Are you ready for a brain twister? murphy can row at 5 kmph in still water. if the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place?

Answers

Answer 1
Answer: 2.4km

In this case, Murphy is rowing to a place and come back so he was going 2x of the place distance. That means when he goes to the place the current velocity is helping him(5+1 kmph) and when he comes back the current velocity is slowing him(5-1kmph).
To calculate the place distance, the calculation would be:
X/6kmph + X/4kmph= 1 hour
X/6kmph + 1.5X/6kmph= 1 hour
2.5X/6kmph= 1hour
2.5X= 1 hour x 6km/ hour
X= 6km/2.5
X= 2.4km

Related Questions

People with long-term clinical depression tend to have more heart disease because A. people who are clinically depressed eat foods that are higher in fat. B. depressed people don't care about their heart health. C. the levels of heart-damaging chemicals in the blood are generally higher in depressed people. D. exercise is too difficult for people who are depressed.

Answers

The correct answer is C. the levels of heart-damaging chemicals in the blood are generally higher in depressed people.

Answer:

Option (A).

Explanation:

Depression may be defined as physical condition in which the individual may get depress and loss the interest in any activity. Depression can leads to various mental health problems in the individual.

The depressed people eat foods that include more content of food. The high fatty food causes the heart related problems in the organisms and may completely block the functioning of heart.

Thus, the correct answer is option (A).

A particular wave can be described as transverse and self-propagating. What type of wave could it be?
A sound wave
A seismic wave
An ocean wave
A radio wave

Answers

Radio waves are transverse. Self-propagating, I guess means without any specific support, like a string or a body, so radio waves can propagate in vacuum.

So, the last one, radio wave

Answer:

A radio wave

Explanation:

Self propagating waves are those type of waves in which wave will induce the effect of by its own components.

One of the best example for this is Electromagnetic waves.

In electromagnetic waves electric field components and magnetic field components will oscillate perpendicular to each other and they both are perpendicular to the direction of propagation of wave also.

So here the disturbance due to electric field and magnetic field is since perpendicular to wave propagation so it is known as transverse wave.

So here we can say that correct answer must be an electromagnetic type of wave

so it must be

A Radio Wave.

By definition, work is a force that's applied over a specific
a. weight.
b. period of time.
c. amount of horsepower.
d. distance.

Answers

the best answer is letter D.) distance

the answer for this one will be D.

A certain car is capable of accelerating at a rate of 10.60 m/s 2 . how long does it take for this car to go from a speed of 55 mi/h to a speed of 60 mi/h

Answers

Given:
acceleration rate: 10.60 m/s²
1st speed: 55 mi/hr
2nd speed: 60 mi/hr

notice that they use different units. m/s² and mi/hr. We need to convert one unit to the other for uniformity and consistency.

1 m/s = 2.23694 mi/hr     OR    1 mi/hr = 0.44704 m/s

1st speed: 55 mi/hr → 55mi/hr * 0.44704 m/s / 1mi/hr = 24.5872 m/s
2nd speed: 60 mi/hr → 60mi/hr * 0.44704 m/s / 1mi/hr = 26.8224 m/s

Acceleration formula:
Acceleration = Change in velocity / time → Vf-Vi / t

10.60 m/s² = (26.8224 m/s - 24.5872 m/s) / t
10.60 m/s²  * t = 2.2352 m/s
t = 2.2352 m/s ÷ 10.60 m/s²
t = 0.2109 s. 

It would take 0.2109 seconds to change from 55 mi/hr to 60 mi/hr at 10.60 m/s² acceleration rate.

Final answer:

To calculate the time required for a car to accelerate from 55 mi/h to 60 mi/h with an acceleration of 10.60 m/s², convert the speeds to m/s, then use the formula Δt = (ο - νi) / a to find that it takes approximately 0.2106 seconds.

Explanation:

The question involves calculating the time it takes for a car to accelerate from 55 miles per hour (mi/h) to 60 miles per hour (mi/h) given an acceleration rate of 10.60 meters per second squared (m/s2). First, convert the speeds from miles per hour to meters per second. One mile per hour is approximately 0.44704 meters per second. Therefore, 55 mi/h is about 24.5872 m/s, and 60 mi/h is about 26.8224 m/s.

To find the time (Δt) taken to accelerate from the initial speed (νi) to the final speed (ο), one can use the formula Δt = (ο - νi) / a, where a is the acceleration. Plugging in the given values, Δt = (26.8224 m/s - 24.5872 m/s) / 10.60 m/s2 = 0.2106 seconds. Therefore, it takes approximately 0.2106 seconds for the car to accelerate from 55 to 60 miles per hour.

A silica-rich igneous rock that has large crystals and makes up much of the continental crust is ________

Answers

A silica-rich igneous rock that has large crystals and makes up much of the continental crust is called granite. These rocks are usually pink, gray or white  in color depending on the minerals found on the rock. Generally, granite would have a range of 20% to 60% by volume of quartz and a minimum of 35% feldspar. This rock is a result from  volcanic arcs and from the collision of continental masses. Due to its abundance, it has been used in a number of applications. It is used as an aggregate and filler in roading and construction industries. It is also cut and polished to be used in foyers, building facings, bench counters and tops.

Final answer:

Granite is a silica-rich igneous rock with large crystals, playing a significant role in the composition of the continental crust due to its quartz and feldspar content. It is less dense than the oceanic crust, contributing to the elevation of continental crust.

Explanation:

A silica-rich igneous rock that has large crystals and makes up much of the continental crust is granite. Granite is a coarse-grained, felsic, intrusive rock, characterized by the presence of quartz, which indicates its silica-rich nature. Additionally, granite commonly contains large amounts of salmon pink potassium feldspar and white plagioclase crystals visible cleavage planes, making it a good approximation of the continental crust in terms of density and composition.

The composition of continental crust largely consists of various types of igneous, metamorphic, and sedimentary rocks, with granite playing a significant role due to its less dense characteristics compared to the mafic rocks of the oceanic crust. This relatively low density contributes to the continental crust rising higher on the mantle compared to the oceanic crust. Furthermore, quartz and feldspar, significant components of granite, are the two most abundant minerals in the continental crust, emphasizing granite's fundamental role in the structure of the Earth's crust.

If a tank filled with water contains a block and the height of the water above point A within the block is 0.6 meter, what's the pressure at point A? A. 7.84 kPa B. 3.85 kPa C. 9.80 kPa D. 5.88 kPa

Answers

[tex]Given:\\\rho=1000 \frac{kg}{m^3}\\g=9.8 \frac{m}{s^2} \\h=0.6m\\\\Find:\\p=?\\\\Solution:\\\\p=\rho gh\\\\p=1000 \frac{kg}{m^3}\cdot 9.8 \frac{m}{s^2} \cdot0.6m=5880Pa=5.88kPa\\\\Correct\;is\;answer\;\;D[/tex]

If a tank filled with water contains a block and the height of the water above point A within the block, then the pressure will be equal to 5.88 Kpa. Hence, option D is correct.

What is Pressure?

In the natural sciences, pressure is defined as the vertical unit area of force or even the strain at a particular location inside a confined fluid. The force multiplied by the area throughout which it is exerted, and one pound per square inch, determines the pressure that a 42-pound box with an 84-square-inch bottom will impose on a surface.

Atmospheric pressure, which is at sea level is roughly 15 pounds per square inch, is the amount of weight that the atmosphere exerts on each unit area of the Earth's surface.

As per the given information in the question,

ρ = 1000 kg/m³

g = 9.8 m/s²

h = 0.6 m

Use the formula of pressure,

p = ρ × g × h

p = 1000 × 9.8 × 0.6

p = 5880 Pa or,

p = 5.88 Kpa

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A car travels south at 30 m/s for 5 minutes. What is its velocity

Answers

Answer:

Explanation:

Velocity = 30 (-j) m/s

Displacement = velocity x time = 30 x 5 x 60 = 9000 m South = - 9000 j m

The velocity of the car traveling south for 5 minutes is 30 m/s is 9000 m and acceleration of the car is 0.1 m/s² (if its direction is changing).

What is velocity ?

Velocity of an object is the distance travelled by the object per unit time. Velocity is a vector quantity having both direction and magnitude. It is the ratio of distance to the time taken for travel.

Given that,

velocity v = 30 m/s

time t = 5 minutes

t = 5 × 60 = 300 seconds

Then, distance travelled = v × t

d = 300 s × 30 m/s =9000 m

Acceleration of the object is the rate of change in its velocity. If the object is moving with constant speed and there is a change in direction there will be an acceleration.

a = v/t

a = 30 m/s/300 s = 0.1 m/s².

Therefore, the distance travelled by the car is 9000 m and its acceleration is 0.1 m/s².

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Your question is incomplete. But your complete question probably was:

A car travels south at 30 m/s for 5 minutes. What is distance of travel and acceleration ?

Argelia has a stack of schoolbooks sitting in the backseat of her car. When Argelia makes a sharp right turn, the books slide to the left of the seat until they come to a rest against the car door. Explain why this happens.

Answers

Answer:

The books slide to the left due to inertia, and then they come to a rest due to the force applied by the car door.

Explanation:

The entire motion of the books can be explained by using the first two laws of Newton:

- 1st Newton's law (also called Law of Inertia): an object at rest stays at rest and an object in motion stays in motion with constant velocity if no unbalanced forces act on it

- 2nd Newton's law: when an object is acted upon unbalanced forces, an acceleration is induced in the motion of the object, according to the equation

[tex]F=ma[/tex]

where F is the net force on the object, m is its mass and a is its acceleration.

Coming back to our problem:

- At the beginning, Argelia makes a sharp turn right. Due to the law of inertia, the books (which are not fixed to the car) continue their motion straight as it was before the curve: so, since the car is moving right, they appear to go the left of the car.

- When the books hit the car door, they stop moving due to the 2nd Newton's law: in fact, the car door applies an unbalanced force against the books, and as a result the books have a negative acceleration (=deceleration), so they slow down and eventually they stop.

The books moved due to the force that was applied and they came to rest due to inertia.

Inertia simply means the tendency to do nothing or to be able to remain unchanged. It is the resistance of any object to any change in the velocity of the object.

The books moved due to the force that was applied and they came to rest due to inertia. The book will be at rest as long as there's no force that acted on them.

In this case, the sharp turn of the car resulted in a force that acted on the car.

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The nature of a volcanic eruption is determined largely by the ________ of the magma.

Answers

The properties of magma that determines the intensity or nature of volcanic eruptions are: (1) viscosity, (2) temperature, and (3) the amount of dissolved gases. Viscosity describes the flowability of a fluid and its resistance to flow. Magma with low viscosity are more fluid-like and lets gases escape. 

Answer:

Chemistry

Explanation:

The composition of magma, the temperature of magma and the amount of dissolved gasses in the magma are all responsible for the nature of eruption.

Magma could be composed of dust, blocks, bombs, cinders and other gases.

The nature of eruption also depends on the temperature as magma could erupt at varying temperatures from 700[tex]^{2}[/tex]C to 1300[tex]^{2}[/tex]C and even at higher temperatures reaching 1600[tex]^{2}[/tex]C.

In thinking of an inductor as a circuit element, it is helpful to consider its limiting behavior at high and low frequencies. at one extreme, the inductor might behave like a short circuit, that is, like a resistor with almost no resistance (an ideal wire) having essentially no voltage drop across it no matter what the current. alternatively, the inductor might behave like an open circuit, that is, like a resistor with large resistance so that essentially no current will flow no matter what the applied voltage. based on the formula you obtained for the reactance, how does an inductor behave at high and low frequencies?

Answers

An inductor is just a coil of wire with magnetic properties. It is a device that stores electromotive force or energy in the form of magnetic field.  A current yields a magnetic field around it through a conductor. The pattern of flux for this magnetic field would be the number of concentric circle perpendicular to the detection of current. The capacity of the inductor is affected by the number of coils which would give more inductance, the material that is used for the coil, the cross sectional area of the coil and the length of the coil. For instance you have an 8 meters diameter coil with seven loops of wire. You place the coil on an area where there is a parked car. The inductance of the coil will be much larger compared to the coil without a parked car nearby because of the presence of the steel from the car. It changes the magnetic field of the coil because it acts as a core of the inductor.

Why are chemicals and hot objects never placed directly on the balance pan?

Answers

Final answer:

To prevent damage to the balance and ensure accurate measurements, hot objects and chemicals are not placed directly on the balance pan but rather in appropriate containers or on heat-resistant mats.

Explanation:

Chemicals and hot objects are never placed directly on the balance pan because it can cause damage to the balance and lead to inaccurate measurements. Such items can affect the balance's mechanisms and result in erroneous readings. Hot objects can also pose a safety hazard and may harm the operator. Additionally, they might leave residue or cause chemical reactions that could contaminate the balance, further skewing future measurements. Therefore, it is essential to use appropriate containers or heat-resistant mats when weighing hot or chemically active specimens on a double-pan mechanical balance.

Drive at a speed that is _____ and _______ at all times. this means showings careful or ______ judgment.

Answers

1. Reasonable
2. Prudent
3. Good

When you make a cell phone call, which type of electromagnetic wave is most likely transmitting the signal?

Answers

Radio waves are the only electromagnetic wave 
the cell towers are equipped to receive and process.

microwaves

A microwave is an electromagnetic wave with a wavelength in the range 0.001–0.3 m, shorter than a normal radio wave but longer than an infrared wave.

Which classification scheme is based on the brightness of a star as it appears to you in the night sky?

Answers

The apparent magnitude scale is a classification scheme which is based on the brightness of stars. The range of brightness values is from 1 to 6.
The stars which are the most brightest are ranked as number 1 and also called first magnitude stars, stars which are little dimmer than number 1 are ranked as number 2 and also called second magnitude stars. Similarly the most faintest stars are ranked number 6 and also called as the sixth magnitude stars.

A kite suspended in the sky is flowing back and forth. Which type of friction is being described?

Answers

The type of friction of a kite suspendedin the sky that is flowing back and forth is fluid friction.

Answer:

C.) Fluid Friction.

Explanation:

I had this question.

A red apple will appear black when illuminated with

Answers

A red apple will appear black when illuminated with cyan light
Cyan, Magenta and Yellow light.

A thin film of oil (n = 1.27) is located on smooth, wet pavement. when viewed perpendicular to the pavement, the film reflects most strongly red light at 640 nm and reflects no blue light at 427 nm. how thick is the oil film?

Answers

You are given a thin film of oil (n = 1.27) that is located on smooth, wet pavement. Also, it is said that it is viewed perpendicular to the pavement and that the film reflects most strongly red light at 640 nm and reflects no blue light at 427 nm. You are asked to find the thickness of the oil film.

The first thing you need to do is to divide the wavelength of the red light by the index of refraction of the oil to determine the wavelength of the red light in the oil. Then you will use 2t = mλ where t is the thickness, λ is the wavelength and m is the magnification. Note that it is viewed in a perpendicular pavement, m = 1 because it is a constructive interference. 

2t = mλ
2t = (1) (640nm/1.27)
2t = 503.94 nm
t = 251.97 nm

the measurement of an exoplanet radius is measured in units compared to

Answers

After an exoplanet has been identified using a given detection method, scientists attempt to identify the basic properties of the planet which can tell us what it might be made of, how hot it might be, whether or not it contains an atmosphere, how that atmosphere might behave, and finally, whether the planet may be suitable for life. It is often useful to first determine basic properties of the parent star (such as mass and distance from the Earth). This is then followed by the use of planetary detection methods to calculate planetary mass, radius, orbital radius, orbital period, and density. The density calculation will provide clues as to what the planet is made of and whether or not it contains a significant atmosphere. Mass and Distance of Parent Star The mass and distance of an exoplanet's parent star must often be calculated first, before certain measurements of the exoplanet can be made. For example, determining the star's distance is an important step in determining a star's mass (see below). Knowing the mass of a star then allows the mass of the planet to be measured, for example when using the Radial Velocity Method.

Exoplanet radii are measured in comparison to known planetary sizes to understand their scale and characteristics.

Exoplanet radii are typically measured in units compared to either Earth's radius or the radius of Jupiter, which are used as reference points in astronomical studies.

The comparison of exoplanet radii to these well-known planetary sizes helps scientists understand the scale and characteristics of these distant worlds.

For example, if an exoplanet is said to have a radius of 0.5 times that of Jupiter, it means the exoplanet's radius is half the size of Jupiter's radius.

A box is being pulled by two ropes. Eduardo pulls to the left with a force of 500 N, and Clara pulls to the right with a force of 200 N. The box moves because of the two forces applied to it. Leon records the forces and direction of the forces acting on the box in his lab notebook. In the table, which force has the wrong direction?


Tension by Eduardo
Tension by Clara
Kinetic friction
Gravity

Answers

Draw a diagram to illustrate the problem, as shown below.

m = mass of the box, kg
mg =  weight of the box, N, acting downward

Because of Newton's 3rd law, a normal force of N = mg acts upward on the box.
C = 200 N, the force applied by Clara, horizontally to the right
E = 500 N, the force applied by Eduardo, horizontally to the left.

Because E is greater than C, the box will move left.
The frictional force, F, will resist the initial motion. Its magnitude is
F = μN = μmg, where μ = kinetic coefficient of friction.
F acts horizontally to the right.

From the given table, we can conclude that
Normal force acting upward is correct
Tension by Eduardoacting left is correct.
Tension by Clara acting right is correct.
Kinetic friction acting left is Incorrect.
 Gravity acting downward is correct.correct

Answer:
The direction of the kinetic friction force is incorrect

Answer:

kinetic friction

Explanation:

The method of body composition measurement that sends a small current through the body to measure the resistance based on percentage of body water is

Answers

The method of body composition measurement that sends a small current through the body to measure the resistance based on percentage of body water is called the Bioelectrical Impedance Analysis. The opposition of the flow of electric current through the body is measured as the composition of body water and body fat.

If an object has a mass of 20 grams and a volume of 40 cm3, what is its density in g/cm3?

Answers

20/40=0.5 g/cm^3 becuase, mass/volume=density.

If an object has a mass of 20 grams   its density in g/cm3 is [tex]0.5 g/cm^3[/tex]

What is density?

The measure of how closely a material is packed together is called its density. The mass per unit volume is how it is defined. Density Formula: ρ = m/V, where ρ is the density, m is the object's mass, and V is its volume. Density Symbol:

[tex]density = \frac{mass}{volume}[/tex]

[tex]Density = \frac{20}{40}[/tex]

=[tex]0.5 g/cm^3[/tex]

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What is the average rate of formation of br2?

Answers

time interval is 8.40* 10^-5 moles/sec.maArk as brainliest


Why is the transverse spatial extent of a photon proportional to its wavelength which is a longitudinal quantity?

Answers

In quantum mechanics, particularly the wave-particle theory, it states that light behaves like a wave or a particle. For the wave behavior, its movement is measured in wavelengths while the time for each wavelength is the frequency. For the particle behavior, according to Planck, the energy of the photon (light particle) is determined as

E = hc/wavelength, where h is the Planck's constant (6.626 x 10-34 J-s per particle) and c is the speed of light ( 3 x 10^8m/s)

As you can see, the energy of the photon is INVERSELY PROPORTIONAL to the wavelength with the Planck's constant as the constant of proportionality.

Piece of cake

Chocolate cake

In quantum mechanics, the uncertainty principle also known as "Heisenberg's uncertainty principle" is any of a variety of mathematical inequalities, asserting a fundamental limit to the precision with certain pairs of physical properties of a particle known as complimentary variables, such as position X and momentum P can be known.

The moon has a mass of 7.35 e 22 kg and is located 3.84 e 8 meters from the earth. if ellen, an earthling, has a mass of 47 kg, what is the gravitational force between ellen and the moon?

Answers

Answer:

The gragitacional force is 1.56 10⁻³ Kg

Explanation:

The gravitational force between two bodies is proportional to their mass and inversely proportional to the square of the distance between them, is described by the equation

      F = G m₁ m₂ / r²

With G being the universal gravitation constant with a value of 6.67 10⁻¹¹ Nm²/Kg², as they give us the mass of the bodies and the distance between them, we can calculate the force.

     F = 6.67 10⁻¹¹ 47  7.35 10²² / (3.84 10⁸)²

     F =  1.56 10⁻³ Kg

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A packaging company purchases corrugated cardboard boxes in which to pack its goods. The boxes are not made up when they are delivered, but are flat,A bundle of these boxes measures 0.60 m x 0.50 m x 0.20 m and has a
weight of 72 N. Calculate the pressure exerted by the cardboard boxes

Answers

Pressure is force divided by area, P = F/A, so we don't actually care about the dimension of depths, the 0.20 m, in this problem at all. All we have to do to get the area of the boxes is multiple the length times the width, or A= Area = 0.60*0.50 = 0.30 m², then we can just take the 70 N of force and divide by that area to get pressure. So P = 70 N/0.30 m² = 233.33 Pa. Pascals (Pa) are the standard unit of pressure and are the same thing as N/m².
Final answer:

To calculate the pressure exerted by cardboard boxes, divide the force due to gravity (weight) by the area over which it is applied. Using the given weight of 72 N and the calculated base area of 0.30 m², the pressure exerted by the boxes can be determined.

Explanation:

The question relates to calculating the pressure exerted by a stack of corrugated cardboard boxes on a surface. Pressure is defined as the force applied per unit area. The formula to calculate pressure (P) is P = F / A, where F is the force in newtons (N) and A is the area in square meters (m²). Given that the weight of the boxes is 72 N (which is the force due to gravity acting on them) and the base area of the boxes is calculated from the provided dimensions (0.60 m x 0.50 m = 0.30 m²), the pressure exerted can be calculated by dividing the force by the area over which it is applied.

To find the pressure, we thus use: P = 72 N / 0.30 m². Executing this calculation provides the pressure exerted by the cardboard boxes on the surface they are lying on.

A bowling ball weighs 7.26 kg and takes 3.64 seconds to travel the 19.2 m length of the bowling alley. assuming the velocity is constant, what is the kinetic energy of the bowling ball?

Answers

The kinetic energy of the bowling ball is 100.81 J.

Given data:

The mass of bowling ball is, m = 7.26 kg.

The time interval is, t = 3.64 s.

The length of path covered is, L = 19.2 m.

First obtain the speed of ball from the given equation,

[tex]v = \dfrac{L}{t}[/tex]

Here, v is the speed of ball.

Solving as,

[tex]v = \dfrac{19.2}{3.64}\\\\v=5.27 \;\rm m/s[/tex]

Now, the expression for the kinetic energy is,

[tex]KE = \dfrac{1}{2}mv^{2}[/tex]

Solve by substituting the values as,

[tex]KE = \dfrac{1}{2} \times 7.26 \times 5.27^{2}\\\\KE=100.81 \;\rm J[/tex]

Thus, we can conclude that the kinetic energy of the bowling ball is 100.81 J.

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The kinetic energy of the bowling ball is approximately 100.81 Joules, which is calculated using the mass of the ball, the distance it covers, and the time it takes to cover that distance with constant velocity.

The student is asking for the kinetic energy of a bowling ball that has a given mass and travels a certain distance in a specified time with constant velocity. To solve this, we must first calculate the velocity of the ball using distance and time, then use this velocity to determine the kinetic energy.

Step 1: Calculate the velocity.
Velocity (v) = Distance (d) / Time (t)
v = 19.2 m / 3.64 s

v = 5.27 m/s

Step 2: Calculate the kinetic energy (KE). The formula for KE is

[tex]KE = \frac{1}{2} X m X v^2\\KE = \frac{1}{2} X 7.26 \ kg X (5.27 \ m/s)^2\\KE = 100.81 \ Joules[/tex]

Therefore, the kinetic energy of the bowling ball is approximately 100.81 Joules.

The average adult heart pumps about 84./mls of blood at 72 beats per minute. suppose you need to calculate how long it would take the average heart to circulate 6600.ml of blood.

Answers

Data and interpretation:

84 ml/s of blood  at 72 beats per minute: this means that the heart pumps 84 mililiter of blood per second, at 72 beats per minute

Question: how long it takes to pump 6600 ml?

Solution:

Calculate how many times is 84 contained in 6600

6600 ml / 84 ml/s = 78.6 s

Answer:78.6s

The heart takes [tex]\boxed{79{\text{ s}}}[/tex]  to circulate [tex]6600{\text{ mL}}[/tex]  of blood.

Explanation:

The average rate of blood pumping by adult heart at rate of [tex]72[/tex]  beats per minute is [tex]84{\text{ }}{{{\text{mL}}}\mathord{\left/{\vphantom{{{\text{mL}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] .

Our aim is to obtain the time required by heart to circulate [tex]6600{\text{ mL}}[/tex]  of blood.

The rate [tex]84{\text{ }}{{{\text{mL}}}\mathord{\left/{\vphantom{{{\text{mL}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex]  can be referred as the adult heart pumps  [tex]84[/tex] milliliters of blood in one second at the rate of [tex]72[/tex]  beats per minute.

Consider [tex]t[/tex]  be the time required for heart to pump [tex]6600{\text{ mL}}[/tex]  blood.

Since, in one second the heart pumps [tex]84{\text{ }}{{{\text{mL}}}\mathord{\left/{\vphantom{{{\text{mL}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex]  and this can be written as,

[tex]84{\text{ mL}}\Rightarrow 1{\text{ second}}[/tex]

In [tex]t[/tex]  second the heart will pump [tex]6600{\text{ mL}}[/tex]  of blood and this can be written as,

[tex]6600{\text{ mL}}\Rightarrow t{\text{ second}}[/tex]

The value of [tex]t[/tex]  is calculated as shown below.

[tex]\begin{aligned}t&=\frac{{6600{\text{ mL}}\times 1{\text{ second}}}}{{84{\text{ mL}}}}\\&=\frac{{6600}}{{84}}{\text{ seconds}}\\&=78.57{\text{ seconds}}\\&\approx 79{\text{ s}}\\\end{aligned}[/tex]

Therefore, it takes heart to circulate [tex]6600{\text{ mL}}[/tex]  of blood in approximately [tex]79{\text{ s}}[/tex].

Since, blood can flow so it is called as fluids. Fluid has no fixed shape and having definite volume.

The expression for density for any fluid can be written as,

[tex]\rho=\frac{m}{V}[/tex]

Here, [tex]{{\rho }}[/tex]  is density, [tex]m[/tex]  is the mass of the fluid and [tex]V[/tex]  is the volume of fluid.

