At a harvest 16 ears of corn are being picked for every 18 peppers if 9 peppers have been picked how many ears of corn have been picked(I need the actual math)

Answers

Answer 1
16:18
 x : 9

x = 8

Hope this helps!

Related Questions

X2 -2x + 1= 0. Solve the equation using the quadratic formula. Then solve the equation by factoring to check your solutions

Answers

using the formula  x = [-(-2) +/- sqrt((-2)^2 - 4*1*1)] /  2

=  2 +/- sqrt 0
    --------------     = 2/2  = 1
           2

The solution is x = 1  Duplicity 2

Factoring we have (x - 1)(x - 1)  = 0  which  is x = 1 Duplicity 2

The solutions to the given quadratic equation are x=1 and x=1.

The given quadratic equation is x²-2x+1=0.

The roots of a quadratic equation ax² + bx + c = 0 are given by x = [-b ± √(b² - 4ac)]/2a.

Here, a=1, b=-2 and c=1

Now, x = [2 ± √(4 - 4)]/2

x=2±0/2

x=1

With factoring, we get

x²-2x+1=0

x²-x-x+1=0

x(x-1)-1(x-1)=0

(x-1)(x-1)=0

(x-1)=0

x=1

Therefore, the solutions to the given quadratic equation are x=1 and x=1.

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what is bigger 4/5 or 5/9

Answers

4/5

It is 0.8

5/9
is 0.555....
Work: 4/5 or 5/9
Find common denominator
Common denominator is 45
4/5×9/9= 36/45
5/9×5/5=25/45
36/45 is bigger than 25/45
Answer: 4/5
Check your work:

What is the relationship between the 6s in 660, 472?

Answers

The 6 is in the hundred thousands place and ten thousands place

hope this helps

Answer:

1st 6 is 1/10 of 2nd 6 and 2nd 6 is 10 times the 2nd 6.

Step-by-step explanation:

We are asked to find the relationship between the 6s in 660,472.

Upon looking at our given number, we can see that 1st see is in 10 thousands place and 2nd 6 is in hundred thousands place.

Place value of 1st 6: 60,000

Place value of 2nd 6: 600,000

Let us compare our both numbers as:

We can see that 600,000 is 10 times greater than 60,000, therefore, 1st 6 is 1/10 of 2nd 6 and 2nd 6 is 10 times the 2nd 6.

Write out the sample space for the given experiment. use the letter b to indicate boys and g for girls. a couple plans to have 33 children.

Answers

An example of one possible outcome in the sample space:

[tex]\[ \text{bgbbggbggbgbgbggbbgbgbgbbggbgbgb} \][/tex]

To create the sample space for the given experiment, where a couple plans to have 33 children, we'll represent the possible outcomes using the letters "b" for boys and "g" for girls. The sample space for having 33 children can be represented as a sequence of "b" and "g", where each letter represents the gender of a child. Since there are 33 children, the sample space will consist of all possible sequences of 33 "b"s and "g"s.

[tex]\[ \text{bgbbggbggbgbgbggbbgbgbgbbggbgbgb} \][/tex]

Each letter in the sequence represents the gender of a child, with "b" indicating a boy and "g" indicating a girl. The sample space consists of all possible sequences of 33 "b"s and "g"s, representing all possible combinations of boys and girls the couple could have among their 33 children.

carly has a soccer game every 4th day matt has a soccer game every 5th day. when will they first have a game oh the same day

Answers

On the 20th day Carly and Matt will have their soccer games on the same day.

Final answer:

To determine the first time Carly and Matt will have a soccer game on the same day, we find the least common multiple (LCM) of 4 and 5, which is 20. Thus, they will both have a game on the 20th day.

Explanation:

The question is asking when Carly, who has a soccer game every 4th day, and Matt, who has a soccer game every 5th day, will both have a game on the same day. This is a problem that can be solved using the concept of the least common multiple (LCM). The LCM of two numbers is the smallest number that is a multiple of both numbers. To find when Carly and Matt will have a soccer game on the same day, we need to find the LCM of 4 and 5.

