A material will float on the surface of a liquid if the material has a density less than that of the liquid. Given that the density of water is approximately 1.0 g/mL, will a block of material having a volume of 1.2 x 10^4 in^3 and weighing 350 lb float or sink when placed in a reservoir of water?

The ionic charge for X in the compound X3Y2, with Y having a ionic charge of -3, is +2. This is deduced from the subscripts in the compound formula which correspond to the absolute values of the ionic charges

In the field of Chemistry, the formula for a compound gives a distinct representation of the ions present and their subscripts usually indicate their ionic charges. In the compound X3Y2, the subscript of X (3) corresponds to the absolute value of the charge on the Y ion which is 3 (ignoring the negative sign since we're only interested in the absolute value) and vice versa.

Therefore, since the subscript for Y is 2, the ionic charge for X would be +2.

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Answer:

At the gaseous phase the intermolecular force of attraction between atoms becomes far apart. The atoms can easily be added up with an electron or electrons can be removed from an atom.

Higher energy is required in this process.

Explanation:

Why do scientists use atoms in the gas phase to measure ionization energies and electron affinities

Electron Affinity is where there is a change in energy when  electron is added to atom in its gaseous phase. The atom becomes negatively charged.

Ionization Energy is defined as the energy required to remove an electron from gaseous atom.

At the gaseous phase the intermolecular force of attraction between atoms becomes far apart. The atoms can easily be added up with an electron or electrons can be removed from an atom.

Answer:

C.) balance in number of electrons and protons.

Explanation:

Its the right answer i swear!!!

The density of solid W is 19.3 g/cm³. To find the number of atoms per cm³, we calculate the volume of one unit cell of W and then multiply by the number of unit cells. The volume of one unit cell is found using the formula for the volume of a cube. The edge length of a unit cell is 3.165 Å.

The density of solid W is given as 19.3 g/cm³. To calculate the number of atoms per cubic centimeter of W, we need to know the volume of one W atom. Since W adopts a body-centered cubic unit cell, each unit cell contains 2 atoms (1 atom in the center and 8 atoms at each corner). The volume of one unit cell can be calculated using the formula for the volume of a cube: volume = edge length³. Given that the edge length is 3.165 Å, we can convert it to cm and calculate the volume of one unit cell. Once we have the volume of one unit cell, we can calculate the number of unit cells per cubic centimeter of W.

The volume of one unit cell of W is (3.165 Å)³ = 31.152 ų. Converting this to cm³ gives us 3.1152 x 10⁻²³ cm³. To find the number of unit cells per cm³, we take the reciprocal of the volume of one unit cell: 1/(3.1152 x 10⁻²³ cm³) = 3.2054 x 10²² unit cells/cm³. Since each unit cell contains 2 atoms, the number of atoms per cm³ can be calculated by multiplying the number of unit cells by 2: 3.2054 x 10²² x 2 = 6.4108 x 10²² atoms/cm³.

The volume of one unit cell is given by the formula volume = edge length³. In this case, the edge length is 3.165 Å. To find the volume of one unit cell in cm³, we need to convert the edge length from Å to cm: 3.165 Å = 3.165 x 10⁻⁸ cm. Now, we can calculate the volume of one unit cell: (3.165 x 10⁻⁸ cm)³ = 3.1152 x 10⁻²³ cm³. The edge length of a unit cell is 3.165 Å, or 3.165 x 10⁻⁸ cm.

Final answer:

A substance with a high specific heat requires more energy to increase its temperature by 25°C than a substance with a low specific heat, because it absorbs more heat without a significant temperature change.

Explanation:

A substance that requires more energy to undergo an increase in temperature has a high specific heat. Specific heat is defined as the amount of heat energy required to raise the temperature of 1 gram of a substance by 1°C. A material with a high specific heat will absorb more heat without a significant rise in temperature. For instance, water has a high heat capacity and specific heat, making it resistive to temperature change. Therefore, a substance with a high specific heat needs more energy to experience a temperature increase of 25°C compared to one with a low specific heat. Conversely, a substance with a low specific heat requires less energy to change its temperature, as its temperature will rise more quickly when heat is applied.

