Draw three resonance structures for CNO-. This species has its three atoms bonded sequentially in the following fashion: C-N-O. Draw your resonance structures so that the atoms in them are bonded together in this order. Select the most important resonance structure for this species based on the formal charges on the atoms of the three resonance structures you have drawn. Now select the statement from the multiple choices which is true about this most important resonance structure. In the most important resonance structure of CNO- : a) The leftmost bond (between C and N) is a double bond. b) The rightmost bond (between N and O) is a double bond. c) The formal charge on the leftmost (C) atom is -2. d) The number of nonbonding pairs (lone pairs) of electrons on the leftmost (C) atom is 2. e) The number of nonbonding (lone) pairs of electrons on the rightmost (O) atom is 3.

Answers

Answer 1

To calculate the charge of each atom.

Formal charge= Valence electrons-(non bonding electron+bonding electron/2)

The possible resonance of CNO- ( check attachment)

The second structure is the most stable because in this structure each atoms carry less formal charge than other.

(a) In the most stable resonance structure of CNO- leftmost bond is a triple bond.

Therefore the statement is False

(b) in the most stable resonance structure of CNO- rightmost bond is single.

Therefore the statement is true

(c) in the most stable resonance

structure of CNO- the formal charge on the leftmost is -1.

Therefore the statement is False

(d) in the most stable resonance structure of CNO-,the number of non bonding electron pairs on the leftmost carbon is 1.

Therefore the statement is False

(e) in the most stable resonance structure of CNO-the number of non bonding electron pairs on rightmost oxygen atom is 3.

Therefore the statement is False

Draw Three Resonance Structures For CNO-. This Species Has Its Three Atoms Bonded Sequentially In The

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Causes movement in the heart

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organ

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Use the observation in the first column to answer the question in the second column. observation question The enthalpy of vaporization of Substance C is bigger than that of Substance D. Which has the higher boiling point? Substance C Substance D Neither, C and D have the same boiling point. It's impossible to know without more information. At 1atm pressure, Substance E boils at 89.°C and Substance F boils at 128.°C. Which has a higher enthalpy of vaporization? Substance E Substance F Neither, E and F have the same enthalpy of vaporization. It's impossible to know without more information. At −3°C, Substance A has a vapor pressure of 147.torr and Substance B has a vapor pressure of 177.torr. Which has a higher boiling point? Substance A Substance B Neither, A and B have the same boiling point. It's impossible to know without more information.

Answers

Answer:

See explaination

Explanation:

1. Substance C

With Vapor pressure (VP) of C = 136 torr and VP of D = 186 torr. Since VP (C) < VP (D), this entaills that one needs to supply more energy to get C into the vapor phase. Hence, enthalpy of vaporization of C will be higher.

2. Substance A

B.pt (A) = 109 C

B,pt (B) = 125 C

Having A boils at a lower temperature than B, this automatically will make A to have a higher vapor pressure.

3. Substance E

Since E has a lower enthalpy of vaporization, it can be brought into the vapor phase with lower energy as compared to F. Hence, E will have a higher vapor pressure.

Final answer:

Substance C has a higher boiling point than Substance D, Substance F has a higher boiling point (and thereby a higher enthalpy of vaporization) than Substance E, and Substance A has a higher boiling point than Substance B due to its lower vapor pressure.

Explanation:

The boiling point of a substance is directly related to its enthalpy of vaporization. In other words, a substance with a higher enthalpy of vaporization requires more heat to transform from a liquid to a gaseous state, making it have a higher boiling point.

So, based on the given observations:

Substance C has a higher enthalpy of vaporization than Substance D, therefore Substance C has a higher boiling point.Substance E boils at 89°C and Substance F boils at 128°C, therefore Substance F has a higher boiling point and consequently a higher enthalpy of vaporization.Substance A has a lower vapor pressure than Substance B at the same temperature (-3°C). Therefore, Substance A would require more energy to convert to the gaseous phase and so between Substance A and Substance B, Substance A has a higher boiling point.

Learn more about Enthalpy of Vaporization here:

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