Can someone help me with these problems? I'm in k12 and this assignment was in classkick, so if anyone already completed this and can help, please do. I also am going to be asking some more questions, if you can help with those too. Thanks! (Will give brainliest.)

PLEASE HELP ME!

Answer:

k=2

Step-by-step explanation:

3k-k+5k-7=7

2k+5k=7+7

7k=14

k=14/7

k=2

Answer:

[tex] \: \: \: \: \: \: \: \: 3k - k + 5k - 7 = 7 \\ = > 8k - k = 7 + 7 \\ = > 7k = 14 \\ = > k = \frac{14}{7} \\ = > k = 2[/tex]

Final answer:

The Peace of Augsburg allowed rulers to establish either Lutheranism or Roman Catholicism as the official religion in their lands, giving birth to the principle 'whose realm, their religion' but excluded other religious groups such as Calvinists and Anabaptists.

Explanation:

The religious settlement reached with the Peace of Augsburg in 1555 allowed rulers within the Holy Roman Empire to choose either Lutheranism or Roman Catholicism as the official religion of their territories. This principle, known as cuius regio, eius religio ('whose realm, their religion'), meant that a ruler's subjects were obliged to follow the same religion.

The Peace of Augsburg formally recognized the division between Catholics and Protestants, mainly Lutherans, and ended the religious conflict within the empire at that time. However, other religious groups, such as Calvinists and Anabaptists, were not accommodated, and the agreement failed to resolve underlying tensions leading to future wars, including the devastating Thirty Years' War.

The slope is -4/5

Step-by-step explanation:

We have to observe the graph to find two points to find slope.

The graph has two points

(-5,0) and (0, -4)

The formula for slope is given by:

[tex]m = \frac{y_2-y_1}{x_2-x_1}\\[/tex]

Here

(x1,y1) = (-5,0)

(x2,y2) = (0,-4)

Putting the values

[tex]m = \frac{-4-0}{0+5}\\=-\frac{4}{5}[/tex]

Hence,

The slope is -4/5

Keywords: slope, steepness

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Answer:

The numbers are 165 and 113

Step-by-step explanation:

Let

x ----> one number

y ----> the other number

we know that

[tex]x+y=278[/tex] ----> equation A

[tex]x=y+52[/tex] ----> equation B

substitute equation B in equation A

[tex](y+52)+y=278[/tex]

solve for y

[tex]2y=278-52[/tex]

[tex]2y=226[/tex]

[tex]y=113[/tex]

Find the value of x

[tex]x=y+52[/tex]

[tex]x=113+52=165[/tex]

therefore

The numbers are 165 and 113

Answer:

Option C) 24 < x < 54

Step-by-step explanation:

we know that

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

Let

x ----> the measure of the third side

Applying the triangle inequality theorem

1) [tex]15+39 > x[/tex]

[tex]54 > x[/tex]

Rewrite

[tex]x < 54\ units[/tex]

2) [tex]x+15> 39[/tex]

[tex]x > 39-15[/tex]

[tex]x > 24\ units[/tex]

therefore

The range of possible measures for the third side is the interval (24,54)

Answer:

30%

Step-by-step explanation:

Use formula to find percent decrease

[tex]\text{Percent Decrease}=\dfrac{\text{Old Value}-\text{New Value}}{\text{Old Value}}\cdot 100\%[/tex]

In your case,

Old Value = 2.5 pounds

New Value = 1.75 pounds

Hence,

[tex]\text{Percent Decrease}=\dfrac{2.5-1.75}{2.5}\cdot 100\%\\ \\=\dfrac{0.75}{2.5}\cdot 100\%\\ \\=\dfrac{75}{250}\cdot 100\%\\ \\=\dfrac{3}{10}\cdot 100\%\\ \\=30\%[/tex]

Answer:

Length of the base = 8

Step-by-step explanation:

Area of a triangle = 1/2(h*b)

h = height

b = base

52 = 1/2 (13 * b)

Rearrange the equation to get b on it's own

52 * 2 = 13 * b

104 = 13 * b

104/13 = b

b = 8

A = 1/2(bh)

in this case, b = 2a/h. plug in the values:

steps

b = 2a/h

b = 2(52)/13

b = 104/13

b = 8 meters

Answer:

[tex]6 \frac{5}{9} [/tex]

is greater than

[tex]6 \frac{15}{28} [/tex]

Answer:6 5/9 is greater than 6 15/28

Step-by-step explanation: positive proper fractions: 15/28, 5/9;

1 positive integer number: 6; Any positive proper fraction is smaller than

any positive integer number Sort the positive proper fractions:

15/28 and 5/9 15/28 already reduced to the lowest terms;

the numerator and the denominator have no common prime factors:

15 = 3 × 5;

28 = 22 × 7;

5/9 already reduced to the lowest terms;

the numerator and the denominator have no common prime factors:

5 is a prime number;

9 = 32; 15 = 3 × 5;

5 is a prime number;

Multiply all the unique prime factors, by the largest exponents:

LCM (15, 5) = 3 × 5 = 15 Divide LCM by the numerator of each fraction:

For fraction: 15/28 is 15 ÷ 15 = (3 × 5) ÷ (3 × 5) = 1;

For fraction: 5/9 is 15 ÷ 5 = (3 × 5) ÷ 5 = 3;  Build up all the fractions to the same numerator (which is LCM).

Multiply the numerators and the denominators by their expanding number:

15/28 = (1 × 15)/(1 × 28) = 15/28;

5/9 = (3 × 5)/(3 × 9) = 15/27;

Answer:

26.4 ft^2 (1 d.p.)

Step-by-step explanation:

[tex]area \: of \: circle = \pi {r}^{2} [/tex]

Since it is given that r, the radius of the circle, is 2.9 ft,

area of circle= π(2.9)^2= 8.41π= 26.4 ft^2 (1 d.p.)

Answer: x = 12

Step-by-step explanation:

[tex]\frac{6}{x}[/tex] = [tex]\frac{4}{8}[/tex]

cross multiply

4x = 6 × 8

4x = 48

divide through by 4

x = 12

Answer:

B. 28 degrees

Step-by-step explanation:

ok so,

the starting temperature is 35 degrees then the temperature dropped 4 degrees. making the temp 31 degrees. next the temperature rose 2 degrees, making it 33 degrees. lastly, the temperature dropped another 5 degrees making it 28 degrees out on wednesday.  

so the number line showing this would be B.

Final answer:

After a cold front caused the temperature to drop by 40 degrees from the initial 35 degrees Fahrenheit, the resulting temperature would be -5 degrees Fahrenheit on the number line for Wednesday morning at 8:00am.

Explanation:

The student originally observed a temperature of 35 degrees Fahrenheit on Sunday morning. If we suppose a cold front blows in and drops the temperature by 40.0 Fahrenheit degrees, the temperature change can be calculated by subtracting 40 from the initial temperature:

35 °F - 40 °F = -5 °F

Therefore, the number line that shows the temperature on Wednesday morning at 8:00am should have a point at -5 degrees Fahrenheit, representing the new temperature after the cold front.

Answer:

x-intercept

= 7/6

= 1.16667

Answer:

1.997 x 10²

Step-by-step explanation:

The number with the highest exponent is the greatest value.

10² is bigger than 10⁻⁶ and 10⁻⁸, so 1.997 x 10² is your answer.

Answer:

2/25

Step-by-step explanation:

Answer:

0.08

Step-by-step explanation:

Answer:

Step-by-step explanation:

X=-1/2

Hope this helps mark me as brainiest pls

Yes, -1/2 will be the x-coordinate for the solution. We can also find the y-coordinate by subbing in -1/2 for x in the equation y=4x+7.

y=4(-1/2)+7

y=-2+7

y=5

The intersection point would be (-1/2,5).

Answer:

They are not equal? I don't get what you're trying to ask.

Answer:

OPTION A: [tex]$ \frac{12}{1 + 8x} $[/tex], where [tex]$ x \ne - \frac{1}{8} $[/tex].

