Can someone help me

Answer:

Histogram

Step-by-step explanation:

A histogram is a type that has a wide application in the field of statistics. Histograms provide a visual interpretation of numerical data, indicating the number of data points within a range of values. These values are called classes or boxes. The frequency of data per class is illustrated by the use of a bar. The higher the rod, the higher the data values in the box. The following steps are followed to create a histogram

-Data of the group is sorted from small to large.

-The data group has an opening.

-The group width is calculated using the data opening and number of groups. The number of groups may be given to the question or asked to be determined by the solver.

The odd number closest to the number found is then taken as the group width. The reason for taking an odd number is to simplify the process by obtaining whole numbers in the calculations.

-The data is grouped in a group width and a table is created with the number of data belonging to each group.

-The groups in the table are placed on the vertical axis and the data numbers are placed on the horizontal axis and a histogram graph is created.

Answer:

Step-by-step explanation:

Bill received $12 to feed a neighbor's cat for 3 days. His pay rate, x would be 12/3 = 4

He is paid $4 for feeding the cat per day.

To earn $40, the number of days that bill would have to work would be 40/4 = 10 days.

The neighbor's family is going on

vacation for 3 weeks next summer. There are 7 days in a week. Converting 3 weeks to days, it becomes 7 × 3 = 21 days.

The total amount of money that Bill will earn in 21 days would be

21 × 4 = $84

Since Bill wants to earn enough money to buy a CD player that costs $89, $84 won't be enough. He still needs $5 more and that would be from 2 more days.

Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is [tex]f(x)=x^{2}[/tex] in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

[tex]g'(0)=g'(1)[/tex]

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

[tex]g(x)=x^{2}\\g'(x)=2x\\ g'(0)=2(0) \Rightarrow g'(0)=0[/tex]

[tex]g(x)=x^{2}\\g'(x)=2x\\ g'(1)=2(1) \Rightarrow g'(1)=2[/tex]

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

[tex]f'(c)=\lim_{x\rightarrow c}\left [\frac{f(b)-f(a)}{b-a} \right ]\\\\g'(0)=\lim_{x\rightarrow 0}\left [\frac{g(b)-g(a)}{b-a} \right ]\\\\g'(1)=\lim_{x\rightarrow 1}\left [\frac{g(b)-g(a)}{b-a} \right ][/tex]

This is what the Bilateral Theorem says:

[tex]\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L[/tex]

Answer: 240 candied flowers

Step-by-step explanation:

She places 5 candied flowers on top of each cupcake she decorates. She will decorate 2 dozen cupcakes today. A dozen cupcakes is 12. 2 dozen cupcakes would be 24. Total number of candied flowers that she will place on top of each cupcake today would be 24 × 5 = 120 candied flowers.

She will also decorate 2 dozens tomorrow. Total number of candied flowers that she will place on top of each cupcake tomorrow would be 24 × 5 = 120 candied flowers

Total number if candied flowers that Fatima will use in 2 days would be 120 + 120 = 240

Answer:

The Inequality For determining number of equation written by Mustafa for school paper is [tex]x+\frac{1}{4}x+ \frac{3}{2}x\geq 22[/tex].

Mustafa has written more than 8 articles.

Step-by-step explanation:

Given:

Combined Total Number of articles = 22

Let the number of articles written by Mustafa be 'x'.

Now Given:

Heloise has written [tex]\frac{1}{4}[/tex] as many articles as Mustafa has.

Number of article written by Heloise = [tex]\frac{1}{4}x[/tex]

Gia has written [tex]\frac{3}{2}[/tex] as many articles as Mustafa has.

Number of article written by Gia = [tex]\frac{3}{2}x[/tex]

Now we know that;

The sum of number of articles written by Mustafa and Number of article written by Heloise and Number of article written by Gia is greater than or equal to Combined Total Number of articles.

framing in equation form we get;

[tex]x+\frac{1}{4}x+ \frac{3}{2}x\geq 22[/tex]

Hence the Inequality For determining number of equation written by Mustafa for school paper is [tex]x+\frac{1}{4}x+ \frac{3}{2}x\geq 22[/tex].

Now Solving the Inequality we get;

Taking LCM for making the denominator common we get:

[tex]\frac{x\times 4}{4}+\frac{1\times1}{4\times1}x+ \frac{3\times2}{2\times2}x\geq 22\\\\\frac{4x}{4}+ \frac{x}{4}+\frac{6x}{4}\geq 22\\\\\frac{4x+x+6x}{4} \geq 22\\\\11x\geq 22\times4\\\\11x\geq 88\\\\x\geq \frac{88}{11} \\\\x\geq 8[/tex]

Hence Mustafa has written more than 8 articles.

