Find the volume. *
6 in
11 in
Volume =

Answer:

Just as the angles of the sun, moon and Earth affect tidal heights over the course of a lunar month, so do their distances to one another. Because the moon follows an elliptical path around the Earth, the distance between them varies by about 31,000 miles over the course of a month.

Hope this helped, have a nice rest of your day!

Answer:

D they both have rocky surfaces

The earth and mars are similar to each other because both the planets have rocky surfaces. Thus, the correct option is D.

Earth and Mars are similar when it comes to their basic makeups, however it has been given that they are both the terrestrial type of planets. Earth and mars, both are differentiated between a dense metallic core and an overlying mantle and crust which are composed of less dense materials like silicate rocks.

Mars is about the half the size of the Earth by diameter and has a much thinner atmosphere, with an atmospheric volume which is less than 1% of the volume of the Earth. The atmospheric composition of the two planets are also significantly different because primarily they are carbon dioxide-based, while the Earth's is rich in nitrogen and oxygen gases.

Therefore, the correct option is D.

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Answer:

What speed is the car traveling at the longest distance and the shortest distance, and how do they compare?"

"Does the car move faster or slower for longer distances?

Explanation:

Hope it helps! :)

The experiment aims to examine how the force exerted on the cart does work as the cart moves through a distance by using various materials and equipment.

The general scientific question that can be answered by conducting this experiment is: How does the force exerted on the cart do work as the cart moves through a distance?

In this experiment, you can examine the relationship between force, work, and distance by using a cart track, two carts, several masses, a position-sensing pulley, and a rough surface. By varying the force exerted on the cart and measuring the work done as the cart moves through a distance, you can analyze how force affects the work done on the cart.

An example of how to design this experiment would involve measuring the force using the masses and the position-sensing pulley. By increasing the mass and measuring the displacement of the cart, you can determine how the force applied affects the work done.

Answer:

Decreased, The Same, 2.5 and .25

Explanation:

Answer:

The correct options are;

D. The Sun

C. Galactic halo, thick disc, thin disc, extreme disc, black hole

Explanation:

1) The Milky Way galaxy consists of a disk, a central bulge and a halo , with the most prominent and visible part of the Milky Way galaxy being the disk

The  Sun can be found in the thin disk and not in the Milky Way's galactic halo

2) The structure of the Milky Way galaxy consists of

(1) Galactic halo (2) Spherical component (3) Spiral arms (4) Thick and thin disk (5) Central bulge (extreme disc) (6) Nucleus with black hole

Therefore, the correct order of the components of the Milky Way galaxy from outermost to innermost is as follows

Galactic halo, thick disc, thin disc, extreme disc, black hole.

The Sun is not found in the Milky Way galaxy's galactic halo. The order of components of the Milky Way galaxy from outermost to innermost is: Galactic halo, thick disc, thin disc, extreme disc, black hole.

The Milky Way galaxy's galactic halo is a spherical region encompassing the main, disc-shaped structure of the galaxy. It encompasses a few lone stars (Option A), dark matter (Option B), and some star clusters (Option C). However, the Sun (Option D) is not located in the galactic halo; instead, it's positioned within one of the spiral arms of the galaxy's disc. So, the answer is the Sun (Option D) is NOT found in the Milky Way galaxy’s galactic halo.

As for the order of components of the Milky Way galaxy from outermost to innermost: it starts with the galactic halo, followed by the thick disc, thin disc, extreme disc, and finally, at the center, we have the supermassive black hole. Therefore, the correct order is presented in Option C: Galactic halo, thick disc, thin disc, extreme disc, black hole.

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Answer:

the answer is B :Bohr believed electron orbits were circular, but Schrödinger’s equations represent complex shapes describing the probable locations of electrons.

Explanation:

just took the test on edge

The main differences between the Schrödinger and Bohr atomic models are the representation of electron orbits and the explanation of the emission and absorption spectrum.

The main difference between the Schrödinger model and the Bohr atomic model is that Bohr believed electron orbits were circular, while Schrödinger's equations describe complex shapes representing the probable locations of electrons. This means that according to Bohr, electrons could only exist in specific orbits, while Schrödinger's model allows for electrons to be found in a range of locations within an atom.

Another difference is that the Bohr model did not explain the emission and absorption spectrum, whereas the energy levels described by Schrödinger's model successfully explained this property.

