Question 49 (1 point)
What kind of relationship, if any, exists between an orbit's semimajor axis length and
its period?
A direct
B inverse
Cno relationship

Answers

Answer 1

Answer:

Orbit's semi-major axis length and  its period  is directly proportional.

Explanation:

Orbital period(T) is the time taken for an celestial object to make one complete revolution in the orbit around other object

According to  Kepler's laws  3rd of planetary motion  stating

The square of an orbital period T of a planet is “directly proportional” to the cube of the "semi-major axis"  of its orbit.

The orbital period  T is given by

[tex]T=2 \pi \sqrt{\frac{a^{3}}{\mu}}[/tex]

Where

a is the semi-major axis of the orbit

µ = GM  which is the standard gravitational parameter

With G is the gravitational constant  and M is the mass of  body.


Related Questions

SP: Describe what moment is,
give the formula and unit for it.
Rearrange the equation to make
a force as a subject

Answers

Answer:

Moment of force (often just moment) is a measure of its tendency to cause a body to rotate about a specific point or axis.ORA force that tends to cause rotation.

Explanation:

The unit for moment is N/m(newton per meter).

The formula for moment of force(also known as torque) is:

T= r.F sinθ

To make force as a subject,

T = r.F sinθ

T/r = F sinθ

F = T / r sinθ

An astronaut weighs 700 N on Earth what is the astronaut's Mass on Earth?

Answers

Answer:

70 kg

Explanation:

On earth, g = 9.8 m/s².

W = mg

700 N = m (9.8 m/s²)

m ≈ 71 kg

Rounded to 1 significant figure, the astronaut's mass is 70 kg.

__________ is the process of separating one’s identity from a particular aspect of performance or group. A. Stereotyping B. Perception C. Motivation D. Disidentification

Answers

Answer:

The answer is dis identification.

Explanation:

Answer:

D

Explanation:

D.

Disidentification

Urgently!
Crickets perceive sounds with a frequency of 300 - 8000 Hz. What is the period of sound vibrations and the length of the sound wave perceived by an insect?

Answers

Answer:

0.003333 s to 0.000125s or from 3.33ms to 0.125ms wher m is for milli

1.1m to 0.04125 m

Explanation:

T= 1/f=

if f= 300Hz then T = 1/300 =0.003333 s

if f= 8000 then T= 1/8000 = 0.000125s

now v=f×wave length

or wavelength = speed/ frequency

when f = 300 Hz

wavelength = 330/300=1.1 m

wavelength = 330/8000 = 0.04125m

note : i have taken speed of sound as 330 m/s you can take any value given in between 330m/s to 340m/s

An airplane takes off from Boston for
the 980 km trip to Detroit. The plane
lands two hours later. Which of the
following best describes the average
speed and direction of the airplane's
flight?
A. 325 km/h W
B. 490 km/h W
C. 980 km/h W
D. 1960 km/h W​

Answers

Answer:B

Explanation:

Calculate speed using equation:V=S/t

S=980 km ------------   distance Boston-Detroit

t=2h ---------------------   time

v=?

------------------------

V=S/t

V=980km/2h

V=490km/h

Final answer:

The average speed of the airplane for the trip from Boston to Detroit, covering a distance of 980 km in two hours, is 490 km/h. The direction of flight is westward.

Explanation:

The subject of this question is Physics, and it would typically be encountered by students at the High School level. The question involves calculating the average speed and direction of an airplane's flight from Boston to Detroit, which is a 980 km trip that the airplane completes in two hours. To find the average speed, we divide the total distance traveled by the total time of the trip.

The calculation would be Average speed = Total distance / Total time = 980 km / 2 hours = 490 km/h. Since the plane is flying from Boston to Detroit, the general direction is westward. Therefore, the best description of the airplane's average speed and direction is 490 km/h West.

What is the difference in light that is refracted compared to light that is reflected? Think in terms of speed of light as well as what happens to light waves when they interact with a medium.

Answers

Answer:

The refracted light wave is bent at an angle while the reflected light wave is bounced back either at 90° or at angle less than 180°.

The refracted light wave changes its speed when it moves from one medium to another based on the density of the medium.

The reflected light does not change its speed once it contacts another medium. It just bounces back with the same speed.

Explanation:

A 2 000-kg sailboat experiences an eastward force of 3 000 N by the ocean tide and a wind force against its sails with a magnitude of 6 000 N directed toward the northwest (45 N of W). What is the magnitude of the resultant acceleration? with steps, please.

