Find the nth term of this quadratic sequence:
4, 7, 12, 19, 28

Answer:

y = -5x + 39

Step-by-step explanation:

Plug either ordered pair into the Point-Slope Formula FIRST, y - y₁ = m(x - x₁), then convert to Slope-Intercept Form by moving whichever term is nearest to y, over to the right side of the equivalence symbol to get the above answer.

Answer:

22

Step-by-step explanation:

Solve the inequality  (20 + 0.5x) + 0.15(20 + 0.5x)   ≤ $62.10 for x:

20 + .5x + 3 + 0.75x ≤ 62.10

Combining the x terms, we get:

20 + 3 + 1.25x ≤ 62.10.

Combining the constants on the left:

23 + 1.75x ≤ 62.10

Combining the constants:

1.75x = 39.10

Solving for x:  39.10/1.75 = 22.34

Thus, the max number of whole pages she can have in her book is 22.

Answer:

22

Step-by-step explanation:

For this case we must simplify the following expression:

[tex]\sqrt [5] {\frac {10x} {3x ^ 3}}[/tex]

We rewrite the expression as:

[tex]\sqrt [5] {\frac {10x} {x * 3x ^ 2}} =[/tex]

We eliminate common factors:

[tex]\sqrt [5] {\frac {10} {3x ^ 2}} =\\\frac {\sqrt [5] {10}} {\sqrt [5] {3x ^ 2}}[/tex]

We multiply the numerator and denominator:

[tex](\sqrt [5] {3x ^ 2}) ^ 4:\\\frac {\sqrt [5] {10}} {\sqrt [5] {3x ^ 2}} * \frac {(\sqrt [5] {3x ^ 2}) ^ 4} {(\sqrt [5] {3x ^ 2}) ^ 4} =[/tex]

\frac {\ sqrt [5] {10} * (\sqrt [5] {3x ^ 2}) ^ 4} {\sqrt [5] {3x ^ 2} * (\sqrt [5] {3x ^ 2} ) ^ 4} =

[tex]\frac {\sqrt [5] {10} * (\sqrt [5] {3x ^ 2}) ^ 4} {(\sqrt [5] {3x ^ 2}) ^ 5} =\\\frac {\sqrt [5] {10} * (\sqrt [5] {3x ^ 2}) ^ 4} {3x ^ 2} =[/tex]

[tex]\frac {\sqrt [5] {10} * \sqrt [5] {(3x ^ 2) ^ 4}} {3x ^ 2} =\\\frac {\sqrt [5] {10} * \sqrt [5] {81x ^ 8}} {3x ^ 2} =\\\frac {\sqrt [5] {10} * \sqrt [5] {81x ^ 5 * x ^ 3}} {3x ^ 2} =[/tex]

[tex]\frac {\sqrt [5] {10} * x \sqrt [5] {81x ^ 3}} {3x ^ 2} =\\\frac {x \sqrt [5] {810x ^ 3}} {3x ^ 2}[/tex]

Answer:

[tex]\frac {x \sqrt [5] {810x ^ 3}} {3x ^ 2}[/tex]

[tex]\frac {\sqrt [5] {810x ^ 3}} {3x}[/tex]

Answer:

The simplified form is [tex]\frac{\sqrt[5]{810 x^{3}}}{3x}[/tex]

Step-by-step explanation:

we need to simplify the value of x in given expression:

[tex]\sqrt[5]{\frac{10x}{3x^{3}}}[/tex]

Re- write the above as,

[tex]\sqrt[5]{\frac{10}{3x^{2}}}[/tex]

[tex]\frac{\sqrt[5]{{10}}}{\sqrt[5]{3x^{2}}}[/tex]

Multiply numerator and denominator by [tex](\sqrt[5]{3x^{2}})^{4}[/tex]

[tex]\frac{\sqrt[5]{{10}}}{\sqrt[5]{3x^{2}}} \times \frac{(\sqrt[5]{3x^{2}})^{4}}{(\sqrt[5]{3x^{2}})^{4}}[/tex]

[tex]\frac{\sqrt[5]{{10}}{\sqrt[5]{(3x^{2}}})^4}{{3x^{2}}}[/tex]

[tex]\frac{\sqrt[5]{{10}}{\sqrt[5]{81x^{8}}}}{{3x^{2}}}[/tex]

[tex]\frac{x \sqrt[5]{810 x^{3}}}{3x^{2}}[/tex]

[tex]\frac{\sqrt[5]{810 x^{3}}}{3x}[/tex]

Hence, the simplified form is

[tex]\frac{\sqrt[5]{810 x^{3}}}{3x}[/tex]

Answer:

P = 2x + 2y + 14

Step-by-step explanation:

Length (L) = x + 8 units

Width (W) = y - 1 units

Perimeter (P) = 2L + 2W

P = 2(x + 8) + 2(y - 1)

P = 2x + 16 + 2y - 2

P = 2x + 2y + 16 - 2

P = 2x +2y + 14

Answer:

P = 2x + 2y + 14

Step-by-step explanation:

Answer: 26%

Step-by-step explanation:

See attached photo. - my answer got deleted lol

Without additional information, we cannot determine the exact percentage of students age 15 and above who travel to school by bus.

