tex]
Substituting the values and calculating:
[tex]\rm \[ R = r \cos(\theta) \]\\\\rm \omega = \frac{{v_b}}{{r \cos(\theta)}} \][/tex]
Now, substituting [tex]\rm \( v_b = 1.8 \, \text{ft/s} \), \( \theta = 40^\circ \), and \( r \)[/tex] (distance from B to D) in feet, we can find [tex]\rm \( \omega \)[/tex] and then the velocity [tex]\rm \( v_d \)[/tex].
(Note: Make sure to convert [tex]\rm \( \theta \)[/tex] to radians before plugging it into the equations.)
Let's assume the distance from B to D [tex](\( r \))[/tex] is 5 feet.
[tex]\[ \theta = 40^\circ = \frac{{40}}{{180}} \pi \, \text{radians} \approx 0.698 \pi \, \text{radians} \]\\\ \\R = 5 \cos(0.698 \pi) \approx 2.42 \, \text{ft} \]\\\\ \omega = \frac{{1.8}}{{2.42}} \approx 0.744 \, \text{rad/s} \][/tex]
Now, using [tex]\rm \( \vec{r} = 5 \cos(0.698 \pi) \hat{i} + 5 \sin(0.698 \pi) \hat{j} \)[/tex]:
[tex]\rm \[ v_d = 1.8 \hat{j} + (0.744 \, \text{rad/s}) \times (5 \cos(0.698 \pi) \hat{i} + 5 \sin(0.698 \pi) \hat{j}) \]\\\\\\rm v_d = 1.8 \hat{j} + 0.744 \, \text{rad/s} \times (2.42 \hat{i} + 3.63 \hat{j}) \]\\\ \\\rm v_d = 1.8 \hat{j} + 1.8 \hat{i} + 2.6964 \hat{j} \approx (1.8 + 1.8) \hat{i} + (2.6964) \hat{j} \approx 3.6 \hat{i} + 2.6964 \hat{j} \, \text{ft/s} \][/tex]
So, the angular velocity of the door is [tex]\rm \( 0.744 \, \text{rad/s} \)[/tex], and the velocity of end D is approximately [tex]\rm \( 3.6 \, \text{ft/s} \)[/tex] in the horizontal direction and [tex]\rm \( 2.6964 \, \text{ft/s} \)[/tex] in the upward direction.
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please help on this one?
a is the right answer
C reactant. Both 2C0 and 02 are reactants and 2C02 is the product
What is the gravity between two objects proportional to?
The gravitational force between two objects is proportional to their masses and inversely proportional to the square of the distance between their centers.
as more resistors are added in series to a constant voltage source, the power supplied by the source will decrease. Why?
this is because the resistors cause the energy that is flowing through to go at a slower rate and this helps preserve a battery or power source. also it can be used as a trip for a alarm.
As more resistors are added in series to a constant voltage source, the current drawn from the source decreases, and as a result, the power supplied by the source also decreases, assuming the voltage remains constant.
Let's consider Ohm's Law, which states that the current (I) flowing through a circuit is directly proportional to the voltage (V) and inversely proportional to the resistance (R):
[tex]\[ I = \frac{V}{R} \][/tex]
The power (P) dissipated by a resistor is given by:
[tex]\[ P = I^2R \][/tex]
or, using Ohm's Law to eliminate I:
[tex]\[ P = \left(\frac{V}{R}\right)^2R = \frac{V^2}{R} \][/tex]
When resistors are added in series, the total resistance ([tex]R_total[/tex]) is the sum of the individual resistances:
[tex]\[ R_{total} = R_1 + R_2 + R_3 + \ldots \][/tex]
As [tex]R_total[/tex] increases, the current I decreases according to Ohm's Law. However, the power supplied by the source is not solely determined by the current; it is also influenced by the voltage and resistance.
If we keep the voltage constant and increase the resistance by adding more resistors in series, the power supplied by the source can be calculated using the formula:
[tex]\[ P_{source} = V \times I = V \times \frac{V}{R_{total}} = \frac{V^2}{R_{total}} \][/tex]
As [tex]R_{total}[/tex] increases, the denominator in the power equation increases, which means that the power supplied by the source will decrease if the voltage remains constant.
Sound waves travel through liquids tend to move faster than sound waves traveling through
sound waves travel through liquids tends to move faster than sound waves travelling through air (gases)
As more resistors are added in parallel across a constant voltage source, the power supplied by the sourcea. decreases.b. does not change.c. increases.
Answer:
C. increases
Explanation:
The total resistance of a parallel circuit is given by:
[tex]\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}+...[/tex]
where R1, R2, etc. are the individual resistances.
