Answer:
A. 1560 Hz
Explanation:
The Doppler effect occur when a source of a wave (like sound) is moving relative to an observer (or when the observer is moving relative to the source). When this happens, the apparent frequency of the sound as heard by the observer is shifted with respect to the real frequency, according to the formula:
[tex]f'=\frac{v}{v-v_s}f[/tex]
where
f' is the apparent frequency
v is the speed of the wave
vs is the velocity of the source relative to the observer (positive if the source is moving towards the observer, negative if it is moving away from the observer)
f is the real frequency of the wave
In this problem, we have the following data:
f = 1100 Hz is the original frequency of the sound
v = 340 m/s is the speed of the sound wave
[tex]v_s = 100 m/s[/tex] is the velocity of the car approaching the pit crew
Substituting these numbers into the formula, we can find the frequency heard by the pit crew:
[tex]f'=\frac{340 m/s}{340 m/s-100 m/s}(1100 Hz)=1558 Hz \sim 1560 Hz[/tex]
Answer: option A. 1560 Hz
Explanation:
Doppler effect is the phenomenon wherein the frequency of the source of the sound is different from what is received. This happens when either of the source or observer or both are relatively in motion.
In the given question, the observer is stationary and the source of sound is moving at the speed of [tex]v_s = 100 m/s[/tex] towards the observer. The frequency of the sound emitted is [tex]f_s = 1100 Hz[/tex]. The frequency heard by the pit crew member would be given by:
[tex]f_o = \frac{V}{V-v_s}f_s[/tex]
[tex]f_o = \frac{340 m/s}{340m/s - 100 m/s}\times 1100 Hz = 1558.3 Hz = 1560 Hz (approx)[/tex]
Thus, the frequency heard by the pit crew would be 1560 Hz. Correct option is A.
what is the net force of this object?
F air=400N
F grav=600N
A) 0 nuetons
B) 200 nuetons
C) 400 nuetons
D) 600 nuetons
Answer:
B) 200 Newtons
Explanation:
We have two forces acting on the object:
- Fgrav = 600 N: this is the force of gravity, which is equal to the weight of the object, which pushes downward
- Fair = 400 N: this is the force due to the air resistance, which is against the direction of motion of the object, so for an object in free fall, its direction is upward
Therefore, we have two forces acting in opposite directions: therefore, the net force is equal to the difference between the two forces:
[tex]F_{net}=F_{grav}-F_{air}=600 N-400 N=200 N[/tex]
A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. its speed is 40 m/s when it reaches ground level. part a what was its speed when its height was half that of its starting point? what was its speed when its height was half that of its starting point? 33 m/s 14 m/s 20 m/s 28 m/s
Given that,
Initial velocity , Vi = 0
Final velocity , Vf = 40 m/s
Acceleration due to gravity , a = 9.81 m/s²
Distance can be calculated as,
2as = Vf² - Vi²
2 * 9.81 *s = 40² - 0²
s = 81.55 m
For half height, that is, s = 40.77m
Vf= ??
2as = Vf² - Vi²
2 * 9.81 * 40.77 = Vf² - 0²
Vf² = 800
Vf = 28.28 m/s
Therefore, speed of roller coaster when height is half of its starting point will be 28 m/s.
A student throws a coin vertically downward from the top of a building. The coin leaves the throwers hand with a speed of 15.0 m/s. What is the magnitude of its velocity after falling 10.0 m?
A.) 18.0 m/s
B.) 14.5 m/s
C.) 20.5 m/s
D.) 19.8 m/s
Answer:
The correct answer is option C
Explanation:
We have the equation of motion, [tex]v^2=u^2+2as[/tex], where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement.
Here initial velocity = 15 m/s
Displacement = 10 m
Acceleration = acceleration due to gravity = 9.8 m/s²
Substituting to get final velocity,
[tex]v^2=u^2+2as\\ \\ \\v^2=15^2+2*9.8*10\\ \\ v=20.52m/s[/tex]
So the correct answer is option C
In Physics, the magnitude of the velocity of a coin thrown downward from a building can be calculated using the equation of motion. Here, the initial velocity of the coin is added to the effect of gravity. The final downward speed after falling 10.0 m is approximately 20.5 m/s.
