Can someone please help me how to set this up?

A police car receives a radio call to catch a vehicle which is speeding down the highway at 80 mph. The police car, which is 12 miles away, drives after it at 108 mph. How long will it take for the police car to catch up? ...?

The Kinetic energy of the athlete will be 50 times of the mass of the athlete.

We have a athlete who completed a 100m race in 10 seconds.

We to estimate the average kinetic energy of the athlete.

The formula to calculate the kinetic energy of any moving body is -

K.E. = [tex]\frac{1}{2} mv^{2}[/tex]

According to question -

Distance covered by athlete = 100 meters

Time taken by the athlete = 10 seconds

Let's assume the mass of the athlete = M Kg

Consider the formula for the Kinetic energy of the body -

K.E. = [tex]\frac{1}{2} mv^{2}[/tex]

We know that -

v = [tex]\frac{distance}{time} = \frac{x}{t}[/tex]

Substituting the value of velocity in equation of kinetic energy -

K.E =  [tex]\frac{1}{2} m(\frac{x}{t}) ^{2}[/tex]

We can see that the kinetic energy of the athlete is -

K.E. [tex]\alpha\; (\frac{x}{t})^{2}[/tex]

Greater the square of the ratio of x and t, greater will be the kinetic energy.

K.E. = 0.5 x M x 10 x 10

K.E. = 50M

Hence, the Kinetic energy of the athlete will be 50 times of the mass of the athlete.

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The most efficient nuclear fission reactor would require a higher ratio of U-235 to U-238 due to the higher fissionability of U-235.

The most efficient nuclear fission reactor would require a higher ratio of U-235 to U-238.

U-235 is the fissile isotope of uranium and readily undergoes fission, producing a large amount of energy. U-238, on the other hand, is a fertile isotope that can be converted into plutonium-239, which is also highly fissionable. By increasing the ratio of U-235 to U-238, more U-235 will be available for fission reactions, leading to a higher energy output and efficiency.

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Answer:

a. its velocity is zero.

Explanation:

At maximum height no activities is going on that is the velocity becomes zero because no movement occurs at that point

Since there is no moveent the velocity is zero.

At an object's maximum height in projectile motion, its velocity is zero but its acceleration due to gravity remains constant. Therefore, the correct statement is option a).

Here is the detailed reasoning:

An object thrown upwards will decelerate due to gravity until its velocity becomes zero at the maximum height. This is the point where its upward motion stops, and it is about to start descending.

The velocity magnitude at maximum height is zero, but its acceleration is still the acceleration due to gravity (g), acting downwards. Therefore, option d. its acceleration is zero, is incorrect.

Terminal velocity refers to the constant speed that a free-falling object eventually reaches, which is not relevant here. So, option b is incorrect.

Even at its maximum height, an object is still under the influence of gravity, meaning it is in free fall, which makes option c incorrect.

Therefore, the correct answer is a. its velocity is zero.    

Final answer:

The work done by a person who exerted a force of 500 Newtons to move a full wheelbarrow over a distance of 30 meters is 15000 Joules.

Explanation:

If a person exerted a force of 500 Newtons (F = 500 N) to move a full wheelbarrow over a distance of 30 meters (d = 30 m), the work done can be calculated using the formula:

Work (W) = Force (F) × Distance (d)

Plugging in the given values, we get:

W = (500 N) × (30 m) = 15000 Joules (J)

The work done is therefore 15000 Joules, which demonstrates the transfer of energy through force applied over a distance.

Answer:

C.the moon at apogee coming between Earth and the sun along a straight line

Explanation:

As we know that Earth rotate about the sun in elliptical orbit as one of the planet.

While moon rotate about the Earth similarly as one of the satellite around it

now when moon, Sun and Earth all lie in the same line such that position of moon is between the positions of Sun and Earth then in this case the light coming from sun is totally bounded by the position of moon

This situation of moon is known as Solar Eclipse

so here during the motion if the moon at apogee coming between Earth and the sun along a straight line then it is the most likely cause of annular solar eclipse.

Answer:

-1.176 m/s²

Explanation:

Given:

weight of aluminium block is w = 20.0 N

frictional force, f = 2.4 N

final velocity, v = 0

distance covered, d = 10 m

From Newton's second equation of motion,

F = ma

where, m is the mass and a is the acceleration.

mass of the block, m g = 20.0 N

m = 2.04 kg

The block is brought to rest by friction force:

f =- m a

⇒ 2.4 N = -(2.04 kg)(a)

⇒a = -1.176 m/s²

The efficiency of the machine is  54.76%.

The efficiency of a machine refers to the amount of useful work that is done by the machine. Efficiency is usually expressed as a percentage.