Lastly, Bohr believed that electrons circled the nucleus due to the attraction between positive and negative charges, while Schrödinger believed that electrons have wave-like properties.

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Answer:

Approximately [tex]2.9 \times 10^2 \; \rm m[/tex].

Explanation:

In that [tex]0.39\; \rm s[/tex], this sound wave travelled from the surface of the lake to the bottom, got reflected, and travelled back from the bottom to the surface. The sound wave travelled from the surface to the bottom (without bouncing back) in only [tex]1/2[/tex] that much time. In other words, it took only [tex]\displaystyle ((1/2) \times 0.39)\; \rm s[/tex] for the sound wave to travel from the surface to the bottom of the lake.  

The speed [tex]v[/tex] of sound in cold water ([tex]20\; \rm ^\circ C[/tex], [tex]1\; \rm atm[/tex]) is approximately [tex]1.482\times 10^{3} \; \rm m \cdot s^{-1}[/tex].

In [tex]t = ((1/2) \times 0.39) \; \rm s[/tex], that sound wave would have travelled a distance of:

[tex]\begin{aligned}s &= v \cdot t \\ &= 1.482 \times 10^3 \; \rm m \cdot s^{-1} \times \left(\frac{1}{2} \times 0.39 \; \rm s\right) \\ &\approx 2.9 \times 10^2\; \rm m \end{aligned}[/tex].

Therefore, the depth of the lake is approximately [tex]2.9 \times 10^2 \; \rm m[/tex].

Answer:

Explanation:

We shall apply law of refraction which is as follows

sin i / sinr = μ  , where i is angle of incidence , r is angle of refraction and μ is refractive index

here i = θa = 22.5°

r = θb

μ  = 1.77

sin22.5 / sinθb = 1.77

.3826 / sinθb = 1.77

sinθb = .216

θb  = 12.5 °.

The energy of a sound wave as it travels through a medium decreases

It is the physical vibration waves that travel through the air to reach the ears . Sound energy is the result when force makes an object vibrate.

A wave can lose energy as it travel through a medium because medium can also absorb the energy . The medium changes some of the acoustic energy of the sound wave into heat .

correct option is d) it decreases

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The energy of a sound wave decreases as it propagates through a medium due to damping, which lessens the amplitude of the wave. The decrease happens because the energy is dispersed over a growing area and is absorbed by the medium.

The question asks which best describes the energy of a sound wave as it travels through a medium. The correct answer is that the energy of a sound wave decreases as it propagates through a medium. This decrease in energy is due to damping, which is an effect that decreases the amplitude of the wave as it travels. Damping occurs because the energy of the sound wave is spread out over an increasingly larger area and is absorbed by the medium.

Answer:

a) developed

b) simple

c) simple

d) developed

e) developed

f) developed

Question:

Which of the following sentences are simple sentences and which are developed sentences? Orally argue the answers

a) the cat scribbled the little girl.

b) Grandma will cook

c) The cat will spin

d) You don't love cats?

e) in one jump, the cat will be at the window

f) we will never arrived on time

Explanation:

To differentiate the simple sentences from the developed sentences, let's understand what they are.

A Simple sentence is a sentence that contain a subject and a predicate. The sentence is complete in thought.

A developed sentence is a sentence that contain a subject, predicate as well as other parts of sentence.

a) the cat scribbled the little girl (developed)

b) Grandma will cook (simple)

c) The cat will spin (simple)

d) You don't love cats? (developed)

e) in one jump, the cat will be at the window (developed)

f) we will never arrived on time (developed)

Hence option b and c are simple sentences, while options a, d, e and f are developed.

Answer:

C. The light appears brighter

Explanation:

As the amplitude of a light wave increases, the light appears brighter.

The amplitude is the vertical distance from the axis of the sinusoidal wave at a particular time.

When the amplitude of a wave is increased, its energy is increased. Energy of the wave is directly proportional to the square of the amplitude. Energy is actually the intensity of the wave.

Thus, as the amplitude of a light wave increases, the light appears brighter.

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Answer:

No work was done.

W = 0

Explanation:

Work is said to be done whenever a force of one newton moves a body of one kilogram through a distance of one meter. Meaning the applied force has to move the body from a point of rest through certain distance.

Work = force × distance

So, in the case of this question, we only have the force been applied, but no distance was covered. Hence, no work was done.

W = 3000× 0 meter

W = 0

Answer:

It is done via an electromagnetic wave.

Explanation:

Answer:

Electromagnets.

