Ann increased the quantities of all the ingredients in a recipe by 60\%60%60, percent. She used 808080 grams (\text{g})(g)left parenthesis, start text, g, end text, right parenthesis of cheese. How much cheese did the recipe require?

Answer:

3d + 4p = $37.25

5d + 2p = $38.75

Actual Answer:

Bag of popcorn is $5

A drink is $5.75

Step-by-step explanation:

Let drinks = d

Let popcorn = p

Noah: 3d + 4p = $37.25

Other: 5d + 2p = $38.75

Choose a variable to eliminate (We'll choose p)

3d + 4p = $37.25

(5d + 2p = $38.75) -2

Distribute

-10d - 4p = -77.5

The -4p cancels out the 4p, then we combine

-7d = -40.25

Divide both sides by -7

-7d/-7 = -40.25/-7

d = 5.75

Back to 3d + 4p = $37.25

Substitute d with 5.75

3(5.75) + 4p = $37.25

17.25 + 4p = 37.25

Move the constant to the other side

17.25 + 4p = 37.25

-17.25           -17.25

4p = 20

Divide both sides by 4

4p/4 = 20/4

p = 5

Answer:

  $6

Step-by-step explanation:

Susan can easily figure the tip by the following procedure. 10% of the bill is the amount with the decimal point moved one place to the left, so is $4.00. 5% of the bill is half that, or $2.00.

15% of the bill is 10% + 5%, so is $4.00 +2.00 = $6.00. The tip will be $6.00.

Answer:

The in equality representing the number of can school can collect each day is [tex]500+5x\geq 3000[/tex].

Eddy MS school has to collect at least 500 cans in each day.

Step-by-step explanation:

Number of cans Eddy has = 500

Number of days left = 5

Target to achieve = 3000

Let number of cans which can be collected in each day be 'x'.

Now we know that;

Number of can he has plus number of can which can be collected in each day multiplied with number of days left should be greater than or equal to 3000

Framing in equation form we get;

[tex]500+5x\geq 3000[/tex]

Hence, The in equality representing the number of can school can collect each day is [tex]500+5x\geq 3000[/tex].

Solving the same we get;

[tex]500+5x\geq 3000[/tex].

Subtracting Both side with 500 using Subtraction property for Inequality we get;

[tex]500+5x-500\geq 3000-500\\\\5x\geq 2500[/tex]

Now Dividing both side by 5 using Division property of Inequality we get;

[tex]\frac{5x}{5}\geq\frac{2500}{5}\\\\x\geq 500[/tex]

Hence Eddy MS school has to collect at least 500 cans in each day.

Answer:

Xmin = π/3 and Xmax = 7π/3

Step-by-step explanation:

I assume that the function is:

y = 5 + 3 cos² (x − π/3)

cos² x has a period of π, so to graph two periods, you need a domain that is 2π wide, so:

Xmax − Xmin = 2π

You can choose any values you want for Xmax and Xmin, so long as they are 2π units apart.  To make it easy to graph, you'll probably want to choose Xmin = π/3 and Xmax = 7π/3.

Graph:

desmos.com/calculator/9w3pptakde

Answer:

[tex](x,y) - (x + 4, y-3)[/tex]

Step-by-step explanation:

Given:

A triangle is drawn on the coordinate plane. It is translated 4 units right and 3 units down.

It is translated 4 units right and 3 units down.

We need to find the rule of translation.

Solution:

Now to the right of the axis which is positive of X axis and 4 units to the right means 4 units are added to X co-ordinate.

Also to the Down of the axis which is negative of Y axis and 3 units to the down means 3 units are Subtracted to Y co-ordinate.

Hence The co-ordinates at which triangle is drawn is [tex](x + 4, y-3)[/tex]

Answer:

The apples cost $3.82 per pounds.

