Does the force of kinetic friction depend on the weight of the block? explain.

Answers

Answer 1
Yes for an object moving on a horizontal plane, R = mg (where mg = weight). therefore, for an object moving on a horizontal plane: F = μmg



Answer 2

The force of kinetic friction is determined by surface properties and the normal force, not the weight of the object. Thus, objects with different weights experience the same kinetic friction on the same surface.

The force of kinetic friction does not depend on the weight of the block. Kinetic friction is the force that opposes the relative motion of two surfaces in contact when they are sliding past each other. It is determined by the nature of the surfaces and the normal force, which is the force exerted by a surface to support the weight of an object resting on it.

The weight of an object (or the force of gravity acting on it) affects the normal force, but it does not directly impact the coefficient of kinetic friction between the surfaces. The coefficient of kinetic friction remains constant for a given pair of materials, regardless of the weight of the object.

In simpler terms, if you have two objects made of the same material and they are sliding on the same surface, the force of kinetic friction will be the same for both objects, even if they have different weights. This is because the frictional force depends on the properties of the surfaces in contact, not the mass or weight of the objects involved.

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Related Questions

Which statement about matter is correct? A) In matter, molecules never stop moving. B) In the solid state, molecules stop moving. C) Pressure and temperature do not affect matter. D) Liquids have a lower level of energy than solids.

Answers

Answer: A

Explanation:

When a simple machine multiplies force, it decreases
a.potential energy.
b.distance moved.
c.both
d.neither?

Answers

When a simple machine multiplies force, it decreases (B) Distance moved, force is described as an interaction, which, unopposed, will change the motion of an object, the potential energy, however, remains the same. 

What is meant by the terms composition and structure when referring to matter?

Answers

When it comes to the composition and structure when referring to matter, it regards the state of matter that the given object is in, and the inherent structure that is used in order to create the object in question. The composition is the former, and the structure is the latter.

In a hospital setting, which of the following presents the possibility of being the source of an arc flash?

Answers

The answer to this question would be Electrocautery Device

In a hospital, the device that can cause arc flash would be an electrocautery device or a circuit breaker. In fact, the electrocautery device is using the arc flash principle to work. The arc flash will cause burns that surgeon use to clot bleeding in surgery or to destroy a tissue.

A student pours 10.0 g of salt into a container of water and observes the amount of time it takes for the salt to dissolve. She then repeats the process using the same amounts of salt and water but this time she slowly stirs the mixture while it is dissolving. The student performs the experiment one more time but this time she stirs the mixture rapidly.
In order to get the best results, the student should:

Answers

In order to get the best result, the student should heat the salt water mixture gently.
Application of heat will increase the amount of the kinetic energy that is available to the molecules of the salt, the particles will be moving faster and in the process they will dissolve faster. Application of heat will make the water molecules too to gain energy and take in more salts more rapidly.

What part causes the disc brake caliper piston to retract when the brakes are released?

Answers

The part that causes the disc caliper piston to retract when the brakes are released is the square-cut O-ring.
The square cut seal is the most important part of a disc brake caliper, for keeping the brake behind the piston so that when you step on the brake pedal, it releases a pressure that applied to the piston which in return applies the pad to the rotor.

A particle moving uniformly along the x axis is located at 13.4 m at 1.72 s and at 3.13 m at 4.6 s. what is its average velocity during this time interval? answer in units of m/s.

Answers

The formula for average velocity is: (final distance - initial distance9 / (final time - inital time). Using that, the anwer will be:

(3.13 - 13.4)m / (4.6 - 1.72)s = - 3.57 m/s.

According to these results, if we assume positive numbers are right, the particle was moving left.
Final answer:

The average velocity of a particle moving uniformly along an axis can be found using the formula v = Δx/ Δt where Δx is the change in displacement and Δt is the change in time. In this case, the initial position and time are subtracted from the final position and time to find these changes, and the answer is negative, indicating motion in the negative x-direction.

Explanation:

The average velocity of a particle moving uniformly along the x-axis can be determined using the formula for average velocity, which is the change in displacement divided by the change in time. In this case, the initial position of the particle is x1 = 13.4 m at time t1 = 1.72 s, and the final position is x2 = 3.13 m at time t2 = 4.6 s.

Subtract the initial position from the final position to get the change in displacement (Δx = x2 - x1), and subtract the initial time from the final time to get the change in time (Δt = t2 - t1).

A negative answer implies motion in the negative x-direction. The average velocity (v) is then given by the formula v = Δx/Δt.

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True or False A scientific law only states that an event occurs?

Answers

True

A scientific law only states that an event occurs.

Hope this helps!

Which of the following buildings would be least likely to be damage after a very large earthquake

Answers

a very small building that has been built recently

Soft-story buildings are least likely to withstand large earthquakes compared to well-designed structures that comply with modern building codes. Building codes are meant to reduce damage through various levels of seismic activity, but they only apply to new or significantly renovated structures. The type of ground and construction materials also significantly impacts a building's earthquake resilience.

Among various building types, soft-story buildings are least likely to withstand a very large earthquake due to their vulnerability to horizontal forces. Such structures, which include two- or three-car garages with a living space above, can fail catastrophically during an earthquake because of less bracing in the open areas compared to standard walls. In contrast, well-designed buildings that adhere to modern building codes and consider earthquake resilience are more likely to sustain only minor damage, even during severe shaking. Understanding building performance during earthquakes is essential, especially in regions where adherence to building codes might be poor and materials used might be inadequate, leading to increased structural vulnerability.

Building codes play a crucial role in dictating how well a structure can survive an earthquake. The codes are designed to ensure that buildings resist minor ground motion without damage, moderate shaking without structural damage, and major motion with an intensity equivalent to the region's maximum considered earthquake without collapse, despite possible structural damage. However, the effectiveness of these codes is limited to new constructions or major renovations. Buildings built before the establishment of stringent earthquake-related standards, such as old unreinforced masonry buildings or non-ductile reinforced concrete frames, tend to suffer the most damage. Moreover, buildings constructed on unconsolidated sediments are likely to experience more severe earthquake damage than those on solid rock due to the amplification of seismic waves. In addition to the type of ground, the materials and construction methods used also determine a building's seismic performance. Brittle structures like unreinforced masonry and nonductile concrete frames perform poorly during earthquakes due to their susceptibility to sheer and collapse.

The name of the group of science that deals with earth and its neighbors in space is called

Answers

astrology is the answer

A sailboat is heading directly north at a speed of 20 knots (1 knot 50.514 m/s). the wind is blowing toward the east with a speed of 17 knots. (a) determine the magnitude and direction of the wind velocity as measured on the boat. (b) what is the component of the wind velocity in the direction parallel to the motion of the boat?

Answers

(a) The magnitude of the wind as it is measured on the boat will be the result of the two vectors. Since they are at 90°, the resultant can be determined by the Pythagorean theorem.
 
                   R = sqrt ((20 knots)² + (17 knots)²)
                    R = sqrt (400 + 289)
                      R = 26.24 knots

The direction of the wind will have to be angle between the boat and the resultant.
                   cos θ = (20 knots)/(26.24 knots)
                        θ = 40.36°

Hence, the direction is 40.36° east of north.

(b) As stated, the wind is blowing in the direction that is to the east. This means that it only has one direction. Parallel to the motion of the boat, the magnitude of the wind velocity will have to be zero. 

How long does it take for the ball to hit the wall?
At what height does the ball hit the wall?

Answers

your answers are correct

The cannonball takes approximately 4.40 seconds to hit the wall and strikes it at a height of around 157.15 meters.

Let's solve this step by step:

Step 1: Calculate the time of flight

To find how long it takes for the cannonball to hit the wall, we need to consider the horizontal motion.

Initial horizontal velocity ([tex]u_x[/tex]): 89 m/s * cos(40°)[tex]u_x[/tex] = 89 * 0.766[tex]u_x[/tex] ≈ 68.174 m/sDistance to the wall (d): 300 mTime of flight (t) = d / [tex]u_x[/tex]t = 300 / 68.174t ≈ 4.40 seconds

So, it takes approximately 4.40 seconds for the ball to hit the wall.

Step 2: Calculate the height at which the ball hits the wall

For vertical motion:

Initial vertical velocity ([tex]u_y[/tex]): 89 m/s * sin(40°)[tex]u_y = 89 \times 0.643[/tex][tex]u_y \approx 57.227\ m/s[/tex]

Vertical displacement (y) after time t: [tex]y = u_y \times t - 0.5 \times g \times t^2[/tex] (where g is the acceleration due to gravity, approximately 9.8 m/s²)

[tex]y = 57.227 \times 4.40 - 0.5 \times 9.8 \times (4.40)^2[/tex][tex]y \approx 251.79 - 94.64[/tex][tex]y \approx 157.15 meters[/tex]

Therefore, the ball hits the wall at a height of approximately 157.15 meters.

The complete question is as follows:

A cannon elevated at 40 degrees is fired at a wall 300 m away on level ground. The initial speed of the cannonball is 89 m/sec.

1) how long does it take for the ball to hit the wall?

2) at what hight does the ball hit the wall?

People who study the effects of human activities on earth land air water and living Thing are

Answers

Environmental scientist is the answer . :-) good luck 

Answer:

People who study the effects of human activities on earth land air water and living thing are Environmental scientist

What is the setting of the story in "the pedestrian"?
a.a space station orbiting mars
b.a deserted neighborhood street
c.a lonely road in the countryside
d.a large metropolis?

Answers

Answer:

b.a deserted neighborhood street

Explanation:

ap3x

The setting of the story in "the pedestrian" is a large metropolis. The correct option is D.

"The Pedestrian" is a short story by Ray Bradbury that was first published in 1951. The story is set in the future in the year 2053 in a large metropolis where people spend their evenings indoors watching television or communicating through advanced technology.

The main character, Leonard Mead, is an exception to this pattern. He enjoys taking long walks through the city streets at night, something that is seen as strange and suspicious by the society around him. One evening, he is stopped by a police car and questioned about his activities. The police officers are suspicious of him and don't understand why he would want to walk when he could stay inside and be entertained.

After a brief conversation, the police let Leonard go and he continues his walk. However, he soon realizes that he is the only person outside in the entire city. He reflects on the society he lives in and how it has become so obsessed with technology that people have lost the ability to appreciate the simple pleasures of life. As he continues his walk, he is suddenly surrounded by a bright light and taken away by the police, who see his activities as a threat to society.

The story is a critique of the growing influence of technology and its impact on human interaction and personal freedoms. It highlights the danger of becoming too dependent on technology and losing sight of the things that truly make life worth living.

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Chinook salmon are able to move through water especially fast by jumping out of the water periodically. this behavior is called porpoising. suppose a salmon swimming in still water jumps out of the water with velocity 6.65 m/s at 48.1° above the horizontal, sails through the air a distance l before returning to the water, and then swims the same distance l underwater in a straight, horizontal line with velocity 3.79 m/s before jumping out again. (a) determine the average velocity of the fish for the entire process of jumping and swimming underwater. incorrect: your answer is incorrect. your response differs from the correct answer by more than 10%. double check your calculations. m/s (b) consider the time interval required to travel the entire distance of 2l. by what percentage is this time interval reduced by the jumping/swimming process compared with simply swimming underwater at 3.79 m/s?

Answers

When it jumps, the fish travels a horizontal distance of
[tex]d_1=(v^2/g)*sin(2\theta) =(6.65^2/9.81)*\sin(2*48.1) =4.48 m[/tex]
The horizontal speed when the fish jumps is
[tex]v_1=v\cos \theta =6.65*\cos(48.1) =4.44 (m/s)[/tex]
The average speed is give by the equation
[tex]v=(v_1*d_1+v_2*d_2)/(d_1+d_2) [/tex]
[tex]v=(4.44*4.48 +3.79*4.48)/(4.48+4.48)=4.115 (m/s)[/tex]
Time to travel this way (jumping and swimming) is
[tex]t=t_1+t_2=4.48/4.44+4.48/3.79 =2.19 s[/tex]
If it were to swim the time was
[tex]tt=2*t_2=2*4.48/3.79 =2.364 s[/tex]
Percentage change is
[tex]\epsilon =(tt-t)/t =(2.364-2.19)/2.364 =0.073=7.3% [/tex]

A student walks 1.0 mi west and then 1.0 mi north. afterward, how far is she from her starting point?

Answers

1.0 mi because as he has covered 1 the disrance of 1 m and then 1 m in north so he can go straight 1m north so the distance is actually 1m from the starting point

A 1100kg car pulls a boat on a trailer. (a) what total force resists the motion of the car, boat,and trailer, if the car exerts a 1900n force on the road and produces an acceleration of 0.550 m/s2? the mass of the boat plus trailer trailer is 700kg. (b) what is the force in the hitch betweenthe car and the trailer if 80% of the resisting forces are experienced by the boat and trailer?

Answers

Refer to the figure shown below.

m₁ = 1100 kg, the mass of the car
m₂ = 700 kg, the mass of the trailer and boat
F = 1900 N, the driving force acting on the car
N₁ = m₁g,  the normal reaction on the car
N₂ = m₂g, the normal force on the trailer and boat
μN₁ and μN₂ are frictional forces, where  =  kinetic coefficient of friction
T = the force in the hitch between the car and trailer.

Part (a)
Let R₁ = the total force that resists the motion of the car, boat, and trailer.
Because the acceleration is 0.550m/s², therefore
(m₁ + m₂ kg)*(0.55 m/s²) = F
(1100+700 kg)*(0.55 m/s²) = (1900 - R₁) N
990 = 1900 - R
R₁ = 910 N

Answer: The resistive force is 910 N

Part (b)
80% of the resistive forces are experienced by the boat and trailer.
Let the resistive force be R₂.
Then
R₂ = 0.8*R₁ = 728 N
If the tension in the hitch between the car and the trailer is T, then
T - R₂ = m₂(0.55 m/s²)
(T - 728 N) = (700 kg)*(0.55 m/s²)
T - 728 = 385
T = 1113 N

Answer: The force in the hitch is 1113 N

Explain the relationship between resistance and the velocity of shortening.

Answers

The velocity of shortening refers to the speed of the contraction from the muscle shortening while lifting a load. The relationship between the resistance and velocity of shortening is inverse. The greater the resistance, the shorter the velocity of shortening and the smaller the resistance, the larger the velocity of shortening.

Hopefully this help :)

A car traveling at a speed of v can brake to an emergency stop in a distance x. assuming all other driving conditions are all similar, if the traveling speed of the car doubles, the stopping distance will be

Answers

We will use the formula: 

2as = v² - u²; where the final velocity v is 0, the distance s will be represented by x and the initial velocity will be represented by v. So:

2ax = -v²

x₁ = 1/2 av²

for the distance it takes to stop, let's see what happens when we double the value v

x₂ = 1/2 A (2v)² = 4(1/2 * av²)

Now divide the formulae, getting

x₂ / x₁ = 

(4(1/2 * av²)) / (1/2 av²) = 4

Doing the division, everything cancels out except for the value 4. So if your speed doubles, the stopping distance quadruples, or becomes 4 times the original.

What units do chemists normally use for density of liquids and solids? for gas density? explain the differences?

Answers

We can define density as per unit volume.

The SI unit to measure the density of solid, liquid and gas is kilogram per cubic metre (kg/m3) and in the centimetre–gram–second system of units (cgs unit) is gram per cubic centimetre (g/cm3). Gas density is very dependent of pressure and temperature whereas the density of solids and liquids is not so dependent, that is why the gas density is given at a standard temperature and pressure.

Chemists typically use g/mL or g/cm³ for liquids and solids, and g/L for gases. Differences arise due to the varying densities and volumes of these states of matter.

Chemists use different units for density based on the state of matter being measured. For liquids and solids, the density is usually expressed in grams per milliliter (g/mL) or grams per cubic centimeter (g/cm³). This is because liquids and solids generally have higher densities and smaller volumes compared to gases, making these units convenient for laboratory measurements and calculations.

For gases, the density is typically expressed in grams per liter (g/L). Gases have much lower densities and occupy larger volumes compared to liquids and solids, so g/L is more appropriate. The larger unit (liter) helps to manage the lower mass of gases, ensuring the numerical values are easy to work with.

The choice of units helps chemists maintain consistency and accuracy when measuring and comparing densities across different substances and states of matter. Using units that reflect the typical scales of measurement for each state ensures that the values are neither too large nor too small, facilitating easier interpretation and communication of data.

Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant (and quite modest) acceleration. a train travels through a congested part of town at 7.0 m/s . once free of this area, it speeds up to 14 m/s in 8.0 s. at the edge of town, the driver again accelerates, with the same acceleration, for another 16 s to reach a higher cruising speed. what is the final speed?

Answers

First let us calculate the acceleration.

v1 = v0 + a t1

where v1 is final velocity, v0 is initial velocity, a is acceleration and t is time

Calculating for a:

14 m/s = 7 m/s + a * 8 s

a = 0.875 m/s^2

 

Therefore the final speed is calculated similarly:

v2 = v1 + a t2

v2 = 14 m/s + (0.875 m/s^2) * 16 s

v2 = 28 m/s

What is a type of science that studies earth and and space

Answers

Earth sciences are the sciences that study the earth and space through natural observations, structure, and morphology. This science investigates the behavior of the earth in relation to space and determines its elements and characteristics and is part of the planetary studies and the planets of the solar system.

What is her mass on the moon, where g=1.62m/s2 ?

Answers

Answer: The same

Explanation.
The weight of an object of mass M is Mg, where g =  acceleration due to gravity.
On the moon, g is about 1/6 the value of g on earth.
The weight varies, but the mass does not change.
Final answer:

The mass of an object remains constant, in any location. As such, a person's mass on the Moon is the same as their mass on Earth. However, their weight would be approximately 1/6th of what it is on Earth, due to the Moon's lower gravity.

Explanation:

The mass of an object remains the same regardless of location - it is a fixed measure of the amount of matter within an object. The force of gravity does change depending on location, and as such, the weight of an object can vary. On the Moon, for example, the value of 'g' (the acceleration due to gravity) is 1.62 m/s², which is about 1/6 of the Earth's gravity. Therefore, if you weigh 60 kg on Earth, you would still possess that same mass on the Moon. However, your weight on the Moon would be much less due to the lower gravity.


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A falling stone is at a certain instant 90 feet above the ground. two seconds later it is only 10 feet above the ground. if it was thrown down with an initial speed of 4 feet per second, from what height was it thrown?

Answers

Final answer:

The stone was originally thrown from a height of 234 feet. This solution was obtained using the physics kinematic equation for vertical motion.

Explanation:

This problem can be solved using the kinematic equation:

Δy = V₀t + 1/2gt²

, where:

Δy is the displacement (final position - initial position)V₀ is the initial velocityt is the timeg is the acceleration due to gravity, which is -32 ft/s² (negative because it's acting downwards)

From the statement we know: Δy = 10 ft - 90 ft = -80 ft after 2 seconds. We substitute these values and solve for the initial position, y₀. The equation becomes:

-80 = 4*2 + 1/2*(-32)*2²

. Solving gives us -80 = 8 - 64, so

y₀ = 80 + 64 + 90 = 234 ft

. Therefore, the stone was thrown from a height of 234 feet.

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Final answer:

Using the equations of motion under gravity, it's determined that the stone was thrown from a height of 162 feet considering it was thrown down with an initial velocity and passed specific heights in its journey.

Explanation:

The question involves finding the original height from which a stone was thrown, given that it was thrown down with an initial speed and passes specific points in its descent. To solve this problem, we can use the equations of motion under the influence of gravity. The formula that relates the initial velocity (u), the acceleration due to gravity (g = 32 feet/second2 downward), the time taken (t), and the displacement (s) is s = ut + (1/2)gt2.

In this instance, the stone is observed to move from 90 feet above the ground to 10 feet above the ground in 2 seconds, with an initial downward speed of 4 feet/second. The drop in height (displacement) is 80 feet (90 - 10). We can insert these values into the formula to find the initial height: Let H be the initial height, the equation becomes H - 90 = 4(2) + (1/2)(32)(22). Simplifying, we find that H - 90 = 8 + 64, which resolves to H = 162 feet.

Hence, the stone was thrown from a height of 162 feet.

which of the following professionals would most likely be called upon to treat a person suffering from a dangerous level of schizophrenia

Answers

The primary physician in cases of schizophrenia is the psychiatrist. 

hope this helps, Terrakmiller80! :-)

Which of the following survey questions would be an example of question-wording bias? A. Do you think background checks before buying a gun is a good idea? B. Do you think there should be a ban on assault rifles? C. Do you think hand guns should be registered? D. Do you think we should ignore our constitutional rights and let the government take citizens' guns away?

Answers

D is incredibly biased and is a leading question, and overall it is a poor excuse for any sort of unbiased surveying. 

Answer:

D. Do you think we should ignore our constitutional rights and let the government take citizens' guns away?

Explanation:

A question wording biased is what happens when the question states directly a point of biew and suggests the interviewed a certain answer that is clear once you´ve heard the question, in this case it is obvious that the question is against the ban on guns, because it is already judging any decision that the congress could make on it and suggesting a point of view to the interviewed.

The auditory cortex is located in which lobe of the brain?

Answers

The auditory cortex is located in temporal lobe of the brain.

What is auditory cortex?

The  auditory cortex is the part of the temporal lobe that processes hear-able data in people and numerous different vertebrates.

It is a piece of the  auditory framework, carrying out fundamental and higher roles in hearing. For example, potential relations to language switching.

The auditory cortex is situated on the predominant transient gyrus in the fleeting curve and gets highlight point input from the ventral division of the average geniculate complex.  Consequently, it contains an exact tonotopic map.

It is found generally at the upper sides of the fleeting curves in people, bending down and onto the average surface, on the prevalent transient plane, inside the sidelong sulcus and containing portions of the cross over worldly gyri, and the unrivaled worldly gyrus, including the planum polare and planum temporale.

Thus,  auditory cortex is located in temporal lobe of the brain.

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A vector has an x component of -27.5 units and a y component of 43.0 units. find the magnitude and direction of this vector.

Answers

Magnitude ={(-27.5)^2+(43.0)^2}^(1/2)
=51.0 units
Direction=tan-1(43.0/-27.5)
=122 degrees

The magnitude of the vector is approximately 50.5 units and its direction is around 122.6 degrees with respect to the positive x-axis, which lies in the second quadrant.

To find the magnitude and direction of a vector with an x component of -27.5 units and a y component of 43.0 units, we can use the Pythagorean theorem and trigonometry. The magnitude of the vector is calculated using the formula \( \sqrt{x^2 + y^2} \). Plugging in the values, the magnitude (R) is \( \sqrt{(-27.5)^2 + (43.0)^2} \) which equals approximately 50.5 units. To determine the direction, we calculate the angle (θ) with respect to the positive x-axis using the arctangent function \( \tan^{-1}(\frac{y}{x}) \). Since the x-component is negative and the y-component is positive, the vector lies in the second quadrant. Thus, the angle from the positive x-axis is \( \tan^{-1}(\frac{43.0}{-27.5}) \) plus 180 degrees (to adjust for the quadrant), which gives us an angle of approximately 122.6 degrees.

If your front lawn is 17.0 feet wide and 20.0 feet long,and each square foot of lawn accumulates 1050 new snow flakes every minute, how much snow in kilograms accumulates on your lawn per hour? assume an average snow flake has a mass of 1.90mg.

Answers

Well 17x20= 340 do 340x1050= 357000 per minitue, 357000x60=21420000 per hour and 21420000x1.90mg=40698g, 40698g/1000= 40.698kg

6 A small rock is thrown vertically upward with a speed of 14.0 m/s from the edge of the roof of a 30.0 m tall building. The rock doesn't hit the building on its way back down and lands in the street below. Air resistance can be neglected.  

A)What is the speed of the rock just before it hits the street?
B)
How much time elapses from when the rock is thrown until it hits the street?

Answers

Refer to the diagram shown below.

Air resistance is ignored, and g = 9.8 m/s².
All quantities are measured as positive upward.

Part A)
The ground is at a distance of  s = - 30 m from the launch point.
If the rock strikes the ground with velocity,v, then
v² = u² + 2as
v² = (14 m/s)² - 2*(9.8 m/s²)(-30 m) = 784 (m/s)²
    = 28 m/s

Answer:  28 m/s

Part B)
Let t = time for the rock to hit the ground.
s = ut + (1/2)at²
(-30 m) = (14 m/s)*(t s) + 0.5*(-9.8 m/s²)*(t s)²
-30 = 14t - 4.9t²
4.9t² - 14t - 30 = 0
t² - 2.857t - 6.1224 = 0

Solve with the quadratic formula.
t = (1/2) [2.8571 +/- √(8.163+24.4896)]
  = 4.286 or -1.429 s
Reject negative time.

Answer:  4.29 s  (nearest hundredth)

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