From the formula, we notice that as new resistors are added to the configuration, the total resistance [tex]R_T[/tex] decreases.
According to Ohm's law, the current flowing in the circuit is inversely proportional to the total resistance:
[tex]I=\frac{V}{R_T}[/tex]
where V is the voltage supplied by the source: so, when adding more resistors in parallel, the total resistance decreases and the current increases.
Finally, the power supplied by the source is
[tex]P=VI[/tex]
we said that V (voltage) remains constant, while I (the current) increases, so the power supplied increases as well.
A positive charge of 3.2 x 10 -5 C is located 0.85 m away from another positive charge of 7.4 x 10 -6 C. What is the electric force between the two charges?
by using Coulumbs Law its 2.95N.
Match the glacier feature with its description.
A. (Kettles) Holes left by glaciers
B.( Drumlins) Egg-shaped hills
C.(Erratics) Three-sided valleys
D.(Cirques) Large, out-of-place boulders
Answer:
kettles: holes left by glaciers.
cirques: three-sided valleys
erratics: large, out-of-place rocks bouldersleft by glaciers.
drumlins: egg-shaped hills
Explanation:
Final answer:
Kettles are holes left by glaciers, drumlins are egg-shaped hills, erratics are large, out-of-place boulders, and cirques are three-sided valleys carved out by glaciers.
Explanation:
A. Kettles are holes left by glaciers. They are formed when a block of ice becomes buried in glacial sediments and then melts, leaving behind a depression or hole.
B. Drumlins are egg-shaped hills, typically found in clusters. They are formed when glaciers deposit sediments in elongated mounds parallel to the flow of the ice.
C. Erratics are large, out-of-place boulders that are transported by glaciers and left behind when the ice melts. They can be found in areas different from the type of rock they are made of.
D. Cirques are three-sided valleys carved out by glaciers. They are typically found at the head of a mountain valley and have steep walls.
Two long parallel wires placed side-by-side on a horizontal table carry identical size currents in opposite directions. The wire on your right carries current toward you, and the wire on your left carries current away from you. From your point of view, the magnetic field at the point exactly midway between the two wires
A) points away from you.
B) is zero.
C) points toward you.
D) points down.
E) points up.
Answer:
D) points down.
Explanation:
The problem can be solved by using the right-hand rule to determine the direction of the magnetic field produced by each wire:
- Thumb: direction of the current in the wire
- The other fingers wrapped around the wire: direction of the magnetic field
So let's apply this rule to both wires:
- Wire on the right:
-- Thumb: direction of current --> toward you
-- Other fingers: direction of magnetic field --> point down (at a point on the left of the wire, which is where we want to determine the total field)
- Wire on the left:
-- Thumb: direction of current -->away from you
-- Other fingers: direction of magnetic field --> point down (at a point on the right of the wire, which is where we want to determine the total field)
So, at the point exactly midway between the two wires, both magnetic fields point down, so when they add together the total field will also point down.
The nucleus of an atom contains positively charged particles, called protons, and neutral particles, called neutrons. How is the nucleus of an atom held together?
Final answer:
The nucleus of an atom, which contains positively charged protons and neutral neutrons, is held together by the strong nuclear force. This force overcomes the repulsive electromagnetic force between protons, allowing the nucleus to remain stable.
Explanation:
The nucleus of an atom is at the center and contains protons and neutrons, known together as nucleons. While the protons carry a positive charge, the neutrons are neutral. The presence of protons with like charges would typically cause them to repel each other due to electromagnetic force. However, protons and neutrons in the nucleus do not fly apart because they are bound together by the strong nuclear force. This is a much stronger force than the electromagnetic force that causes like charges to repel each other and it is the key to keeping the nucleus stable, despite the repulsion between positively charged protons.
Many nuclei contain roughly equal numbers of protons and neutrons, with these nucleons making up most of the atom's mass. The atomic nucleus is incredibly dense and occupies only a tiny portion of the atom's volume, suggesting its strong nuclear forces are short-range but potent within that small space.
It's the strong nuclear force that prevents the nucleus from disintegrating under the repulsive force experienced by the protons. Without this force, the positive protons would indeed repel each other and the atom would not be stable. The strong nuclear force ensures that atoms can exist and form the matter that constitutes the world around us.
True or false? A protostellar cloud spins faster as it contracts
Answer:
No. The protostellar cloud spins faster in the collapsing stage (stage 1) and becomes much slower in the contraction stage (stage 2)
Explanation:
Once the cloud is so dense that the heat which is being produced in its center cannot easily escape, pressure rapidly rises, and catches up with the weight, or whatever external force is causing the cloud to collapse, and the cloud becomes stable, as a protostellar cloud.
