Name the three basic parts of a spiral galaxy and describe what is found in each.
What type of radiation is given off in the nuclear reaction 210 84po → 206 82pb + ?
Alpha emission radiation is given off in the given nuclear reaction.
What is alpha emission radiation?
When the nucleus of an atom becomes unstable (the ratio of neutrons to protons is too low), alpha particles are released to bring the atom back into equilibrium.
Alpha decay occurs in high-atomic-number elements including uranium, radium, and thorium.
Alpha decay is a form of radioactive disintegration in which certain unstable atomic nuclei spontaneously release an alpha particle to expend excess energy.
Because alpha particles have two positive charges and a mass of four units, they form offspring nuclei with a positive nuclear charge or atomic number two units lower and a mass four units lower than their parents.
As a result, polonium-210 (mass number 210 and atomic number 84, i.e. a nucleus with 84 protons) decays to lead-206 by alpha emission (atomic number 82).
Hence alpha emission radiation is given off in the given nuclear reaction.
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Which theory of language development and acquisition includes the concepts of reinforcement, stimuli control, deprivation, and aversive stimulation?
a.skinner’s idea of language
b.jean piaget’s theory of cognitive development
c.chomsky’s nativist approach
d.bruner’s theory of language development
The answer is: a. Skinner’s idea of language
Skinner was a psychologists and one of the first behaviorists. In his language acquisition theory, he states that language acquisition is an environmental and social phenomenon; therefore, children acquire language through operant conditioning, which includes stimuli control, reinforcement (positive and aversive), and deprivation.
The correct answer is option A
The Skinner's idea of language was based on the behaviorist reinforcement principles which is associated with the words and the meaning.
The utterance of the words are reinforced on the child when he or she realizes the value of sentence formation, communication et cetera.
Example: if a child asks for milk and the mother smiles after the child asks for milk then the child will find his outcome with some rewards.
A water rocket can reach a speed of 75 m/s in 0.050 seconds from launch. What is its average acceleration?
Answer:
[tex]a = 1500 m/s^2[/tex]
Explanation:
Initial speed of the rocket is ZERO as it starts from rest
[tex]v_i = 0[/tex]
final speed of the rocket is 75 m/s
[tex]v_f = 75 m/s[/tex]
so we will say that average acceleration is defined as rate of change in velocity
so it is given as
[tex]a = \frac{v_f - v_i}{\Delta t}[/tex]
[tex]a = \frac{75 - 0}{0.05}[/tex]
[tex]a = 1500 m/s^2[/tex]
The average acceleration of the water rocket is 1500 m/s².
Explanation:To find the average acceleration of the water rocket, we can use the formula:
average acceleration = change in velocity / change in time
Given that the rocket reaches a speed of 75 m/s in 0.050 seconds, the change in velocity is 75 m/s and the change in time is 0.050 seconds. Plugging these values into the formula, we get:
average acceleration = 75 m/s / 0.050 seconds = 1500 m/s²
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The law of conservation of mass states that _______________________________. matter cannot be created or destroyed atoms conserve mass when they fuse to form molecules mass can be created if a chemical reaction occurs
The law of conservation of mass, established by French chemist Antoine Lavoisier, states that matter is neither created nor destroyed in a chemical reaction, ensuring that the mass remains unchanged in a closed system.
The law of conservation of mass states that in a chemical reaction, matter cannot be created or destroyed. This fundamental principle was established by Antoine Lavoisier, a French chemist, in the year 1789. Essentially, this means that the mass of the reactants, or the starting materials, is equal to the mass of the products formed as a result of the chemical reaction. Even though matter may change form into liquids, gases, or solids during a reaction, the total mass remains constant within a closed system. An everyday example of this law is the burning of wood, where the combined mass of the resultant soot, ashes, and gases is equal to the mass of the original wood and oxygen.
What is the relationship between force and potential energy?
Final answer:
The relationship between force and potential energy is that potential energy is defined within a conservative field based on the position, and force is the negative gradient of the potential energy. It is exemplified in gravitational and electric potential energies, with voltage used as a practical measure for electric potential energy.