List the multiples of 4 (4, 8, 12, 16, 20, ...) and 5 (5, 10, 15, 20, ...).

Identify the smallest multiple that is common to both lists, which would be 20.

Therefore, the first day Carly and Matt will have a game on the same day is the 20th day.

Lev has 9 tens . Jim has 1 ten. They put all their tens together. Dawn puts 9 ones with the tens. What number did they make?

Answers

The answer would be 109. 9 tens is 90, and 1 ten is 10, 90+10=100 plus the 9 ones that Dawn put, 109

Lev and Jim have a total of 100 in tens, and with Dawn's 9 ones added, they make the number 109.

Lev has 9 tens which is equal to 90 (because 9 times 10 equals 90). Jim has 1 ten which is equal to 10. When they put all their tens together, we add 90 and 10 to get 100. Dawn then adds 9 ones to the tens. To find the final number, we add Dawn's 9 ones to the previously combined tens, which is adding 9 to 100, resulting in 109. Therefore, by pooling together their tens and ones, they made the number 109.

Which method do you prefer to use to find sums__count by tens and ones,use compatible numbers,or use friendly numbers and adjust? Explain why.

Answers

I count by tens and ones. Let me show you why with an example;

X=56+27

What is x?

To solve this equation, all you have to do is add 56 and 27. Easy. Since there are 7 tens, (5 plus 2), 7 will be in the tenths place. Like this: 7_. What will be next to it? To find this, just add the ones. 6+7=13. “Uh. Oh, 13 is bigger than ten,) you might be wondering. This problem has a simple fix. How many tens are in 13? One. You add ten to your 7, and you now have 8 in your tens place. Add the remaining three ones, and you’ve got your answer. 83.

56+27=83

X=83.

This method is easier and faster than any other method. Did you know calculators are actually programmed to use this method for simple addition? Who would’ve thought?


Which conversion factors are used to multiply to 18 cm/s to get meters per minute?

Answers

18 cm/s = 18cm/s * 1m/100cm = (18/100) m/s
(notice how the units cancel out, and 1m/100cm = 1 so we're not changing anything)

(18/100) m/s = (18/100) m/s * 60s/1min (also = 1)
Therefore we get
(1080/100) m/min = 10.8 m/min
So basically 18 *60/100 m/min

Answer:

[tex]\frac{60}{100}[/tex]

Step-by-step explanation:

Here, the given expression,

18 cm per sec

That is, measure in 1 sec = 18 cm

∵ 1 minute = 60 seconds,

⇒ 1 second = [tex]\frac{1}{60}[/tex] minutes,

Also, 1 meters ( m ) = 100 centimeters ( cm ),

⇒ 1 cm = [tex]\frac{1}{100}[/tex] m,

So, the measure in [tex]\frac{1}{60}[/tex] minutes = 18× [tex]\frac{1}{100}[/tex] cm,

Thus, the measure in 1 minute = [tex]18\times \frac{60}{100}[/tex] cm

Hence, the conversion factors are used to multiply to 18 cm/s to get meters per minute is [tex]\frac{60}{100}[/tex]

there are some numbers that can be made into only one array. Find all of these numbers up to 50.

Answers

Numbers that can be made into only one array are called prime numbers.

The prime numbers up to 50 are:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43 and 47

Six less than the product of 9 and a number is equal to 4

Answers

9x - 6 = 4

9x = 4 + 6

9x/9 = 10/9

x = 10/9

hope this helps
if you're searching for the equation, then: 9x - 6 = 4


Let f(x) = 2x - 7 and g(x) = -6x - 3. Find f(x) + g(x) and state its domain.

