Braces are important because they __________.
A.
protect you from impacts
B.
provide support for a weakened joint
C.
apply pressure to cuts and scrapes
D.
keep your joints cool and comfortable

Answers

Answer 1
I believe the answer is B) Provide support for a weakened joint. HOPE this helps
Answer 2

The correct answer would be B. To provide support for a weakened joint. I just took the test!


Related Questions

Which statement is true regarding the "relationship merry-go-round"?

A. By the age of 40, about 75% of Americans have married at least once.
B. Most people chose to remain single in order to pursue career goals.
C. Arranged marriages are no longer the norm in India.
D. In some cultures, romantic love was considered a form of madness.

Answers

A common finding with couples who can’t connect or resolve their problems is that they reason out or feel that it’s the other individual who can’t connect, not them. It’s the other individual that has the problem and they remain to think "I’m right and you’re wrong." The answer is letter a. In 40 percent of new weddings, one or both partners has been wedded no less than once before. Men are more probable to re-wed than women who've been wedded before.

What was the correct answer?

A girl delivering newspapers travels one block west then three blocks north then five blocks east. what is her resultant displacement?

Answers

3^2+4^2=25^2 = 5 units

Two cars are driving at the same constant speed on a straight road, with car 1 in front of car 2. car 1 suddenly starts to brake with constant acceleration and stops in 10 m. at the instant car 1 comes to a stop, car 2 begins to brake with the same acceleration. it comes to a halt just as it reaches the back of car 1. what was the separation between the cars before they starting braking?

Answers

Final answer:

To find the initial separation between two cars before braking, we use the kinematic equation related to uniform acceleration. By calculating the deceleration of car 1, we can determine the total stopping distance for car 2, which includes the initial separation distance plus the stopping distance of car 1.

Explanation:

The question involves the concept of uniform acceleration and the use of kinematic equations to determine the initial separation between two cars before they start braking. Under the assumption that both cars decelerate with the same constant acceleration and car 2 stops exactly at the position where car 1 initially started to brake, we can use the kinematic equation:

\[ v^2 = u^2 + 2as \]

Where \(v\) is the final velocity, \(u\) is the initial velocity, \(a\) is the acceleration, and \(s\) is the distance. Since car 1 stops in 10 m, we can find the acceleration by setting \(v=0\), and since car 2 stops at the back of car 1 exactly, the initial separation
\(s\) is actually the distance car 2 travelled while car 1 was braking plus the 10 m stopping distance of car 1.

To solve this, we first calculate the acceleration of car 1 as it comes to a stop:

\[ 0 = u^2 + 2a(10) \]

This gives us the value of \(a\), and since car 2 has the same acceleration and stops in the same way, it will travel a distance of 10 m after starting to brake, plus the initial separation distance while car 1 was braking. This total distance equals the stopping distance of car 1, which is 10 m, plus the distance car 2 travels before it starts braking.

Therefore, the initial separation between the two cars before braking started is the distance car 2 travels while car 1 is braking (which can be calculated using the found acceleration and the fact that car 2 starts braking 10 m after car 1 has come to a stop).

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When Emeka was first training his dog, Smooches, to heel he would give Smooches a treat when she stayed close during walks. Now Smooches stays right by Emeka's side, even when she is not on her leash. In this case, a. the dog treats were positive reinforcers for staying close. b. the dog treats were negative reinforcers for staying close. c. the staying close was a positive reinforcer for receiving dog treats. d. the staying close was a negative reinforcer for receiving dog treats.

Answers

Answer a. is correct. In this case the dog treats were positive reinforcers for staying close (the desirable behaviour). Repeated rewards for a certain behaviour work as positive reinforcers.

PLZZZZ I NEED HELP ASAP!!!!

Would Wegener have been more or less successful in convincing scientists today than he was when he proposed his ideas? Why or why not?

Answers

I believe Alfred Wegener would be much more succesful today.
Alfred wegener presented his continental drift hypothesis in 1912, and his idea was dismissed back then (he died in 1930s.)
But after entering 1950s, many scientists started to accepted the idea of the continental drift, which means that the scientific community just only accepted his idea 20 years after his death.

A planet is in circular orbit around the sun. its distance from the sun is nine times the average distance of the earth from the sun. the period of this planet, in earth years, is:

Answers

By the Kepler's third law, the time period of this planet in earth years can be calculated to be 8 years.

What is Kepler's third law?

Kepler's Third Law states that the squares of the orbital periods of the planets are directly proportional to the cubes of the semi-major axes of the planet's orbits. Kepler's Third Law implies that the period for a planet to orbit around the Sun increases rapidly with the radius of its orbit.

In planetary motion, the planet's net external torque is equal to zero. As a result, the angular momentum will not change.

T² is proportional to r³, and the orbital period square is proportional to the distance cubes.

(Tearth/ Tplanet)² = (rearth/ r planet)³

The planet's distance from the sun is 4 times the semi-major axis of the earth's orbit.

(Tearth/ Tplanet)² = (1/4)³

Tearth = Tplanet × √1/64 = Tplanet × (1/8)

Tplanet = 8 × Tearth

Tearth = 1 year

Tplanet = 8 years

Therefore, the time period of this planet is 8 years.

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Your question is incomplete, most probably the complete question is:

A planet is in a circular orbit around the sun. It distance from the sun is 4 times the semi major axis of earth's orbits. The period of the planets is

earth years

Final answer:

Using Kepler's third law of planetary motion, the period of a planet in circular orbit around the Sun at a distance of nine times the Earth's from the Sun is calculated to be 27 Earth years.

Explanation:

The question asks to determine the orbital period of a planet that is nine times farther from the Sun than the Earth, using Kepler's third law, which relates a planet’s orbital period to its distance from the Sun. The law states that the orbital period squared (P^2) is proportional to the average distance from the Sun cubed (a^3). Given that the Earth's average distance from the Sun is about 150 million km (1 astronomical unit or AU), the planet in question is 9 AU from the Sun.

According to Kepler's third law, (P_earth/P_planet)^2 = (a_earth/a_planet)^3. We know P_earth is 1 year and a_earth is 1 AU, so substituting for a_planet with 9 AU, we get (1 year / P_planet)^2 = (1 AU / 9 AU)^3.
Solving this equation for P_planet gives us an orbital period of 3^3, or 27 Earth years for the planet.

what velocity does a 2kg mass have when its kinetic energy is 16 J

Answers

Final answer:

The velocity of a 2kg mass with a kinetic energy of 16 J is 4 m/s. This result is obtained by rearranging and plugging the given values into the kinetic energy formula.

Explanation:

To find the velocity of a 2kg mass when its kinetic energy (KE) is 16 J, we can use the kinetic energy formula:

KE = (1/2)mv²

where:

m is the mass of the objectv is the velocity of the object

By rearranging the formula to solve for v, we get:

v = √(2KE/m)

Substituting the given values:

v = √(2 × 16 J / 2 kg)

v = √(16 J / kg) = 4 m/s

So, the velocity of the 2kg mass when its kinetic energy is 16 J is 4 m/s.

Final answer:

The velocity of a 2 kg mass with 16 J of kinetic energy is 4 m/s, calculated using the kinetic energy formula KE = 0.5 * m * v² and solving for v.

Explanation:

To find the velocity of a 2 kg mass when its kinetic energy is 16 J, we can use the kinetic energy formula:


KE = ½mv²

where:

KE is the kinetic energy,

m is the mass,

v is the velocity.

First, we can solve for v:

v = √(2KE/m)

Substitute the given values (KE = 16 J and m = 2 kg) into the formula:

v = √(2*16 J / 2 kg)

v = √(16 J/kg)

v = 4 m/s

Therefore, the velocity of the 2 kg mass is 4 m/s.

To a stationary observer, a bus moves north with a speed of 10 m/s. A man inside walks toward the back of the bus with a speed of 0.4 m/s relative to the bus. What is the velocity of the man according to a stationary observer? A. 0.4 m/s north B. 10.4 m/s north C. 10 m/s north D. 9.6 m/s north

Answers

An observer would see the man moving north with a velocity of 9.6 m/s

Which of the following would most likely result in a flash flood?

An ice storm

Melting snow on a plain

Excess precipitation in one location

A tornado with speeds of 110 km/h

Answers

excess precipitation in one location 

c a tornado with speeds of 110km/h

When rocks experience high temperatures and differential stresses deep in the earth, their grains tend to ________?

