at 1 kilometer per year , how many centuries would it take for people to move from africa to china which is 10,000 kilometers away-

Answers

Answer 1
100 years are in 1 century
so if its moving 1km per year that means it would take 10,000 years and to make that into centuries you would divide 10,000 by 100
it would take 100 centuries
Answer 2

     (10,000 km) divided by (1 km/yr)  =  10,000 years

     (10,000 years) times (1 Century/100 years)  =  100 Centuries

Related Questions

What is the acceleration of a 10-N freely falling object with no air resistance?

Answers

about 9.81 m/s^2 . Hope that helps
The acceleration of ANY freely falling body, regardless of
it's mass, is the local acceleration of gravity. 

At any place on Earth, that's about 9.8 m/s².

Which statement is true concerning the evidence for black holes?

Scientists can see black holes with powerful telescopes.

Scientists can see the effect of black holes on nearby stars.

Scientists can see trails left in space by black holes.

There is no evidence for black holes.

Answers

Scientists can see the effect of black holes on nearby stars is true concerning the evidence for black holes.

10 kg cart and a 5 kg cart are placed on identical surfaces. The 10 kg cart experiences a net force of 12 N to the left, while the 5 kg cart experiences a net force of 8 N to the left. Compare and contrast the motion of the two carts.

Answers

F=ma

For the first (10kg) cart,
12=10a
a=6/5 m/s^2 to the left

For the second (5kg) cart,
8=5a
a=8/5 m/s^2 to the left

Therefore, the lighter (5kg) cart experiences a greater acceleration.
Final answer:

The 10 kg cart and 5 kg cart under different net forces will move to the left but with different accelerations. Despite the larger force acting on the 10 kg cart, the lighter 5 kg cart will actually accelerate at a greater rate.

Explanation:

Comparing the motion of a 10 kg cart experiencing a net force of 12 N to the left and a 5 kg cart experiencing a net force of 8 N to the left involves the principles of Newton's second law of motion, F=ma. For the 10 kg cart, the acceleration is found by dividing the force by mass(12 N / 10 kg), which equals 1.2 m/s² to the left. For the 5 kg cart, the acceleration is (8 N / 5 kg), which equals 1.6 m/s² to the left.

Therefore, despite the 10 kg cart experiencing a larger force, the 5 kg cart actually accelerates at a greater rate due to its lighter mass. This illustrates the principle that net force not only depends on the magnitude of the force but also on the mass of the object it is acting on.

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How long is a pendulum with a period of 1.0 S on the moon which has 1/6 of the earths gravity

Answers

Final answer:

To find the length of a pendulum with 1.0 seconds on the Moon, we use the formula for a pendulum's period, adjust the acceleration due to gravity to the Moon's 1.63 m/s², and solve for the pendulum's length.

Explanation:

The subject question inquires about the length of a pendulum on the Moon that has a period of 1.0 seconds, taking into consideration that the Moon's gravity is 1/6th that of Earth's. The formula for the period of a simple pendulum is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.

On Earth, assuming the acceleration due to gravity (g) is approximately 9.81 m/s², the length (L) for a pendulum with a period (T) of 1.0 seconds can be calculated using this formula. However, since we are interested in the situation on the Moon where g is 1/6th that of Earth's, we would have to adjust the acceleration due to gravity in our formula to be 1.63 m/s² (since 9.81 m/s² divided by 6 equals approximately 1.63 m/s²).

Accordingly, by rearranging the formula to L = T²g/(4π²), and substituting T with 1.0 second, and g with 1.63 m/s², one can compute the appropriate length of the pendulum on the Moon that would have a period of 1.0 second.

Final answer:

The length of a pendulum with a period of 1.0 second on the Moon can be calculated by rearranging the period formula for a simple pendulum, T = 2π√(L/g), and substituting in the Moon's gravity of 1.63 m/s².

Explanation:

The length of a pendulum that has a period of 1.0 second on the Moon, where gravity is 1/6th of Earth's gravity, can be found using the formula for the period of a simple pendulum, T = 2π√(L/g). On Earth, where the standard acceleration due to gravity, g, is approximately 9.81 m/s², a 1.0-second period requires a certain pendulum length. However, on the Moon, the acceleration due to gravity is only 1.63 m/s².

We can rearrange this formula to solve for the length (L) of the pendulum on the Moon: L = (T² * g) / (4π²). By substituting T for 1.0 second and g for 1.63 m/s², the length of the pendulum on the Moon can be calculated.

Using the provided formula, we get L = (1.0² seconds² * 1.63 m/s²) / (4π²) which gives us the length of the pendulum on the Moon. You would then perform the calculation to find the exact value for L.

As the time required to run up the stairs increases, the power developed by that person
Increases, decreases, or remains the same. Is the answer decreases?

Answers

Yes. Power will decrease.

'cause Power = Work / time
So, power is indirectly proportional to time so, when one increases other would decrease

Hope this helps!

As the time to run up the stairs increases, the power developed decreases..

When analyzing the relationship between time and power, it's essential to consider the fundamental definition of power as the rate at which work is done.

In the context of running up stairs, the work done involves overcoming the gravitational force acting against the person's ascent.As time increases while climbing the stairs, it indicates a slower pace, meaning the person is taking longer to cover the same vertical distance. Since the work done (ascending against gravity) remains constant, the longer time translates to a lower rate of work done, leading to a decrease in power output.

This can also be understood using the formula for power -

Power (P) = Work (W) / Time (t)

When the time (t) increases and the work (W) remains constant, the power output (P) decreases.

Thus, as the time required to run up the stairs increases, the power developed by that person decreases.

Which of the following is true about melting and freezing points?

Choices:

A. The melting point is always the same as the freezing point.
B. The melting point is achieved at a higher temperature than the freezing point.
C. The freezing point is applied to liquids, whereas the melting point is applied only to gases.
Which of the following is true about melting and freezing points?

Choices:

A. The melting point is always the same as the freezing point.
B. The melting point is achieved at a higher temperature than the freezing point.
C. The freezing point is applied to liquids, whereas the melting point is applied only to gases.

Answers

Answer:

Explanation:

I agree with what the first person said

Final answer:

The correct answer is that the melting point and freezing point of a substance are always the same, illustrating the equilibrium between the solid and liquid states of that substance at a specific temperature, such as 0°C for water.

Explanation:

The correct answer to which of the following is true about melting and freezing points is: The melting point is always the same as the freezing point. This principle is crucial in understanding the thermal properties of substances. The temperature at which a substance changes from solid to liquid (melting point) is the same temperature at which it changes from liquid to solid (freezing point) when the process is reversible and under the same pressure conditions. For instance, with water (H₂O), this equilibrium occurs at 0°C, illustrating that at this temperature, the solid and liquid states of H₂O are in equilibrium (H₂O (s) = H₂O (l)).

It's essential to refute common misconceptions like the melting point being higher than the freezing point or that these concepts apply differently to liquids and gases. All materials, whether solid, liquid, or gas at room temperature, have characteristic melting/freezing points that do not depend on their state at room temperature but rather on their inherent thermal properties.

I'LL GIVE ONE OF YOU BRAINLIEST ANSWER. PLEASE HELP ME
a) The electric field between two equally but oppositely charged parallel plates is 2.35 N/C [south]. If a charge of –2.00 C was placed at the midway point between the plates, what force (magnitude and direction) would act on the charge?
Give the direction as acting north or south. b) For another set of parallel plates, a charge of –4.00 C experiences a force of 6.00 x 10–3 N [east]. Determine the magnitude and direction of the electric field between these plates. Give the direction as east or west. (continued) 58 G r a d e 1 2 P h y s i c s Assignment 7.4: Electric Field between the Plates of a Parallel Plate Capacitor (continued) d) Label each plate in the diagram below with the appropriate polarity according to the information from part (c) above

Answers

a) The magnitude of the electric field = (electric force)/(charge of particle)

Electric force = (charge of particle) (electric field magnitude)
= (2 C)(2.35 N/C) = 4.7 N

(electric force and electric field are always in the same direction)
so, force = 4.7 N south

b) Electric field magnitude = (electric force)/(particle charge)
= (6*10^-3 N)/(-4 C) = -0.0015 N/C = -1.5*10^-3 N/C east

For part d, I think I'll need to see part c first. 

PLEASE HELP The rotating light on a lighthouse is 400 feet from a cliff. It completes one rotation every 10 seconds. The equation representing the distance, d, in feet that the center of the circle of light is from the lighthouse is d(t) = 400sec (πt/5). What is the period of d(t)? (Enter only the number.) ...?

Answers

The period is [2(pi)] / |b| 

so, it would be 2pi / pi/5 = 10 

for the second part, just plug in 10 where the "t" is. 

400sec(10pi/5) or 400sec(2pi) 

Sec = 1 / cos 

SO, you get 400*(1/cos(2pi)) = 400* 1/1 = 400. since cos(2pi) = 1 
so you get 400 as your answer 


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

The temperature of water in a beaker is 45°C. What does this measurement represent?

Answers

Temperature represents the degree of "Hotness" or "Coldness" of the body so, 45 C represents that it's neither a cold nor very hot.

Hope this helps!

Answer:

the average kinetic energy of water particles

Explanation:

How much force is needed to stop a 90-kg soccer player if he decelerates at 15 m/s²? A. 6 N B. 15 N C. 135 N D. 1350 N

Answers

The answer is: D. 1350 N

The answer is 1350 N

Please help!
Find the tension in each cord in the figure if the weight of the suspended object is w = 210N

A) Find the tension in the cord A for system (b).
B) Find the tension in the cord B for system (b).

Answers

We have to solve the system of equations:
- T a * cos 60° + T b * sin 45° - 210 N = 0
- T a * sin 60° + Tb cos 45° =  0
------------------------------------------------------
- 1/2 T a + √2 / 2 T b = 210 N
- √3 / 2 T a + √ 2 / 2 T b = 0     / * ( - 1 )
---------------------------------------------------
- 1/2 T a + √2 / 2 T b = 210 N
√ 3 / 2 T a - √2 / 2 T b = 0
----------------------------------------
T a ( √3 / 2 - 1 / 2 ) = 210 N
0.366 T a = 210 N
T a = 210 N : 0.366
1 ) T a = 573.77 N
Ta * √3 / 2 = T b * √ 2 / 2
T b = ( 573.77 * 1.732 ) : 1.4142
2 ) T b = 702.7 N 

A) Tension in the cord A ≈ 570 Newton

B) Tension in the cord B ≈ 700 Newton

[tex]\texttt{ }[/tex]

Further explanation

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

[tex]\large {\boxed {F = ma }[/tex]

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

weight of the suspended object = w = 210 N

Asked:

tension in the cord A = T_A = ?

tension in the cord B = T_B = ?

Solution:

Let:

γ = 360° - 60° - 45° - 90° = 165°

α = 90° + 45° = 135°

β = 60°

[tex]\texttt{ }[/tex]

We will use Lami's Theorem in this question.

If the system is in equilibrium , then:

[tex]\large {\boxed{\frac{T_A}{\sin \alpha} = \frac{w}{\sin \gamma}}}[/tex]

[tex]T_A = w \times \frac{\sin \alpha}{sin \gamma}[/tex]

[tex]T_A = 210 \times \frac{\sin 135^o}{sin 165^o}[/tex]

[tex]T_A = 210 \times ( 1 + \sqrt{3} )[/tex]

[tex]T_A \approx 570 \texttt{ Newton}[/tex]

[tex]\texttt{ }[/tex]

[tex]\large {\boxed {\frac{T_B}{\sin \beta} = \frac{w}{\sin \gamma}}}[/tex]

[tex]T_B = w \times \frac{\sin \beta}{sin \gamma}[/tex]

[tex]T_B = 210 \times \frac{\sin 60^o}{sin 165^o}[/tex]

[tex]T_B = 210 \times \frac{1}{2}( 6 + 3\sqrt{2} )[/tex]

[tex]T_B \approx 700 \texttt{ Newton}[/tex]

[tex]\texttt{ }[/tex]

Learn moreImpacts of Gravity : https://brainly.com/question/5330244Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454The Acceleration Due To Gravity : https://brainly.com/question/4189441Newton's Law of Motion: https://brainly.com/question/10431582Example of Newton's Law: https://brainly.com/question/498822

[tex]\texttt{ }[/tex]

Answer details

Grade: High School

Subject: Physics

Chapter: Dynamics

[tex]\texttt{ }[/tex]

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant


A state patrol officer saw a car start from rest at a highway on-ramp. She radioed ahead to another officer 30 mi along the highway. When the car reached the location of the second officer 26 min later, it was clocked going 60 mi/hr. The driver of the car was given a ticket for exceeding the 60/mi/hr speed limit. Why can the officer conclude that the drive exceeded the speed limit?

Answers

speed = distance /time

speed  = 30 miles / 26 minute

speed = 30 miles /26 minute x 60 minutes/1 hour

speed = 900 miles/13 hours

speed = 69 mph

The speed actually exceed the limit

hope this helps

The officer conclude that the driver exceeded the speed limit as the speed was 69mph.

speed = distance /time

speed  = 30 miles / 26 minute

speed = 30 miles /26 minute x 60 minutes/1 hour

speed = 900 miles/13 hours

speed = 69 mph.

What is your maximum speed limit?

the prevailing maximum pace limit for cars on expressways is a hundred and twenty km and on national highways, the maximum velocity restriction is 100 mph.

Velocity limits in India vary by way of nation and car type. In April 2018, the Union Ministry of street shipping and Highways constant the most velocity limit on expressways at a hundred and twenty km/h, for national highways at one hundred km/h, and for urban roads at 70 km/h for the M1 class of vehicles.

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If a construction worker drops a wrench
from the top of a building 375 feet high the
wrench will be
s(t) = −16t2 + 375
feet above the ground after t seconds.
Determine the velocity of the wrench 4 seonds after it was was dropped.

Answer in units of ft/sec
...?

Answers

To find velocity at a given moment, also known as instantaneous velocity, we need to know how to take the derivative of an equation;
you can take the derivative of s(t)=62t^2+ 375 by first moving the 2 in front of 162 and multiply both which well give you 324t and 375 will turn to 0
-16t^2 results in -32t
so our velocity at t=4 is -32(4) = -128ft per second

The velocity of the wrench 4 seconds after being dropped is -128 ft/sec, indicating it is moving downwards.

To determine the velocity of the wrench 4 seconds after it was dropped from the top of the building, we use the height function s(t) = -16[tex]t^2[/tex] + 375, which represents the wrench's position over time.

The velocity at any time t is given by the derivative of the position function, which is v(t) = s'(t).

Calculating the derivative, we get v(t) = -32t. Therefore, the velocity of the wrench at t = 4 seconds is v(4) = -32(4) = -128 ft/sec. The negative sign indicates that the wrench is moving downwards.


Match the layers of the atmosphere with the description that best matches it according to the graph titled Temperature Profile.

Troposphere A) Layer closest to the Earth where all weather occurs
Mesosphere B) temperature increases as elevation increases
Mesopause C) temperature remains constant as elevation increases
Stratosphere D) temperature remains at a constant zero degrees celius as elevation increases
Stratopause E) begins between 50-60km and decreases in temperature as elevation increases ...?

Answers

Answer: Atmosphere can be broadly divided into four distinct layers based on their altitude and temperature.

These layers are- Troposphere, Stratosphere, Mesosphere, and Thermosphere.

1) Troposphere ( extends upto 18 km from earth surface)- a layer that is closest to the surface of earth. It is called zone of weather as all the weather phenomenon ( such as storm, wind, precipitation, formation of clouds) occur in this layer. Temperature decreases with altitude in this layer.

2) Stratosphere (extends from 18 km to 50 km) - a layer above troposphere, where temperature increases with increase in altitude.

A boundary between stratosphere and mesosphere where temperature remains constant as elevation increases  is called Stratopause.

3) Mesosphere (extends 50 km upto 85 km) - a layer above stratosphere, where temperature decreases with increase in altitude.

A boundary between mesosphere and thermosphere, where temperature remains constant as elevation increases  is called Mesopause.

4) Thermosphere (extends from 85 km upto 600 km)-  a layer above mesosphere, where temperature again increases with increase in altitude. It is an extremely hot layer because of absorption of X rays and UV rays.

Thus, correct match for the question is-  

Troposphere -A) Layer closest to the Earth where all weather occurs.

Mesosphere- E) begins between 50-60km and decreases in temperature as elevation increases.

Mesopause- C) temperature remains constant as elevation increases.

Stratosphere -B) temperature increases as elevation increases.

Stratopause -D) temperature remains at a constant zero degrees Celsius as elevation increases.

Final answer:

The layers of the atmosphere can be matched with their descriptions based on the temperature profile as follows: Troposphere - layer closest to the Earth where all weather occurs. Mesosphere - begins between 50-60 km and decreases in temperature as elevation increases. Stratosphere - temperature increases with an increase in elevation. Stratopause - temperature remains constant as elevation increases. Mesopause - temperature remains at a constant zero degrees Celsius as elevation increases.

Explanation:

The layers of the atmosphere can be matched with their descriptions based on the temperature profile as follows:

Troposphere: A) Layer closest to the Earth where all weather occurs. In the troposphere, temperature decreases rapidly with increasing elevation.Mesosphere: E) Begins between 50-60 km and decreases in temperature as elevation increases. The mesosphere is the layer where meteorites usually burn up.Stratosphere: B) Temperature increases with an increase in elevation. Most of the stratosphere is cold and free of clouds, and it contains the ozone layer.Stratopause: C) Temperature remains constant as elevation increases. The stratopause is the isothermal layer that separates the stratosphere from the mesosphere.Mesopause: D) Temperature remains at a constant zero degrees Celsius as elevation increases. The mesopause is the outermost boundary of the mesosphere.

A sign has a mass of 1050 kg, a height h = 1 m, and a width W = 4 m. It is held by a light rod of length 5 m that is perpendicular to a rough wall. A guy wire at 23° to the horizontal holds the sign to the wall. Note that the distance from the left edge of the sign to the wall is 1 m.

Suppose we rely upon friction between the wall and the rod to hold up the sign (there is no hinge attaching the rod to the wall). What is the smallest value of the coefficient of friction µ such that the sign will remain in place? ...?

Answers

the reason I use the moments is for a problem to be in static equilibrium the moments about any point is zero the reason I take the moments about where the rod touches the wall is the unknown horizontal force and force of friction are produce zero moments at that point the only contributing forces are the tension in the guy wire and the weight acting down the weight can be considered a point acting at a distance 3 meters from the wall along the rod since the sigh is attached to the rod why i used y' is to reduce variables; the moment is the same y' * T = y T(vertical); just wanted to find total T in one step sum M about O = 0 = W*3m - T(y') solve for T then use Net Force X = 0 therefore R(horizontal) = T(horizontal) use Net Force Y = R(vertical) + T(vertical) - W = 0 the reaction horizontal is where the rod meets the wall and is the normal force or from a materials point of veiw where the rod is being compressed into the wall the reaction vertical is the force of friction along the end of the rod on the wall you need on final formula force of friction = µ * normal force( which is R(horizontal))

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Which electrons participate in chemical bonding?

A. the innermost electrons
B. valence electrons
C. any electrons
D. core electrons

Answers

B valence electrons..

B. Valence Electrons

_________________

Reason:

The valence electrons are the number of electrons in an outer shell of an atom that can participate in forming chemical bonds with other atoms. Atoms with a relatively empty outer shell will want to give up electrons.

White bunnies are a common sight on farms and in pet stores. Why are these domestic white rabbits uncommon in the wild?

Answers

White bunnies are bred seperatly from the wild. There is a gene inside of them which makes them white and scientists (millers) also know how to control the level of genes which are inside a bunny. This is why there aren't common in the while.

Answer:

c

Explanation:

Why magnetic monopole does not exist? ...?

Answers

Currently, many researchers are still working to find them.

Currently , its only theorized and they should be based on  the quantum and particle theory

hope this helps

A car advertisement claims their car can go from a stopped position to 60 miles per hour in 5 seconds. The advertisement is describing the car's
acceleration.
speed.
velocity.
direction.

Answers

Acceleration.
The ability to change its velocity in given amount of time is the car's ability to accelerate.

The answer is A. Acceleration.

During an investigation, a student determines that a copper sample has a density of 8.10 g/ml. What is the students percent error of the accepted density for copper is 8.96 g/ml

Answers

During an investigation, a student determines that a copper sample has a density of 8.10 g/ml. What is the students percent error of the accepted density for copper is 8.96 g/ml

Eliminate the parameter t. Find a rectangular equation for the plane curve defined by the parametric equations.
x = 6 cos t, y = 6 sin t; 0 ≤ t ≤ 2π

A. x^2 - y^2 = 6; -6 ≤ x ≤ 6
B. x^2 - y^2 = 36; -6 ≤ x ≤ 6
C. x^2 + y^2 = 36; -6 ≤ x ≤ 6

Answers

Final answer:

To eliminate the parameter t and find a rectangular equation for the plane curve defined by the parametric equations x = 6 cos t, y = 6 sin t; 0 ≤ t ≤ 2π, we can square both equations and then add them together. The rectangular equation for the plane curve is x^2 + y^2 = 36.

Explanation:

To eliminate the parameter t and find a rectangular equation for the plane curve defined by the parametric equations x = 6 cos t, y = 6 sin t; 0 ≤ t ≤ 2π, we can square both equations and then add them together. This will eliminate the parameter t and give us a rectangular equation. Let's do the calculations:

x^2 = (6 cos t)^2 = 36 cos^2 t

y^2 = (6 sin t)^2 = 36 sin^2 t

Adding the two equations together: x^2 + y^2 = 36 (cos^2 t + sin^2 t) = 36

So, the rectangular equation for the plane curve is x^2 + y^2 = 36. This means that option C is the correct answer.

When a current is running through a coil of wire with an iron core, what is created around the wire that is carrying the current?

Answers

Electromagnetism is created, making the iron core magnetic.

Answer:

A magnetic field

Explanation:

Which three statements about electromagnetic radiation are true?
1)Light is a kind of electromagnetic radiation.
2)Electromagnetic radiation can travel only short distances.
3)Electromagnetic radiation has no mass.
4)Electromagnetic radiation can travel through a vacuum.
5)All kinds of electromagnetic radiation are invisible.

Answers

Answers

1)Light is a kind of electromagnetic radiation.

3)Electromagnetic radiation has no mass.

4)Electromagnetic radiation can travel through a vacuum.

Explanations

Electromagnetic waves are waves that can travel through vacuum. that is they do not require material medium for propagation.

Light is in the electromagnetic spectrum.

Electromagnetic waves can travel through a long distance. For instance, radio waves are electromagnetic radiations that travel long distances.

Electromagnetic radiations carry energy with it but no mass.

Some of the electromagnetic radiations are visible such as visible light.

Which heavenly bodies are involved in causing the earths tides?

only the moon and earth.
only the earth.
the earth, moon, and sun.
all the planets plus the moon.

Answers

All of them except any planet means "Earth, Moon and the Sun"

so, option C is your answer.

Hope this helps!

What is the direction of the force that acts on clothes in the spin cycle of a washing machine?

a. outward
b. inward
c. up
d. down

Answers

Final answer:

The answer is option a.

During a washing machine's spin cycle, the force that acts on the clothes is directed outward, which is a result of the centrifugal force.

Explanation:

In the context of a washing machine's spin cycle, the force that acts on the clothes is directed outward. This is due to the principle of centrifugal force, a type of inertial force that acts on an object moving in a circular path. The centrifugal force pushes the clothes against the wall of the washing machine drum when it rotates, effectively helping to draw water out of the clothes.

This centrifugal force pushes the clothes away from the center of rotation, causing them to stick to the drum's inner surface during the spin cycle.

Therefore, the answer is option a.

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Identify which sets of Quantum Numbers are valid for an electron. Each set is ordered (n,ℓ,mℓ,ms).

3,2,0,1/2
2,2,-1, 1/2
4,3,-4,1/2
1,0,0,1/2
2,2,1,-1/2
3,2,1,1
0,1,1,-1/2
3,3,1,1/2
2,-2,-2,-1/2
3,2,2,1/2
4,2,1,1/2
2,1,-1,-1/2

Answers

If the choices are:

a.) 1,3.0,1/2 
b.) 3,2,-1,-1/2 
c.) 1,0,0,-1/2 
d.) 2,1,1,1/2 
e.) 2,-2,-2,-1/2 
f.) 3,2,0,1/2 
g.) 0,2,0,1/2 
h.) 2,2,1,1/2 
i.) 3,3,-2,-1/2 
j.) 4,3,3,-1/2 
k.) 4,3,4,-1/2 
l.) 3,2,1,1 

The "rules" for the quantum numbers are: 
* n is the energy shell: n = 1, 2, ... 
* ℓ is the subshell, the orbital: ℓ = 0, 1, ... n - 1 (s, p, d etc.) 
* mℓ is the specific orbital: mℓ = 0, ±1, ... ±ℓ 
* ms is the electron spin: ms = ±½ 

(n, ℓ, mℓ, ms) 

a.) Invalid, ℓ can not be greater than n - 1. 
b.) Valid 
c.) Valid 
d.) Valid 
e.) Invalid, ℓ can not be negative 
f.) Valid 
g.) Invalid, n can not be 0, ℓ can not be greater than n - 1 
h.) Invalid, ℓ can not be greater than n - 1 
i.) Invalid, ℓ can not be greater than n - 1 
j.) Valid 
k.) Invalid, mℓ can not be greater than ℓ 
l.) Invalid, ms can not be 1

What is the magnitude of the acceleration of a speck of clay on the edge of a potter’s wheel turning at 45 rpm (revolutions per minute) if the wheel’s diameter is 35 cm?

Answers

The magnitude of the acceleration of a speack of clay on the edge of potter's wheel turning at 45 rpm if the wheels diameter is 35cm ?

4.66 is your answer. 

OK.  We can do this !  Fasten your seat belt.

The formula we need is:  A = V²/R
                           Centripetal acceleration = (speed)² / (radius) .

Also        V  =  D / T           Speed = (distance) / (time).

with everything in meters, kilograms, and seconds.

Circumference of the wheel = (π · diameter) = 0.35 π  meters.

Speed = (0.35π m) x (45 / minute) x (1 minute / 60 sec)

           = (0.35π · 45 / 60) m/sec

           =     0.2625π m/sec

Acceleration  =  (speed²) / (radius)

                    =  (0.2625π m/s)² / (0.175 m)

                    =  (0.06890625π² / 0.175)  m² / s²·m

                    =     3.89  m / s²

You have 9 stones that are identical in appearance. One of these stones weighs just a bit more than the other 8. These other 8 stones are exactly the same in weight. Using a balance scale only TWICE, how can you determine exactly which stone is the heavier?

Answers

i think you can weigh it 3 and 3.
If they balance, choose set not used.

If not balanced, take the heavier side

then weigh 1 and 1
if balanced, stone not used, if not balanced, take the heavier side

hope this helps

Explain how you can tell the difference between the voices of two people if they are saying the same word.

Answers

you can tell the difference between two peoples voices while they say the same word by the pitch of their voice

t (sec) 0.0 - 0.5 - 1.0 - 1.5 - 2.0 - 2.5 - 3.0 - 3.5 - 4.0
s (ft) 12.5 - 26 - 36.5 - 44 - 48.5 - 50 - 48.5 - 44 - 36.5
Assuming that this smooth curve represents the motion of the body, estimate the velocity at t = 1.0, t = 2.5, and t = 3.5.

Answers

 Well let me help you here. My suggestion is that you use your favorite technique to find a smooth curve that fits the data points 
reasonably well. Lets remember that  the t values are equally spaced, I'd use Newton's forward difference formula 
It tells you that s(t) = 12.5 + 30t - 6t², and this fits the data perfectly. 
So s'(t) = 30 - 12t,
Apply what im telling you and yu will get to the result
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