Explanation:

They acquire their magnetism by flow of current and electromagnetic induction

The kind of magnet that should be shown in the figure is electromagnet.

An electromagnet refer to the type of magnet where the magnetic field is generated via an electric current. It comprise of wire wound into a coil. A current via the wire develops a magnetic field i.e. concentrated in the hole, represents the center of the coil. Also, it acquire their magnetism with the help of flow of current and electromagnetic induction.

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Question:

What are the magnitudes of the  pulling force and the magnetic field

Answer:

The magnetic field strength is 2.7 T

The pulling force [tex]F_p[/tex] is 0.975 N

Explanation:

Here we have;

Length of wire, l = 10.0 cm = 0.1 m

Resistance of wire, R = 0.300 Ω

Speed of wire, v = 4.00 m/s

Power dissipated = 3.90 W

Based on the given data, we apply the relation;

[tex]I =\frac{Blv}{R}[/tex]..............(1)

Where:

B = Magnetic field strength

I = Current

Since P = I²R, we have;

3.9 = I²·0.300Ω

∴ I² = 3.9/0.300 = 13

From which I = √13

Substituting the value of I in equation (1) above, we have;

[tex]\sqrt{13}= \frac{B \times 10.0 \times 4.00}{0.300}[/tex]

Therefore;

[tex]B = \frac{\sqrt{13} \times 0.300}{0.1 \times 4.00} = 2.70416 \ T\approx 2.7 \ T[/tex]

The magnitude of the pulling force is given by the following relation;

[tex]F_p = F_m = IlB = l\sqrt{\frac{P}{R} } \frac{\sqrt{PR} }{lv} =\frac{P}{v} = \frac{3.9 \ W}{4.00 \ m/s} = 0.975 \ N[/tex]

The pulling force [tex]F_p[/tex] = 0.975 N.

Answer:

It contracts and returns to its original length when it stops.

Explanation:

As it approaches the speed of light, the length of the object is observed to contract. Then as it comes to a stop, it returns back to its original length.

Answer:D

Explanation:

Because I got it wrong

The Answer is:

Weight

(hope that helped)

Answer:

Earth’s gravity causes the downward pull on the washers.

Explanation:

This is the sample answer on Edmentum. :)

Answer:

The net force in the middle particle is zero, and it has no direction.

Explanation:

First, the force that one charge does in other charge is:

F = K*q1*q2/r^2

where k is a constant, q1 and q2 are the charges, and r is the distance between the charges.

If the force is positive, the force is repulsive (pushes away the charge) if the force is negative, is attractive.

Now, we have that the middle charge has a charge of 4.00nC, and in each side at a distance of 4m, has a charge of 4.00nC.

i will write qL as the charge in the left, qR as the charge in the right, and qM as the charge in the middle.

The force that the charge in the right does to the charge in the middle is:

Fr = (k*(4.00nC)^2)/4m^2 = k*(nC/m)^2

And is positive, so this is a repulsive force, this means that if the charge is at the right of the middle charge, then this force pushes the middle charge to the left.

For the left charge we have the same:

Fl = (k*(4.00nC)^2)/4m^2 = k*(nC/m)^2

But in this case, the force pushes the particle to the right, then this force, that is equal in magnitude to the previous force, pushes it in the opposite direction, then the total force in the middle particle is anulated. This is because the two external particles are "pushing" the middle particle with the same force and in the opposite direction.

The net force in the middle particle is zero, and it has no direction.

[tex]F = K*q_1*q_2/r^2[/tex]

where,

k is a constant,

q1 and q2 are the charges, and

r is the distance between the charges.

If the force is positive, the force is repulsive (pushes away the charge) if the force is negative, is attractive.

Given :

Charge = 4.00nC

Distance = 4.00m

The force that the charge in the right does to the charge in the middle is:

[tex]F_r = (k*(4.00nC)^2)/4m^2\\\\F_r = k*(nC/m)^2[/tex]

And is positive, so that is a repulsive pressure, because of this if the charge is on the proper of the center fee, then this pressure pushes the center fee to the left.

For the left charge we have the same:

[tex]F_l = (k*(4.00nC)^2)/4m^2 \\\\F_l = k*(nC/m)^2[/tex]

But on this case, the pressure pushes the particle to the right, then this pressure, this is same in importance to the preceding pressure, pushes it within side the contrary direction, then the entire pressure within side the center particle is annulated. This is due to the fact the 2 outside debris are "pushing" the center particle with the identical pressure and within side the contrary direction.