The protostellar cloud will become more dense over thousands of years. This stage of decreasing size is known as a contraction, rather than a collapse. In the contraction stage the cloud has become much slower, and because weight and pressure are more or less in balance. In the first stage of formation, the decrease of size is very rapid, and compressive forces completely overwhelm the pressure of the gas, and we say that the cloud is collapsing.
A car is traveling in a race. The car went from the initial velocity of 35 m/s to the final velocity of 65 m/s in 5 seconds. What is the acceleration?
Answer:
6 m/s
Explanation:
edge 2021
A double-slit diffraction pattern is formed on a distant screen. If the separation between the slits decreases, what happens to the distance between interference fringes? Assume the angles involved remain small.
The effect cannot be determined unless the distance between the sits and the screen is known.
The distance between interference fringes increases.
The distance between interference fringes remains the same.
The distance between interference fringes also decreases.
Answer:
The distance between interference fringes increases.
Explanation:
In a double-slit diffraction pattern, the distance of the n-order fringe from the centre of the pattern is
[tex]y=\frac{n \lambda D}{d}[/tex]
where [tex]\lambda[/tex] is the wavelength of the light, D the distance of the screen, and d the separation between the slits.
If we take two adjacent fringes, n and (n+1), their distance is
[tex]\Delta y = \frac{(n+1)\lambda D}{d}-\frac{n\lambda D}{d}=\frac{\lambda D}{d}[/tex]
so, we see that it is inversely proportional to the slit separation, d.
Therefore, if the separation between the slits decreases, the distance between the interference fringes increases.
Why is iron significant to understanding how a supernova occurs?
Iron cannot release energy by fusion.
Explanation;Supernovae are some of the most magnificent events in the cosmos. When a massive star dies, it can result in a spectacular explosion many times that of man's total nuclear arsenal.When a star has used up all the lighter elements and has just iron left, it has no more nuclear "fuel". That causes the star to contract then explode very violently as a supernova.
Substance A has a higher heat capacity than does substance B, and substance B has a higher heat capacity than does substance C. If you add the same amount of heat to all three, which order shows the proper temperature increase for the three substances?
A.
Temperature of C will increase first, then B, then A.
B.
Temperature of A will increase first, then B, then C.
C.
Temperature of B will increase first, then C, then A.
Answer:
A. Temperature of C will increase first, then B, then A.
Explanation:
Heat capacity is the amount of heat required to raise the temperature of one mole of an object by one degree Celsius.
A higher value of heat capacity indicates that higher amount of heat will be required to change the temperature of that substance.
So in the given statement the order of heat capacity is:
A > B > C
So, it will be harder to change the temperature of A(larger amount of heat will be required) as compared to B and C. And between B and C it will be hard to change the temperature of B.
So, if equal amount of heat is supplied, substance C must undergo a temperature change first, then the substance B and substance A in the end.
Therefore, the correct option is:
A. Temperature of C will increase first, then B, then A.
What is the MAIN reason water from the oceans turns to water vapor, and then evaporates into the air?
This has a two word answer: sun's heat. The faster moving molecules near the ocean's surface are provided with enough energy from the sun to escape the surface they are near.
A mass of 50g is attatched with one end of a spring o spring constant 10Nm^-1 whose other end is tied with a wall.Find the period and frequency of its oscillation.
Answer:
T = 0.444 sec
f = 2.25 Hz
Explanation:
Mass of the object = m = 50g = 0.05 kg
Spring constant = k = 10N/m
The time period of mass attached to a spring is calculated as:
[tex]T=2\pi\sqrt{\frac{m}{k} }[/tex]
Using the values in the formula, we get:
[tex]T=2\pi\sqrt{\frac{0.05}{10} }=0.444[/tex]
Thus the time period is 0.444 sec.
Frequency is the reciprocal of the time period.
[tex]f=\frac{1}{T}\\\\ f=\frac{1}{0.444} =2.25[/tex]
Thus the frequency of oscillation is 2.25 Hertz
The period of the oscillations of the mass on the spring is 0.4472 seconds and the frequency is 2.236 Hz. This is calculated using the formula for simple harmonic motion T=2π √(m/k)
Explanation:The question relates to the motion of a mass attached to a spring commonly studied in physics as simple harmonic motion. The period and frequency of the motion can be calculated using the equations of physics that relate to this type of motion. Specifically, these are the equations for the period(T) and frequency(f) of simple harmonic motion:
T = 2π √(m/k)
f = 1/T
The mass (m) 50g needs to be converted to kilograms, so m = 0.05 kg. The spring constant (k) is provided as 10 N/m. Substituting these into the equation for T we get:
T = 2π √(0.05/10) = √(0.01*π*2) = 0.4472 seconds
The frequency of the oscillations is then given by:
f = 1/T = 1/0.4472 = 2.236 Hz
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what is the preception of intensity?