Final answer:

The mass of 3.01 x 10^23 molecules of oxygen is 9.632 x 10^23 grams.

Explanation:

The mass of 3.01 x 10^23 molecules of oxygen can be calculated using the concept of molar mass. The molar mass of oxygen (O2) is 32.00 g/mol.

Therefore, the mass of 1 mole of oxygen is 32.00 g.

Using this information, we can set up a conversion factor to find the mass of 3.01 x 10^23 molecules:

1 mole of O2 = 32.00 g

3.01 x 10^23 molecules of O2 = x grams

Cross multiplying gives us:

x = (3.01 x 10^23 molecules of O2 * 32.00 g) / 1 mole of O2

x = 9.632 x 10^23 g

Therefore, the mass of 3.01 x 10^23 molecules of oxygen is 9.632 x 10^23 grams.

In the Periodic Table, a set of properties repeats from group to group, not element to element, column to column, or row to row. This is because elements in the same group have the same number of valence electrons.

In the context of the Periodic Table, a set of properties repeats not from element to element, or column to column, or row to row, but actually from group to group. This is because elements in the same group or column of the periodic table have the same number of electrons in their outer orbitals (Valence Electrons). This concept is known as periodicity. For instance, all elements in Group 1 (alkali metals) are very reactive metals because they each have one electron in their outermost shell.

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Explanation:

When 30 grams of barium chloride crystals when heated at 400 degree Celsius and again weighed again which comes to be 20 grams. This means that water of crystallization associated with the barium chloride crystal got vaporized when heated at 400 degree Celsius.

Water of crystallization: Water molecules associated to a crystal structure of a compound.

[tex]BaCl_2.2H_2O\overset{400^o C}\rightarrow BaCl_2+2H_2O[/tex]

Hence, the sample of barium chloride crystals was hydrated.

Final answer:

The decrease in mass of barium chloride crystals after heating likely resulted from the loss of water of crystallization or the evaporation of volatile impurities.

Explanation:

The difference in mass of the barium chloride crystals before and after heating indicates that some part of the compound or its adherents has been lost during the heating process. Barium chloride itself is stable at high temperatures, but if it was hydrated barium chloride (BaCl2·xH2O), the heating could cause the water of crystallization to evaporate, which would result in a decrease in the mass.

Another possibility is that there might be impurities or other volatile substances in the crystalline material that could have evaporated or decomposed, resulting in less mass after the heating process.

The artifact was made approximately 1866 years ago.

To solve this problem, we can use the formula for exponential decay:

[tex]\[ N = N_0 \left( \frac{1}{2} \right)^\frac{t}{T_{1/2}} \][/tex]

Where:

- [tex]\( N \)[/tex] is the final amount of the substance (in this case, the remaining amount of carbon-14 in the artifact).

- [tex]\( N_0 \)[/tex] is the initial amount of the substance (in this case, the amount of carbon-14 in living trees).

- [tex]\( t \)[/tex] is the time that has passed (in years).

- [tex]\( T_{1/2} \)[/tex] is the half-life of the substance (in this case, 5730 years).

Given that the wooden artifact contains 80% of the carbon-14 present in living trees, we can set up the equation as follows:

[tex]\[ 0.80N_0 = N_0 \left( \frac{1}{2} \right)^\frac{t}{5730} \][/tex]

Now, we can solve for t, the time that has passed:

[tex]\[ \left( \frac{1}{2} \right)^\frac{t}{5730} = 0.80 \][/tex]

Taking the natural logarithm of both sides to isolate the exponent:

[tex]\[ \frac{t}{5730} \ln \left( \frac{1}{2} \right) = \ln(0.80) \][/tex]

[tex]\[ \frac{t}{5730} = \frac{\ln(0.80)}{\ln \left( \frac{1}{2} \right)} \][/tex]

[tex]\[ t = 5730 \times \frac{\ln(0.80)}{\ln \left( \frac{1}{2} \right)} \][/tex]

[tex]\[ t \approx 1865.896 \, \text{years} \][/tex]

Rounding to the nearest whole number, we get:

[tex]\[ t \approx 1866 \, \text{years} \][/tex]

Therefore, the artifact was made approximately 1866 years ago.

