Find the distance between 0,3 and -2-5 round nearest hundreth

Answer:

New coordinates are (-2, -3)

Step-by-step explanation:

First we need the centre coordiates. In (x - a)² + ( y - b)² = r² , a is the x coordinate for the circle centre and b is the y coordinate for the circle centre, so this means the coordinate of the circle centre is:

(3 , -4)

If moving to the left 5 spaces, then 5 has to be subtracted from the x coordinate:

3 - 5 = -2

Now moving one up you add one to the y coordinate:

-4 + 1 = -3

So the new coordinates are (-2, -3)

The unit for kinetic energy, when mass is in grams and velocity is in centimeters per minute, is D) grams-centimeters squared per minute squared.

The formula for kinetic energy is given by KE = 1/2 mv², where m represents mass and v represents velocity. To find the units of kinetic energy, we need to plug in the units of mass and velocity into the formula.

If m is measured in grams (g) and v is measured in centimeters per minute (cm/min), the units for velocity squared will be (cm/min)². Therefore:

KE = 1/2 (grams) (centimeters/minute)²

When we square velocity (cm/min), we get cm²/min². Thus, the units for kinetic energy become:

D) grams-centimeters squared per minute squared (g∙cm²/min²)

2A on 2A + 3B + 3C = 8 pieces

The probability:

[tex]\dfrac{2}{8}=\dfrac{2:2}{8:2}=\dfrac{1}{4}[/tex]

[tex]\dfrac{1}{4}=\dfrac{1}{4}\cdot100\%=25\%[/tex]

Answer:c is the answer

Step-by-step explanation:

Answer:

C. m∠Y = 100°

Step-by-step explanation:

Answer:

-67.2

Step-by-step explanation:

Simplify the given expression (−3.5)(−3)(−6.4)

WE apply PEMDAS rule to simplify it

Lets start with parenthesis part

We multiply first two parenthesis

(−3.5)(−3)

Negative and negative becomes positive

(−3.5)(−3) is 10.5

Now we multiply it with -6.4. Positive times negative is negative.

[tex]10.5 \cdot (-6.4)= -67.2[/tex]

[tex](-3.5)(-3)(-6.4)=-67.2[/tex]

If the 4 states have to be in a specific order say ABCD, then the total number of different possible routes is:

 43P4 = 2,961,840

So the probability is:

1 / 2,961,840 = 3.38 x 10^-7

But if the 4 states can be in any order such as DBAC, ACBD etc, then the total number of different possible routes is:

 43C4 = 123,410

So the probability is:

1 / 123,410 = 8.1 x 10^-6

No I don’t think it is practical to list all the different possible routes to select the one that is best. We can simply use mathematical models to solve for that one.

The contrapositive of 'If v≥4, then v≤4' is not true because it would imply 'If v>4, then v<4', which is logically inconsistent.

No, the contrapositive of the given conditional statement 'If v≥4, then v≤4' is not true. This is because the contrapositive of a conditional statement is always logically equivalent to the original statement. The contrapositive inverts and negates both the hypothesis and the conclusion. So the contrapositive of the original statement would be 'If v>4, then v<4', which does not hold true as a statement can't be both greater and less than 4 at the same time.

Contrapositive is the term used when the implication and its converse are both negated. In the context of the given conditional statement, this practice does not validate the original statement.

Final answer:

You could read the time on a tritium-based watch in dark places for approximately 34.87 years before the tritium decays below 18% of its original amount, necessitating this calculation using first-order kinetics and the half-life of tritium (12.32 years).

Explanation:

To calculate how many years you could read the time at night with a watch containing tritium, we need to understand first-order kinetics and the half-life of tritium.

Tritium has a half-life of 12.32 years, meaning after 12.32 years, half of the original tritium remains.

The question specifies that a minimum of 18% of the original tritium is needed for readability in dark places.

To find the number of years you could read the time, we use the formula for first-order decay:

[tex]N = N_0(1/2)^{(t/T)[/tex],

where N is the final amount of substance left, N_0 is the initial amount of substance, t is the time in years, and T is the half-life (12.32 years in this case).

We rearrange the formula to solve for t:

t = T*log(N/N_0)/log(1/2).

Plugging in the values, assuming N/N_0 = 0.18 (18%), and T = 12.32 years, we get:

t = 12.32*log(0.18)/log(1/2) ≈ 34.87 years.

Therefore, you could read the time on a tritium-based watch in dark places for approximately 34.87 years before the tritium decays below the level necessary for visibility.

The total number of teeth in a shark's mouth can theoretically be determined by multiplying the number of teeth in a single row by the total number of rows of teeth. The multiplication will be defined by the particular shark species.

Assuming that we want to find out the total number of teeth in a shark's mouth and we know the number of teeth in one row (coded as t), we would need to multiply this number by the number of rows of teeth in the shark's mouth. For instance, if a shark has two rows of teeth, the total number of teeth would be 2t.

It is important to recognize that each species of shark might have a different number of rows of teeth, so without specifying the particular species, the exact total of teeth can't be computed but it would still be 't' times the number of rows. But in general, a Sand Tiger Sharks like Carcharias Taurus for example, can have around 3 to 7 rows of teeth.

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The given equation is:

x y – 5000 = y

Rewrite this to create an explicit equation:

x y – y = 5000

y ( x – 1) = 5000

y = 5000 / (x – 1)

Derive to get dy / dx:

dy = - 5000 dx / (x – 1)^2

dy / dx = - 5000 / (x – 1)^2

So plugging in x = 6,

dy / dx = - 5000 / (6 – 1)^2

dy / dx = - 200

Answer:

[tex]\frac{dy}{dx}|_{x=6}= -200[/tex]

Step-by-step explanation:

Given : Demand equation [tex]xy − 5,000 = y[/tex]

To Find [tex]\frac{dy}{dx}|_{x=6}[/tex]

Solution :

[tex]xy- y= 5000[/tex]

[tex]y(x-1)= 5000[/tex]

[tex]y= \frac{5000}{x-1}[/tex]

Differentiating with respect to x

[tex]\frac{dy}{dx}= \frac{-5000}{(x-1)^2}[/tex]

Now substitute x = 6

[tex]\frac{dy}{dx}|_{x=6}= \frac{-5000}{(6-1)^2}[/tex]

[tex]\frac{dy}{dx}|_{x=6}= \frac{-5000}{5^2}[/tex]

[tex]\frac{dy}{dx}|_{x=6}= \frac{-5000}{25}[/tex]

[tex]\frac{dy}{dx}|_{x=6}= -200[/tex]

Hence [tex]\frac{dy}{dx}|_{x=6}= -200[/tex]  =T-shirts per dollar

I believe we are to find for values in this problem.

a. The graph of the function

b. The domain and range

c. The slope

d. The c intercept value

Answers:

a. see the graph photo attached

b. The domain is the set of all x that can be input to the function. Since x is the distance and we know that distance cannot be negative hence the domain is:

x ≥ 0

So the range starts from x = 0:

c (x) = 0.5 * 0 + 70 = 70

Therefore the range is:

c ≥ 70

Domain: x ≥ 0                     Range: c ≥ 70

c. A linear equation has a general form of:

y = mx + b

where m is the slope

From the given equation, the slope is 0.5.

slope = 0.5

d. The c intercept is simply the value of c when x is equal to 0

c intercept = 70

Answer:Given function: c(x) = 0.5x+70.Where c is the cost (in dollars) and x is the number of miles you drive the truck.If we compare given function by slope-intercept form y=mx+b, we get Slope m = 0.5 in fractions could be written as 1/2.And y-intercept b =70.So, in order to graph it, we need to plot y-intercept at 70 first and then plot some more points using rise/run = 1/2.The red line is the graph for the given function.We can see that starting value of cost is $70 for 0 number of miles.x values represents domain and C(x) represents range.We can take x values greater than or equal to 0 and C values greater than equal to 70.Therefore, Domain: x≥0 and Range : C(x) ≥ 70.

Step-by-step explanation:Credit:User named PiaDeveau thanks for providing the answer and hope this helps

:)

multiply 4/5 by 10

4/5 * 10 = 40/5 = 8 inches total

The missing mean square (MS) for the treatment is 252.64, and there were 6 blocks used in the experiment. The p-value is less than 0.01, indicating a statistically significant effect of the treatment.

To fill in the blanks of the ANOVA table provided, we will perform some calculations. The mean square (MS) for the treatment can be found by dividing the sum of squares (SS) for the treatment by its degrees of freedom (df). Hence, for the treatment:

MS treatment = SS treatment / df treatment = 1010.56 / 4 = 252.64

Given that the total df equals 29 and the df for treatment and error sum up to 24 (4 + 20), the df for blocks will be:

df total - df treatment - df error = 29 - 4 - 20 = 5

Therefore, the number of blocks used in this experiment equals the df for blocks plus 1, giving us:

Number of blocks = df blocks + 1 = 5 + 1 = 6 blocks

As for the p-value associated with the F-statistic, we cannot calculate the exact value, but it is indeed lower than the conventional alpha levels (0.05, 0.01). So we describe the p-value as being less than 0.01

Conclusions:

With an F-statistic of 29.84 and a p-value much lesser than conventional alpha levels, we can conclude that there is a statistically significant effect of the treatment on the outcome variable.

The specific p-value bounds are not provided, but given that it is very low, the results are statistically significant. Thus, we can reject the null hypothesis that there is no effect of the treatment.

Final answer:

An equivalent fraction for 4/21 can be found by multiplying the numerator and denominator by the same non-zero number, such as 2 to get 8/42.

Explanation:

An equivalent fraction for 4/21 is a fraction that has the same value but is expressed with different numerator and denominator. To find an equivalent fraction, you can multiply or divide both the numerator and denominator by the same non-zero number. For example, if we multiply the numerator and denominator by 2, we will get 8/42, which is an equivalent fraction to 4/21. It's important to note that this new fraction can be simplified further, just like 4/21 can be simplified to its lowest terms if there were any common factors.

The data on student heights and weights suggests a strong positive correlation, implying that as a student's height increases, their weight tends to increase as well.

The data provided on student's heights and weights suggests a linear relationship. To complete the sentences based on the data:

The data seems to have a correlation coefficient close to positive one. This indicates that the weight of a student increases as the height of the student increases.

In statistics, when we observe that as one variable increases, the other also increases, we describe this as a positive correlation. A positive correlation coefficient closer to +1 implies a strong positive correlation, meaning that generally taller students in the given data set tend to weigh more.

Final answer:

The correlation coefficient for the given data is approximately 0.86, indicating a positive correlation between height and weight.

Explanation:

The data seems to have a correlation coefficient close to 0.86. This indicates that the weight of a student increases as the height of the student increases.

The sum of b and c is equal to 54.

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.

Given is the following quadratic equation -

x² - 6x + 66

x² - 6x + 9 - 9 + 66

x² - 3x - 3x + 9 - 9 + 66

x(x - 3) - 3(x - 3) - 9 + 66

(x - 3)² + 57

The given form of resultant is -

(x + b)² + c

On comparing, we get -

b = - 3

c = 57

Therefore -

b + c = -3 + 57 = 54

Therefore, the sum of b and c is equal to 54.

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Answer:

I just got it right the answer is 9:6

Step-by-step explanation: