Exactly 1/20 of the students in mr.perez's class has a bird. what percentage of his students has a bird.

Answers

Answer 1

1/20 is equal to 5/100, meaning 5% have a bird

Related Questions

a garden table and a bench cost 817 dollars combined. The garden table costs 83 less than the bench. what is the cost of the bench

Answers

table=t
bench=b

t=b-83

t+b=817
b-83+b=817
2b=900
b=450 ($)

"Non nobis, Domine, non nobis, sed Nomini tuo da gloriam."

Regards M.Y.

$10,000 is invested at two different rates. $2,500 is invested at 4%, and the rest is invested at 5%. How much interest is earned at the end of one year? Show all work for full credit.

Answers

hmm is very straight forward, how much is whatever% of anything? is just (whatever/100) * anything.

[tex]\bf \textit{4\% of 2,500}\implies \cfrac{4}{100}\cdot 2,500\implies 100 \\\\\\ \textit{the rest is 7,500 at 5\%, what's 5\% of that?}\implies \cfrac{5}{100}\cdot 7,500\implies 375[/tex]

An animal shelter has a total of 350 animals comprised of cats, dogs, and rabbits. If the number of rabbits is 5 less than one-half the number of cats, and there are 20 more cats than dogs, how many cats are at the shelter?

Answers

This is the concept of algebra, suppose that the number of cats is x;
number of cats will be x-20
number of rabbits will be 3/2x
thus the total number of animals will be:
x+(x-20)+3/2x=350
7/2x=350+20
7/2x=370
x=370*2/7
x=105.7=106
therefore we conclude that there we 106 cats in the shelter

Final answer:

To find the number of cats at the animal shelter, we can set up and solve a system of equations using the given information. In this case, the number of dogs is 126 and the number of cats is 146.

Explanation:

To solve this problem, let's assign variables to represent the number of cats, dogs, and rabbits at the shelter. Let's say the number of cats is 'c', the number of dogs is 'd', and the number of rabbits is 'r'.

From the given information, we can form three equations:

The total number of animals is 350: c + d + r = 350The number of rabbits is 5 less than one-half the number of cats: r = (1/2)c - 5There are 20 more cats than dogs: c = d + 20

Using these equations, we can solve for the value of 'c' (the number of cats).

By substituting the value of 'c' from equation 3 into equation 2, we get:

r = (1/2)(d + 20) - 5

Now, we substitute the values of 'c' and 'r' from equations 3 and 1 into equation 1:

(d + 20) + d + ((1/2)(d + 20) - 5) = 350

Simplifying this equation, we get:

2d + (1/2)d + 35 = 350

Combining like terms, we have:

4d + d + 70 = 700

Simplifying further, we find:

5d + 70 = 700

Subtracting 70 from both sides of the equation, we get:

5d = 630

Dividing both sides by 5, we find that d = 126. Therefore, there are 126 dogs at the shelter.

Finally, by substituting the value of d back into equation 3, we find:

c = 126 + 20 = 146. Thus, there are 146 cats at the shelter.

Learn more about Solving Systems of Equations here:

https://brainly.com/question/29050831

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A journal entry for the sale of $10 par common stock for $18 per share would include
a. a credit to Cash
b. a debit to common stock
c. a credit to Paid in Capital in Excess of Par-Common Stock
d. a debit to Paid in Capital n Excess of Par-Common Stock

Answers

credit to paid in capital in excess of par-common stock. the word stock in the question instantly removes a and b there is no debit so c or d but i would go with c. just cause d is missing an i in one of its 'in'

A $28,000 car loan is used to purchase a new car. The loan is for 6 years and has a 5.75% APR. Use the amortization formula to determine the amount of the monthly payments.

Answers

[tex]\bf \qquad \qquad \textit{Amortized Loan Value} \\\\ pymt=P\left[ \cfrac{\frac{r}{n}}{1-\left( 1+ \frac{r}{n}\right)^{-nt}} \right][/tex]

[tex]\bf \qquad \begin{cases} P= \begin{array}{llll} \textit{original amount}\\ \end{array}\to & \begin{array}{llll} 28,000 \end{array}\\ pymt=\textit{periodic payments}\\ r=rate\to 5.75\%\to \frac{5.75}{100}\to &0.0575\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{payments are monthly, thus} \end{array}\to &12\\ t=years\to &6 \end{cases} \\\\\\ pymt=28000\left[ \cfrac{\frac{0.0575}{12}}{1-\left( 1+ \frac{0.0575}{12}\right)^{-12\cdot 6}} \right][/tex]

WILL GIVE BRAINLIEST...
You have 45 ft of the fence you enclose your yard, you are going to use the side of your house as one of the sides and put a fence down the width of the yard so your dog as a place to play, the length is three less than the width. What is the area of your yard?

Answers

We have 45 ft of the fence and we are going to use the side of the house as one of the sides ( on length ).
L = W - 3
2 W + L = 45
2 W + W - 3 = 45
3 W = 45 + 3
3 W = 48
W = 48 : 3
W = 16 ft
L = 16 - 3 = 13 ft
A = 16 * 13 = 208 ft²
Answer: The area of the yard is 208 ft².

(03.03 HC)

The table shows the outputs, y, for different inputs, x:

Input (x) 6 12 15 25
Output (y) 14 15 15 16

Part A: Do the data in this table represent a function? Justify your answer. (3 points)

Part B: Compare the data in the table with the relation f(x) = 7x − 15. Which relation has a greater value when x = 6? (2 points)

Part C: Using the relation in Part B, what is the value of x if f(x) = 6? (5 points)

Answers

part A the table does not show function because 15 is repeated which is a relationship.

The equation d=13/v shows that the density of a particular substance equals a mass of 13 grams divided by the volume of the substance. What happens to the density as the volume approaches 0?

Answers

d = M/V where M=mass and V = volume

Assume the Mass is 1 kg and the Volume = 1 cm³, so d= 1/1 kg/cm³

for V=0.1 → d = 1/0.1 = 10 kg.cm³
for V = 0.01 → d = 100.kg.cm³
for V = 0.001 → d = 1000.kg.cm³
for V = 0.000001 → d = 1,000,000.kg.cm³
and when Volume → 0. density →∞
.

Answer: the density approaches infinity

Step-by-step explanation:

Two people are traveling and need to exchange the currency of their native country for the currency of the country they are visiting. drag each exchange to match the ratio of currency to currency in each category.

Answers

Answer:

The solution is shown in attached figure.

Step-by-step explanation:

In table 1,