Step-by-step explanation:

Given: [tex]$ \frac{- 12x^4}{x^4 + 8x^5} $[/tex]

Taking [tex]$ x^4 $[/tex] common outside in the denominator, we get:

[tex]$ = \frac{-12x^4}{(x^4)(1 + 8x)} $[/tex]

[tex]$ x^4 $[/tex] will get cancelled on the numerator and denominator, we get:

[tex]$ = \frac{-12}{1 + 8x} $[/tex]

we know that the denominator can not be zero.

That means, 1 + 8x [tex]$ \ne $[/tex] 0.

[tex]$ \implies 8x \ne -1 $[/tex]

[tex]$ \implies x \ne \frac{-1}{8} $[/tex]

So, the answer is: [tex]$ \frac{-12}{1 + 8x} $[/tex], where [tex]$ x \ne \frac{-1}{8} $[/tex].

Answer:

The width of the sandbox is 4 feet

Step-by-step explanation:

Area = Length x Width

Fill in known values

26 sq ft = 6.5 ft x w

Divide by 6.5 on both sides

4 ft = w

Width = 4 ft

:)

Answer:

the most it could cost would be $83 dollars

Step-by-step explanation:

2000-1500=500

500/3=83.33

Answer:

Step-by-step explanation:

The probability of drawing the 8 of spades from a deck of cards is 1/52, or approximately 0.0192, which can also be expressed as 1.92%.

The probability of drawing the 8 of spades from a deck of cards is calculated as the number of favorable outcomes divided by the total number of possible outcomes. In this case, there is only 1 8 of spades card in the deck, and there are a total of 52 cards. Therefore, the probability is 1/52, or approximately 0.0192, which can also be expressed as 1.92%.

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Final answer:

The fraction of a 3-gallon container filled with 1/3 gallon of water is 1/9. This is found by dividing the amount of water by the total capacity of the container. It can be represented through multiplication and division, both yielding the result 1/9.

Explanation:

The question asks what fraction of a container is filled if there is 1/3 gallon of water in a 3-gallon container. To represent this situation, we can simply realize that the fraction filled is equal to the amount of water in the container (1/3 gallon) divided by the container's total capacity (3 gallons).

So, 1/9 of the container is filled with water.

To set up a multiplication and division equation to represent the situation:

These representations show how to derive the fraction of the container that is filled using multiplication and division.

Answer:

[tex]\displaystyle 2x - 3y = 6\:OR\:y = \frac{2}{3}x - 2 \\ \\ 3x - 2y = 40\:OR\:y = \frac{3}{2}x - 20[/tex]

Step-by-step explanation:

2 = ⅔[6] + b

4

[tex]\displaystyle -2 = b \\ \\ y = \frac{2}{3}x - 2[/tex]

If you want it in Standard Form:

y = ⅔x - 2

- ⅔x - ⅔x

_________

−⅔x + y = −2 [We do not want fractions in our standard equation, so multiply by the denominator to get rid it.]

−3[−⅔x + y = −2]

[tex]\displaystyle 2x - 3y = 6[/tex]

_______________________________________________

−5 = 3⁄2[10] + b

15

[tex]\displaystyle -20 = b \\ \\ y = \frac{3}{2}x - 20[/tex]

If you want it in Standard Form:

y = 3⁄2x - 20

- 3⁄2x - 3⁄2x

__________

−3⁄2x + y = −20 [We do not want fractions in our standard equation, so multiply by the denominator to get rid of it.]

−2[−3⁄2x + y = −20]

[tex]\displaystyle 3x - 2y = 40[/tex]

* Parallel Lines have SIMILAR RATE OF CHANGES [SLOPES], so ⅔ and 3⁄2 remain the way they are.

I am joyous to assist you anytime.

Complete Question:

As you may have unintentionally forgotten to add the answer choices in your question, but I was able to find the complete the question and answering your question based on this as it may surely clear your concepts. Here is the complete question.

In which of the following functions would it be appropriate to use only positive integers for the domain? Select all that apply.

The function c(p) represents The cost for P people to attend the movies. The function m(t) represents the miles driven over T hours. The function t(m) represents the average high temperature for a given number of months. The function p(w) represents the prophet of a farmer who sells whole watermelons. The function h(n) represents the number of person-hours it takes to assemble n engines in a factory.