Answers

Break into small particles. The heat causes the rock to break up and form pebbles or sand. Hope that helped. Have a nice day

A force of 40 N is applied on a body so that it attains a velocity of 20 m/s in 5 s. What is the mass of the body?

Answers

Let m (kg) = the mass of the body.

The body attains a velocity of 20 m/s in 5 s. Therefore the acceleration is
a = (20 m/s)/(5 s) = 4 m/s².

Note that
F = ma
where
F = applied force,
a = acceleration,
m = mass

The applied force is 40 N, therefore
(m kg)*(4 m/s²) = 40 N
m = 40/4 = 10 kg

Answer: 10 kg

Two identical spring-loaded dart guns are simultaneously fired straight forward. one fires a regular dart; the other a weighted dart. which dart goes farther?

Answers

Final answer:

In terms of physics, the regular dart goes further. Despite both darts being fired with the same energy from the spring-operated dart guns, the heavier weighted dart experiences a greater recoil force, which slows it down more than the regular dart.

Explanation:

The question asks which of two darts fired from identical spring-loaded dart guns would go farther: a regular dart or a weighted dart. This relates to the principles of physics, specifically, the concepts of energy conservation and Newton's third law.

In a spring-operated dart gun, energy is stored in the compressed spring and then transferred to the dart when the spring is released. This total energy put into the system is conserved in the closed system of the dart gun and dart, and it is mostly converted into the kinetic energy of the dart (ignoring the system's internal energy losses).

Newton's third law states that for every action, there's an equal and opposite reaction. In this case, the spring's force propels both darts forward. However, the reaction - the backward push on the dart - will be greater for the heavier weighted dart, slowing it more compared to the regular one. Therefore, the regular dart will go further given that it faces less opposing force from the gun itself.

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What is the minimum work needed to push a 950-kg car 710 m up along a 9.0° incline? ignore friction?

Answers

Answer:

Work done, [tex]W=1.03\times 10^6\ J[/tex]

Explanation:

It is given that,

Mass of the car, m = 950 kg

Distance up to the incline, d = 710 m

Angle of inclination of the car is 9 degrees.

When the car is push in the inclined path, the vertical component of the force will act on it such that the work done is given by :

[tex]W=mg\ sin\theta\times d[/tex]

[tex]W=950\times 9.8\times \ sin(9) \times 710[/tex]  

[tex]W=1.03\times 10^6\ J[/tex]

So, the minimum work needed to push a car is [tex]1.03\times 10^6\ J[/tex]. Hence, this is the required solution.

Final answer:

The minimum work needed to push a car up an incline can be found by calculating the work done against gravity. This is done by multiplying the mass of the car by the gravitational acceleration and the height, which can be deduced from the sin of the incline angle and the distance.

Explanation:

The question is asking for the minimum work done to push a car up an inclined plane. To solve this, you use the concept of work done against gravity. The formula for work done against gravity is Work = m * g * h, where m is the mass, g is the gravitational acceleration and h is the height. Since the distance and incline angle are provided, we can calculate the height with the trigonometric function sine, h = sin(angle) * distance. Substituting these values, we get Work = 950kg * 9.81m/s² * sin(9.0°) * 710m. The required calculation will then provide the answer to the work done in pushing the car up the incline.

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What is the difference between contact forces and forces that act through a force field?

Answers

Contact forces are forces that occur when two objects make contact, ex. Frictional Force. Non-contact forces occur without contact, ex. Gravitational Force or Electric Force.

Contact forces occur when two objects are in contact while Non-contact forces occur without any physical contact.

What is force?

Force is the action of push or pull which cause an object to move or stop.

Contact forces are the forces that come into existence when two objects come in contact to apply a force, For example: Frictional Force.

Non-contact forces takes place without any physical contact. For example: Gravitational force, Electric force, Magnetic force.

Thus, Contact forces occur when two objects are in contact while Non-contact forces occur without any physical contact.

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A ball with a mass of 0.25 kg hits a gym ceiling with a force of 78.0 n. what happens next?
a. the ball accelerates downward with a force of 80.5 n.
b. the ball accelerates downward with a force of 78.0 n.
c. the ball accelerates downward with a force of 2.45 n.
d. it depends on the height of the ceiling.

Answers

Final answer:

After the ball hits the ceiling with a force of 78.0 N, it experiences a net force of 75.5 N downward due to the impact force minus its weight, causing it to accelerate downward.

Explanation:

When a ball with a mass of 0.25 kg hits the gym ceiling with a force of 78.0 N, the force exerted on the ceiling by the ball is equal and opposite to the force exerted on the ball by the ceiling, according to Newton's third law of motion. Right after the impact, the ball will experience a net force in the downward direction which will cause it to accelerate downward. This net force can be calculated by subtracting the weight of the ball from the applied force. The weight of the ball, which is the force due to gravity, is the mass of the ball times the acceleration due to gravity (0.25 kg * 9.8 m/s² = 2.45 N). Thus, the net force on the ball after hitting the ceiling would be 78.0 N - 2.45 N = 75.5 N downward. Therefore, the correct answer to what happens to the ball next is that it accelerates downward with a force of 75.5 N.

Which of the following is an example of two sets?

Answers

 Five sit ups followed by a rest and then five more sit ups

i need a answer quick pleasee!!!!
Which of the following are correct statements about electrons

A. the valence shell is the furthest shell from the nucleus
B. there are four electrons in every electron shell
C. Electrons are in the nucleus of an atom
D. Electrons are located in layers around the nucleus

Answers

i think it is  c but i dont know

C. Electrons are in the nucleus of an atom.

If 31.25

10
18
electrons are removed from a
neutral dielectric, how much charge is stored in
coulombs?

Answers

1 C = 6.24150965(16)×10^18 electrons

31.25 x 10^18 electrons / (6.24150965(16)×10^18 electrons / C) = 5.007 Coulombs

I hope this helps. 

Answer:

it will become charged by Q = 5C

Explanation:

When electron is removed from matter then the system will get positively charged

So we will have

[tex]Q = Ne[/tex]

here N = number of electrons that is removed

[tex]N = 31.25 \times 10^{18}[/tex]

also we know that charge on one electron is given as

[tex]e = 1.6 \times 10^{-19}[/tex]

here we have

[tex]Q = Ne[/tex]

[tex]Q = (31.25 \times 10^{18})(1.6 \times 10^{-19})[/tex]

[tex]Q = 5 C[/tex]

so it will become charged by Q = 5C

List three examples of material culture.

Answers

Cars, transportation, clothes, and technology

There are various examples of material culture like Tool, Monuments, Machines, etc.

What is Material Culture?

The physical components of a society—the things that humans have created or altered—are referred to as material culture. These things are identified by their characteristics, whether chemical, physical, or biological, and they surround a population and its activities.

Shape, size, surface roughness, chemical composition and organization, molecular or cellular structure, color, and weight are examples of intrinsic properties of an entity.

Some more examples of material culture are :

AppliancesBeverages ArchitectureBooksCosmeticsCraftsFactories etc.

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A 9 m3 container is filled with 300 kg of r-134a at 10°c. what is the specific enthalpy (kj/kg) of the r-134a in the container? (4 significant figures)

Answers

Given the mass of R-134a m = 300kg; Volume of the container V = 9  cu. meter; Temperature of R-134a T = 10 degrees Celsius; 
Formula of specific volume : v = V / m = 9 / 300 = 0.03 cu. m / kg. 
At T = 10 degrees Celsius from saturated R-134a tables, vf = 0.0007930 cu. m /kg; vg = 0.049403 cu. m/kg. We know v = vf + x (vg - vf), so 0.03 = 0.0007930 + x (0.049403 - 0.0007930), which makes x = 0.601.  
Specific enthalpy of R-134a in the container is h = hf + x*hfg = 65.43 + (0.601 * 190.73). Answer is 180.0587 kJ/kg

Find an expression for the acceleration a of the red block after it is released. use mr for the mass of the red block, mg for the mass of the gray block, and μk for the coefficient of kinetic friction between the table and the red block. express your answer in terms of mr, mg, μk, and g.

Answers

Assuming pulley is frictionless. Let the tension be ‘T’. See equation below.

 

The expression for the acceleration of the red block after it is released from the rest is

[tex]\fbox{\begin{minispace}\\{a = \dfrac{{\left( {{m_g} - \mu {m_r}} \right)g}}{\left( {{m_g} + {m_r}} \right)}}\end{minispace}}[/tex]

Further Explanation:

The friction force acting on the red block placed on the table is acting opposite to the direction of motion of block. The motion of the system, of red block and grey block, is vertically downward direction. It implies that the tension on the string is less than the weight on the grey block.