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Answer:

A is the correct answer

Electric field

Electric field is a electric force per unit charge.

The electric field is radially in toward a negative point charge and radially outward from a positive charge.

The direction of the field is in the direction of the force it exert on a positive test charge.

The formula of electric field is given as.

E = F /Q.

Properties of an Electric Field

Electric Field lines never intersect each other and they are perpendicular to the surface charge.

Electric field is strong when the lines are close together, and it is weak when the field lines move apart from each other.

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Answer:

[tex]n=5[/tex]

Explanation:

The De Broglie equation is given by:

[tex]\lambda=\frac{h}{mv}[/tex]

Where:

Then:

[tex]v=\frac{h}{m\lambda}[/tex] (1)

The  energy equation of a hydrogen electron in a orbit n is:

[tex]E=-\frac{R_{H}}{n^{2}}[/tex] (2)

We can write E as a kinetic energy an use v of the equation (1)

[tex]\frac{1}{2}mv^{2}=\frac{R_{H}}{n^{2}}[/tex]

[tex]n^{2}=\frac{2R_{H}}{mv^{2}}[/tex]        

[tex]n=\frac{m\lambda}{h}\sqrt{\frac{2R_{H}}{m}}[/tex]      

[tex]n=\frac{9.1*10^{-31}*1.66*10^{-9}}{6.626*10^{-34}}\sqrt{\frac{2*2.18*10^{-18}}{9.1*10^{-31}}}[/tex]  

[tex]n=5[/tex]

I hope it helps you!

Given an electron in a hydrogen atom with a de Broglie wavelength of 1.66 nm, the quantum number or integer n that corresponds to its orbit is likely 1, suggesting the electron is in the ground state orbit of the atom.

Given the de Broglie wavelength (λ) of an electron in a hydrogen atom is 1.66 nm, we're to identify the integer n or quantum number that corresponds to its orbit. Specifically in the model of the atom proposed by Bohr and later modified by de Broglie, the electron orbits the nucleus in quantized orbits. These quantized orbits correspond to the de Broglie 'standing wave' concept where an integer number of wavelengths must fit exactly within the orbit.

To determine the quantum number n for the electron's orbit, we need to apply the formula for the de Broglie wavelength in a Bohr orbit: λ = 2πrn/n, where rn is the radius of the nth orbit. The radius of the nth orbit in a hydrogen atom is given by the formula rn = 0.529 * n² nm. Solving for n, we find n equals to approximately 1. This means the electron is likely in the ground state orbit of the hydrogen atom.

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Genotypes describe the specific genetic makeup of a living thing and cannot be observed.

Genotypes represent the combination of alleles or genes that an organism possesses for a particular trait or set of traits. They are responsible for determining the inherited characteristics and potential traits that an organism can exhibit.

They can vary for different traits within an individual organism or across different individuals within a species. They play a fundamental role in genetics and inheritance, as they determine the genetic information that is passed from one generation to the next.

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Answer:

For mirror A:

Object distance from mirror is 15 cm

Image distance from mirror is 30 cm

For mirror B;

Object distance = 15 cm

Image distance = 3.75 cm

Focal lenght = 3 cm

Explanation:

Detailed explanation and calculation is shown in the images below.

Answer:

I'll just assume that the question is what's the velocity of the airplane before it takes off because you haven't included a question. Where u: velocity, a: acceleration, t: time

[tex]u = a \times t \\ u = 2.5 \times 30 \\ u = 70ms[/tex]

The correct option is "work function of the photoemissive metal". The threshold frequency in a photoelectric effect experiment is most closely related to the work function of the photoemissive metal, which is the amount of energy required to eject an electron from the metal's surface.

The threshold frequency in a photoelectric experiment is closely related to the work function of the photoemissive metal (Option B). The threshold frequency is a characteristic of a metal and represents the minimum frequency of incident light required to eject electrons from the metal surface. If the frequency of the incident light is below this threshold, no photoelectrons are ejected regardless of the light's intensity or any other factors, such as the area or thickness of the metal.

In the case of using a metal with a lower threshold frequency (Option 3), this would correspond to a photoemissive metal with a lower work function, allowing electrons to be ejected with lower frequency (and thus, less energetic) light. Conversely, if a metal with a higher work function is used (Option 4), photons with energy less than this work function would not eject electrons, as their energy would be insufficient to overcome the electron binding energy inherent to the metal.

