Hi please help me with this question. ..
A man throws a stone upwards with a 'u' velocity and after spending ' t' seconds  watching the motion of the stone he once again projects another stone upwards hoping that that these 2 stones should  meet eachother.  If his assumption is correct and these two stones collide with eachother,  show that the 2 stones should meet each other 't/2 + u/g 'seconds later from the time of the first projection. ​

Answers

Answer 1

Explanation:

For projectile motion, use constant acceleration equation:

Δx = v₀ t + ½ at²

where Δx is the displacement,

v₀ is the initial velocity,

a is the acceleration,

and t is time.

Both objects are projected upward with velocity u.  The second object is thrown after a time t₀.

For the first object:

Δx = u t + ½ (-g) t²

Δx = u t − ½g t²

For the second object:

Δx = u (t−t₀) + ½ (-g) (t−t₀)²

Δx = u (t−t₀) − ½g (t−t₀)²

Assuming the objects meet, the displacements will be equal:

u t − ½g t² = u (t−t₀) − ½g (t−t₀)²

u t − ½g t² = u (t−t₀) − ½g (t² − 2tt₀ + t₀²)

u t − ½g t² = u t − u t₀ − ½g t² + g tt₀ − ½g t₀²

0 = -u t₀ + g tt₀ − ½g t₀²

0 = -u + g t − ½g t₀

g t = u + ½g t₀

t = u/g + t₀/2


Related Questions

Two substances were mixed and there was a color change and small flames. What can you infer happened?

A physical property was observed
A chemical change occurred
A change in state from solid to liquid
Matter was destroyed

Answers

A chemical change occurred

Explanation:

There are two types of changes, physical changes and chemical changes:

A chemical change occurs when the nature of a substance changes, and new substances are formed. This occurs when the bonds between molecules in the reactants break, and they re-form into new substance. A change in the colors of the substance involved is, for example, a sign that a chemical change occurredA physical change occurs when there is a change in state of a substance, but no new substances are formed. For instance, a physical change is the melting of ice, or the boiling of water, or the condensation of water..

In this problem, two substances are mixed and there is a color change and small flames. The color change indicates the formation of new substances, so a chemical change has occurred. Moreover, the presence of small flames indicates that a chemical reaction has occurred (burning of oxygen), so a new substance has formed, so this is another indication of a chemical change.

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A kitten sits in a lightweight basket near the edge of a table. A person accidentally knocks the basket off the table. As the kitten and basket fall, the kitten rolls, turns, kicks, and catches the basket in its claws. The basket lands on the floor with the kitten safely inside. If air resistance is negligible, what is the acceleration of the kitten-basket system while the kitten and basket are in midair? A The acceleration is directed downward with magnitude less than g because the basket is light. B The acceleration is directed downward with magnitude equal to g because the system is a projectile. C The acceleration fluctuates because of the rolling, turning, and kicking motion of the kitten. D The acceleration cannot be determined without knowing how hard the basket is pushed.

Answers

Answer:

the answer is B

Explanation: this was actually an ap exam question a few years back. the reason for answer B is that the only force being applied to the kitten is the force of gravity after being pushed.

The acceleration of the kitten-basket system is directed downward with a magnitude equal to g because the system is a projectile, therefore the correct answer is B.

What is acceleration?

The rate of change of the velocity with respect to time is known as the acceleration of the object.

As given in the problem kitten sits in a lightweight basket near the edge of a table. A person accidentally knocks the basket off the table. As the kitten and basket fall, the kitten rolls, turns, kicks, and catches the basket in its claws. The basket lands on the floor with the kitten safely inside. If air resistance is negligible,

There is no external force acting on the kitten-basket system except the gravitational force of the earth hence we can conclude that the acceleration is directed downward with a magnitude equal to g because the system is a projectile, thus the correct answer is option B.

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FIGURE 1 shows part of a mass spectrometer. The whole arrangement is in a vacuum. Negative ions of mass 2.84 x 10-20 kg and charge -2.0 x 10-19 C are produced at S, which is at a potential difference of - 3000 V. The ions are accelerated in a narrow beam towards H, a hole in a hollow metal container. Inside the container, the negative ions enter a region where an electric field of strength E and a magnetic field of strength 0.83 T act.