Answers

2x-7+-6x-3                                                                                                             2x+-6x=-4x                                                                                                          
 -4x-10=0                                                                                                          
-5/2 is the answer  

Answer:

[tex]\( f(x) + g(x) = -4x - 10 \).[/tex]

To find the domain of [tex]\( f(x) + g(x) \)[/tex], we need to consider the values of [tex]\( x \)[/tex] for which the function is defined. Since [tex]\( f(x) \)[/tex]  and [tex]\( g(x) \)[/tex] are both linear functions, their domain is all real numbers.

So, the domain of [tex]\( f(x) + g(x) \)[/tex] is [tex]\( \mathbb{R} \)[/tex] , which means that [tex]\( x \)[/tex] can be any real number.

Explanation:

To find [tex]\( f(x) + g(x) \)[/tex] , we simply add the functions [tex]\( f(x) \) and \( g(x) \)[/tex] together:

[tex]\[ f(x) + g(x) = (2x - 7) + (-6x - 3) \][/tex]

Now, let's simplify:

[tex]\[ f(x) + g(x) = 2x - 7 - 6x - 3 \][/tex]

[tex]\[ f(x) + g(x) = (2x - 6x) + (-7 - 3) \][/tex]

[tex]\[ f(x) + g(x) = -4x - 10 \][/tex]

40.8 gallons of paint among 8 containers

Answers

divide the two

40.8 / 8 = 5.1 gallons per container

The manager at Jessica's Furniture Store is trying to figure out how much to charge for a couch that just arrived. If the couch was bought at a wholesale price of $113.00 and Jessica's Furniture Store marks up all furniture by 45%, at what price should the manager sell the couch?

Answers

the couch would be 163.85

Answer: The manager sold the couch at $163.85.

Step-by-step explanation:

Since we have given that

Wholesale price of the couch = $113.00

If Jessica's Furniture Store marks up all furniture by 45%.

So, Increment in whole sale price is given by

[tex]\frac{45}{100}\times 113\\\\=\frac{5085}{100}\\\\=\$50.85[/tex]

So, the manager sold the couch at the price is given by

[tex]\$113.00+\$50.85\\\\=\$163.85[/tex]

Hence, the manager sold the couch at $163.85.

What is equivalent to 5.300

Answers

Equivalent of 5.300 is 5.3

They literally are the same

hope this helps

can a sequence be both arithmetic and geometric?

Answers

an aritmetic sequence is like this
[tex]a_n=a_1+d(n-1)[/tex] where a1=first term and d=common difference

geometric is [tex]a_n=a_1(r)^{n-1}[/tex] where a1=first term and r=common ratio


can it be both aritmetic and geometric
hmm, that means that the starting terms should be the same

therfor we need to solve [tex]d(n-1)=(r)^{n-1}[/tex]
what values of d and r make all natural numbers of n true?
are there values that make all natural numbers for n true?

when n=1, then d(1-1)=0 and r^(1-1)=1, so already they are not equal

the answer is no, a sequence cannot be both aritmetic and geometric

A sequence can be both arithmetic and geometric, and this is illustrated where terms follow both an arithmetic and geometric progression.

Yes, a sequence can be both arithmetic and geometric. An example of such a sequence is when the terms of the sequence follow both an arithmetic progression, where the difference between consecutive terms is constant, and a geometric progression, where each term after the first is found by multiplying the previous term by a fixed, non-zero number.

If g(x)=5x-3 and h(x) = x find (goh) (4)

Answers

Goh means

G(h(4))
G(4)
5*4-3
17

In this composition, we first apply the function h, which is simply the identity function, to the input 4, resulting in 4. Then, we apply the function g to this result. As g(x) = 5x - 3, g(4) equals 17. Hence, (g◦h)(4) = 17.

To find (g◦h)(4), which represents the composition of functions g and h evaluated at x = 4, we first need to find h(4), then substitute the result into g(x).

Given h(x) = x, h(4) = 4.

Now, we substitute h(4) into g(x).

So, g(h(4)) becomes g(4).

