Compute

$(\sqrt{3755}+\sqrt{3752})(-\sqrt{3755}-\sqrt{3752})(\sqrt{3755}-\sqrt{3752})(\sqrt{3752}-\sqrt{3755})$.
Thanks!

Answers

Answer 1
We could use:

[tex](a-b)(a+b)=a^2-b^2[/tex]

For the first and third factors there will be:

[tex](\sqrt{3755}+\sqrt{3752})(\sqrt{3755}-\sqrt{3752})=(\sqrt{3755})^2-(\sqrt{3752})^2=\\\\3755-3752=3[/tex]

and for the second and fourth:

[tex](-\sqrt{3755}-\sqrt{3752})(\sqrt{3752}-\sqrt{3755})=\\\\= (-\sqrt{3755}-\sqrt{3752})(-\sqrt{3755}+\sqrt{3752})=\\\\= (-\sqrt{3755})^2-(\sqrt{3752})^2=3755-3752=3[/tex]

So the answer is:

[tex]3\cdot 3=\boxed{9}[/tex]

Related Questions

A taxi service charges a flat fee of $4.20 per ride plus an additional $.80 per mile.
If a taxi ride costs $6.60, how many miles did the taxi travel?

Answers

im pretty sure he traveled 3 miles

Answer:

3.    

Step-by-step explanation:

An athlete eats
45
grams of protein per day while training. How much is this in milligrams?

Answers

it is 45,000 milligrams 
your answer would be 45000.

Need help with this one!!!

Answers

[tex]\bf (2x^2)^4(5x^6)\impliedby \textit{distributing the exponent} \\\\\\ 2^4x^{2\cdot 4}5x^6\implies 2^4\cdot 5x^{2\cdot 4}x^6\implies 16\cdot 5x^8x^6\implies 80x^{8+6} \\\\\\ 80x^{14}[/tex]

The percentage results of a quiz are as follows: 62, 83, 90, 72, 88, 92, 75, 88, 96, 86, 81, 68, 87. About what percent of the class scored below an 80?

Answers

The fraction will be out of 13.
62, 72, 75, 68 are the only scores less than 80
4/13
30 percent scored less than 80

Hello There!

There are 13 results so that is the total number, 
4 results are below 80
Making it [tex] \frac{4}{13} [/tex]
This is percentages is 30.77%
Making it approximately 31%.

Hope This Helps You!
Good Luck :)

You spend $28 on ingredients to make cookies. You charge $4 per container of cookies. How many containers do you need to sell to earn $20 in profit?

Answers

x = container

4x - 28 = 20
4x = 20 + 28
4x /4 = 48 / 4
x = 12

You need to sell 12 containers to earn 20 dollars in profit

slove for u=vw+z to get v by its self

Answers

u = vw + z
vw = u - z
v = (u-z)/w

Which method do you prefer to use to find sums__count by tens and ones,use compatible numbers,or use friendly numbers and adjust? Explain why.

Answers

I count by tens and ones. Let me show you why with an example;

X=56+27

What is x?

To solve this equation, all you have to do is add 56 and 27. Easy. Since there are 7 tens, (5 plus 2), 7 will be in the tenths place. Like this: 7_. What will be next to it? To find this, just add the ones. 6+7=13. “Uh. Oh, 13 is bigger than ten,) you might be wondering. This problem has a simple fix. How many tens are in 13? One. You add ten to your 7, and you now have 8 in your tens place. Add the remaining three ones, and you’ve got your answer. 83.

56+27=83

X=83.

This method is easier and faster than any other method. Did you know calculators are actually programmed to use this method for simple addition? Who would’ve thought?



Let f(x) = 2x - 7 and g(x) = -6x - 3. Find f(x) + g(x) and state its domain.

Answers

2x-7+-6x-3                                                                                                             2x+-6x=-4x                                                                                                          
 -4x-10=0                                                                                                          
-5/2 is the answer  

Answer:

[tex]\( f(x) + g(x) = -4x - 10 \).[/tex]

To find the domain of [tex]\( f(x) + g(x) \)[/tex], we need to consider the values of [tex]\( x \)[/tex] for which the function is defined. Since [tex]\( f(x) \)[/tex]  and [tex]\( g(x) \)[/tex] are both linear functions, their domain is all real numbers.

So, the domain of [tex]\( f(x) + g(x) \)[/tex] is [tex]\( \mathbb{R} \)[/tex] , which means that [tex]\( x \)[/tex] can be any real number.

Explanation:

To find [tex]\( f(x) + g(x) \)[/tex] , we simply add the functions [tex]\( f(x) \) and \( g(x) \)[/tex] together:

[tex]\[ f(x) + g(x) = (2x - 7) + (-6x - 3) \][/tex]

Now, let's simplify:

[tex]\[ f(x) + g(x) = 2x - 7 - 6x - 3 \][/tex]

[tex]\[ f(x) + g(x) = (2x - 6x) + (-7 - 3) \][/tex]

[tex]\[ f(x) + g(x) = -4x - 10 \][/tex]

can a sequence be both arithmetic and geometric?

Answers

an aritmetic sequence is like this
[tex]a_n=a_1+d(n-1)[/tex] where a1=first term and d=common difference

geometric is [tex]a_n=a_1(r)^{n-1}[/tex] where a1=first term and r=common ratio


can it be both aritmetic and geometric
hmm, that means that the starting terms should be the same

therfor we need to solve [tex]d(n-1)=(r)^{n-1}[/tex]
what values of d and r make all natural numbers of n true?
are there values that make all natural numbers for n true?

when n=1, then d(1-1)=0 and r^(1-1)=1, so already they are not equal

the answer is no, a sequence cannot be both aritmetic and geometric

A sequence can be both arithmetic and geometric, and this is illustrated where terms follow both an arithmetic and geometric progression.

Yes, a sequence can be both arithmetic and geometric. An example of such a sequence is when the terms of the sequence follow both an arithmetic progression, where the difference between consecutive terms is constant, and a geometric progression, where each term after the first is found by multiplying the previous term by a fixed, non-zero number.

How many combinations of four different odd numbers whose sum is 30 can you find?

Answers

The answer is 2 combinations

carly has a soccer game every 4th day matt has a soccer game every 5th day. when will they first have a game oh the same day

Answers

On the 20th day Carly and Matt will have their soccer games on the same day.

Final answer:

To determine the first time Carly and Matt will have a soccer game on the same day, we find the least common multiple (LCM) of 4 and 5, which is 20. Thus, they will both have a game on the 20th day.

Explanation:

The question is asking when Carly, who has a soccer game every 4th day, and Matt, who has a soccer game every 5th day, will both have a game on the same day. This is a problem that can be solved using the concept of the least common multiple (LCM). The LCM of two numbers is the smallest number that is a multiple of both numbers. To find when Carly and Matt will have a soccer game on the same day, we need to find the LCM of 4 and 5.

List the multiples of 4 (4, 8, 12, 16, 20, ...) and 5 (5, 10, 15, 20, ...).

Identify the smallest multiple that is common to both lists, which would be 20.

Therefore, the first day Carly and Matt will have a game on the same day is the 20th day.

One- third of a number is five-sixths. Find the number

Answers

Our problem in word form is:
[tex] \frac{1}{3}y= \frac{5}{6} [/tex]
Multiply the denomintor by three on the left side to get that:
[tex] y=\frac{5}{6}*3 [/tex]
Solving, we get that y=15/6.

:)

Solve the inequality. Graph the solution.
z - 4.7 ≥ -1.6

Answers

z - 4.7 > = -1.6
z > = -1.6 + 4.7
z > = 3.1

closed circle on 3.1, shading to the right

** it is a closed circle because there is an equal sign in the problem...it is shaded to the right because it is greater then

The solution of the given inequality is z ≥ 3.1

The Graph of the solution of the inequality z - 4.7 ≥ -1.6 is attached below.

What is a solution set to an inequality or an equation?

If the equation or inequality contains variable terms, then there might be some values of those variables for which that equation or inequality might be true. Such values are called solution to that equation or inequality.

Given that the inequality;

z - 4.7  ≥  -1.6

Solving;

z ≥ 1.6 + 4.7

z ≥ 3.1

Therefore, The solution of the given inequality is z ≥ 3.1

The Graph of the solution of the inequality z - 4.7 ≥ -1.6 is attached below.

Learn more about inequalities here:

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What is equivalent to 5.300

Answers

Equivalent of 5.300 is 5.3

They literally are the same

hope this helps

What is the relationship between the 6s in 660, 472?

Answers

The 6 is in the hundred thousands place and ten thousands place

hope this helps

Answer:

1st 6 is 1/10 of 2nd 6 and 2nd 6 is 10 times the 2nd 6.

Step-by-step explanation:

We are asked to find the relationship between the 6s in 660,472.

Upon looking at our given number, we can see that 1st see is in 10 thousands place and 2nd 6 is in hundred thousands place.

Place value of 1st 6: 60,000

Place value of 2nd 6: 600,000

Let us compare our both numbers as:

We can see that 600,000 is 10 times greater than 60,000, therefore, 1st 6 is 1/10 of 2nd 6 and 2nd 6 is 10 times the 2nd 6.

f (1)= 7, f (n)= f (n-1) + 14

Answers

(f-7) +14

f +7 is your answer i believe

hope this helps

Evaluate –32 + (2 – 6)(10).