Intensity being the physical parameter that describes the sound signal, sound stimulus, at the basilar membrane that we talked about last time. And, loudness being the perception of the sound signal intensity.
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Final answer:
The perception of sound intensity is known as loudness, measured in phons or more commonly in decibels (dB). Light intensity is perceived as brightness and measured in candelas. The overall perception of sound, including loudness, pitch, and timbre, is processed by the CNS through the encoding of action potentials.
Explanation:
The perception of intensity in sound is commonly referred to as loudness, which is influenced by the physical property of sound wave amplitude. The unit of measurement for loudness is the phon, though more commonly, sound intensity level is measured in decibels (dB). In the case of light, intensity is perceived as luminous intensity or brightness, with the candela as its standard unit. Furthermore, timbre is what distinguishes different sounds at the same pitch and loudness, being influenced by the unique frequencies and intensities produced by an instrument.
The intensity of a stimulus, such as sound, can be encoded in two ways in the nervous system. One is by the rate of action potentials: an intense stimulus generates a rapid train of action potentials. The second method is by the number of receptors activated—the more intense the stimulus, the more receptors stimulated. The Central Nervous System (CNS) integrates these signals, further processing the sensory information into what we perceive.
Light enters air from water. The angle of refraction will be A. less than the angle of incidence. B. greater than or equal to the angle of incidence. C. less than or equal to the angle of incidence. D. equal to the angle of incidence. E. greater than the angle of incidence.
Answer:
E. greater than the angle of incidence.
Explanation:
Snell's law states that:
[tex]n_i sin \theta_i = n_r sin \theta_r[/tex] (1)
where
[tex]n_i, n_r[/tex] are the refractive index of the first and second medium
[tex]\theta_i, \theta_r[/tex] are the angle of incidence and refraction, respectively
For light moving from water to air, we have:
[tex]n_i = 1.33[/tex] (index of refraction of water)
[tex]n_r = 1.00[/tex] (index of refraction of air)
Substituting into (1) and re-arranging the equation, we get
[tex]\sin \theta_r = \frac{n_i}{n_r} sin \theta_i = 1.33 sin \theta_i[/tex]
which means that
[tex]\theta_r > \theta_i[/tex]
so, the correct answer is
E. greater than the angle of incidence.
Light enters air from water. The angle of refraction will be
A. less than the angle of incidence. B. greater than or equal to the angle of incidence. C. less than or equal to the angle of incidence. D. equal to the angle of incidence. E. greater than the angle of incidence.Further explanationRefractive Index is the value that calculated from the speed of light ratio in a vacuum to in a second medium of greater density. The refractive index variable is symbolized by the letter [tex]n[/tex] or [tex]n'[/tex] in descriptive text and mathematical equations.
Light enters air from water, the angle of refraction will be greater than the angle of incidence.
When light passed from a less dense to a more dense substance for example passing from air into water, the light is refracted towards the normal. The normal is a line perpendicular (forming a 90 degree angle) to the boundary between the two substances.
Hope it helps!
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Grade: 9
Subject: physics
Chapter: refraction
Keywords: The angle of refraction, the angle of incidence
A 20.0 μf capacitor is charged to a potential difference of 850 v. the terminals of the charged capacitor are then connected to those of an uncharged 12.0 μf capacitor. (a) compute the original charge of the system. (b) compute the final potential difference across capacitor. (c) compute the final energy of the system. (d) compute the decrease in energy when the capacitors are connected.
All four values are in 3 sig. fig.
Explanation(a)
[tex]Q = C\cdot V = 20.0\times 10^{-6} \times 850\;\text{V} = 1.70\times 10^{-2}\;\text{J}[/tex].
(b)
Sum of the final charge on the two capacitors should be the same as the sum of the initial charge. Voltage of the two capacitors should be the same. That is:
[tex]C_1\cdot V_\text{final} +C_2 \cdot V_\text{final} = C_1\cdot V_\text{initial}[/tex];
[tex](C_1+C_2)\cdot V_\text{final} = C_1\cdot V_\text{initial}[/tex];
[tex]\displaystyle V_\text{final} = \frac{C_1}{C_1+C_2}\cdot V_\text{initial}\\\phantom{V_\text{final}} = \frac{20.0\;\mu\text{F}}{20.0\;\mu\text{F} + 12.0\;\mu\text{F}} \times 850\;\text{V}\\\phantom{V_\text{final}} =531\;\text{V}[/tex].
(c)
[tex]\displaystyle E = \frac{1}{2}\cdot C\cdot V^{2}[/tex].