Answers

Answer:

The magnitude of the resultant acceleration is 2.2 [tex]m/s^2[/tex]

Explanation:

Mass (m) of the sailboat =  2000 kg

Force acting on the sailboat due to ocean  tide is [tex]F_1[/tex] = 3000N

Eastwards means takes place along the positive x direction

Then[tex]F_{1x}[/tex] = 3000N and [tex]F_{1y}[/tex]= 0

Wind Force acting on the Sailboat is[tex]F_2[/tex]  = 6000N directed towards the northwest that means at an angle  45 degree above the negative x axis

Then  

[tex]F_{2x}[/tex] = -(6000N) cos 45 degree = -4242.6 N

[tex]F_{2y}[/tex]  = (6000N) cos 45 degree = 4242.6 N

Hence  , the net force acting on the sailboat in x direction is  

[tex]F_x = F_{1x}+ F_{2x}[/tex]

=  - 3000 N + 4242.6 N

=  - 3000 N +4242.6 N

= 1242.6N

Net Force acting on the sailboat in y direction is  

[tex]F_y = F_{1y}+ F_{2y}[/tex]

= 0+ 4242.6N

= 4242.6N

The magnitude of the resultant force =

Using pythagorean theorm of 1243 N and 4243 N

[tex]\sqrt{(1242.6)^2 + (4242.6)^2[/tex]

[tex]\sqrt{(1544054.76) + (17999654.8)}[/tex]

[tex]\sqrt{(19543709.5)^2}[/tex]

4420.8 N

F = ma

[tex]a = \frac{F}{m}[/tex]

[tex]a =\frac{4420.8}{ 2000}[/tex]

=2.2 [tex]m/s^2[/tex]

Convert the following units
4.8 g/cm^3 to kg/m^3

Answers

Final answer:

To convert 4.8 g/cm³ to kg/m³, multiply by the conversion factors (0.001 kg/g) and (1,000,000 cm³/m³) to obtain 4800 kg/m³.

Explanation:

To convert the density from grams per cubic centimeter (g/cm³) to kilograms per cubic meter (kg/m³), we use the conversion factors: 1 g = 0.001 kg and 1 cm³ = 0.000001 m³. Therefore, to convert 4.8 g/cm³ to kg/m³, multiply by the conversion factors:

4.8 g/cm³ × (0.001 kg/g) × (1,000,000 cm³/m³) = 4.8 × 1000 kg/m³ = 4800 kg/m³.

Thus, the density is 4800 kg/m³ when converted from 4.8 g/cm³.

HELP FAST You should visit a sporting goods store so that you can see the products and try them out in person before you make a purchase Question 3 options: True False

Answers

Answer:

true

Explanation:

if you purchase something online, it often times gets damaged or mixed up with a different product.

Answer:

False

Explanation:

You can purchase online without seeing or trying the goods you want.

If you trust in the store in which you are purchasing (because it has a good online reputation or it was recommended by a friend), an online bought is a good option, it is faster, it is done without leaving your home and many times it is even cheaper than bought in person.

A .005kg projectile leaves a 1500kg launcher with a velocity of 750 m/s. What is the recoil velocity of the projectile

Answers

Answer:

The recoil velocity of the projectile is 0.0025m/s

Explanation:

Given:

Mass of the projectile =0.005kg

Mass of the launcher = 1500kg

Velocity =  750 m/s.

To Find:

The recoil velocity of the projectile = ?

Solution:

The recoil velocity is the obtained by dividing the "recoil momentum"  by the "mass of the recoil body".  The recoil momentum is equal to the momentum of the other body. The momentum of the other body is equal to it mass times its velocity.

Lets find the recoil momentum,

Recoil momentum = mass of the projectile X velocity

Recoil momentum =[tex]0.005 \times 750[/tex]

Recoil momentum = 3.75

Now Recoil Velocity,

Recoil Velocity = [tex]\frac{\text { Recoil Momentum}}{\text {Mass of the launcher}}[/tex]

Recoil Velocity = [tex]\frac{ 3.75}{1500}[/tex]

Recoil Velocity = 0.0025m/s

The initial kinetic energy imparted to a 0.020 kg bullet is 1200 J. (a) Assuming it
accelerated down a 1.00 m rifle barrel, estimate the average power delivered to it during
the firing. (b) Neglecting air resistance, find the range of this projectile when it is fired
at an angle such that the range equals the maximum height attained.