Given g(x) = 5x - 3, substituting x = 4 into g(x), we get g(4) = 5(4) - 3 = 20 - 3 = 17.

Therefore, (g◦h)(4) = 17.

A mountain climber climbed down a cliff 50 feet at a time . He did this 5 times in one day . What is the overall change in his elevation ?

Answers

-150 if im correct, it goes down 5 times and thats what i got

You have 10,600 to 10,425 find the percent decrease

Answers

Step 1) Find the amount decrease by subtracting
10600 - 10425 = 175

Step 2) Divide the result of step 1 over the original value (10600) to get 175/10600 = 0.016509
This value is approximate

Step 3) Multiply the result from step 2 by 100
0.016509*100 = 1.6509%
This value is approximate

The percent decrease is roughly 1.6509%

A factory produces 5−packs of pencils. To be within the weight specifications, a pack of 5 pencils should weigh between 60 grams and 95 grams. Each package has a mass of 15 grams. Enter a compound inequality to represent the mass of a single pencil in a pack. Can each pencil have a mass of 10.5 grams?

Answers


Divide the weight variance of a pack by 5, yielding
12 to 19 grams.
Then a single pencil can be between 12 < pencil < 19 grams.
Therefore each pencil cannot have a mass of 10.5 grams.

The compound inequality will be:  [tex]9\leq x\leq 16[/tex], where [tex]x[/tex] is the mass of a single pencil and each pencil can have a mass of 10.5 grams.

Explanation

Suppose, the mass of a single pencil in the pack is  [tex]x[/tex] gram.

So, the total mass of 5 pencils will be:  [tex]5x[/tex] grams.

Each package has a mass of 15 grams. So, the total weight of the pack of 5 pencils [tex]=(5x+15)[/tex] grams.

To be within the weight specifications, a pack of 5 pencils should weigh between 60 grams and 95 grams. So, the compound inequality will be..........

[tex]60\leq 5x+15\leq 95\\ \\ 60-15\leq 5x+15-15\leq 95-15\\ \\ 45\leq 5x\leq 80\\ \\ \frac{45}{5}\leq \frac{5x}{5}\leq \frac{80}{5}\\ \\ 9\leq x\leq 16[/tex]

So, the compound inequality to represent the mass of a single pencil in a pack will be:  [tex]9\leq x\leq 16[/tex], where [tex]x[/tex] is the mass of a single pencil.


As 10.5 grams lies inside the interval [tex]9\leq x\leq 16[/tex] , so each pencil can have a mass of 10.5 grams.

a number x plus 9 is 3036 write equation solve for x

Answers

3036-9=x Hope this helped
Hi Lolgirl44

The equation would be 3027 + 9 = 3036

I figured out this answer by subtracting 3036 - 9 which is 3027 so to check back and make sure I was right I added 9 + 3027 and it equaled 3036 so I knew I was 100% true on that so x + 9 = 3036 is really 3027 + 9 = 36 which is true and that would be your answer.

which of the following inequality has solution set

Answers

I4Ix-3 has a solution set.

What is the next number in the sequence: 4, 11, 25, 53...?

Answers

Answer:

109

Step-by-step explanation:

Given that there is a sequence of numbers as

4,11,25,53,...

We have to find the next number.

To find the next number, let us see the pattern from the given four numbers

We have

I number = 4

II number = 4+7

III number = II number + 2(7)

Iv number = III number +4(7)

So if we guess this pattern continues the next number namely v number would be

V number = IV number +8(7)

=53+56

109

i.e. I number is added by 7, II number by 2(7), III number by 2^2(7)

hence next number 2^3(7)

Answer is 109

The next number in the sequence is:

109

Obtaining the sequence

As can be seen, the first number is a selected number, which in this case is four, to which seven are added to obtain:

4 + 7 = 11

Then double 7 is added to that number, that is 14, with which you get:

11 + 14 = 25

The double of 14 is added to that number, which is 28, so the next number is:

25 + 28 = 53

And to get the next number, double 28 must be added, which is 56, therefore:

53 + 56 = 109

By this reason, the next number in the sequence is 109.