To find the percentage of students age 15 and above who travel to school by bus, we need to compare the number of students who travel by bus to the total number of students in that age group. However, we don't have that information in the given question.

We need more data to calculate the percentage. Without additional information, we cannot determine the exact percentage of students age 15 and above who travel to school by bus.

Answer:

B. 14x^3+39x^2+18x+20

Step-by-step explanation:

Given polynomials are:

[tex](7x^2+2x+4)(2x+5)\\For\ product\\(2x+5)(7x^2+2x+4)\\= 2x(7x^2+2x+4)+5(7x^2+2x+4)\\= 14x^3+4x^2+8x+35x^2+10x+20\\Combining\ alike\ terms\\= 14x^3+4x^2+35x^2+8x+10x+20\\=14x^3+39x^2+18x+20[/tex]

The product of given polynomials is:

14x^3+39x^2+18x+20

Hence, Option B is correct ..

Answer:

B.  14x^3 + 39x^2 + 18x + 20.

Step-by-step explanation:

(7x^2 + 2x + 4)(2x + 5)

= 2x(7x^2 + 2x + 4) + 5(7x^2 + 2x + 4)

Distribute over the 2 parentheses:

= 14x^3 + 4x^2 + 8x + 35x^2 + 10x + 20

Add like terms:

= 14x^3 + 39x^2 + 18x + 20.

The integer that represents the change in temperature is -16°F.

To find the change in temperature, we need to calculate the difference between the final temperature and the initial temperature.

The initial temperature was 6°F, and the final temperature was -10°F. To calculate the change, we subtract the initial temperature from the final temperature:

Change in temperature

= Final temperature - Initial temperature

                             = (-10°F) - (6°F)

                             = -10°F - 6°F

                             = -16°F

Therefore, the integer that represents the change in temperature is -16°F.

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Answer:

a) Equation: 9x+9 = 72

b) x =7

Step-by-step explanation:

The total cost of 9 bracelets = $72

Shipping charge = $9

a) Define your variable and write an equation that models the cost of each bracelet.

Let x be the cost of one bracelet, the equation will be

9x + 9 = 72

As 9 bracelets were there and the shipping cost was 9 and total cost was 72.

b) Use the equation you have written above determine the cost for each bracelet. Show the algebraic steps that it takes to find the answer.

Now solving the equation to find the value of x that represent cost of each bracelet

9x + 9 = 72

Adding -9 on both sides

9x +9 -9 = 72 -9

9x = 63

Dividing both sides by 9

9x/9 = 63/9

x = 7

The value of x=7 so, the cost of each bracelet is $7

c) Provide your conclusion.

So, each bracelet was of cost $7 and $9 was the shipping charge. so, the total cost is $72.

We would check whether our equation is satisfied.

9x+ 9 = 72

9(7) + 9 = 72

63 + 9 = 72

72 = 72

The equation is satisfied.

Answer:

The cost of each bracelet is: $7

Step-by-step explanation:

Let's call x the cost of each bracelet.

Then the cost of the 9 bracelets is:

9x

If we know that the cost of the bracelets plus the shipping was $ 72 and the cost of shipping is $ 9.

So

The total cost was:

[tex]9x + 9 = 72[/tex]

Now we solve the equation for the variable x.

[tex]9x + 9 = 72[/tex]

Subtract 9 on both sides of equality

[tex]9x + 9-9 = 72-9[/tex]

[tex]9x = 72-9[/tex]

[tex]9x = 63[/tex]

Divide by 9 on both sides of equality

[tex]\frac{9}{9}x = \frac{63}{9}[/tex]

[tex]x = \frac{63}{9}[/tex]

[tex]x = \$7[/tex]

Neither the reflection over the y-axis nor the 270° counterclockwise rotation would map figure ACB onto itself.

To determine whether a reflection over the y-axis and a 270° counterclockwise rotation would map figure ACB onto itself, we need to analyze the effects of these transformations.

Therefore, neither the reflection over the y-axis nor the 270° counterclockwise rotation would map figure ACB onto itself.

Answer: y=-2x+2/4

Step-by-step explanation:

Answer:

y + 4 =1/2 (x + 4)

Step-by-step explanation:

Your welcome uwu

Answer:

Second option: y = 8x-3

Step-by-step explanation:

The equation tha satisfies the given values will be the required linear equation

So,

y = 8x + 45

For x=3 and y=21

21 = 8(3) +45

21 = 24+45

21≠69

As this equation is not satisfied by the values, it is not the correct option..

For y = 8x-3

x=3,y=21

21 = 8(3)-3

21 = 24-3

21=21

x=5, y=37

37 = 8(5)-3

37=40-3

37=37

x=7, y=53

53 = 8(7)-3

53 = 56-3

53 = 53

As the equation is true for all values of x and y. This is this correct option..

Answer:

Point-slope equations:

y - 5 = 4/3 (x - 6)

or

y - 1 = 4/3 (x - 3)

Step-by-step explanation:

Given two coordinate points (6, 5) and (3, 1)

Slope = (5 - 1)/(6 - 3) = 4/3

Point-slope equations:

y - 5 = 4/3 (x - 6)

or

y - 1 = 4/3 (x - 3)

Two point-slope equations for the line passing through the points

(6, 5) and (3, 1) are,

Here, the line passes through the points (6,5) and (3,1).

Let,

[tex]$$(6,5)=\left(x_{1}, y_{1}\right)$$[/tex]

[tex]$(3,1)=\left(x_{2}, y_{2}\right)$[/tex]

Substitute

Slope(m) = [tex]\frac{1-5}{3-6}=\frac{-4}{-3}[/tex]

Slope(m) =[tex]\frac{4}{3}[/tex]

Point-slope equations of the line passing through [tex]$(6,5 \6})$[/tex] and [tex](3}, 1)$[/tex]

Substitute[tex]$m=4 / 3$[/tex], and [tex]$(a, b)=(6,5)$[/tex]into [tex]$y-b=m(x-a)$[/tex]

[tex]y-5=\frac{4}{3}(x-6)[/tex] (point-slope equation)

Substitute[tex]$m=4 / 3$[/tex], and [tex]$(a, b)=(3,1)$[/tex] into [tex]$y-b=m(x-a)$[/tex]

[tex]$y-1=\frac{4}{3}(x-3)$[/tex] (point-slope equation)

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Answer:

C

Step-by-step explanation:

-567.45 + 567.45 = 0

Answer:

Choice B

Step-by-step explanation:

Formula for slope:

[tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex]

[tex]y_2 = 1\\y_1 = -10\frac{2}{3} \\\\x_2 = -3\\x_1 = 4[/tex]

[tex]1 - (-10\frac{2}{3}) = 11\frac{2}{3} \\-3 - 4 = -7[/tex]

[tex]\frac{-11\frac{2}{3} }{-7} = \frac{5}{3} = 1\frac{2}{3}[/tex]

Answer:

Q1: 2nd row 2nd tile

Q2: 1st row 1st tile

Q3: 1st row 3rd tile

Q4: 2nd row 3rd tile

Step-by-step explanation:

When

[tex]y = a {(x + p)}^{2} + q[/tex]

Vertex is (-p, q)

Answer:

[tex](-1,-\frac{3}{7} )-->f(x)=\frac{1}{2}|x+1|-\frac{3}{7}\\(5,\frac{2}{3} )-->f(x)=\frac{3}{5}|x-5|+\frac{2}{3}\\(0,-\frac{4}{5} )-->f(x)=\frac{1}{2}|x|-\frac{4}{5}\\(\frac{2}{5},\frac{5}{3} )-->f(x)=\frac{3}{2}|x-\frac{2}{y5}|+\frac{5}{3}[/tex]

Step-by-step explanation:

We can solve all of them by writing the equations in a general form

[tex]f(x)=a|x+b|+c[/tex]

This is a function transformation of

[tex]f(x)=|x|[/tex]

where:

a=Factor of vertical stretch

b=Horizontal shift (- shifts right, + shifts left)

c=Vertical shift (+ shifts right, - shifts left)

The original function has its vertex in [tex](0,0)[/tex] so the horizontal shift will be the new x coordinate in the new vertex and the vertical shift will be the new y in the new vertex like this:

[tex]f(x)=\frac{1}{2}|x+1|-\frac{3}{7}\\b=1=HorizontalShiftof-1\\c=-\frac{3}{7}=VerticalShiftof-\frac{3}{7}\\(-1,-\frac{3}{7})\\f(x)=-\frac{3}{5}|x-5|+\frac{2}{3}\\b=-5=HorizontalShiftof5\\c=\frac{2}{3}=VerticalShiftof\frac{2}{3}\\(5,\frac{2}{3})\\f(x)=\frac{1}{2}|x|-\frac{4}{5}\\b=0=HorizontalShiftof0\\c=-\frac{4}{5}=VerticalShiftof\frac{4}{5}\\(0,-\frac{4}{5})\\f(x)=-\frac{3}{2}|x-\frac{2}{5}|+\frac{5}{3}\\b=-\frac{2}{5}=HorizontalShiftof\frac{2}{5}\\c=\frac{5}{3}=VerticalShiftof\frac{5}{3}\\(\frac{2}{5},\frac{5}{3})[/tex]

Answer:

Total length of the x inches long pieces = 4x inches

She has to cut another piece = 7.75 inches

Total length = 4x + 7.75

This is what y represent, so

y = 4x + 7.75

The graph of the equation is continuous

Answer:

The required equation is [tex]y=4x+7.75[/tex] and the graph of the equation is continuous.

Step-by-step explanation:

Consider the provided information.

Julie needs to cut 4 pieces of yarn,

Let x  represent the length of each yarn.

Then the length of 4 pieces will be: 4x

y represents the total length of all of the yarn that Julie decides to cut

Therefore the required equation that can be used to determine the total length of all of the yarn is:

[tex]y=4x+7.75[/tex]

Here, the graph is continuous, because the length of yarn can be any number.

Answer:

M(t) = 0.1t3 + 5(1.07)t - 5

Step-by-step explanation:

Answer:

[tex]M(t) = 0.1t^{3}[/tex] [tex]+ 5(1.07)^{t}[/tex]- 5

Step-by-step explanation:

(on attachment with step by step explanation)

Answer:

We need to know angle C which is (180 -123 -34) = 23°

We'll use the Law of Sines

Sine (A) / side a = Sine (B) / side b

Sine (34) / 10 = Sine (123) / side b

0.55919 / 10 = 0.83867 / side b

10 * .83867 / .55919 = side b

side b (or line AC) = 14.998

Step-by-step explanation:

Final answer:

The dog’s movement 5 seconds after the command, considering different frames of reference for speed, can be described by the distance it would have traveled: either 25 meters on the sidewalk (at 5 m/s) or 10 meters from the student's perspective (at 2 m/s).

Explanation:

The student's question pertains to describing the dog’s movement 5 seconds after the command was given, considering the dog's speed. Since we have learned that the dog has different speeds in different frames of reference—5 m/s on the sidewalk and 2 m/s in the student’s frame—we can describe the dog’s movement based on these speeds. If the dog started moving at the moment the command was given and continued to move for 5 seconds, we can calculate the distance it would have covered in that time.

For the sidewalk's frame, where the dog's speed is 5 m/s, the dog would have covered a distance of:

Distance = Speed × Time

Distance = 5 m/s × 5 s = 25 meters

In the student’s frame, where the dog's speed is 2 m/s, it would have moved:

Distance = 2 m/s × 5 s = 10 meters

The statement that could describe the dog’s movement 5 seconds after the command was given is that the dog could have traveled either 25 meters from its starting point on the sidewalk or 10 meters from the student's perspective, depending on the frame of reference being considered.

Answer:

r = 7

Step-by-step explanation:

The common ratio r of a geometric sequence is

r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{a_{3} }{a_{2} }[/tex], that is

r = [tex]\frac{21}{3}[/tex] = [tex]\frac{147}{21}[/tex] = 7

The common ratio of the sequence 3, 21, 147 is 7.

Start with the first and second terms:
21 ÷ 3

= 7

Confirm with the second and third terms:
147 ÷ 21

= 7

Thus, the common ratio (r) is 7.

Answer:

[tex]\sqrt{98}[/tex]

Step-by-step explanation:

Using the distance formula

with (x₁, y₁ ) = (- 4, 2) and (x₂, y₂ ) = (3, - 5)

d = [tex]\sqrt{(3+4)^2+(-5-2)^2}[/tex]

  = [tex]\sqrt{7^2+(-7)^2}[/tex]

  = [tex]\sqrt{49+49}[/tex]

  = [tex]\sqrt{98}[/tex]

C= [tex]\sqrt{98}[/tex]

We could say that the square root or the square cancel each other out. They are a inverse of each other. If we have the number written with the index two ( squared) then taking the square root simply means that we leave out the two ( this only applies on the positive numbers ).

Using the distance formula

with (x₁, y₁ ) = (- 4, 2) and (x₂, y₂ ) = (3, - 5)

[tex]d= \sqrt{(3+4)^{2} +(-5-2)^{2}} \\\\= \sqrt{7^{2} + (-7)^{2}} \\\\= \sqrt{49+49} \\\\=\sqrt{98}[/tex]

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Answer:

D

Step-by-step explanation:

g(x)=f(5x)

this means plugging in 5x for x in f(x):

g(x)=f(5x)=(5x)^2

which can be further simplified:

5^2x^2=25x^2

Since the coefficient of x being larger means a vertical stretch, the answer is D

example:

g(2)=f(5*2)=f(10)=f(10^2)=100

so for g(x), it has the coordinates (2,100), which is most definitely not C

The graph of g(x) = f(5x) is a parabola that is narrower than the graph of f(x) by a factor of 1/5, with the vertex remaining the same.

The graph of g(x) = f(5x) can be obtained by substituting 5x for x in the function f(x) = x^2. So, g(x) = f(5x) = (5x)^2 = 25x^2. This means that the graph of g(x) is a parabola that is narrower than the graph of f(x) by a factor of 1/5. The vertex of the parabola remains the same, but the x-values and the y-values are scaled.

For this case we have by definition, that the equation of a line in the point-slope form is given by:

[tex](y-y_ {0}) = m (x-x_ {0})[/tex]

Where:

m: It's the slope

[tex](x_ {0}, y_ {0}):[/tex] It is a point through which the line passes.

[tex]m = \frac {y2-y1} {x2-x1}[/tex]

We have as data two points, replacing:

[tex]m = \frac {1-6} {0 - (- 5)}\\m = \frac {1-6} {0 + 5}\\m = \frac {-5} {5}\\m = -1[/tex]

We substitute a point, then the equation is:

[tex](y-1) = - 1 (x-0)\\(y-1) = - x[/tex]

Answer:

[tex](y-1) = - x[/tex]

Answer: [tex]y-6=-(x+5)[/tex]

Step-by-step explanation:

The Point-slope form of the equation of the line is:

[tex]y-y_1=m(x-x_1)[/tex]

Where "m" is the slope of the line and [tex](x_1,y_1)[/tex] is a point on the line.

We know that this line passing through the points (-5,6) and (0,1), then we can find the slope with this formula:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Substituting, we get:

 [tex]m=\frac{1-6}{0-(-5)}=-1[/tex]

Finally, we can substitute the point (-5,6) and the slope into  [tex]y-y_1=m(x-x_1)[/tex], then:

[tex]y-6=-(x-(-5))[/tex]

[tex]y-6=-(x+5)[/tex]

Answer:

.5

Step-by-step explanation:

4/2   -n=3n

2      -n=3n

2          =4n

2/4      =n

.5        =n

Answer:

D. 9/4 ÷ 3/4

Step-by-step explanation:

In the question, the number line represents 9/4 divided into 3 equal units.

The size of each unit is 3/4 as shown.

Showing that 3/4 divides 9/4 into 3 divisions:

9/4 ÷ 3/4

= 9/4 x 4/3

= 9/3 x 4/4

= 9/3 x 1

= 3 x 1

= 3

Hence, the number line represents three divisions given by 9/4 ÷ 3/4.

Answer:

y=3x+8, :m=3, b=8

Hope this helps!

The line y - 5 = 3(x + 1) in the form of slope intercept is y = 3x + 8 and slope of the line is 3, y-intercept is 8.

A straight line is a combination of endless points joined on both sides of the point.

The slope 'm' of any straight line is given by:

[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have a line:

y - 5 = 3(x + 1)

In slope intercept form:

y = 3x + 3 + 5

y = 3x + 8

Thus, the line y - 5 = 3(x + 1) in the form of slope intercept is y = 3x + 8 and slope of the line is 3, y-intercept is 8.

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Answer:

Add 6 to both sides.

Step-by-step explanation:

You are trying to solve for x in this type of question. In this case, note that there is a equal sign, and that what you do to one side you do to the other. Also note that to isolate the x (your goal), you must do the opposite of PEMDAS. (Note that PEMDAS = Parenthesis, Exponent (& Roots), Multiplication, Division, Addition, Subtraction).

So your first step is to add 6 to both sides.

2/5x - 6 (+6) = -16 (+6)

Simplify. Solve:

2/5x + (-6 + 6) = -16 + 6

2/5x = -10

_________________________________________________________

Finish finding for x.

Multiply the recipricol of the fraction to both sides to isolate the x. Multiply 5/2 to both sides:

(5/2)(2/5)x = (-10)(5/2)

x = (-10)(5/2)

x = (-50)/2

x = -25

x = -25 is your answer.

~

Answer:

Step-by-step explanation:

4 square root 5