Answer:
See explaination
Explanation:
package miscellaneous;
import java.text.NumberFormat;
import java.util.Currency;
import java.util.Locale;
public class sales {
public static void main(String[] args) {
double[][] sales= {
{1540.0,2010.0,2450.0,1845.0},//region1
{1130.0,1168.0,1847.0,1491.0},//region2
{1580.0,2305.0,2710.0,1284.0},//region3
{1105.0,4102.0,2391.0,1576.0}};//region4
//object for NumberFormat class
//needed in $
NumberFormat defaultFormat = NumberFormat.getCurrencyInstance(java.util.Locale.US);
System.out.println("The sales report application: ");
//the j(th) element in i(th) row in sales matrix contains sales value for
//sales in j(th) quarter
System.out.println("Sales by quarter: ");
System.out.println("Region\tQ1\t\tQ2\t\tQ3\t\tQ4");
for(int i=0;i<sales.length;i++) {
System.out.print(i+1+"\t");
for(int j=0;j<sales[i].length;j++) {
System.out.print(defaultFormat.format(sales[i][j])+"\t");
}
System.out.println();
}
//i(th) row in the matrix has sales for i(th) region
System.out.println("Sales by region: \n");
for(int i=0;i<sales.length;i++) {
System.out.print("Region "+(i+1)+":");
double region_sale=0;
for(int j=0;j<sales[i].length;j++) {
region_sale+=sales[i][j];
}
System.out.println(defaultFormat.format(region_sale));
}
System.out.println("\nSales by Quarter: \n");
//we have quarters so for adding up their sales we need 4 variables
double q1=0;
double q2=0;
double q3=0;
double q4=0;
for(int i=0;i<sales.length;i++) {
for(int j=0;j<sales[i].length;j++) {
//j=0 implies the sales data for first quarter
if(j==0) {
q1+=sales[i][j];
}
//j=1 implies the sales data for second quarter
if(j==1) {
q2+=sales[i][j];
}
//j=2 implies the sales data for third quarter
if(j==2) {
q3+=sales[i][j];
}
//j=3 implies the sales data for fourth quarter
if(j==3) {
q4+=sales[i][j];
}
}
}
System.out.println("Q1: "+defaultFormat.format(q1));
System.out.println("Q2: "+defaultFormat.format(q2));
System.out.println("Q3: "+defaultFormat.format(q3));
System.out.println("Q4: "+defaultFormat.format(q4));
//with the help of 2 loops every sales data
//in the matrix can be accessed, which can be added
//to total_sales variable
double total_sales=0;
for(int i=0;i<sales.length;i++) {
for(int j=0;j<sales[i].length;j++) {
total_sales+=sales[i][j];
}
}
System.out.println("\nTotal Sales: "+defaultFormat.format(total_sales));
}
}
1. In a language with zero-based indexing, at what index will the 100th item in an array be?
2. Same as 1.1, but for a language with one-based indexing.
The 100th item in an array would be at index 99 in a zero-based indexing language and at index 100 in a one-based indexing language. Indexing helps in accessing elements within data structures like arrays.
In a language with zero-based indexing, such as Python or Java, the 100th item in an array would be at index 99. This is because the first item in an array is at index 0, and the index increases by 1 for each subsequent item. Therefore, the index can be found by subtracting one from the item number (i.e., 100 - 1 = 99).
For a language with one-based indexing, like MATLAB or R, the 100th item would be at index 100 because the indexing starts from 1. Here, the index of the 100th item is the same as the item number.
Understanding the concept of array indexing is vital as it helps in accessing the elements in the data structure efficiently. The for loop can be set up with different starting indices and conditions depending on the language's indexing convention. For example, you might initialize the index i with 0 or 1, and the loop could run while i < 101 for zero-based or i <= 100 for one-based indexing.
Homework assignment number 13 Binary search trees have their best performance when they are balanced, which means that at each noden, the size of the left subtree of n is within one of the size of the right subtree of n. Write a program thatwill take an array of generic values that are in sorted order in the array, create a binary search tree, and put the values in the array into the tree. Your binary search tree should be complete ("complete" as defined in chapter 24). Or put another way, it should have the fewest number of levels and still be "complete".Use the following array: "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M","N".Remember, your code is to handle generic data types, not just strings. So while I want you to use the specified array of strings, your program should work if I choose to use an array of Integers, or Characters. Printout the values from the tree (not the array) in a tree fashion so that I can readily see the tree structure, something like this:HD LBFJN A C EGIK M-Name the file that contains the main method TreeDriver.ja
Answer:
See explaination for the program code
Explanation:
Code below:
package trees;
import java.util.NoSuchElementException;
public class TreeDriver<T extends Comparable<? super T>> {
private Entry<T> root;
publicTreeDriver() {
root = null;
}
public static<T extends Comparable<? super T>>TreeDriver<T> createTestTree() {
return newTreeDriver<T>();
}
public void insert(T value) {
root = insert(value, root);
}
public void remove(T value) {
root = remove(value, root);
}
public boolean contains(T value) {
return valueOf(find(value, root)) != null;
}
private T valueOf(Entry<T> entry) {
return entry == null ? null : entry.element;
}
private Entry<T> insert(T value, Entry<T> entry) {
if (entry == null)
entry = new Entry<T>(value);
else if (value.compareTo(entry.element) < 0)
entry.left = insert(value, entry.left);
else if (value.compareTo(entry.element) > 0)
entry.right = insert(value, entry.right);
else
throw new RuntimeException("Duplicate Entry : " + value.toString());
return entry;
}
private Entry<T> remove(T value, Entry<T> entry) {
if (entry == null)
throw new NoSuchElementException("Entry not found : " + value.toString());
if (value.compareTo(entry.element) < 0)
entry.left = remove(value, entry.left);
else if (value.compareTo(entry.element) > 0)
entry.right = remove(value, entry.right);
else {
// Entry found.
