At 3pm, Mikayla’s shadow was 1.2 meters long. Mikayla is 1.7 meters tall. She measures a tree’s shadow to be 7.5 meters. How tall is the tree?

Answer:

experiment

Step-by-step explanation:

The slope of the line that passes through (4, 8) and (6, 12) will be 1/2.

A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

The slope of the line is given as,

m = (y₂ - y₁) / (x₂ - x₁)

If a straight line passes through the point x​ = 8 and y​ = 4 and also through the point x​ = 12 and y​ = 6. Then the slope is given as,

m = (6 - 4) / (12 - 8)

m = 2 / 4

m = 1 / 2

The slope of the line that passes through (4, 8) and (6, 12) will be 1/2.

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The correct option is A. 8

Given f (x)=1/4 (2)^x.

[tex]f(x)[/tex] [tex]=\frac{1}{4} 2^{x}[/tex]

We have to calculate F(5), means put x = 5.

So, [tex]f(5)=\frac{1}{4} 2^{5}[/tex]

[tex]f(5)=\frac{1}{4} \times 32[/tex]

[tex]f(5)=8[/tex]

Hence [tex]f(5)=8[/tex] .

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Answer:

0.4 liters of sugar.

Step-by-step explanation:

Hello, I think I can help you with this

you can easily solve this by using a rule of three

Step 1

if

5 liters flour⇒  1 liter sugar

2 liters flour⇒ x?liter sugar

do the relation

[tex]\frac{5\ liters\ flour}{1\ liter\ sugar}=\frac{2\ liters\ flour}{x}\\\\solve\ for\ x\\\\\\\frac{x*5\ liters\ flour}{1\ liter\ sugar}=2\ liters\ flour\\x=\frac{2\ liters\ flour*1\ liter\ sugar}{5\ liters\ flour} \\x=\frac{2}{5}liter\ sugar\\x=0.4\ liters\ of\ sugar\\[/tex]

0.4 liters of sugar

I hope it helps, Have a great day-

Adding together the whole number parts gives us 21. When we add the fractions, we get 25/15, which simplifies to 1 10/15. Adding this to our whole number sum gives us 22 10/15, or 22 2/3.

To find the sum of these mixed numbers, you'll want to first add the whole number parts, and then add the fractions. In this case, adding together the whole numbers 7, 5, and 9 gives us 21.

The fractions 2/15, 2/3, and 13/15 can be added together by finding a common denominator. The common denominator for 15 and 3 is 15, therefore 2/3 becomes 10/15 when it is converted.

When we add 2/15, 10/15, and 13/15, we get 25/15, which can be reduced to 1 10/15.

When we add this to our whole number sum, we get 22 10/15,

which simplifies to 22 2/3.

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quotient is divide

-20/4 = -5

-5 -3 = -8

Answer:

1.3 times

Step-by-step explanation:

Answer:

8.25y-14

Step-by-step explanation:

The given expression is [tex]4(1.75y-3.5)+1.25y[/tex]

Distribute 4 over the parenthesis

[tex]4\cdot1.75y+4\cdot(-3.5)+1.25y\\\\=7y-14+1.25y[/tex]

Now. group the like terms

[tex](7y+1.25y)-14[/tex]

Finally combine the like terms

[tex]8.25y-14[/tex]

Therefore, the simplified expression is 8.25y-14

The distance Fritz travels to work is 24 miles if Fritz drives to work his trip takes 36 ​minutes, but when he takes the train it takes 20 minutes.

Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.

It is given that:

Fritz drives to work his trip takes 36 ​minutes, but when he takes the train it takes 20 minutes.

Let the distance Fritz travels to work is x.

As we know,

1 hour = 60 minutes

36/60 = 0.6 hrs

20/60 = 0.33 hrs

Speed = distance/time

Train speed - drive speed = 32

x/0.33 - x/0.6 = 32

After simplification:

9d - 5x = 96

4x = 96

x = 96/4

d = 24 miles

Thus, the distance Fritz travels to work is 24 miles if Fritz drives to work his trip takes 36 ​minutes, but when he takes the train it takes 20 minutes.

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Answer:

y=log4 64=2.6665.

Step-by-step explanation:

We are given that logarithmic expression

y=log 464

By using logarithmic rules

Substitute the decimal point after end digit and then put zero after decimal point

We can write as

y=log464.0

To put the decimal point after one digit from left then we move two steps.Therefore ,we write 2 on left side of the decimal point in final result

Now, we see the value of 46 at 4 from log table then we get the value of 46 at 4 is 6665

Therefore , y=log464=2.6665

Hence, the value of y=2.6665

The value of y to the equation log₄(64) = y is y = 3.

The given logarithmic equation is :

y = log₄(64)

This can be written in exponential form as :

4^(y) = 64

It is known that :

4 × 4 × 4 = 64

So,

4³ = 64

Hence the value of y = 3.

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the equation would look something like

total = 6y

since you don't show the choices look for something similar.

To find two points with negative slopes, we can calculate the slopes of the lines passing through the point (2, 8) and each of the given points. The pairs of points with negative slopes are (-2, -6) and (1, -3).

A line has a negative slope when it goes down from left to right. To find two points with negative slopes, we can calculate the slopes of the lines passing through the point (2, 8) and each of the given points.

Using the slope formula, slope = ∆y / ∆x, we can calculate the slopes:

-2, -6: slope = (-6 - 8) / (-2 - 2) = -14 / -4 = 3.5

1, -3: slope = (-3 - 8) / (1 - 2) = -11 / -1 = 11

Therefore, the pairs of points with negative slopes are (-2, -6) and (1, -3).

To write the equation in point-slope form, we can use the formula y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.

To write an equation in point-slope form, we can use the formula y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope. In this case, the given point is (-8, -2) and the slope is 5. Plugging in these values into the formula, we get:

y - (-2) = 5(x - (-8))

Simplifying the equation, we get:

y + 2 = 5(x + 8)

Therefore, the equation in point-slope form of the line that passes through the point (-8, -2) with a slope of 5 is y + 2 = 5(x + 8).

she "grew" negative 3.25 inches

 it is negative because she was taller in December than she was in January

Jean is 12 years old. Joan is 24 years old, and Jane is 20 years old. Four years ago, Joan was 20 and Jane was 16.

Let's denote:

- Joan's current age as J

- Jane's current age as N

- Jean's current age as I

Given:

1. Jean is 12 years younger than Joan: I = J - 12

2. Joan is twice as old as Jean: J = 2I

3. Four years ago, Joan was the same age as Jane is now: J - 4 = N

4. Jane was twice as old as her niece four years ago: N - 4 = 2(I - 4)

Using equation (1) and (2):

J = 2(J - 12)

J = 2J - 24

J = 24

Now substituting J = 24 into equation (1):

I = 24 - 12

I = 12

So, Jean is currently 12 years old.

The expression for the number of quarters Peter has in terms of the number of dimes is [tex]\( \frac{3}{4}d \)[/tex].

Let's denote the number of dimes Peter has as [tex]\( d \)[/tex]. According to the problem, Peter has three times as many quarters as dimes. Therefore, if we let [tex]\( q \)[/tex] represent the number of quarters, we can write the relationship between the number of quarters and dimes as:

[tex]\[ q = 3d \][/tex]

However, the question asks for an expression that gives the number of quarters in terms of the number of dimes, but using the same variable [tex]\( d \)[/tex]  to represent the total value of the dimes in dollars. Since each dime is worth $0.10, the total value of the dimes in dollars is:

[tex]\[ \text{Total value of dimes} = 0.10d \][/tex]

To find the number of quarters in terms of the total value of the dimes in dollars, we need to divide the total value of the dimes by the value of one quarter, which is $0.25, and then multiply by 3 because there are three times as many quarters as dimes:

[tex]\[ q = \frac{0.10d}{0.25} \times 3 \][/tex]

Simplifying the fraction [tex]\( \frac{0.10}{0.25} \)[/tex] gives us [tex]\( \frac{1}{2.5} \)[/tex], which simplifies further to [tex]\( \frac{2}{5} \)[/tex]. Therefore:

[tex]\[ q = \frac{2}{5}d \times 3 \][/tex]

[tex]\[ q = \frac{3}{5} \times 2d \][/tex]

[tex]\[ q = \frac{3}{5} \times 2 \times \frac{d}{1} \][/tex]

[tex]\[ q = \frac{3}{5} \times \frac{2d}{1} \][/tex]

[tex]\[ q = \frac{3}{5} \times d \times 2 \][/tex]

[tex]\[ q = \frac{3}{5} \times d \times \frac{2}{1} \][/tex]

[tex]\[ q = \frac{3}{5} \times \frac{2d}{1} \][/tex]

[tex]\[ q = \frac{3 \times 2d}{5} \][/tex]

[tex]\[ q = \frac{6d}{5} \][/tex]

However, we must remember that the original relationship was [tex]\( q = 3d \)[/tex], not . This means we made a mistake in our calculation. Let's correct it:

[tex]\[ q = 3d \][/tex]

Since each quarter is worth $0.25, the total value of the quarters in dollars is:

[tex]\[ \text{Total value of quarters} = 0.25q \][/tex]

[tex]\[ \text{Total value of quarters} = 0.25 \times 3d \][/tex]

[tex]\[ \text{Total value of quarters} = 0.75d \][/tex]

Now, to express the number of quarters [tex]\( q \)[/tex] in terms of the total value of the dimes in dollars using the same variable [tex]\( d \)[/tex], we need to adjust our equation to account for the value difference between dimes and quarters. Since the value of the dimes is given in dollars as [tex]\( d \)[/tex], and each quarter is worth $0.25, we can express the number of quarters as:

[tex]\[ q = \frac{d}{0.25} \times 3 \][/tex]

[tex]\[ q = \frac{d}{\frac{1}{4}} \times 3 \][/tex]

[tex]\[ q = d \times 4 \times 3 \][/tex]

[tex]\[ q = 4d \times 3 \][/tex]

[tex]\[ q = 12d \][/tex]

But this is not the expression we are looking for, as it gives us the number of quarters in terms of the total value of the dimes in dollars, not in terms of the number of dimes. We need to divide by 10 to convert the total value of the dimes in dollars back to the number of dimes:

[tex]\[ q = \frac{12d}{10} \][/tex]

[tex]\[ q = \frac{3}{4}d \times 4 \][/tex]

[tex]\[ q = 3d \][/tex]

This is the correct expression, as it gives us the number of quarters in terms of the number of dimes, with [tex]\( d \)[/tex] representing the number of dimes, not their value in dollars.

The correct answers are:

A) yes; B) 0.0059; C) 0.0059; D) 1; E) 0.9872.

Explanation:

A) A binomial experiment is one in which the experiment consists of identical trials; each trial results in one of two outcomes, called success and failure; the probability of success remains the same from trial to trial; and the trials are independent.

All of these criteria fit this experiment.

B) The formula for the probability of a binomial experiment is:

[tex] _nC_r\times(p^r)(1-p)^{n-r} [/tex]

where n is the number of trials, r is the number of successes, and p is the probability of success.

In this problem, p = 0.9.

For part B, n = 100 and r = 97:

[tex] _{100}C_{97}(0.9)^{97}(1-0.9)^3
\\=\frac{100!}{97!3!}\times (0.9)^{97}(0.1)^3
\\
\\=161700(0.9)^{0.97}(0.1)^3=0.00589\approx 0.0059 [/tex]

C) We are changing the probability of success this time. Since 90% of people have had chicken pox, then 100%-90% = 1-0.9 = 0.1 have not had chicken pox. For part C, n = 100, r = 3, and p = 0.1:

[tex] _{100}C_3(0.1)^3(1-0.1)^{100-3}
\\
\\=_{100}C_3(0.1)^3(0.9)^{97}
\\=\frac{100!}{97!3!}\times (0.1)^3(0.9)^{97}
\\
\\=161700(0.1)^3(0.9)^{97}=0.00589\approx 0.0059 [/tex]

D) For this part, we want to know the probability that at least 1 person has contracted chicken pox. For this part, p = 0.9, n = 10 and r = 0. We will then subtract this from 1; this will first give us the probability that none of the 10 contracted chicken pox, then subtracting from 1 means that 1 or more people did:

[tex] 1-(_{10}C_0(0.9)^0(1-0.9)^{10-0})
\\
\\=1-(\frac{10!}{0!10!}\times (0.9)^0(0.1)^{10})
\\
\\=1-(1\times 1\times (0.1)^{10})= 1-0 = 1 [/tex]

E) For this part, we find the probability that 3 people, 2 people, 1 person and 0 people have not had chicken pox. The probability p = 0.1; n = 10; and r = 3, 2, 1 and 0, respectively:

[tex] _{10}C_3(0.1)^3(1-0.1)^{10-3}+_{10}C_2(0.1)^2(1-0.1)^{10-2}+
_{10}C_1(0.1)^1(1-0.1)^{10-1}+_{10}C_0(0.1)^0(1-0.1)^{10-0}
\\
\\=_{10}C_3(0.1)^3(0.9)^7+_{10}C_2(0.1)^2(0.9)^8+_{10}C_1(0.1)^1(0.9)^9+
_{10}C_0(0.1)^1(0.9)^{10}
\\
\\120(0.1)^3(0.9)^7+45(0.1)^2(0.9)^8+10(0.1)^1(0.9)^9+1(0.1)^0(0.9)^{10}
\\
\\0.057395628+0.1937102445+0.387420489+0.3486784401
\\
\\=0.9872 [/tex]

The binomial distribution is appropriate for calculating the probability of having a specific number of American adults who had chickenpox during childhood. The probability of exactly 97 out of 100 adults having chickenpox can be calculated using the binomial probability formula. The probability that at least 1 out of 10 adults have had chickenpox and at most 3 out of 10 adults have not had chickenpox can also be calculated using the binomial probability formula.

(a) To determine if the use of the binomial distribution is appropriate, we need to check if the conditions for using it are satisfied: (1) There are only two possible outcomes - having or not having chickenpox. (2) Each trial is independent - one person's chickenpox status does not affect another person's. (3) The probability of having chickenpox is the same for each person. The given information satisfies these conditions, so the binomial distribution is appropriate.

(b) The probability of exactly 97 out of 100 randomly sampled American adults having chickenpox during childhood can be calculated using the binomial probability formula:

P(X = k) = C(n, k) * p^k * (1-p)^(n-k)

Where:

P(X = k) is the probability of getting exactly k successes (97 in this case)

C(n, k) is the number of ways to choose k successes out of n trials (100 in this case)

p is the probability of success (probability of having chickenpox = 0.90)

n is the total number of trials (100 in this case)

Using these values, we can calculate:

P(X = 97) = C(100, 97) * 0.90^97 * 0.10^3

= 100 * (0.90)^97 * (0.10)^3

≈ 0.0975

So, the probability that exactly 97 out of 100 randomly sampled American adults had chickenpox during childhood is approximately 0.0975 or 9.75%.

(c) The probability that exactly 3 out of a new sample of 100 American adults have not had chickenpox in their childhood can be calculated using the binomial probability formula:

P(X = k) = C(n, k) * p^k * (1-p)^(n-k)

Where:

P(X = k) is the probability of getting exactly k successes (3 in this case)

C(n, k) is the number of ways to choose k successes out of n trials (100 in this case)

p is the probability of success (probability of not having chickenpox = 0.10)

n is the total number of trials (100 in this case)

Using these values, we can calculate:

P(X = 3) = C(100, 3) * 0.10^3 * 0.90^97

= 161,700 * (0.10)^3 * (0.90)^97

≈ 0.0315

So, the probability that exactly 3 out of a new sample of 100 American adults have not had chickenpox in their childhood is approximately 0.0315 or 3.15%.

(d) To calculate the probability that at least 1 out of 10 randomly sampled American adults have had chickenpox, we can use the complement rule: P(at least 1) = 1 - P(none)

Where P(none) is the probability of none of the 10 sampled adults having chickenpox.

Using the binomial formula:

P(X = 0) = C(n, k) * p^k * (1-p)^(n-k)

Where:

P(X = 0) is the probability of getting exactly 0 successes

C(n, k) is the number of ways to choose 0 successes out of n trials (10 in this case)

p is the probability of success (probability of having chickenpox = 0.90)

n is the total number of trials (10 in this case)

Using these values, we can calculate:

P(X = 0) = C(10, 0) * 0.90^0 * 0.10^10

= 1 * (0.90)^0 * (0.10)^10

≈ 0.3487

So, P(none) ≈ 0.3487

Therefore, P(at least 1) = 1 - P(none) = 1 - 0.3487 = 0.6513

So, the probability that at least 1 out of 10 randomly sampled American adults have had chickenpox is approximately 0.6513 or 65.13%.

(e) To calculate the probability that at most 3 out of 10 randomly sampled American adults have not had chickenpox, we can add up the probabilities of getting 0, 1, 2, and 3 successes:

P(X ≤ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

We can use the binomial probability formula to calculate each individual probability:

P(X = k) = C(n, k) * p^k * (1-p)^(n-k)

Where:

P(X = k) is the probability of getting exactly k successes (0, 1, 2, or 3 in this case)

C(n, k) is the number of ways to choose k successes out of n trials (10 in this case)

p is the probability of success (probability of not having chickenpox = 0.10)

n is the total number of trials (10 in this case)

Using these values, we can calculate each individual probability:

P(X = 0) = C(10, 0) * 0.10^0 * 0.90^10

P(X = 1) = C(10, 1) * 0.10^1 * 0.90^9

P(X = 2) = C(10, 2) * 0.10^2 * 0.90^8

P(X = 3) = C(10, 3) * 0.10^3 * 0.90^7

Adding up these probabilities, we get:

P(X ≤ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

≈ 0.9873

So, the probability that at most 3 out of 10 randomly sampled American adults have not had chickenpox is approximately 0.9873 or 98.73%.