Thus, the heart takes [tex]\boxed{79{\text{ s}}}[/tex]  to circulate [tex]6600{\text{ mL}}[/tex]  of blood.

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Answer Details:

Grade: High School

Subject: Physics

Chapter: Fluids

Keywords:

Heart, pumps, 84 mL/s, blood, 72 beats, minute, long, average , circulate, 79 s, 6600 mL, fluids, property, calculate.

A 750.0-kg boulder is raised from a quarry 125 m deep by a long uniform chain having a mass of 575 kg. this chain is of uniform strength, but at any point it can support a maximum tension no greater than 2.50 times its weight without breaking. (a) what is the maximum acceleration the boulder can have and still get out of the quarry, and (b) how long does it tak

Answers

Answer:

Part a)

[tex]a = 0.82 m/s^2[/tex]

Part b)

[tex]t = 17.44 s[/tex]

Explanation:

Part a)

Maximum tension that is obtained by the rope is 2.5 times the weight of the rope

So here we know that

mass of the boulder = 750 kg

mass of the chain = 575 kg

now total mass of the boulder and chain = 750 kg + 575 kg

[tex]M = 1325 kg[/tex]

Now we have maximum tension in the rope is given as

[tex]T = 2.5 \times 575 \times 9.8[/tex]

[tex]T = 14087.5 N[/tex]

now from Newton's 2nd law we have

[tex]T - Mg = Ma[/tex]

[tex]14087.5 - (1325\times 9.81) = 1325 a[/tex]

[tex]a = 0.82 m/s^2[/tex]

Part b)

Time taken by the boulder to raise by 125 m depth

we can use kinematics and we will assume here that it will start from rest and accelerate at above maximum value that we found in part a)

so by kinematics

[tex]d = v_i t + \frac{1}{2}at^2[/tex]

[tex]125 = 0 + \frac{1}{2}(0.82)t^2[/tex]

[tex]t = 17.44 s[/tex]

Which scientist first proposed physical laws to mathematically describe the effect of forces on the motions of bodies?

Answers

The three laws of motion were first compiled by Isaac Newton.

An electrical motor spins at a constant 2035 rpm. if the armature radius is 5.862 cm, what is the acceleration of the edge of the rotor?

Answers

An object that moves in a uniform circular motion would have a constant speed. However, we would not say that acceleration would be zero. The object would be accelerating due to the changes in the direction. Acceleration or this case would be the ratio of the square of its velocity an the radius of the circular motion. We would calculate as follows:

Acceleration = velocity^2 / radius
         velocity = 2035 rpm (1 min / 60 s) (5.862 cm)
         velocity = 198.8195 cm/s
Acceleration = (198.8195 cm/s)^2 / 5.862 cm = 33.92 cm/s^2

Therefore, the acceleration of the edge of the rotor would be 33.92 cm per s^2.
Final answer:

The acceleration at the edge of the rotor in the electrical motor spinning at a constant 2035 rpm with an armature radius of 5.862 cm is approximately 267476.4 m/s², found using the principles of centripetal acceleration in physics.

Explanation:

To solve this question, we first need to convert the given motor speed from revolutions per minute (rpm) to radians per second, which is the SI unit for angular velocity. This is done by multiplying by 2π, which is the radian equivalent of one revolution, and dividing by 60, the number of seconds in a minute. In this case, our conversion gives us a value for the angular velocity ω of approximately 213.2 rad/s.

We then use the formula for centripetal acceleration: ac = rω². Here, r is the radius of the armature (0.05862 meters using SI units), and ω is the angular velocity we converted earlier. Computing these, we find the centripetal acceleration ac to be around 267476.4 m/s².

Therefore, the acceleration at the edge of the rotor in the electrical motor spinning at a constant 2035 rpm with an armature radius of 5.862 cm is approximately 267476.4 m/s².

Learn more about Centripetal Acceleration here:

https://brainly.com/question/14465119

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