Step-by-step explanation:

We are given the following in the question:

Cost of grapes = $2.45 per pd

Total money spent = $15

Total purchasing = 2 lbs of apples and 3 lbs of grapes

Total cost of grapes =

[tex]=\text{Cost of grapes}\times \text{Amount of grapes}\\= 2.45\times 3 = 7.35\$[/tex]

Total cost of apples =

[tex]\text{Total cost} - \text{Total cost of grapes}\\= 15 - 7.35 = 7.65\$[/tex]

Cost of apple =

[tex]= \dfrac{\text{Total cost of apple}}{\text{Amount of apple}}\\\\= \dfrac{7.65}{2} = 3.825\$\text{ per pound}[/tex]

Thus, the apples cost $3.82 per pounds.

Answer: one pound of apple costs $3.825

Step-by-step explanation:

Let x represent the cost of one pound of apple.

Total amount spent on 2 lbs of apple and 3 lbs of grapes is $15

The grapes cost $2.45 per pound. This means that the total cost of 3 lbs of grapes would be

2.45 × 3 = $7.35

Since Cindy spent a total of $15, it means that

2x + 7.35 = 15

Subtracting 7.35 from both sides of the equation, it becomes

2x + 7.35 - 7.35 = 15 - 7.35

2x = 7.65

x = 7.65/2 = $3.825

Answer:

31 hours

Step-by-step explanation:

June and Stella can create 6 floral arrangements in one hour.

They take in 372 Valentine's Day order

No of hours = orders / (June's rate + Stella's rate)

June's rate = 6 arrangements / hour

Stella's rate = 6 arrangements / hour

June's rate + Stella's rate = 2(6 arrangements /hour)

= 12 arrangements / hour

No of hours = 372 arrangements / 12 arrangements / hour

= 31 hours

June and Stella have 31 hours to fulfill the 372 Valentine's Day order

Answer: The total number of tickets that John sold is 27

Step-by-step explanation:

Let x represent the number of adult tickets that John sold at the concert.

Let y represent the number of children's tickets that John sold at the concert.

Adult tickets cost $6.50 and children's tickets cost $4.50. John collects a total of 157.50 from the ticket sales it means that

6.5x + 4.5y = 157.5 - - - - - - - - - -1

John sells twice as many adult tickets as children's tickets. This means that

x = 2y

Substituting x = 2y into equation 1, it becomes

6.5 × 2y + 4.5y = 157.5

13y + 4.5x = 157.5

17.5y = 157.5

y = 157.5/17.5 = 9

x = 2×9 = 18

The total number of tickets that John sold is 9 + 18 = 27

Answer:

ali's solution is incorrect

9y+y is the same as 9y+1y

9y^2 is the same as 9y x y

9y+y simplifies to 10y.

Step-by-step explanation:

Answer:

The Middle One which says 9Y2 is the same as 9y . 2y

Step-by-step explanation:

Answer:

Option B.

Step-by-step explanation:

Given information:

Σ(x − M) = 44

where, M is mean.

Sample size = 12

The computational formula for sample variance is

[tex]s^2=\dfrac{\sum (x-M)^2}{N-1}[/tex]

where, M is sample mean and N is sample size.

Substitute Σ(x − M) = 44 and N=12 in the above formula.

[tex]s^2=\dfrac{44}{12-1}[/tex]

[tex]s^2=\dfrac{44}{11}[/tex]

[tex]s^2=4.0[/tex]

The sample variance is 4.0.

Therefore, the correct option is B.

Answer:

  11.2 ft

Step-by-step explanation:

Assuming the building meets the ground at right angles, the right triangle formed has side length 10 ft and hypotenuse 15 ft. Then the other side length (d) is given by the Pythagorean theorem as ...

  d² + 10² = 15²

  d² = 225 -100 = 125

  d = √125 = 5√5 ≈ 11.2 . . . feet

The bottom of the ladder is about 11.2 feet from the building

Answer:

O dono deverá gastar 1764 reais

Step-by-step explanation:

Oi!

Em anexo, você encontrará a figura do apartamento que encontrei na web.

