Be-6 what must be done with the vessel’s registration paper?

Answers

Answer 1
This is not a chemistry question. May be someone believed that Be-6 identified a chemical element, but it does not.

This question is about boats, documents and the rules to navigate.

Vessel's registration paper must be kept aboard whenever you are navigating or operating.

That is the answer: keep the documents aboard.


Answer 2

The Certificate of Documentation must stay onboard a Vessel Registration Number while it is in US waters, in accordance with Title 46 for the Code of Federal Regulations (CFR), Part 67.

Make sure it complies with the following specifications. Your boat's or vessel's bow must have their Vessel Registration Number permanently painted or fastened to either side be shown in larger than three-inch-high figures and simple, vertical block letters. The Certificate of Documentation must stay onboard a vessel while it is in US waters, in accordance with Title 46 for the Code of Federal Regulations (CFR), Part 67.

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Related Questions

Is laundry detergent an element compound or mixture?

Answers

laundry detergents are commonly mixtures of chemical compounds
It is a mixture 

I hoped I helpd and if you need more you could always ask me :)

-Dawn

In the reaction 2 c o2 → 2 co, how many moles of carbon are needed to produce 66.0 g of carbon monoxide

Answers

The solution would be like this for this specific problem:

Given:

66.0 g of carbon monoxide

reaction 2 C + O2 → 2 CO

 

mol e= mass / molar mass 
mole of 2CO = 66.0g / (12.011  15.999)g / mol 
mole of 2CO = 2.36 (CO and C has a 1:1 mole ratio) 

mole of 2CO = 2.36 -> mole of 1 CO = 2.36 / 2 = 1.18 

We got 2 moles of C, thus 1.18 x 2 = 2.36

So, we 2.36 moles of carbon are needed to produce 66.0 g of carbon monoxide in the reaction 2 C + O2 → 2 CO.   To add, Carbon nonmetallic and tetravalent, thus, making four electrons available to form covalent chemical bonds. 

In the given reaction moles of carbon are needed to produce 66.0 g of carbon monoxide is 2.35 moles.

How we calculate moles?

Moles of any substance will be calculated as:

n = W/M, where

W = given mass

M = molar mass

Given chemical reaction is:

2C + O₂ → 2CO

Moles of 66g of CO = 66g / 28g/mol = 2.35 mol

2 moles of CO = produced by 2 moles of carbon

2.35 moles of CO = produced by 2.35 moles of carbon

Hence, required moles of carbon are 2.35 moles.

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Which of the following does not describe a characteristic of carbon?
A.) It is non-metallic
B.) It has four valence electrons
C.) It has an electron configuration of 1s2s2p2
D.) It forms bonds only, with itself and not other atoms.

Answers

The characteristic that is not descriptive of C, would be D. It forms bonds with only itself. It forms bonds with almost all other nonmetals, present, like H,O,N, etc.
Carbon can bond with other atoms, such a oxygen, to produce carbon monoxide, carbon dioxide etc.

If 1.20 moles of an ideal gas occupy a volume of 18.2 l at a pressure of 1.80 atm, what is the temperature of the gas, in degrees celsius?

Answers

We can calculate for temperature by assuming the equation for ideal gas law:

P V = n R T

Where,

P = pressure = 1.80 atm

V = volume = 18.2 L

n = number of moles = 1.20 moles

R = gas constant = 0.08205746 L atm / mol K

Substituting to the given equation:

T = P V / n R

T = (1.8 atm * 18.2 L) / (1.2 moles * 0.08205746 L atm / mol K)

T = 332.70 K

We can convert K unit to ˚C unit by subtracting 273.15 to Kelvin, therefore

T = 59.55 ˚C

If 1.20 moles of an ideal gas occupy a volume of 18.2 L at a pressure of 1.80 atm, what is the temperature of the gas, in degrees Celsius?
-125°C
59.5°C
273°C
32°C

Answers

The equation that we will use to solve this problem is :
PV = nRT where:
P is the pressure of gas = 1.8 atm
V is the volume of gas = 18.2 liters
n is the number of moles of gas = 1.2 moles
R is the gas constant =  0.0821
T is the temperature required (calculated in kelvin)

Using these values to substitute in the equation, we find that:
(1.8)(18.2) = (1.2)(0.0821)(T)
T = 332.5 degree kelvin

The last step is to convert the degree kelvin into degree celcius:
T = 332.5 - 273 = 59.5 degree celcius

What number of atoms of phosphorus are present in 1.00g of each of the compounds in exercise 48?