[tex]\displaystyle E_\text{final} = \frac{1}{2} (C_1 + C_2) \cdot {V_\text{final}}^{2} \\\phantom{E_\text{final}} = \frac{1}{2} \times (20.0\times 10^{-6} + 12.0\times 10^{-6}) \times 531.25\\\phantom{E_\text{final}} = 4.52\;\text{J}[/tex].
(d)
Initial energy of the system, which is the same as the initial energy in the [tex]20.0\;\mu\text{F}[/tex] capacitor:
[tex]\displaystyle E_\text{initial} = \frac{1}{2} \times 20.0\times 10^{-6} \times 850^{2} = 7.225\;\text{J}[/tex].
Change in energy:
[tex]\Delta E = 7.225\;\text{J} - 4.516\;\text{J} = 2.70\;\text{J}[/tex].
The properties of the capacitors can be calculated the answers are:
a) Q₁ = 1.70 10-2 C
b) V_f = 531 V
c) U_f = 4.52 J
d) ΔU = 2.71 J
Given parameters
The capacitance C₁ = 20.0 10⁻⁶ F and C₂ = 12.0 10⁻⁶ F The initial potential deference V1 = 850 VTo find
a) The initial charge
b) The potential difference of the system connected capacitors
c) The final energy of the system
d) the energy change when connecting the capacitors
A capacitor is a system formed by two separate parallel plates that serves to store electrical charge,
Q = C V
Where Q is the stored charge, C the capacitance and V the potential difference
a) ask for the initial charge
Q₀ = C₁ V₀
Q₀ = 20.0 10⁻⁶ 850
Q₀ = 1.70 10⁻² C
b) The law of conservation of charge establishes that the electric charge cannot be created or destroyed, therefore the initial charge (Q₀) must be distributed between the two connected capacitors
Q₀ = [tex]Q_{1f} + Q_{2f}[/tex]
C₁ V₀ = C₁ [tex]V_{1f}[/tex] + C₂ [tex]V_{2f}[/tex]
the Power Difference final between the two capacitors must be the same, parallel connection
C₁ V₀ = (C₁ + C₂) [tex]V_f[/tex]
[tex]V_f[/tex] = [tex]\frac{C_1}{C_1+C_2} \ V_o[/tex]
V_f = [tex]\frac{20}{20+12} \ 850[/tex]
V_f = 531.25 V
c) The stored energy capacitor is
U = ½ C V²
The final energy system is
U = ½ (C₁ + C₂) [tex]V_f^2[/tex]
U = ½ (20 + 12) 10⁻⁶ 531.25²
U = 4.516 J
d) To calculate the energy change
ΔU = U₀ - [tex]U_f[/tex]
let's look for the initial energy
U₀ = ½ C₁ V₀²
U₀ = ½ 20 10⁻⁶ 850²
U₀ = 7.225 J
whereby the energy change is
ΔU = 7.225 - 4.516
ΔU = 2.71 J
In conclusion using the properties of the capacitors we were able to calculate the answers are:
a) Q₁ = 1.70 10-2 C
b) V_f = 531 V
c) U_f = 4.52 J
d) ΔU = 2.71 J
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As more lamps are put into a series circuit, the overall current in the circuit a. Increasesb. Decreasesc. Remains the same
Answer:
b. Decreases
Explanation:
The total resistance of a series circuit is equal to the sum of the individual resistances:
[tex]R_T=R_1+R_2+...+R_n[/tex] (1)
Therefore, as we add more lamps, the total resistance increases (because we add more positive tems in the sum in eq.(1).
The current in a circuit is given by Ohm's law:
[tex]I=\frac{V}{R_T}[/tex]
where V is the voltage provided by the power source and [tex]R_T[/tex] is the total resistance. We notice that the current, I, is inversely proportional to the total resistance: therefore, when more lamps are added to the series circuit, the total resistance increases, and therefore the current in the circuit decreases.
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A student suspends an object from a spring scale. A spring scale measures the weight of an object. The student records the weight. The student then submerges the object in water and observes that the spring shows a smaller weight than when the object was out of the water. The student then submerges the object in motor oil, vegetable oil, milk, and gasoline and observes the reading on the scale.
The independent variable in this experiment is the:
the weight read on the spring scale
the type of liquid in which the object was submerged
the size of the object
the amount of liquid in which the object was submerged
I would say it would be the weight read.
Only because the Control is the type of liquid and the constants are Size of object and amount of liquid
Answer:
the amount of liquid in which the object was submerged
Explanation:
As we know that spring balance will read the spring force that is exerted by spring on the object
Now when the object is suspended by the spring then in that case the spring force is balanced by the weight so spring will read the correct mass of the object.
Now the object is suspended by the spring and then submerged into the liquid so in that case we can say
[tex]F_{spring} + F_b = mg[/tex]
[tex]F_{spring} = mg - \rho_{liquid}Vg[/tex]
so here the reading will be less and it depends on volume of object and density of liquid
so independent variable will be
the amount of liquid in which the object was submerged
Why are there temperature differences on the moon's surface even though there is no atmosphere present?
The lack of an atmosphere means convection cannot happen on the moon. Therefore, there is no form of heat dissipation on regions in direct sunlight. In addition, the lack of an atmosphere means there is no greenhouse effect on the moon. This is why regions facing away from sunlight are very cold.
The moon's low gravity prevents it from retaining an atmosphere, which leads to drastic temperature changes due to the lack of an insulating layer of gases. Moreover the moon's surface's porous nature allows it to cool more rapidly than solid rock, contributing to the temperature extremes.
Explanation:The primary reason for the large temperature differences on the moon's surface, despite the absence of an atmosphere, is related to the moon's gravity, surface composition, and the radiation from the Sun.
The moon has about one-sixth Earth's surface gravity. This is too low to retain an atmosphere. Gaseous molecules can easily escape from the moon into space, leaving it without an atmosphere. This means that there is no layer of gases to absorb and redistribute the Sun's energy, leading to extreme temperature fluctuations.
The fact that the moon's surface is also predominantly made up of lunar soil (also known as lunar regolith), which is porous and cools more rapidly than solid rock, aids in these temperature extremes. During lunar daytime when the Sun is high in the sky, the temperature can rise above the boiling point of water. However during the long lunar night, the temperature drops dramatically to approximately 100 K (-173 °C).
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If the temperature of an iron sphere is increased a. Its mass will decreaseb. Its density will increasec. Its density will decreased. Its density will remain unchanged
a. Its mass will decreaseb.
What wavelength of light contains enough energy in a single photon to ionize a hydrogen atom?
There's probably a much quicker, easier way to do it, but I don't work with this stuff every day so this is the way I have to do it:
First, I searched the "ionization energy" of Hydrogen on Floogle. That's how much work it takes to rip the one electron away from its Hydrogen atom, and it's 13.6 eV (electron-volts).
In order to find the frequency/wavelength of a photon with that energy, I need the energy in units of Joules.
1 eV = 1.602 x 10⁻¹⁹ Joule (also from Floogle)
13.6 eV = 2.179 x 10⁻¹⁸ Joule
OK. Now we can use the popular well-known formula for the energy of a photon:
Energy = h · (frequency)
or Energy = h · (light speed/wavelength)
' h ' is Max Planck's konstant ... 6.626 × 10⁻³⁴ m²-kg / s
Wow ! The only thing we don't know in this equation is the wavelength, which is what we need to find. That's gonna be a piece-o'-cake now, because we know the energy, we know ' h ', and we know the speed of light.
Wavelength = h · c / energy
Wavelength =
(6.626 x 10⁻³⁴ m²-kg/sec) · (3 x 10⁸ m/s) / (2.179 x 10⁻¹⁸ joule)
Wavelength = 9.117 x 10⁻⁸ meter
That's 91.1 nanometers .
It's not visible light (visible is between about 390 to 780 nm), but it's not as short as I was expecting. I thought it was going to be an X-ray, but it's not that short. X-rays are defined as 0.1 to 10 nanometers. This result is in the short end of Ultra-violet.
(You have no idea how happy I am with this result. I figured it out exactly the way I showed you, and I never peeked. Then, AFTER I had my solution, I went to Floogle and searched to see what it really is, and whether I came out anywhere close. I found it in the article on the "Lyman Series". It says the wavelength of the energy released by an electron that falls in from infinity and settles in the n=1 energy level of Hydrogen is 91.175 nm ! This gives me a big hoo-hah for the day, and I'm going to bed now.)
Wavelength of the light is about 9.14 × 10⁻⁸ m
[tex]\texttt{ }[/tex]
Further explanationThe term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is :
[tex]\large {\boxed {E = h \times f}}[/tex]
E = Energi of A Photon ( Joule )
h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )
f = Frequency of Eletromagnetic Wave ( Hz )
[tex]\texttt{ }[/tex]
The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.
[tex]\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}[/tex]
[tex]\large {\boxed {E = qV + \Phi}}[/tex]
E = Energi of A Photon ( Joule )
m = Mass of an Electron ( kg )
v = Electron Release Speed ( m/s )
Ф = Work Function of Metal ( Joule )
q = Charge of an Electron ( Coulomb )
V = Stopping Potential ( Volt )
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
energy of photon = E = 13.6 eV = 2.176 × 10⁻¹⁸ Joule
Unknown:
wavelength of light = λ = ?
Solution:
[tex]E = h \times \frac{c}{\lambda}[/tex]
[tex]2.176 \times 10^{-18} = 6.63 \times 10^{-34} \times \frac{3 \times 10^8}{\lambda}[/tex]
[tex]2.176 \times 10^{-18} = 1.989 \times 10^{-25} \div \lambda[/tex]
[tex]\lambda = (1.989 \times 10^{-25}) \div (2.176 \times 10^{-18})[/tex]
[tex]\lambda \approx 9.14 \times 10^{-8} \texttt{ m}[/tex]
[tex]\texttt{ }[/tex]
Learn morePhotoelectric Effect : https://brainly.com/question/1408276Statements about the Photoelectric Effect : https://brainly.com/question/9260704Rutherford model and Photoelecric Effect : https://brainly.com/question/1458544[tex]\texttt{ }[/tex]
Answer detailsGrade: College
Subject: Physics
Chapter: Quantum Physics
[tex]\texttt{ }[/tex]
Keywords: Quantum , Physics , Photoelectric , Effect , Threshold , Wavelength , Stopping , Potential , Copper , Surface , Ultraviolet , Light
There is a current of 0.99 a through a light bulb when its connected to a 9.7 v battery what is the resistance of the light bulb
Ohm's law states that V=IR, where V=voltage, I=current(amps), and R=resistance (in Ohms).
Plugging the values into the above equation yields a resistance in the light bulb of 9.8 ohms
Which of the following sets of characteristics describes the image formed by a plane mirror?A. Virtual and invertedB. Real and uprightC. Virtual and uprightD. Real and invertedE. All the previous statements can be correct
A plane mirror is a highly polished flat surface with a very high capacity to reflect incident light.
We can understand in a better way how this works with the figure attached:
1. The incident rays coming from the real object reach the mirror and
2.are reflected following the law of Reflection.
3.The prolongation of those reflected rays converge at a point that does not coincide with the actual position of the object. At that point the virtual image of the object is formed.
4.Then, the reflected divergent rays are captured by our eye converging on the retina.
Now, the image is said to be virtual because it is a copy of the object that looks as if the object is behind the mirror and not in front of it or on the surface, but it is not really there. However, it can be seen when we focus it with our eyes.
In addition, the image formed is:
symmetrical, because apparently it is at the same distance from the mirror
the same size as the object.
upright, because it retains the same orientation as the object.
what is ohm law form?
Answer:
[tex]V=RI[/tex]
Explanation:
Ohm's law states the relationship between voltage, resistance and current in an electrical circuit containing passive elements only:
[tex]V=RI[/tex]
where
V is the voltage supplied by the battery
R is the resistance of the circuit
I is the current
From the equation, we see that the voltage, V, is directly proportional to the current in the circuit, I.
Ohm's Law is the mathematical relationship among electric current, resistance, and voltage. The principle is named after the German scientist Georg Simon Ohm. In direct-current (DC) circuits, Ohm's Law is simple and linear. Suppose a resistance having a value of R ohm s carries a current of I ampere s.
A 1000-kg car is slowly picking up speed as it goes around a horizontal curve whose radius is 100 m. The coefficient of static friction between the tires and the road is 0.350. At what speed will the car begin to skid sideways?
Answer:
18.5 m/s
Explanation:
On a horizontal curve, the frictional force provides the centripetal force that keeps the car in circular motion:
[tex]\mu mg = m\frac{v^2}{r}[/tex]
where
[tex]\mu[/tex] is the coefficient of static friction between the tires and the road
m is the mass of the car
g is the gravitational acceleration
v is the speed of the car
r is the radius of the curve
Re-arranging the equation,
[tex]v=\sqrt{\mu gr}[/tex]
And by substituting the data of the problem, we find the speed at which the car begins to skid:
[tex]v=\sqrt{(0.350)(9.8 m/s^2)(100 m)}=18.5 m/s[/tex]
The car will begin to skid sideways at 18.5 m/s
[tex]\texttt{ }[/tex]
Further explanationCentripetal Acceleration can be formulated as follows:
[tex]\large {\boxed {a = \frac{ v^2 } { R } }[/tex]
a = Centripetal Acceleration ( m/s² )
v = Tangential Speed of Particle ( m/s )
R = Radius of Circular Motion ( m )
[tex]\texttt{ }[/tex]
Centripetal Force can be formulated as follows:
[tex]\large {\boxed {F = m \frac{ v^2 } { R } }[/tex]
F = Centripetal Force ( m/s² )
m = mass of Particle ( kg )
v = Tangential Speed of Particle ( m/s )
R = Radius of Circular Motion ( m )
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
mass of car = m = 1000 kg
radius of curve = R = 100 m
coefficient of static friction = μ = 0.350
Asked:
speed of the car = v = ?
Solution:
We will derive the formula to calculate the maximum speed of the car:
[tex]\Sigma F = ma[/tex]
[tex]f = m \frac{v^2}{R}[/tex]
[tex]\mu N = m \frac{v^2}{R}[/tex]
[tex]\mu m g = m \frac{v^2}{R}[/tex]
[tex]\mu g = \frac{v^2}{R}[/tex]
[tex]v^2 = \mu g R[/tex]
[tex]\boxed {v = \sqrt { \mu g R } }[/tex]
[tex]v = \sqrt { 0.350 \times 9.8 \times 100 }[/tex]
[tex]v = \sqrt { 343 }[/tex]
[tex]v = 7 \sqrt{7} \texttt{ m/s}[/tex]
[tex]\boxed {v \approx 18.5 \texttt{ m/s}}[/tex]
[tex]\texttt{ }[/tex]
Learn moreImpacts of Gravity : https://brainly.com/question/5330244Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454The Acceleration Due To Gravity : https://brainly.com/question/4189441[tex]\texttt{ }[/tex]
Answer detailsGrade: High School
Subject: Physics
Chapter: Circular Motion
Which statement correctly describes the movement of thermal energy according to the second law of thermodynamics? The natural tendency of systems is for heat to flow from a cooler object to a warmer one. The natural tendency of systems is to evenly distribute energy until the objects are the same temperature. The natural tendency of systems is for heat to flow continuously between objects of the same temperature.
Your answer is B) The natural tendency of systems is to evenly distribute energy until the objects are the same temperature.
Answer:
The correct answer is:
The natural tendency of systems is to evenly distribute energy until the objects are the same.
Explanation:
Thermal equilibrium
When ever two bodies differing in temperatures comes in contact with each other heat flow takes place from hotter body to cooler body in order to establish an equilibrium in which temperature of both the bodies becomes constant.
According to second law of thermodynamics:
When the energy of the system increases, matter moves more freely and change in entropy that is disorderliness of the system increases.
This increase in entropy is due to the energy possessed by the matter particles which has resulted in their motion or movement
With this increase in entropy of system, system will start interacting with its surroundings .And this interaction will results in evenly distribution of energy in its surroundings.
One of the harmonics of a column of air in a tube that is open at one end and closed at the other has a frequency of 448 Hz, and the next higher harmonic has a frequency of 576 Hz. How long is the tube? The speed of sound in air is 343 m/s. One of the harmonics of a column of air in a tube that is open at one end and closed at the other has a frequency of 448 Hz, and the next higher harmonic has a frequency of 576 Hz. How long is the tube? The speed of sound in air is 343 m/s. 1.00 m 2.68 m 1.34 m 0.335 m 0.670 m
Answer:
1.34 m
Explanation:
For an open-end tube, the frequency difference between two consecutive harmonics is equal to the fundamental frequency of the tube:
[tex]f_1 = f_{n+1}-f_n[/tex]
In this case, we have
[tex]f_{n+1}=576 Hz\\f_n = 448 Hz[/tex]
so, the fundamental frequency is
[tex]f_1=576 Hz-448 Hz= 128 Hz[/tex]
For an open-end tube, the fundamental frequency is also given by:
[tex]f_1 = \frac{v}{2L}[/tex]
where v is the speed of sound and L the length of the tube.
Since we know v = 343 m/s, we can solve the formula for L:
[tex]L=\frac{v}{2f_1}=\frac{343 m/s}{2(128 Hz)}=1.34 m[/tex]
Final answer:
To find the length of the tube, we can use the formula v = fλ, where v is the speed of sound and f is the frequency. By calculating the wavelength for the fundamental frequency and the second harmonic, we can determine the length of the tube. In this case, the length of the tube is approximately 0.595 m.
Explanation:
To determine the length of the tube, we need to find the wavelength of each harmonic. The fundamental frequency corresponds to the first harmonic, so its wavelength is twice the length of the tube. The second harmonic has a wavelength equal to the length of the tube. Using the formula v = fλ, where v is the speed of sound and f is the frequency, we can solve for the length of the tube.
For the fundamental frequency:
v = fλ
λ = v/f
Substituting the values:
λ = (343 m/s) / 448 Hz
For the second harmonic:
λ = (343 m/s) / 576 Hz
Since the wavelength of the second harmonic is equal to the length of the tube, we can solve for the length:
Length = λ = (343 m/s) / 576 Hz
Substituting the values:
Length = (343 m/s) / (576 Hz)
Calculating the length:
Length = 0.595 m
Therefore, the length of the tube is approximately 0.595 m.