Para encontrar a superfície do tapete que o proprietário precisa comprar, precisamos encontrar a superfície do dormitório e da sala.

Superfície do dormitório:

A superfície do dormitório é calculada multiplicando a base pela altura do retângulo.

Da figura:

base = 3,5 m

altura = 3 m

Superfície do tapete do dormitório = 3,5 m · 3 m = 10,5 m²

A superfície da sala de estar é a superfície do retângulo composto pela sala e pelo banheiro menos a superfície do banheiro:

superfície da sala de estar = superfície do retângulo sala / banheiro - superfície do banheiro

Superfície do banheiro:

Conhecemos um lado do banheiro: 2 m

O outro lado será:

lado do banheiro = 9 m - 3,5 m - 3,5 m = 2 m

Então, a superfície do banheiro será:

Superfície do banheiro = 2 m · 2 m = 4 m²

Superfície da sala / banheiro

A altura do retângulo é (3 m + 2,5 m) 5,5 m

A base do retângulo é (9 m - 3,5 m) 5,5 m

Então, a superfície da sala / banheiro é (5,5 m) ² = 30,25 m²

Superfície da sala

A superfície da sala será igual à superfície da sala / banheiro menos a superfície do banheiro:

Superficie da sala = 30,25 m² - 4 m² = 26,25 m²

A superfície do tapete será (26,25 m² + 10,5 m²) 36,75 m²

Como cada metro quadrado custa  $ 48, o proprietário terá que gastar

(48 reais / m² · 36,75 m²) 1764 reais.

Tenha um bom dia!

Answer:

We conclude that the steel has an average hardness index of at least 64.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 64

Sample mean, [tex]\bar{x}[/tex] = 62

Sample size, n = 50

Alpha, α = 0.051

Sample standard deviation, s = 8

First, we design the null and the alternate hypothesis

[tex]H_{0}: \mu = 64\\H_A: \mu < 64[/tex]

We use one-tailed(left) z test to perform this hypothesis.

Formula:

[tex]z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }[/tex]

Putting all the values, we have

[tex]z_{stat} = \displaystyle\frac{62 - 64}{\frac{8}{\sqrt{50}} } = -1.767[/tex]

Now, [tex]z_{critical} \text{ at 0.05 level of significance } = -2.33[/tex]

Since,  

[tex]z_{stat} > z_{critical}[/tex]

We fail to reject the null hypothesis and accept the null hypothesis. Thus, we conclude that the steel has an average hardness index of at least 64.

This means that there is not enough evidence to support the claim that the average hardness index is less than 64.

To test the manufacturer's claim, we can conduct a one-sample z-test. The null hypothesis  is that the average hardness index is 64, and the alternative hypothesis  is that the average hardness index is less than 64.

 Given:

First, we calculate the standard error (SE) of the mean:

[tex]\[ SE = \frac{\sigma}{\sqrt{n}} = \frac{8}{\sqrt{50}} \approx 1.1314 \][/tex]

 Next, we calculate the test statistic (z):

[tex]\[ z = \frac{\bar{x} - \mu_0}{SE} = \frac{62 - 64}{1.1314} \approx -1.7679 \][/tex]

 Now, we need to find the critical z-value for a one-tailed test at the 1% significance level.

From the standard normal distribution table, the critical z-value for the 99th percentile is approximately 2.326.

 Since the calculated z-value (-1.7679) is greater than the critical z-value (-2.326), we fail to reject the null hypothesis.

This means that there is not enough evidence to support the claim that the average hardness index is less than 64.

Answer:

The direct variation equation can be given as:

[tex]y=6x[/tex]

Step-by-step explanation:

Given:

At a summer camp there are 6 campers under one counselor.

To find the direct variation equation for the number of campers in terms of number of counselor.

Solution:

[tex]y\rightarrow[/tex] Number of campers

[tex]x\rightarrow[/tex] Number of counselors

We have [tex]y[/tex] ∝ [tex]x[/tex]

The direct variation equation can be written as:

[tex]y=kx[/tex]

where [tex]k[/tex] is the direct variation constant.