if (entry.left != null && entry.right != null) {
// Replace with in-order successor (the left-most child of the right subtree)
entry.element = findMin(entry.right).element;
entry.right = removeInorderSuccessor(entry.right);
// Replace with in-order predecessor (the right-most child of the left subtree)
// entry.element = findMax(entry.left).element;
// entry.left = removeInorderPredecessor(entry.left);
} else
entry = (entry.left != null) ? entry.left : entry.right;
}
return entry;
}
private Entry<T> removeInorderSuccessor(Entry<T> entry) {
if (entry == null)
throw new NoSuchElementException();
else if (entry.left != null) {
entry.left = removeInorderSuccessor(entry.left);
return entry;
} else
return entry.right;
}
private Entry<T> removeInorderPredecessor(Entry<T> entry) {
if (entry == null)
throw new NoSuchElementException();
else if (entry.right != null) {
entry.right = removeInorderPredecessor(entry.right);
return entry;
} else
return entry.left;
}
private Entry<T> findMin(Entry<T> entry) {
if (entry != null)
while (entry.left != null)
entry = entry.left;
return entry;
}
private Entry<T> findMax(Entry<T> entry) {
if (entry != null)
while (entry.right != null)
entry = entry.right;
return entry;
}
private Entry<T> find(T value, Entry<T> entry) {
while (entry != null) {
if (value.compareTo(entry.element) < 0)
entry = entry.left;
else if (value.compareTo(entry.element) > 0)
entry = entry.right;
else
return entry;
}
return null;
}
private void printInOrder(Entry<T> entry) {
if (entry != null) {
printInOrder(entry.left);
System.out.println(entry.element);
printInOrder(entry.right);
}
}
public void printInOrder() {
printInOrder(root);
}
private static class Entry<T extends Comparable<? super T>> {
T element;
Entry<T> left;
Entry<T> right;
Entry(T theElement) {
element = theElement;
left = right = null;
}
}
private static class Test implements Comparable<Test> {
private String value;
public Test(String value) {
this.value = value;
}
public String toString() {
return value;
}
atOverride // Replace the at with at symbol
public int compareTo(Test o) {
return this.value.compareTo(o.toString());
}
}
private static class Test1 extends Test {
public Test1(String value) {
super(value);
}
}
public static vo id main(String[] args) {
TreeDriver<Test> tree =TreeDriver.createTestTree();
int size = 20;
for (int i = 0; i <= size; i++) {
tree.insert(new Test1(String.valueOf(i)));
}
tree.insert(new Test1("100"));
tree.remove(new Test1("10"));
tree.remove(new Test1(String.valueOf(15)));
tree.remove(new Test1(String.valueOf(20)));
tree.printInOrder();
System.out.println("Contains (10) : " + tree.contains(new Test1("10")));
System.out.println("Contains (11) : " + tree.contains(new Test1(String.valueOf(11))));
}
}
Final answer:
To create a balanced binary search tree from a sorted array, you can use a recursive approach. Here is an example Java code that can be used as a starting point. The code creates a balanced binary search tree by selecting the middle element as the current node and calling the createBalancedBST method on the left and right subarrays.
Explanation:
In order to create a balanced binary search tree from a sorted array, you can use a recursive approach. Here is an example Java code that can be used as a starting point:
import java.util.ArrayList;
class Node<T> {
Node<T> left;
Node<T> right;
T value;
Node(T value) {
this.value = value;
this.left = null;
this.right = null;
}
}
public class TreeDriver<T extends Comparable<T>> {
Node<T> root;
TreeDriver() {
this.root = null;
}
private Node<T> createBalancedBST(T[] arr, int start, int end) {
if (start > end)
return null;
int mid = (start + end) / 2;
Node<T> node = new Node<>(arr[mid]);
node.left = createBalancedBST(arr, start, mid - 1);
node.right = createBalancedBST(arr, mid + 1, end);
return node;
}
private void inOrderTraversal(Node<T> node) {
if (node == null)
return;
inOrderTraversal(node.left);
System.out.print(node.value + " ");
inOrderTraversal(node.right);
}
public void createAndPrintBalancedBST(T[] arr) {
this.root = createBalancedBST(arr, 0, arr.length - 1);
inOrderTraversal(this.root);
}
public static void main(String[] args) {
TreeDriver<String> tree = new TreeDriver<>();
String[] arr = {"A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M","N"};
tree.createAndPrintBalancedBST(arr);
}
}
The createBalancedBST method takes an array arr, a start index, and an end index. It recursively creates a balanced binary search tree by selecting the middle element as the current node and calling the createBalancedBST method on the left and right subarrays.
The inOrderTraversal method is used to print the values of the created BST in order.
This is a program that calculates information about orders of shirts and pants. All orders have a quantity and a color. Write a Clothing class that matches this UML: The no-argument constructor will set the quantity to zero and the color to the empty string. The calculatePrice() method returns 0.0. The two-argument constructor and the setQuantity() method must ensure that the quantity will be greater than or equal to zero. Hint: use Math.abs()
Answer:
Check the explanation
Explanation:
// Clothing.java
public class Clothing {
//Declaring instance variables
private int quantity;
private String color;
//Zero argumented constructor
public Clothing() {
this.quantity = 0;
this.color = "";
}
//Parameterized constructor
public Clothing(int quantity, String color) {
this.quantity = quantity;
this.color = color;
}
// getters and setters
public int getQuantity() {
return quantity;
}
public void setQuantity(int quantity) {
this.quantity = quantity;
}
public String getColor() {
return color;
}
public void setColor(String color) {
this.color = color;
}
public double calculatePrice()
{
return 0.0;
}
}
_____________________________
// Pants.java
public class Pants extends Clothing {
//Declaring instance variables
private int waist;
private int inseam;
//Zero argumented constructor
public Pants() {
this.waist = 0;
this.inseam = 0;
}
//Parameterized constructor
public Pants(int quantity, String color, int waist, int inseam) {
super(quantity, color);
setWaist(waist);
setInseam(inseam);
}
// getters and setters
public int getWaist() {
return waist;
}
public void setWaist(int waist) {
if (waist > 0)
this.waist = waist;
}
public int getInseam() {
return inseam;
}
public void setInseam(int inseam) {
if (inseam > 0)
this.inseam = inseam;
}
public double calculatePrice() {
double tot = 0;
if (waist > 48 || inseam > 36) {
tot = 65.50;
} else {
tot = 50.0;
}
return tot;
}
}
__________________________
// Shirt.java
public class Shirt extends Clothing {
//Declaring instance variables
private String size;
//Zero argumented constructor
public Shirt() {
this.size = "";
}
//Parameterized constructor
public Shirt(int quantity, String color, String size) {
super(quantity, color);
this.size = size;
}
// getters and setters
public String getSize() {
return size;
}
public void setSize(String size) {
this.size = size;
}
public double calculatePrice() {
double tot = 0;
if (size.equalsIgnoreCase("S")) {
tot = getQuantity() * 11.00;
} else if (size.equalsIgnoreCase("M")) {
tot = getQuantity() * 12.50;
} else if (size.equalsIgnoreCase("L")) {
tot = getQuantity() * 15.00;
} else if (size.equalsIgnoreCase("XL")) {
tot = getQuantity() * 16.50;
} else if (size.equalsIgnoreCase("XXL")) {
tot = getQuantity() * 18.50;
}
return tot;
}
}
___________________________
//Test.java
import java.util.ArrayList;
public class Test {
public static void main(String[] args) {
int totShirts=0,totPants=0;
double sprice=0,pprice=0,totWaist=0,totinseam=0,avgWaist=0,avginseam=0;
int cnt=0;
ArrayList<Clothing> clothes=new ArrayList<Clothing>();
Shirt s=new Shirt(8,"Green","XXL");
Pants p1=new Pants(6,"Brown",48,30);
Pants p2=new Pants(4,"Blue",36,34);
clothes.add(s);
clothes.add(p1);
clothes.add(p2);
for(int i=0;i<clothes.size();i++)
{
if(clothes.get(i) instanceof Shirt)
{
Shirt s1=(Shirt)clothes.get(i);
totShirts+=s1.getQuantity();
sprice+=s1.calculatePrice();
}
else if(clothes.get(i) instanceof Pants)
{
Pants pa=(Pants)clothes.get(i);
totPants+=pa.getQuantity();
pprice+=pa.calculatePrice();
totinseam+=pa.getInseam();
totWaist+=pa.getWaist();
cnt++;
}
}
System.out.println("Total number of shirts :"+totShirts);
System.out.println("Total price of Shirts :"+sprice);
System.out.println("Total number of Pants :"+totPants);
System.out.println("Total price of Pants :"+pprice);
System.out.printf("Average waist size is :%.1f\n",totWaist/cnt);
System.out.printf("Average inseam length is :%.1f\n",totinseam/cnt);
}
}
_________________________
Output:
Total number of shirts :8
Total price of Shirts :148.0
Total number of Pants :10
Total price of Pants :100.0
Average waist size is :42.0
Average inseam length is :32.0
Create a script that internally calls the Linux command 'ps aux' and saves the output to a file named unprocessed.txt (you do not need to append to an existing file, if a file already exists, simply overwrite it). The program should pause and display the following message to the screen: Press 'q' to exit or 'ctrl-c' to process the file and exit' If the user presses 'q', exit the program leaving the filename on the disk as 'unprocessed.txt'. If the user presses 'ctrl-c', then catch the signal (hint - covered in chapter 16) and rename the file to 'processed.txt' and then exit. You must build a signal handler to catch the ctrl-c signal and rename the file. g
Answer:
see explaination
Explanation:
SIG{INT} = sub {
`mv unprocessed.txt processed.txt`;
print "\n";
exit;
};
`ps aux > unprocessed.txt`;
print "Press 'q' to exit or 'ctrl-c' to process the file and exit:\n";
$inp = <>;
if ($inp == 'q')
{
exit;
}
Let's now use our new calculator functions to do some calculations!
A. Add the square of 3 to the square root of 9 Save the result to a variable called calc_a
B. Subtract the division of 12 by 3 from the the multiplication of 2 and 4 Save the result to a variable called calc_b
C. Multiply the square root of 16 by the sum of 7 and 9 Save the result to a variable called calc_c
D. Divide the square of 7 by the square root of 49 Save the result to a variable called calc_d
Answer:
Ans1.
double calc_a;
calc_a=Math.pow(3.0,2.0)+Math.sqrt(9);
Ans2.
double calc_b;
calc_b=((12.0/3.0)-(2.0*4.0));
Ans 3.
double calc_c;
calc_c=(Math.sqrt(16.0)*(7.0+9.0));
Ans 4.
double calc_d;
calc_d=Math.pow(7.0,2.0)/Math.sqrt(49.0);
Explanation:
The expressions are done with Java in answer above.
To solve these calculations, we can use mathematical functions on a calculator.
Explanation:To solve these calculations, we can use the mathematical functions on a calculator.
Calculation A:
To add the square of 3 to the square root of 9, we can write it as follows:
calc_a = [tex]3^2 + sqrt(9)[/tex]
calc_a = 9 + 3
calc_a = 12
Calculation B:
To subtract the division of 12 by 3 from the multiplication of 2 and 4, we can write it as follows:
calc_b = (2 * 4) - (12 / 3)
calc_b = 8 - 4
calc_b = 4
Calculation C:
To multiply the square root of 16 by the sum of 7 and 9, we can write it as follows:
calc_c = sqrt(16) * (7 + 9)
calc_c = 4 * 16
calc_c = 64
Calculation D:
To divide the square of 7 by the square root of 49, we can write it as follows:
calc_d = [tex](7^2) / sqrt(49)[/tex]
calc_d = 49 / 7
calc_d = 7
A mother calls you to report that her 15-year-old daughter has run away from home. She has access to her daughter's e-mail account and says her daughter has a number of emails in her inbox suggesting she has run away to be with a 35-year-old woman. Write a 2 to 3 page paper/report (not including title or reference page) explaining how you should proceed. Make sure you adhere to the grading rubric and write the report in APA format.
Answer: Wait, you're asking strangers to write a report for you? Just use common sense--tell her to forward the emails to the police department, or to provide the login details or the IPv4 logs (depending on the email service) to work off of. Considering that she most likely has the email linked to her phone, you should get into contact with her phone provider to locate the daughter. I don't know what else to say considering that you're asking strangers for an essay to be written for you. Hopefully what I said helps, but I doubt that anyone's going to write a full two page essay.
APA offers authors a dependable structure they can use each time they write. Authors' arguments or research are more effectively organized when they are consistent.
What are advantages to write issue in APA format?The APA format helps papers on usually complex issues to be more understandable. It makes reading and understanding papers easier.
Utilize common sense and instruct her to transmit the emails to the police department, or, depending on the email service, to supply the login information or the IPv4 logs for investigators to use.
You should get in touch with her phone provider to find the daughter because she almost certainly has the email connected to her phone.
Therefore, I don't know what else to say, considering that you're asking strangers for an essay to be written for you.
Learn more about APA format here:
https://brainly.com/question/12548905
#SPJ2
Write a function so that the main program below can be replaced by the simpler code that calls function mph_and_minutes_to_miles(). Original main program: miles_per_hour = float(input()) minutes_traveled = float(input()) hours_traveled = minutes_traveled / 60.0 miles_traveled = hours_traveled * miles_per_hour print('Miles: {:f}'.format(miles_traveled))
Answer:
def mph_and_minutes_to_miles():
miles_per_hour = float(input())
minutes_traveled = float(input())
hours_traveled = minutes_traveled / 60.0
miles_traveled = hours_traveled * miles_per_hour
print('Miles: {:f}'.format(miles_traveled))
mph_and_minutes_to_miles()
Explanation:
Create a function called mph_and_minutes_to_miles that takes no parameter
Get the code from the main part and put them inside the function
Call the function as requested
Answer:
Check the explanation
Explanation:
Solution(Simplified main code):
# Function written to simplify main code
def mph_and_minutes_to_miles(miles_per_hour, minutes_traveled):
hours_traveled = minutes_traveled / 60.0
miles_traveled = hours_traveled * miles_per_hour
return miles_traveled
miles_per_hour = float(input())
minutes_traveled = float(input())
print('Miles: %f' % mph_and_minutes_to_miles(miles_per_hour, minutes_traveled))
Kindly check the attached image below for the code screenshot and output.
Priscilla is providing the junior analysts in her firm with some real-world illustrations to explain some of the recommendations that they must be prepared to make to clients, based on what they have studied in their coursework, in order to solidify their understanding. Which is a reason Priscilla will share with the new analysts for recommending that a client purchase a software package?
Options:
a) The client wants to develop internal resources and capabilities
b) The client is looking for the lowest possible costs
c) The client has unique business requirement that must be satisfied by this software application
d) The client has some existing technology in place whose requirements must be met by the new software
Answer:
d) The client has some existing technology in place whose requirements must be met by the new software
Explanation:
For a client to purchase a software, the client has an already existing technology that requires that software for adequate functioning. The analyst will recommend the new software to the client based on the technology he/she previously has and the requirements he wants to meet.
The other options are not impossible, but they are not the primary reason why the software will be purchased, the overall aim for all the company's activities may be to develop internal resources and capabilities or to meet some unique business requirements, but these are secondary. The primary purpose is that the client has a technology that cannot function properly without the recommended software.
For the preceding simple implementation, this execution order would be nonideal for the input matrix; however, applying a loop interchange optimization would create a nonideal order for the output matrix. Because loop interchange is not sufficient to improve its performance, it must be blocked instead. (a) What should be the minimum size of the cache to take advantage of blocked execution
Answer:
hi your question lacks the necessary matrices attached to the answer is the complete question
1024 bytes
Explanation:
A) The minimum size of the cache to take advantage of blocked execution
The minimum size of the cache is approximately 1 kilo bytes
There are 128 elements( 64 * 2 ) in the preceding simple implementation and this because there are two matrices and every matrix contains 64 elements .
note: 8 bytes is been occupied by every element therefore the minimum size of the cache to take advantage of blocked execution
= number of elements * number of bytes
= 128 * 8 = 1024 bytes ≈ 1 kilobytes
Write a program that encodes English-language phrases into pig Latin. To translate an English word into a pig Latin word, place the first letter of the English word at the end of word and add "ay". For example, "dog" would become "ogday" and cat would become "atcay". Your program should prompt the user to enter an English sentence and then print the sentence with every word changed to pig Latin. (One way to do this would be to split the sentence into words with the split() method.) For simplicity, there will be no punctuation in the sentences. This is sample run of your program: Enter·a·string·to·be·translated:the·fox·jumps·over·the·lazy·dog↵ hetay·oxfay·umpsjay·veroay·hetay·azylay·ogday↵
Answer:
Explanation:
PiLatinWithMultipleWords.java
import java.util.Scanner;
public class PiLatinWithMultipleWords {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.print("Enter a string to be translated: ");
String s = scan.nextLine();
String words[] = s.split("\\s+");
for(String word: words){
System.out.print(pigLatin(word)+" ");
}
System.out.println();
}
public static String pigLatin (String s){
s = s.toLowerCase();
s = s.substring(1,s.length())+ s.charAt(0) + "ay";
return s;
}
}
Output
Enter a string to be translated: the fox jumps over the lazy dog
hetay oxfay umpsjay veroay hetay azylay ogday
can someone please help i have no idea what’s going on in this code
Explanation:
The first 3 lines of code tell the user to input a 5 digit number (ex. 72,910) or a 1 digit number (ex. 3). The next 5 lines of code determine if it is a 5/1 digit number or not. If it is, it prints "Success!". The rest of the code just tells that if it's not a 5/1 digit number, and if it's not, it gives errors and tells the user to try again.
Hope this helps!
You're helping Professor Joy to calculate the grades for his course. The way his course is organised, students take two exams and their final grade is the weighted average of the two scores, where their lowest score weights 70% and their highest score 30%. To accomplish this, you are going to need to do the following: (1) Build the Student named tuple with the following attributes: name (string) exam1 (float) exam2 (float) (2) Write a function create_student, which will ask the user to input a single student's name, exam 1 score, and exam 2 score. The function will then create a named tuple with this information and return it. (3) Write a function create_class, which an integer n as a parameter, and calls create_student n times and returns a list with the n students created. (4) Write a function calculate_score, which takes a single Student named tuple as a parameter, and returns the final score, where their lowest grade is weighted 70% and their highest grade is weighted 30%.
Answer:
see explaination
Explanation:
# importing "collections" for namedtuple()
from collections import namedtuple
# function creates student records and return the named tuple
def create_student():
Student = namedtuple('Student',['name','exam1','exam2']) # creating the object Student
# taking input the name and scores of the students
name = input()
exam1 = float(input())
exam2 = float(input())
return Student(name, exam1, exam2) # return the named tuple
# function creates list of student records and return it
def create_class(n):
student_list = []
# creating student data for n students
for i in range(n):
student_list.append(create_student()) # storing data in the student_list
return student_list # return the student data i.e. student_list
# function calculates the final score of each student and returns it
def calculate_score(S):
final_score = 0
if S[1] > S[2]: # if exam1 score is greater than exam2
final_score = S[1] * 0.3 + S[2] * 0.7 # final score is sum of 30% of exam1 and 70% exam2
elif S[1] < S[2]: # if exam2 score is greater than exam1
final_score = S[1] * 0.7 + S[2] * 0.3 # final score is sum of 30% of exam2 and 70% exam1
elif S[1] == S[2]: # if both scores are equal
final_score = S[1] # final score is sum if 30% of exam1 and 70% exam2, but here both scores are equal so final score is equal to any one of the score
else: # if scores are invalid
print('Invalid entries')
return final_score # return final score
# driver function
def main():
n = int(input()) # enter the no. of students in class
if n < 1: # if n is less than 1 return nothing and stop execution
return
student_list = create_class(n) # call create_class to create class of n students
for i in student_list:
print(round(calculate_score(i), 2)) # calculate the final score for each student and print it
if __name__ == "__main__": main()
The arrays list1 and list2 are identical if they have the same contents. Write a method that returns true if list1 and list2 are identical, using the following header: public static boolean equals (int[] list1, int[] list2) Write a test program that prompts the user to enter two lists of integers and displays whether the two are identical. Here are some sample runs. Note that the first number in the input indicates the number of the elements in the list. This number is not part of the list.
Answer:
See Explaination
Explanation:
import java.util.Arrays;
/**
*
* atauthor xxxx //replace at with the at symbol
*/
public class Test {
public static void main(String[] args) {
java.util.Scanner input = new java.util.Scanner(System.in);
// Enter values for list1
System.out.print("Enter list1: ");
int size1 = input.nextInt();
int[] list1 = new int[size1];
for (int i = 0; i < list1.length; i++)
list1[i] = input.nextInt();
// Enter values for list2
System.out.print("Enter list2: ");
int size2 = input.nextInt();
int[] list2 = new int[size2];
for (int i = 0; i < list2.length; i++)
list2[i] = input.nextInt();
if (equal(list1, list2)) {
System.out.println("Two lists are identical");
}
else {
System.out.println("Two lists are not identical");
}
}
public static boolean equal(int[] list1, int[] list2) {
if(list1.length == list2.length)
Arrays.sort(list1);
return true;
else
Arrays.sort(list2);
return false;
// Hint: (1) first check if the two have the same size.
// (2) Sort list1 and list2 using the sort method.
// (3) Compare the corresponding elements from list1 and list2.
// return false, if not match. Return true if all matches.
}
}
A computer company has $3840000 in research and development costs. Before accounting for these costs, the net income of the company is $2580000. What is the amount of net income or loss before taxes after these research and development costs are accounted for?
Answer:
The answer is "loss of 1,260,000"
Explanation:
Following are the important points of the question:
The cost of research and development is = $3840000
net income of the company is= $2580000
Find: loss or profit .
According to the rate of the cost, the company cost is higher than the company rate. So, the company goes in loss stage, then
Loss = total cost - net income
Loss = $3840000 - $2580000
Loss= $ 1,260,000
The computer company would face a net loss of $1,260,000.
The question is asking about the calculation of net income or loss for a computer company after accounting for research and development costs. To determine the net income or loss, we subtract the research and development (R&D) costs from the company's income before these costs are accounted for.
So, if the net income before R&D costs is $2,580,000 and the R&D costs are $3,840,000, we perform the following calculation:
Net Income after R&D = Net Income before R&D - R&D costs
Net Income after R&D = $2,580,000 - $3,840,000
Net Income after R&D = -$1,260,000
This result is a net loss of $1,260,000 after accounting for R&D costs.
The partners of a small architectural firm are constantly busy with evolving client requirements. To meet the needs of their clients, the architects must visit several job sites per day. To share and send sensitive project/client information back to the office or with clients, the employees dial into the IPSec-based VPN remotely. For classified proprietary information, two separate extranets were set up with partners in the engineering firm on a server housed inside the office.
What firewall setup would provide the firm both flexibility and security? Justify your response.
Answer:
Check the explanation
Explanation:
IPSec-based VPN is configured in two different modes namely
IPSec Tunnel mode and IPSec Transport mode so here we are using IPsec transport mode which is used for end to end communications between a client and a server in this original IP header is remain intact except the IP protocol field is changed and the original protocol field value is saved in the IPSec trailer to be restored when the packet is decrypted on the other side due to this arrangement you need to use application based firewall because there are certain specific rules that can address the particular field (explained above-change in IP protocol field) which at the other end need to be same so at the type of decryption, original IP protocol field can be matched.
Write a method printShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, print "Too few.". If more than 4, print "Too many.". Else, print "N: Lather and rinse." numCycles times, where N is the cycle number, followed by "Done.". End with a newline. Example output with input 2: 1: Lather and rinse. 2: Lather and rinse. Done. Hint: Declare and use a loop variable. import java.util.Scanner; public class ShampooMethod { /* Your solution goes here */ public static void main (String [] args) { Scanner scnr = new Scanner(System.in); int userCycles; userCycles = scnr.nextInt(); printShampooInstructions(userCycles); } }
Answer:
import java.util.Scanner;
public class nu3 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter number of cycles");
int numCycles = in.nextInt();
//Call the method
printShampooInstructions(numCycles);
}
public static void printShampooInstructions(int numCycles){
if (numCycles<1){
System.out.println("Too few");
}
if (numCycles>4){
System.out.println("Too Many");
}
else {
for (int i = 1;i <= numCycles; i++) {
System.out.println( numCycles+ ": Lather and rinse");
numCycles--;
}
System.out.println(" Done");
}
}
}
Explanation:
This is solved using Java programming language
The method printShampooInstructions() is in bold in the answer section
I have also provided a complete program that request user to enter value for number of cycles, calls the method and passes that value to it
The logic here is using if .... else statements to handle the different possible values of Number of cycles.
In the Else Section a loop is used to decrementally print the number of cycles
Write a function to reverse a given string. The parameter to the function is a string. Function should store the reverse of the given string in the same string array that was passed as parameter. Note you cannot use any other array or string. You are allowed to use a temporary character variable. Define the header of the function properly. The calling function (in main()) expects the argument to the reverse function will contain the reverse of the string after the reverse function is executed.
Answer:
Following are the program to this question:
#include <iostream> //defining header file
using namespace std;
void reverse (string a) //defining method reverse
{
for (int i=a.length()-1; i>=0; i--) //defining loop that reverse string value
{
cout << a[i]; //print reverse value
}
}
int main() //defining main method
{
string name; // defining string variable
cout << "Enter any value: "; //print message
getline(cin, name); //input value by using getline method
reverse(name); //calling reverse method
return 0;
}
Output:
Enter any value: ABCD
DCBA
Explanation:
In the above program code, a reverse method is declared, that accepts a string variable "a" in its arguments, inside the method a for loop is declared, that uses an integer variable "i", in which it counts string value length by using length method and reverse string value, and prints its value.
In the main method, a string variable "name" is declared, which uses the getline method. This method is the inbuilt method, which is used to input value from the user, and in this, we pass the input value in the reverse method and call it.Scott wants to make sure his current power supply has enough power to run his new system.
How will Scott determine whether his current power supply has enough power to run the new system?
Answer:
The correct answer to the following question will be "Wattage ".
Explanation:
The quantity of power needed for the operation of such an electrical system seems to be a Wattage.
The wattage means every device has the highest usable wattage. Remember, furthermore, that perhaps the PSU extracts Electrical energy from either the socket of the panel, transforms it to any other Voltage level, as well as supplies it to your device.By that same Scott determines for certain if his current supply voltage has sufficient energy to function the new program or system.Write a program that opens two text files and reads their contents into two separate queues. The program should then determine whether the files are identical by comparing the characters in the queues. When two nonidentical characters are encountered, the program should display a message indicating that the files are not the same. If both queues contain the same set of characters, a message should be displayed indicating that the files are identical.
Answer:
The program in cpp for the given scenario is shown below.
#include <stdio.h>
#include <iostream>
#include <fstream>
#include <queue>
using namespace std;
int main()
{
//object created of file stream
ofstream out, out1;
//file opened for writing
out.open("words.txt");
out1.open("word.txt");
//queues declared for two files
queue<string> first, second;
//string variables declared to read from file
string s1, s2;
//object created of file stream
ifstream one("words.txt");
ifstream two("word.txt");
//first file read into the que
while (getline(one, s1)) {
first.push(s1);
}
//second file read into the queue
while (getline(two, s2)) {
second.push(s2);
}
//both files compared
if(first!=second)
cout<<"files are not the same"<<endl;
else
cout<<"files are identical"<<endl;
//file closed
out.close();
return 0;
}
OUTPUT:
files are identical
Explanation:
1. The object of the file output stream are created for both the files.
2. The two files are opened using the objects created in step 1.
3. The objects of the file input stream are created for both the files.
4. The queues are declared for both the files.
5. Two string variables are declared.
6. Inside a while loop, the text from the first is read into the string variable. The value of this string variable is then inserted into the queue.
7. The loop continues till the string is read and end of file is not reached.
8. Inside another while loop, the text from the second file is read into the second string variable and this string is inserted into another queue.
9. The loop continues till the end of file is not reached.
10. Using if-else statement, both the queues are compared.
11. If any character in the first queue does not matches the corresponding character of the second queue, the message is displayed accordingly.
12. Alternatively, if the contents of both the queues match, the message is displayed accordingly.
13. In the given example program, the message is displayed as "files are identical." This is because both the files are empty and the respective queues are considered identical since both the queues are empty.
14. Since queues are used, the queue header file is included in the program.
15. An integer value 0 is returned to indicate successful execution of the program.
Which programming language will you use to create an App in code.org?
A. Java Script
B. C++
C. Pearl
Answer:
A. Java Script
Explanation:
java gives languages
Answer:
A. Java Script
Explanation:
That is the only one they teach and is easier than others!
It creates an SQL statement to find the project that has the most employees from the same department. If more than one project meets the condition, they need to be all displayed in the output. The output should display proj_name, dept_name, and total employees that satisfy the condition.It creates a function called DeptDate to return a table containing dept_no, dept_name, emp_no, emp_fname, and job_begin. This function has a date value as input parameter and it finds employees who start a job on a date later than the input date and puts their data into the return table including dept_no and dept_name of their department. In this same file, you must also include three statements with an input of May 05 of 2016, 2015, and 2014, respectively, to test the function you create.
Answer:
Check the explanation
Explanation:
As per requirement submitted above kindly find below solution.
This demonstration is using SQL Server.
Table Names used as
department
project
works_on
SQL query :
select proj_name,dept_name,count(emp_no) as 'most employees ' from
project,department,works_on
where
project.proj_no=works_on. proj_no and
department. dept_no=works_on. dept_no
group by proj_name,dept_name
having count(emp_no)=(
select max(empCount) from (
select proj_name,dept_name,count(emp_no) empCount from project,department,works_on where project. proj_no=works_on. proj_no and department. dept_no=works_on. dept_no
group by proj_name,dept_name) as emp);
Which of the following entries into the username and password fields will NOT cause us to gain admin access? You may assume that the system grants access when a legitimate username/password combo is entered. Count the text inside the double quotation marks, but not the marks themselves. For example, a user would enter ("username", "password") and gain access. You may assume that the password to the admin account is not "asdf"
Explanation: Complete question and answer is attached
What are possible challenges for cyber bullying
Answer:
well, you will have your account deleted/ arrested because of cyber bullying
Explanation:
so don't!!! (hint hint XD)
Answer:
1. they falsely believes he or she cannot control what is posted on his or her social networking site or who sends messages to him or her.
2. they feel uncomfortable telling you what someone else wrote on your their wall because the comment is inappropriate. Therefore your they fears you may be disappointed in him or her.
3. they feels powerless to deal with cyberbullying
Write a class named Employee that holds the following data about an employee in attributes: name, ID number, department, and job title. Don't include a constructor or any other methods. Once you have written the class, write a program that creates three Employee objects to hold the following data: Name ID Number Department Job Title Susan Meyers 47899 Accounting Vice President Mark Jones 39119 IT Programmer Joy Rogers 81774 Manufacturing Engineering The program should store this data in three Employee objects and then print the data for each employee.
Answer:
Check the explanation
Explanation:
#Define the class Employee.
class Employee:
#Declare and initialize the required member variables.
emp_name = ''
Id_num = ''
emp_dept = ''
emp_job_title = ''
#Create an object of the class Employee.
emp_obj1 = Employee()
#Assign required values to the members of the class for a
#particular object.
emp_obj1.emp_name = 'Susan Meyers'
emp_obj1.Id_num = '47899'
emp_obj1.emp_dept = 'Accounting'
emp_obj1.emp_job_title = 'Vice President'
#Create another object of the class Employee.
emp_obj2 = Employee()
#Assign required values to the members of the class for the
#current object.
emp_obj2.emp_name = 'Marke Jones'
emp_obj2.Id_num = '39119'
emp_obj2.emp_dept = 'IT'
emp_obj2.emp_job_title = 'programming'
#Create another object of the class Employee.
emp_obj3 = Employee()
#Assign required values to the members of the class for the
#current object.
emp_obj3.emp_name = 'Joy Rogers'
emp_obj3.Id_num = '81774'
emp_obj3.emp_dept = 'Manufacturing'
emp_obj3.emp_job_title = 'Engineering'
#Display the details of each employee objects.
print('Employee 1 details:')
print('Employee Name:', emp_obj1.emp_name)
print('Employee ID Number:', emp_obj1.Id_num)
print('Employee Department:', emp_obj1.emp_dept)
print('Employee Job Title:', emp_obj1.emp_job_title)
print()
print('Employee 2 details:')
print('Employee Name:', emp_obj2.emp_name)
print('Employee ID Number:', emp_obj2.Id_num)
print('Employee Department:', emp_obj2.emp_dept)
print('Employee Job Title:', emp_obj2.emp_job_title)
print()
print('Employee 3 details:')
print('Employee Name:', emp_obj3.emp_name)
print('Employee ID Number:', emp_obj3.Id_num)
print('Employee Department:', emp_obj3.emp_dept)
print('Employee Job Title:', emp_obj3.emp_job_title)
Kindly check the attached image below for the code output.
Answer:
The previous andwers needed a few tweaks to be correct.
Explanation:
class Employee:
#Declare and initialize the required member variables.
emp_name = ''
Id_num = ''
emp_dept = ''
emp_job_title = ''
#Create an object of the class Employee.
emp_obj1 = Employee()
#Assign required values to the members of the class for a
#particular object.
emp_obj1.emp_name = 'Susan Meyers'
emp_obj1.Id_num = '47899'
emp_obj1.emp_dept = 'Accounting'
emp_obj1.emp_job_title = 'Vice President'
#Create another object of the class Employee.
emp_obj2 = Employee()
#Assign required values to the members of the class for the
#current object.
emp_obj2.emp_name = 'Mark Jones'
emp_obj2.Id_num = '39119'
emp_obj2.emp_dept = 'IT'
emp_obj2.emp_job_title = 'Programmer'
#Create another object of the class Employee.
emp_obj3 = Employee()
#Assign required values to the members of the class for the
#current object.
emp_obj3.emp_name = 'Joy Rogers'
emp_obj3.Id_num = '81774'
emp_obj3.emp_dept = 'Manufacturing'
emp_obj3.emp_job_title = 'Engineer'
#Display the details of each employee objects.
print('Name:', emp_obj1.emp_name)
print('ID Number:', emp_obj1.Id_num)
print('Department:', emp_obj1.emp_dept)
print('Job Title:', emp_obj1.emp_job_title)
print()
print('Name:', emp_obj2.emp_name)
print('ID Number:', emp_obj2.Id_num)
print('Department:', emp_obj2.emp_dept)
print('Job Title:', emp_obj2.emp_job_title)
print()
print('Name:', emp_obj3.emp_name)
print('ID Number:', emp_obj3.Id_num)
print('Department:', emp_obj3.emp_dept)
print('Job Title:', emp_obj3.emp_job_title)
Mobile providers can be susceptible to poor coverage indoors as a result of: a high degree of latency. network congestion that clogs up the network traffic. an increase in bandwidth demand placed on their networks. spectrum used by most mobile phone firms that does not travel well through solid objects. a lack of sufficient number of towers owing to the not-in-my-backyard problem.
Answer:
C. spectrum used by most mobile phone firms that does not travel well through solid objects.
Explanation:
Obstructions on the path of radio waves can result to poor network coverage. This is also called Phone reception or coverage black spot. Just as an obstruction on the path of light waves causes the emergence of shadows, so also an obstruction from waves coming from the cell tower. Common culprits are windows, doors, roofing materials, and walls. These solid objects cause an interruption of network for network providers inside a building.
The use of antennas connected from outside the building to inside can be helpful in reducing the effect of this obstruction. Problems resulting could be low signal, difficulty hearing a caller at the other end, slow internet connection, etc.
1. INTRODUCTION In this project, you will gain experience with many of the Python elements you’ve learned so far, including functions, repetition structures (loops), input validation, exception handling. and working with strings 2. PROBLEM DEFINITION Present the user with the following menu within a continuous loop. The loop will exit only when the user selects option 7. 1. Enter a string 2. Display the string 3. Reverse the string 4. Append a string to the existing one 5. Slice the string 6. Display the number of occurrences of each letter 7. Quit Program operation: Option 1: Prompt the user to enter a string. Option 2: Display the string to the user. Option 3: Reverse the string and display it to the user. Option 4: Prompt the user to enter a string, then append (i.e. concatenate) it to the end of the existing string. Option 5: Prompt the user for the first and second integers of a slice operation, then replace the existing string with a sliced version of it. Option 6: Print on a separate line each alphabetic character contained in the string. Don’t worry about punctuation, special characters, or whitespace. The letters are not to be considered case-sensitive, so you are free to display them either upper or lower case. Along with each letter, display number of occurrences within the string. For example, if the string is "Hello, World", the output would be: h, 1 e, 1 l, 3 o, 2 w, 1 r, 1 d, 1
Answer:
See Explaination
Explanation:
def process_string(s):
global char#global varibles
char=[]
global count
count=[]
for i in s:
#checking whether i is alphabet or not
if(i.isalpha()):
#converting to lower
i=i.lower()
if i in char:
#if char already present increment count
count[char.index(i)]+=1
else:
#if char not present append it to list
char.append(i)
count.append(1)
#menu
print("1. Enter a string")
print("2. Display the string")
print("3. Reverse the string")
print("4. Append a string to the existing one")
print("5. Slice the string")
print("6. Display the number of occurences of each letter")
print("7. Quit")
op=input("Enter option:")
#as I don't know what you have covered
#I am trying to make it simple
#checking whether input is numeric or not
#you can use try except if you want
while(not op.isnumeric()):
op=input("Enter valid option:")
op=int(op)
global x
while(op!=7):
if(op==1):
x=input("Enter a string: ")
elif(op==2):
print("The string is:",x)
elif(op==3):
x=x[::-1]#reversing the string
print("The string is:",x)
elif(op==4):
y=input("Enter a string: ")
x=x+y #string concatnation
elif(op==5):
a=input("Enter first integer: ")
while(not a.isnumeric()):
a=input("Enter valid first integer: ")
a=int(a)
b=input("Enter second integer: ")
while(not b.isnumeric()):
b=input("Enter valid second integer: ")
b=int(b)
x=x[a:b]#string slicing
#you can also use x.slice(a,b)
elif(op==6):
process_string(x)
for i in range(len(char)):
print(char[i],",",count[i])
else:
#incase of invalid input
print("Invalid option")
print("1. Enter a string")
print("2. Display the string")
print("3. Reverse the string")
print("4. Append a string to the existing one")
print("5. Slice the string")
print("6. Display the number of occurences of each letter")
print("7. Quit")
op=input("Enter option:")
while(not op.isnumeric()):
op=input("Enter valid option:")
op=int(op)
You should process the tokens by taking the first letter of every fifth word,starting with the first word in the file. Convert these letters to uppercase andappend them to a StringBuilder object to form a word which will be printedto the console to display the secret message.
Answer:
See explaination
Explanation:
import java.io.File;
import java.io.IOException;
import java.util.Scanner;
import java.util.StringTokenizer;
public class SecretMessage {
public static void main(String[] args)throws IOException
{
File file = new File("secret.txt");
StringBuilder stringBuilder = new StringBuilder();
String str; char ch; int numberOfTokens = 1; // Changed the count to 1 as we already consider first workd as 1
if(file.exists())
{
Scanner inFile = new Scanner(file);
StringTokenizer line = new StringTokenizer(inFile.nextLine()); // Since the secret.txt file has only one line we dont need to loop through the file
ch = line.nextToken().toUpperCase().charAt(0); // Storing the first character of first word to string builder as mentioned in problem
stringBuilder = stringBuilder.append(ch);
while(line.hasMoreTokens()) { // Looping through each token of line read using Scanner.
str= line.nextToken();
numberOfTokens += 1; // Incrementing the numberOfTokens by one.
if(numberOfTokens == 5) { // Checking if it is the fifth word
ch = str.toUpperCase().charAt(0);
stringBuilder = stringBuilder.append(ch);
numberOfTokens =0;
}
}
System.out.println("----Secret Message----"+ stringBuilder);
}
}
}
The Counter Pattern
This pattern is one of the most important ones in all of programming.
It is used to increase the value of a variable by 1. You might call it the counter pattern since it can be used to make a variable that counts up. You'll use this pattern a lot, especially with the draw loop. Let's see what that looks like.
Do This
This program creates a variable counter and then uses the counter pattern to make it count up. When you run the program what do you think you'll see on the screen?
Read the program and make a prediction of what the output will be.
Run the program to check your prediction.
Discuss with a neighbor. Can you explain what you observed?
b) Write a Boolean equation for this sentence showing your work: (Use the variables S,R,O only for the right side) Give two possible interpretations of the logic and show which one is most likely to be the correct interpretation given your knowledge of roads: Let V(S,R,O) = Very Slippery: {1.2} The Road will be very slippery if it snows or it rains and there is oil on the road .
Answer:
Check the explanation
Explanation:
Kindly check the attached image below to see the solution to the above question.
Create an array of strings. Let the user decide how big this array is, but it must have at least 1 element. Prompt them until them give a valid size. Prompt the user to populate the array with strings Display the longest and shortest string Input an array size for you words array: 5 Now please enter 5 words Input a word: apples Input a word: eat Input a word: banana Input a word: spectacular Input a word: no The longest word is : spectacular The shortest word is : no
Answer:
lst = []
n = int(input("Input an array size for you words array: "))
print("Now please enter " + str(n) + " words")
max = 0
min = 1000
index_min = 0
index_max = 0
for i in range(n):
s = input("Input a word: ")
lst.append(s)
if len(s) >= max:
max = len(s)
index_max = i
if len(s) <= min:
min = len(s)
index_min = i
print("The longest word is :" + lst[index_max])
print("The shortest word is :" + lst[index_min])
Explanation:
Create an empty list, lst
Get the size from the user
Create a for loop that iterates "size" times
Inside the loop, get the strings from the user and put them in the lst. Find the longest and shortest strings and their indices using if structure.
When the loop is done, print the longest and shortest