Find the probability of a couple having a baby girlgirl when their fourthfourth child is born, given that the first threethree children were all girlsall girls. assume boys and girls are equally likely. is the result the same as the probability of getting all girlsall girls among fourfour children?

Answers

Answer 1

Every single time a person has a baby, it has a 50% chance of being a boy or a girl. Having 3 girls previously will not change anything. These events are independent. So the probability of having a baby girl given that the first 3 were girls is 50% or 1/2 or 0.5.

However, prior to having any kids, the probability of having all girls among 4 children is : 1.2 * 1/2 * 1/2 * 1/2 = 1/16...so the result are different.

Related Questions

Simplify: 6/3-y -2/y

Answers

Since 6/3=2, we could make it 2-y-2/y. If we wanted everything over y, we could make it (2y-y^2-2)/y by multiplying both 2 and y with y. This is not factorable due to that nothing multiplies to -2 and adds up to 2.

any ideas friends? cant seem to figure this out

Answers

I = 7.6*10^(-4) is the given intensity of the sound
Io = 10^(-12), which is a constant usually shown in a table or in your book

Plug in those values to get
B = 10*log(I/Io)
B = 10*log((7.6*10^(-4))/(10^(-12)))
B = 88.808135922808
B = 88.81

Answer: Approximately 88.81 decibels

The perimeter of a square is in p inches. Write expressions, in terms of p, for the length of the side of the square and the area of the square.

Answers

square has 4 sides of equal length
if the side length is p then the perimiter (distance around) is 4 times the length of the side or 4 times p or 4p

the area is side times side but since all sides are equal length, side^2 is the aera

perimiter=4p
area=p²

(07.03 LC)

The steps below show the incomplete solution to find the value of p for the equation 4p − 2p + 4 = −1 + 21:

Step 1: 4p − 2p + 4 = −1 + 21
Step 2: 4p − 2p + 4 = 20
Step 3: 2p + 4 = 20

Which of these is most likely the next step?
2p = 5
2p = 8
2p = 16
2p = 24

Answers

Step 1: 4p − 2p + 4 = −1 + 21
First they combined like terms on one side.

Step 2: 4p − 2p + 4 = 20
Then they combined like terms on the other side.

Step 3: 2p + 4 = 20
Now you have to subtract 4 from both sides.

Step 4: 2p = 16

So the answer is C. 2p = 16

It's 2p = 16. You subtract 4 from both sides.
2p+4=20
-4=-4
2p = 16

Mario and Luigi want to purchase some extra controllers for their friends.each controller costs 29.99. Use an algebraic expression to describe how much they spend in total,before sales tax,based on purchasing the console(299.00)the number of games(59.99 each) and the number of extra controllers

Answers

How many controllers do they need

i cant answer this question because it doesnt say how many friends they have

A regular pyramid has a height of 12 centimeters and a square base. if the volume of the pyramid is 256 cubic centimeters, how many centimeters are in the length of one side of its base

Answers

Let the length of one side of the base square be a cm.

The Volume of a pyramid is [tex] \frac{1}{3}*area_b_a_s_e *height[/tex]

the area of the base is a^2,

we apply the formula

[tex]256= \frac{1}{3}*a^{2}*12 [/tex]

[tex]256= 4a^{2} [/tex]

[tex]256= (2a)^{2} [/tex]

[tex]2a= \sqrt{256}=16[/tex]

a=8 (cm)

Answer: 8 cm

Dr. Black is standing 15 feet from the streetlamp. The lamp is making his shadow 8 feet long. He estimates that the angle of elevation from the tip of his shadow to the top of the streetlamp is 50°. To the nearest foot, the streetlamp is about _______

Answers

use tangent because tangent is opposite over adjacent ( to remember sin cos and tan use the phrase "Oscar Has A Hairy Old Asss")
the angle is from his shadow so use (15+8) as the adjacent side
so tan(50)=x/23
so tan(50)(23)=x
so x=about 27 feet

Help with geometry...

