Evaluate the expression for s = 11 and v = 8.

(s – v)2


A. 113
B. 6
C. 9
D. 57

Answer: D. 2

Step-by-step explanation:

Final answer:

There are 2600 different possible student IDs when a student ID consists of one letter followed by two digits that can repeat, calculated as 26 possible letters multiplied by 10 possible digits for each of the two digit positions.

Explanation:

The question asks how many different student IDs are possible if an ID consists of a letter followed by two digits, with the digits being allowed to repeat. To calculate the possible combinations, we multiply the number of options for each component of the ID. There are 26 letters in the alphabet and 10 possible digits (0-9) for each of the two positions that follow the letter, allowing for repetition.

The calculation is therefore 26 letters × 10 digits × 10 digits = 2600 possible combinations. Each component is independent of the others, so this follows the fundamental principle of counting in combinatorics.

volume =  l x w x h

area 1 = 3 x 1.5 x 2 = 9 cubic feet

area 2 = 2 x 1.5 x 2 = 6 cubic feet

area 3 = 1.5 x 1 x 2 = 3 cubic feet 

9+6+3 = 18 cubic feet total

The volume of Podium is:  18 cubic feet.

The volume of Podium is equal to the volume of 3 cuboids of different heights.

We know that a volume of cuboid with length l, width b and height h is given by:

Volume= l×b×h

Hence,

Volume of cuboid numbered as 3 is:

Volume= 1×2×1.5= 3 cubic feet.

Volume of cuboid numbered as 2  is:

Volume=2×2×1.5=6 cubic feet.

Similarly volume of cuboid numbered as 1 is:

Volume= 3×1.5×2=9 cubic feet.

             Hence, the Volume of Podium is:

                          3+6+9=18 cubic feet.

Answer:

240 fluid ounces

Step-by-step explanation:

A health clinic has [tex]3\frac{1}{2}[/tex] quarts and 1 gallon of antiseptic wash in inventory.

We have to convert the unit of fluid in ounces.

1 quart = 32 ounces

1 gallon = 128 ounces

[tex]3\frac{1}{2}[/tex] quarts = [tex]3\frac{1}{2}[/tex] × 32 = 112 ounces

Total fluid of antiseptic wash = 112 + 128 = 240 fluid ounces

They have 240 fluid ounces of antiseptic wash in hand.

The polar form for the given expression is sin(θ)=3r−3rsin²(θ)

To convert the equation y = 3x² into polar form, we substitute[tex]\( x = r\cos(\theta) \) and \( y = r\sin(\theta) \)[/tex], where R is the radius and theta is the angle.

[tex]So, \( y = 3x^2 \) becomes:\[ r\sin(\theta) = 3(r\cos(\theta))^2 \][/tex]

Now, we can simplify this equation:

[tex]\[ r\sin(\theta) = 3r^2\cos^2(\theta) \]\[ r\sin(\theta) = 3r^2\cos^2(\theta) \]\[ \frac{r\sin(\theta)}{r^2} = 3\cos^2(\theta) \]\[ \frac{\sin(\theta)}{r} = 3\cos^2(\theta) \]\[ \frac{\sin(\theta)}{r} = 3(1 - \sin^2(\theta)) \]\[ \frac{\sin(\theta)}{r} = 3 - 3\sin^2(\theta) \]\[ \sin(\theta) = 3r - 3r\sin^2(\theta) \][/tex]

This equation describes the curve in polar coordinates.

Final answer:

To find the time at which the weight first reaches the equilibrium position, set the equation of motion equal to zero and solve for t.

Explanation:

The equation of motion for the weight suspended from the spring is given by p(t) = 2sin(t/3) + 5cos(t/3), where p(t) is the displacement from the equilibrium position in centimeters and t is the time elapsed in seconds. The weight first reaches the equilibrium position when the displacement p(t) equals zero. To find the time at which this occurs, we set the equation equal to zero and solve for t.

2sin(t/3) + 5cos(t/3) = 0

Using trigonometric identities, we can rewrite the equation as:

2sin(t/3) = -5cos(t/3)

Dividing both sides by cos(t/3), we get:

2tan(t/3) = -5

Therefore, to find the time at which the weight first reaches the equilibrium position, we need to solve the equation 2tan(t/3) = -5 for t.

Answer:

no, because the initial 180 gets in the way

Step-by-step explanation:

32% = 0.32

300 * 0.32 =96

 Answer is A

Answer:

answer = 60

Step-by-step explanation:

It might be option A or D. Mine was D

When all sides of a quadrilateral are transformed, the resulting quadrilateral  will be similar to the transformed quadrilateral. The fourth side of ABCD is 6 feet

We have the lengths of ABCD in descending order to be:

[tex]Side\ 1 = 24[/tex]

[tex]Side\ 2 = 16[/tex]

[tex]Side\ 3 = 12[/tex]

We have the lengths of EFGH in ascending order to be:

[tex]Side\ 4 = 9[/tex]

[tex]Side\ 3 = 18[/tex]

The missing side of ABCD is the fourth side, and it can be solved using the following equivalent ratios:

Side 4 : Side 3 of ABCD = Side 4: Side 3 of EFGH

Substitute the values of the known sides

[tex]Side\ 4 : 12 = 9 : 18[/tex]

Express as fraction

[tex]\frac{Side\ 4 }{ 12} = \frac{9}{ 18}[/tex]

Multiply both sides by 12

[tex]Side\ 4 = \frac{9}{ 18} \times 12[/tex]

[tex]Side\ 4 = \frac{1}{2} \times 12[/tex]

[tex]Side\ 4 = 6[/tex]

Hence, the fourth side of ABCD is 6 feet

Read more about similar quadrilaterals at:

https://brainly.com/question/85384

The hypergeometric distribution describes the probability of a certain number of successes in samples taken without replacement from a finite population, not an infinite one as stated in the question.

The hypergeometric distribution is a statistical model used to calculate probabilities in experiments where samples are drawn without replacement from a finite population. Unlike the statement presented in the question, the hypergeometric distribution is not used for infinite populations nor for sampling with replacement; that would be the domain of the binomial distribution.

Event E and event F are not independent because:

        [tex]P(E\bigcap F)\neq P(E)\times P(F)[/tex]

We know that two event A and event B are said to be independent if:

         P(A∩B)=P(A)×P(B)

Here we have two events as E and F such that:

[tex]P(E\bigcap F)=\dfrac{1}{8}[/tex]

[tex]P(E)=\dfrac{1}{2}[/tex]

and [tex]P(F)=\dfrac{1}{3}[/tex]

This means that:

[tex]P(E)\times P(F)=\dfrac{1}{2}\times \dfrac{1}{3}\\\\\\i.e.\\\\\\P(E)\times P(F)=\dfrac{1}{6}\neq P(E\bigcap F)[/tex]

        Hence, the events E and F are not independent.