Answers

Answer:

Explanation:

The compounds in exercise 48 are:

a) P4O6,

b) Ca3 (PO4)2, and

c) Na2 H PO4

So, proceed with the calculus for each compound.

a) Molecular formula: P4O6

Molar mass: 4 * 31 g/mol + 6* 16g/mol = 220 g/mol

Number of moles in 1.00 grams of compound = mass in grams / molar mass =

= 1.00 g / 220 g/mol = 0.004545 mol

0.004545 mol of P4O6 contains 4 * 0.004545 =  0.01818moles of atoms of P.

=> 0.01818 moles * 6.022 * 10^23 atoms / mol = 1.095 * 10^ 22 atoms of P.

Answer: 1.095 * 10^22 atoms of P.

b) Ca3 (PO4)2

molar mass = 3 * 40.1 g/mol + 2 * 31.0 g/mol + 8 * 16 g/mol = 310.3 g/mol

number of moles in 1.00 g of Ca3 (PO4)2 = 1.00 g / 310.3 g/mol = 0.00322 mol

0.00322 mol of compound * 2 mol P / mol of compound = 0.00644 mol P

0.00644 mol P * 6.022 * 10^23 atom / mol = 3.878 * 10 ^ 21 atoms P

Answer: 3.878 * 10^21 atoms P

c) Na2 H PO4

molar mass = 2 * 23.0 g/mol + 1 g/mol + 31.0 g/mol + 4 * 16g/mol = 142.0 g/mol

number of moles = 1.00 g / 142.0 g/mol = 0.0070 moles Na2HPO4

=> 0.0070 moles P

=> 0.0070 * 6.022 * 10^23 = 4.215 * 10^21 atoms of P

Answer: 4.215 * 10^21 atoms P

Final answer:

To determine the number of atoms of phosphorus in a compound, you need to use the molar mass and Avogadro's number. Convert the mass of the compound to moles and then multiply by Avogadro's number to get the number of atoms.

Explanation:

The number of atoms of phosphorus present in a compound can be determined using the molar mass and Avogadro's number. We need to convert the mass of the compound to moles using its molar mass, and then multiply by Avogadro's number to get the number of atoms.

For example, if we have 1.00g of phosphorus pentoxide (P2O5), we can calculate the number of atoms of phosphorus by:

Calculating the moles of P2O5 using its molar mass (141.94 g/mol) Converting the moles of P2O5 to moles of phosphorus using the ratio in the balanced equation (2 moles of P per 1 mole of P2O5) Multiplying the moles of phosphorus by Avogadro's number (6.022 x 1023 atoms/mol)

The result will be the number of atoms of phosphorus in 1.00g of P2O5.

Green plants use light from the sun to drive photosynthesis. photosynthesis is a chemical reaction in which water and carbon dioxide chemically react to form the simple sugar glucose and oxygen gas.what mass of water is consumed by the reaction of carbon dioxide

Answers

The equation that represents the process of photosynthesis is: 


6CO2+12H2O+light->C6H12O6+6O2+6H2O


Photosynthesis is the process in plants to make their food. This involves the use carbon dioxide to react with water and make sugar or glucose as the main product and oxygen as a by-product. Since we are not given the mass of CO2 in this problem, we assume that we have 1 g of CO2 available. We calculate as follows:


1 g CO2 ( 1 mol CO2 / 44.01 g CO2 ) ( 12 mol H2O / 6 mol CO2 ) ( 18.02 g / 1 mol ) = 0.82 g of H2O is needed


However, if the amount given of CO2 is not one gram, then you can simply change the starting value in the calculation and solve for the mass of water needed.


Final answer:

Photosynthesis involves converting carbon dioxide and water into glucose and oxygen with sunlight. The balanced chemical equation indicates a 6:1 mole ratio of water to glucose. The mass of water consumed would be six times the molecular weight of water times the moles of glucose formed.

Explanation:

Photosynthesis is a fundamental biological process in which green plants use sunlight to convert carbon dioxide (CO₂) and water (H₂O) into glucose (C₆H₁₂O₆) and oxygen (O₂). The balanced chemical equation for photosynthesis is:

6CO₂ + 6H₂O + sunlight → C₆H₁₂O₆ + 6O₂

The question asks about the mass of water consumed in the reaction with carbon dioxide to form glucose during photosynthesis. To determine this, you need to know the mole ratio between water and glucose from the balanced equation, which is 6:1, meaning six molecules of water are needed to produce one molecule of glucose. To find the specific mass of water used, you would multiply the molecular weight of water (18.01528 g/mol) by the number of moles of water consumed (which is typically six times the moles of glucose formed).

The balanced equation for the reaction occurring when iron(iii) oxide, a solid, is reduced with pure carbon to produce carbon dioxide and molten iron is

Answers

2Fe2O3+3C ---> 3CO2+4Fe

Answer: The balanced chemical equation is written below.

Explanation:

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on the product side. These equations follow law of conservation of mass.

The chemical equation for the reaction of iron (III) oxide with carbon follows:

[tex]2Fe_2O_3(s)+3C(s)\rightarrow 3CO_2(g)+4Fe(l)[/tex]

By Stoichiometry of the reaction:

2 moles of solid iron (III) oxide reacts with 3 moles of pure carbon to produce 3 moles of carbon dioxide gas and 4 moles of molten iron

Hence, the balanced chemical equation is written above.

How many milliliters of a 0.266 m lino3 solution are required to make 150.0 ml of 0.075 m lino3 solution?

Answers

We need an equation that would relate the concentration of the original solution to that of the desired solution. To solve this we use the equation expressed as follows, 

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

M1V1 = M2V2

0.266 M x V1 = 0.075 M x 150 mL

V1 = 42.29 mL


Therefore, we need about 42.29 mL of the 0.266 M of lithium nitrate solution to make 150.0 mL of the 0.075 M lithium nitrate solution.

[tex]\boxed{{\text{42}}{\text{.3 mL}}}[/tex] of a 0.266 M [tex]{\text{LiN}}{{\text{O}}_{\text{3}}}[/tex] solution is required to make 150 mL of a 0.075 M [tex]{\text{LiN}}{{\text{O}}_{\text{3}}}[/tex] solution.

Further Explanation:

The concentration is the proportion of substance in the mixture. The most commonly used concentration terms are as follows:

1. Molarity (M)

2. Molality (m)

3. Mole fraction (X)

4. Parts per million (ppm)

5. Mass percent ((w/w) %)

6. Volume percent ((v/v) %)

Molarity is a concentration term that is defined as the number of moles of solute dissolved in one litre of the solution. It is denoted by M and its unit is mol/L.

The molarity equation is given by the following expression:

[tex]{{\text{M}}_{\text{1}}}{{\text{V}}_{\text{1}}} = {{\text{M}}_{\text{2}}}{{\text{V}}_{\text{2}}}[/tex]                      …… (1)

Here,

[tex]{{\text{M}}_{\text{1}}}[/tex] is the molarity of the initial [tex]{\text{LiN}}{{\text{O}}_{\text{3}}}[/tex] solution.

[tex]{{\text{V}}_{_{\text{1}}}}[/tex] is the volume of the initial [tex]{\text{LiN}}{{\text{O}}_{\text{3}}}[/tex] solution.

[tex]{{\text{M}}_{\text{2}}}[/tex] is the molarity of the new [tex]{\text{LiN}}{{\text{O}}_{\text{3}}}[/tex] solution.

[tex]{{\text{V}}_{_{\text{2}}}}[/tex] is the volume of the new [tex]{\text{LiN}}{{\text{O}}_{\text{3}}}[/tex] solution.

Rearrange equation (1) to calculate [tex]{{\text{V}}_{\text{1}}}[/tex].

[tex]{{\text{V}}_{\text{1}}}=\frac{{{{\text{M}}_{\text{2}}}{{\text{V}}_{\text{2}}}}}{{{{\text{M}}_{\text{1}}}}}[/tex]                    …… (2)

The value of [tex]{{\text{M}}_{\text{1}}}[/tex] is 0.266 M.

The value of [tex]{{\text{M}}_{\text{2}}}[/tex] is 0.075 M.

The value of [tex]{{\text{V}}_{_{\text{2}}}}[/tex] is 150 mL.

Substitute these values in equation (2).

[tex]\begin{aligned}{{\text{V}}_{\text{1}}}&=\frac{{\left({{\text{0}}{\text{.075 M}}} \right)\left( {{\text{150 mL}}} \right)}}{{{\text{0}}{\text{.266 M}}}}\\&=42.29{\text{ mL}}\\&\approx 42.{\text{3 mL}}\\\end{aligned}[/tex]

Learn more:

1. What is the concentration of alcohol in terms of molarity? https://brainly.com/question/9013318

2. What is the molarity of the stock solution of luminol? https://brainly.com/question/2814870

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Concentration terms

Keywords: molarity, LiNO3, 42.3 mL, molarity equation, volume, M1, M2, V1, V2, 150 mL, 0.075 M, 0.266 M, concentration, concentration terms.