Answers

Answer:

(a) Power= 207.97 kW

(b) Range= 5768.6 meter

Explanation:

Given,

Mass of bullet, [tex]m=0.02 kg[/tex]

Kinetic energy imparted, [tex]K=1200 J[/tex]

Length of rifle barrel, [tex]d=1 m[/tex]

(a)

Let the speed of bullet when it leaves the barrel is [tex]v[/tex].

Kinetic energy, [tex]K=\frac{1}{2} mv^{2}[/tex]

[tex]v=\sqrt{\frac{2K}{m} }[/tex]

[tex]=\sqrt{\frac{2\times1200}{0.02} }[/tex]

[tex]=346.4m/s[/tex]

Initial speed of bullet, [tex]u=0[/tex]

The average speed in the barrel, [tex]v_a_v_g=\frac{u+v}{2}[/tex]

[tex]=\frac{0+346.4}{2} \\=173.2 m/s[/tex]

Time taken by bullet to cross the barrel, [tex]t=\frac{d}{v} [/tex]

[tex]=\frac{1}{173.2}\\ =0.00577 second[/tex]

Power, [tex]P_a_v_g=\frac{W}{t}[/tex]

[tex]=\frac{1200}{0.00577} \\=207.97kW[/tex]

(b)

In projectile motion,

Maximum height, [tex]H_m=\frac{v^2\sin^2\theta}{2g} \\[/tex]

Range, [tex]R=\frac{v^2\sin2\theta}{g}[/tex]

given that, [tex]H_m=R[/tex]

then, [tex]\frac{v^2\sin^2\theta}{2g}=\frac{v^2\sin2\theta}{g}\\\sin^2\theta=2\sin\theta\cos\theta\\\\\tan\theta=4\\\theta=\tan^-^14\\\theta=75.96^0\\R=\frac{v^2\sin2\theta}{g}\\=\frac{346.4^2\times\sin(2\times75.96)}{9.8}\\5768.6 meter[/tex]

When an object rolls over a surface, the kind of friction that occurs is called
round friction
A. True
B. False

Answers

Answer:

False, When an object rolls over a surface, the kind of friction that occurs is called ROLLING FRICTION

Explanation:

The correct term for the kind of friction that occurs when an object rolls over a surface is rolling friction, not round friction, making the statement False. Rolling friction, which is different from sliding friction, is weaker and allows a rolling object to travel farther.

The kind of friction that occurs when an object rolls over a surface is not called round friction, making the statement False. When an object rolls over a surface, the friction is correctly called rolling friction. Rolling friction is a force that resists the motion of an object rolling on a surface. It happens due to deformations at the contact area between the rolling object and the surface. Unlike sliding friction, which occurs when there is relative motion between two surfaces in contact without rolling, rolling friction generally requires less force to overcome due to the reduced contact area and the nature of the motion.

During rolling motion, especially without slipping, a kinetic friction force can also arise if there is relative motion between the surfaces. However, rolling friction is primarily responsible for slowing down a rolling object over time, even in the absence of air resistance. It is significantly weaker than sliding friction, allowing a rolling object to travel much farther than it could slide on the same surface. The force of rolling friction is necessary for rolling motion, as it provides the torque needed to change the object’s angular momentum.

9. The most important member of the convention was a ___-year-old scholarly lawyer from
Virginia, James Madison
A. 46
B. 26
C. 36
D. None of the above​

Answers

James Madison was C. 36 when he attended the convention.

Why Apparent weight of substance is less than it Real weight?​

Answers

Answer:

The apparent weight is less than that of the real weight because of buoyancy.

Explanation:

Buoyancy is the upward thrust that is experienced by the object that is either fully or partially immersed in the object. The weight of the immersed object will be equal to the mass of the liquid that is displaced by the object. Buoyancy can be calculate based on Archimedes's Principle.  Buoyancy also acts in the air, the normal force is reduced than the force of gravity. Buoyancy is the ability to float in liquid as well as in air. This floating happens when various forces acts on the opposite direction. The direction of the force will always remain upwards.

A train is moving with the speed of light(c=3*10^8m/s) around the Earth. How much time will it take to complete one round trip along the equator on the surface of the Earth if it's radius is 6400km

Answers

Answer:

t = 0.13 [s]

Explanation:

We know that the speed of light is equal to c = 3 * 10^8m/ s, equivalent to 300000000 [m / s] and the radius of the Earth equal to 6400 [km] or 6400000 [m].

The speed definition is given as:

[tex]c = \frac{x}{t} \\where:\\c = velocity or speed light [m/s]\\t = time [s]\\x = distance [m][/tex]

But we need to know the value of x.