Is it possible for the io
ns to exit slit P without being deflected in the fields?
Explain, with the aid of diagram.​

Answers

Yes, the ions can exit slit P without being deflected, if the electric field strength is 170.6 N/C

Explanation:

When the ions are inside the container, they are subjected to two forces, with directions opposite to each other:

The force due to the electric field, whose magnitude is [tex]F_E=qE[/tex], where q is the charge of the ion and E is the strength of the electric fieldThe force due to the magnetic field, whose magnitude is [tex]F_B=qvB[/tex], where v is the speed of the ions and B is the strength of the magnetic field

The ions will move straight and undeflected if the two forces are equal and opposite. By using Fleming Left Hand rule, we notice that the magnetic force on the (negative) ions point upward: this means that the electric field must be also upward (so that the electric force on the ions is downward). Then, the two forces are balanced if

[tex]F_E = F_B[/tex]

which translates into

[tex]qE=qvB\\\rightarrow v = \frac{E}{B}[/tex]

Therefore, if the speed of the ions is equal to this ratio, the ions will go undeflected.

We can even calculate the value of E at which this occurs. In fact, we know that the ions are earlier accelerated by a potential difference [tex]V=-3000 V[/tex], so we have that their kinetic energy is given by the change in electric potential energy:

[tex]qV=\frac{1}{2}mv^2[/tex]

where

[tex]q=-2.0\cdot 10^{-19}C\\m=2.84\cdot 10^{-20}kg[/tex]

Solving for v, the speed,

[tex]v=\sqrt{\frac{2qV}{m}}=\sqrt{\frac{2(-2.0\cdot 10^{-19})(-3000)}{2.84\cdot 10^{-20}}}=205.6 m/s[/tex]

And since the magnetic field strength is

B = 0.83 T

The strength of the electric field must be

[tex]E=vB=(205.6 m/s)(0.83 T)=170.6 N/C[/tex]

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In which example would the amount of work done equal
zero?

Answers

A. holding a 1,000-N rock overhead  Hope this helps :)

When force is applied to an object, what happens

Answers

Answer:

The force on he object can cause an object to move or speed up. It can also make it stop or change direction.  

Explanation:

The force on the object can cause an object to move or speed up, it can also make it stop or change direction

Which is the standard unit of time in the metric system?

Answers

Explanation:

Metric time is the measure of time intervals using the metric system. The modern SI system defines the second as the base unit of time, and forms multiples and submultiples with metric prefixes such as kiloseconds and milliseconds. Other units of time: minute, hour, and day, are accepted for use with SI, but are not part of it. Metric time is a measure of time intervals, while decimal time is a means of recording time of day.

A custodian is struggling to move a 100. kg desk on a dolly, using a rope. He is pulling on the rope at a 60. ◦ angle. (a) How much force will the custodian need to apply in order to cause the desk to accelerate horizontally at a rate of 1.0 m s 2 ? (b) You suggest that the custodian will have an easier time if he uses a longer rope, which will decrease the angle. If the longer rope results in an angle of 30. ◦ , much force will the custodian need to apply in order to cause the 100. kg desk to accelerate horizontally at 1.0 m s 2 ?

Answers

a) The custodian needs to apply 200 N of force

b) The custodian needs to apply 115.4 N of force

Explanation:

a)

We can solve this problem by applying Newton's second law: in fact, the net force along the horizontal direction must be equal to the product between the mass of the desk and the horizontal acceleration. Mathematically,

[tex]F_x = ma_x[/tex]

where

[tex]F_x = F cos \theta[/tex] is the net force on the horizontal direction, with F being the magnitude of the force applied by the custodian, and

[tex]\theta=60^{\circ}[/tex] the angle at which the force is applied

m is the mass of the desk

[tex]a_x[/tex] is the horizontal acceleration

In this problem we have:

m = 100 kg

[tex]a_x = 1.0 m/s^2[/tex]

Solving for F, we find the force that the custodian must apply:

[tex]F=\frac{ma_x}{cos \theta}=\frac{(100)(1.0)}{cos 60^{\circ}}=200 N[/tex]

b)

In this case, the rope has an angle of [tex]30^{\circ}[/tex] with the horizontal: this means that the force is applied at an angle of

[tex]\theta=30^{\circ}[/tex]

with the horizontal.