There are 6 campers under one counselor. Using this statement we can find value of [tex]k[/tex]

Given: when [tex]x=1[/tex] then [tex]y=6[/tex]

We have,

[tex]6=k(1)[/tex]

∴ [tex]k=6[/tex]

Thus, the direct variation equation can be given as:

[tex]y=6x[/tex]

We can find the points using the equation to plot.

[tex]x[/tex]              [tex]y=6x[/tex]

0                      0

1                       6

2                     12

The graph is sown below.

Answer:

We conclude that the mean lifetime of a brand of fluorescent bulbs is equal to 1500 hours.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 1500 hours

Sample mean, [tex]\bar{x}[/tex] = 1480 hours

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 80 hours

First, we design the null and the alternate hypothesis

[tex]H_{0}: \mu = 1500\text{ hours}\\H_A: \mu < 1500\text{ hours}[/tex]

We use one-tailed(left) t test to perform this hypothesis.

Formula:

[tex]t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }[/tex]

Putting all the values, we have

[tex]t_{stat} = \displaystyle\frac{1480-1500}{\frac{80}{\sqrt{25}}}= -1.25[/tex]

Now,

[tex]t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.71[/tex]

Since,                    

[tex]t_{stat} > t_{critical}[/tex]

We fail to reject the null hypothesis and accept the null hypothesis.

We conclude that the mean lifetime of a brand of fluorescent bulbs is equal to 1500 hours.

After performing a one-sample t-test, the calculated t value of -1.25 does not exceed the critical value of -1.711 at the 0.05 significance level. Therefore, we do not have sufficient evidence to support the claim that the mean lifetime of the bulbs is less than 1500 hours.

The question asks to test the claim that the mean lifetime of a certain brand of fluorescent bulbs is less than 1500 hours. To test this at the 0.05 significance level, we would perform a one-sample t-test since the sample size is less than 30, and we do not know the population standard deviation.

First, we formulate our null hypothesis (H0) as the mean lifetime of the bulbs being 1500 hours or more, and the alternative hypothesis (Ha) being the mean lifetime less than 1500 hours.

Next, we calculate the test statistic using the sample mean, population mean, standard deviation, and sample size:

[tex]t = (Sample Mean - Population Mean) / (Standard Deviation / \sqrt(Sample Size))[/tex]

[tex]= (1480 - 1500) / (80 / \sqrt(25))[/tex]

  = -20 / (80 / 5)

  = -20 / 16

  = -1.25

Then, we check this t value against the t-distribution table for 24 degrees of freedom (df = n - 1) at the 0.05 significance level. The critical value for a one-tailed test with df = 24 at alpha = 0.05 is approximately -1.711. Since our calculated t value of -1.25 is not less than -1.711, we do not reject the null hypothesis.

Conclusion: At the 0.05 significance level, we do not have sufficient evidence to support the consumer's claim that the mean lifetime of the bulbs is less than 1500 hours.

Answer:1 2 34 6

Step-by-step explanation:

Just answered it

Answer:

1,2,3,4,6

Step-by-step explanation:

Edge 2021

Answer:

25%.

Step-by-step explanation:

We have been given that at the end of the day, February 14th, a florist had 120 roses left in his shop, all of which were red, white or pink in color and either long or short-stemmed.

We are also told that 1/3 of the roses were short-stemmed.

[tex]\text{Short-stemmed roses}=120\times \frac{1}{3}=40[/tex]

Since 20 of those were white and 15 of which were pink, so short stemmed red roses would be [tex]40-(20+15)=40-35=5[/tex].

Now, we will find number of long-stemmed roses by subtracting number of short-stemmed roses from total roses as:

[tex]\text{Long-stemmed roses}=120-40=80[/tex]

We are also told that none of the long-stemmed roses were white, so total number of white roses would be [tex]20+0=20[/tex].