We know that the Earth's equator resembles a circumference, and we need to know the length of the circumference that will be the value of x.

[tex]x =2*\pi *r\\where:\\r = Earth radius [m]\\replacing:\\x = 2*\pi *6400000 = 40212385.97[m][/tex]

Then we can find the time.

[tex]t=\frac{40212385.97}{300000000} \\t=0.13[s][/tex]


Please help please help

Answers

Answer: p= m/v so 90kg/.075m^3 = 1,200

2a. .35 m 1.1 m and .015 m

2b. 35 cm x 110 cm x 1.5 cm = 5,775 cm^3 = 57.75 m^3

mass= pv

2700•57.75= 155,925 kg

mass= 155,925 kg

volume= 57.75 m^3

Explanation: physics

A trio of students push a 65 kg crate. The first student pushes 31 N [e], the second student pushes 28 N [s] and the third student pushes 39 N [w]. draw the FBD for the crate.

Answers

Answer:

The free body diagram is attached.

Explanation:

A force of 31[N] to the east, the second force goes to the south and it is equal to 28[N], the third force goes to the west and it is equal to 39 [N].

We can consider the crate as a particle. And all the forces are acting over the particle.

A 3.0-kilogram cart possesses 96 joules of kinetic
energy. Calculate the speed of the car.

Answers

Answer:

8.0 m/s

Explanation:

KE = ½ mv²

96 J = ½ (3.0 kg) v²

v = 8.0 m/s

The kinetic energy of the object is the energy conserved due to the motion of the object.

A cart of 3 kg mass has the kinetic energy of 96 joules hence the speed of the cart is 8 m/s.

How do you calculate the speed of the cart?

Given that cart has a kinetic energy of 96 Joules and the mass of the cart is 3 kg.

The formula for kinetic energy is given below.

[tex]KE = \dfrac {1}{2} mv^2[/tex]

Where KE is the kinetic energy of the cart, m is the mass of the cart and v is the speed of the cart.

Substituting the given values in the above formula to calculate the speed of the cart.

[tex]96 = \dfrac {1}{2} \times 3\times v^2[/tex]

[tex]v^2 = 64[/tex]

[tex]v = 8 \;\rm m/s[/tex]

Hence we can conclude that the speed of the cart is 8 m/s.

To know more about kinetic energy, follow the link given below.

https://brainly.com/question/999862.

what is the acceleration of a 0.50 kilogram ball that hit with a force of 21.5

Answers

Answer:

43m/s^2

It's derived from the equation F=ma.

Assuming that the force is in SI units which is Newtons, the answer is as such. The working is attached

btw,next time put all the units down when asking

Applying Newton's second law of motion, the relation between force and mass is given as F = m * a. The acceleration of a 0.50-kilogram ball hit with a force of 21.5 newtons is 43.0 m/s².

To calculate the acceleration of a 0.50-kilogram ball that is hit with a force of 21.5 newtons, we use Newton's second law of motion, which states that the force applied to an object equals mass times acceleration (F = ma). To find the acceleration (a), rearranging this equation the acceleration (a) would be:

a = F / m

a = 21.5 N / 0.50 kg

a = 43.0 m/s²

Therefore, the acceleration of the ball would be 43.0 meters per second squared (m/s²).

How does a fire prevention plan benefit your workplace

Answers

Answer

Explanation:

Establish a Fire Prevention Plan – A fire prevention plan provides facilities with documentation outlining the employees responsible for identifying combustible materials, fire hazards and heat-producing equipment. It also outlines the procedures necessary to prevent potential emergencies.

A fire prevention plan benefits the workplace by enhancing safety, reducing the risk of fires, and minimizing potential losses.

A workplace can benefit greatly from a well-executed fire protection plan. It primarily reduces the likelihood of fires, which can result in casualties, property damage, and business interruptions. Businesses may dramatically lower the risk of fires by recognizing potential fire dangers, developing safety procedures, and making sure that firefighting equipment is available and maintained.

A plan for fire prevention also improves workplace security in general. It increases staff members' knowledge of the dangers of fire and instructs them on how to safely exit the building in case of an emergency. In addition to saving lives, this fosters a feeling of security and well-being among the staff, raising morale and productivity. It may also result in lower insurance prices.

To know more about fire prevention here https://brainly.com/question/29634607

#SPJ12

In a solid, the atoms are tightly locked in position and do not change position.


(B) True
(A) False

Answers

Answer:

(B) True

The answer is true.

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