As before, we can apply Newton's second law:

[tex]F_x = ma_x[/tex]

And we have again

m = 100 kg (mass of the desk)

[tex]a_x=1.0 m/s^2[/tex] (horizontal acceleration)

This can be rewritten as

[tex]Fcos \theta = ma_x[/tex]

And solving for F, we find

[tex]F=\frac{ma_x}{cos \theta}=\frac{(100)(1.0)}{cos 30^{\circ}}=115.4 N[/tex]

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Final answer:

The custodian should apply 200 N of force at a 60 degree angle and approximately 115.5 N of force at a 30 degree angle to accelerate the 100 kg desk horizontally at 1 m/s^2.

Explanation:

The question is asking about the force the custodian would need to apply to move a 100 kg desk on a dolly at a certain angle to accelerate it horizontally at 1 m/s^2. This concerns the application of Newton's second law in the context of force and acceleration, taking into account the angle at which the force is applied.

(a) To find the force at a 60 degrees angle, we need to use Newton's second law in the vertical component: F=ma. The force applied in the direction of movement (horizontal) would be F=100 kg * 1 m/s^2=100 N. However, because the force is applied at an angle, the horizontal component of the force is F * cos(60), which equals 100 N. Thus, the actual force applied by the custodian must be 100 N / cos(60) = 200 N.

(b) If the angle is reduced to 30 degrees, it becomes easier to move the desk because the horizontal component of the force is greater. In this case, the actual force applied would be 100 N / cos(30) = approximately 115.5 N. So, the custodian would need to apply less force to achieve the same acceleration.

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A 20g book laying on a 40cm high table. Just before a cat knocks it off the table what is the books gravitational potential energy?

Answers

Answer:

The book gravitational potential energy is 0.0784 Joules.

Explanation:

Given:

Mass of book, m = 20 g = 20 ÷ 1000 = 0.02 kg

Table height,   h = 40 cm =40 ÷ 100 = 0.4 m

To Find:

Gravitational Potential Energy = ?

Solution:

Gravitational Potential Energy :

Gravitational potential energy is energy an object possesses because of its position in a gravitational field.

Formula is given by

[tex]\textrm{Gravitational Potential Energy}= m\times g\times h[/tex]

Where,

m = mass

g = acceleration due to gravity = 9.8 m/s²

h = height

Substituting the values we get

[tex]\textrm{Gravitational Potential Energy}= 0.02\times 9.8\times 0.4\\\\\textrm{Gravitational Potential Energy}=0.0784 Joules[/tex]

The book gravitational potential energy is 0.0784 Joules.

A girl pushes a 10.0kg sled at a constant speed by applying a force of 75N at an angle of 30 degrees with respect to the horizontal. The sled is pushed over a distance of 15 meters. How much work is done by the force of friction?

Answers

Answer

given,

mass of sled = 10 Kg

Force applied by girl = ?

angle of inclination = 30°

distance = 15 m

Sled is moving with constant speed hence acceleration will be equal to zero.

now,

F - mg sin θ - f = m a

F - mg sin θ - f = 0

F - mg sin θ = f

where f is the frictional force acting opposite to the applied force

mg sin θ is the component of the weight which is opposing the motion of the sled

now,

f = F - mg sin θ

f = 75 - 10 x 9.8 x sin 30°

f = 26 N

now,

Work done = f. s cos ∅

where ∅ is the angle between frictional  force and displacement which is equal to 180°

W= 26 x 15 x cos 180°

W = -390 J

work done by frictional force is equal to W = -390 J

The work done by child to move the system is 974.25 Joules.