Answers

so... doing the distances from ABC to GHI

[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) A&({{ 1}}\quad ,&{{ 2}})\quad % (c,d) G&({{ -4}}\quad ,&{{ 2}})\\ B&({{ 2}}\quad ,&{{ 3}})\quad % (c,d) H&({{ -3}}\quad ,&{{ 3}})\\ C&({{ 3}}\quad ,&{{ 1}})\quad % (c,d) G&({{ -2}}\quad ,&{{ 1}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\[/tex]

[tex]\bf -------------------------------\\\\ AG=\sqrt{(-4-1)^2+(2-2)^2} \\\\\\ BH=\sqrt{(-3-2)^2+(3-3)^2} \\\\\\ CG=\sqrt{(-2-3)^2+(1-1)^2}[/tex]

and doing the distances from ABC to DEF

[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) A&({{ 1}}\quad ,&{{ 2}})\quad % (c,d) D&({{ 1}}\quad ,&{{ -1}})\\ B&({{ 2}}\quad ,&{{ 3}})\quad % (c,d) E&({{ 2}}\quad ,&{{ 0}})\\ C&({{ 3}}\quad ,&{{ 1}})\quad % (c,d) F&({{ 3}}\quad ,&{{ -2}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}[/tex]

[tex]\bf -------------------------------\\\\ AD=\sqrt{(1-1)^2+(-1-2)^2} \\\\\\ BE=\sqrt{(2-2)^2+(0-3)^2} \\\\\\ CF=\sqrt{(3-3)^2+(-2-1)^2}[/tex]

now... the ABC to JKL... surely you'd know how to do... the same way, just use the distance formula

Is the number of fish caught during a fishing tournamentnumber of fish caught during a fishing tournament discrete or continuous?

Answers

Final answer:

The number of fish caught in a fishing tournament is a discrete variable, as it can only take specific or separate values which are whole numbers, not fractions or decimals.

Explanation:

The number of fish caught during a fishing tournament would be considered a discrete variable in mathematics. This is because discrete variables are variables that can only take specific or separate values.

In this case, you can't catch half a fish or 2.3 fish in a tournament, you can only catch whole fish. This makes the number of fish caught a discrete variable because the count can only be in whole numbers. This is different from a continuous variable, such as the amount of time spent fishing or the weight of the fish caught, which could take on any value within a given range.

Learn more about Discrete Variable here:

https://brainly.com/question/28397043

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the lines shown below are perpendicular. if the green line has a slope of 3/4, what is the slope of the red line
a)4/3
b)-3/4
c)-4/3
d) 3/4

Answers

perpendicular slope is opposite and reciprocal

the green line has a slope of 3/4
so the slope of the red line is -4/3

answer
c)-4/3

The slope of the red line is -4/3. Therefore, option C is the correct answer.

Given that, the green line has a slope of 3/4.

We need to find the slope of the red line.

What is the formula to find the slope of the perpendicular line?

The formula for the slope of perpendicular lines is m1.m2 = -1. The product of the slopes of perpendicular lines is equal to -1.

Since, m1=3/4.

Now, 3/4.m2 = -1

⇒m2 =-4/3

The slope of the red line is -4/3. Therefore, option C is the correct answer.

To learn more about the slope visit:

https://brainly.com/question/3605446.

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Jan is twice as old as her sister betty, but half of joe's age. betty just got married. how old is joe most likely to be?

Answers

For this algebraic problem, you have to assign variables so you can formulate equations to help you solve the problem. Let x be the age of Jan, y be the age of Betty and z be the age of Joe. You are to find the value of z. The equations would be:

x = 2y and x = 0.5z

Equating this two yields 2y = 0.5z. There are two variables but only one equation. Therefore, you have to specify one of the variables to be able to solve this problem. It was mentioned that Betty just got married. Let's assume that Betty's age was around 30 years old. Then, it follows that y=30. Substituting this to the final equation,

2(30) = 0.5z
z = 120 years old

This is impossible. Betty must have been married at an early age. Let's assume that Betty is 18 years old, then

2(18) = 0.5z
z = 72 years old

If Betty was 18 years old, then Joe is 72 years old. This is only an illustration to the problem. You must have introduced Betty's age to know the exact answer for Joe's age.

Simplify 15 to the 18th power over 15 to the 3rd power.

Answers

(15^18) / (15^3)

If the exponents you're dividing have the same base, you subtract them.
18 - 3 = 15

15^15

[tex] \cfrac{15^{18}}{15^3} = 15^{18-3}=15^{15}[/tex]

how to factor 6x^2+5x+1

Answers

Here you go, explains how to do it and your answer.

A hypothesis is only tentative: to make sure it's valid, you have to ___________.

Answers

a hypothesis is only tentative: to make sure it's valid, you have to test it.

B is the midpoint of AC, D is the midpoint of CE. BD=10, and AE =2x. Find the length of CE if CD =3x

Answers

There is a theorem that states that the line joining two midpoints in a triangle is always parallel to the third side and its length is half the length of the third side.

Since B is midpoint of AC and D is midpoint of CE, therefore, BD is parallel to AE and BD = 0.5 AE
AE = 2 BD = 2 x 10 = 2x
Therefore, x= 10

D is the midpoint of CE and CD = 3x, therefore CE = 6x where x = 10
Based on this, CE = 6 x 10 = 60 units of length

In how many ways can 50 cards be chosen from a standard deck of 52 cards?

Answers

The answer must take into account that the order is irrelevant, that is that it is the same J, Q, K that Q, K, J, and K, J, Q and all the variations of those the three cards.

The number of ways you can draw 50 cards from 52 is 52*51*50*49*48*47*...4*3 (it ends in 3).
,
But the number of ways that those 50 cards form the same set repeats is 50! = 50*49*49*47*....3*2*1

So, the answer is (52*51*50*49*48*....*3) / (50*49*48*...*3*2*1) = (52*51) / 2 = 1,326.

Note that you obtain that same result when you use the formula for combinations of 50 cards taken from a set of 52 cards:

C(52,50) = 52! / [(50)! (52-50)!] = (52*51*50!) / [50! * 2!] = (52*51) / (2) = 1,326.

Answer: 1,326

Bruce had an EKG to measure his heartbeat rate. After conversion, the function produced could be modeled by a cosine function, and the wave produced a maximum of 4, minimum of −2, and period of pi over 2. Which of the following functions could represent Bruce's EKG read-out?
f(x) = 4 cos pi over 2x − 2
f(x) = 3 cos 4x + 1
f(x) = 3 cos pi over 2x + 1
f(x) = 4 cos 4x − 2

Answers

y= a.cos (bx) + midline

a = Amplitude = |4+2}/2 = |3|

Period = 2π/b = (2π) / (π/2) = 4

midline = (4-2)/2 = 1

Then the equation is:

y=3.cos(4x) + 1

Answer:

Option B.

Step-by-step explanation:

Bruce had an EKG to measure his heartbeat rate. After conversion, the function produced was modeled by a cosine function.

Now we will form this function.

Function will be in the form of f(x) = a cos(Bx) + d

Amplitude [tex]a=\frac{Maximum-minimum}{2}[/tex]

[tex]a=\frac{4+2}{2}=3[/tex]

Period = π/2

And [tex]Period=\frac{2\pi }{B}[/tex]

⇒[tex]\frac{\pi }{2}=\frac{2\pi }{B}[/tex]

⇒ B = 4

Since minimum is (-2) and maximum is (4), means cosine graph was shifted upwards.

Mid line of the graph is [tex]x=\frac{4+2}{2}=3[/tex] which shows graph is shifted by one unit above the x-axis.

Now the function we get is f(x) = 3 cos4x + 1

Therefore option B is the answer.

Write the equation of a circle with center (-2,3) and a radius of 4. Show all work to receive credit.

Answers

The equation of the circle is given by:
(x-a)^2+(y-b)^2=r^2
where:
(a,b) is the center of the circle
given that the center of our circle is (-2,3) with the radius of 4, the equation will be:
(x+2)^2+(y-3)^2=4^2
expanding the above we get:
x^2+4x+4+y^2-6y+9=16
this can be simplified to be:
x^2+4x+y^2-6y=16-13
x^2+y^2+4x-6y=3

What is the value of n in the equation –(2n + 4) + 6 = –9 + 4(2n + 1)?

Answers

Final answer:

The value of n in the equation –(2n + 4) + 6 = –9 + 4(2n + 1) is -2. This is determined by simplifying and solving the given expression for n.

Explanation:

To find the value of n in the equation –(2n + 4) + 6 = –9 + 4(2n + 1), we need to simplify and solve for n. First, we distribute the negative sign and the 4 into the parentheses and then combine like terms:

-2n - 4 + 6 = -9 + 8n + 4

Now, we combine the constants:

-2n + 2 = -5 + 8n

To isolate n, we move all the terms involving n to one side and the constants to the other:

-2n - 8n = -5 - 2

-10n = -7

Finally, we divide by -10 to solve for n:

n = ⅔

Thus, the value of n is -2.

Write the function in vertex form, and identify its vertex. g(x) = 5x2 - 50x + 128

Answers

hello :
g(x) = 5x² - 50x + 128
= 5(x²-10x +128/5)
= 5 (x²-10x+5²-5² +128/5)
= 5 ((x-5)² +128/5 -125/5)
y = 5 ((x-5)² - 3/5)
y= 5(x-5)² +3.....vertex form
the vertex is : (5,3)

Bob is driving along a straight and level road toward a mountain. At some point on his trip, he measures the angle of elevation to the top of the mountain and finds it to be 21°44'. Find the height of the mountain to the nearest foot if Bob is 13,428.7 feet from the center of the mountain at the base.
A. 5453 ft
B. 5353 ft
C. 53,534 ft
D. 535,342 ft

Answers

tan 21 44 = h / 13428.7
h = 13428.7 * tan 21 44

Height = 5353 feet

Answer:

Option B is the correct answer.

Step-by-step explanation:

The arrangement is given in the below figure.

We have height of the mountain = x

We also have

[tex]tan(21^044')=\frac{x}{13428.7}\\x=5352.98ft[/tex]

Height of the mountain to the nearest foot = 5353 ft

Option B is the correct answer.

0=2x+3(3x-4)-(-x+14)

Fraction answer need help!!!

Answers

0=2x+3(3x-4)-(-x+14)
Follow BEDMAS
0=2x+9x-12-(-x+14)
0=2x+9x-12+x-14
Add like terms
0=11x-12+x-14
0=12x-12-14
0=12x-26
Flip the eqaution
12x-26=0
Move -26 across the equal sign
12x=0+26
12x=26
x=26/12
x=13/6

Hope this helps! A thanks/brainiest answer would be appreciated :)

Solve log 1/100 = log(10^x+2)

A.) x= 0

B.) x= -2

C.) x= -4

D.) x= 4

Answers

i believe the answer is C: x= -4

In the triangle below, what is the side opposite the 30 degree angle

Answers

[tex]tan(30^o)= \frac{opposite }{adjacent} \ \ \ \ \to \\ \\ opposite = adjacent*tan(30^o)=3* \frac{ \sqrt{3} }{3} = \sqrt{3} [/tex]

solve for y. 8x+y=15

Answers

8x + y = 15

y = 15 - 8x

8x + y + -1y = 15 + -1y

8x = 15 + -1y

x = 1.875 + -0.125y

x = 1.875 + -0.125y

how would you prove two circles are similar

Answers

Is this a real question lol? but anyways i think that it's by shape.
GOOD LUCK!

Answer:

it is by similarity transformations

Step-by-step explanation:

so like it would be a rigid transformation then a dilation

EX- A translation then a dilation of R/r

Find three positive numbers x, y, and z that satisfy the given conditions. the sum is 180 and the product is maximum.

Answers

I don't know of any algebraic way to answer this, but 59,60,61 add up to 180, and 60^3 would be the greatest product of 3 numbers, so 59,60,61 yield the greatest product.

Write the sum using summation notation, assuming the suggested pattern continues. -9 - 3 + 3 + 9 + ... + 81

Answers

-9 -3 +3 +9 +15 +....+81=15+21+...+81=(23*66)/2=759

Honestly I believe this is correct:

∑ 15 at the top, n =0 (-9+6n)

He sum of three consecutive odd integers is −375. find the three integers.

Answers

-375/3 = -125

-125-2 =-127

-125+2 = -123

-123 + -125 + -127 = -375

x = first integer
x+2 = second integer
x+4 = third integer

x + x+2 + x+4 = -375
3x = -375 - 6
3x = -381
x = -381/3 = -127 ← first integer

second integer = -127 + 2 = -125

third integer = -127 + 4 = -123

Answer: -127, -125 and -123

Which choices are real numbers? Check all that apply.
A. (-131072)^1/7
B. (-531441)^1/12
C. (-1024)^1/5
D. (-256)^1/8

Answers

Exponents with fractions in them are really just radical notation in a different form. You've probably seen the square root sign.

[tex] \sqrt{x} [/tex]

That can be written as

x^(1/2)

...and when you take an even root of a negative number, there is no real answer. (2 is an even number).

Looking at the answer choices here, we can see that B and D use even roots, so they will give non-real answers.

So, A and C are the answer choices to select.

The real numbers are:

A. [tex]\((-131072)^{1/7}\)[/tex]

C. [tex]\((-1024)^{1/5}\)[/tex]

These have odd roots, resulting in real numbers.

To determine which of the given expressions are real numbers, we need to check if the roots of negative numbers are defined within the set of real numbers.

A. [tex]\((-131072)^{1/7}\)[/tex]

The expression [tex]\((-131072)^{1/7}\)[/tex] is the 7th root of [tex]\(-131072\)[/tex]. Since 7 is an odd number, the 7th root of a negative number is defined and is a real number.

So, [tex]\((-131072)^{1/7}\)[/tex] is a real number.

B. [tex]\((-531441)^{1/12}\)[/tex]

The expression [tex]\((-531441)^{1/12}\)[/tex] is the 12th root of [tex]\(-531441\)[/tex]. Since 12 is an even number, the 12th root of a negative number is not defined within the set of real numbers.

So, [tex]\((-531441)^{1/12}\)[/tex] is not a real number.

C. [tex]\((-1024)^{1/5}\)[/tex]

The expression [tex]\((-1024)^{1/5}\)[/tex] is the 5th root of [tex]\(-1024\)[/tex]. Since 5 is an odd number, the 5th root of a negative number is defined and is a real number.

So, [tex]\((-1024)^{1/5}\)[/tex] is a real number.

D. [tex]\((-256)^{1/8}\)[/tex]

The expression [tex]\((-256)^{1/8}\)[/tex] is the 8th root of [tex]\(-256\)[/tex]. Since 8 is an even number, the 8th root of a negative number is not defined within the set of real numbers.

So, [tex]\((-256)^{1/8}\)[/tex] is not a real number.

Summary:

- A. [tex]\((-131072)^{1/7}\)[/tex] is a real number.

- B. [tex]\((-531441)^{1/12}\)[/tex] is not a real number.

- C. [tex]\((-1024)^{1/5}\)[/tex] is a real number.

- D. [tex]\((-256)^{1/8}\)[/tex] is not a real number.

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