Given:

The mass of the red block is [tex]{m_r}[/tex].

The mass of the grey block is [tex]{m_g}[/tex].

The coefficient of friction between red block and table is [tex]\mu[/tex].

Concept:

The net force on the red block is acting along the direction of motion of the system and is equal to the difference between the tension in the string and friction force.

The net force on the red block is:

[tex]{m_r}a = T - f[/tex]

Rearrange the above expression.

[tex]T = {m_r}a + f[/tex]

Substitute [tex]\mu {m_r}g[/tex] for [tex]f[/tex] in above equation.

[tex]\fbox{\begin\\T = {m_r}a + \mu {m_r}g\end{minispace}}[/tex]                                                           …… (1)

Here,  [tex]T[/tex] is the tension on the string, [tex]{m_r}[/tex] is the mass of the red block, [tex]a[/tex] is the acceleration of the system and [tex]g[/tex] is the acceleration due to gravity.

The net force on the grey block is along the direction of motion of the system and it is equal to the difference between the weight on grey block and tension on the string.

The net force on the grey block is:

[tex]{m_g}a = {m_g}g - T[/tex]                                                                        …… (2)

Here, [tex]{m_g}[/tex] is the mass of the grey block.

Substitute [tex]{m_r}a + \mu {m_r}g[/tex] for [tex]T[/tex] in equation (2).

[tex]{m_g}a = {m_g}g - \left( {{m_r}a + \mu {m_r}g} \right)[/tex]

Rearrange the above expression.

[tex]{m_g}a + {m_r}a = {m_g}g - \mu {m_r}g[/tex]

Simplify the above expression.

[tex]\fbox{\begin{minispace}\\{a = \dfrac{{\left( {{m_g} - \mu {m_r}} \right)g}}{\left( {{m_g} + {m_r}} \right)}}\end{minispace}}[/tex]

Learn more:

1. Change in momentum  https://brainly.com/question/9484203

2.  The motion of a body under friction brainly.com/question/4033012

3. A ball falling under the acceleration due to gravity brainly.com/question/10934170

Answer Details:

Grade: College

Subject: Physics

Chapter: Kinematics

Keywords:

Acceleration, friction, tension, system of two blocks, pulley mass system, motion, net force, string, block placed on the table, block hanging through a pulley, block is released from rest.

Velocity Describes ______ ?

A) speed and direction
B) speed and momentum
C) force and direction
D) gravity and direction

Answers

The answer would be A.) Speed and direction. 

This is because velocity is the displacement of an object during a specific unit of time. Since displacement includes a direction, so does velocity. 
•Speed with direction. 
Velocity is also a vector, a quantity that has both magnitude and direction. 

I hope this helps. 

describe the motion of an unanchored rowboat when a water wave passes

Answers

The boat will move up and down because of the waves but it will not move forward because the wave doesn't carry the boat with it.


Hope this helps. 

The motion of an unanchored rowboat when a water wave passes, the boat moves along with the waves. The boat doesn't move forward as waves could not take the boat along with it.

What is the motion of water waves?

The water waves are waves that have a combination of both longitudinal and transverse waves. Longitudinal waves are the waves that cause the medium to move parallel to the direction of the waves.

Transverse waves are the waves that cause the medium to move perpendicular to the direction of the waves. When the waves travel through the water, the particles move in a clockwise direction. Most of the waves are formed by the winds.

The motion of the unanchored rowboat, when water pass is a boat, is moved up and down along with the wave. But the boat does not move forwards along with the wave. Because the wave does not carry the boat with it.

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Seafloor spreading causes an oceanic plate to collide with a continental plate. If it were to go through the whole tectonic cycle, number the steps that would follow.

Answers

If you're going to ask a question, at least provide the steps or possible answers that you are provided with so that others can help you. Luckily, I know the exact question you are trying to solve. 
The order the steps go in is:
  The oceanic plate would subduct under the continental plate into the asthenosphere. 
From the intense heat and pressure within the mantle, the crust of the oceanic plate would mix with the rock of the mantle. 
Mantle convection would cause magma to rise up through divergent boundaries.

Answer: The entire process is mentioned in  step-wise below-

Firstly, two plates moves opposite to each other, due to this the crust gradually become thin and subsequently rises up.On continuous thinning of the crust, at one point, the magma will come out to the surface producing a small rift.Rifting continuously takes place and results in a rift valley,and slowly after millions of years will form an ocean.Then, the two diverging plate will collide with another oceanic or continental plate, in which the more denser oceanic crust will get subducted beneath the less denser one.This suducted plate, at much greater depth undergoes partial melting and slowly makes its way up to the crust.This magma on further pushing towards the surface, initiates sea floor spreading, thus repeating the entire cycle.

an object has a velocity of 8 m/s and a kinetic energy of 480 J what is the mass of the object

Answers

We have first velocity equals 8 m/s and the kinetic energy is 480 J

The order is the mass of the object

We have this formula K= mv2/2 isolating the mass we have m=k/v2

Now we will have m=480/8×8 > m= 480/64 m= 7.5kg now we deternimed the mass it's 7.5 kg

The Fahrenheit temperature reading is 98 on a hot summer day. What is this reading on the Celsius scale?

Answers

98 Fahrenheit would be equivalent to 36.6667 Celsius.
Hope this helped!
 
36.67 C is your answer

Which positive result could develop if carbon dioxide increases in the atmosphere? A. People breathe carbon dioxide, so Earth could support more human life. B. Plants give off carbon dioxide, so an increase in plant life could decrease world hunger. C. Carbon dioxide will protect people from the sun's radiation. D. Carbon dioxide will create more sunny weather, which is good for plant growth.

Answers

(C) would be the most correct answer. The increase in CO2 in the atmosphere would shield everyone like a blanket from the damaging solar radiation. However, it would also lead to the temperatures beginning to rise in some areas at unusual times of the year, throwing off the growing cycles of plants and animals in those areas.

A block has acceleration a when pulled by a string. if two identical blocks are glued together and pulled with twice the original force, what will their acceleration be?

Answers

F = m x a 2F = 2m x a a = 2F / 2m a = F/m The acceleration would be the same.

PLEASE HELP!!! A small, horizontal pipe with cross-sectional area A is joined to a large horizontal pipe with cross-sectional area 2A.  Both pipes are at the same height, and completely filled with water (density 1000 kg/m^3).  What is the pressure of the water in the large pipe if the speed of the water in the small pipe is one m/s and the pressure of the water in the small pipe is 1000 Pa?

Answers

Let point 1 be the small pipe and 2 be the larger pipe. Using the continuity equation,

ρ₁A₁v₁ = ρ₂A₂v₂

Since density is the same,
A₁v₁ = A₂v₂
A(1) = (2A)(v₂)
v₂ = 0.5 m/s

Then, we use the mechanical energy balance:

(P₂ - P₁)/ρ + (v₂² - v₁²)/2 = 0
(P₂ - 1000 Pa)/ 1000 kg/m³ + (0.5² - 1²)/2 = 0
P₂ = 1375 Pa

Thus, the pressure of the larger pipe is 1,375 Pa.

A 7-hp (shaft) pump is used to raise water to an elevation of 19 m. if the mechanical efficiency of the pump is 82 percent, determine the maximum volume flow rate of water. (round the final answer to four decimal places.)

Answers

Final answer:

To determine the maximum volume flow rate of water, we need to calculate the power supplied by the pump. Plugging in the values, the maximum volume flow rate of water is approximately 0.0019 m³/s.

Explanation:

Answer:

To determine the maximum volume flow rate of water, we need to calculate the power supplied by the pump. The formula to calculate power is power = force * velocity. If we convert the horsepower of the pump to watts (

1 hp = 746 watts), we can use the formula power = (7 hp * 746 W/hp) * (0.82 efficiency) to find the power supplied by the pump. Next, we can use the formula power = work/time = force * distance/time = force * velocity to find the force exerted by the pump. Finally, we can use the formula volume flow rate = velocity * area, where the area can be calculated using the equation area = π * (diameter/2)^2, to find the maximum volume flow rate of water. Plugging in the values, the maximum volume flow rate of water is approximately 0.0019 m³/s.

Other Questions
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