From the question;

Work output= 230 J

Work input=  420 J

We know that efficiency = Work output/work input × 100/1

efficiency =230 J/420 J × 100/1

efficiency = 54.76%

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Answer: The answer to this question is Unbalanced force.

Explanation: There are two types of forces:

1. Balanced force: When two forces equal in their magnitude act opposite to each other are known as balanced force. The net force is equal to 0.

2. Unbalanced force: When two forces acting opposite to each other are not equal in magnitude results in the unbalanced force. The net force of this is not equal to 0. Direction of force is in the direction of net force.

Now, according to Newton's first law of motion, which says that force is the product of the object's mass and acceleration. The force should have some value and hence it cannot be equal to zero. therefore the force must be Unbalanced force.

According to Newton's second law of motion, a net external force causes a body to accelerate, with the acceleration being directly proportional to the force and inversely proportional to its mass.

According to Newton's second law of motion, a force is expected to cause a body to accelerate when it acts upon the body. This law can be summarized by the equation Fnet = ma, where Fnet denotes the net force acting on the body, m stands for mass, and a signifies acceleration. Therefore, the linear acceleration of a rigid body is directly proportional to the net force acting on it and inversely proportional to its mass. It is important to note that the acceleration occurs in the same direction as the net external force. In simple terms, if you apply a net external force to an object, it will accelerate, and the magnitude of this acceleration can be calculated by dividing the net force by the object’s mass.

Answer:

it is cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

Explanation:

becai=use i know

The frictionless ramp A will give the ball the greatest speed at the bottom of the ramp.

Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while u for the final speed. its si unit is m/sec.

The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule. Ball has the most potential energy due to her position at C.

The potential energy is mainly dependent upon the height of the object.

Potential energy = mgh

The potential energy gets converted into kinetic energy at the bottom. If the ramp is frictionless the potential energy completely gets converted into kinetic energy.

The kinetic energy results in the motion of the body.

Hence frictionless ramp A will give the ball the greatest speed at the bottom of the ramp.

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Fleming's right-hand rule (for generators) shows the direction of induced current when a conductor moves in a magnetic field. It can be used to determine the direction of current in a generator's windings.

When a conductor such as a wire attached to a circuit moves through a magnetic field, an electric current is induced in the wire due to Faraday's law of induction. The current in the wire can have two possible directions. Fleming's right-hand rule gives which direction the current flows

The right hand is held with the thumb, first finger and second finger mutually perpendicular to each other (at right angles.

The car was initially traveling at approximately 22.02 m/s.

To solve this problem, we can break it down into horizontal and vertical components. Let's call the initial velocity of the car 'v.'

The car's horizontal velocity after the collision is given by its initial velocity multiplied by the cosine of the angle, which is 28 m/s * cos(37°). The truck's horizontal velocity after the collision is 0 m/s since it was initially stationary.

Since no horizontal forces act on the system after the collision, the momentum in the horizontal direction is conserved. Thus, the sum of the initial flat rates of the car and the truck must equal the final horizontal velocity. Therefore, m * v = m * (28 m/s * cos(37°)), where 'm' represents the mass of the car and the truck.

If we divide both sides of the equation by 'm', we get v = 28 m/s * cos(37°). Evaluating this expression, we find v ≈ 22.02 m/s.

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The power of the toaster, calculated using the formula P = W/t, is 700 Watts.

The power of an appliance like a toaster can be calculated using the formula for power which is P = W/t, where P is Power, W is work done or energy consumed, and t is time.

Given that the toaster does 21,000 Joules of work or consumes 21,000 joules of energy in 30 seconds, the power would thus be calculated as follows: P= 21,000J / 30 s. This equals 700 Watts. So, the toaster has a power of 700 Watts.

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The mass of the window washer who stands on a scaffolding 30 meters above the ground is 78.4 Kg.

Energy of the body due to its position with respect to some other object (say earth) is called potential energy.

Given is a a window washer who stands on a scaffolding 30 meters above the ground.

The amount of work done by the window washer will be stored inside him in the form of potential energy. Therefore, we can write -

mgh = 23520

m x 10 x 30 = 23520

m = 23520/300

m = 78.4 Kg

Therefore, the mass of the window washer who stands on a scaffolding 30 meters above the ground is 78.4 Kg.

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The Ideal Mechanical Advantage (IMA) of the ramp used to move the stereo is 2. This is calculated by dividing the length of the ramp (3 meters) by its height (1.5 meters).

The question is asking for the Ideal Mechanical Advantage (IMA) of the ramp, also known as an inclined plane, used in moving the stereo. The IMA for an inclined plane, or ramp, can be calculated using the formula IMA = length of slope / height of slope. In this scenario, the length of the ramp is 3 meters and the height is 1.5 meters. Plugging these values into the formula, the IMA is calculated as 3 / 1.5 = 2. This means that the ramp multiplies the force applied to the stereo by two, making the task of loading the stereo easier.

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Answer:

s = - 4 cos 4t + 2t + 6.

Explanation:

a = dv/dt = 16 cos 4t ,

dv = 16 cos 4t dt

integrating on both sides

v = 16 x sin 4t /4 + c

    = 4 sin 4t + c

when t = 0 , v = 2

2 = 0 + c

c = 2

v = 4 sin 4t + 2

ds/dt = 4 sin 4t + 2

ds = ( 4 sin 4t + 2) dt

integrating on both sides

s = - 4 cos 4t/4 + 2t + k

    = - cos 4t + 2t + k

when t = 0 s = 5

5 =  -1 + 0 + k

k = 6

s = - 4 cos 4t + 2t + 6.

Ans.

Answer:

Explanation:

The work is defined as the force needed to move an object a certain distance, if there's no change of position, there's no work.

In this case, the work is defined:

[tex]W=Fd[/tex]

Where [tex]F[/tex] is the weight defined with the following equation

[tex]F=W=mg[/tex]

Now, we'll replace all given values and solve for [tex]m[/tex]:

[tex]W=mgy\\178=m(9.8)(0.5)\\m=\frac{178}{4.9}=36.33 kg[/tex]

Therefore, the mass is 36.33 kilograms.

Answer:

[tex]W_{tot}=W_{1}+W_{2}=mgh_{2}=7.55[J][/tex]

Explanation:

The work done on an object is the scalar product between force and displacement. So we can write the work:

[tex]W=F\cdot d=Fd[/tex]

In our case F and d are parallels then we have a common product of their magnitudes.

Now, the total work will be the sum these two works:

Let's recall that the force in this problem is just the weight of the book. F=m*g

Finally, the total work will be the sum of W₁ and W₂.

[tex]W_{tot}=W_{1}+W_{2}=mgh_{2}=2.2*9.81*0.35=7.55[J][/tex]

I hope it helps you!

To calculate the work done on the book, the student librarian must use the formula W = mgh for each segment of lifting the book vertically. The total work done is the sum of the work for lifting the book to 1.25 m and then to 0.35 m. The horizontal distance carried does not contribute to work against gravity.

The work done on the book by the student librarian can be calculated by considering the work done against gravity to lift the book to different heights. The distance carried horizontally does not involve work against gravity under the assumption that there is no horizontal force like friction opposing the motion. The work done to lift the book from the floor to 1.25 m can be calculated using the formula W = mgh, where m is the mass of the book, g is the acceleration due to gravity (approximately 9.8 m/s2), and h is the height.

The initial lift is W = 2.2 kg × 9.8 m/s2 × 1.25 m. When placing the book from the carried position to a shelf at 0.35 m height, the work done is W = 2.2 kg × 9.8 m/s2 × 0.35 m since the vertical displacement is from 1.25 m to 0.35 m, not the full 1.25 m again.

The total work done on the book is the sum of these two amounts of work. Please note that the gravitational constant (g) could be given or assumed in this context. The exact value used may vary slightly depending on the context of the problem.

The velocity of a ball at t = 1 second when it was thrown up with an initial velocity of 42 ft/s, we differentiate the height function to get the velocity function and substitute t = 1 to find the velocity to be 10 feet per second.

The velocity of a ball thrown straight up into the air at a specific time (t = 1 second), using the given position function y = 42t - 16t². To find the velocity at t = 1, we differentiate the position function with respect to time to get the velocity function v(t) = dy/dt. After differentiation, we get v(t) = 42 - 32t and then plug in t = 1 to find the velocity at that moment.

After substituting t into the velocity function, we get v(1) = 42 - 32(1) = 10 ft/s. Hence, the velocity of the ball at t = 1 second is 10 feet per second.

The force exerted by the chin-up bar on the person's body depends on the acceleration. At certain times, the force is 0 N, while at other times it can be calculated using the formula Force = Mass x Acceleration.

The force exerted by the chin-up bar on the person's body can be calculated using the equation:

Force = Mass x Acceleration

At t = 0s, the person's body is at rest, so the acceleration is 0. Therefore, the force exerted by the bar is 0 N.

At t = 0.5s, the person's body is moving upward with a constant speed. Since the velocity is constant, the acceleration is 0 and the force exerted by the bar is 0 N.

At t = 1.1s, the person's body is moving upward with an increasing speed. The acceleration can be calculated using the change in velocity over time, and then substituted into the force equation to find the force exerted by the bar.

At t = 1.6s, the person's body is moving upward with a decreasing speed. The acceleration can be calculated using the change in velocity over time, and then substituted into the force equation to find the force exerted by the bar.