Answers

Final answer:

The expression –32 + (2 – 6)(10) evaluates to –72, by first calculating the operation within the parentheses, multiplying it by 10, and then adding it to –32.

Explanation:

To evaluate the expression –32 + (2 – 6)(10), we must follow the order of operations, often remembered by the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction). Firstly, we calculate the value inside the parentheses (2 – 6), which equals –4. Then we multiply this value by 10 to get –40. Finally, we add the result to –32 which gives us –32 + (–40) = –32 – 40 = –72.

Final answer:

The expression –32 + (2 – 6)(10) evaluates to –372 after performing the operations inside the parentheses and then multiplying and adding as per the order of operations.

Explanation:

To evaluate the expression –32 + (2 – 6)(10), we start by performing the operation inside the parentheses first. We subtract 6 from 2, getting –34. Then we multiply this result by 10 to get –340.

Next, we add this result to –32: –32 + (–340) = –372. So the final answer to the expression is –372.

Which conversion factors are used to multiply to 18 cm/s to get meters per minute?

Answers

18 cm/s = 18cm/s * 1m/100cm = (18/100) m/s
(notice how the units cancel out, and 1m/100cm = 1 so we're not changing anything)

(18/100) m/s = (18/100) m/s * 60s/1min (also = 1)
Therefore we get
(1080/100) m/min = 10.8 m/min
So basically 18 *60/100 m/min

Answer:

[tex]\frac{60}{100}[/tex]

Step-by-step explanation:

Here, the given expression,

18 cm per sec

That is, measure in 1 sec = 18 cm

∵ 1 minute = 60 seconds,

⇒ 1 second = [tex]\frac{1}{60}[/tex] minutes,

Also, 1 meters ( m ) = 100 centimeters ( cm ),

⇒ 1 cm = [tex]\frac{1}{100}[/tex] m,

So, the measure in [tex]\frac{1}{60}[/tex] minutes = 18× [tex]\frac{1}{100}[/tex] cm,

Thus, the measure in 1 minute = [tex]18\times \frac{60}{100}[/tex] cm

Hence, the conversion factors are used to multiply to 18 cm/s to get meters per minute is [tex]\frac{60}{100}[/tex]

Lev has 9 tens . Jim has 1 ten. They put all their tens together. Dawn puts 9 ones with the tens. What number did they make?

Answers

The answer would be 109. 9 tens is 90, and 1 ten is 10, 90+10=100 plus the 9 ones that Dawn put, 109

Lev and Jim have a total of 100 in tens, and with Dawn's 9 ones added, they make the number 109.

Lev has 9 tens which is equal to 90 (because 9 times 10 equals 90). Jim has 1 ten which is equal to 10. When they put all their tens together, we add 90 and 10 to get 100. Dawn then adds 9 ones to the tens. To find the final number, we add Dawn's 9 ones to the previously combined tens, which is adding 9 to 100, resulting in 109. Therefore, by pooling together their tens and ones, they made the number 109.

A factory produces 5−packs of pencils. To be within the weight specifications, a pack of 5 pencils should weigh between 60 grams and 95 grams. Each package has a mass of 15 grams. Enter a compound inequality to represent the mass of a single pencil in a pack. Can each pencil have a mass of 10.5 grams?

Answers


Divide the weight variance of a pack by 5, yielding
12 to 19 grams.
Then a single pencil can be between 12 < pencil < 19 grams.
Therefore each pencil cannot have a mass of 10.5 grams.

The compound inequality will be:  [tex]9\leq x\leq 16[/tex], where [tex]x[/tex] is the mass of a single pencil and each pencil can have a mass of 10.5 grams.

Explanation

Suppose, the mass of a single pencil in the pack is  [tex]x[/tex] gram.

So, the total mass of 5 pencils will be:  [tex]5x[/tex] grams.

Each package has a mass of 15 grams. So, the total weight of the pack of 5 pencils [tex]=(5x+15)[/tex] grams.

To be within the weight specifications, a pack of 5 pencils should weigh between 60 grams and 95 grams. So, the compound inequality will be..........

[tex]60\leq 5x+15\leq 95\\ \\ 60-15\leq 5x+15-15\leq 95-15\\ \\ 45\leq 5x\leq 80\\ \\ \frac{45}{5}\leq \frac{5x}{5}\leq \frac{80}{5}\\ \\ 9\leq x\leq 16[/tex]

So, the compound inequality to represent the mass of a single pencil in a pack will be:  [tex]9\leq x\leq 16[/tex], where [tex]x[/tex] is the mass of a single pencil.


As 10.5 grams lies inside the interval [tex]9\leq x\leq 16[/tex] , so each pencil can have a mass of 10.5 grams.

which of the following inequality has solution set

Answers

I4Ix-3 has a solution set.