Answer:

C. Protons are positive, neutrons are neutral, and electrons are negative

The description that correctly labels each particle's charge is option C: Protons are positive, neutrons are neutral, and electrons are negative. These particles compose the anatomy of an atom.

The question asks for the correct assignment of charges to particles that make up atoms. The best description for each particle is given by option C. Here, protons are correctly labeled as positive, neutrons as neutral, and electrons as negative. In an atom, protons and neutrons reside in the nucleus (the center), while electrons occupy space around the nucleus, in what's known as electron clouds or shells.

Understanding the correct assignment of charges to atomic particles is fundamental in grasping the structure of atoms. Protons, carrying a positive charge, and neutrons, which are neutral, are concentrated in the nucleus, forming the central core. Meanwhile, electrons, negatively charged, orbit the nucleus in electron clouds or shells, contributing to the overall electrical balance of the atom.

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Answer:

The correct option is;

C. 1,715 m

Explanation:

We are given the information from the group of teen at the City edge

Time of arrival of explosion sound = 5 s after sighting

Time of sighting explosion = 5 s before hearing the boom

Speed of sound in air ≈ 343 m/s

Speed of light = 299,792 km/s

Therefore, distance covered by sound in 5 seconds is given by the following equation;

[tex]Speed = \frac{Distance}{Time}[/tex]

[tex]\therefore 343 \ m/s= \frac{Distance}{5 \, s}[/tex]

Hence Distance = 343 m/s × 5 s = 1715 m

To check, we compare the time it would take for the light to cover 1715 m

That is [tex]Time = \frac{Distance}{Speed} = \frac{1715}{299,792,000} = 0.00000572 \, s[/tex] which is instantaneous hence the distance can be approximated by the time duration for the speed of sound.

Therefore, the distance of the students from the factory is approximately 1,715 m

Using the speed of sound at 24.0°C, which is roughly 343 m/s, and knowing the sound took 5 seconds to reach the observers, the calculated distance to the explosion is 1715 meters.

The question involves calculating the distance from an observed event based on the speed of sound, which falls under the subject of Physics. To determine how far the teens are from the factory, we can use the speed of sound, which depends on air temperature. Given the standard temperature of 24.0°C, the speed of sound in air is approximately 343 meters per second. The explosion sound reached the teens 5 seconds after they saw it, meaning the sound traveled for 5 seconds to reach them.

The distance can be calculated using the formula: distance = speed x time. Plugging in the values: distance = 343 m/s x 5 s = 1715 meters. Therefore, the teens were approximately 1715 meters away from the factory when they heard the explosion.

Answer:

C) 4 seconds

Explanation:

The height of an object is given by the following formula:

[tex]s(t)=h+vt-0.5at^2\\\\a=32ft/s[/tex]

To find the flight time you equal the height s to zero:

[tex]0=5ft+70\frac{ft}{s}\ t-0.5(32\frac{ft}{s^2})t^2\\\\0=5ft+70\frac{ft}{s}\ t-16\frac{ft}{s^2}t^2[/tex]

Then, you have a quadratic equation of the form:

[tex]ax^2+bx+c[/tex]

you use the quadratic formula in order to find the roots of the polynomial:

[tex]t_{1,2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\a=-16\\\\b=70\\\\c=5\\\\t_{1,2}=\frac{-70\pm \sqrt{(70)^2-4(-16)(5)}}{2(-16)}\\\\t_{1,2}=\frac{-70\pm 72.24}{-32}\\\\t_1=4.44s\approx4s\\\\t_2=-007s[/tex]

you take the positive value of t because this has physical meaning.

Hence:

the time is C) 4 seconds

From the data provided, the time taken for the baseball to hit the ground is 4.0 seconds

The function: s(t) = vt + h – 0.5at^2 represents the height of an object

From the data provided:

Substituting the values:

0 = 70t + 5 - 0.5(32)t^2

16t^2 -+ 70t - 5 = 0

solving quadratically:

[tex]t = \frac{ - b \sqrt{b {}^{2} - 4ac} }{2a} [/tex]

[tex]t = \frac{ - 70 \sqrt{ {70}^{2} - 4 \times ( - 16) \times 5} }{2 \times ( - 16)} [/tex]

t = 4.4 s or - 0.07

taking only positive values for t, t= 4 seconds

Therefore, the time taken for the baseball to hit the ground is 4.0 seconds.

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