Using the table below, what is the change in enthalpy for the following reaction? 3CO (g) + 2Fe2O3 (s) Imported Asset Fe(s) + 3CO2 (g)

Answers

To solve this problem, we should recall that the change in enthalpy is calculated by subtracting the total enthalpy of the reactants from the total enthalpy of the products:

ΔH = Total H of products – Total H of reactants

You did not insert the table in this problem, therefore I will find other sources to find for the enthalpies of each compound.

ΔHf CO2 (g) = -393.5 kJ/mol

ΔHf CO (g) = -110.5 kJ/mol

ΔHf Fe2O3 (s) = -822.1 kJ/mol

ΔHf Fe(s) = 0.0 kJ/mol

Since the given enthalpies are still in kJ/mol, we have to multiply that with the number of moles in the formula. Therefore solving for ΔH:

ΔH = [3 mol ( − 393.5 kJ/mol) + 1 mol (0.0 kJ/mol)] − [3 mol ( − 110.5 kJ/mol) + 2 mol ( − 822.1 kJ/mol)]

ΔH = 795.2 kJ

Consider the potassium permanganate reaction again.

2KMnO4 + 16HCl → 2KCl + 2MnCl2 + 8H2O + 5Cl2

How many moles of water are produced when 3.45 moles of KMnO4 react? Give your answer to the nearest 0.1 moles.

I know the answer is 13.8 moles but I dont know how to find this. Please explain.

Answers

Hey there !

Mole ratio :

2 KMnO4 + 16 HCl → 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

2 moles KMnO4 ----------------- 8 moles H2O
3.45 moles KMnO4 ------------- (moles H2O )

Moles H2O = 3.45 * 8 / 2

Moles H2O = 27.6 / 2

 = 13.8 moles of H2O

The option that was given is wrong , You're right.

Answer:

Moles of H2O produced = 13.8

Explanation:

Given:

Moles of KMnO4 reacted = 3.45

To determine:

moles of H2O produced

Explanation:

Given reaction:

2KMnO4 + 16HCl →2KCl + 2MnCl2 + 8H2O + 5Cl2

Based on the reaction stoichiometry:

2 moles of KMnO4 produces 8 moles of H2O

Therefore, moles of H2O produced when 3.45 moles of KMnO4 react is:

[tex]= \frac{3.45\ moles\ KMnO4 * 8\ moles\ H2O}{2\ moles\ KMnO4} = 13.8[/tex]

An undergraduate weighed out 20grams of sodium hydroxide pellets. If Na =23, O = 16 andH = 1, What is the mole of this sodium hydroxide.

Answers

Final answer:

To determine the number of moles of NaOH from 20 grams, calculate the substance's molar mass (39.997 g/mol) and divide the given mass by the molar mass, resulting in 0.5001 moles of NaOH.

Explanation:

The question asks about calculating the moles of sodium hydroxide (NaOH) from its mass in grams. To find moles, one has to use the molar mass of the substance.

First, calculate the molar mass of NaOH:
Na (1 x 22.990 g/mol) + O (1 x 15.999 g/mol) + H (1 x 1.008 g/mol) = 39.997 g/mol.

Next, use this molar mass to find the number of moles:
Given: 20.0 g NaOH,
Desired: moles NaOH
Since 1 mole of NaOH weighs 39.997 g, then:
moles of NaOH = mass (20 g) ÷ molar mass (39.997 g/mol) = 0.5001 moles.

Aluminum reacts with chlorine gas to form aluminum chloride. 2al(s)+3cl2(g)→2alcl3(s) what minimum volume of chlorine gas (at 298 k and 225 mmhg) is required to completely react with 7.85 g of aluminum

Answers

The balanced chemical reaction is expressed as:

2Al(s)+3Cl2(g)→2AlCl3(s)

To determine the volume of chlorine gas needed given the mass of aluminum metal to be used, we need to calculate for the moles of chlorine needed and use a relation that relates moles and volume by assuming the gas to be an ideal gas. We use the equation PV =nRT. We calculate as follows:

7.85 g Al ( 1 mol / 26.98 g ) ( 3 mol Cl2 / 2 mol Al ) = 0.43643 mol Cl2

PV = nRT
V = nRT / P
V = 0.43643 (0.08205) (298) / (225/760)
V = 36.04 L chlorine gas

The minimum volume needed would be 36.04 L.
Final answer:

To find the minimum volume of chlorine gas required to react with 7.85 g of aluminum, we convert the mass of aluminum to moles, find the necessary moles of chlorine gas using the balanced equation, and then apply the ideal gas law to find the volume.

Explanation:

The question is asking about the volume of chlorine gas required to completely react with a given amount of aluminum. We know from the balanced equation that 2 moles of aluminum (Al) react with 3 moles of chlorine gas (Cl) to form 2 moles of aluminum chloride (AlCl₃). First, we've to convert the mass of aluminum to moles by dividing the mass 7.85g by the molar mass of aluminum (26.98 g/mol), giving approximately 0.291 mol.

From the equation, we know the mole ratio of Al to Cl2 is 2 to 3. Therefore, 0.291 moles of Al will require 0.437 mol of Cl₂. Next, we apply the ideal gas law (PV=nRT) to find the volume. Here, P=225 mmHg (which is 0.296 atmospheres), R=0.0821(atm L)/(mol K), T=298 K and n=0.437 mol.

Finally, solving for V in PV=nRT gives us V = nRT/P, approximating 11.08 L as the minimum volume of chlorine gas required to react.

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In an open system, the vapor pressure is _____ the outside air pressure.
A. Higher
B. Lower
C. Equal
D. Below

Answers

The vapor pressure is EQUAL TO the outside air pressure.

Answer: Option (c) is the correct answer.

Explanation:

In an open system, the vapor pressure is equal the outside air pressure because there can be mass transfer or energy transfer from the atmosphere to the system as the system is open.

Whereas in a closed system there cannot be mass transfer or energy transfer from the system to the surrounding or vice versa.

Thus, we can conclude that option (c) is the correct answer.

How many grams of solute are present in 375 ml of 0.120 m kbr?

Answers

the answer is 53.54 grams of solute

_______ is the classic structural formula for all the addictive narcotics

Answers

The answer to this statement is codein. Codein, or 3-Methylmorphine by its IUPAC name, is an opiate used as pain reliever and suppressor of coughs. Its structural formula is shown in the picture. The patient's dosage of these narcotics should be strictly prescribed by the doctor. When patients take this, they feel euphoria, hence, they tend to crave for that feeling once it's gone. Too much dosage of this drug would lead to addiction. Examples of drugs with this structural formula are Cotabflu, Nalex AC, T-Koff and Pediatuss.

which one of the following ia a characteristic of a metal?

Answers

Assuming your options are changes the color of litmus paper to red, conducts heat readily, reacts with bases to produce salts, and becomes negative when combined with other elements, the correct answer is conducts heat readily.
This is because the electrons in the metal are allowed to float the space freely, and they are not stuck together like in some solids - this is the reason why they can carry kinetic energy throughout the metal, which is of course related to heat as well. The other options do not refer to metals at all. 

The balanced equation for the generation of sugar from sunlight water and co2 is

Answers

The balanced equation for the generation of sugar from sunlight water and CO₂ is

6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

carbon dioxide + water → sugar + oxygen

The process of photosynthesis occurs when the chlorophyll present in the leaves of plants absorb sunlight to make food in the presence of carbon dioxide (enters through the stomata of leaves) and water (absorbed from the roots). As a result of this reaction sugar and oxygen is formed. After that sugar is converted in to starch and oxygen is released into air.

Final answer:

Photosynthesis is the biological process that transforms sunlight, water, and CO2 into glucose and oxygen. The balanced equation for photosynthesis is 6CO₂ + 6H₂O + light energy --> C6H12O6 + 6O2. The process includes intermediate reactions that eventually form simple carbohydrate molecules.

Explanation:

The process that generates sugar from sunlight, water, and CO2 is called photosynthesis. The balanced chemical equation for photosynthesis is 6CO₂ + 6H₂O + light energy --> C6H12O6 + 6O2.

During photosynthesis, plants use sunlight energy to convert carbon dioxide gas (CO2) and water (H2O) into glucose (C6H12O6) and oxygen (O2). This process is complex and involves intermediate reactions and products.

Glyceraldehyde-3-phosphates, which are simple carbohydrate molecules that can be converted to glucose and various other sugar molecules, are formed during the course of the reaction.

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Consider KOH and the following information. Hsol = –58 kJ/mol Hhydr of = –336 kJ/mol Hhydr of = –532.7 kJ/mol What is the Hlat rounded to the correct number of significant figures? Use Hsol = –Hlat + Hhydr.
A. –927 kJ/mol
B. –926.7 kJ/mol
C. –811 kJ/mol
D. –810.7 kJ/mol

Answers

The total Hhydr is:

Hhydr = – 336 kJ/mol + – 532.7 kJ/mol

Hhydr = - 868.7 kJ/mol

Therefore using the formula Hsol = –Hlat + Hhydr we can get Hlat.

– 58 kJ/mol = – Hlat + - 868.7 kJ/mol

- Hlat = 810.7 kJ/mol

Hlat = - 810.7 kJ/mol

ANSWER: 

D. –810.7 kJ/mol

Answer:D

Explanation:

A metal sphere has a mass of 39.0g and a volume of 10.0cm is the sphere made of pure aluminum

Answers

Note that the density of pure aluminum is  2.7 g/cm³ (from tables).

Given:
m = 39.0 g, the mass of the metal
V = 10.0 cm³, the density of the metal

By definition, the density of the metal is
density = mass/volume
             = (39.0 g)/(10.0 cm³)
             = 3.9 g/cm³

Answer:
The calculated density is not equal to 2.7 g/cm³, therefore the metal sphere is not made of pure aluminum.

If 100. mL of 0.400 M Na2SO4 is added to 200. mL of 0.600 M NaCl, what is the concentration of Na+ ions in the final solution? Assume that the volumes are additive.

Answers

Na₂SO₄ → 2Na⁺ + SO₄²⁻

c₁(Na⁺)=2c(Na₂SO₄)

n₁(Na⁺)=c₁(Na⁺)v₁=2c(Na₂SO₄)v₁

NaCl → Na⁺ + Cl⁻

c₂(Na⁺)=c(NaCl)

n₂(Na⁺)=c₂(Na⁺)v₂=c(NaCl)v₂

n(Na⁺)=n₁(Na⁺)+n₂(Na⁺)=2c(Na₂SO₄)v₁+c(NaCl)v₂

v=v₁+v₂

c(Na⁺)=n(Na⁺)/v={2c(Na₂SO₄)v₁+c(NaCl)v₂}/(v₁+v₂)

c(Na⁺)={2*0.400*0.1+0.600*0.2}/(0.1+0.2)=0.667 mol/L

c(Na⁺)=0.667M

The concentration of Na ion in the final solution is 0.66 M.

To calculate the concentration of Na ions in the solution, the moles of [tex]\rm Na_2SO_4[/tex] in the solution have been calculated.

Moles = molarity [tex]\times[/tex] volume (L)

The molarity of [tex]\rm Na_2SO_4[/tex] solution given is = 0.4

Volume of [tex]\rm Na_2SO_4[/tex] solution = 100 ml = 0.1 L.

Moles of [tex]\rm Na_2SO_4[/tex] = 0.4 [tex]\times[/tex] 0.1

Moles of [tex]\rm Na_2SO_4[/tex] = 0.04

The dissociation of [tex]\rm Na_2SO_4[/tex] will be as follows:

[tex]\rm Na_2SO_2\;\rightarrow\;2\;Na^+\;+\;SO_4^2^-[/tex]

1 mole of [tex]\rm Na_2SO_4[/tex] = 2 moles of Na ions.

0.04 moles of [tex]\rm Na_2SO_4[/tex] = 0.04 [tex]\times[/tex] 2

0.04 moles of [tex]\rm Na_2SO_4[/tex] = 0.08 moles of Na ions.

The moles of Na ions in NaCl solution will be:

Given, molarity of NaCl solution = 0.6 M

Volume of NaCl solution = 200 ml = 0.2 L.

Moles of Na ions in NaCl solution = 0.6 [tex]\times[/tex] 0.2

Moles of Na ions in NaCl solution = 0.12.

The dissociation of NaCl will be as follows:

[tex]\rm NaCl\;\rightarrow\;Na^+\;+\;Cl^-[/tex]

1 mole of NaCl = 1 mole of Na ions

0.12 moles of NaCl gives = 0.12 moles of Na ions.

Thus the total Na ions = Na ion in [tex]\rm Na_2SO_4[/tex] + Na ions in NaCl

Total moles of Na ions = 0.08 + 0.12

Total moles of Na ions = 0.2 moles.

The total volume of solution will be :

0.1 L [tex]\rm Na_2SO_4[/tex] + 0.2 L NaCl

= 0.3 L.

Concentration of Na ion in the final solution = [tex]\rm \dfrac{moles}{volume\;(L)}[/tex]

The concentration of Na ion in the final solution =  [tex]\rm \dfrac{0.2}{0.3}[/tex] M

Concentration of Na ion in the final solution = 0.66 M.

The concentration of Na ion in the final solution is 0.66 M.

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The electron stable state configuration in atoms is best seen in the ______ configuration.

inert gas
full d shell
full f shell
full s shell

Answers

The electron stable state configuration in atoms is best seen in the inert gas configuration.
Inert gas are the most stable since they have their valence electron shell saturated with electrons (the valence shell has the maximum number of electrons it can hold). They need neither donate nor accept electrons.

Aluminium chloride dissolved in Water =? When you dissolve aluminium chloride in water, what is the balanced chemical equation? NOTE: Not a chemical reaction, just dissolving.

Answers

Dissolution and dissociation of aluminum chloride:

AlCl₃(s) → Al³⁺(aq) + 3Cl⁻(aq)


The cation of aluminum is hydrolyzed:

Al³⁺ + 2H₂O ⇄ AlOH²⁺ + H₃O⁺
AlOH²⁺ +2H₂O ⇄ Al(OH)₂⁺ + H₃O⁺
Al(OH)₂⁺ + 2H₂O ⇄ Al(OH)₃ + H₃O⁺

What is the ph of a solution containing 0.12 mol/l of nh4cl and 0.03 mol/l of naoh (pka of is 9.25)?

Answers

The Henderson-Hasselbalch equation fails to provide accurate pH readings for excessively diluted buffer solutions because it ignores the self-dissociation that occurs in water. The pH of the solution is 8.65.

The Henderson-Hasselbalch equation establishes a connection between an acid's pKa (acid dissociation constant) and pH in aqueous solutions. When the concentration of the acid and its conjugate base, or the base and the corresponding conjugate acid, are known, the pH of a buffer solution can be determined with the use of this equation.

The expression used to calculate pOH is:

pOH = pKb + log  [Conjugate acid]/ [Weak base]

pKa + pKb = 14

pKb = 14 - pKa

pKb = 14 - 9.25

pKb = 4.75

pOH = 4.75 + log 0.12 / 0.03

pOH = 5.35

pH = 14 - pOH

pH = 14 - 5.35

pH = 8.65

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A(n) ________ chemical reaction releases energy, whereas a(n) ________ reaction requires an input of energy.

Answers

There are two types of chemical reaction based on the direction of heat or energy. 

If the energy or heat is absorbed by the system of reactants in order to form the specific products then, the reaction is called endothermic. 

However, if the energy is released by the reactants in the process of producing the products then, the reaction is exothermic.

Hence, for this item, the first blank should be filled with exothermic and the second blank should be filled with endothermic. 

There are sometimes given chemical reactions that do not involve the transfer of heat from the system or from the system. 

Answer:

Exothermic chemical reaction

Endothermic chemical reaction

An Exothermic chemical reaction releases energy, whereas an Endothermic chemical reaction requires an input of energy.

An Exothermic chemical reaction involves the release of heat(thermal energy) in a system to the surroundings. The enthalpy(heat) change which is ΔH decreases in this type of reaction

An Endothermic chemical reaction involves the absorption or input of heat in the form of thermal energy by the system from the surroundings. The enthalpy(heat) change which is ΔH increases in this type of reaction.  

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Sheila's measured glucose level one hour after a sugary drink varies according to the normal distribution with μμ = 120 mg/dl and σσ = 20 mg/dl. what is the level l such that there is probability only 0.15 that the mean glucose level of 5 test results falls above l?

Answers

Since the sample size is below 30, in this case we use the t statistic. The formula for t score is:

t = (x – u) / (σ / sqrt n)

where,

x = the level l = unknown

u = sample mean = 120 mg / dl

σ = standard deviation = 20 mg / dl

n = sample size or number of results = 5

Using the standard distribution tables for t, we can find the value of t given the probability (P = 0.15) and degrees of freedom (DOF).

t  = 1.036

Going back to the formula for t score:

1.036 = (x – 120) / (20 / sqrt 5)

x = 129.27 mg / dl = l

Final answer:

To find the glucose level such that the probability of the mean of 5 tests being above it is 0.15, we calculate the reduced standard deviation for the mean of the tests, find the corresponding z-score for a cumulative probability of 0.85, and apply the formula for the mean's distribution. The level l is found to be 129.267 mg/dl.

Explanation:

The question asks for the level l such that there is only a 0.15 probability that the mean glucose level of 5 test results falls above l, given that Sheila's glucose level after a sugary drink follows a normal distribution with a mean (μ) of 120 mg/dl and a standard deviation (σ) of 20 mg/dl.

To solve for l, we first need to recognize that the distribution of the mean of several test results (in this case, 5) will also be normally distributed, with the same mean but with a reduced standard deviation that is equal to the original standard deviation divided by the square root of the number of tests (σ/√n). For 5 tests, the new standard deviation (σnew) is 20/√5 = 8.9443 mg/dl.

The next step involves determining the z-score that corresponds to a probability of 0.85 (since 1 - 0.15 = 0.85) in the standard normal distribution. Consulting a z-table or using statistical software, we find that the z-score corresponding to 0.85 is approximately 1.036. Using the formula l = μ + z σnew, we calculate:

l = 120 + (1.036)(8.9443) = 120 + 9.267 = 129.267 mg/dl.

Therefore, the level l such that there is a probability of only 0.15 that the mean glucose level of 5 test results falls above l is 129.267 mg/dl.

A 1.50-g sample of hydrated copper(ii) sulfatewas heated carefully until it had changed completely to anhydrous copper(ii) sulfate () with a mass of 0.957 g. determine the value of x. [this number is called the number of waters of hydration of copper(ii) sulfate. it specifies the number of water molecules per formula unit of in the hydrated crystal.]

Answers

CuSO₄·xH₂O → CuSO₄ + xH₂O

M(CuSO₄)=159.61 g/mol
M(H₂O)=18.02 g/mol
m(CuSO₄·xH₂O)=1.50 g
m(CuSO₄)=0.957 g

m(CuSO₄·xH₂O)/M(CuSO₄·xH₂O)=m(CuSO₄)/M(CuSO₄)

M(CuSO₄·xH₂O)=M(CuSO₄)+xM(H₂O)

m(CuSO₄·xH₂O)/{M(CuSO₄)+xM(H₂O)}=m(CuSO₄)/M(CuSO₄)

M(CuSO₄)+xM(H₂O)=m(CuSO₄·xH₂O)M(CuSO₄)/m(CuSO₄)

xM(H₂O)=m(CuSO₄·xH₂O)M(CuSO₄)/m(CuSO₄)-M(CuSO₄)

x=M(CuSO₄)/M(H₂O){m(CuSO₄·xH₂O)/m(CuSO₄)-1}

x=159.61/18.02*{1.50/0.957-1}=5.0

x=5

CuSO₄·5H₂O

Research the amount of carbon dioxide generally found in the air and in breath. which has more carbon dioxide? what are some of the other sources of carbon dioxide in air?

Answers

In atmosphere there is 0.04 % of co2 in the air
In breath we breath out about 2 to 3 pounds of  co2 which is greater than the amount of co2 found in air \
The sources of co2 are
respiration 
combustion of organic fuels or compounds

Answer:

1- Carbon dioxide in our breath comes from the carbon in our food.

2- All plants need carbon dioxide to survive.

3- About .04 percent of the atmosphere's air is carbon dioxide and  4.4       percent of our breath is carbon dioxide we breathe out more carbon          dioxide than we breathe in.

4- Some effects might include combustion with other gasses and it could also potentially kill all life.

Explanation:

Nitrogen is naturally abundant in the atmosphere. Why are nitrogen fertilizers added to soil, despite the dangers they produce when they enter aquatic ecosystems?

Answers

Nitrogen fertilizers are added to soil because nitrogen is very important for plant growth and most organisms can not utilize atmospheric nitrogen. Even though the percentage of nitrogen in the atmosphere is very high, yet it is not available to most living organisms for use because the energy required to break the bonds that hold the diatomic nitrogen together is very high. 
Final answer:

Nitrogen fertilizers are added to soil to provide readily available forms of nitrogen that plants can use. However, when these fertilizers enter aquatic ecosystems through runoff, they can cause eutrophication and harm aquatic fauna.

Explanation:

Nitrogen fertilizers are added to soil despite the dangers they pose to aquatic ecosystems because atmospheric nitrogen is not readily available for plants to use. Most plants require nitrogen in the form of nitrate or ammonium, which can be obtained from fertilizers. However, when these fertilizers enter aquatic ecosystems through runoff, they can cause eutrophication, leading to the overgrowth of microorganisms and the depletion of dissolved oxygen levels, which can be harmful to aquatic fauna.

Helium has a density of 1.79×10^-4 g/mL at standard temperature and pressure. A balloon has a volume of 6.3 liters. Calculate the mass of helium that it would take to fill the balloon. Be sure to follow significant figure rules when calculating the answer.

A. 35,000g
B. 1.1×10^-3 g
C. 2.8×10^-5 g
D. 1.1g

Answers

6,3 L = 6300 mL
..................
1,79×10^-4g -------- 1 mL
Xg --------------------- 6300 mL
X = 0,000179×6300
X = 1,1277g ≈ 1,1g

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