If you want to learn more about Sequences, you can visit the following link: https://brainly.com/question/16130064

Prime factorization practice all factors 1.- 25 2.- 49 3.- 7 4.- 13 5.- 24 6.- 48 7.- 168

Answers

Do u still need the answer

slove for u=vw+z to get v by its self

Answers

u = vw + z
vw = u - z
v = (u-z)/w

Complete the equation below by writing an equation equivalent to height h of a cylinder

Answers

formula for the volume of a cylinder V = πr2h Divide both sides by πr2 to isolate h. V / πr2 = πr2h / πr2 You find the height, h, is equal to . V / πr2 = h H = V / πr2

Is the product of an irrational number with a rational number always an irrational number??

Answers

Yes the product of any rational number with an irrational number is always irrational. For example, 2/3 times pi is going to be an irrational result. In this case simply (2/3)pi or (2pi)/3

So the template is
(rational)*(irrational) = irrational

-------------------------------------------------------------------------------------

Here's proof of the claim. Let's make p, q, r, s to be integers. Let's also make m be some irrational number

For now let's assume that multiplying a rational number with an irrational number leads to a rational result. The aim is to use contradiction to prove the opposite.

p/q is rational by definition (make q nonzero)
so is r/s
m is irrational

So the claim so far is
(p/q)*m = r/s

Now multiply both sides by the reciprocal of p/q. That would be q/p
(p/q)*m = r/s
(q/p)*(p/q)*m = (q/p)*(r/s)
m = (q*r)/(p*s)
The right side of the last equation is a rational number since q*r and p*s are integers (p and s are nonzero)

But m was originally irrational. So this is where the contradiction kicks in. This invalidates the initial claim "the product of a rational and irrational number is rational" proving the claim made by your textbook. 

So this completes the proof. 

Need help with this one!!!

Answers

[tex]\bf (2x^2)^4(5x^6)\impliedby \textit{distributing the exponent} \\\\\\ 2^4x^{2\cdot 4}5x^6\implies 2^4\cdot 5x^{2\cdot 4}x^6\implies 16\cdot 5x^8x^6\implies 80x^{8+6} \\\\\\ 80x^{14}[/tex]

25/5 as a mixed number

Answers

25/5 as a mixed number would be 5.
[tex]\bf \textit{well, 5 goes into 25 \underline{5 times}, with a \underline{remainder} of 0} \\\\\\ 5\frac{0}{5}\implies 5+\frac{0}{5}\implies 5+0\implies \implies 5[/tex]

Solve the inequality. Graph the solution.
z - 4.7 ≥ -1.6

Answers

z - 4.7 > = -1.6
z > = -1.6 + 4.7
z > = 3.1

closed circle on 3.1, shading to the right

** it is a closed circle because there is an equal sign in the problem...it is shaded to the right because it is greater then

The solution of the given inequality is z ≥ 3.1

The Graph of the solution of the inequality z - 4.7 ≥ -1.6 is attached below.

What is a solution set to an inequality or an equation?

If the equation or inequality contains variable terms, then there might be some values of those variables for which that equation or inequality might be true. Such values are called solution to that equation or inequality.

Given that the inequality;

z - 4.7  ≥  -1.6

Solving;

z ≥ 1.6 + 4.7

z ≥ 3.1

Therefore, The solution of the given inequality is z ≥ 3.1

The Graph of the solution of the inequality z - 4.7 ≥ -1.6 is attached below.

Learn more about inequalities here:

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Shelia has to pack 128 baskets of apples. She had packed 1/4 of the baskets. How many baskets are left for her to pack?

Answers

1/4 of 128 is 32,
32 x 3 = 96

There are 96 baskets left.
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