Let p represent the number of total pink roses.

Now, total number of red roses would be total roses (120) minus total pink roses (p) minus total white roses (20).

[tex]\text{Total red roses}=120-p-20[/tex]

[tex]\text{Total red roses}=100-p[/tex]

We have been given that the percentage of pink roses that were short-stemmed equaled the percentage of red roses that were short-stemmed. We can represent this information in an equation as:

[tex]\frac{\text{Short-stemmed pink roses}}{\text{Total pink roses}}=\frac{\text{Short-stemmed red roses}}{\text{Total red roses}}[/tex]

[tex]\frac{15}{p}=\frac{5}{100-p}[/tex]

Let us solve for p by cross-multiplication:

[tex]1500-15p=5p[/tex]

[tex]1500-15p+15p=5p+15p[/tex]

[tex]1500=20p[/tex]

[tex]20p=1500[/tex]

[tex]\frac{20p}{20}=\frac{1500}{20}[/tex]

[tex]p=75[/tex]

Since total number of pink roses is 75, so total number of red roses would be [tex]100-75=25[/tex].

We already figured it out that 5 roses are short-stemmed, so long-stemmed roses would be [tex]25-5=20[/tex].

Now, we have long stemmed roses is equal to 20 and total long-stemmed roses is equal to 80.

Let us find 20 is what percent of 80.

[tex]\text{Percentage of the long-stemmed roses that were red}=\frac{20}{80}\times 100[/tex]

[tex]\text{Percentage of the long-stemmed roses that were red}=\frac{1}{4}\times 100[/tex]

[tex]\text{Percentage of the long-stemmed roses that were red}=25[/tex]

Therefore, 25% of the long-stemmed roses were red.

Final answer:

The 'month' variable referenced by the café owner is a categorical variable used to group revenue data across different time periods within a year.

Explanation:

In the context of the café owner's situation, the type of variable that 'month' represents is a categorical variable. A categorical variable is one that has two or more category values and can be used to group or label individuals or items in a dataset. In this case, 'month' is used as a means to categorize the revenue data collected over different time periods within a year, allowing the café owner to compare the performance of latte sales across these distinct categories.

Answer:

The answer to your question is None of the answers is correct

Step-by-step explanation:

                                            [tex]3x - \frac{1}{5} = 10[/tex]

Solve for x

                                            [tex]3x = 10 + \frac{1}{5}[/tex]

                                            [tex]3x = \frac{50 + 1}{5}[/tex]

                                            [tex]3x = \frac{51}{5}[/tex]

                                            [tex][tex]x = \frac{17}{5} [/tex]x = \frac{51}{(3)(5)}[/tex]

                                            [tex]x = \frac{17}{5}[/tex]

Answer: $375,000

Step-by-step explanation:

Given : The subject property is a four-bedroom, two-bath, two-car-garage home in a new subdivision.

Comp A is a three-bedroom, two-bath home with a screened-in porch that sold for $365,500.

I.e. It has one less bedroom and one extra porch .

i.e. It requires to add one bedroom and remove screened-in porch .

Since ,The appraiser values the porch at $12,500 and estimates the bedroom adjustment at $22,000.

So , the A's adjusted sale price would become

Selling price of Comp A  + Value of bedroom - Value of  porch

= $365,500 + $22,000- $12,500

= $375,000

Hence, A's adjusted sale price= $375,000

Answer:

14.

Center = (-7,4)

Radius = 7

15.  189 square yards

16.  84 square inches

Step-by-step explanation:

14.

The standard form of a circle is given as:

[tex](x-h)^2 + (y-k)^2 = r^2[/tex]

Where

(h,k) is the center

and

r is the radius of the circle

Given, the circle equation in this problem as:

[tex](x+7)^2+(y-4)^2=49[/tex]

We re arrange this:

[tex](x-(-7))^2+(y-(4))^2=7^2[/tex]

Now, we clearly see that the center is (-7,4)  and  the radius is 7

Hence,

Center = (-7,4)

Radius = 7

15.