Explanation:The subject here is Physics, more specifically, mechanics relating to motion under gravity. It's important to know that when an object is dropped, it accelerates due to gravity. The standard rate due to Earth's gravity is 9.8 m/s^2. However, in this case, the coin is thrown downward (i.e., in the direction of gravity), which means we must add this initial speed to gravity's influence.
The magnitude of velocity is calculated using this equation: final velocity = initial velocity + acceleration due to gravity * time. But you have an issue here. You don't have the time. Instead, you have the distance fallen. We need to use the second equation of motion: final velocity^2 = initial velocity^2 + 2*acceleration*distance. Substituting the given values: final velocity^2 = (15 m/s)^2 + 2*9.8 m/s^2 * 10.0 m = 225 m^2/s^2 + 196 m^2/s^2. The square root of the sum gives us the final velocity which is approximately 20.5 m/s, as velocity is a scalar quantity, we take the magnitude, so we get 20.5 m/s
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can someone help on this one
An action-reaction pair shows the direct relationship two objects have directly on each other. Therefore, the correct answer is C. The Moons gravity pulls on you, and your gravity pulls on the Moon because it is moon gravity-person person gravity-moon.
Choice A would be made correct if it was you pull on a drawer and the drawer pushes on you OR the table pushes on the ground and the ground pushes on the table.
Choice B would be made correct if it was a computer sits on a table and the table pushes up on the computer.
Choice D would be made correct if it was an eraser sits on a shelf and the shelf pushes up on the eraser OR the wall pushes on the shelf and the shelf pushes against the wall.
Hope this helps!!
If you are standing at a beach on Earth at the same time that the shadow of the moon falls across your location, what event would you be able to witness at that time? A solar eclipse B lunar eclipse C low tide D full moon
Answer:
The answer is A, a solar eclipse.
Explanation:
From the Bohr Model diagram, assuming the atom is neutral, what element is represented by the diagram? A) Argon B) Chlorine Eliminate C) Nitrogen D) Oxygen
The actual answer is B) Chlorine
According to the Bohr Model diagram, the atom has seventeen electrons. This makes it Chlorine.
Sorry if i'm late!!
Answer:
B)
Explanation:
Usatestprep
A capacitor stores 7.6 x 10^-11 C when the electric potential difference between the plates is 5.8 v. What is the electric potential energy in the capacitor
Use the formula for energy stored between the plates of a capacitor:
[tex]E = \frac{1}{2}QU=\frac{1}{2}7.6\cdot 10^{-11}C\cdot 5.8V= 2.2\cdot 10^{-10}J[/tex]
where Q is he charge (given) and U is the electric potential (aka voltage), given.
The stored energy is 2.2 10^{-10} Joules.
Hakeem was dismayed to discover that he offended coworkers by standing 2 feet away from them during business conversations. In the U.S., what distance would have been more appropriate? PS 2100
Final answer:
In the U.S., a more appropriate distance for business conversations is maintaining an arm's length of space between each other when talking face to face.
Explanation:
In the U.S., a more appropriate distance for business conversations is maintaining an arm's length of space between each other when talking face to face. This means standing approximately 3-4 feet away from the person you are conversing with.
Standing 2 feet away from coworkers may be considered too close and can make them uncomfortable. It's important to pay attention to cues from coworkers, and if they seem uncomfortable, it's best to adjust your distance accordingly. Remember that personal space preferences can vary among individuals, but generally, maintaining an arm's length of space is a good guideline to follow in the U.S.
What will the distance from the point of origin if a car traveled at a speed of 25 km/hr for a time of 1 hour and 15 minutes?
1. ____ is defined as a force acting over a distance
A. Power
B. Energy
C. Work <--
D. Potential energy
3. The unit that represents 1 Joule of work done each second is the
A. Power
B. Newton
C. Watt <--
D. Mechanical advantage
4. Which of the following situations does not involve potential energy being changed into kinetic energy?
A. An apple falling from a tree
B. Shooting a dart from a spring-loaded gun
C. Pulling back on the string of a bow <--
D. A creek flowing downstream
5. ____ is determined by both mass and velocity
A. Work
B. Power
C. Potential Energy
D. Kinetic Energy <--
6. Energy that does not involve the large-scale motion or position of objects in a system is called
A. Potential energy
B. Mechanical energy
C. Nonmechanical energy <--
D. Conserved energy
Need help checking over my answers. Some I am not sure on.. especially number four.
1. Work (C) is defined as a force acting over a distance
3. The unit that represents 1 Joule of work done each second is the Watt. (C)
4. Pulling back on the string of a bow (C) does not involve potential energy being changed into kinetic energy?
5. Kinetic energy is determined by both mass and velocity
6. Energy that does not involve the large-scale motion or position of objects in a system is called (I'm not sure; could be nonmechanical or potential)
Work is the force acting over a distance, power is the rate at which work is done, kinetic energy depends on mass and velocity, potential energy involves position or condition, and nonmechanical energy encompasses forms not related to large-scale motion or position of objects. The correct options are 1. C, 3..C, 4. C, 5.D, 6. C.
1. Work. Work is defined as the product of force and the distance over which the force is applied. It is a measure of the energy transfer that occurs when an object is moved by the application of force. Power (A) is the rate at which work is done or energy is transferred. Energy (B) is the capacity to do work. Potential energy (D) is the energy possessed by an object due to its position or condition.
3. Watt. The unit of power is the watt, which represents the rate at which work is done or energy is transferred. One watt is equal to one joule of work done per second. Power (A) represents the rate of doing work or transferring energy. Newton (B) is a unit of force. Mechanical advantage (D) is a measure of the amplification of force achieved by using a machine.
4. Pulling back on the string of a bow. This situation does not involve potential energy being changed into kinetic energy. When pulling back on the string of a bow, potential energy is stored in the bow itself due to the deformation of its structure. When the string is released, the potential energy is converted into kinetic energy as the arrow moves forward. In all the other options, potential energy is converted into kinetic energy. In option A, the apple's potential energy is converted into kinetic energy as it falls. In option B, the potential energy stored in the spring is converted into kinetic energy as the dart is launched. In option D, the potential energy of the elevated water is converted into kinetic energy as it flows downstream.
5. Kinetic Energy. Kinetic energy is determined by both mass and velocity. It is the energy possessed by an object due to its motion. The kinetic energy of an object increases with both mass and velocity. Work (A) is not determined by velocity alone but by force and displacement. Power (B) is the rate at which work is done or energy is transferred. Potential energy (C) is determined by the position or condition of an object and is not directly related to mass and velocity.
6. Non-mechanical energy. Nonmechanical energy refers to the energy that does not involve the large-scale motion or position of objects in a system. It includes forms of energy such as thermal energy, chemical energy, electrical energy, and nuclear energy. Potential energy (A) is the energy possessed by an object due to its position or condition. Mechanical energy (B) includes both potential and kinetic energy. Conserved energy (D) is not a recognized term in this context.
Therefore, The correct options are 1. C, 3. C, 4. C, 5.D, 6. C.
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Determine the displacement of a plane that experiences uniform acceleration from 66 m/s north to 88 m/s north in 12 s.
The plane experiences an acceleration of 1.83 m/s². Using the formula for acceleration, the displacement of the plane during this time is found to be 1363.92 m north.
Explanation:To determine the displacement of a plane with uniform acceleration, we must first figure out the rate of acceleration. Acceleration is defined as the change in velocity divided by the time it takes for this change to occur. In this case the change in velocity (final velocity - initial velocity) is 88 m/s - 66 m/s = 22 m/s. This acceleration occurs over a period of 12 seconds, so the rate of acceleration is 22 m/s / 12 s = 1.83 m/s².
Now, with the rate of acceleration determined, the displacement of the plane can be calculated using the equation for acceleration d = vi*t + 0.5*a*t², where 'd' is displacement, 'vi' is initial velocity, 'a' is acceleration, and 't' is the time. After substituting the given values we get the answer as 66m/s * 12s + 0.5 * 1.83 m/s² * (12s)² = 1363.92 m. So the displacement of the plane during this period is 1363.92 m north.
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A net force of 3000 N is accelerating a 1200 kg elevator upward. If the elevator starts from rest, how long will it take to travel up 15 m?
F = net force acting on the elevator in upward direction = 3000 N
m = mass of the elevator = 1200 kg
a = acceleration of the elevator = ?
Acceleration of the elevator is given as
a = F/m
a = 3000/1200
a = 2.5 m/s²
v₀ = initial velocity of the elevator = 0 m/s
Y = displacement of the elevator = 15 m
t = time taken
Using the kinematics equation
Y = v₀ t + (0.5) a t²
15 = (0) t + (0.5) (2.5) t²
t = 3.5 sec
The elevator will take approximately 1.10 seconds to travel up 15 m.
Explanation:To find the time it will take for the elevator to travel up 15 m, we can use the equation:
vf = vi + at
Where vf is the final velocity, vi is the initial velocity (which is 0 m/s since the elevator starts from rest), a is the acceleration, and t is the time.
We can rearrange the equation to solve for t:
t = (vf - vi) / a
Given that the net force is 3000 N and the mass of the elevator is 1200 kg, we can calculate the acceleration using:
a = F_net / m
Substituting the values:
a = 3000 N / 1200 kg = 2.5 m/s²
Now we can calculate the time:
t = (vf - 0 m/s) / 2.5 m/s²
t = vf / 2.5 m/s²
We can solve for vf using the kinematic equation:
vf² = vi² + 2ad
Since the initial velocity is 0 m/s:
vf² = 2ad
vf = √(2ad)
Substituting the values:
vf = √(2 * 2.5 m/s² * 15 m)
vf = √(7.5 m²/s²)
vf = 2.74 m/s
Now we can calculate the time:
t = 2.74 m/s / 2.5 m/s²
t ≈ 1.10 s
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Which is the most widely held ideal of the US political culture?
A. belief in a limited government and protect individual liberties.
B. belief in a unitary government and centralized decision making.
C. belief in a strong government that monitors individual actions.
D. belief in a weak central government and strong local governments.
The correct answer is A.
Quizlet is always my trusty sidekick!
I hope this helps!
Cheers, July.
There is a potential difference of 12 V across a resistor with 0.25 A of current in it. The resistance of the resistor is?
Answer:
[tex]48 \Omega[/tex]
Explanation:
The resistance of the resistor can be calculated by using Ohm's law:
[tex]V=RI[/tex]
where
V is potential difference across the resistor
I is the current through the resistor
R is the resistance
In this problem, we have
[tex]V=12 V[/tex]
[tex]I=0.25 A[/tex]
So we can re-arrange Ohm's law to calculate the value of the resistance of the resistor:
[tex]R=\frac{V}{I}=\frac{12 V}{0.25 A}=48 \Omega[/tex]
Suchita makes a table to identify the variables used in the equations for centripetal force.
What quantities belong in cells X and Y?
X: tangential speed
Y: radius
X: radius
Y: tangential speed
X: centripetal force
Y: mass
X: mass
Y: centripetal force
Answer : The correct option is, X : radius and Y : tangential speed
Explanation :
Centripetal force : It is defined as a force which acts on the object to keep the object moving along a circular path.
Formula for centripetal force :
[tex]F_c=\frac{m\times V^2}{r}[/tex]
where,
[tex]F_c[/tex] = centripetal force
m = mass
r = radius
V = tangential speed
The quantity belong in cell X is radius and in the cell Y is tangential speed
Hence, the correct option is, X : radius and Y : tangential speed
Elaborate on the reason why heating water up will increase the rate of dissolving for a solute.
This is because heat energy is released when the solute dissolves in solution. Increasing temperature introduces more heat into the system. ... This increase in kinetic energy allows greater movement in the gas particles resulting in the intermolecular bonds between the gas solute and solvent being broken.
Answer:D
Explanation:
Carter pushes a bag full of basketball jerseys across the gym floor. The he pushes with a constant force of 21 newtons. If he pushes the bag 9 meters in 3 seconds, how much power does he use? (Hint: 1 watt = 1 .) A. 3 watts B. 7 watts C. 27 watts D. 63 watts E. 189 watts
Work = (force) x (distance)
Work = (21 Newtons) x (9 meters) = 189 Joules
Power = (work done) / (time to do the work)
Power = (189 Joules) / (3 sec)
Power = (63 watts/sec)
Power = 63 watts (D)
The tenancy of a moving object to continue moving in a strait line or a stationary object to remain in place is called
The tendency of a moving object to continue moving in a straight line or a stationary object to remain in place is called inertia.
According to law of inertia, an object maintains its state of rest or motion unless acted upon by an external force. an object can not move on its own unless force is applied on it to move it. also an object can not come to stop on its own unless acted upon by an external force to stop it.This is also known as newton's first law.
Will Mark BRAINLIEST!!!!!!!!!!!!!!!!!!!
3. Jessica stretches her arms out 0.6 m from the center of her body while holding a 2 kg mass in each hand. She then spins around on an ice rink at 1.1 m/s.
a. What is the combined angular momentum of the masses?
b. If she pulls her arms in to 0.15 m, what is her linear speed if the angular momentum remains constant?
3.
a)
r = distance of each mass in each hand from center = 0.6 m
m = mass of each mass in each hand = 2 kg
v = linear speed = 1.1 m/s
L = combined angular momentum of the masses = ?
Combined angular momentum of the masses is given as
L = 2 m v r
L = 2 (2) (1.1) (0.6)
L = 2.64 kg m²/s
b)
v' = linear speed when she pulls her arms = ?
r' = distance of each mass from center after she pulls her arms = 0.15 m
Using conservation of momentum , angular momentum remains same, hence
L = 2 m v' r'
2.64 = 2 (2) (0.15) v'
v' = 4.4 m/s
What is the speed of a wave with a wavelength of 10 mm and a frequency of 5.0 Hz?
Final answer:
The speed of a wave with a wavelength of 10 mm and a frequency of 5.0 Hz is calculated by the formula v = f λ. Multiplying the frequency (5.0 Hz) by the wavelength (10 mm or 0.01 m) results in a wave speed of 0.05 m/s.
Explanation:
The speed of a wave can be found by multiplying its frequency (f) by its wavelength (λ). This relationship is given by the equation v = f λ, where v is the speed of the wave, f is the frequency, and λ is the wavelength.
Using the given details for the student's question, with a wavelength of 10 mm (which is 0.01 meters) and a frequency of 5.0 Hz, the speed v of the wave is calculated as follows:
v = f × λ
v = 5.0 Hz × 0.01 m
v = 0.05 m/s
Therefore, the speed of the wave is 0.05 meters per second (m/s).
please help on this one ? :)
KE depends on velocity. It is easier to answer this question in terms of the earth.
The closer the object (earth/comet) is to the sun, the faster it moves. that means that the fastest moving point would be as the comet/earth passes through point C.
The slowest speed would be the furthest away from the sun which is point A.
Answer: The faster the planet moves the greater the Kinetic Energy.
The Slower the planet moves, the less the KE.
Point A is where it is slowest with the lowest amount of energy.
Discussion
The formula for KE is KE = 1/2mv^2. The mass of the comet or earth is a constant. It doesn't change no matter which point the comet passes through. If v goes down KE will go down. If v goes up, KE goes up.
You posted the same picture yesterday, and learned that ‘C’ is the point of the MOST kinetic energy because it’s closest to the sun and moving fastest. Then I suggested that you review Kepler’s 2nd law.
From that answer OR from Kepler, it should be clear that the LEAST kinetic energy is at ‘A’ .
A scientist must only base his or her conclusions on observable evidence from investigation
is this a true of false cuz if so this it true
https://prnt.sc/ltsn4z
A bowling bowl is thrown off the top of a building. Determine distance the ball has fallen after falling for 3.0 s. Remember, the gravitational acceleration (g) is 9.8 m/s2. (Hint: d = ½gt2)
A 3 kg lunch box is pushed across the lunch table. The acceleration of the lunch box is 2.0 m/s2. What was the net force applied to the lunch box? (Hint: F = ma) Show all your work!
Find the weight of a 10 kg rock. Remember, acceleration due to gravity is -9.8 m/s2. (Hint: w = mg) Show all your work!
Question 1:
d = distance the bowling ball has fallen = ?
g = acceleration due to gravity acting on the ball by earth = 9.8 m/s²
t = time of fall for the ball = 3.0 s
distance the ball has fallen is given as
d = (0.5) g t²
inserting the above values in the equation above
d = (0.5) (9.8 m/s²) (3.0 s)²
d = (0.5) (9.8 m/s²) (9.0 s²)
d = (4.9 m/s²) (9.0 s²)
d = 44.1 m
Question 2 :
m = mass of the lunch box pushed = 3 kg
a = acceleration of the lunch box = 2 m/s²
F = net force acting on the lunch box
as per newton's second law , net force is given as
F = ma
F = 3 x 2
F = 6 N
Question 3 :
m = mass of rock = 10 kg
g = acceleration due to gravity = 9.8 m/s²
W = weight of the rock
weight of rock is given as
W = mg
W = 10 x 9.8
W = 98 N
what is the net force acting on Hector and the toboggan?
a. 245 N
b. 735 N
c. 490 N
d. 980 N
Answer:
C.490N
Explanation:
in chemistry, the law of conversation allows for energy allows for which of the following?
B. Energy to be stored
The force on an object is given by the equation F = ma. In this equation, F is the force, m is the mass, and a is the acceleration. What is the force on an object that has a mass of 10 kg and an acceleration of 2.5 m/s^2
A. 4 N
B. 0.25 N
C. 25 N
D. 12.5 N
Formula
F= ma
Givens
m = 10 kga= 2.5 m/s^2Solution
F = 10 * 2.5F = 25 NewtonsAnswer
C
Final answer:
The force on an object with a mass of 10 kg and an acceleration of 2.5 m/s² is calculated using F = ma, resulting in a force of 25 N.
Explanation:
Calculating Force Using Newton's Second Law of Motion
To find the force exerted on an object with a mass of 10 kg and an acceleration of 2.5 m/s², we use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object times its acceleration. In formula form, it is written as F = ma.
So, we calculate the force by multiplying the mass of the object by its acceleration:
F = (10 kg) × (2.5 m/s²) = 25 N
Thus, the force on the object is 25 Newtons (N), which corresponds to answer choice C.
What type of particle results from the formation of a covalent bond?
proton
ion
atom
molecule
Answer: molecule
Explanation:
Covalent bond is the type of bond formed when there is sharing of electrons between two similar or different atoms.
1. Proton is the subatomic particle of an atom which is present in the nucleus of atom and bears positive charge.
2. Ions are formed when there is a loss or gain of electrons in an atom.
3. An atom is smallest unit of a matter or substance.It consist of three subatomic particles : electrons, protons, neutrons.
4. Molecules of element is a pure substance which is formed by bonding of atoms of similar elements. Example: [tex]H_2[/tex] .Molecule of compound is a pure substance which is formed by bonding of atoms of different elements combined together in a fixed ratio by mass. Example: [tex]H_2O[/tex]
A car is traveling at 20meters/seconds and is brought to rest by applying brakes over a period of 4 seconds what is it's average acceleration over this time interval?
v=vo-at<=>0=20-4a<=>4a=20=>a=5 m/s^2
plz help WILL GIVE BRAINLIEST
If force = mass x acceleration, What is the force applied to a 20 kg rock that is acceleration at a 20 m/s^2? Question 12 options: 40 N 0 N 20 N 10 N
If force = mass x acceleration, and you're walking down the street one day and you see a 20kg rock that is accelerating at 20 m/s², then you can say to yourself:
"Self ! That rock has 20 kg of mass and it's accelerating at 20 m/s², and since force = mass x acceleration, the net force acting on the rock must be (20kg) x (20 m/s²) which is 400 Newtons. How strange that 400 N is not one of choices under the question!"
A stopwatch starts while race car travels at 4 m/s from the pit area and accelerates at a uniform rate to a speed of 23 m/s in 2 s moving on a circular track of radius 527 m.
Assuming constant tangential acceleration, find
(a) the tangential acceleration, and
(b) the radial acceleration,at the instant when the speed is v = 16
Once you have both of those ... find the magnitude of a at any moment
(a) Tangential acceleration: [tex]9.5 m/s^2[/tex]
The tangential acceleration is given by:
[tex]a_t = \frac{v-u}{t}[/tex]
where
v = 23 m/s is the final velocity of the car
u = 4 m/s is the initial velocity of the car
t = 2 s is the time taken for the car to accelerate from u to v
Substituting the numbers into the formula, we find
[tex]a_t = \frac{23 m/s-4 m/s}{2 s}=9.5 m/s^2[/tex]
(b) Radial acceleration: [tex]0.49 m/s^2[/tex]
The radial acceleration is equivalent to the centripetal acceleration, which is given by:
[tex]a_r = \frac{v^2}{r}[/tex]
where
v = 16 m/s is the tangential speed
r = 527 m is the radius of the circular orbit
Substituting numbers, we find
[tex]a_r = \frac{(16 m/s)^2}{527 m}=0.49 m/s^2[/tex]