Complete the following sentences. Match the words in the left-hand column with the appropriate blank in the sentences in the right-hand column. View Available Hint(s) ResetHelp 1. A monosaccharide is a(n) glucose if the carbonyl group is on the end of the carbon chain. 2. If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n) aldotriose. 3. Any carbohydrate with the carbonyl group on the second carbon is a(n) ketopentose. 4. With the carbonyl group on the end of a six-carbon chain, the carbohydrate would be classified as a(n) aldose. 5. The most common carbohydrate, ketose, has six carbon atoms. 6. Glyceraldehyde is an example of a(n) aldohexose, because it has three carbon atoms.

Answers

Answer 1

1. If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n) ketopentose.

2. Any carbohydrate with the carbonyl group on the second carbon is a(n) ketose.

3. The most common carbohydrate, glucose, has six carbon atoms.

4. A monosaccharide is a(n) aldose if the carbonyl group is on the end of the carbon chain.

5. Glyceraldehyde is an example of a(n) triose, because it has three carbon atoms.

6. With the carbonyl group on the end of a six-carbon chain, the carbohydrate would be classified as a(n) aldohexose.

1. The term "ketopentose" refers to a five-carbon carbohydrate with a carbonyl group on the second carbon.

2. A "ketose" is a carbohydrate with a carbonyl group (ketone group) on an internal carbon atom.

3. "Glucose" is a common hexose sugar with six carbon atoms.

4. An "aldose" is a monosaccharide with a carbonyl group at the end of the carbon chain.

5. "Triose" denotes a three-carbon sugar, and glyceraldehyde is an example.

6. An "aldohexose" is a six-carbon sugar with the carbonyl group at the end of the carbon chain.

In summary, Carbohydrates are classified based on carbon atom count and carbonyl group placement. Xylulose is a ketopentose. Glucose is a common hexose. An aldose has the carbonyl group at the chain end, while glyceraldehyde is a triose. An aldohexose has a six-carbon chain with the carbonyl group at the end.

The question probable may be:

Complete the following sentences. Match the words in the left-hand column with the appropriate blank in the sentences in the right-hand column.
aldose, ketose, ketopentose, aldohexose, triose, glucose
1. 1. If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n)

2. 2. Any carbohydrate with the carbonyl group on the second carbon is a(n)

3. The most common carbohydrate,_________, has six carbon atoms.

4. A monosaccharide is a(n)______ if the carbonyl group is on the end of the carbon chain.

5. Glyceraldehyde is an example of a(n) _________ , because it has three carbon atoms.
6.  With the carbonyl group on the end of a six-carbon chain, the carbohydrate would be classified as a(n)____________.


Related Questions

Cardiac muscle causes movement in the .

Answers

Causes movement in the heart

Answer:

organ

Explanation:

it causes movement in the heart and the heart is an organ

Use the observation in the first column to answer the question in the second column. observation question The enthalpy of vaporization of Substance C is bigger than that of Substance D. Which has the higher boiling point? Substance C Substance D Neither, C and D have the same boiling point. It's impossible to know without more information. At 1atm pressure, Substance E boils at 89.°C and Substance F boils at 128.°C. Which has a higher enthalpy of vaporization? Substance E Substance F Neither, E and F have the same enthalpy of vaporization. It's impossible to know without more information. At −3°C, Substance A has a vapor pressure of 147.torr and Substance B has a vapor pressure of 177.torr. Which has a higher boiling point? Substance A Substance B Neither, A and B have the same boiling point. It's impossible to know without more information.

Answers

Answer:

See explaination

Explanation:

1. Substance C

With Vapor pressure (VP) of C = 136 torr and VP of D = 186 torr. Since VP (C) < VP (D), this entaills that one needs to supply more energy to get C into the vapor phase. Hence, enthalpy of vaporization of C will be higher.

2. Substance A

B.pt (A) = 109 C

B,pt (B) = 125 C

Having A boils at a lower temperature than B, this automatically will make A to have a higher vapor pressure.

3. Substance E

Since E has a lower enthalpy of vaporization, it can be brought into the vapor phase with lower energy as compared to F. Hence, E will have a higher vapor pressure.

Final answer:

Substance C has a higher boiling point than Substance D, Substance F has a higher boiling point (and thereby a higher enthalpy of vaporization) than Substance E, and Substance A has a higher boiling point than Substance B due to its lower vapor pressure.

Explanation:

The boiling point of a substance is directly related to its enthalpy of vaporization. In other words, a substance with a higher enthalpy of vaporization requires more heat to transform from a liquid to a gaseous state, making it have a higher boiling point.

So, based on the given observations:

Substance C has a higher enthalpy of vaporization than Substance D, therefore Substance C has a higher boiling point.Substance E boils at 89°C and Substance F boils at 128°C, therefore Substance F has a higher boiling point and consequently a higher enthalpy of vaporization.Substance A has a lower vapor pressure than Substance B at the same temperature (-3°C). Therefore, Substance A would require more energy to convert to the gaseous phase and so between Substance A and Substance B, Substance A has a higher boiling point.

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