April works at the grocery store. She needs to move a heavy crate of bananas (m = 65 kg) to the produce section. She drags the crate along the floor by applying a force of 280 N at an angle of 35° above the horizontal.

a. If there is no friction, what is the acceleration of the crate? (5 points)
280/65=4.3
b. If the coefficient of kinetic friction between the crate and the floor is 0.4, what is the acceleration of the crate? (5 points)

Answer:

a) I = 0.363 kg*[tex]m^{2}[/tex]

b) [tex]I_{T}[/tex] = 0.82385 kg*[tex]m^{2}[/tex]

Explanation:

a) If we approximate the skater how a cylinder his moment of inertia is:

I = [tex]\frac{mr^{2} }{2}[/tex]

I = [tex]\frac{(60)(0.110)^{2} }{2}[/tex]

I = 0.363 kg*[tex]m^{2}[/tex]

b)  If the skater has his arms extended then:

[tex]I_{T} = I_{B} + I_{A}[/tex]

       where   [tex]I_{B}[/tex]: Body’s moment of inertia

                     [tex]I_{A}[/tex]: Moment of inertia of the arms

[tex]I_{B}[/tex] = [tex]\frac{mr^{2} }{2}[/tex]

[tex]I_{B}[/tex] = [tex]\frac{(52.5)(0.110)^{2} }{2}[/tex] = 0.3176 kg*[tex]m^{2}[/tex]

[tex]I_{A}[/tex] = 2 * [tex]\frac{mL^{2} }{12}[/tex]

[tex]I_{A}[/tex] = 2 * [tex]\frac{(3.75)(0.9)^{2} }{12}[/tex] = 0.50625 kg*[tex]m^{2}[/tex]

[tex]I_{T}[/tex]  = 0.3176 + 0.50625 = 0.82385 kg*[tex]m^{2}[/tex]

The moment of inertia for a skater can be calculated using the mass and radius in the formula for the moment of inertia of a cylinder. If the skater extends their arms, the moment of inertia increases, and this is calculated by adding the moment of inertia of the skater to the moments of inertia of the arms.

The moment of inertia of a body is a measure of its resistance to rotational motion. It depends on the mass and how that mass is distributed relative to the axis of rotation. In the case of the skater (approximated as a cylinder), you calculate this using the formula for the moment of inertia of a cylinder, which is I=0.5MR², where M is the mass and R is the radius.

(a) For the skater without extended arms, substitute the given mass (60 kg) and radius (0.11 m) into the formula to get: I = 0.5 * 60 kg * (0.11 m)² = 0.363 kg-m².

(b) For the skater with extended arms, first, calculate the skater's body moment of inertia as before, but now with 52.5 kg mass. Secondly, calculate the moment of inertia of each arm (approximated as a rod rotating about one end) with the formula I=1/3mL², where m is the mass of an arm and L is the length. Add those values to get the total moment of inertia.

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Answer:

354 cm³

Explanation:

Step 1: calculate the density of PEG 400

[tex]Specific gravity({\gamma}) = \frac{density of liquid (\rho _{l})}{density of water (\rho_{w})}[/tex]

[tex]1.13=\frac{\rho _{l}}{1(\frac{g}{m^3})}[/tex]

[tex]{\rho _{l}[/tex] = 1.13X1 = 1.13 [tex]\frac{g}{cm^3}[/tex]

Step 2:

Molecular weight of PEG 400 = 400g/mol

Step 3: calculate the volume of PEG 400 to be measured

[tex]Volume _{PEG 400} =\frac{mass of _{PEG 400}}{density of _{PEG 400}}[/tex]

[tex]Volume _{PEG 400}=\frac{400}{1.13}(cm^3)[/tex]

                                       = 353.98 cm³

                                       ≅354 cm³

353.4 cm³ volume should be measured for the preparation.

Given:

Specific gravity=1.13

To find:

Volume=?

Specific gravity is the ratio of the density (mass of a unit volume) of a substance to the density of a given reference material, often a liquid.

On substituting the values, we will get:

[tex]\text{Density of liquid}=1.13*1=1.13 gcm^{-3}[/tex]

Molecular weight of PEG 400 =400g/mol

Now, we have the values of density and mass thus volume can be calculated easily:

The density of a substance is its mass per unit volume.

[tex]\text{Volume}=\frac{\text{mass}}{\text{density}}=\frac{400}{1.13} \\\\\text{Volume}=353.4 cm^{3}[/tex]

353.4 cm³ volume should be measured for the preparation.

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Answer:

D. Graphing the force as a function of distance and calculating the area under the curve.

Explanation:

Answer:

The correct option is (D). "Graphing the force as a function of distance and calculating the area under the curve"

Explanation:

1) As we know from the definition of Work done which is Work = Force × Displacement. Time doesn't have any use in the mentioned equation and thus the stop watch is of no use to us.

2) Using the meter stick, we can measure the distance for which the block is pulled horizontally i.e "Displacement"

3) Using the spring scale, we can calculate the "Force" applied on the block of wood to move it horizontally.

4) For example, lets say that for a constant force of 4 Newtons, the wooden block is pulled horizontally 4 meters. Plotting Force vs Displacement on a graph would yield a horizontal line as shown in the attachment. Area under the F vs D graph will give us the total work done.

Answer:

d=1.49×1011m

Explanation:

Velocity is defined as the rate of travel, and can be found using the distance formula.

velocity=distancetime

Rearranging this formula we can solve for distance given velocity and time of travel.

d=vt

We are given velocity and time, and so can solve for distance, but if we plug in the values given;

d=(3.00×108m/s)(8.3minutes)

We can see that the units do not match up. Since seconds are the SI unit for time, we will need to convert 8.3 minutes to seconds.

t=(8.3minutes)(60seconds/minute)=(498s)

Now our units work out and we can solve for distance.

= 15.85

(8.3 min)/(1 AU) = (T)/(1.52 AU)

(8.3 min)x(1.52 AU) = (T x 1 AU)

T = (8.3 min x 1.52 AU) / (1 AU)

T = 12.62 minutes

Final answer:

The speed of sound in the metal is 444.44 m/s.

Explanation:

To determine the speed of sound in the metal, we can use the information given and the speed of sound in air. The pulse traveling through the metal arrives 9ms earlier than the pulse traveling through air. From this, we can calculate the time difference it takes for the pulses to travel through the length of the metal bar. The speed of sound in air is given as 343 m/s. We can use the formula: speed = distance/time. Rearranging the formula, we have: time = distance/speed. As the distance is given as 4.00 m and the time difference is given as 9 ms (0.009 s), we can calculate the speed of sound in the metal by dividing the distance by the time difference: speed = 4.00 m / 0.009 s = 444.44 m/s.

Answer:

B. increasing the temperature of the atmosphere

Explanation:

Generally, atmospheric loss can be defined as the loss of the gases in the atmosphere to outer space. This process usually occur through either thermal escape or non-thermal escape. Atmospheric loss of gases to outer space by thermal escape occurs when the molecular velocity due to thermal energy is considerably high. One of the factors that can lead to increase in thermal energy and ultimately increase in atmospheric loss is increase in the temperature of the atmosphere. Therefore, the correct answer is option B.

Answer:

[tex]v_{f}[/tex] = 0  miles/h

Explanation:

This exercise should be resolved with the moment. The system is formed by the two cars. Let's write the moment

Initial. Before the crash

           p₀ = m v₁ - m v₂

The sign is because they go in the opposite direction

Final. After the crash

          [tex]p_{f}[/tex] = (m + m) [tex]v_{f}[/tex]

The moment is preserved

         p₀ = [tex]p_{f}[/tex]

         m v₁- m v₂ = 2m [tex]v_{f}[/tex]

         [tex]v_{f}[/tex] = m / 2m (v₁-v₂)

But the speed of the cars is the same v1 = v2 = 50 liters / h

       [tex]v_{f}[/tex] = 0

so the two faces do not move after the crash

Answer:

+ 3.0 m

Explanation:

displacement is shortest distance from fixed point O in particular direction . in diagram shortest distance at end from O is 3 m and it is right of O so +. HENCE +3.0m

Answer:

I = 1.21x10^-5 A

Explanation:

You are missing the first part of the problem. This is an example, but it will give you the idea of how to solve yours with your data.

The first part is like this:

A      4.0 cm  diameter parallel plate capacitor has a  0.44 m  m    gap. What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000 V/s?

Now with this, we can solve the problem.

In order to do this, we need to use the following expression:

q = CV (1)

Where:

C: Capacitance of a parellel capacitor (in Faraday)

q: charge of plate or capacitor (In coulombs)

V: voltage in Volts.

However, we need is the current, and we have data of potential difference, so, all we have to do is divide the expression between time so:

q/t = CV/t

And the current is q/t, thus:

I = C * V/t (2)

And finally, Capacitance C with two plates of area A separated by a distance d is:

C = Eo*A/d (3)

Where:

Eo = constant equals to 8.85x10^-12 F/m.

A = Area of the plate, in this case, πr²

d = gap of the capacitor.

Let's calculate first the Capacitance using equation (3):

C = 8.85x10^-12 * π * (0.04/2)² / 0.00046 = 2.42x10^-11 F

Now, it's time to use equation (2) and solve for I:

I = 2.42x10^-11 * 500,000

I = 1.21x10^-5 A

Final answer:

The question pertains to the rotational kinetic energy of a rolling spherical object with non-uniform density and how it compares to the total kinetic energy using its moment of inertia.

Explanation:

The student is asking about the rotational kinetic energy of a spherical object with non-uniform density in comparison to its total kinetic energy. The given moment of inertia for the object is 0.59 M R2, where M is the mass, and R is the radius of the sphere. Using the formula for rotational kinetic energy, Krot = (1/2) I ω2, and the formula for translational kinetic energy, Ktrans = (1/2) m v2, we can find the energy components. However, because the spherical object rolls without slipping, there is a relationship between linear velocity (v) and angular velocity (ω) which is v = ωR. This allows us to compare the rotational kinetic energy to the total kinetic energy.

Answer:E)Valley Fever;meningitis

Explanation:Valley fever is a a fungal lung infection while the meningitis is a viral or bacterial disease that affect the meninges.

The second player is 91 meters far from the first player.

Why?

First, let be the +y the North, so, to solve the problem we can use the following formula:

[tex]y=yo+v_o*t+\frac{1}{2}*a*t[/tex]

Now, subsituting the given information, we have(assuming that the speed is constant):

\\\\y-yo=13\frac{m}{s}*7s+\frac{1}{2}*0*7s\\\\y-yo=91m\\\\distance=91m[/tex]

Hence, we have that the second player is 91m far from the first player.

Have a nice day!

Answer:

188.7 m

Explanation:

height of bridge above water (h) = 393 m

mass of bungee jumper (m) = 150 kg

length of cord (L) = 78 m

acceleration due to gravity (g) = 9.8 m/s  

initial energy = mgh = 150 x 9.8 x 393 = 577,710 J

since the jumper barely touches the water, the maximum extension of the cord (x) = 393 - 78 = 315 m

from the conservation of energy mgh = [tex](\frac{1}{2})kx^{2}[/tex]

therefore

577,710 = [tex](\frac{1}{2})kx315^{2}[/tex]

k = 11.64 N/m

from Hooke's law, force (f) = kx' ⇒ mg = kx'

where x' is the extension of the cord when it comes to rest

150 x 9.8 = 11.64 × x'

x' = 126.3 m

the final height at which the cord comes to a rest = height of the bridge - length of the cord - extension of the cord when it comes to rest

the final height at which the cord comes to a rest = 393  - 78 - 126.3 = 188.7 m

The rate of change of the volume of the cone at the specified instant is approximately [tex]\(6.03 \times 10^{9} \pi\)[/tex] cubic centimeters per second.

To find the rate of change of the volume of the cone, you can use the formula for the volume of a cone:

[tex]\[V = \frac{1}{3}\pi r^2 h\][/tex]

Where:

- V is the volume of the cone.

- r is the radius of the cone.

- h is the height of the cone.

You are given that the radius is increasing at a rate of 333 cm/s (dr/dt = 333 cm/s) and the height is decreasing at a rate of 444 cm/s (dh/dt = -444 cm/s). At a certain instant, the radius is 888 cm (r = 888 cm) and the height is 101010 cm (h = 101010 cm).

To find the rate of change of the volume (dV/dt) at that instant, you can use the product rule for differentiation:

[tex]\[ \frac{dV}{dt} = \frac{1}{3} \pi \left(2rh\frac{dr}{dt} + r^2\frac{dh}{dt}\right) \][/tex]

Now, plug in the values:

[tex]\[ \frac{dV}{dt} = \frac{1}{3} \pi \left(2(888 cm)(101010 cm)(333 cm/s) + (888 cm)^2(-444 cm/s)\right) \][/tex]

Calculate:

[tex]\[ \frac{dV}{dt} = \frac{1}{3} \pi \left(5910088880 cm^3/s + (-157593984 cm^3/s)\right) \][/tex]

Now, simplify:

[tex]\[ \frac{dV}{dt} = \frac{1}{3} \pi \cdot 5752494896 cm^3/s \][/tex]

[tex]\[ \frac{dV}{dt} \approx 6.03 \times 10^{9} \pi \; cm^3/s \][/tex]

So, the rate of change of the volume of the cone at that instant is approximately [tex]\(6.03 \times 10^{9} \pi\)[/tex] cubic centimeters per second.

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Answer:

A = 2 cm ,   λ = 8 cm

Explanation:

The amplitude of a wave is the maximum height it has, in this case the height is measured by the vertical ruler,

We are told the balance point is in the reading of 5 cm, that the maximum reading is 3 cm and the Minimum reading is 7 cm. Therefore, the distance from the ends of the ridge to the point of equilibrium is

          d = 7-5 = 2 cm

          d = 5-3 = 2 cm

          A = 2 cm

The wavelength is the minimum horizontal distance for which the wave is repeated, that is measured by the horizontal ruler.

The initial reading for 4 cm and the final reading for 8 cm, this distance corresponds to a crest of the wave, the complete wave is formed by two crests whereby the wavelength is twice this value

          Δx = 8-4 = 4 cm

          λ = 2 Δx

          λ = 8 cm

The amplitude of the wave is approximately [tex]2cm[/tex], measured from the equilibrium to the crest or trough. The wavelength of the wave is approximately [tex]8cm[/tex].

To determine the wavelength and amplitude of the given wave, we need to analyze the provided measurements.

The crest rises from the equilibrium position of [tex]5 cm `[/tex] to just before [tex]3 cm[/tex] , giving an amplitude measurement of approximately [tex]2 cm (5 cm - 3 cm)[/tex] .

Similarly, the trough falls from the equilibrium of [tex]5 cm[/tex] to just before [tex]7 cm[/tex], again giving a vertical displacement of approximately [tex]2 cm (7 cm - 5 cm)[/tex].

The horizontal distance from the start of the first crest to the start of the next crest should be measured. According to the provided data, the first crest aligns from [tex]0[/tex]  to just under [tex]4 cm[/tex] , and the next crest starts just under [tex]8 cm[/tex].

The wavelength is the horizontal distance covering one complete cycle, measuring just less than [tex]8 cm[/tex]. Therefore, the wavelength is approximately [tex]8 cm[/tex] .

Hence,

Final answer:

To determine how long it takes for the flywheel to come to a stop, calculate the angular acceleration using the torque and moment of inertia. Then, use the angular acceleration to find the time.

Explanation:

To determine how long it takes for the flywheel to come to a stop, we need to calculate the angular acceleration first. To do this, we can use the formula:

α = τ / I

Where α is the angular acceleration, τ is the torque, and I is the moment of inertia. The torque can be calculated using the formula:

τ = rF

Where r is the radius of the flywheel and F is the force exerted on it. Once we have the angular acceleration, we can use it to find the time it takes for the flywheel to come to a stop using the formula:

t = ω / α

Where t is the time, ω is the initial angular velocity, and α is the angular acceleration.

The ratio of the low temperature to the high temperature in the Carnot engine, given that the real engine's efficiency is 55% of a Carnot engine's efficiency, is calculated to be 0.3535.

The question involves thermodynamics and specifically deals with the operation and efficiency of a Carnot engine.

The given heat engine absorbs 450 J of heat from the high-temperature reservoir and expels 290 J to the low-temperature reservoir. The efficiency (efficiency) of this engine is given as 55% of a Carnot engine's efficiency. Using the first law of thermodynamics, wecan calculate the work done (W) by the engine:

W = Qh - Qc = 450 J - 290 J = 160 J.

The efficiency of the engine is the ratio of the work done to the heat absorbed:

efficiency = W / Qh = 160 J / 450 J = 0.3556, or 35.56%.

Now, the efficiency of a Carnot engine is defined as:

efficiencyCarnot = 1 - (Tc / Th).

The problem states that the engine's efficiency is 55% of a Carnot engine's efficiency, which means:

0.3556 = 0.55 * efficiencyCarnot

From this equation, we can solve for efficiencyCarnot and then use it to calculate the ratio of the low temperature to the high temperature in the Carnot engine:

efficiencyCarnot = 0.3556 / 0.55

efficiencyCarnot = 0.6465, or 64.65%

Thus:

0.6465 = 1 - (Tc / Th)

Tc / Th = 1 - 0.6465 = 0.3535.

Therefore, the ratio of the low temperature to the high temperature in the Carnot engine is 0.3535.

The ratio of the low temperature to the high temperature in the Carnot engine is  [tex]\( \frac{1}{3} \)[/tex].

The correct ratio of the low temperature to the high temperature in the Carnot engine is given by:

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = 1 - \frac{W_{\text{actual}}}{Q_{\text{in}}} \cdot \frac{1}{\eta_{\text{Carnot}}} \][/tex]

where [tex]\( W_{\text{actual}} \)[/tex] is the work done by the actual engine, [tex]\( Q_{\text{in}} \)[/tex] is the heat absorbed from the high-temperature reservoir, and [tex]\( \eta_{\text{Carnot}} \)[/tex]  is the efficiency of the Carnot engine.

First, we calculate the actual efficiency of the given heat engine using the provided values:

[tex]\[ W_{\text{actual}} = Q_{\text{in}} - Q_{\text{out}} \][/tex]

[tex]\[ W_{\text{actual}} = 450 \, \text{J} - 290 \, \text{J} \][/tex]

[tex]\[ W_{\text{actual}} = 160 \, \text{J} \][/tex]

The actual efficiency [tex]\( \eta_{\text{actual}} \)[/tex] is then:

[tex]\[ \eta_{\text{actual}} = \frac{W_{\text{actual}}}{Q_{\text{in}}} \][/tex]

[tex]\[ \eta_{\text{actual}} = \frac{160 \, \text{J}}{450 \, \text{J}} \][/tex]

[tex]\[ \eta_{\text{actual}} = \frac{16}{45} \][/tex]

Given that the efficiency of the actual engine is 55% of the efficiency of a Carnot engine operating between the same two temperatures, we can write:

[tex]\[ \eta_{\text{actual}} = 0.55 \cdot \eta_{\text{Carnot}} \][/tex]

The efficiency of a Carnot engine is given by:

[tex]\[ \eta_{\text{Carnot}} = 1 - \frac{T_{\text{low}}}{T_{\text{high}}} \][/tex]

Combining the two equations, we get:

[tex]\[ \frac{16}{45} = 0.55 \left( 1 - \frac{T_{\text{low}}}{T_{\text{high}}} \right) \][/tex]

Solving for [tex]\( \frac{T_{\text{low}}}{T_{\text{high}}} \)[/tex]:

[tex]\[ \frac{16}{45} = 0.55 - 0.55 \cdot \frac{T_{\text{low}}}{T_{\text{high}}} \][/tex]

[tex]\[ 0.55 \cdot \frac{T_{\text{low}}}{T_{\text{high}}} = 0.55 - \frac{16}{45} \][/tex]

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = \frac{0.55 - \frac{16}{45}}{0.55} \][/tex]

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = \frac{0.55 \cdot \frac{45}{45} - \frac{16}{45}}{0.55} \][/tex]

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = \frac{\frac{24.75}{45} - \frac{16}{45}}{0.55} \][/tex]

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = \frac{\frac{8.75}{45}}{0.55} \][/tex]

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = \frac{8.75}{45 \cdot 0.55} \][/tex]

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = \frac{8.75}{24.75} \][/tex]

[tex]\[ \frac{T_{\text{low}}}{T_{\text{high}}} = \frac{1}{3} \][/tex]

Answer:

The number of bright fringes per unit width on the screen is, [tex]x=\dfrac{\lambda D}{d}[/tex]      

Explanation:

If d is the separation between slits, D is the distance between the slit and the screen and [tex]\lambda[/tex] is the wavelength of the light. Let x is the  number of bright fringes per unit width on the screen is given by :

[tex]x=\dfrac{n\lambda D}{d}[/tex]

[tex]\lambda[/tex] is the wavelength

n is the order

If n = 1,

[tex]x=\dfrac{\lambda D}{d}[/tex]

So, the the number of bright fringes per unit width on the screen is [tex]\dfrac{\lambda D}{d}[/tex]. Hence, the correct option is (B).

Final answer:

The number of bright fringes per unit width in a Young's double-slit experiment is given by the reciprocal of the fringe spacing, which is d/(Dλ), corresponding to answer choice E.

Explanation:

In a Young's double-slit experiment, to find the number of bright fringes per unit width on the screen, we consider the separation between the slits (d), the distance from the slits to the screen (D), and the wavelength of light used (λ). The distance between adjacent bright fringes, or fringe spacing, is given by Δy = Dλ/d. From this relation, the number of bright fringes per unit width can be obtained by taking the reciprocal of the fringe spacing, which implies 1/Δy = d/(Dλ).

Therefore, the correct formula to calculate the number of bright fringes per unit width on the screen is the reciprocal of Δy, which is d/(Dλ), matching answer choice E.

Answer:

option D

Explanation:

given,

uniform length of cylinder = 1 m

diameter of the cylinder = 10 cm = 0.1 m

Eels have been recorded to spin = 14 rev/s

camera records at = 120 frames per second

time = [tex]\dfrac{1}{120}\ s/frame[/tex]

angle at which eel rotate = ?

ω = 14 rev/s

ω = 14 x 2 π rad/s

ω = 28 π rad/s

angle at which eel rotate

 θ = ω t

θ = [tex]28\pi\times \dfrac{1}{120}[/tex]

θ = 0.733 rad

θ =[tex]0.733 \times \dfrac{180^0}{2\pi}[/tex]

θ =[tex]42^0[/tex]

Hence, the correct answer is option D

The angle of rotation is the angle at which the object is rotate about the fixed point.

The angle at which the eel rotates from one frame to next frame is 42 degree.

Given that, we can treat the eel as a uniform cylinder.

So, uniform length of cylinder = 1 [tex]\rm m[/tex]  and diameter of the cylinder = 10 [tex]\rm cm[/tex] = 0.1 [tex]\rm m[/tex]. Eels have been recorded to spin at up to 14 rev/s when feeding in this way. The camera records at 120 frames per second.

Time taken by the camera to record one frame is [tex]t\;=\; \dfrac {1} {120} \;\rm s/\rm frame[/tex]

Revolution done by eel in radian per second is 14.

Angular Velocity is  [tex]\omega\;=\; 14\;\times\;2\pi\;\times\;0.1\;\rm rad/s[/tex].

The angle of rotation can be calculated by the formula given below.

Angle of rotation   [tex]\theta=\omega\;\times\;t[/tex].

Substituting the values in the above formula, the angle of rotation is,

[tex]\theta\;=\;14\;\times\;2\;\times\;3.14\;\times\;0.1\;\times\;\dfrac {1}{120}\;\rm rad[/tex]

 [tex]\theta=0.0733\;\rm rad[/tex]

[tex]\theta=0.0733\;\times\;\dfrac {360^\circ}{2\pi}[/tex]

[tex]\theta=41.5^\circ[/tex] or [tex]42^\circ[/tex].

The angle at which the eel rotates from one frame to next frame is 42 degree.

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Answer:

Electrolytes are considered ions when placed in a solution and allow for adequate conduction of particle charges.

Explanation:

Electrolytes are substances that, when are dissolved in solution, separates into electrical positive charges (cations) and electrical negative charges (anions) which are known as ions.

These ions have an adequate capacity to conduct particle charges and, therefore electricity.

Sodium, calcium, phosphate and potassium, are examples of electrolytes.  

Hence, the correct answer is:

Electrolytes are considered ions when placed in a solution and allow for adequate conduction of particle charges.

I hope it helps you!

Answer:C. 10N

Explanation:

The applied force needed to maintain a constant velocity is 10N. This is because the moving force acting on the body will always be equal to the frictional force if the velocity of the body is constant.

But note that this is not the case if the body ia accelerating. If the body is accelerating then the frictional force will not be able to overcome the moving force acting on the body and such the moving force will be greater than the frictional force in that regards.

The applied force needed to maintain a constant velocity is 10 N.

The given parameters;

The net horizontal force on the object is calculated by applying Newton's second law of motion as shown below;

∑F = ma

[tex]F- F_k = ma[/tex]

where;

At constant velocity, the acceleration of the object is zero.

[tex]F-F_k = m(0)\\\\F-F_k = 0\\\\F= F_k\\\\F = 10 \ N[/tex]

Thus, the applied force needed to maintain a constant velocity is 10 N.

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Answer:

d) kinetic energy transformed to mechanical energy

Explanation:

Wind energy comes from its movement, so kinetic energy

         Em = K = ½ m v²2

This energy spins the mill aspadle that this movement of the rotor within a magnetic field creates electricity in accordance with Faraday's law.

Consequently, from the above we should make a graph of the wind speed (kinetic energy) according to the electricity produced

The correct answer is d

kinetic energy transformed to mechanical energy this best completes the chart. Hence option D is correct.

Kinetic energy is the energy associated with a motion of a body. When a body is in motion having mass m then it has kinetic energy. Kinetic energy is denoted by K or T. it is expressed in joules. Kinetic energy is given by,

K = 1/2 mv²

Hence an object having zero mass or zero velocity have zero kinetic energy.

In line with Faraday's law, when the mill asp rotates under the influence of this energy, electricity is generated.

In light of the foregoing, we should create a graph showing the wind speed (kinetic energy) in relation to the power generated.

To know more about Kinetic Energy :

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Answer:

1000 mph

Explanation:

P = Perimeter = 24000 mi

r = Radius of the equator

t = Time taken to complete one rotation = 24 h

Perimeter of a circle is given by

[tex]P=2\pi r\\\Rightarrow r=\dfrac{P}{2\pi}\\\Rightarrow r=\dfrac{24000}{2\pi}\ mi[/tex]

Angular speed is given by

[tex]\omega=\dfrac{2\pi}{t}\\\Rightarrow \omega=\dfrac{2\pi}{24}[/tex]

Velocity if given by

[tex]v=r\omega\\\Rightarrow v=\dfrac{24000}{2\pi}\times \dfrac{2\pi}{24}\\\Rightarrow v=1000\ mph[/tex]

The person would be going at a speed of 1000 mph

Explanation:

The infographic lacks a possible solution to the issue, but it does explain where plastics emerge from, how they get into the marine, what they will do to marine wildlife, and how they will be removed to eliminate ocean plastic waste.

According to estimates reported in 2015 in the journal Science, between 4.8 million and 12.7 million tons of plastic enter the ocean every year. As large, identifiable items or as micro plastics, plastic can enter the ocean-pieces of less than five millimeters in length.

Answer:

dr/dt = -2 cm/s.

Explanation:

The volume of a cone is given by:

[tex]V=\frac{1}{3} \pi r^{2}h[/tex] (1)

Let's take the derivative with respect to time in each side of (1).

[tex]\frac{dV}{dt}=\frac{1}{3} \pi \frac{d}{dt}(r^{2}h)=\frac{1}{3} \pi \left(2r\frac{dr}{dt}h+r^{2}\frac{dh}{dt} \right)[/tex] (2)

We know that:

We can calculate how fast is the radius changing using the above information.

[tex]0=\frac{1}{3} \pi \left( 2\cdot 4\cdot \frac{dr}{dt} \cdot 10 + 4^{2}\cdot 10)\right[/tex]  

Therefore dr/dt will be:

[tex]\frac{dr}{dt}=-\frac{160}{80}=-2 cm/s[/tex]

The minus signs means that r is decreasing.

I hope it helps you!

Answer:

T=2.94*10^-10  N/m.

Explanation:

Biologists think that some spiders "tune" strands of their web to give enhanced response at frequencies corresponding to those at which desirable prey might struggle. Orb spider web silk has a typical diameter of 20μm, and spider silk has a density of 1300 kg/m³.

To have a fundamental frequency at 150Hz , to what tension must a spider adjust a 14cm -long strand of silk?

l=length of the spider silk, 14cm

velocity of wave = √(T/μ)          

where T = tension and

μ = mass per unit length)

λ/2=l

for fundamental frequency λ/2 =14cm    

 (λ= wavelength of standing wave;  as there will be no node

   except the endpoints of silk strand)

               λ = 28 cm = 0.28 m

and since frequency * wavelength = speed of wave. we have,

                  150 * 0.28 = √(T/μ)                                        ..................(#)

now μ = mass/length = [volume * density]/length = [(length*area) * density] / length = area * density

         = [π * (10 * 10^(-6))²] * 1300  = 13π * 10^(-8).

now putting this in equation (#) we get

    150 * 0.28 = √(T/[13π * 10^(-8)]).

thus T = [13π * 10^(-8)] * (42)²     =  

2.94*10^-10  N/m.

Answer:

Explanation:

Given

Length of segment is [tex]L=1 unit[/tex]

inclination of segment [tex]\theta =30^{\circ}[/tex]

To calculate the coordinates of segment we need to resolve its component in x and y co-ordinates

such that in triangle OPQ

[tex]\sin \theta =\frac{y}{L}[/tex]

[tex]y=L\sin 30[/tex]

[tex]y=1\times \frac{1}{2}=0.5 unit[/tex]

[tex]\cos \theta =\frac{x}{L}[/tex]

[tex]x=L\cos \theta [/tex]

[tex]x=1\times \cos 30[/tex]

[tex]x=1\times \frac{\sqrt{3}}{2}[/tex]

[tex]x=\frac{\sqrt{3}}{2} units[/tex]      

Answer:

1.81779 m/s in the same direction as the car

0.43220 m/s in the same direction

Explanation:

[tex]m_1[/tex] = Mass of van= 1055 kg

[tex]m_2[/tex] = Mass of car = 715 kg

[tex]u_1[/tex] = Initial Velocity of van = 0 m/s

[tex]u_2[/tex] = Initial Velocity of car = 2.25 m/s

[tex]v_1[/tex] = Final Velocity of van

[tex]v_2[/tex] = Final Velocity of car

As momentum and Energy is conserved

[tex]m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}[/tex]

[tex]{\tfrac {1}{2}}m_{1}u_{1}^{2}+{\tfrac {1}{2}}m_{2}u_{2}^{2}={\tfrac {1}{2}}m_{1}v_{1}^{2}+{\tfrac {1}{2}}m_{2}v_{2}^{2}[/tex]

From the two equations we get

[tex]v_{1}=\dfrac{m_1-m_2}{m_1+m_2}u_{1}+\dfrac{2m_2}{m_1+m_2}u_2\\\Rightarrow v_1=\dfrac{1055-715}{1055+715}\times 0+\dfrac{2\times 715}{1055+715}\times 2.25\\\Rightarrow v_1=1.81779\ m/s[/tex]

The final velocity of the van is 1.81779 m/s in the same direction as the car

[tex]v_{2}=\dfrac{2m_1}{m_1+m_2}u_{1}+\dfrac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\dfrac{2\times 1055}{1055+715}\times 0+\dfrac{1055-715}{1055+715}\times 2.25\\\Rightarrow v_2=0.43220\ m/s[/tex]

The final velocity of the car is 0.43220 m/s in the same direction

Answer:

(a). The final velocity of the car is -0.432 m/s.

(b). The final velocity of the van is 1.82 m/s.

Explanation:

Given that,

Mass of van = 1055 kg

Mass of car = 715 kg

Initial velocity of car= 2.25 m/s

(a). We need to calculate the final velocity of the car

Using formula of velocity

[tex]v_{c}=\dfrac{m_{v}-m_{c}}{m_{v}+m_{c}}\times u_{c}[/tex]

Put the value into the formula

[tex]v_{c}=\dfrac{715-1055}{715+1055}\times2.25[/tex]

[tex]v_{c}=-0.432\ m/s[/tex]

(b). We need to calculate the final velocity of the van

Using formula of velocity

[tex]v_{v}=\dfrac{2m_{v}}{m_{v}+m_{c}}\times u_{c}[/tex]

Put the value into the formula

[tex]v_{v}=\dfrac{2\times715}{715+1055}\times2.25[/tex]

[tex]v_{v}=1.82\ m/s[/tex]

Hence, (a). The final velocity of the car is -0.432 m/s.

(b). The final velocity of the van is 1.82 m/s.

Answer:

When flying the LNAV Approach, the missed approach point (MAP) would be indicated by reaching:

C. the RW30 waypoint.

Explanation:

The missed approach point (MAP) during an LNAV approach is indicated by reaching the RW30 waypoint.

When flying the LNAV approach, the missed approach point (MAP) would be indicated by reaching the RW30 waypoint. During an LNAV approach, which is a type of non-precision instrument approach procedure, pilots use lateral navigation to align with the runway. The MAP is typically defined by a waypoint and not by reaching a particular altitude or distance to the runway. Unlike precision approaches that can bring an aircraft to a lower minimum descent altitude or decision height based on a glideslope, LNAV approaches only provide lateral guidance and rely on predetermined waypoints to establish the MAP.

The work done by air resistance on a skydiver with a constant velocity is -2.93 × 10⁵ J, as the air resistance force is equal but opposite to the gravitational force, and work is calculated as force times distance in the direction of the force.

The work done by a nonconservative force such as air resistance can be calculated as the product of the force and the distance over which it acts, in the direction of the force. Since the skydiver is falling with a constant velocity, the force of air resistance must be equal and opposite to the gravitational force acting on the skydiver, resulting in no net force and therefore no acceleration. The work done by air resistance is thus equal to the gravitational force times the distance fallen, with a negative sign because the force of air resistance acts in the opposite direction to the displacement.

First, we need to calculate the gravitational force acting on the skydiver:

F_gravity = mass × acceleration due to gravity

F_gravity = 92.0 kg × 9.8 m/s²

F_gravity = 901.6 N

Now, we can calculate the work done by air resistance:

Work = force × distance × cos(ϸ)

Since the angle (ϸ) between the force of air resistance and the direction of displacement is 180 degrees (opposite directions), cos(ϸ) is -1. Therefore:

Work = -901.6 N × 325 m × -1

Work = -2.93 × 10⁵ J

The correct answer is D) -2.93 times 10⁵ J, which means the work done by air resistance is negative because it acts in the direction opposite to the displacement.