Answer:

inequality - m+ 1/4m + 3/2m > 22

solution set - m>8

Step-by-step explanation:

Answer:

Rina will need 6 tickets.

Explanation:

Rina needs only 1 ticket to ride the ferris wheel once, and 1 ticket to ride the bumper cars once. If she wants to ride the ferris wheel 5 times, then she'll need 5 tickets since 1 x 5 = 5. If she wants to ride the bumper cars only once, she'll only need 1 ticket since 1 x 1 = 1.

Add the answers together, and you get 6 tickets since 5 + 1 = 6.

Hope this helps! :)

Answer:

The probability that the amount dispensed per box will have to be increased is 0.0062.

Step-by-step explanation:

Consider the provided information.

Sample of 16 boxes is selected at random.

If the mean for 1 hour is 1 pound and the standard deviation is 0.1

1 Pound = 16 ounces , then 0.1 Pound = 16/10 = 1.6 ounces

Thus: μ = 16 ounces and σ = 1.6 ounces.

Compute the test statistic [tex]z=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z=\frac{15-16}{\frac{1.6}{\sqrt{16}}}[/tex]

[tex]z=\frac{-1}{\frac{1.6}{4}}[/tex]

[tex]z=\frac{-1}{0.4}[/tex]

[tex]z=-2.5[/tex]

By using the table.

P value = P(Z<-250) = 0.0062

Thus, the probability that the amount dispensed per box will have to be increased is 0.0062.

To keep the taste consistent, Brendan should use 18 cups of cranberry juice to mix with 27 cups of orange juice, preserving the original 3:2 juice ratio.

Brendan's original mixture was 15 cups of orange juice to 10 cups of cranberry juice. This creates a ratio of 15:10, which simplifies to 3:2 when divided by 5. To maintain the same taste, Brendan will want to keep the same ratio.

Now to calculate the amount of cranberry juice needed for 27 cups of orange juice, we set up a proportion

Set up a proportion to find the unknown value (x), representing the amount of cranberry juice:

3/2 = 27/x

Cross-multiply to solve for x:

3x = 2 x 27

3x = 54

Divide both sides by 3 to solve for x:

x = 54 / 3

x = 18

Brendan should use 18 cups of cranberry juice to mix with 27 cups of orange juice to keep the taste of the drink consistent.

The complete question is:

Brendan makes a cranberry-orange drink by mixing 15 cups of orange juice with 10 cups of cranberry juice. If he uses 27 cups of orange juice, how many cups of cranberry juice should he use in order for the drink to taste the same?

Answer:

D) dy/dx > 0 and d²y/dx² > 0

Step-by-step explanation:

Use implicit differentiation to find dy/dx and d²y/dx².

x²y³ = 576

x² (3y² dy/dx) + (2x) y³ = 0

3x²y² dy/dx = -2xy³

3x dy/dx = -2y

dy/dx = -2y / (3x)

d²y/dx² = [ (3x) (-2 dy/dx) − (-2y) (3) ] / (3x)²

d²y/dx² = (-6x dy/dx + 6y) / (9x²)

d²y/dx² = (-6x (-2y / (3x)) + 6y) / (9x²)

d²y/dx² = (4y + 6y) / (9x²)

d²y/dx² = 10y / (9x²)

Evaluating each at (-3, 4):

dy/dx = -2(4) / (3(-3))

dy/dx = 8/9

d²y/dx² = 10(4) / (9(-3)²)

d²y/dx² = 40/81

Both are positive.

Answer:

[tex]P(\bar X >80)=P(Z>2.143)=1-P(z<2.143)=1-0.984=0.016[/tex]

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable that represent the Student scores on exams given by a certain instructor, we know that X have the following distribution:

[tex]X \sim N(\mu=74, \sigma=14)[/tex]

The sampling distribution for the sample mean is given by:

[tex]\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})[/tex]

The deduction is explained below we have this:

[tex]E(\bar X)= E(\sum_{i=1}^{n}\frac{x_i}{n})= \sum_{i=1}^n \frac{E(x_i)}{n}= \frac{n\mu}{n}=\mu[/tex]

[tex]Var(\bar X)=Var(\sum_{i=1}^{n}\frac{x_i}{n})= \frac{1}{n^2}\sum_{i=1}^n Var(x_i)[/tex]

Since the variance for each individual observation is [tex]Var(x_i)=\sigma^2 [/tex] then:

[tex]Var(\bar X)=\frac{n \sigma^2}{n^2}=\frac{\sigma}{n}[/tex]

And then for this special case:

[tex]\bar X \sim N(74,\frac{14}{\sqrt{25}}=2.8)[/tex]

We are interested on this probability:

[tex]P(\bar X >80)[/tex]

And we have already found the probability distribution for the sample mean on part a. So on this case we can use the z score formula given by:

[tex]z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

Applying this we have the following result:

[tex]P(\bar X >80)=P(Z>\frac{80-74}{\frac{14}{\sqrt{25}}})=P(Z>2.143)[/tex]

And using the normal standard distribution, Excel or a calculator we find this:

[tex]P(Z>2.143)=1-P(z<2.143)=1-0.984=0.016[/tex]

Final answer:

Using the Central Limit Theorem and the z-score formula, we calculate that the approximate probability that the average test score in the class of size 25 exceeds 80 is approximately 1.62%.

Explanation:

To approximate the probability that the average test score in the class of size 25 exceeds 80, we can use the Central Limit Theorem which tells us that the sampling distribution of the sample mean will be approximately normally distributed if the sample size is large enough (typically n ≥ 30 is considered sufficient, but we can still use this for a sample of 25 when the population distribution is not overly skewed).

The formula for the z-score of a sample mean is:

z = (X - μ) / (σ / √n)

where X is the sample mean, μ is the population mean, σ is the population standard deviation, and n is the sample size. Given the population mean μ = 74, population standard deviation σ = 14, and sample size n = 25, we can calculate the z-score for a sample mean of 80.

Using these values:

z = (80 - 74) / (14 / √25) = (6) / (14 / 5) = 6 / 2.8 = 2.14

Now, we need to find the probability corresponding to a z-score of 2.14. We check the standard normal distribution table or use a calculator with normal distribution functions to find that the area to the left of z = 2.14 is approximately 0.9838. The probability that the average is above 80 is the area to the right of 2.14, so we subtract this value from 1.

Probability = 1 - 0.9838 = 0.0162

The approximate probability that the average test score in the class of size 25 exceeds 80 is approximately 0.0162, or 1.62%.

Final answer:

Larry studied a total of 5 1/12 hours on Monday and Tuesday. To find this, convert the mixed numbers to improper fractions, find a common denominator, add the fractions together, and simplify to get the final sum.a

Explanation:

To calculate the total amount of time Larry spent studying on Monday and Tuesday, we need to add the hours together:

    1.  Monday: 2 1/4 hours
    2.  Tuesday: 2 5/6 hours

Let's convert these mixed numbers to improper fractions to simplify the addition:

Next, we find a common denominator, which is 12, and rewrite the fractions:

Now that they have the same denominator, we can add them together:

To simplify, divide 61 by 12, which is 5 with a remainder of 1. Thus, the mixed number is 5 1/12. Therefore, the addition sentence to show how many hours Larry spent studying Monday and Tuesday is:

Answer:

Step-by-step explanation:

Let x represent the cost of an adult ticket and

Let y represent the cost of a child ticket.

Your school is sponsoring a pancake dinner to raise money for a field trip. You estimate that 200 adults and 250 children will attend.

The equation that can be used to find what ticket prices to set in order to raise $3800 would be

200x + 250y = 3800

The equation that can be used to find what ticket prices to set in order to raise $3800 is [tex]3800=200x+250y[/tex].

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

As it is given that the cost of an adult ticket is x while the number of adult tickets sold was 200. Similarly, the cost of a child ticket is y while the number of child tickets sold will be 250. And the total money that is needed to be raised is $3800, therefore, the equation can be written as,

Total amount= Total amount of Adult Tickets + Total amount of Child Ticket

[tex]\$3,800 = (\$x \times 200)+(\$y \times 250)\\\\3800=200x+250y[/tex]

Hence, the equation that can be used to find what ticket prices to set in order to raise $3800 is [tex]3800=200x+250y[/tex].

Learn more about Equation:

https://brainly.com/question/2263981

Answer:

300pi

Step-by-step explanation:

Final answer:

The rate of change of the surface area of the sphere at that instant is 942.48 meters squared per minute.

Explanation:

To find the rate of change of the surface area S(t)S(t)S, (, t, )of the sphere at that instant, we need to differentiate the surface area formula with respect to time and then substitute the given values.

The formula for the surface area of a sphere is [tex]S = 4\pi r^2.[/tex]

Taking the derivative with respect to time, we have dS/dt = 8πr(dr/dt).

Given that dr/dt = 7.5 meters per minute and r = 5 meters, we can substitute these values into the derivative formula to find the rate of change of the surface area at that instant.

= dS/dt = 8π(5)(7.5)

= 300π

= 942.48 meters squared per minute.

Answer:

  12

Step-by-step explanation:

The difference of the two coordinates is ...

  23 -(-10) = 33

The desired coordinate is 2/3 of that length from J, so is ...

  J + (2/3)·33 = J +22 = -10 +22 = 12

The desired coordinate is 12.

Answer:

"minimum value = 0; maximum value = 8"

Step-by-step explanation:

This is the absolute value function, which returns a positive value for any numbers (positive or negative).

For example,

| -9 | = 9

| 9 | = 9

| 0 | = 0

Now, the domain is from -8 to 7 and we want to find max and min value that we can get from this function.

If we look closely, putting 7 into x won't give us max value as putting -8 would do, because:

|7| = 7

|-8| = 8

So, putting -8 would give us max value of 8 for the function.

Now, we can't get any min values that are negative, because the function doesn't return any negative values. So the lowest value would definitely be 0!

|0| = 0

and

ex:  |-2| = 2 (bigger),  |-5| = 5 (even bigger).

So,

Min Value = 0

Max Value = 8

Answer:

minimum value = 0; maximum value = 8

Step-by-step explanation:

The function [tex]f(x)[/tex] is an absolute value function, which means that for negative values in it's domain it gives positive values of  [tex]f(x)[/tex], and therefore it's minimum value is 0.

In the given domain interval the maximum value of the function is 8 because [tex]f(-8)=8[/tex].

Step-by-step explanation:

We need to find um of the first 100 terms of

               [tex]\frac{1}{n}-\frac{1}{n+1}[/tex]

That is

           [tex]\texttt{Sum = }\frac{1}{1}-\frac{1}{1+1}+\frac{1}{2}-\frac{1}{2+1}+\frac{1}{3}-\frac{1}{3+1}.....+\frac{1}{100}-\frac{1}{100+1}\\\\\texttt{Sum = }\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}.....+\frac{1}{100}-\frac{1}{101}\\\\\texttt{Sum = }\frac{1}{1}-\frac{1}{101}\\\\\texttt{Sum = }\frac{101-1}{101\times 1}\\\\\texttt{Sum = }\frac{100}{101}[/tex]

Option E is the correct answer.

Final answer:

The sum of the first 100 terms of the sequence an = 1/n - 1/(n+1) is 100/101 because it's a telescoping series where almost all terms cancel each other out except the very first and the very last term.

Explanation:

The student's question involves finding the sum of the first 100 terms of the sequence an = 1/n - 1/(n+1). To find this sum, we can notice that many terms will cancel each other out when we add up the sequence. This is because the sequence is telescoping. Let's illustrate this with the first few terms:

a1 = 1 - 1/2

a2 = 1/2 - 1/3

a3 = 1/3 - 1/4

...

a99 = 1/99 - 1/100

a100 = 1/100 - 1/101

When we add all these up, notice that every negative term cancels out with the positive term that precedes it, except for the very first term, which is 1, and the very last negative term, which is -1/101. Hence, the sum is 1 - 1/101 which simplifies to 100/101. Therefore, the correct answer is (e) 100/101.

Answer:

The right inequa is

8 < 2n

:)

Answer:

8<2n is correct :) Hope it helped

Answer:

See below because there are 9 parts (A through I)

Explanation:

Part A: write an equation that models the area of the figure. Let y represent the area, and write your answer in the form y = ax2 + bx + c.

The figure shows a rectangular table with these dimensions:

The area of a rectangle is width × length:

Use distributive property:

Simplify:

Part B. Graph the equation you wrote in part A. Adjust the zoom of the graphing window so the vertex, x-intercepts, and y-intercept can be seen.

1. Factor the equation:

          [tex]-x^2+60x+256=-(x^2-60x-256)[/tex]

[tex]-(x-64)(x+4)[/tex]

2. Find the roots:

Equal the expression to zero:

[tex]-(x-64)(x+4)=0\\ \\ x-64=0\implies x=64\\ \\ x+4=0\implies x=-4[/tex]

Those are the x-intercepts: (-4,0) and (64,0)

3. Find the symmetry axis:

The simmetry axis is the line x = the middle value between the two roots:

[tex]x=(64-4)/2=60/2=30[/tex]

4. Find the vertex

The vertex has x-coordinate equal to the x axis (30 in this case).

Substitute in the equation of find the y-coordinate:

[tex]y=-(30-64)(30+4)=-(-34)(34)=1,156[/tex]

Hence, the vertex is (30, 1,156)

5. Find the y-intercept

Make x = 0

[tex]y=-(x^2-60x-256)=-(0-256)=256[/tex]

Hence, the y-intercept is (0, 256)

With the x-incercepts, the y-intercept, the axis of symmetry, and the vertex, you can sketch the graph.

You can see now the graph in the attached figure

Part C. Extreme location of the graph

The graph shows that the parabola opens downward. That is due to the fact that the coefficient of the leading term (x²) is negative.

The parabola starts in the second quadrant. starts growing, crosses the x-axis at (-4,0), crosses the y-axis at (0,256), reaches the maximum value at (30, 1156), and then decreases toward the fouth quadrant, crossing the x-axis at (64,0).

Thus the vertex is a maximun, and the coordinates of the maximum are (30, 1156).

Part D. According to the graph, what is the maximum possible area of the game board? Give your answer to the nearest whole number. (Assume that the maximum area is not reduced by the open hole in the game board.)

The maximum possible area of the game is the maximum value of the function y = -x² + 60x + 256.

This value was calculated as y = 1156.

Part E. Use the original expressions for the length and width, and substitute the x-coordinate from the extreme location. What are the length and width of the game board at the extreme location?

The length is:

The width is:

Part F. What type of quadrilateral will be formed when the game board covers the maximum possible area?

Since the length and the width are equal, the quadrilateral is a square.

Part G.  Suppose the carnival director asks you to create a game board that is 1,120 square inches. Find the dimensions that would meet this request by setting the area equation equal to 1,120, solving for x, and substituting x into the expressions for the length and width.

[tex]y=-x^2+60x+256\\ \\ 1,120=-x^2+60x+256\\ \\ x^2-60x-256+1120=0\\ \\ x^2-60x+864=0[/tex]

Factor:

Find two numbers whose sum is - 60 and the product os 864. They are  -24 and - 34:

[tex]x^2-60x+864=(x-24)(x-36)[/tex]

Use the zero product rule:

[tex](x-24)(x-36)=0\\ \\ x-24=0\implies x=24\\ \\ x-36=0\implies x=36[/tex]

Now substitute to find the dimensions:

x = 36

Hence, legth = 28, width = 40

x = 24

Part H. When you solved the area equation for x, did any extraneous solutions result? Describe how an extraneous solution would arise in this situation.

The two solutions are valid (non extraneous) because both leads to positive real dimensions for which the areas can be 1,120 in².

An extraneous solution could arise if you try to find areas for which  x is greater than or equal to 64, because in that case - x + 64 would be zero or negative and dimensions must be positive.

For the same reason, also an extraneous solution would arise if you try to fix areas for which x is less than or equal to - 4.

So, the domain of your function has to be - 4 < x < 64.

Part I. What method of solving quadratics did you use to solve the equation set equal to 1,120? Why did you choose this method?

The method use was factoring.

Discuss the usefulness of other methods of solving quadratics as they pertain to this scenario.

The other importants methods are graphical and the quadratic equation.

For graphical method you graph your parabola and find the values of x that sitisfies the area searched (value of y).

The quadratic equation gives the y-values (areas) without factoring:

[tex]\frac{-b+/-\sqrt{b^2-4(a)(c)} }{2(a)}[/tex]

Answer:

[tex]\sigma =\frac{478}{6}=79.667[/tex]

Step-by-step explanation:

The empirical rule, also referred to as "the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)". The empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

And on this case since we are within 3 deviations (because we have 99.7% of the data between 568 and 1066hours), the result obtained using the z score agrees with the empirical rule.  

So on this case we can find the standard deviation on this ways:

[tex]\mu -3\sigma = 568[/tex]     (1)

[tex]\mu +3\sigma = 1066[/tex]   (2)

If we subtract conditions (2) and (1) we got:

[tex]1066-588 =\mu +3\sigma -\mu +3\sigma[/tex]

[tex]478= 6\sigma[/tex]

[tex]\sigma =\frac{478}{6}=79.667[/tex]

Answer: length = 20.1

Width=17.6

Step-by-step explanation:

Answer:

1. 96.08%; 2. x=764.8; 3. 63.31%; 4. 93.57%; 5. 99.74%

Step-by-step explanation:

The essential tool here is the standardized cumulative normal distribution which tell us, no matter the values normally distributed, the percentage of values below this z-score. The z values are also normally distributed and this permit us to calculate any probability related to a population normally distributed or follow a Gaussian Distribution. A z-score value is represented by:

[tex]\\ z=\frac{(x-\mu)}{\sigma}[/tex], and the density function is:

[tex]\\ f(x) = \frac{1}{\sqrt{2\pi}} e^{\frac{-z^{2}}{2} }[/tex]

Where [tex]\\ \mu[/tex] is the mean for the population, and [tex]\\ \sigma [/tex] is the standard deviation for the population too.

Tables for z scores are available in any Statistic book and can also be found on the Internet.

The combined math and verbal scores for students taking a national standardized examination for college admission, is normally distributed with a mean of 500 and a standard deviation of 170. If a college requires a minimum score of 800 for admission, what percentage of student do not satisfy that requirement?

For solve this, we know that [tex]\\ \mu = 500[/tex], and [tex]\\ \sigma = 170[/tex], so

z = [tex]\frac{800-500}{170} = 1.7647[/tex].

For this value of z, and having a Table of the Normal Distribution with two decimals, that is, the cumulative normal distribution for this value of z is F(z) = F(1.76) = 0.9608 or 96.08%. So, what percentage of students does not satisfy that requirement? The answer is 96.08%. In other words, only 3.92% satisfy that requirement.

The combined math and verbal scores for students taking a national standardized examination for college admission, is normally distributed with a mean of 630 and a standard deviation of 200. If a college requires a student to be in the top 25 % of students taking this test, what is the minimum score that such a student can obtain and still qualify for admission at the college?

In this case [tex]\\ \mu = 630[/tex], and [tex]\\ \sigma = 200[/tex].

We are asked here for the percentile 75%. That is, for students having a score above this percentile. So, what is the value for z-score whose percentile is 75%? This value is z = 0.674 in the Standardized Normal Distribution, obtained from any Table of the Normal Distribution.

Well, having this information:

[tex]\\ 0.674 = \frac{x-630}{200}[/tex], then

[tex]\\ 0.674 * 200 = x-630[/tex]

[tex]\\ (0.674 * 200) + 630 = x[/tex]

[tex]\\ x = 764.8 [/tex]

Then, the minimum score that a student can obtain and still qualify for admission at the college is x = 764.8. In other words, any score above it represents the top 25% of all the scores obtained and 'qualify for admission at the college'.

[...] The collagen amount was found to be normally distributed with a mean of 69 and standard deviation of 5.9 grams per milliliter.

In this case [tex]\\ \mu = 69[/tex], and [tex]\\ \sigma = 5.9[/tex].

What percentage of compounds have an amount of collagen greater than 67 grams per milliliter?

z = [tex]\frac{67-69}{5.9} = -0.3389[/tex]. The z-score tells us the distance from the mean of the population, then this value is below 0.3389 from the mean.

What is the value of the percentile for this z-score? That is, the percentage of data below this z.

We know that the Standard Distribution is symmetrical. Most of the tables give us only positive values for z. But, because of the symmetry of this distribution, z = 0.3389 is the distance of this value from the mean of the population. The F(z) for this value is 0.6331 (actually, the value for z = 0.34 in a Table of the Normal Distribution).

This value is 0.6331-0.5000=0.1331 (13.31%) above the mean. But, because of the symmetry of the Normal Distribution, z = -0.34, the value F(z) = 0.5000-0.1331=0.3669. That is, for z = -0.34, the value for F(z) = 36.69%.

Well, what percentage of compounds have an amount of collagen greater than 67 grams per milliliter?

Those values greater that 67 grams per milliliter is 1 - 0.3669 = 0.6331 or 63.31%.

What percentage of compounds have an amount of collagen less than 78 grams per milliliter?

In this case,

z = [tex]\frac{78-69}{5.9} = 1.5254[/tex].

For this z-score, the value F(z) = 0.9357 or 93.57%. That is, below 78 grams per milliliter, the percentage of compounds that have an amount of collagen is 93.57%.

What exact percentage of compounds formed from the extract of this plant fall within 3 standard deviations of the mean?

We need here to take into account three standard deviations below the mean and three standard deviations above the mean. All the values between these two values are the exact percentage of compounds formed from the extract of this plant.

From the Table:

For z = 3, F(3) = 0.9987.

For z = -3, F(-3) = 1 - 0.9987 = 0.0013.

Then, the exact percentage of compounds formed from the extract of this plant fall within 3 standard deviations of the mean is:

F(3) - F(-3) = 0.9987 - 0.0013 = 0.9974 or 99.74%.

A z-score is used to determine how many standard deviations a value is from the mean. A score of 720 on the SAT is 1.74 standard deviations above the mean, whereas a score of 692.5 is 1.5 standard deviations above the mean. To compare scores from different tests, like the SAT and ACT, you compute the z-scores for each and compare them.

In statistics and probability theory, when comparing values from different normal distributions, one useful tool is the z-score. It informs us of how many standard deviations an element is from the mean of its distribution. A z-score is calculated using the formula Z = (X - μ) / σ, where X is the value in question, μ is the mean, and σ is the standard deviation.

To calculate a z-score for an SAT score of 720 when the mean is 520 and the standard deviation is 115:
Z = (720 - 520) / 115 = 200 / 115 ≈ 1.74.

This z-score of approximately 1.74 implies that the score of 720 is 1.74 standard deviations above the mean SAT score.

To find an SAT score that is 1.5 standard deviations above the mean:
X = μ + 1.5σ = 520 + 1.5 × 115 = 520 + 172.5 = 692.5.

So, a score of approximately 692.5 is 1.5 standard deviations above the mean, indicating a well-above-average performance.

Comparing an SAT math score of 700 and an ACT score of 30 with respect to their respective mean and standard deviation:

Based on their z-scores, the individual with the ACT score performed slightly better relative to others who took the same test than the individual who took the SAT math test.

Answer:

16 Weeks.

Step-by-step explanation:

1050 - 150 = 900.

900 divided by 55 = 16.3.

Round down, because 3 is less than 5.

Therefore, Johnny can spend $55 each week for 16 weeks and have at least $150 left in his account.

Hope this helps.

Answer:

  QR = 28 inches or 44 inches

Step-by-step explanation:

In right triangle QNP, the length of QN is given by the Pythagorean theorem as ...

  QP² = QN² +PN²

  QN = √(QP² -PN²) = √(1521 -225) = √1296 = 36

In right triangle RNP, the length of RN is similarly found:

  RN = √(RP² -PN²) = √(289 -225) = √64 = 8

So, we have N on line QR with QN = 36 and RN = 8.

If N is between Q and R, then ...

  QR = QN +NR = 36 +8 = 44

If R is between Q and N, then ...

  QR = QN -NR = 36 -8 = 28

The possible lengths of QR are 28 in and 44 in.

Final answer:

To determine QR in ∆PQR, the Pythagorean theorem is used on the two right triangles formed by the altitude PN. Calculating gives QN = 36 inches and RN = 8 inches, hence, QR = QN + RN = 44 inches.

Explanation:

To find the length QR in ∆PQR, where PQ = 39 inches, PR = 17 inches, and the altitude PN = 15 inches, we can use the properties of right triangles. Since PN is the altitude to base QR, it forms two right triangles, ∆PNQ and ∆PNR, within ∆PQR. We can use the Pythagorean theorem to solve for the lengths of QN and RN, and then sum these to find QR.

Firstly, let’s find QN in ∆PNQ:

Secondly, we do the same for RN in ∆PNR:

Therefore, QR = QN + RN = 36 inches + 8 inches = 44 inches.

Answer:

D) 8.667 mph

Step-by-step explanation:

Given: Distance= 6.5 miles

           Times= 45 minutes

First, convert the time into hours as we need to find speed in the unit of mph.

We know, 1 hour= 60 minutes

∴ Time= [tex]\frac{45}{60} = 0.75\ h[/tex]

Now, find the speed of John´s bike

Speed= [tex]\frac{distance}{time}[/tex]

⇒ Speed= [tex]\frac{6.5}{0.75} = 8.667\ mph[/tex]

∴ Speed of John´s bike is 8.667 mph

Answer:16

Step-by-step explanation:

Answer:

the correct option is D.

Step-by-step explanation:

x+3y>6

y≥2x+4

consider the equation x+3y=6

3y = 6-x

[tex]y=\frac{-x}{3} +2[/tex]

this line is in the form of y = mx + c

where m is the slope os the line and c is the y intercept of the line

therefore the line has a y intercept of 2  and slope of-1/3

therefore the line has negative slope with positive intercept.

now consider the line y=2x+4

this line is in the form of y = mx + c

where m is the slope os the line and c is the y intercept of the line

therefore slope = 2 and y intercept = 4

therefore the line has positive slope and positive y intercept.

in option a both line has positive intercept so it cant be an answer.

in option b one line has positive intercept of 2 and another with negative intercept of -4 but we need intercept of both line to be positive so it cant be an answer.

in option c both line has negative intercept of -2 and -4 but we need intercept of both line to be positive so it cant be an answer.

in option d both line has positive intercept of 2 and 4 and also one of the line has negative slope and another line has positive slope so it should be an answer

further to confirm consider x+3y>6

put the point 0,0 in the inequality

0>6 which is wrong so 0,0 cant lie in the region which is true according to the graph.

Answer:

d

Step-by-step explanation:

A clothing store is selling a shirt for a discounted price of $43.61 . The original price of the shirt was approximately $49.01.

To find the original price of the shirt, we can use the formula: Original Price = Discounted Price / (1 - Discount Rate). In this case, the discounted price is $43.61 and the discount rate is 11%, or 0.11. Plugging these values into the formula, we get: Original Price = 43.61 / (1 - 0.11) = 43.61 / 0.89 ≈ 49.01. Therefore, the original price of the shirt was approximately $49.01.

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Check the picture below.

Answer: The angle that the ladder makes with the ground at the maximum height is 65.37 degrees

Step-by-step explanation:

The triangle ABC is formed by the ladder and the wall is shown in the attached photo.

The angle that the ladder makes with the ground at the maximum height is represented as #. To determine #, we will apply trigonometric ratio

Sin # = 0pposite side / hypotenuse.

Hypotenuse = 110

Opposite side = 100

Sin# = 100/110 = 0.909

# = Sin^(-1)0.909

# = 65.37

Answer:The fraction of the almonds that Roberto and his friends ate is 3/4

Step-by-step explanation:

Let x represent the total number of almonds in the bag initially. He shares 1/8 bag with Jeremy. This means that the amount of almonds that he gave to Jeremy is 1/8 × x = x/8

He shares 2/8 bag with Emily. This means that the amount of almonds that he gave to Emily is 2/8 × x = 2x/8

He eats 3/8 bag of the almonds himself. This means that the amount of almonds that he ate is 3/8 × x = 3x/8

Total number of almonds that Robert and his friends ate would be

x/8 + 2x/8 + 3x/8 = 6x/8 = 3x/4

The fraction of the almonds that Roberto and his friends ate would be

(3x/4)/x = 3/4

Roberto and his friends eat a total of 3/4 of a bag of almonds, calculated by adding the fractions of the bag each person consumed.

The student is asking how to calculate the total fraction of a bag of almonds eaten by Roberto and his friends. Roberto shares 1/8 of the bag with Jeremy, 2/8 of the bag with Emily, and eats 3/8 of the bag himself. To find the total fraction consumed, we add these fractions together:

1/8 (Jeremy) + 2/8 (Emily) + 3/8 (Roberto) = 6/8

Since 2/8 can be simplified to 1/4, and 6/8 can be simplified to 3/4, the total fraction of the almonds eaten by Roberto and his friends is 3/4 of the bag.

Answer:

8,855

Step-by-step explanation:

The way to solve this problem is by using Combinations.

In Combinations, we can form different collections of k elements from a total of n elements where the order of them does not matter and any member of them is not repeated.

Combinations is expressed mathematically as:

[tex]\\nC_k = \frac{n!}{(n-k)!k!} [/tex] [1]

Where n is the total elements, k is the number of elements selected from n, and n! is n factorial, or, for instance, 3! is 3*2*1 = 6; 4! is 4*3*2*1 = 24.

This formula tells us how to form groups of k members from a total of n elements. These groups of k members have no repeated elements, that is, in the context of this question, no flavor is repeated in any group.

Likewise, different orders of the same members do not matter, or, in other words, if we have two groups of four members flavors (vanilla, chocolate, strawberry, lemon) and (chocolate, vanilla, lemon, strawberry), they are considered the same group since order does not matter in Combinations.

In this way, to determine the number of four dip sundaes (k) from 23 flavors (n) that an ice cream store sells, we need to apply the formula [1], as follows:

[tex]\\23C_4 = \frac{23!}{(23-4)!4!} [/tex]

[tex]\\23C_4 = \frac{23!}{19!4!} [/tex]

[tex]\\23C_4 = \frac{23*22*21*20*19!}{19!4!} [/tex], since 19!/19! = 1.

[tex]\\23C_4 = \frac{23*22*21*20}{4*3*2*1} [/tex]

[tex]\\23C_4 = 8,855 [/tex]

To find the number of 4-dip sundaes possible with 23 flavors of ice cream, we use combinations. The formula for combinations is C(n, r) = n! / (r!(n-r)!). Applying this formula, we find that there are 8855 possible 4-dip sundaes.

To determine the number of 4-dip sundaes possible with 23 flavors of ice cream, we can use combinations.

A combination is used when the order does not matter, and no repetitions are allowed.

In this case, we use the formula for combinations of r items selected from a set of n items without replacement: C(n, r) = n! / (r!(n-r)!)

So, the number of 4-dip sundaes possible is C(23, 4) = 23! / (4!(23-4)!) = 23! / (4!19!)

Calculating this using a calculator, we find that there are 8855 possible 4-dip sundaes with 23 flavors of ice cream.

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