can u guys help me on this one? please and ty!

First one is C and second one is A

x/2+3=-5

x/2 = -5+3

x/2 = -2

x = -2(2)

x = -4

Answer:

X = - 16

PLEASE RATE AND THANKS ME IF THIS HELPED

Answer:

FIRST OPTION.

THIRD OPTION.

FOURTH OPTION.

FITH OPTION.

Step-by-step explanation:

The equation of the line in slope-intercept form is:

[tex]y=mx+b[/tex]

Where m is the slope, b the y-intercept and the exponent of x is always 1 or 0.

Solve for y from  the equations shown below:

[tex]5+2y=13\\2y=8\\y=4[/tex]

(In this linear function the slope is 0)

[tex]y-5=2(x-1)\\y=2x-2+5\\y=2x+3[/tex]

(It is a linear function)

[tex]\frac{y}{2}=x+7\\ y=2(x+7)\\y=2x+14[/tex]

 (It is a linear function)

Equation of the line whose slope is not defined:

[tex]x=-4[/tex]

Answer:

1, 3, 4, and 5

Step-by-step explanation:

Edge 2021!

Proof:

Answer:

the answer is 30

Step-by-step explanation:

9(5)=45

45-15=30

➷ Substitute 5 into everywhere you see 'n'

9(5) - 15

Simplify:

9 x 5 = 45

45 - 15 = 30

The answer is 30.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

Answer:

20m and 40m

Step-by-step explanation:

The area (A) of a kite is calculated using the formula

A = [tex]\frac{1}{2}[/tex] product of diagonals

Let one diagonal be d then the other diagonal is 2d ( twice as long )

Hence

[tex]\frac{1}{2}[/tex] × 2d × d = 400

d² = 400 ← take the square root of both sides

d = [tex]\sqrt{400}[/tex] = 20

and 2d = 2 × 20 = 40

The diagonals are 20m and 40m in length

The lengths of the diagonals of a kite, where the area is 400 square meters and one diagonal is twice the length of the other, are 20 meters for the shorter diagonal and 40 meters for the longer diagonal.

You asked how the lengths of the diagonals of a kite can be determined given that the area is 400 square meters and one diagonal is twice as long as the other. To find the diagonals, we'll use the formula for the area of a kite, which is Area = (d1 * d2) / 2, where d1 and d2 are the lengths of the diagonals.

Let's denote the shorter diagonal as d, which means the longer diagonal is 2d. Plugging these into the area formula gives us:

400 m2 = (d * 2d) / 2

Multiplying both sides by 2 gives us 800 m2 = d * 2d, which simplifies to 800 m2 = 2d2.

Dividing both sides by 2 gives us 400 m2 = d2. Taking the square root of both sides, we find that d = 20 meters. Hence, the longer diagonal is 2 * 20 meters = 40 meters.

The lengths of the diagonals of the kite are 20 meters and 40 meters.

Answer:

[tex]\large\boxed{A=(120+32\pi)cm^2}[/tex]

Step-by-step explanation:

Look at the picture.

We have the half of circle and a triangle.

The fromula of an area of a circle:

[tex]A_O=\pi r^2[/tex]

r - radius

We have r = 8cm. Substitute:

[tex]A_O=\pi(8)^2=64\pi\ cm^2[/tex]

The formula of an area of a triangle:

[tex]A_\triangle=\dfrac{bh}{2}[/tex]

b- base

h - height

We have b = 8cm + 8cm = 16cm and h = 15cm. Substitute:

[tex]A_\triangle=\dfrac{(16)(15)}{2}=(8)(15)=120\ cm^2[/tex]

The area of the figure:

[tex]A=\dfrac{1}{2}A_O+A_\triangle[/tex]

Substitute:

[tex]A=\dfrac{1}{2}(64\pi)+120=32\pi+120=(120+32\pi)cm^2[/tex]

The half-life of the substance is calculated using the decay constant and is found to be 5.0 days when rounded to the nearest tenth.

To find the half-life of a substance, we use the decay formula N = [tex]N0e^{-kt}[/tex], where N is the remaining mass at time t, N0 is the initial mass, k is the decay constant, and t is the time in days. For a substance to reach its half-life, the remaining mass (N) will be half of the initial mass (N0).

Let's substitute the known values to find the half-life:

Initial mass N0 = 22 g

The decay constant k = 0.138

Half of the initial mass would be 11 g, so N = 11 g

Using the formula for half-life:

0.693 / k = t1/2

Substitute k = 0.138 into the equation:

t1/2 = 0.693 / 0.138

Calculate the half-life:

t1/2 = 5.0 days

Thus, we round to the nearest tenth to get the half-life as 5.0 days.

1. 311

2. 522

3. 603

4. 341.47826087

5. 221.558823

5b. All i did was divide the regular way or u could just put it in a calculator?

The correct answers are 2,3, and 4.

(if not 4, then the last one)

Answer:

C.Vertical angles prove that angle 3= angle 6

D.The triangles are similar because alternate interior angles are congruent.

Step-by-step explanation:

When line d is parallel to line c.

We have to find the true statements about the figure.

Then, [tex]\angle 3=\angle 6[/tex](Vertical angles are equal)

[tex]\angle 1=\angle 4[/tex]

[tex]\angle 2=\angle 5[/tex]

Reason: Alternate interior angles

Two triangles are similar by AA postulate

Reason:Alternate interior angle are congruent.

Option C and D are true.

C.Vertical angles prove that angle 3= angle 6

D.The triangles are similar because alternate interior angles are congruent.

Answer:  x = {1, -1, 2i, -2i}

Step-by-step explanation:

x⁴ + 3x² - 4 = 0

               ∧

             -1 +4 = 3   this works!

(x² - 1)(x² + 4) = 0

x² - 1 = 0     and      x² + 4 = 0

x² = 1          and      x² = -4

x = ±1         and       x = ± 2i

x = 1, -1      and       x = 2i, -2i

The answer is:

[tex]x=3\\y=2[/tex]

Ordered pair: (3,2)

The substitution method for solving system of equations consists in finding the solution by isolating and substituting each variable value into the given equations, doing that, all the variable value can be found.

So, we are given two equations:

[tex]2x+y=8\\y= -x+5[/tex]

We need to substitute (y) into the first equation,so:

[tex]2x+(-x+5)=8[/tex]

[tex]2x-x+5=8[/tex]

[tex]x+5=8[/tex]

[tex]x=8-5[/tex]

[tex]x=3[/tex]

Now that we know "x" we need to substitute it into the second equation, so:

[tex]y=-(3)+5[/tex]

[tex]y=2[/tex]

Hence,

[tex]x=3\\y=2[/tex]

So, the ordered pair will be: (3,2)

Have a nice day!

Answer:

Ordered pair = (3, 2)

Step-by-step explanation:

We are given the following equations and we are to solve them by substitution method:

[tex]2x+y=8[/tex] --- (1)

[tex]y= -x+5[/tex] --- (2)

Substituting the value of y from equation (2) to (1):

[tex]2x+(-x+5) = 8[/tex]

[tex]2x-x+5=8[/tex]

[tex]x = 8-5[/tex]

x = 3

Substituting this value of x in equation (2):

[tex]y = -(3)+5[/tex]

y = 2

So the ordered pair is (3, 2).

Answer:

3x=0 or x+4=0

x=0 or x=−4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3x2+12x=0

Step 2: Factor left side of equation.

3x(x+4)=0

Step 3: Set factors equal to 0.

3x=0 or x+4=0

x=0 or x=−4

Answer:

C.) 60 feet

Step-by-step explanation:

Knowing that the formula for finding the circumference of a circle is [tex]\pi d[/tex] or [tex]2\pi r[/tex], we are able to set up the equation to be:

[tex]188.4=3.14d[/tex]

[tex]\frac{188.4}{3.14} =d[/tex]

[tex]60=d[/tex]

and done! :)

Answer:

Step-by-step explanation:

This time we'll do this using 1 formula to get the answer.

Givens

n = 9 (number of sides in an 9-gon.

inradius (apothem) = a= 7

Formula

Area = a^2 * n * tan(180/n)     Substitute

Solution

Area = 9^2 * 9 * tan(180/9)     Combine

Area = 81 * 9 * tan(20)

Area = 729 * tan (20)

Area = 265.33

Area rounded = 265

Answer:

175 I believe.

Step-by-step explanation:

The distance between the sandbag and the target is 325 meters.

The distance between the sandbag and the target can be calculated by subtracting the distance of the sandbag from the balloon's height from the total distance between the balloon and the target. In this case, the balloon is 250 meters above the target and the sandbag is 75 meters below the balloon. So, the distance between the sandbag and the target is 250 + 75 = 325 meters.

Answer:

Step-by-step explanation:

The formula of a distance between two points:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

We have (-3, 1) and (-1, 5). Substitute:

[tex]d=\sqrt{(-1-(-3))^2+(5-1)^2}=\sqrt{2^2+4^2}=\sqrt{4+16}=\sqrt{20}\\\\=\sqrt{4\cdot5}=\sqrt4\cdot\sqrt5=2\sqrt5\approx2\cdot2.23=4.46[/tex]

Answer:

it 4.47

Step-by-step explanation:

I TOOK THE TEST

Answer:

8.79

Step-by-step explanation:

Rounding the nearest hundredth would be using the thousandths place to determine if the hundredths place must be rounded up or down. Because there is no visible thousandths place in 8.79, then it stays as 8.79. Because technically, there is an infinite number of zero's after the 9- and because 0 is less than 5, we leave the number as it is.

85+92+84+71+94+x /6>86

Multiply both sides by 6

426+x>516

Subtract 426 from both sides

X>90

Answer:

Part 1) [tex]y=-(1/4)x[/tex]

Part 2) [tex]y=-(3/5)x+2[/tex]

Part 3) [tex]y=(1/5)x-2[/tex]

Step-by-step explanation:

we know that

The equation of the line into slope intercept form is equal to

[tex]y=mx+b[/tex]

where

m is the slope

b is the y-coordinate of the y-intercept

Part 1) we have

[tex]20x+80y=0[/tex]

Simplify

Divide by 20 both sides

[tex]x+4y=0[/tex]

isolate the variable y

Subtract x both sides

[tex]4y=-x[/tex]

Divide by 4 both sides

[tex]y=-(1/4)x[/tex] ------> equation of the line into slope intercept form

[tex]m=-(1/4)[/tex]

[tex]b=0[/tex]

Part 2) we have

[tex]30x+50y-100=0[/tex]

Simplify

Divide by 10 both sides

[tex]3x+5y-10=0[/tex]

isolate the variable y

Subtract (3x-10) both sides

[tex]5y=-(3x-10)[/tex]

Divide by 5 both sides

[tex]y=-(3/5)x+2[/tex] ------> equation of the line into slope intercept form

[tex]m=-(3/5)[/tex]

[tex]b=2[/tex]

Part 3) we have

[tex]3x-15y-30=0[/tex]

Simplify

Divide by 3 both sides

[tex]x-5y-10=0[/tex]

isolate the variable y

Subtract (x-10) both sides

[tex]-5y=-(x-10)[/tex]

Divide by -5 both sides

[tex]y=(1/5)x-2[/tex] ------> equation of the line into slope intercept form

[tex]m=(1/5)[/tex]

[tex]b=-2[/tex]

Answer:

AB is A

BC is B

AC is D

Step-by-step explanation:

To find the length of each side, use the formula for the distance between coordinate pairs.

We can find the distance using the distance formula:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

AB

We then substitute (-3,6) as [tex](x_1,y_1)[/tex] and (2,1) as [tex](x_2,y_2)[/tex].

[tex]d=\sqrt{(2--3)^2+(1-6)^2} \\d=\sqrt{(2+3)^2+(-5)^2} \\d=\sqrt{25+25}\\d=\sqrt{50}[/tex]

BC

We then substitute (2,1) as [tex](x_1,y_1)[/tex] and (9,5) as [tex](x_2,y_2)[/tex].

[tex]d=\sqrt{(9-2)^2+(5-1)^2} \\d=\sqrt{(-7)^2+(4)^2} \\d=\sqrt{49+16}\\d=\sqrt{65}[/tex]

AC

We then substitute (-3,6) as [tex](x_1,y_1)[/tex] and (9,5) as [tex](x_2,y_2)[/tex].

[tex]d=\sqrt{(9--3)^2+(5-6)^2} \\d=\sqrt{(12)^2+(-1)^2} \\d=\sqrt{144+1}\\d=\sqrt{145}[/tex]

Answer:11x4+3=47

Step-by-step explanation:

Answer:

47

Step-by-step explanation:

11 x 4 + 3 = 47

Answer:

It has 2.

Step-by-step explanation:

Since the numbers aren't zeroes they are automatically significant figures.

Answer:

2

Step-by-step explanation:

There are 2 digits needed to nail down the precise value of 12: a 1 in the tens place and a 2 in the ones place, giving it 2 significant figures.

For a few more examples, the number 1.23 would have 3 significant figures, the number 56.89 would have 4, and the number 1.00000 would have 1, as the trailing zeroes don't contribute anything to the number's actual value.

Answer:

The answer is the first

Amie should have multiplied 54 by 2/3

Step-by-step explanation:

* Lets start with the rule of the volume of each solid

∵ Volume the sphere = 4/3 π r³

∵ Volume the cylinder = π r² h

∵ The radii and the heights of the sphere and the cylinder are equal

∴ The ratio between there volumes are

   4/3 π r³ : π r² h

- Lets divide each part by π r²

∴ 4/3 r : h

∵ The height of the sphere = the diameter of it = 2r

∴ The height of the cylinder = 2r

∴ The ratio will be:

   4/3 r : 2r

- Now divide each part by 2r

∵ (4/3)r ÷ 2r = 2/3

∵ 2r ÷ 2r = 1

∴ The ratio is 2/3 : 1

∴ The volume of the sphere = 2/3 the volume of the cylinder

∵ The volume of the cylinder = 54 m³

∴ The volume of the sphere = 2/3 × 54 = 36 m³

∴ The answer is Amie should have multiplied 54 by 2/3

Answer:

The answer is Amie should have multiplied 54 by 2/3

Step-by-step explanation:

Answer:

4 units left and 2 units up

Step-by-step explanation:

Translation notation is the words you would use to describe the translation of the point or shape. It says that the point was translated 4 units left and 2 units up, and that is the translation notation.

Here is your answer

d. CD overbar congruent to EF overbar.

REASON:

Since, line segment CD is congruent to line segment EF and im geometry an overbar represents a line segment.

So, we can say that CD overbar means line segment CD and EF overbar means line segment EF.

Hence, the statement is justified.

HOPE IT IS USEFUL

Here is your answer

d. CD overbar congruent to EF overbar.

REASON:

Since line segment CD is congruent to line segment EF and in geometry an overbar represents a line segment.

So, we can say that CD overbar means line segment CD and EF overbar means line segment EF.

Hence, the statement is justified.

hope this helps :)

remember to love urself <3

Answer:

0.55511330152

Step-by-step explanation:

Answer:

x = 47

Step-by-step explanation:

Using the cofunction identity

cos x = sin(90 - x), hence

cos43 = sin (90 - 43) = sin47

Answer:

16.25=1.75x

Step-by-step explanation:

so write it like this to that the bigger number(16.25) is on the left then write the other number(1.75)then put the X by the 1.75

Answer:

Part a) The drawn in the attached figure

Part b)The slant height of the outside edge is [tex]x=10\ in[/tex]

Step-by-step explanation:

Part a) The drawn in the attached figure

Part b) What is the slant height of the outside edge?

we have that

The diameter of the base of the cone is 12 in

so

[tex]r=12/2=6\ in[/tex] ----> the radius is half the diameter

[tex]h=8\ in[/tex]

Applying the Pythagoras Theorem find the slant height x

[tex]x^{2}=r^{2}+h^{2}[/tex]

substitute the values

[tex]x^{2}=6^{2}+8^{2}[/tex]

[tex]x^{2}=100[/tex]

[tex]x=10\ in[/tex]

Answer:

22 degrees

Step-by-step explanation:

Since both triangles correspond, side x is correspondent to 22 degrees, Since that is also the only given piece of information, that is your answer.

Answer:

[tex]\large\boxed{VW=\sqrt{113}}[/tex]

Step-by-step explanation:

The formula of a distance between two points:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

We have the points W(4, 6) and V(-3, -2). Substitute:

[tex]VW=\sqrt{(-3-4)^2+(-2-6)^2}=\sqrt{(-7)^2+(-8)^2}=\sqrt{49+64}=\sqrt{113}[/tex]