Answer Explanation:

Domain is termed as all the input values on a certain interval that define the function.

Here are the appropriate function scenarios where it is appropriate to use only positive integers.

The function c(p) represents The cost for P people to attend the movies.

As the function c(p) contains people. And People are not counted as negative, although they can be zero. So, only positive integers should be appropriate to use in this scenario.

The function m(t) represents the miles driven over T hours

As the function m(t) contains miles. And miles are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

The function t(m) represents the average high temperature for a given number of months.

As the function t(m) contains months. And months are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

The function p(w) represents the prophet of a farmer who sells whole watermelons.

As the function p(w) contains the number of watermelons. And watermelons are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

The function h(n) represents the number of person-hours it takes to assemble n engines in a factory.

As the function h(n) contains the number of engines. And engines are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

Keywords: domain, function, positive integer

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(gof)(0) cannot be evaluated

Solution:

Given that,

[tex]f(x) = \frac{1}{x}\\\\g(x) = x - 4[/tex]

A composite function is denoted by (g o f) (x) = g (f(x)).

The notation g o f is read as “g of f”

Therefore, let us find whether (gof)(0) can be evaluated or not

To find (gof)(0):

(g o f) (x) = g (f(x))

Now substitute the given value of f(x)

[tex](g o f) (x) = g(\frac{1}{x})[/tex]

[tex]\text{ Substitute } x = \frac{1}{x} \text{ in } g(x) = x - 4[/tex]

[tex](g o f) (x) = \frac{1}{x} - 4[/tex]

Now to find (gof)(0), substitute x = 0

[tex](g o f) (x) = \frac{1}{0} - 4[/tex]

Since 1 divided by 0 is undefined, because any number divided by 0 is undefined

(gof)(0) cannot be evaluated

Answer:

You must evaluate the function f first.

Division by 0 is undefined.

The composition cannot be evaluated.

Step-by-step explanation:

Answer:

[tex]\angle a=35^o[/tex]

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

An isosceles triangle has two equal sides and two equal interior angles

The angles opposite to the equal sides of an isosceles triangle are equal.

[tex]\angle b=\angle c[/tex]

we have

[tex]\angle c=55^o[/tex] -----> given problem

so

[tex]\angle b=55^o[/tex]

Remember that

The sum of the interior angles in any triangle must be equal to 180 degrees

[tex]\angle b+\angle c+2\angle a=180^o[/tex]

substitute the given values

[tex]55^o+55^o+2\angle a=180^o[/tex]

[tex]110^o+2\angle a=180^o[/tex]

[tex]2\angle a=180^o-110^o[/tex]

[tex]2\angle a=70^o[/tex]

[tex]\angle a=35^o[/tex]

Answer:

AY = 10 cm.

Step-by-step explanation:

Given that, ΔABC is similar to ΔAXY

and [tex]\frac{AB}{AX }  = \frac{5}{3}[/tex]

⇒  [tex]\frac{AC}{AY }  =  [tex]\frac{BC}{XY } = \frac{5}{3}[/tex]

⇒ BC = XY× \frac{5}{3}[/tex] =  \frac{20}{3}[/tex] (as XY = 4 cm given)

Now, check the attached figure,

given, BY bisects ∠XYC

let ∠XYB = ∠BYC = x

⇒ ∠AYX = 180-2x (angle on a straight line)

and also ∠AYX = ACB (similar triangle properties)

⇒ ∠ACB = 180-2x

Now, sum of angles in ΔBYC = 180°

⇒ ∠YBC = x

⇒ BC = YC (as two sides of equal angles are equal in a triangle)

⇒ YC =  \frac{20}{3}[/tex]

And also [tex]\frac{AC}{AY }  = \frac{5}{3}[/tex]

AC = AY + YC

⇒ [tex]\frac{AY+YC}{AY }  = \frac{5}{3}[/tex]

⇒ [tex]\frac{AY+\frac{20}{3}[/tex]}{AY }  = \frac{5}{3}[/tex]

⇒ 5AY = 3AY + 20

⇒ AY = 10 cm

Answer:

y = 3

Step-by-step explanation: