Atoms with an electric charge come charged by gaining or losing

Answer:

C

Explanation:

The higher the temperatures the higher the kinetic energy of the particles. This is because the particles move more rapidly and faster with increased temperatures. This is why the more you heat a substance it changes phases as it molecules/particles move more rapidly and collide with more force.

The average kinetic energy of the particles of a substance is directly proportional to the temperature of the substance (Option C).

In conclusion, the average kinetic energy of the particles of a substance is directly proportional to the temperature of the substance (Option C).

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The answer is that you have to write this in your own words.

To help you on how to get started, here's what you need to do:

Just say what planet you want to go and why you want to go there. Then, say what you wish to learn on that planet.

Template: My space mission would be going to planet _______. I would like to go there because ___________________. I hope to learn that ________________.

Our space mission involves studying Mars' geological features and potential for life. This will enhance our understanding of the possibility of life beyond our solar system and specifically detail the environment on Mars. The mission might also reveal evidence of past or present life.

Our space mission will aim to explore the unique geological features and potential habitability of Mars. Mars is a planet of particular interest due to evidence suggesting its past was warmer and wetter, hinting at the possibility of life beyond our solar system.

We wish to explore this aspect of the solar system because it could fundamentally alter our understanding of life's existence in the universe. The mission will involve the use of hi-tech equipment to identify potential biomarkers, signs of past or present life.

Through this mission, we hope to learn more about the environment on Mars, detail its capacity for sustaining life, and possibly find evidence of life itself. Our findings will not only influence future Mars missions but also add a significant chapter to our understanding of life in the universe.

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Red and yellow make orange.

Red and yellow mix together to create the color orange.

When you mix red and yellow, you are essentially combining their respective pigments or light wavelengths.

Red has a longer wavelength and is a primary color, meaning it cannot be made by combining other colors. On the other hand, yellow, which is a primary hue as well, has a medium wavelength.

The color orange is perceived as a new color when red and yellow are combined. This occurs as a result of the red pigment's or wavelength's stimulation of our eyes' long-wavelength receptors and the yellow pigment's or wavelength's stimulation of our eyes' medium-wavelength receptors. The brain interprets the mix of inputs as the color orange after processing the data from these receptors.

When red and green light are combined at their maximum intensity in the RGB (Red, Green, Blue) color model, they produce yellow rather than orange. Red and yellow combine to form orange in the subtractive color model, which is the one utilized for physical pigments like paint. This is caused by variations in how light and pigments interact to create perceptions of color.

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Answer:

Part A: 10.7.

Part B: 2) the solution is basic.

Part C: 5.9.

Part D: 1) the solution is acidic.

Part E: 8.1.

Part F: 2) the solution is basic.

Explanation:

Part A [OH−]= 4.5×10−4 M . Express your answer using two significant figures.  

∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

[OH⁻] = 4.5×10⁻⁴ M.

∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻]  = 10⁻¹⁴/(4.5×10⁻⁴  M) = 2.22 × 10⁻¹¹ M.

∵ pH = - log[H₃O⁺]

∴ pH = - log(2.22 × 10⁻¹¹) = 10.65 ≅ 10.7.

Part B 1) the solution is acidic 2) the solution is basic 3) the solution is neutral  

The solution is basic, because the pH is higher than 7.

Part C [OH⁻]= 7.7×10⁻⁹ M . Express your answer using two significant figures.  

∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

[OH⁻] = 7.7×10⁻⁹ M.

∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻]  = 10⁻¹⁴/(7.7×10⁻⁹ M) = 1.29 × 10⁻⁶ M.

∵ pH = - log[H₃O⁺]

∴ pH = - log(1.29 × 10⁻⁶) = 5.88 ≅ 5.9.

Part D 1) the solution is acidic 2) the solution is basic 3) the solution is neutral  

The solution is acidic, because the pH is lower than 7.

Part E A solution in which [OH−] is 140 times greater than [H+]. Express your answer using two significant figures.  

∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

∵  [OH⁻] = 140[H₃O⁺]

∴ [H₃O⁺](140[H₃O⁺]) = 10⁻¹⁴.

∴ 140 [H₃O⁺]² = 10⁻¹⁴.

[H₃O⁺]² = 10⁻¹⁴/ 140 = 7.14 x 10⁻¹⁷.

∴ [H₃O⁺] = √(7.14 x 10⁻¹⁷) = 8.45 x 10⁻⁹ M.

∵ pH = - log[H₃O⁺]

∴ pH = - log(8.45 x 10⁻⁹) = 8.07 ≅ 8.1.

Part F 1) the solution is acidic 2) the solution is basic 3) the solution is neutral

The solution is basic, because the pH is higher than 7.

The [H+] for solutions with given [OH−] are calculated using the ion product of water, with solutions having [H+] less than 1.0 × 10-7 being basic and those with more being acidic. The solutions for Part A and E were found to be basic while the solution for Part C was found to be acidic.

The [H+] of a solution can be determined from its [OH−] by using the ion product of water, which is 1.0 × 10-14 at 25°C. This can be represented by the equation [H+][OH−] = 1.0 × 10-14.

For Part A, you needed to calculate [H+] for a solution with [OH−] = 4.5 × 10-4M. [H+] = 1.0 × 10-14 / [OH−] = 1.0 × 10-14 / 4.5 × 10-4= 2.2 × 10-11 M. Since [H+] is less than 1.0 × 10-7, the solution is basic.

For Part C, [OH−] is 7.7 × 10-9M. [H+] = 1.0 × 10-14 / 7.7 × 10-9= 1.3 × 10-6M. Because [H+] is higher than 1.0 × 10-7, the solution is acidic.

In Part E, the solution's [OH−] is 140 times that of [H+]. Therefore, if we let [H+] = x, we get [OH−] = 140x. Since [H+][OH−] = 1.0 × 10-14, we get x(140x) = 1.0 × 10-14. Solving for x, we get [H+] = x = 5.37 × 10-14M. Since [H+] is less than 1.0 × 10-7, the solution is basic.

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Answer:

Basic solution.

Explanation:

∵ pOH = -log[OH⁻] = - log(1.0 x 10⁻⁴) = 4.

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 4 = 10.

Since, the pH of the solution is 10 (> 7) and the concentration of [OH⁻]  is 1.0 x 10⁻⁴ (> 1.0 x 10⁻⁷) is a basic solution.

Answer:

The solution is basic

Explanation:

Given:

Concentration of OH- = 1*10⁻⁴ m

To determine:

The nature of the solution i.e. acidic or basic

Formula:

A solution where the pH = 7 is neutral

pH < 7 is acidic

pH > 7 is basic

[tex]p[OH] = -log[OH-] = -log[1*10^{-4}] = 4\\ \\p[H] + p[OH] = 14\\\\Therefore\ pH = 14 - p[OH] = 14 - 4 = 10[/tex]

Since, pH > 7, the solution is basic

Older people had no money to buy stuff

Answer:

The recent graduate invests taking risks and betting on profitability.

The retired man protects the estate by sacrificing the gain.

Explanation:

Answer:

Explanation:

1) Word equation (given)

2) Kind of reaction

This is a single replacement reaction.

Alkali metals is the group of metals in the group 1 of the periodic table. These are the most active metals, meaning that they react violently with water releasing hydrogen gas.

         Metal + Water → hydroxide + gaseous hydrogen

            X + H₂O → XOH(aq) + H₂ (g) ↑

3) Chemical equation

4) Balance

There is the same number of each atom on both sides: 2 K in the left and in the right, 4 H in the left and in the right, and 2 oxygen in the left and in the right. So, the equation is balanced.

The reaction of potassium metal with water produces potassium hydroxide and hydrogen gas, represented by the balanced chemical equation [tex]2K(s) + 2H_2O(l) \rightarrow 2KOH(aq) + H_2(g)[/tex]

The balanced chemical equation for the reaction between potassium metal (K) and liquid water (H2O) is:

[tex]2K(s) + 2H_2O(l) \rightarrow 2KOH(aq) + H_2(g)[/tex]

In this reaction, potassium metal reacts vigorously with water to produce potassium hydroxide (KOH), which is an alkali, and hydrogen gas ([tex]H_2[/tex]). This is an exothermic reaction and heat is also released. The products include the aqueous potassium hydroxide and gaseous hydrogen. The equation is balanced with two atoms of potassium and two molecules of water on the reactant side, and two formula units of potassium hydroxide and one molecule of hydrogen gas on the product side.

To draw the structure of each reaction first determine the product of the reaction and then draw the structure by using the line formula method.

In chemistry, the word product refer to the substance or substances after a reaction. For example in the reaction H2+O = H2O, the product is water (H2O).

Note: This question is incomplete; due to this, I answered it based on general knowledge.

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Answer:

1) Add more sulfate ions.

2) 1 M K₂SO₄.

Explanation:

1) Which of the following actions would shift this reaction toward solid barium sulfate?

Add more sulfate ions will increase the concentration of the products side, so the reaction will be shifted towards the reactants side to relieve the stress and attain the equilibrium again.

So, the right choice is: Add more sulfate ions.

2) In which of the following would barium sulfate be least soluble?  

The answer is 1 M K₂SO₄, it has a common ion effect of SO₄⁻ ions that increase the concentration of the products side, so the reaction will be shifted towards the reactants side to relieve the stress and attain the equilibrium again.

So, the solubility will decrease.

1. b) Adding more sulfate ions shifts the reaction towards solid barium sulfate.

2. Barium sulfate is least soluble in a c) 1 M K₂SO₄ solution.

1. Le Châtelier's principle states that if a stress is applied to a system at equilibrium, the system will shift to relieve that stress.

For the reaction:

To shift this reaction towards solid barium sulfate, one must consider the factors that affect the equilibrium. Using Le Châtelier's principle:

Hence, adding more sulfate ions would shift the reaction towards the solid barium sulfate. The correct option is b).

2. Solubility Consideration

Barium sulfate would be least soluble in a 1 M K₂SO₄ solution. This is because K₂SO₄ provides additional SO₄²⁻ ions, which increases the common ion effect, thus decreasing the solubility of BaSO₄. The correct option is c).

Question: Le Châtelier's principle states that if a stress is applied to a system at equilibrium, the system will shift to relieve that stress. This is true for all types of equilibrium, including the dissolution of salts that are only sparingly soluble.

Here is the chemical reaction that represents solid barium sulfate dissolving in water:

BaSO₄(s) ⇌ Ba₂+(aq) + SO₄²⁻(aq), with Ksp = 1.1×10⁻¹⁰

1. Which of the following actions would shift this reaction toward solid barium sulfate?

a) Add more barium sulfate.

b) Add more sulfate ions.

c) Remove sulfate ions.

d) Remove barium ions.

2. In which of the following would barium sulfate be least soluble?

a) pure water

b) 1 M NaNO3

c) 1 M K2SO4

Answer: option A, using 1 gram of powdered zinc.

Explanation:

The rate of chemical reactions are affected by a number of factors, which you can summarize in this form:

1) Concentration of the reactants

The more concentrate are the reactants, more frequently they will interact (collide) and will be able to yield product. So, the higher the concentration the higher the rate.

This means using 1 M hydrochloric acid, as the option B states, instead of 3 M (stated for the original reaction) will slow down the reaction instead of increase the rate.

The same is valid for the option D. Decreasing the concentration of zinc will not increase the rate of the reaction, but will decrease it.

2) Surface area of the reactants

Increasing the surface area will permit that the reactants reach a faster intimate contact, occurring more of collisions per unit of time, and, consequently increasing the rate of the reaction.

Then, option A, using 1 gram of powdered zinc, i.e. the same amount stated for the original reaction, but with more surface area, will produce the desired effect of increasing the rate of reaction.

3) Temperature

Higher temperatures means that the kinetic energies of the reactants are higher and so the collisions will occur with more energy and the probability of effective collisions will increase. Decreasing the temperature will have the opposite effect (the rate of reaction will decrease).

Hence, the option C, decreasing the temperature to 20° C will not increanse the rate of the reaction.

3) Catalyst

Catalyst ares substances that modify the path of the reaction, decreasing the activation energy and, consequently, increasing the rate of reaction. Since, none of the statements indicates the use of catalyst, this is not an option.

The correct option is A. using 1 gram of powdered zinc.

To understand why using powdered zinc would most likely increase the rate of the reaction, one must consider the factors that affect reaction rates. These factors include the concentration of reactants, the surface area of reactants, the temperature at which the reaction occurs, and the presence of a catalyst.

 In this case, the reaction between zinc and hydrochloric acid can be represented by the following equation:

[tex]\[ \text{Zn}(s) + 2\text{HCl}(aq) \rightarrow \text{ZnCl}_2(aq) + \text{H}_2(g)[/tex]

 Now, let's analyze each option:

 A. Using 1 gram of powdered zinc: Increasing the surface area of the zinc by using it in powdered form would increase the number of particles that can react with the hydrochloric acid at any given time. This would increase the rate of the reaction because more collisions between the zinc and hydrochloric acid molecules would occur, leading to a faster reaction rate.

B. Using 1 M hydrochloric acid: Decreasing the concentration of hydrochloric acid from 3 M to 1 M would actually decrease the rate of the reaction. According to the collision theory, a higher concentration of reactants leads to more frequent collisions and thus a faster reaction rate.

 C. Decreasing the temperature to 20°C: Generally, decreasing the temperature would decrease the kinetic energy of the particles, leading to fewer successful collisions and a slower reaction rate. The Arrhenius equation shows that the rate constant \(k\) is directly related to the temperature [tex]T[/tex] by the equation [tex](k = A \cdot e^{-\frac{E_a}{RT}}\)[/tex], where [tex]\(A\)[/tex] is the pre-exponential factor, [tex]\(E_a\)[/tex] is the activation energy, and [tex]R[/tex] is the gas constant.

 D. Decreasing the concentration of the zinc: This option would decrease the rate of the reaction for the same reason as option B. A lower concentration of zinc would mean fewer zinc particles are available to react with the hydrochloric acid, resulting in a slower reaction rate.

 Therefore, the most effective way to increase the rate of the reaction, based on the given options, is to increase the surface area of the zinc by using it in powdered form, which corresponds to option A.

Depends on the gas and grams of solute. If you were able to give me a gas i would be able to help you but i cannot without the gas or chemical makeup.

Intermolecular forces.

No. When water first begins to cool down, it contracts. However, as it gets colder and eventually freezes, it begins to expand.

You can test this by freezing water in a water bottle: when you take it out of the freezer, the cap might have popped off or cracks may have formed in the sides of the bottle.

Answer: Water expands when frozen, not contracts.

Answer:

1.5 mol/L.

Explanation:

∵ M = no. of moles of solute/V of the solution.

∴ M = (3.0 mol)/(2.0 L) = 1.5 mol/L.

The molarity of the given silver chloride solution is 1.5 M, calculated by dividing the number of moles of solute by the liters of solution. To find the concentration of chlorine, one must calculate the moles from the mass of each chloride compound, convert to grams, and divide by the solution volume in liters.

The molarity of a solution is defined as the number of moles of solute per liter of solution. For the first question provided with 3.0 moles of silver chloride (AgCl) dissolved to make a 2.0-liter solution, the molarity (M) can be calculated using the formula M = moles of solute / liters of solution. Therefore, the molarity is 1.5 M, because M = 3.0 moles / 2.0 liters.

For the second question, to calculate the concentration of chlorine in grams per liter, first determine the moles of chlorine in each compound, then convert the total moles to grams and divide by the volume of solution in liters. We can find the molar mass of CaCl₂, MgCl₂, and MnO₂, calculate how many moles of Cl are in each using their respective weights, and sum them up to find the total chlorine content. The grams of chlorine per liter can then be calculated by converting the total grams of chlorine to the volume of the solution.

Answer:

The pH of the solution is 6.35.

Explanation:

Concentration of hydroxide ions = [tex][OH^-]=2.20\times 10^{-8} M[/tex]

pH + pOH = 14

pH = 14 - pOH

[tex]pOH=-\log[OH^-][/tex]

[tex]pOH=-\log[2.20\times 10^{-8} M]=7.65[/tex]

[tex]pH=14-pOH=14-7.65=6.35[/tex]

The pH of the solution is 6.35.

The pH of the solution with a [tex]\( 2.20 \times 10^{-8} \)[/tex] M hydroxide ion concentration is approximately [tex]\( 6.34 \)[/tex].

To find the pH of a solution with a given hydroxide ion concentration [tex](\( [\text{OH}^-] \))[/tex], we can use the relationship between [tex]\( [\text{OH}^-] \)[/tex] and [tex]\( \text{pOH} \)[/tex], and then convert [tex]\( \text{pOH} \)[/tex] to pH.

The relationship between [tex]\( [\text{OH}^-] \)[/tex] and [tex]\( \text{pOH} \)[/tex] is:

[tex]\[ \text{pOH} = -\log([\text{OH}^-]) \][/tex]

Given [tex]\( [\text{OH}^-] = 2.20 \times 10^{-8} \) M[/tex], we can calculate [tex]\( \text{pOH} \)[/tex]:

[tex]\[ \text{pOH} = -\log(2.20 \times 10^{-8}) \][/tex]

[tex]\[ \text{pOH} = -\log(2.20) - \log(10^{-8}) \][/tex]

[tex]\[ \text{pOH} = -(\log(2.20) + (-8 \times \log(10))) \][/tex]

[tex]\[ \text{pOH} = -(0.3424 - 8 \times 1) \][/tex]

[tex]\[ \text{pOH} = -(0.3424 - 8) \][/tex]

[tex]\[ \text{pOH} = -(7.6576) \][/tex]

[tex]\[ \text{pOH} = -(-7.6576) \][/tex]

[tex]\[ \text{pOH} = 7.6576 \][/tex]

Now, we can convert [tex]\( \text{pOH} \)[/tex] to pH using the relationship:

[tex]\[ \text{pH} + \text{pOH} = 14 \][/tex]

[tex]\[ \text{pH} = 14 - \text{pOH} \][/tex]

[tex]\[ \text{pH} = 14 - 7.6576 \][/tex]

[tex]\[ \text{pH} = 6.3424 \][/tex]

pOH = 3.08

NX3 + H2O <----> NHX3+ + OH-  

Kb = 4.0 x 10^-6

Kb = c(NH₄⁺) · c(OH⁻) ÷ c(NH₃).

c(NH₄⁺) = c(OH⁻) = x.

x² = Kb · c(NH₃)

x² = 4.0 × 10⁻⁶ × 0.175 = 7.0 × 10⁻⁷.

x = c(OH⁻) = √(7.0 × 10⁻⁷)

    = 8.367 × 10⁻⁴

pOH = -log(c(OH⁻))

        =- log ( 8.367 × 10⁻⁴)

        = 3.08

Final answer:

To calculate the pOH of a 0.175 M aqueous solution of NX₃ with Kb of 4.0×10⁻⁶, we simplify the dissociation equation and find the OH- concentration to be approximately 1.67×10⁻³ M, resulting in a pOH of about 2.78.

Explanation:

To find the pOH of a 0.175 M aqueous solution of NX₃, given that Kb for NX3 is 4.0×10⁻⁶, we start by setting up the base dissociation reaction NX₃ + H₂O → NX₃H+ + OH−. The equilibrium expression associated with this dissociation is Kb = [NX3H+][OH−]/[NX3]. We can assume the concentrations of NX₃H+ and OH− to be equal (x) and much smaller than the initial concentration of NX₃, thus [NX₃] approximately equals 0.175 M. With these assumptions, Kb can be rewritten as 4.0×10⁻⁶ = x₂ / (0.175 − x).

Assuming x is much smaller than 0.175, we simplify to 4.0×10⁻⁶ ≈ x2 / 0.175. Solving for x gives us x ≈ √(4.0×10⁻⁶ ∗ 0.175) ≈ 1.67×10⁻³ M, which is the concentration of OH−. The pOH is calculated using the formula pOH = −log[OH−], resulting in pOH ≈ 2.78.

The branch of science that relates with the interaction of matter and electromagnetic radiation is spectroscopy. Thus, option C is correct.

Electromagnetic radiations are given as the beam of protons with the presence of the perpendicular magnetic and electrical waves travelling at the speed of light.

The interaction of the electromagnetic radiations with the matter results in the propagation of the valence electrons of matter to the higher energy level and creating transitions.

These interactions between the electromagnetic radiations and matter are studies with spectroscopy. Thus, option C is correct.

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The pH IS 9.6

Moles NH3 initially present = 0.0750 L X 0.2 mol/L = 0.015 mol NH3  

Moles HNO3 added = 0.015 L X 0.500 mol/L = 7.5X10^-3 mol HNO3 added  

NH3 + HNO3 --> NH4+ + NO3-  

So, after the addition, the solution contains 7.50X10^-3 mol NH4+ and 9.5X10^-3 mol NH3. The concentrations are:  

[NH4+] = 7.5X10^-3 mol / 0.090 L = 0.0833 M  

[NH3] = 1,5X10^-2mol / 0.090 L = 0.1667 M  

The equilbirium involved is:  

NH3 + H2O <--> NH4+ + OH-  

Kb = [NH4+][OH-]/[NH3] = 1.8X10^-5  

1.8X10^-5 = (0.0833)[OH-]/0.1667  

[OH-] = 3.602 X10^-5  

pOH = 4.44

pH = 14.00 - pOH

     = 9.557 or 9.6

I believe the answer is A. However, I would double check the formula.

The isomer of the given structure of the Butane is Iso-Butane. Therefore, option (B) is correct.

Structural isomers are those isomers with the same molecular formulas but the atoms are completely arranged in a different manner. These are the molecules having the same molecular formula with different connectivities among the atoms.

For example, the structure of alkane (C₄H₁₀) is representing structural isomers with different structures. As there is an increase in the number of carbon atoms, the structural isomers of the alkane molecule increase.

The phenomenon of this structural isomer is known as structural isomerism. Structural isomerism is also known as constitutional isomerism as per the IUPAC.

The molecular formula of the butane is C₄H₁₀ where the linear chain of the four carbon atoms of butane is n-butane isomer. While the branched chain of the butane is an iso-butane isomer in which one carbon is tertiary.

Therefore, the structure in option (B) is isobutane, which is an isomer of butane.

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A. Zinc (Zn)

Like all the other metals, it has a cloud of an electron because of the free electrons in the valence shell. These electrons are easier to move.

When some electric force is applied, the electrons start moving towards the positive end due to the attraction. This causes the flow of electrons, and, ultimately, the generation of electricity. Zinc one has 27%

Answer:

A

Explanation:

It is formed after the star has ended its star cycle into a supernova. The star collapsed into a neutron star that is smaller than the progenitor star but has inherited angular momentum. IT, therefore, spins faster emitting electromagnetic radiation that seems to pulsate.

Answer:

A)   Pulsar

Explanation:

Pulsars are collapsed cores of stars usually supergiant stars

this happens when a supernova leaves behind the star core that has no outer protection layer of high gravity so the core collapses in on itself to create a very high magnitude star and also has trillions more mass.  

Answer:

From the chemical formula of a compound you can learn about its composition:

Also, with the ratios and the atomic masses of each kind of atom, you can obtain the mass composition (%) of the compound.

Explanation:

Using indexes (subscripts), the chemical formula of a compound shows  the elements (kind of atoms) in the compound and the relative proportions of those elements.

The following example will show you how you learn that information from the chemical formula.

A very familiar compound is water and its chemical formula (also very familiar) is H₂O.

From that, you learn that water (a chemical compound):

        * hydrogen, H: 2 × 1.008 g/ mol = 2.016 g/,ol

        * oxygen, O: 1 × 15.999 g/mol = 15.999 g/mol

        * Molar mass of water: 2.016 g/mol + 15.999 g/mol = 18.015 g/ mol

        * H: (2.016 g/mol / 18.015 g/mol) × 100 = 11.19%

        * O: (15.999 g/mol / 18.015 g/mol) × 100 = 88.81%

No you can’t do that, that’s idiotic

Answer:

C) 8.9x10-19M

Explanation:

Whe disolving a solid in water, this solid splits in anions and cations, in our example for CuS solid:

CuS (s) -------> Cu+2 (ac)  +   S-2 (ac)

Whe this solution is saturated, and balance is reached, this balance can be represented with Ksp formula (solubility constant), as following:

Ksp= [Cu+2][S-2], and for tgis ecuation, you only consider aqueous ions, but not the solid salt

When balance is reached, you may suppose that "X" moles of CuC gives you "X" moles of Cu+2 and "X" moles of S-2 (according to the stoicheometry of the above reaction):

XCuS (s) ------> XCu+2(ac)  +  XS-2(ac) , for which:

[Cu+2]=X and [S-2]=X so this gives us: Ksp=8x10-37=X.X=X²

X= √8x10-37 and finally X=[Cu+2]=8.9x10-19M (expressed in molar units)

The spoon will get warmer as it takes in the heat of the water

Answer: Phosphorylation

Answer:

= 230 ppb

Explanation:

Considering that;

1ppm = 1mg/L  

Then;

0.00023g = 0.23mg  

Therefore;

0.00023 g/L = 0.23 mg/L

0.23 mg/L = 0.23 ppm

1 ppm = 100 ppb

Therefore;

0.23 ppm = 0.23 ×1000

                = 230 ppb

Answer:

0.23 ppm , 230 ppb  

Explanation:

1 ppm (parts per million) is equivalent to 1 mg of SO₂ in 1 L of the water

Given mass of SO₂ = 0.00023 g = 0.00023 x 1000 mg (1g = 1000 mg) = 0.23 mg

So 0.23 mg/ L = 0.23 ppm

1 ppb (parts per billion) (10⁹) = 1000 ppm (parts per million) (10⁶)

0.23 ppm x 1000 = 230 ppb  

Copper nitrate and nitric oxide are produced in this reaction.

The digestion of copper wire by nitric acid is a redox reaction producing copper(II) nitrate, nitrogen dioxide, and water. The resulting copper salts are blue in solution.

The digestion of solid copper wire by nitric acid is a type of redox reaction.

When copper metal reacts with concentrated nitric acid, it forms aqueous copper(II) nitrate, accompanies by the release of brown fumes of nitrogen dioxide (NO₂) and water. This chemical reaction is influenced by factors such as concentration of the acid, the metal's activity, and temperature. With concentrated nitric acid, copper generally reduces the acid to nitrogen dioxide.

In a redox reaction, there is a transfer of electrons between the reacting species, with one substance being oxidized (losing electrons) and the other being reduced (gaining electrons).

For the reaction of copper with concentrated nitric acid, the balanced chemical equation would reflect the formation of Cu(NO₃)₂ and NO₂, which can be represented as follows after balancing:

Cu(s) + 4HNO₃(aq) → Cu(NO₃)₂(aq) + 2NO₂(g) + 2H₂O(l).

Copper salts, such as Cu(NO₃)₂, are characterized by a blue color in solution, which indicates the presence of copper(II) ions that have emerged from the copper metal.

PH = 7.58

KOH will interact with HClO to provide KClO. you may have an answer that contains unreacted HClO and KOH. this is often a solution.

HClO + KOH → KClO + H2O

HClO reacts with KOH in a very 1: 1 molar ratio

Mole of acid in 50 ml of an answer of 0.150 m = 50/1000 * 0,150 = 0.0075 mole of acid

Mole of KOH in 30 ml of 150 M solution = 30/1000 * 0,150 = 0.0045 mole of KOH

This reacts to provide 0.0045 moles of KClO and there are 0.0030 moles of HClO unreacted

The volume of the answer = 50 ml + 30 ml = 80 ml = 0.080 l

Deposition of acid in solution = 0.0030 / 0.080 = 0.0375M

KClO deposit in solution = 0.0045 / 0.080 = 0.0562 m

pKa HClO = -log (4.0 * 10 ^ -8) = 7.40

PH = pKa + log ([KClO] / [HClO])

PH = 7.40 + notes (0.0562 / 0.0375)

PH = 7.40 + 1.50 notes

PH = 7.40+ 0.18

PH = 7.58

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Mole of Acid  https://brainly.com/question/9465562

HClO  https://brainly.com/question/12355703

Details

Grade: College

Subject: Chemistry

Keyword: mole, acid, HClO

Final answer:

In this titration of HClO with KOH, the pH at different volumes of added base is calculated. At 0.00 mL, the pH requires the ionization constant of HClO. At 15.0 mL, the pH is 0.903. At 25.0 mL, the pH is 7. At 30.0 mL, the pH is 14.

Explanation:

In this titration, we are diluting a 0.150 M solution of HClO with a 0.150 M solution of KOH. The goal is to calculate the pH at different volumes of added base.

In summary, the pH at different volumes of added base in the titration of HClO with KOH is as follows: 0.00 mL: pH = ? (Requires ionization constant of HClO); 15.0 mL: pH = **0.903**; 25.0 mL: pH = **7**; 30.0 mL: pH = **14**.

Answer:

The answer is "solubility is how much solvent will dissolve in solute."

Explanation:

Final answer:

Solubility is the amount of solute that can dissolve in a given quantity of solvent at a certain temperature and pressure, resulting in a saturated solution.

Explanation:

Solubility is defined as the maximum amount of a substance (solute) that can dissolve in a given amount of solvent at a specified temperature and pressure, leading to a saturated solution. It is often expressed in grams of solute dissolved in 100 grams of solvent.

The concept of solubility is essential in chemistry as it helps predict the behavior of substances in various environments and is a key factor in reactions like precipitation.

For instance, when a solution's concentration exceeds the substance's solubility, the excess will precipitate out of the solution. Meanwhile, substances with low solubility tend to precipitate readily under most conditions.

The phrase 'like dissolves like' is a useful heuristic that indicates that polar solvents will typically dissolve polar solutes, while nonpolar solvents will dissolve nonpolar solutes. This is key when trying to determine if a solute will be soluble in a given solvent.