Explanation:
Relationship Between Force and Potential Energy
The relationship between force and potential energy is intrinsic and significant in physics. When a force is conservative, which means it allows the energy to be conserved within a system, a potential energy can be defined and associated with that force. This potential energy is dependent only on the position within a conservative field, making it an efficient way to discuss energy changes without having to deal with the force that caused these changes directly. The connection is mathematically represented by the force being equal to the negative gradient of the potential energy.
The most common examples of this relationship are seen in gravitational potential energy and electric potential energy. Gravitational potential energy is the work done by gravitational force on an object due to its position relative to a larger mass, like Earth. Analogously, electric potential energy is work done by electric forces within an electric field, and is often referred to through the concept of voltage, which simplifies electrical interactions by focusing on energy per charge instead of the actual interaction forces.
Understanding potential energy and its relation to force, especially in conservative fields, deepens our comprehension of energy transformations. For example, when we lift a rock off the ground, we are increasing its gravitational potential energy by doing work against gravitational forces. If the rock is dropped, this potential energy transforms into kinetic energy as the force of gravity acts on the rock, accelerating it downwards.
How to find resultant displacement |R|?
When you kick a soccer ball, you apply a force f1 to the ball. what force f2 does the soccer ball exert on your foot? 1. there is no force f2. 2. f1 = f2, acting in the same direction 3. f1 = f2, acting in opposite directions 4. f2 < f1 5. f1 < f2?
Which waves are longitudinal waves? Check all that apply. sound waves ocean waves ultraviolet waves earthquake P-waves earthquake S-waves radio waves
Sound waves
Earthquake P-waves
Longitudinal waves?Longitudinal waves are waves in which the vibration of the medium is parallel to the direction the wave travels and displacement of the medium is in the same direction of the wave propagation.
Examples of longitudinal wavesSpeaking on the microphone. A sound wave is a significant example of a longitudinal wave. Clapping. Vibrating Drumheads. Tsunami Waves. Earthquake (Seismic-P wave) Vibration in Window Panels after a Thunder. Music Woofers.Read more about waves:
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What is the rate at which energy is transformed
The rate at which energy is transformed is called power, which is measured in watts. One watt equals one joule of energy transferred per second. This concept is important in understanding energy use and efficiency.
Explanation:The rate at which energy is transformed or transferred is called power. Power is measured in watts (W) in the International System of Units (SI). One watt is equal to one joule of energy transformed per second.
For example, if a light bulb transforms 60 joules of electrical energy into light and heat energy every second, we would say that the power of the light bulb is 60 watts.
By understanding the rate of energy transformation, we can calculate how much energy a device uses over a given period of time, which is useful for things like understanding electricity bills or determining the efficiency of different appliances.
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A 6.0 kg bucket of water is raised from a well by a rope. if the upward acceleration of the bucket is 3.9 m/s2, find the force exerted by the rope on the bucket
You've always wondered about the acceleration of the elevators in the 101 story-tall empire state building. one day, while visiting new york, you take your bathroom scale into the elevator and stand on them. the scales read 130 lb as the door closes. the reading varies between 110 lb and 160 lb as the elevator travels 101 floors. part a what is the magnitude of the acceleration as the elevator starts upward?
The acceleration of the elevator can be calculated using Newton's second law of motion and the recorded changes in weight on the scale while standing in the elevator. When the elevator begins its ascent, the apparent weight increases due to the increased force needed to move upward, which can be converted to calculate the acceleration.
Explanation:The subject of your question involves understanding the physics concepts of acceleration and force. When standing in an elevator that is accelerating upwards, the scale reads a higher weight because the scale must exert more force to move you upwards, resulting in a feeling of being heavier.
To determine the acceleration of the elevator, we first need to comprehend the concept of net force, which in this scenario, is the difference between your apparent weight (the reading on the scale) and your actual weight. From Newton's second law, we know that net force is equal to mass times acceleration (F=ma).
So, if your weight on the scale varies between 110 lb and 160 lb, then the difference is 50lb. Converting this weight difference to force (gravity being ~9.8 m/s^2), we get approximately 222.41 Newtons.
Given that your regular weight is 130lb, converting this to mass gives us approximately 59 kg (1lb ≈ 0.453592 kg). So, we can now find the acceleration (a) using the formula a = F/m. Substituting the values, we get the acceleration as approximately 3.76 m/s² as the elevator starts upward. Note that this is an ideal value, actual acceleration would be less due to factors like air resistance, friction, etc.
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Determine which type of property each statement describes by typing “physical” or “chemical” in the blank. Hydrogen is a colorless, tasteless, and odorless gas. Hydrogen is very combustible in the presence of oxygen. Hydrogen is very reactive with most elements. Hydrogen is the least dense of all elements.
Answer:
Hydrogen is a colorless, tasteless, and odorless gas.
physical
Hydrogen is very combustible in the presence of oxygen.
chemical
Hydrogen is very reactive with most elements.
chemical
Hydrogen is the least dense of all elements.
physical
Explanation:
I put these in order
Hydrogen is a colorless, tasteless, and odorless gas.
⇒ physical
Hydrogen is very combustible in the presence of oxygen.
⇒ chemical
Hydrogen is very reactive with most elements.
⇒ chemical
Hydrogen is the least dense of all elements.
⇒ physical
Look at the graph.
If the price of peaches increases, what can be expected?
Answer:
The correct answer is B) Fewer peaches will be sold.
Explanation:
Hope this helps! :)
Candace is interested in learning more about colors. Which question about colors could be answered through scientific investigation? Which color bends the most to make a rainbow? What color of scented marker has the best smell? Which flower has the prettiest shade of purple on its petals? What is the best-looking color on a high-performance sports car?
Like all metals, copper is malleable. This property is related to the bonds in copper. Examine a straw and try to bend it. Is a straw a good model for showing the malleability
A computer is reading data from a rotating cd-rom. at a point that is 0.0130 m from the center of the disk, the centripetal acceleration is 393 m/s2. what is the centripetal acceleration at a point that is 0.0884 m from the center of the disc?
The formula relating acceleration and angular velocity is:
a = ω^2 r
where a is acceleration, ω is angular velocity and r is radius
But the angular velocity ω is constant all throughout the disk therefore:
a1 / r1 = a2 / r2
So at points:
r1 = 0.0130 m -> a1 = 393 m/s^2
r2 = 0.0884 m -> a2 = ?
393 / 0.0130 = a2 / 0.0884
a2 = 2,672.4 m/s^2
You push an object 0.032 m by exerting 0.010 N in force. The work is the force times the distance. How much work have you done expressed in ergs?
A. 3200 ergs
B. 0.00032 ergs
C. 0.32 ergs
D. 32 ergs
Answer:
Work done, W = 3200 ergs
Explanation:
It is given that
Force acting on the object, F = 0.01 N
Distance covered by the object, d = 0.032 m
Let W is the work done by the object. The product of force and the distance is called the work done by the object. Mathematically, it is given by :
[tex]W=F\times d[/tex]
[tex]W=0.01\ N\times 0.032\ m[/tex]
W = 0.00032 Joules
Since, [tex]1\ joule=10^7\ ergs[/tex]
This gives, work done by the object, W = 3200 ergs. So, the correct option is (a).
While hiking in the mountains, tanya observed a narrow and steep valley with a stream at the bottom of it. what most likely caused the valley to first form?
Final answer:
The narrow and steep valley with a stream at the bottom that Tanya observed was most likely formed primarily by tectonic activity, with subsequent shaping by erosion from streams and other processes such as wind and landslides.
Explanation:
Tanya most likely observed a valley that formed through tectonic activity, where over time, crustal tensions created narrow and steep valleys. These cracks may then have been further shaped by erosion from streams at the bottom, along with other processes such as wind and landslides. Such valleys are often further deepened and widened as water continues to erode the valley floor and sides. In some cases, valleys like this can also be created or shaped by the movement of glaciers, which carve out the terrain beneath them. However, the presence of the stream at the bottom of the valley Tanya observed suggests that water played a significant role in its formation.
A volleyball player’s hand applies a 39 N force while in contact with a volleyball for 2 seconds. What is the impulse on the ball?
Answer:
78 N - S
Explanation:
It is correct
What kind of mouse is a battery-powered mouse that uses radio waves or bluetooth technology to communicate with a device?
A wireless mouse is a battery-powered mouse that uses radio waves or bluetooth technology to communicate with a device.
Explanation:A battery-powered mouse that uses radio waves or bluetooth technology to communicate with a device is called a wireless mouse. A wireless mouse eliminates the need for a physical connection between the mouse and the device, allowing for greater freedom of movement. The mouse is powered by batteries and uses either radio waves or bluetooth technology to transmit signals to the device.
A car moving at a speed of 8.0 meters per second enters a highway and accelerates at 3.0 meters per second^2. How fast will the car be moving after it has accelerated for 56 meters?
Answer:
Final speed of the car, v = 20 m/s
Explanation:
It is given that,
Initial speed of the car, u = 8 m/s
Acceleration of the car, [tex]a=3\ m/s^2[/tex]
Let v is the speed of the car after it has accelerated for 56 meters. It can be calculated suing the third equation of motion. It is given by :
[tex]v^2-u^2=2ad[/tex]
[tex]v^2=u^2+2ad[/tex]
[tex]v^2=(8)^2+2\times 3\times 56[/tex]
v = 20 m/s
So, the car is moving after it has accelerated for 56 meters is 20 m/s. Hence, this is the required solution.
El thrust SSC es un vehiculo terrestre que en 1997 supero la velocidad del sonido.si logro recorrer 1366m en 4 s ¿cual fue su velocidad media en este intervalo?
1.Which of the following is an example of work?
A.Tim worked hard to carry a box of books across a room
B.A scientist works in the laboratory
C.Sam and Rachel worked hard to push the car but it did not move
D.Joann did work on a box when she pulled it across the floor
2.Joe carries his 5 kg cat 3 m horizontally across the living room. What is the net work done on the cat?
A. 0J
B. 15J
C. 150J
D. 180J
3.Which of the following is associated with an object in motion?
A.potential energy
B.nonmechanical energy
C.kinetic energy
D.elastic potential energy
4.Which of the following is associated with an object due to its position?
A.potential energy
B.positional energy
C.total energy
D.kinetic energy
5.What is kinetic energy of a 1000 kg truck moving at 32.0 m/s? *
A.1.2 x 10⁵ J
B.3.21 x 10⁵ J
C.5.12 x 10⁵ J
D.6.34 x 10⁵ J
Describe the motion of a biker as shown by the velocity time graph in figure 1b
The motion of a biker can be determined by analyzing the velocity-time graph. The slope of the graph indicates acceleration and the direction of motion.
Explanation:The motion of a biker as shown by the velocity-time graph in figure 1b can be determined by analyzing the graph. In the graph, the biker's velocity changes over time. The slope of the graph represents the acceleration of the biker. If the slope is positive, it indicates that the biker is accelerating in the positive direction. If the slope is negative, it indicates that the biker is decelerating or moving in the negative direction.
For example, if the graph shows a straight line with a positive slope, it means that the biker is accelerating at a constant rate in the positive direction. If the graph shows a curved line with an increasing slope, it means that the biker is accelerating at an increasing rate. Conversely, if the graph shows a curved line with a decreasing slope, it means that the biker is decelerating or slowing down.
By analyzing the velocity-time graph, we can understand how the biker's motion is changing over time and determine important aspects such as acceleration and direction of motion.
The air is less dense at higher elevations, so skydivers reach a high terminal speed. The highest recorded speed for a skydiver was achieved in a jump from a height of 39,000 m. At this elevation, the density of the air is only 4.3% of the surface density. Estimate the terminal speed of a skydiver at this elevation. Suppose that the density of air at sea level is 1.2 kg/m3, the mass of the skydiver is 75 kg , and the cross section area of the skydiver is 0.72 m2.
Answer: The terminal velocity of the skydiver is 281.30 m/s.
Explanation:
Mass of the sky diver = 75 kg
Density of the air at height of 39,000 m =4.3% of the surface density of the air
= [tex]1.2 kg/m^3\times \frac{4.3}{100}=0.0516 kg/m^3[/tex]
Cross sectional area of the sky diver , A = [tex]0.72 m^2[/tex]
Coefficient of drag ,C = 0.5
The terminal speed is given by the formula:
[tex]v_T=\sqrt{\frac{2mg}{c\rho A}}[/tex]
[tex]v_T=\sqrt{\frac{2\times 75 kg\times 9.8 m/s^2}{0.5\times 0.0516 km/m^3\times 0.72 m^2}}=281.30 m/s[/tex]
The terminal velocity of the skydiver is 281.30 m/s.
The terminal speed of the skydiver is [tex]\boxed{281.452{\text{ m/s}}}[/tex].
Further Explanation:
When a body falls from the sky it will accelerate continuously in the downward direction by the force of gravity results in increment in the acceleration. Another force is acting on the body is friction force due to air or the particles present in the atmosphere in the in the upward direction or opposite to the direction of motion also called drag force. The drag force is directly proportional to the square of the velocity of falling body. Therefore, with increase in the velocity the drag force also increasing which is proportional to equal to the square of the velocity of falling body. And time will come where the drag force is equal to the weight or the force of gravity results in zero resultant force means zero acceleration. At this point the speed become constant and reached its maximum velocity. This speed is called the terminal velocity.
Given:
The height of the jump is [tex]39000\text{ m}[/tex].
The density air is [tex]4.3\%[/tex] of the surface density.
The density of air at sea level is [tex]1.2{\text{ kg/}}{{\text{m}}^3}[/tex].
The mass of the skydiver is [tex]75\text{ kg}[/tex].
The cross sectional area of the skydiver is [tex]0.72{\text{ }}{{\text{m}}^2}[/tex].
Concept:
The expression for the terminal speed is:
[tex]\fbox{\begin\\{v_t} =\sqrt {\dfrac{{2mg}}{{\rho A{C_d}}}}\end{minispace}}[/tex] …… (1)
Here, [tex]{v_t}[/tex] is the terminal speed, [tex]m[/tex] is the mass of the skydiver, [tex]g[/tex] is the acceleration due to gravity, [tex]\rho[/tex] is the density, [tex]A[/tex] is the cross sectional area and [tex]{C_d}[/tex] is the drag coefficient.
The term [tex]g[/tex] is called acceleration due to gravity and it has a constant value of [tex]9.81{\text{ m/}}{{\text{s}}^2}[/tex] and the drag coefficient of a human in free fall is [tex]0.5[/tex].
The density of the air at the altitude of [tex]39000\text{ m}[/tex] is:
[tex]\rho=4.3\%\times{\rho _{air}}[/tex]
Here,[tex]\rho[/tex] is the density of the air at the altitude of [tex]39000\text{ m}[/tex] and [tex]{\rho _{air}}[/tex] is the surface density of the air.
Substitute [tex]1.2{\text{ kg/}}{{\text{m}}^3}[/tex] for [tex]{\rho _{air}}[/tex] in the above equation.
[tex]\begin{aligned}\rho&=4.3\%\times1.2{\text{ kg/}}{{\text{m}}^3}\\&=\frac{{4.3}}{{100}}\times1.2{\text{ kg/}}{{\text{m}}^3}\\&=0.0516{\text{ kg/}}{{\text{m}}^3}\\\end{aligned}[/tex]
Substitute [tex]0.0516{\text{ kg/}}{{\text{m}}^3}[/tex] for [tex]\rho[/tex], [tex]75\text{ kg}[/tex] for [tex]m[/tex], [tex]9.81{\text{ m/}}{{\text{s}}^2}[/tex] for [tex]g[/tex], [tex]0.72{\text{ }}{{\text{m}}^2}[/tex] for [tex]A[/tex] and [tex]0.5[/tex] for [tex]{C_d}[/tex] in equation (1).
[tex]\begin{aligned}{v_t}&=\sqrt{\frac{{2\left({75{\text{ kg}}}\right)\left( {9.81{\text{ m/}}{{\text{s}}^2}} \right)}}{{\left({0.0516{\text{ kg/}}{{\text{m}}^3}}\right)\left({0.72{\text{}}{{\text{m}}^2}} \right)\left( {0.5} \right)}}}\\ &=\sqrt{\frac{{1471.5}}{{0.018576}}}{\text{ m/s}}\\&=\sqrt{79215.116}{\text{ m/s}}\\&=281.452{\text{ m/s}}\\ \end{aligned}[/tex]
Therefore, the terminal speed of the skydiver is [tex]\boxed{281.452{\text{ m/s}}}[/tex].
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Answer Details:
Grade: High school
Subject: Physics
Chapter: Kinematics
Keywords:
Air, less, dense, higher, elevation, skydivers, reach high, terminal speed, recorded, achieved, jump, height, 39,000 m, density, air, 4.3%, surface density, estimate, sea, level, , mass, 75 kg, cross section, area, , 281.452 m/s.
An airplane is flying 340 km/hr at 12o east of north. the wind is blowing 40 km/hr at 34o south of east. what is the plane's actual velocity?
To find the airplane's actual velocity, vector addition is used by breaking down the airplane's and wind's velocities into their respective components and summing them up. Trigonometry and the Pythagorean theorem are used for the calculations.
Explanation:The student's question involves calculating the actual velocity of an airplane considering both its speed in a given direction and the effect of wind blowing in a different direction. This is a typical vector addition problem in physics where velocities are vectors; hence they have both magnitude and direction.
To compute the plane's actual velocity, you would break down the plane's and the wind's speeds into their north-south and east-west components and then add these components vectorially. The process uses trigonometric functions to determine the components and then applies the Pythagorean theorem to find the magnitude of the resultant velocity. The direction can be calculated using the arctangent function.
For example: An airplane with a velocity of 340 km/hr at 120° east of north can be broken down into an eastward component and a northward component. Similarly, the wind's velocity of 40 km/hr at 34° south of east would also have an eastward and a southward component. Adding or subtracting these components according to their directions will give the actual velocity of the airplane.
Give several examples of an object's motion is which a great distance is traveled but the displacement is zero
Two airplanes leave an airport at the same time. The velocity of the first airplane is 650 m/h at a heading of 60.5 ◦ . The velocity of the second is 560 m/h at a heading of 85◦ . How far apart are they after 2.9 h? Answer in units of m.
The distance between two airplanes that have flown in different directions for a certain period of time can be calculated using the principles of relative velocity and the law of cosines in vector operations.
Explanation:This question involves concepts of relative velocity and vector operation in physics. To find how far apart the two airplanes are after 2.9 hours, we first need to calculate how far each plane has traveled in their separate directions. The distance traveled by each airplane is calculated using the formula distance = speed x time.
For the first plane, the distance is 650 m/h x 2.9 h = 1885 m; And for the second plane, it's 560 m/h x 2.9 h = 1624 m. However, they've traveled these distances at different directions (angles). Hence, we then have to calculate the resultant distance between these two paths, which is a task of vector analysis. We'll use the law of cosines because the heading direction forms an angle between two vectors.
Using the Law of Cosines, the resultant distance, d can be found with the formula [tex]d^2 = D1^2 + D2^2 - 2*D1*D2*[/tex]cos(Δθ), where D1 and D2 are the distances traveled by each plane, and Δθ is the difference in their heading angles (85°-60.5°). Putting the distances and the angle in the formula will then give us the resultant separation between the two planes after 2.9 hours.
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Teams red and blue are having a tug-of-war. According to Newton's third law, the force with which the red team pulls on the blue team exactly equals the force with which the blue team pulls on the red team.How can one team ever win?
According to Newton's third law, the forces between the red and blue teams cancel each other out. However, the team that can exert a larger net force on the ground will be able to win the tug-of-war. Net force accounts for the forces between each team and the ground.
Explanation:According to Newton's third law of motion, the force with which the red team pulls on the blue team is exactly equal in magnitude and opposite in direction to the force with which the blue team pulls on the red team. So, it may seem like neither team can win because the forces cancel each other out. However, the key to understanding how one team can win lies in the concept of net force.
Net force is the vector sum of all the individual forces acting on an object. In the case of the tug-of-war, each team is exerting a force on the other, but they are also exerting a force on the ground. These ground forces are in opposite directions, but they are not equal in magnitude, as the ground provides more resistance to one team than the other.
Therefore, the team that can exert a larger net force on the ground will be able to accelerate in that direction and win the tug-of-war. It's not just about the forces between the teams, but also the forces between each team and the ground.
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