For simplicity, let the point at DE, where it makes the right angle, be the point "H".

DEF is the triangle.

So, we see now that:

DE = 21 yd

FH = 18 yd

DE is the base of the triangle and FH is the height of the triangle.

The area of a triangle is:

Area = 0.5 * base * height

So, we now find the area to be:

Area = 0.5 * 21 * 18 = 189 square yards

16.

Rhombus is a quadrilateral (figure with 4 sides) whose 4 sides have equal length.

The diagonal is the length from one corner to the opposite corner. So, a rhombus has 2 diagonals.

The area of the rhombus, in terms of diagonals, would be:

Area = (Diagonal1 * Diagonal2)/2

So, we multiply the 2 diagonal's length and divide the answer by 2.

We have:

Diagonal 1 = 12

Diagonal 2 = 14

Hence, area would be:

Area = (12*14)/2 = 84 square inches

Answer:

Sally bought 4 pounds of Strawberries and 3 pounds of Cantaloupes.

Step-by-step explanation:

Let the number of pounds of Strawberries bought by Sally = x

Let the number of pounds of Cantaloupes bought by Sally = y

[tex]\[x + y = 7\][/tex]  ---------------------------------(1)

Moreover,

[tex]\[2.5 x + 2.25 y = 16.75\][/tex] ---------------(2)

Solving (1) and (2) by substitution:

[tex]\[x = 7 - y\][/tex]

=> [tex]\[2.5 *(7-y) + 2.25 y = 16.75\][/tex]

=> [tex]\[17.5 - 2.5y + 2.25 y = 16.75\][/tex]

=> [tex]\[0.25y = 0.75\][/tex]

=> [tex]\[y = 3\][/tex]

From (1), x = 7-3 = 4

Explanation:

Let L be the length and W be the width.

We have only 2 sides are fenced

         Fencing = 2L + W

Fencing = 18 m

          2L + W = 18

           W = 18 - 2L

We need to find what is the largest area that can be enclosed.

     Area = Length x Width

      A = LW

       A = L x (18-2L) = 18 L - 2L²

For maximum area differential is zero

So we have

      dA = 0

      18 - 4 L = 0

        L = 4.5 m

      W = 18 - 2 x 4.5 = 9 m

Area = 9 x 4.5 = 40.5 m² = 81/2 m²

Option E is the correct answer.

Answer:

Number of students who prefer chocolate ice cream is approximately 713.

Step-by-step explanation:

Given,

Total number of students = 950

Students who prefer chocolate ice cream = 75%

We have to find out number of students who prefer chocolate ice cream.

For calculating number of students who prefer chocolate ice cream, we have to multiply total number of students with given percentile of students.

Now framing the above sentence in equation form, we get;

Number of students who prefer chocolate ice cream = [tex]950\times75\%[/tex]

Now we have to remove the percentile.

For this we have to divide 75 by 100, we get;

Number of students who prefer chocolate ice cream =[tex]950\times\frac{75}{100}=\frac{71250}{100}=712.50\approx713[/tex]

Hence Number of students who prefer chocolate ice cream is approximately 713.

Answer:

14

Step-by-step explanation:

Ordinarily, a quick multiplication of 7 by other integers up to 10 indicates that only 7*9 yields 63, i.e ends with 3 as required.

Thus the set of possible multiples of the integer 7 ending with the digit 3 will form the arithmetic series with the first term being Ao = 63 and the common difference being d= 7*10= 70. That is we can see the series in details....

the nth term could be evaluated from the formular

An=Ao+(n-1)d        (1)

The series could be explicitly depicted as follows:

       9*7=63= 63+70*0

(10+9)*7=133 = 63+70*1

(20+9)*7=203=63+70*2

(30+9)*7=273=63+70*3

.................................

(130+9)*7=973=63+70*13

The last 'n' corresponding to the problem statement could be evaluated from equation (1), assuming An=1000:

1000=63+(n-1)*70

1000-63=70(n-1)

937/70=13.38=n-1

n=14.38

Thus the number of possible multiples of 7 less than 1000 ending with digit 3 will be 14.

Check: 7 times 142 is 994, so there are exactly 142 positive multiples of 7 less than 1000.

One tenth of these, ignoring the decimal fraction, end with a digit of 3.

Answer:

Explanation:

The function that represents the number of E.coli bacteria cells per 100 mL of water as the time t years elapses is:

The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function:

Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.

Answer:

a)  25  feet

b)  Base width   23.57  feet

Step-by-step explanation: The expression:

h(x)  =  -0,18*x²  +  25

is a quadratic function ( a parable). as  a < 1   open down

The vertex of the parable is V(x,y)

a) V(x)  =  - b/2a    =  0/2a    V(x)  = 0    to find   V(y) we make use of the original equation and plugging  x = 0

y = - 0.18*x²  +  25    ⇒  y  =  0 + 25      ⇒  y  = 25

The  Vertex is  V  (  0 , 25 )

Now vertex in this case is the maximum height.

h(max)  =  25  feet

b) To find how wide is the base of the tunnel. We have to consider that for  h   = 0  we are at ground level therefore the two roots of the quadratic equation will give the wide of the base of the tunnel

Then

h (x)  =  -018*x² +25     ⇒  0  =   -018*x² +25      ⇒ x²   =  25/0.18

x²  =  138.89

x  =  ±   11.79  ft

So we found interception with  x axis   and wide of the base is

2 *  11.79    =  23.57   feet

Answer:

For isometric drawings, these are true :

II. Circles are drawn as ellipses and not as exact circles.

III. Horizontal lines are drawn at 30° angles above the horizontal.

V. Vertical lines are drawn at 90° angles above the horizontal.

Step-by-step explanation:

Now,

An isometric drawing allows the designer to draw an object in three dimensions. Isometric drawings are also called isometric projections. This type of drawing is often used by engineers and illustrators that specialize in technical drawings.

For example, when an engineer has an idea for a new product, he or she will probably create a sketch to show a client or investor. And chances are, the sketch will be an isometric drawing.

In isometric projections, horizontal lines are drawn at 30° to the original horizontal, where as vertical lines are remained unchanged.

Even though horizontal lines are at 30°. the measurements of length does not change. so, the circle look like an ellipse.

⇒ The true statements are:

 II. Circles are drawn as ellipses and not as exact circles.

III. Horizontal lines are drawn at 30° angles above the horizontal.

V. Vertical lines are drawn at 90° angles above the horizontal.

In an isometric drawing, circles are represented as ellipses (II), the horizontal lines are commonly drawn at 30° angles above the horizontal (III), and the vertical lines are drawn at 90° angles above the horizontal (V).

From the given list, statements II, III, and V about isometric drawings of solid objects are true. II. In isometric drawings, circles are not drawn as exact circles but are instead represented as ellipses. This is due to the three-dimensional perspective presented in isometric drawings making the circle appear distorted. III. Horizontal lines in isometric drawings are commonly drawn at 30° angles above the horizontal line that forms part of the axonometric grid. This provides a consistent upward inclination for all lines sketched or perceived as horizontal in the actual object. V. Vertical lines are drawn at 90° angles above the horizontal. In isometric projections, just like in any form, the vertical lines always maintain the same 90° angle with respect to ground regardless of the viewpoint.

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Answer: $75

Step-by-step explanation:

Since Terry is paid once a month and earns $36000 in a year,

a year = 12 months

To get the amount he is paid in a month we simply divide the $36000 by 12

$36000 / 12 = $3000

In a month he is paid $3000

Now to get the pay raise;

since the pay raise is 2.5 %, we will find 2.5% of $3000

2.5/100 × $3000 = 2.5 × $30 =$75

There Terry receive an increase of $75 in a month