The work done is given by an expression shown below,

                      [tex]Workdone=Force*Distance*Cos\theta[/tex]

Where [tex]\theta[/tex] angle between force  and direction of displacement.

Given that, [tex]Force=75N,Distance=15m,\theta=30[/tex]

Substitute in above expression.

        [tex]Workdone=75*15*cos(30)\\ \\ Workdone=75*15*0.866\\ \\ Workdone=974.25Joule[/tex]

Hence, the work done by child to move the system is [tex]974.25[/tex] Joules.

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calculate the magnitude of impulse applied to a 0.75 kilogram cart to change its velocity from 0.50 meters per second east to 2.00 meters per second east​

Answers

Answer:

1.125 N s towards  East

Explanation:

since both velocities are in same direction  hence change in velocity is

Δ V = final - initial

       = 2.00 - 0.50

       = 1.50 towards East

impulse = change of linear momentum

             = mass ×  change in velocity

            =  0.75 ×1.50

          =  1.125 N s towards  East

A charge is moving in a magnetic field that points to the left.
What direction can the charge move and experience no
magnetic force? Check all that apply
Oup
down
O left
right
into the screen
out of the screen

Answers

The charge experiences no magnetic force when it is moving to the left or to the right

Explanation:

The force experienced by a charge moving in a magnetic field is given by the equation

[tex]F=qvB sin \theta[/tex]

where

q is the magnitude of the charge

v is its velocity

B is the strength of the magnetic field

[tex]\theta[/tex] is the angle between the directions of v and B

From the equation, we observe that:

The force is zero when the charge is moving parallel (or anti-parallel) to the field, so when the angle between v and B is zero (or 180 degrees): [tex]sin 0^{\circ} = 0[/tex] ([tex]sin 180^{\circ}=0[/tex]The force is maximum when the charge is moving perpendicular to the field, so when the angle between v and B is 90 degrees: [tex]sin 90^{\circ}=1[/tex]

From the first observation, we can say therefore that the charge in the problem will experience no magnetic force when it is moving parallel (or anti-parallel) to the field. Since the magnetic field points to the left, this means that the charge will experience no force when it is moving in one of the following directions:

To the leftTo the right

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Final answer:

A charge moving in the direction of the magnetic field or the exact opposite direction experiences no magnetic force. Thus, if the magnetic field points to the left, the charge can move left or right without experiencing any magnetic force.

Explanation:

A charge moving in a magnetic field experiences a magnetic force that is always perpendicular to both the velocity of the charge and the magnetic field. This force is explained by the right-hand rule, where the thumb points in the direction of the velocity of the positive charge, the fingers point in the direction of the magnetic field, and the palm indicates the direction of the force for a positive charge, and the back of the hand indicates the force direction for a negative charge.

If a charge is moving left and the magnetic field points left, then according to the right-hand rule, there is no direction for the perpendicular force to act since the velocity of the charge is parallel to the magnetic field. Thus, a charge would experience no magnetic force if it moved parallel to the magnetic field. Therefore, the correct answers are:

Left - moving parallel to the field

Right - moving parallel to the field in opposite direction

If instead, the charge moves up or down, it will experience a magnetic force because the motion is perpendicular to the magnetic field. Similarly, moving into or out of the screen would also result in the charge experiencing a magnetic force, since this is another direction perpendicular to the magnetic field.

Which of these describes the majority of our space observations humans have utilized over the history of human space exploration?
A) Gamma ray telescope
B) radio wave telescopes
C) ultraviolet telescopes
D) visible light observatories

Answers

Gamma Ray telescopes are the one mostly used by humans for majority of space observations.

Answer: Option A

Explanation:

Since the year 1965, Gamma ray telescopes have attained a major area in space research. As gamma rays are emitted by most of the astrophysical particles like novae, black holes, dwarf stars, supernovae, neutron stars, pulsars, so it is easy to find any changes in space. Even highly energetic gamma burst can also be observed by these telescopes.

So, among the other telescopes like radio, ultraviolet, visible light observations, gamma ray telescopes are mostly preferred for space observations. As the other telescopes have low range of observations and they may have losses. But gamma rays does not interact with other particles, there will be less chance of loss of signals for gamma observations.

Answer:

d

Explanation:

visible light observations

What an object at rest stays at rest and an object in motion with the same speed and in the same direction unless acted upon by an unbalanced force is newton's 1st law of motion?
True
Or
False

Answers

Answer:

True.

Explanation:

Newton's First Law of Motion states that every object continues in it's state of rest or of uniform motion in a straight line unless acted upon by an external force.

The newt stays at rest and is an object in motion

Factors that influence Wellness

Answers

Answer:

Physical and mental factors, work, and lifestyle

Explanation:

I'm kind of taking a guess at this, but I'd assume these factors affect and influence personal wellness

Just after vertical launch from Earth surface, the space shuttle takes 8.0 s to reach a speed of 160 km/h. During this phase, what is the apparent weight of an 84 kg astronaut?

Answers

Answer:

1291.08 N

Explanation:

acceleration=change in speed per unit time

[tex]a=\frac {v-u}{t}[/tex] where v and u are final and initial velocities respectively.

u is zero and v=160 km/h converted to m/s becomes[tex]160\times \frac {1000m}{3600s}\approx 44.44 m/s[/tex]

acceleration=[tex]\frac {44.44-0}{8}\approx 5.56 m/s^{2}[/tex]

Apparent weight, [tex]F_N=m(g+a)[/tex]

Taking g as 9.81 and m as 84 Kg then

[tex]F_N=84(9.81+5.56)\approx 1291.08 N[/tex]

Final answer:

The astronaut's apparent weight just after launch is about 467.04 N. This is calculated using the equation F = ma, where m is the astronaut's mass and a is the shuttle's acceleration (derived from the given final velocity and time).

Explanation:

To calculate the apparent weight of the astronaut, we need to find the acceleration of the shuttle first. We'll use the formula v = u + at, where v is the final velocity, u is the initial velocity (zero in this case as it's a vertical launch), a is the acceleration, and t is the time. We're given that v = 160 km/h which is equivalent to 44.44 meters per second (160000 m / 3600 seconds) and t = 8 seconds.

Calculating for a = (v - u) / t, we get a = 5.56 m/s². Then we calculate the apparent weight using the equation F = ma, where F is the force (apparent weight) and m is the mass. Using m = 84 kg and a = 5.56 m/s², we find that F (the apparent weight) = 467.04 N (rounded to the nearest hundredths place).

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A dog, that has a mass of 16 kgs, runs across a yard. What is the average force applied to the dog from the ground as it runs across the yard?

Answers

Answer:

156.96 N

Explanation:

F=ma where m is the mass and a is acceleration

Substituting 16 Kg for m and 9.81 m/s2 for g then

F=16*9.81= 156.96 N


Question 49 (1 point)
What kind of relationship, if any, exists between an orbit's semimajor axis length and
its period?
A direct
B inverse
Cno relationship

Answers

Answer:

Orbit's semi-major axis length and  its period  is directly proportional.

Explanation:

Orbital period(T) is the time taken for an celestial object to make one complete revolution in the orbit around other object

According to  Kepler's laws  3rd of planetary motion  stating

The square of an orbital period T of a planet is “directly proportional” to the cube of the "semi-major axis"  of its orbit.

The orbital period  T is given by

[tex]T=2 \pi \sqrt{\frac{a^{3}}{\mu}}[/tex]

Where

a is the semi-major axis of the orbit

µ = GM  which is the standard gravitational parameter

With G is the gravitational constant  and M is the mass of  body.

a girl performed 50j of work lifting a heavy box it took her 5 seconds to lift the box what is her power

Answers

Answer:

10 W

Explanation:

Power is work over time.

P = W / t

P = 50 J / 5 s

P = 10 W

Answer:

It is 10 W

Explanation:

As water moves down through the ground, what force is acting against it?

