You drive your car for 4.5 hours at an average speed of 70 miles per hour how far did you go
i need help:( Solve. 3m+72=−2m+52
What value of H makes the equation true
−1/8 x (2H + 4) + 1/2= −7/4
A 7
B 25/16
C 7/16
D 25
(-4x^2+3xy-y^2)/-(-7x^2-xy+6y^2)/(x^2+4xy-2y^2)
Answer:
7x+x^-16x+
Step-by-step explanation:
There are (108)2 ⋅ 100 candies in a store. What is the total number of candies in the store?
To find the total number of candies, square 108 and then multiply by 100. The steps result in a total of 1,166,400 candies in the store.
Calculating the Total Number of Candies
The expression provided is (108) 2 × 100. To calculate this, first square 108, which means you multiply 108 by itself, and then multiply the result by 100. So the calculation will look like this: 108 × 108 × 100.
To carry out this multiplication, the steps are:
Square 108: 108 × 108 = 11,664.
Multiply the result by 100: 11,664 × 100 = 1,166,400.
Therefore, the total number of candies in the store is 1,166,400.
To find the total number of candies in the store given the expression [tex](108)^2[/tex] times 100, you first square 108 to get 11,664 and then multiply that by 100, resulting in 1,166,400 candies.
The student's question asks for the total number of candies in a store given the expression [tex](108)^2[/tex] times 100.
To find the total, we need to calculate the square of 108 and then multiply the result by 100.
First, 1082 equals 11,664 (108 multiplied by itself).
Next, we multiply 11,664 by 100 to find the total number of candies, which gives us 1,166,400 candies.
Hence, there are 1,166,400 candies in the store.
Step-by-Step Solution:
Calculate the square of 108: 108 x 108 = 11,664.Multiply the result by 100: 11,664 x 100 = 1,166,400.Therefore, the store has 1,166,400 candies in total.
tana fills the prism shown (3 1/4 and 4 inch) with 110 1/2 in squared of liquid what is the height of the prism
Answer:
[tex]h=8\frac{1}{2}\text{ inch}[/tex]
Step-by-step explanation:
Let h represent height of prism.
We have been given that Tana fills the prism with base lengths [tex]3\frac{1}{4}[/tex] inch and [tex]4[/tex] inch with a [tex]110\frac{1}{2}\text{ inch}^3[/tex].
We know that volume of prism is area of base times height, so we can set an equation as:
[tex]\text{Volume of prism}=\text{Base length}\times\text{Base width}\times \text{Height of prism}[/tex]
[tex]110\frac{1}{2}\text{ inch}^3=3\frac{1}{4}\text{ inch}\times 4\text{ inch}\times h[/tex]
[tex]\frac{221}{2}\text{ inch}^3=\frac{13}{4}\text{ inch}\times 4\text{ inch}\times h[/tex]
[tex]\frac{221}{2}\text{ inch}^3=13\text{ inch}^2\times h[/tex]
[tex]\frac{221}{2*13\text{ inch}^2}\text{ inch}^3=\frac{13\text{ inch}^2\times h}{13\text{ inch}^2}[/tex]
[tex]\frac{221}{26}\text{ inch}=h[/tex]
[tex]8\frac{13}{26}\text{ inch}=h[/tex]
[tex]8\frac{1}{2}\text{ inch}=h[/tex]
Therefore, the height of the prism is [tex]8\frac{1}{2}\text{ inch}[/tex].
What property is being used in the equation 3a+0=3a
4 3/2
-
3 1/4
________
katy's favorite rides at the amuesment park are the rollercoaster and the water slide. the wait time for the rollercoaster is 25 minutes and the wait time for the water slide is 10 minutes. if she went on 12 rides total and waited three hours in line,how many times did she go on each ride
What is 12-(3-1/2)? I NEED ASAP!! THANK YOU
Francine and Cheryl received equal scores on a test made up of multiple choice questions and an essay. Francine got 34 multiple choice questions correct and received 14 points for her essay. Cheryl got 30 multiple choice questions correct and received 22 points for her essay. How many points was each multiple choice question worth? Enter your answer in the box. 5 points
34x +14 = 30x +22
34x = 30x + 8
4x =8
x = 8/ = 2
each question was worth 2 points
Compare the values of the 2's and 5's in 55,220
Help!! what is -2r-1= -11
What do I write for my problem. Reply quickly please
For the problem 135 divided by 5, draw two different ways to break apart the array. Use the Distributive Property to write products for each different way. (Please show picture of arrays!)
the difference of a positive integer and its inverse is 15/4. find the integer
Christian paid $12 and 50 Cent for taxi fare from his home to the airport including a $1.60 tip.City cab charges $1.90 for the 1st mile plus $.15 for each additional 1/6 of a mile how many miles is Christian home from the airport
Christian's home is 10 miles away from the airport. He paid for one mile at the initial fare and 60 sets of 1/6 mile at the per-set rate, totaling 10 miles including the first mile.
The taxi fare Christian paid was $12.50, including a $1.60 tip. The initial charge by the cab company is $1.90 for the first mile. Therefore, without the tip, the fare for the distance traveled is $12.50 - $1.60 = $10.90. The first mile costs $1.90, so the remaining $9.00 covers the additional miles. As the company charges $0.15 for each additional 1/6 of a mile, we need to calculate how many sets of 1/6 mile are covered by $9.00.
To find out how many 1/6 miles can be covered by $9.00, we divide $9.00 by $0.15, which gives us 60. This means Christian traveled 60 sets of 1/6 mile beyond the first mile. Therefore, the total distance is the first mile plus 60 times 1/6 mile, which equals 10 miles in total.
So, Christian's home is 10 miles away from the airport.
Betty had $70. She bought a necklace for $9 and a ring for $7. Which expression correctly shows the total money Betty has left? A $70 − (−$9) + (−$7) B $70 + (−$9) + (−$7) C $70 − (−$9) − (−$7) D $70 + (−$9) − (−$7) A B C D???
PLZZ HELP ASAP
The answer would be B!
What is 485 times 34
what is the solution to log2(9x)-log2^3=3?
Answer:
[tex]x = \frac{8}{3}[/tex] is the solution to [tex]\log_2 9x - \log_2 3 = 3[/tex]
Step-by-step explanation:
Using the logarithmic rules:
[tex]\log \frac{m}{n} = \log m -\log n[/tex]
if [tex]\log_b x = a[/tex] then;
[tex]x = b^a[/tex]
Given the equation:
[tex]\log_2 9x - \log_2 3 = 3[/tex]
Solve for x:
Apply the logarithmic rules:
[tex]\log_2 \frac{9x}{3} = 3[/tex]
⇒[tex]\log_2 3x = 3[/tex]
Apply the logarithmic rules;
[tex]3x = 2^3[/tex]
⇒[tex]3x = 8[/tex]
Divide both sides by 3 we have;
[tex]x = \frac{8}{3}[/tex]
Therefore, the solution for the given equations is, [tex]x = \frac{8}{3}[/tex]
Answer: B or option two on edg
X = 8/3
Step-by-step explanation:
After a 5% sale discount, the price of an item became $38.00. What was the original price?
At a country concert, the ratio of the number of boys to girls is 2:7. If there are 250 more girls than boys, how many boys are at the concert? PLZ HELP
Answer:
100 boys at the concert
Step-by-step explanation:
At a country concert, the ratio of the number of boys to girls is 2:7
Let 'b' be the number of boys in the concert
there are 250 more girls than boys
so b+250 are the number of girls in the concert
the ratio of boys to girls is b: b+250
Now make a proportion using the ratio
[tex]\frac{2}{7} =\frac{b}{b+250}[/tex]
Now solve for b . cross multiply the fraction
[tex](b+250) \cdot 2= 7 \cdot b[/tex]
[tex]2b+500= 7b[/tex]
Subtract 2b from both sides
[tex]5b= 500[/tex]
Divide both sides by 5
b=100
So there are 100 boys at the concert
What is 53,806 in expanded form using exponents
An architect is designing a house in which a 104-square-foot room and a 130-square-foot room share a wall. What is the greatest possible integer length of the shared wall?
I will give brainliest to whoever got the right answer first, so please get it right, help me do number 25, number 26, and number 27, remember and please, READ THE DIRECTIONS.
The weight of an elephant is 10 to the third times the weight of a cat. If the elephant weighs 14,000 pounds how many pounds does the cat weigh how did you find your answer
The rehearsal for Acts I and II of the school play lasted 5 1⁄2 hours. If 3 3⁄4 hours were spent rehearsing Act I, how much time was spent practicing Act II
The required time that spent on the Act II in the rehearsal is 1 3/4 hours.
What are equation models?The equation model is defined as the model of the given situation in the form of an equation using variables and constants.
Here,
The rehearsal for Acts I and II of the school play lasted 5 1⁄2 hours.
3 3⁄4 hours were spent rehearsing Act I,
let the time spent on the Act II be x,
According to the question,
x = 5 1/2 - 3 3/4
x = 5 - 3 + 1/2 - 3/4
x = 2 -1/4
x = 1 3/4
Thus, the required time that spent on the Act II in the rehearsal is 1 3/4 hours.
Learn more about models here:
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Steve washed 15 cars in 3 hours.how many cars can he Wash in 7 hours?
Steve washed 15 cars in 3 hours and can wash 35 cars in 7 hours.
We have given that Steve washed 15 cars in 3 hours.
We have to determine if the cars can be Washed in 7 hours.
What is the condition given?
15/3 = x/7.
Use cross products and multiply 15*7
= 105/3
= 35.
He can wash 35 cars in 7 hours
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Is 0.7105386266520861 a rational or irrational number?
how to do this question?