Does Anyone know how many time can 4 go into 0

We are given that:
>perfect score- 100
>number of questions of the test- 25
>worth of each question- 4 points
>Fred's score- 84
Let us say that n- number of questions Fred answered wrong

The solution: 
let us solve for n
>division sentence: (100 ÷ 4 ) -  ( 84 ÷ 4 ) = n

(100 ÷ 4 ) -  ( 84 ÷ 4 ) = n
25 - 21 = n
4= n

Therefore Fred answered 4 test questions incorrectly. 

Final answer:

To create a division sentence expressing the number of incorrect answers as a negative integer, you would divide the total number of questions by -0.16. This implies that Fred answered 16% of the questions incorrectly.

Explanation:

To write a division sentence using negative integers where the quotient represents the number of questions Fred answered incorrectly, we need to first determine the total number of questions on the test. We can assume that a perfect score is 100%. If Fred scored an 84, that implies he got 84% of the questions correct. We do not know the total number of questions, so let's denote the total number as x.

Since Fred got 84 out of 100 percent, that means he answered 16% of the questions incorrectly. In terms of the total number of questions x, he answered 0.16x questions incorrectly. Since he answered these questions incorrectly, and incorrect answers are considered as losses or negatives, we can multiply the total number of questions x by -0.16 to find the number of questions he answered incorrectly. Therefore, the division sentence could be -x/(-0.16) = y, where y represents the number of questions Fred answered incorrectly.

I hope that helps!

Answer:

The answer is

B. It makes more sense to find an underestimate to make sure there are enough seats for everybody who buys a ticket to the show.

Step-by-step explanation:

Final answer:

TJ's age eight years ago is found by dividing the sum of their current ages, s, by 3 to find each person's age and then subtracting 8. Hence, TJ's age eight years ago is (s/3) - 8.

Explanation:

If TJ, Max, and Misha are all the same age and the sum of their ages is s years, we can establish that the age of each one of them is s/3. To determine how old TJ was eight years ago, we simply subtract eight from his current age.

So TJ's age eight years ago can be calculated as follows:

Find TJ's current age: TJ's age = s/3.

Subtract eight years to find his age at that time: Age eight years ago = TJ's age - 8

Therefore, TJ's age eight years ago = (s/3) - 8.

1st number = x

 2nd number = x-6

x +x-6 = 20

2x-6 = 20

2x=26

x = 26/2 = 13

13-6 = 7

 the 2 numbers are 7 & 13

Answer:

No, the root 3 has multiplicity of 2.

Final answer:

Mariana is incorrect because the Fundamental Theorem of Algebra states that a third-degree polynomial must have three complex roots, and she has found only two real zeros.

Explanation:

Mariana is not correct in her assumption that the Fundamental Theorem of Algebra does not apply to the function ƒ(x) = x^3 − 4x^2 − 3x + 18. The Fundamental Theorem of Algebra states that every non-constant single-variable polynomial with complex coefficients has at least one complex root. This theorem guarantees that a polynomial of degree n has exactly n complex roots, though some of the roots may be repeated and not all of them may be real. In Mariana's case, the polynomial is of the third degree, so it should have three complex roots. She has found two real zeros, −2 and 3. There must be another root, which could also be real or complex. If all roots were real, she would see all three zeros on the graph. If the third root is complex, it will not appear on the real number graph that Mariana is using.

To write a percent as a fraction in lowest terms, we need to remember that a percent is a ratio that compares a number to 100.

40% can be written as the ratio [tex]\frac{40}{100}[/tex]. [tex]\frac{40}{100}[/tex] is not in lowest terms so we need to divide the numerator and the denominator by 20 which gives us [tex]\frac{2}{5}[/tex].

Therefore, 40% can be written as the fraction [tex]\frac{2}{5}[/tex].

the answer to your question is b: y-9=2(x-5)

The unit of time spent trying locker combinations is seconds, with the student already having spent 150 seconds. Introducing a variable x for additional combinations, the total time is expressed as 10x + 150 seconds.

Let's define the unit for the length of time spent trying combinations as seconds. Since the student spends 10 seconds on each try, and has tried 15 combinations, that's already 150 seconds spent. Now, let's introduce the variable x to represent the number of additional combinations the student will try. If each additional combination takes 10 seconds to try, then the total length of time spent trying combinations would be 10x seconds for the additional tries. Add this to the initial 150 seconds, and we get an expression for the total time spent as 10x + 150 seconds.