A. Capillary action
B. Saturation
C. Gravity
D. Permeability

Answers

As water moves down through the ground, the force that is acting against it is gravity, which is in option c, as gravity pulls the water down through the soil and towards the water table or the nearest body of water.

What is capillary action?

Gravity is a force that pulls objects towards each other, and it is what causes water to move downward through soil and rock. When it rains or when water is added to the soil, the force of gravity causes the water to percolate or move down through the soil and towards the water table or the nearest body of water. Capillary action refers to the ability of water to move upward through small spaces or pores, such as in soil or rock. It is caused by the surface tension of water and the adhesion of water molecules to surfaces.

Hence, as water moves down through the ground, the force that is acting against it is gravity, which is option c.

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Final answer:

The force acting against water as it moves down through the ground is Gravity(C). It pulls the water downwards, and this motion is resisted by the earth's material, which is referred to as permeability.

Explanation:

As water moves down through the ground, the force that is acting against it is Gravity(C). Gravity is the force of attraction that pulls two masses towards each other, in this case, the mass of the earth and the mass of water. This downward pull of water is resisted by the earth's material leading to the permeability of soil and rocks, that is the ability for water to flow through them. However, the answer to your actual question is Gravity as it’s the primary force pulling the water downwards.

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NEED ANSWER NOW PLZ!!


Carbon-14 undergoes radioactive decay in the reaction above. Determine the type of radiation emitted in this reaction and describe what is happening to the nucleus during this reaction.

A) Alpha radiation is emitted in this equation because the atomic number increases (from 6 to 7). This means a helium atom has been emitted from the nucleus.

B) Beta radiation is emitted in this equation because the atomic number increases (from 6 to 7). This means a neutron has decayed into a proton, which occurs by emitting an electron.

C) Beta radiation is emitted in this equation because the atomic number increases (from 6 to 7). This means a neutron has decayed into a electron, which occurs by emitting an proton.

D) Gamma radiation is emitted in this equation because the atomic number increases (from 6 to 7). This means a neutron has decayed into a proton, which occurs by emitting an electron.

Answers

Final answer:

OPTION B

Emission of beta radiation is what's occurring in the radioactive decay of Carbon-14. This is due to a neutron decaying into a proton and giving off an electron (beta particle), causing the atomic number to increment from 6 to 7.

Explanation:

In the case of Carbon-14 undergoing radioactive decay, the correct answer would be B) Beta radiation is emitted because the atomic number increases (from 6 to 7). This increase indicates that a neutron in the nucleus of Carbon-14 has decayed into a proton. This decay process emits an electron, known as a beta particle, and this is what gives this type of radioactive decay its name: beta decay. The emission of this beta particle is what causes the atomic number to increase (as the atomic number is simply the number of protons in the nucleus), and thus transforms the Carbon-14 nucleus into a Nitrogen-14 nucleus.

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John traveled East at 10 m/s for ten
seconds. He realized he had gone too
far and made a U-turn. He traveled
West at 5 m/s for six seconds. Calculate
John's displacement.
a. 30 m
b. 70 m
C. 100 m
d. 130 m

Answers

Answer:

Option D

130 m

Explanation:

From the concept of speed, distance=speed*time

When traveling East, displacement=10*10=100 m (since he takes 10 seconds while traveling at a speed of 10 m/s)

When traveling West, displacement=5*6=30 m (since John takes 6 seconds to travel at a speed of 5 m/s)

Total displacement=Displacement East+ Displacement West=100+30=130 m

One day in second grade, Chris drank chocolate milk before recess. She then played hard during recess and got sick from the heat. That was years ago, but Chris never drank chocolate milk again because even thinking about chocolate milk makes her feel sick. Chris is most likely experiencing __________. A. food aversion B. superstition C. phobia D. learned helplessness

Answers

Answer:

A. Food Aversion

It's right on ED2020, good luck!! Stay healthy and safe!!

Final answer:

Chris is experiencing food aversion, which is an associative learning process where one learns to avoid certain tastes associated with past sickness.

Explanation:

Chris is most likely experiencing a food aversion. This type of conditioning occurs when an individual associates the taste of a certain food or drink with a negative experience, such as illness, and then avoids it in the future. The event where Chris felt sick after playing hard in heat post-drinking chocolate milk exemplifies how a single adverse incident can lead to a long-lasting aversion. This aversion is a learned response when the conditioned stimulus (in Chris's case, chocolate milk) is paired with an unconditioned stimulus (feeling sick) resulting in a conditioned aversion to the food or drink.

Similar to Chris's experience with chocolate milk, taste aversion conditioning can happen when flavors associated with stomach pain or illness become avoided and disliked, an evolutionary mechanism important for animals and humans to avoid potential toxins. An example is how cancer patients may develop aversions to certain foods right before chemotherapy since the treatment often leads to nausea or sickness, strengthening the association between the flavor and the negative reaction.

a ball is thrown downward with an initial speed of 7m/s. the balls velocity after 3 seconds is m/s

Answers

Answer: -36.4

Explanation:

It says that the initial speed is 7 and the time is 3. acceleration is -9.8 ( its always 9.8 but since its going downward its negative)

The equation you want to use is Vf = Vo + AT.

When you plug in the answers it is

0 = 7 + -9.8(3)

-9.8(3) = -29.4

Then add 7

and you get -36.4

The ball's velocity after 3 seconds is 24.4 m/s.

The ball is thrown downward with an initial speed of 7 m/s. The acceleration due to gravity is 9.8 m/s². So, the ball's velocity is increasing at a rate of 9.8 m/s^2.

After 3 seconds, the ball's velocity is 7 m/s + 3 * 9.8 m/s²

= 24.4 m/s.

Therefore, the ball's velocity after 3 seconds is 24.4 m/s.

First, we find the acceleration of the ball by multiplying the acceleration due to gravity by the time it has been falling.

Next, we add the initial velocity of the ball to the acceleration we just found to find the final velocity of the ball.

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Answer the question please

Answers

Answer:

B. solubility I think lmk if its wrong

The property that she is testing is what is known as the boiling point. This describes the temperature (given a pressure) that a liquid begins to transition into the gas phase. By monitoring the production of bubbles (gas), she is investigating the boiling points of the two liquids. Hope this helps!

Rodney is trying out one of Santa's new games that consists of three pieces that blow apart if the wrong key is inserted into the door. The elf picks the wrong key and the board explodes. One piece of mass 2 kg goes off at an angle of 60° from the horizon at 10 m/s. A second piece of mass 1.2 kg travels at an angle of 180° and is moving at 15 m/s.

a) find the momentum of the third piece.

b) find the velocity of the third piece if it's mass is 3 kg.​

Answers

a) The momentum of the third piece is 19.1 kg m/s

b) The velocity is 6.4 m/s at an angle of [tex]-65^{\circ}[/tex]

Explanation:

a)

We can solve this problem by applying the law of conservation of momentum in 2D. In fact, the total momentum of the board before the explosion must be equal to the total momentum of the 3 pieces after the explosion.

Before the explosion, the total momentum is zero, since the board is at rest. Resolving into the x- and y- components, this means that the two components of the momentum are zero:

[tex]p_x = 0\\p_y = 0[/tex]

After the explosion, we have:

[tex]p_x = (2 kg)(10 m/s)( cos 60^{\circ}) + (1.2 kg)(15 m/s)(cos 180^{\circ})+p_{3x}[/tex]

where [tex]p_{3x}[/tex] is the x-component of the momemtum of the 3rd piece. By solving,

[tex]p_x = -8+p_{3x}[/tex]

And since the x-momentum must be conserved,

[tex]0=-8+p_{3x} \rightarrow p_{3x}=8 kg m/s[/tex]

Similarly, along the y-axis,

[tex]p_y = (2 kg)(10 m/s)( sin 60^{\circ}) + (1.2 kg)(15 m/s)(sin 180^{\circ})+p_{3y}[/tex]

where [tex]p_{3y}[/tex] is the y-component of the momemtum of the 3rd piece. By solving,

[tex]p_y = 17.3+p_{3y}[/tex]

And since the y-momentum must be conserved,

[tex]0=17.3+p_{3y} \rightarrow p_{3y}=-17.3 kg m/s[/tex]

So now we can find the momentum of the third piece:

[tex]p_3 = \sqrt{p_{3x}^2+p_{3y}^2}=\sqrt{8^2+(-17.3)^2}=19.1 kg m/s[/tex]

b)

The momentum of the third piece is given by

[tex]p_3 = m v_3[/tex]

where

m = 3 kg is the mass of the piece

[tex]v_3[/tex] is the velocity

Solving for [tex]v_3[/tex], we find

[tex]v_3 = \frac{p_3}{m}=\frac{19.1}{3}=6.4 m/s[/tex]

We can also find the direction, which is identical to the direction of the momentum, by using the following equation:

[tex]\theta = tan^{-1}(\frac{p_{3y}}{p_{3x}})=tan^{-1}(\frac{-17.3}{8})=-65^{\circ}[/tex]

So, the third piece flies off at 6.4 m/s at an angle of [tex]-65^{\circ}[/tex].

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Find the speed of a dog that runs .05 km in 1 min (convert to meters and seconds)​

Answers

.05km= 50m

1m=60s

s= d/t

50/60

.83 m/s

A basic substance consisting of only one kind of atom is called a(n)
ion
compound
element
molecule

Answers

Answer:

Element

Explanation:

A man can jog 10 miles in 90 minutes. What’s his speed in mph?

Answers

Answer:

hi there!

the correct answer to this question is: 6.67 mph

Explanation:

you convert minutes to hours

10 miles * 60 mins / 90 mins

Final answer:

To find the man's jogging speed in mph, divide the distance he jogs, 10 miles, by the time it takes in hours. He jogs 10 miles in 1.5 hours (90 minutes), giving him a speed of 6.67 mph.

Explanation:

To calculate the man's speed in mph (miles per hour), we need to divide the distance traveled by the time it took him to travel that distance. The man jogs 10 miles in 90 minutes. Since there are 60 minutes in an hour, we convert 90 minutes to hours by dividing by 60, which equals 1.5 hours.

To find the speed, we use the formula:

Speed = Distance ÷ Time

Speed = 10 miles ÷ 1.5 hours

Speed = 6.67 mph

This calculation shows that the man's jogging speed is 6.67 mph.

vector A has a magnitude of 60 units eastward and vector
B has a magnitude of 11 units northward. What is the
magnitude of the resultant between vectors A & B?

Answers

Answer:

Resultant Vector will 71 units

Explanation:

if we draw vector A in eastward direction such that its head coincides with the tail of vector B in northward direction then the resultant vector will be equal to

Va+ Vb= 60 +11= 71 units

and its direction will be from the tail of vector A to the head of vector B

What does the slope of a Position vs. Time graph represent?

Answers

Your question asks what the slope of a Position vs. Time graph represents.

Your answer would be Velocity.

The slope of a Position vs. Time graph would represent the velocity of the object.

If the slope is positive, then the object has a positive velocity ,in which it is going forward.

If the slope is negative, then the object has a negative velocity, which means that it's going the opposite direction, or backwards.

If the slope is at a "horizontal" position, this means that the object is stopped or isn't moving at all.

Final answer:

The slope of a Position vs. Time graph represents velocity, specifically the instantaneous velocity at a given point in time.

Explanation:

This means that when you look at a graph and see the position of an object on the y-axis and the time on the x-axis, the steepness of the curve or straight line (slope) that describes the object's motion gives you a measure of how fast the object is moving (velocity). More importantly, the slope of this graph at any particular point corresponds to the instantaneous velocity at that point in time.

To further illustrate, consider a car that is speeding up. The graph representing its position vs time would start at a lower point (indicating zero or smaller velocity) and rise to a high point (indicating a high velocity), showing it is accelerating. The actual value of the slope would give you the car's speed or velocity at any particular time.

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