At a real estate​ agency, an agent sold a house for ​$392 comma 000. The commission rate is 7.5​% for the real estate agency and the commission rate for the agent is 20​% of the amount the real estate agency gets. How much did the agency make on the​ house? How much did the agent earn in​ commission? The agency made ​$ nothing on the house.

Answer:

-6

Step-by-step explanation:

DC=14

Explanation

consider triangle ADB

<BAD=54°

sin<BAD=opposite side/ hypotenuse

sin 54°=BD/BA

BD=BA sin 54°=20*0.8=16

consider triangle BDC

cos <BCD=adjacent side/hypotenuse

=DC/BC

cos 28°=DC/BC

DC=cos28°  *BC

=0.88*16=14.08

Answer: she has 30 pages left to read.

Step-by-step explanation:

Let x represent the total number of pages in the book which Lilla is reading.

Lilla read 1/5 of her book last week. This means that the number of pages that she read last week is

1/5 × x = x/5

This week she read 3 times as much as she read last week. This means that the number of pages that she read this week is

3 × x/5 = 3x/5

The number of pages that she has left to read would be

x - 3x/5

= (5x - 3x)/5 = 2x/5

b. There are 75 pages in Lilla's book. It means that the number of pages that she has left to read would be

(2 × 75)/5 = 150/5

= 30

Final answer:

Lilla read 4/5 of her book after two weeks and has 1/5, or 15 pages, left to read of her 75-page book.

Explanation:

Lilla read 1/5 of her book last week. This week she read 3 times as much as she read last week. To express how much of her book Lilla has left to read, let us denote the total amount of the book as 1 (or 100%).

a. The amount she read this week would be 3 times 1/5, which is 3/5. Thus, the total amount Lilla read over the two weeks is 1/5 + 3/5, which simplifies to 4/5 of the book. Therefore, the expression for the amount of the book Lilla has left to read is 1 - 4/5, which simplifies to 1/5 of the book.

b. Lilla's book has 75 pages. To find out how many pages she has left to read, we calculate 1/5 of 75. This is done by multiplying 75 by 1/5:

75  imes 1/5 = 75/5 = 15 pages

Therefore, Lilla has 15 pages left to read.

Answer:

The perimeter of Roxanne's right triangular garden is 79 feet.

Step-by-step explanation:

Given,

Length of 1 side = 19 feet

Hypotenuse = 33 feet

We have to find out the perimeter of the triangular garden.

Solution,

Since the garden is in shape of right triangle.

So we apply the Pythagoras theorem to find the third side.

"In a right angled triangle the square of the hypotenuse is equal to the sum of the squares of the other two sides".

So framing in equation form, we get;

[tex]33^2=19^2+(third\ side)^2\\\\1089=361+(third\ side)^2\\\\(third\ side)^2=1089-361\\\\(third\ side)^2=728[/tex]

Now taking square root on both side, we get;

[tex]\sqrt{(third\ side)^2} =\sqrt{728} \\\\third\ side=26.98\approx27\ ft[/tex]

Now we know that the perimeter is equal to sum of all the three side of a triangle.

Perimeter = [tex]19+27+33=79\ ft[/tex]

Hence The perimeter of Roxanne's right triangular garden is 79 feet.

Answer:

True

Step-by-step explanation:

First statement

[a b c | d][x]

[a b c]x=d

ax+bx+cx=d

Second statement

Ax=d

Given that A = [a b c]

[a b c]x=d

ax+bx+cx=d

ax+bx+cx=d

Then, they are going to have the same solutions

The statement is false. The solution sets for the augmented matrix [a, b, c, d] and the matrix equation Ax = d (where A = [a, b, c]) are not the same unless 'd' is consistently a column vector with 'a', 'b', 'c'.

The statement presented in the question is false. When we talk about a linear system, an augmented matrix generally pairs a coefficient matrix with an answer matrix. This would look like [A|d], where 'A' would be a matrix, and 'd' is the constants column vector.

Conversely, Ax = d is a matrix equation where 'A' is again the coefficient matrix, 'x' is the variable matrix, and 'd' is the constants column vector.

In your provided augmented matrix, [a b c d], unless 'd' is a consistent column vector with the other column vectors, it can't be virtually the same as the matrix system Ax = d where A = [a b c] because the augmented matrix [a b c d] would mean that A = [a b c] and d = [d].

Unless 'd' is mathematically consistent with the column vectors 'a', 'b', and 'c', the solution sets would not be the same.

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Answer:

Step-by-step explanation:

The absolute value of z is the distance between the point graphed from the complex number and the origin on a complex plane.  In a complex plane, the x axis is replaced by R, real numbers, and the y axis is replaced by i, the complex part of the complex number.  Our real number is positive 3 and the complex number is -5, so we go to the right 3 and then down 5 and make a point.  Connect that point to the origin and then connect the point to the x axis at 3 to construct a right triangle that has a base of 3 and a length of -5.  To find the distance of the point to the origin is to find the length of the hypotenuse of that right triangle using Pythagorean's Theorem.  Therefore:

[tex]|z|=\sqrt{(3)^2+(-5)^2}[/tex] and

[tex]|z|=\sqrt{9+25}[/tex] and

[tex]|z|=\sqrt{34}[/tex]

Final answer:

To have a monthly income of $2600, the salesman needs to make total sales of $29,616.67, considering his base salary of $925 and a 6% commission for sales over $1700.

Explanation:

The question asks us to calculate how much a local salesman needs to sell to have a monthly income of $2600. The salesman receives a base salary of $925 and earns a commission of 6% for all sales over $1700.

To solve this, we need to figure out the total sales that would give the salesman an extra $1675 ($2600 total desired income minus the $925 base salary), knowing that he only gets a commission on the amount over $1700.

Let's denote the total amount in sales that the salesman needs to make as S.

The commission is only applied to the amount exceeding $1700, so the equation can be set up as follows:

Therefore, the salesman would need to sell $29,616.67 worth of goods in a month to have a total monthly income of $2600.

Answer:

The total number of buns Mrs Klein made = 400

Step-by-step explanation:

Question

Mrs Klein made fruit buns. She sold 3/5 of it in morning and 1/4 of the remaining in the afternoon. If she sold 200 more buns in the morning than afternoon, how many buns did she make?

Given:

Mrs Klein sold  [tex]\frac{3}{5}[/tex]  of the buns in the morning.

Mrs Klein sold [tex]\frac{1}{4}[/tex]  of the remaining buns in the evening.

She sold 200 more buns in the morning than afternoon.

To find the total number of buns she make.

Solution:

Let the total number of buns be  =  [tex]x[/tex]

Number of buns sold in the morning will be given as =  [tex]\frac{3}{5}x[/tex]

Number of buns remaining = [tex]x-\frac{3}{5}x[/tex]

Number of buns sold in the evening will be given as =  [tex]\frac{1}{4}(x-\frac{3}{5}x)[/tex]

Difference between the number of buns sold in morning and evening = 200

Thus, the equation to find [tex]x[/tex] can be given as:

[tex]\frac{3}{5}x-\frac{1}{4}(x-\frac{3}{5}x)=200[/tex]

Using distribution:

[tex]\frac{3}{5}x-\frac{1}{4}x+(\frac{1}{4}.\frac{3}{5}x)=200[/tex]

[tex]\frac{3}{5}x-\frac{1}{4}x+\frac{3}{20}x=200[/tex]

Multiplying each term with the least common multiple of the denominators to remove fractions.

The L.C.M. of 4, 5 and 20  = 20.

Multiplying each term with 20.

[tex]20\times \frac{3}{5}x-20\times\frac{1}{4}x+20\times\frac{3}{20}x=20\times 200[/tex]

[tex]12x-5x+3x=4000[/tex]

[tex]10x=400[/tex]

Dividing both sides by 10.

[tex]\frac{10x}{10}=\frac{4000}{10}[/tex]

∴ [tex]x=400[/tex]

Thus, total number of buns Mrs Klein made = 400

First bag has 47 coins and second bag has 49 coins and third bag has 51 coins and fourth bag has 53 coins

Solution:

Given that,

Total number of coins = 200

Number of bags = 4

I put the coins into each bag so that each bag has 2 more coins than the one before

Therefore,

Each bag has 2 more coins than the one before. Based on this we can say,

Let "x" be the number of coins put in first bag

Then, x + 2 is the number of coins put in second bag

Then, x + 4 is the number of coins put in third bag

Then, x + 6 is the number of coins put in fourth bag

We know that,

Total number of coins = 200

[tex]x + x + 2 + x + 4 + x + 6 = 200\\\\4x + 12 = 200\\\\4x = 200-12\\\\4x = 188\\\\x = 47[/tex]

Thus,

Coins put in first bag = x = 47

Coins put in second bag = x + 2 = 47 + 2 = 49

Coins put in third bag = x + 4 = 47 + 4 = 51

Coins put in fourth bag = x + 6 = 47 + 6 = 53

Thus number of coins in each bag are found

Final answer:

By setting up an algebraic equation to distribute 200 coins into 4 bags with each bag having 2 more coins than the previous one, we find the number of coins in each bag are 47, 49, 51, and 53, respectively.

Explanation:

The question involves distributing 200 coins into 4 bags so that each subsequent bag has 2 more coins than the previous one. To find out how many coins are in each bag, let's denote the number of coins in the first bag as x. Consequently, the second bag would have x + 2 coins, the third bag x + 4 coins, and the fourth bag x + 6 coins. The total number of coins across all bags would be x + (x + 2) + (x + 4) + (x + 6) = 200.

Simplifying the equation, we get 4x + 12 = 200, which simplifies further to 4x = 188. Dividing both sides by 4 yields x = 47. Therefore, the number of coins in each bag, starting from the first to the fourth, are 47, 49, 51, and 53, respectively.

Answer:

The type of sample is Stratified sampling.

Step-by-step explanation:

Consider the provided information.

Types of sampling.

Here the population is divided into groups of males and females therefore it is stratified sampling.

Hence, the type of sample is Stratified sampling.

The drag force can be mathematically expressed as Fd = 0.5 × ρ × v^2 × A × Cd, where Fd is the drag force, ρ is the density of the fluid, v is the velocity of the object, A is the reference area, and Cd is the drag coefficient.

The drag force can be mathematically expressed as:

Fd = 0.5 × ρ × v2 × A × Cd

Where:

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- We´re gonna work with two separate triangles:

-The first one is the larger triangle (40º angle) and a vertical side that represents the ENTIRE height, b, of the tower.

Larger triangle with height b: tan 40°= [tex]\frac{b}{87}[/tex] ; .8390996312 = [tex]\frac{b}{87}[/tex];  b≈73.00166791

-The second one the smaller triangle (25º angle) and a vertical side, a, that represents the height of the first (bottom) section of the tower.

Smaller triangle with height a: tan 25°= [tex]\frac{a}{87}[/tex] ; ..4663076582 = [tex]\frac{a}{87}[/tex];  a≈40.56876626

-Then you need to solve for the vertical heights (b and a) in the two separate triangles.

-The needed height, x, of the second (top) section of the tower will be the difference between the ENTIRE height, b, and the height of the first (bottom) section, a. You will need to subtract.

In both triangles, the solution deals with "opposite" and "adjacent" making it a tangent problem.

Difference (b - a): 73.00166791 - 40.56876626 = 32.43290165 ≈ 32 feet

Answer:

Step-by-step explanation:

AB:AC=4:5

AB:BC=4:5-4 OR 4:1

So B divides AC in the ratio 4:1

Answer:

The answer to your question is below

Step-by-step explanation:

c)  6x + 4x - 6 = 24 + 9x

     6x + 4x - 9x = 24 + 6

     x = 30                       This equation has one solution, it's an identity

d) 25 - 4x = 15 - 3x + 10 - x

    -4x + 3x + x = 15 + 10 - 25

   0 = 0                           It has infinite number of solutions, it is an identity

e)  4x + 8 = 2x + 7 + 2x - 20

    4x - 2x - 2x = 7 - 20 + 8

                  0 = -5          It has no solution it is a contradiction

Answer: right-tailed

Step-by-step explanation:

By considering the given information , we have

Null hypothesis : [tex]H_0: p\leq0.6[/tex]

Alternative hypothesis : [tex]H_a: p>0.6[/tex]

The kind of test (whether  left-tailed, right-tailed, or​ two-tailed.) is based on alternative hypothesis.

Since the given alternative hypothesis([tex]H_a[/tex]) is right-tailed , so out test is a right-tailed test.

Hence, the correct answer is "right-tailed".

Unfortunately you are incorrect. The answer is actually tan(y) = 20/21

The tangent of an angle is the ratio of the opposite and adjacent sides.

tan(angle) = opposite/adjacent

tan(K) = JL/LK

tan(y) = 20/21

----------------------

Side note: the tangent of angle x would be the reciprocal of this fraction since the opposite and adjacent sides swap when we move to angle J

tan(angle) = opposite/adjacent

tan(J) = LK/JL

tan(x) = 21/20

Answer:

Therefore, we conclude that  R is an equivalence relation.

Step-by-step explanation:

We know that  a relation on a set  is called an equivalence relation if it is reflexive, symmetric, and transitive.

R is refleksive because we have that   a+b = a+b.

R is symmetric because we have that a+d =b+c equivalent with   b+c =a+d.

R is transitive because we have that:

((a, b), (c, d)) ∈ R ; ((c, d), (e, f)) ∈ R

a+d =b+c ⇒ a-b=c-d

c+f =d+e ⇒ c-d =e-f

we get

a-b=e-f ⇒  a+f=b+e ⇒((a, b), (e, f)) ∈ R.

Therefore, we conclude that  R is an equivalence relation.

Question is Incomplete; Complete question is given below;

Roger is having a picnic for 78 guests. He plans to  serve each guest at least one hot dog. If each  package, p, contains eight hot dogs, which  inequality could be used to determine how many  packages of hot dogs Roger will need to buy?

1) [tex]p \geq 78[/tex]

2) [tex]8p \geq 78[/tex]

3) [tex]8 +p \geq 78[/tex]

4) [tex]78 + p \geq 8[/tex]

Answer:

2) [tex]8p \geq 78[/tex]

Step-by-step explanation:

Given:

Number of guest in the picnic = 78 guest

Number of hot dog each guest will have = 1

Number of hot dogs in each package = 8 hot dogs.

We need to write the In equality used to determine the number of packages of hot dogs roger must buy

Solution:

Let the number of packages be 'p'.

First we will find the total number of hot dogs required.

so we can say that;

total number of hot dogs required is equal Number of guest in the picnic multiplied by Number of hot dog each guest will have.

framing in equation form we get;

total number of hot dogs required = [tex]78\times 1 =78[/tex]

Now we can say that;

Number of hot dogs in each package multiplied by number of packages should be greater than or equal to total number of hot dogs required.

framing in equation form we get;

[tex]8p\geq 78[/tex]

Hence The In equality used to determine the number of packages of hot dogs roger must buy is [tex]8p\geq 78[/tex].

Answer:

a. [1,2]

[tex] m= \frac{9-0}{2-1}=9[/tex]

b. [1,3.5]

[tex] m =\frac{17-0}{3.5-1}=6.8[/tex]

c. [1,5]

[tex] m =\frac{0-0}{5-1}=0[/tex]

d. [0,3.5]

[tex] m =\frac{17-(-5)}{3.5-0}=6.29[/tex]

So then we can conclude that the highest slope is for the interval [1,2] and that would be our solution for the fastest average rate.

a. [1,2]

[tex] m= \frac{9-0}{2-1}=9[/tex]

Step-by-step explanation:

Assuming that we have the figure attached for the function. For this case we just need to quantify the slope given by:

[tex] m = \frac{\Delta y}{\Delta x}[/tex]

For each interval and the greatest slope would be the interval on which the volume of the box is changing at the fastest average rate

a. [1,2]

[tex] m= \frac{9-0}{2-1}=9[/tex]

b. [1,3.5]

[tex] m =\frac{17-0}{3.5-1}=6.8[/tex]

c. [1,5]

[tex] m =\frac{0-0}{5-1}=0[/tex]

d. [0,3.5]

[tex] m =\frac{17-(-5)}{3.5-0}=6.29[/tex]

So then we can conclude that the highest slope is for the interval [1,2] and that would be our solution for the fastest average rate.

a. [1,2]

[tex] m= \frac{9-0}{2-1}=9[/tex]

The correct answer is A. [1,2].

To determine over which interval the volume of the box changes at the fastest average rate, we need to find the average rate of change of the volume function ( V(x) ) over the given intervals and compare them.
The volume ( V(x) ) of the box is given by:
[tex]\[ V(x) = (x + 1)(5 - x)(x - 1) \][/tex]
We first need to express ( V(x) ) in a simplified form. Let's expand the expression:
[tex]\[ V(x) = (x + 1)(5 - x)(x - 1) \]\[ V(x) = (x + 1)(x^2 - 6x + 5) \]\[ V(x) = x(x^2 - 6x + 5) + 1(x^2 - 6x + 5) \]\[ V(x) = x^3 - 6x^2 + 5x + x^2 - 6x + 5 \]\[ V(x) = x^3 - 5x^2 - x + 5 \][/tex]
Now, we calculate the average rate of change over each interval. The average rate of change of ( V(x) ) over an interval ([a, b]) is given by:
[tex]\[ \text{Average Rate of Change} = \frac{V(b) - V(a)}{b - a} \][/tex]
We need to compute this for each interval provided.
1. Interval [1, 2]:
[tex]\[ V(1) = (1 + 1)(5 - 1)(1 - 1) = 0 \]\[ V(2) = (2 + 1)(5 - 2)(2 - 1) = 3 \times 3 \times 1 = 9 \]\[ \text{Average Rate of Change} = \frac{V(2) - V(1)}{2 - 1} = \frac{9 - 0}{2 - 1} = 9 \][/tex]
2. Interval [1, 3.5]:
[tex]\[ V(1) = 0 \]\[ V(3.5) = (3.5 + 1)(5 - 3.5)(3.5 - 1) = 4.5 \times 1.5 \times 2.5 = 16.875 \]\[ \text{Average Rate of Change} = \frac{V(3.5) - V(1)}{3.5 - 1} = \frac{16.875 - 0}{3.5 - 1} = \frac{16.875}{2.5} = 6.75 \][/tex]
3. Interval [1, 5]:
[tex]\[ V(1) = 0 \]\[ V(5) = (5 + 1)(5 - 5)(5 - 1) = 6 \times 0 \times 4 = 0 \]\[ \text{Average Rate of Change} = \frac{V(5) - V(1)}{5 - 1} = \frac{0 - 0}{5 - 1} = 0 \][/tex]
4. Interval [0, 3.5]:
[tex]\[ V(0) = (0 + 1)(5 - 0)(0 - 1) = 1 \times 5 \times -1 = -5 \]\[ V(3.5) = 16.875 \]\[ \text{Average Rate of Change} = \frac{V(3.5) - V(0)}{3.5 - 0} = \frac{16.875 - (-5)}{3.5 - 0} = \frac{16.875 + 5}{3.5} = \frac{21.875}{3.5} \approx 6.25 \][/tex]
Comparing these average rates of change:
[tex]\([1, 2]\): 9\\ \([1, 3.5]\): 6.75\\ \([1, 5]\): 0\\ \([0, 3.5]\): 6.25[/tex]
The interval where the volume of the box is changing at the fastest average rate is [tex]\([1, 2]\)[/tex], with an average rate of change of 9.
Therefore, the correct answer is: A.[tex]\([1, 2]\)[/tex].

Complete question :

Answer:

81.85% of the workers spend between 50 and 110 commuting to work

Step-by-step explanation:

We can assume that the distribution is Normal (or approximately Normal) because we know that it is symmetric and mound-shaped.

We call X the time spend from one worker; X has distribution N(μ = 70, σ = 20). In order to make computations, we take W, the standarization of X, whose distribution is N(0,1)

[tex] W = \frac{X-μ}{σ} = \frac{X-70}{20} [/tex]

The values of the cummulative distribution function of the standard normal, which we denote [tex] \phi [/tex] , are tabulated. You can find those values in the attached file.

[tex]P(50 < X < 110) = P(\frac{50-70}{20} < \frac{X-70}{20} < \frac{110-70}{20}) = P(-1 < W < 2) = \\\phi(2) - \phi(-1)[/tex]

Using the symmetry of the Normal density function, we have that [tex] \phi(-1) = 1-\phi(1) [/tex] . Hece,

[tex]P(50 < X < 110) = \phi(2) - \phi(-1) = \phi(2) - (1-\phi(1)) = \phi(2) + \phi(1) - 1 = \\0.9772+0.8413-1 = 0.8185[/tex]

The probability for a worker to spend that time commuting is 0.8185. We conclude that 81.85% of the workers spend between 50 and 110 commuting to work.

Answer:

Step-by-step explanation:

Check the attachment the solution of the work is given there

Answer: 0.74

Step-by-step explanation:

Let h = rhombus' height

Looking at the attachment, we see that the circle has an area of [tex]\pi *(\frac{h}{2}) ^{2}[/tex]

The rhombus has an area of [tex]\frac{h^2}{sin(70°)}[/tex]

because the base is [tex]\frac{b}{sin(90)} = \frac{h}{sin(70)}[/tex]

due to the law of sines

Thus, Area Circle / Area Rhombus is

[tex]\frac{(\pi(\frac{h}{2})^2)}{(\frac{h^2}{sin(70)}) } = 0.74[/tex]

The maximum weight of boxes that can be placed into the elevator is:

[tex]\to 2000 - 200 = 1800 \ lbs[/tex]  

It should be noted that Y must be an even integer for the equivalence to hold, whereas X might be odd or even because 40X is always even.

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Answer:

11 different combinations

Step-by-step explanation:

A salesman packed 3 shirts and 5 ties.

With one shirt, he could wear all 5 ties = 5 combinations

With another shirt, he could wear 4 ties  = 4 combinations

With the third shirt, he could wear only 2 ties= 2 combinations

number of different combinations= [tex]5+4+2=11[/tex]

so answer is 11

Answer:

Estimated Average Requirement (EAR)

Step-by-step explanation:

The Estimated Average Requirement (EAR) is the average amount of daily intake value which is estimated to meet the needs of 50% of the healthy individuals.

The EAR is estimated on the basis of specific conditions of adequacy, and are derived from a careful study of the literature.

The major parameters which is selected for the criterion are reduction of disease risk.

Answer:

d. dog

Step-by-step explanation:

The BCG matrix is a tool used to assess the performance of the products of an organization on the basis of market share and market growth.

Basically there are 4 classes of products namely; Star, cash cow, question mark and dog.

Dogs are product with low market share and low growth.

Question mark have high growth but low market share while cash cows are the products with high mark share but low growth.

Stars are products with high market share and high market growth.

Hence dog is a poor performer that has only a small share of a slow-growth market. Option d.

Answer:

Current balance in Marcelo's account = $132.63

Step-by-step explanation:

Given:

Initial amount in Marcelo's bank account = $49.13

Amount paid in two fees = $32.50 each

Amount added by two deposits = $74.25 each

To find balance in dollars in Marcelo's account.

Solution:

Total amount paid in fees = [tex]2\times \$32.50=\$65[/tex]

Total amount deposited = [tex]2\times \$74.25=\$148.50[/tex]

The balance in Marcelo's account can be represented as:

⇒ Initial balance - Amount given in fees + Amount deposited

⇒ [tex]\$49.13-\$65+\$148.50[/tex]

⇒ [tex]\$132.63[/tex]

Thus, balance in Marcelo's account now = $132.63

Answer: 132.63

Step-by-step explanation:

I copied the other guy lol thanks for the points

Answer:

Option 3)  Closer to 0      

Step-by-step explanation:

Correlation:

Values between 0 and 0.3 tells about a weak positive linear relationship, values between 0.3 and 0.7 shows a moderate positive correlation and a correlation of 0.7 and 1.0 states a strong positive linear relationship.

Values between 0 and -0.3 tells about a weak negative linear relationship, values between -0.3 and -0.7 shows a moderate negative correlation and a correlation value of of -0.7 and -1.0 states a strong negative linear relationship.

Thus, for the given situation, if there is no relationship between two quantitative variables then the value of the correlation coefficient, r, is close to 0

Answer:

the opportunity cost of producing each additional car REMAINS CONSTANT

Answer:

The code is attached. I used python to define the function and matplotlib library to plot the histogram.

Step-by-step explanation:

=======================================

The tangent of an angle is the ratio of the opposite over adjacent sides.

tan(angle) = opposite/adjacent

tan(theta) = 4/3

This means that

opposite = 4 and adjacent = 3

This only happens when angle P is the reference angle. In other words,

tan(P) = 4/3