The manager at Jessica's Furniture Store is trying to figure out how much to charge for a couch that just arrived. If the couch was bought at a wholesale price of $113.00 and Jessica's Furniture Store marks up all furniture by 45%, at what price should the manager sell the couch?

Answers

the couch would be 163.85

Answer: The manager sold the couch at $163.85.

Step-by-step explanation:

Since we have given that

Wholesale price of the couch = $113.00

If Jessica's Furniture Store marks up all furniture by 45%.

So, Increment in whole sale price is given by

[tex]\frac{45}{100}\times 113\\\\=\frac{5085}{100}\\\\=\$50.85[/tex]

So, the manager sold the couch at the price is given by

[tex]\$113.00+\$50.85\\\\=\$163.85[/tex]

Hence, the manager sold the couch at $163.85.

X2 -2x + 1= 0. Solve the equation using the quadratic formula. Then solve the equation by factoring to check your solutions

Answers

using the formula  x = [-(-2) +/- sqrt((-2)^2 - 4*1*1)] /  2

=  2 +/- sqrt 0
    --------------     = 2/2  = 1
           2

The solution is x = 1  Duplicity 2

Factoring we have (x - 1)(x - 1)  = 0  which  is x = 1 Duplicity 2

The solutions to the given quadratic equation are x=1 and x=1.

The given quadratic equation is x²-2x+1=0.

The roots of a quadratic equation ax² + bx + c = 0 are given by x = [-b ± √(b² - 4ac)]/2a.

Here, a=1, b=-2 and c=1

Now, x = [2 ± √(4 - 4)]/2

x=2±0/2

x=1

With factoring, we get

x²-2x+1=0

x²-x-x+1=0

x(x-1)-1(x-1)=0

(x-1)(x-1)=0

(x-1)=0

x=1

Therefore, the solutions to the given quadratic equation are x=1 and x=1.

To learn more about the quadratic formula visit:

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Complete the equation below by writing an equation equivalent to height h of a cylinder

Answers

formula for the volume of a cylinder V = πr2h Divide both sides by πr2 to isolate h. V / πr2 = πr2h / πr2 You find the height, h, is equal to . V / πr2 = h H = V / πr2

Shelia has to pack 128 baskets of apples. She had packed 1/4 of the baskets. How many baskets are left for her to pack?

Answers

1/4 of 128 is 32,
32 x 3 = 96

There are 96 baskets left.

What is the equation in point slope form of the line passing through (4,0) and (2,6)

Answers

To answer this question, we first need to find the slope. We can do this using the equation (y2 - y1)/(x2 - x1) and substitute in our coordinates. This would give:
(6 - 0)/(2 - 4) = 6/-2 = -3

Now we know that the x term is -3, we need to find the y-intercept. To do this, we simply substitute our coordinates into y = mx + c, along with our x term:

6 = (2 × -3) + c
6 = -6 + c
+ 6
12 = c

So your final answer is y = -3x + 12, which would be the third option of y = -3(x - 4)

I hope this helps! Let me know if you want any further explanation :)

40.8 gallons of paint among 8 containers

Answers

divide the two

40.8 / 8 = 5.1 gallons per container

(b) we often read that iq scores for large populations are centered at 100. what percent of these 78 students have scores above 100? (round your answer to one decimal place.)

Answers

Final answer:

IQ scores follow a bell curve distribution where 100 is the mean. About 50% of people score above 100. Therefore, in a group of 78 students, we would expect about 39 students to have IQ scores above 100.

Explanation:

The question is asking to determine what percent of 78 students in a population have IQ scores above a 100. Given that the IQ scores in large populations are centered at 100 and follow a bell curve, most people fall within the range of 85 to 115. The percentage of people who score above 100 is the same as those who score below it - about 50%.

According to the nature of a bell curve, approximately 34% of people score between 100 and 115, and about 14% score above 115. Therefore, around 50% (34% + 14%) of the people score above 100.

Applying this percentage to the population of the 78 students, we would expect about 50% of this student population to have scores above 100. So, 50% of 78 students amounts to 39 students. Rounded off to one decimal place, the answer would be 39.0 students. However, students can't be divided, so we conclude that about 39 students from the group of 78 have IQ scores above 100.

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Prime factorization practice all factors 1.- 25 2.- 49 3.- 7 4.- 13 5.- 24 6.- 48 7.- 168

Answers

Do u still need the answer

Six less than the product of 9 and a number is equal to 4

Answers

9x - 6 = 4

9x = 4 + 6

9x/9 = 10/9

x = 10/9

hope this helps
if you're searching for the equation, then: 9x - 6 = 4

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