Answer:

synthesis

Explanation:

  The reaction equation properly written is shown below:

               4Al + 3O₂ → 2Al₂O₃

  A synthesis reaction is a form of combination of atoms. It involves the formation of a single product from two or more reactants.

Decomposition is the formation of two or more products from a single reactant.

Single replacement is a reaction in which one substance is replacing another.

In double displacement, there is an actual exchange of partners to form new compounds.

Answer:

synthesis

Explanation:

Answer:The correct answer is option D.

Explanation:

Electrolyte: An electrolyte is defined as those compound which dissociates into ions when dissolved in water and these ions in the solution will facilitate the movement of the electrons from the solution. Thus making it electrical conductive solution.

Good electrolytes are those electrolytes which completely dissociates or ionizes in water.Like strong acid, strong base, water soluble ionic salts(not of weak acid  or weak base).

[tex]HCl(aq)\rightarrowH^+(aq)+Cl^-(aq)[/tex]

HCL; Strong acid gets completely ionized in water.

[tex]KOH(aq)\rightarrow K^+(aq)+OH^-(aq)[/tex]

KOH; Strong base gets completely ionized in water.

Hence, the correct answer is option D.

The example of a single replacement reaction is as follows: Cu + 2AgNO3 → 2Ag + Cu(NO3)2. Details about single replacement reaction can be found below.

A single replacement reaction is a reaction that involves the displacement of only one element by another element.

In the reaction between copper and silver nitrate as follows: Cu + 2AgNO3 → 2Ag + Cu(NO3)2

Copper displaces silver to form copper nitrate, hence, it can be said to be an example of a single replacement reaction.

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Physical Because changing phases such as solid, liquid, gas are physical forms.

Answer: False

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

Acids have pH ranging from 1 to 6.9, bases have pH ranging from 7.1 to 14 and neutral solutions have pH equal to 7.

[tex]pH=-\log [H^+][/tex]

[tex]pOH=-\log[OH^-][/tex]

When the concentration of [tex][H^+]=[OH^-][/tex], the solution is neutral, [tex]H^+[/tex]> [tex]OH^-[/tex] , the solution is acidic and if [tex]H^+[/tex]< [tex]OH^-[/tex] , the solution is basic.

Answer:

1 mole of uranium

Explanation:

It is the greatest with about a mass of about 238 amu or 238 g/mol

Answer:

The complete and balance the equation for this reaction in acidic solution is given by:

[tex]Cr+4H_2O+6Ag^+\rightarrow CrO_4^{2-}+8H^++6Ag[/tex]

Explanation:

Oxidation reaction of chromium to chromate in acidic medium:

[tex]Cr\rightarrow CrO_4^{2-}[/tex]

Add 4 molecules of water on the left hand side to balance the oxygen:

[tex]Cr+4H_2O\rightarrow CrO_4^{2-}[/tex]

Now balance hydrogen atoms by adding hydrogen ions on opposite to the side where water molecule are present .

[tex]Cr+4H_2O\rightarrow CrO_4^{2-}+8H^+6e^-[/tex]....[1]

In last, to balance the charge on the both sides add electrons to sides where positive charge is more.

Reduction reaction of silver ions to silver in acidic medium:

[tex]Ag^++e^-\rightarrow Ag[/tex]..[2]

By [1] + 6 × [2] , we will get the balance equation for this reaction in acidic solution:

[tex]Cr+4H_2O+6Ag^++6e^-\rightarrow CrO_4^{2-}+8H^+6e^-+6Ag[/tex]

[tex]Cr+4H_2O+6Ag^+\rightarrow CrO_4^{2-}+8H^++6Ag[/tex]

Answer:

This took me a really long time I hope you like it ;]

Drawn by a marker

Explanation: