The molar mass of element X is determined in g/mol by taking into account the mole ratio in the X₂O₃ compound. The mass of X (1.0000 g) is first divided by the moles of X, which is two-thirds of the moles of Oxygen, calculated by dividing the mass of Oxygen in X₂O₃ by its molar mass.
Explanation:To calculate the molar mass of element X, the mole ratio in the X₂O₃compound needs to be considered. This mole ratio suggests that for every 1 mole of X, 1.5 moles of Oxygen is used given that from the formula of X₂O₃hat would be 2 moles of X for every 3 moles of oxygen (2:3).
The mass of Oxygen in the compound can be calculated by subtracting the mass of X from the total compound weight. Given that 1.1xxx grams of X₂O₃ was obtained from 1.0000 grams of X, the mass of Oxygen in the compound would be 1.1xxx g - 1.0000 g giving a mass of Oxygen in the compound as 0.1xxx grams.
We know that the molar mass of Oxygen (O) is 16.00 g/mol. So, the number of moles of Oxygen in the compound can be calculated as (0.1xxx g)/(16.00 g/mol) which gives the number of moles for Oxygen. Given the mole ratio from the X₂O₃ formula, the number of moles of X will be two-thirds of the moles of Oxygen.
Finally, the molar mass of X can be calculated by dividing the mass of X (1.0000 g) by the number of moles of X calculated. This will give the answer for the molar mass of X in g/mol.
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A 0.100 g sample of a carbon–hydrogen–oxygen compound is combusted in a stream of pure oxygen and produces 0.220 g co2 and 0.239 g h2o. what is the mass percent of hydrogen in the sample?
a.13.3
First we assume that the compound containing only C,H,and O is combusted completely in the presence of excess oxygen, so that the only things that can be produced are water and carbon dioxide.
From there we should back calculate the amount of Hydrogen that is in the original sample by taking all of the hydrogen in the 0.239g to came from the organic compound.
And since we know that the original mass of the sample was .100g, we can also easily get a mass % H by taking the mass Hydrogen calculated over the total original mass (.100 g)
So that:
0.239g H2O / (18.01 g/mol) = .01327 moles H20
.01327 Moles H20 * 2.02g H (per every mole H2O) = .0268g H initially present in the sample
.0268g H / .100g sample = 26.8% H by mass
The mass percent of hydrogen in the 0.1 g sample of compound containing carbon–hydrogen–oxygen is 26.6%
We'll begin by calculating the mass of the hydrogen in the compound. This can be obtained as follow:
Molar mass of H₂O = (2×1) + 16 = 18 g/mol
Molar mass of H₂ = 2 × 1 = 2 g/mol
Mass H₂O produced = 0.239 g
Mass of H =?Mass of H = [tex]\frac{2}{18} * 0.239[/tex]
Mass of H = 0.0266 gFinally, we shall determine the mass percent of Hydrogen in the compound. This can be obtained as follow:
Mass of H = 0.0266 g
Mass of compound = 0.1
Mass percent of H =?[tex]Percentage = \frac{mass}{mass of compound} * 100\\\\= \frac{0.0266}{0.1} * 100[/tex]
Mass Percent of H = 26.6%Thus, the mass percent of hydrogen in the sample is 26.6%
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Each of the diagrams below shows an electrically neutral atom. fill in the missing number of protons (n) neutrons (and), electrons (e), and atomic mass (m). then complete the questions in the space below
What is a substance that contains only a single type of atom
Ions how are ions made from neutral atoms worksheet answers
Final answer:
Ions are created when neutral atoms either lose or gain electrons, forming cations and anions, respectively. The periodic table helps predict the charges of ions depending on their group, where alkali metals form +1 cations, alkaline earth metals form +2 cations, and halogens form -1 anions. The formation of ionic compounds involves the combination of these oppositely charged ions to achieve electrical neutrality.
Explanation:
Ions are formed when atoms gain or lose electrons. When a neutral atom loses one or more electrons from its valence shell, it becomes a cation (a positive ion). Conversely, when it gains one or more electrons in its valence shell, it becomes an anion (a negative ion).
Charges of Ions and Ionic Compounds:
The periodic table can be a tool for predicting the charges of many ions based on their group. For instance, alkali metals form +1 ions, while alkaline earth metals form +2 ions. Halogens typically form -1 ions. Ionic compounds consist of these positive and negative ions in a ratio that balances their total charges, resulting in an electrically neutral compound.
Electron Configurations and Ion Charges:
It's important to note that ions only form through the movement of electrons, not protons. For elements within the same group on the periodic table, the number of valence electrons determines the common ion charge. Elements will either reach a stable electron configuration by losing or gaining electrons to form ions.
Write 266000 in scientific notation
which term best describes the rate at which glacial erosion takes place
The molecular mass of the compound is 90 amu. What is the molecular formula for C2H5O?
First let us get the molecular mass of the compound C2H5O.
C has molar mass of 12 amu, H is 1 amu, while O is 16 amu, therefore:
C2H5O = 12 amu * 2 + 1 amu * 5 + 16 amu = 45 amu
So to get 90 amu, simply double all the elements, therefore:
C4H10O2
Let us assume that the given formula of elements is empirical formula where elements have simplest whole number ratio
The empirical mass = 2 X atomic mass of carbon + 5 X atomic mass of hydrogen + at mass of O
The empirical mass = 2 X 12 + 5 + 16 = 45
The ratio of molecular mass and empirical mass = 90 / 45 = 2
Molecular formula is obtained by multiplying the empirical formula with this ratio / factor
molecular formula = 2 X (C2H5O) = C4H10O2
If 3.0 g of aluminum and 6.0 g of bromine react to form AlBr3, how many grams of product would theoretically be produced? How many grams of each reagent would remain at the end of this reaction?
What mass (in grams) of product would be collected if the reaction above proceeded in 72% yield?
Final answer:
To calculate the amount of AlBr3 produced from 3.0 g of Al and 6.0 g of Br2, first, the limiting reactant is determined, which is Al. The theoretical yield of AlBr3 is 29.61 g, with no bromine remaining and some aluminum unreacted. For a 72% yield, 21.3192 g of AlBr3 would be collected.
Explanation:
To calculate the theoretical yield of AlBr3 produced from 3.0 g of aluminum (Al) and 6.0 g of bromine (Br2), first, we need to determine the limiting reactant. The balanced chemical equation for the reaction is:
2 Al + 3 Br2 → 2 AlBr3
Using molar masses (Al = 26.98 g/mol, Br2 = 159.808 g/mol), we calculate the moles of each reactant:
Al: 3.0 g / 26.98 g/mol = 0.111 moles
Br2: 6.0 g / 159.808 g/mol = 0.0375 moles
Based on the stoichiometry of the equation, 2 moles of Al react with 3 moles of Br2, making aluminum the limiting reactant.
The theoretical yield of AlBr3 can be calculated using the molar ratio from the balanced equation, from which 0.111 moles of Al would produce 0.111 moles of AlBr3. The molar mass of AlBr3 (266.693 g/mol) gives us a mass of 29.61 g.
No bromine would remain as all of it reacts, but some aluminum will remain unreacted.
For a 72% yield, the actual yield of AlBr3 = theoretical yield × percentage yield = 29.61 g × 0.72 = 21.3192 g.
Please help! I’m on my last attempt
A 0.100-g sample of your favorite candy is burned in a calorimeter that contains 1.00 kg of water initially at 21.0 ∘C. After the candy is burned, the water temperature is 34.5 ∘C. How many Calories are there per gram of your candy?
A 2.07-g sample of an iron–aluminum alloy (ferroaluminum) is dissolved in excess HCl(aq) to produce 0.100 g H2(g).
Fe(s)+2HCl(aq)→FeCl2(aq)+H2(g)
2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g).
What is the percent composition, by mass, of the ferroaluminum?
Final answer:
The percent composition of Fe in the ferroaluminum alloy is approximately 33.82%.
Explanation:
To find the percent composition of the ferroaluminum, we need to determine the mass of iron and aluminum in the alloy. Based on the balanced chemical equations given, 1 mole of Fe is produced for every 2.07 g of the alloy, and 3 moles of H2 are produced for every 2.07 g of the alloy. From the molar mass of Fe (55.85 g/mol) and H2 (2.02 g/mol), we can calculate the mass of Fe and H2 produced. So, the percent composition of Fe in the alloy is:
mass of Fe / mass of ferroaluminum × 100%
= (0.70 g / 2.07 g) × 100%
= 33.82%
Therefore, the percent composition of Fe in the ferroaluminum is approximately 33.82%.
For the reaction 6 Li + N2 → 2 Li3N , what is the maximum amount of Li3N (34.8297 g/mol) which could be formed from 14.18 mol (6.941 g/mol) of Li and 16.37 mol of N2 (28.0134 g/mol)? Answer in units of mol.
The reaction is limited by the amount of Lithium available. With the given amount of Lithium and Nitrogen gas, the maximum amount of Li3N that could be produced is 4.726 moles.
Explanation:The question is looking for the maximum amount of Li3N that can be produced from given amounts of Li and N2. According to the chemical equation 6 Li + N2 → 2 Li3N, six moles of Li react with one mole of N2 to produce two moles of Li3N. Hence, the Li:N2:Li3N mole ratio is 6:1:2. If you have 14.18 moles of Li and 16.37 moles of N2, the reaction is limited by Li because it would require 16.37 moles of N2 to entirely consume 98.22 moles of Li (16.37 moles * 6). But since you only have 14.18 moles of Li, this will limit the formation of Li3N. Therefore, the maximum amount of Li3N that could be produced is 2/6 * 14.18 moles, which equals to 4.726 moles of Li3N.
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How do chemical weathering and the formation of biochemical sediment remove carbon from the atmosphere and store it in the geosphere?
Chemical weathering and the formation of biochemical sediment remove carbon from the atmosphere by releasing carbon dioxide through the breakdown of rocks. This carbon dioxide can then be stored in the geosphere as biochemical sediments.
Explanation:Chemical weathering and the formation of biochemical sediment play a crucial role in removing carbon from the atmosphere and storing it in the geosphere. Chemical weathering refers to the breakdown of rocks and minerals through chemical reactions, which releases carbon dioxide into the atmosphere. This carbon dioxide can then be dissolved in water and can react with other compounds to form biochemical sediments, such as calcium carbonate. These sediments eventually become part of the geosphere, storing carbon for long periods of time.
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A new element is discovered that is very unstable and highly reactive, and it likes to lose its one valence electron. in what group should this element be placed in? explain.
Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon monoxide gas, CO?
A. the mass
B. the volume
C. the number of molecules
D. the number of oxygen atoms
If a sample containing 2.50 ml of nitroglycerin (density=1.592g/ml) is detonated, how many total moles of gas are produced?
What volume would 4 moles of gas occupy at stp? do this without a calculator. you may need to use longhand calculations. the question is designed to tolerate reasonable rounding?
The box holds 70 cm3 of water. Water has a density of 10 g/cm³. What is the mass of the water
Iki indicator tests for the presence of which substance? benedict's reagent tests for the presence of which substance?
Iki also known as Lugol's solution, is an indicator used to test for the presence of starch. Benedict's reagent is used to test for the presence of reducing sugars, such as glucose and fructose
Lugol's solution is a yellow-brown solution that turns blue-black in the presence of starch.
Benedict's reagent is a clear blue solution that changes color to green, yellow, orange, or red, depending on the amount of reducing sugar present. Benedict's test is commonly used in the laboratory to detect the presence of reducing sugars in various substances.
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An atom contains one proton, one electron, and one neutron. Which two partials are most similar in mass?
The very common mineral shown in this photograph is commonly a pink- to cream-colored mineral with wavy, light-colored lines. it does not effervesce. what mineral is it?
Which interaction is a direct result of chemical weathering?
A.
root pry
B.
ice wedging
C.
wave action on beaches
D.
rust forming on rocks
The interaction which is a direct result of chemical weathering is rust
forming on rocks.
What is Chemical weathering?Chemical weathering involves the interaction of rocks with chemical
substances such as minerals. In this process, the composition of the rocks
are usually changed.
Rusts forms on rocks during this process which hastens the breakdown of
rocks into tiny particles.
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which element on the periodic table contains 5 valence electrons and is a metalloid
The number of atoms in 8.93 g of zinc ?
Zinc has a molar mass of about 65.38 g/mol. So we calculate the number of moles first:
moles Zinc = 8.93 g / (65.38 g/mol) = 0.1366 mol
We can calculate for the number of atoms using Avogadros number.
atoms Zinc = 0.1366 mol * 6.022 x 10^23 atoms / mol
atoms Zinc = 8.23 x 10^22 atoms
If electrons were used in the two slit experiment instead of light, what change would need to be made to the slit spacing in order to see a diffraction pattern?
What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP
Answer: 3808 ml
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atm respectively.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{4.03}{24}=0.17moles[/tex]
[tex]2Mg+O_2\rightarrow 2MgO[/tex]
2 moles of magnesium react with= [tex[2\times 22.4=44.8L[/tex] of oxygen at STP
Thus 0.17 moles of magnesium react with=[tex]\frac{44.8}{2}\times 0.17=3.8L=3808ml[/tex]
Thus the volume of oxygen required to react with 4.03 g of magnesium at STP is 3808 ml.
A scientist has discovered a new molecular compound that is a long chain of 26 carbons bonded together, with a methyl group on one end and an acid group on the other end of the molecule. the compound does not contain any nitrogen or sulfur atoms. based on this information, the compound is a(n) _____.
The compound described is a fatty acid with a chain of 26 carbons, known as hexacosanoic acid, unless there are unsaturations not mentioned in the question.
Based on the information provided, the compound with a long chain of 26 carbons, a methyl group on one end, and an acid group on the other end, and without any nitrogen or sulfur atoms, can be regarded as a fatty acid. Fatty acids are carboxylic acids with long hydrocarbon chains. With 26 carbons, this compound can be considered a type of saturated or unsaturated fatty acid, depending on whether there are any double bonds in the hydrocarbon chain. The methyl group (CH3) indicates the end of the hydrocarbon chain, which is known in organic chemistry as the omega (ω) end. The acid group is the carboxylic acid functional group (COOH) at the other end of the molecule. Since the longest chain in this question is 26 carbons in length, with no double bonds mentioned, we might name it using the prefix for 26 carbons, which would be 'hexacos', followed by 'anoic acid' for the acid group, resulting in hexacosanoic acid. However, without more details on the nature of the hydrocarbon chain (specifically, its saturation), this nomenclature could change.
Assume that 50.0 cal of heat is applied to a 15 g sample of sulfur at 20°C. What is the final temperature of the sample if the specific heat of sulfur is 0.175 cal/(g • °C)?
100 ml of soft drink A contains 75g of sugar and weighs 110g. calculate density
The density of soft drink A is indeed 0.35 g/ml.
Given:
Mass of the soft drink (including sugar) = 110 g
The volume of the soft drink = 100 ml
Mass of sugar = 75 g
First, we need to find the mass of just the liquid (excluding the sugar), then we can calculate the density.
Mass of liquid = Total mass of soft drink - Mass of sugar
= 110 - 75
= 35 g
Now we can calculate the density:
Density = Mass ÷ Volume
Density = 35 ÷ 100
Density = 0.35 g/ml
The density of soft drink A is indeed 0.35 g/ml.
The main reasons why h2co has a higher vapor pressure at a given temperature when compared to ch3oh is that h2co