Find the volume of the solid bounded above by the plane z = y + 8, below by the xy-plane, and on the sides by the circular cylinder x2 + y2 = 64.

CIDR, or Classless Inter-Domain Routing, is tied to IP address aggregation and subnetting, which help in efficient IP address allocation and network management.

Classless Inter-Domain Routing, commonly known as CIDR, is a method for allocating IP addresses and routing Internet Protocol packets.

Two terms often associated with CIDR are IP address aggregation and subnetting. IP address aggregation involves the grouping of multiple networks into a single, larger network, represented as a CIDR block.

Subnetting refers to dividing a larger network into smaller, more manageable sub-networks or subnets. This technique can help reduce the number of routing table entries needed in a network, which improves routing efficiency and conserves the limited supply of IP addresses.

Rounded to the nearest thousandth, it's 0.357. So, the correct answer is: A) 0.357.

To express  5/14 as a decimal, divide 5 by 14 to get 0.357142857. Rounding to the nearest thousandth means considering the third digit after the decimal point. Since the fourth digit is 1, which is less than 5, it doesn't affect the rounding. Therefore, 5/14 as a decimal rounded to the nearest thousandth is 0.357. This approximation maintains three decimal places, with the third digit being 7.

[tex]\frac{5}{14}=0.357142857[/tex]

Complete Question:

Express 5/14 as a decimal number rounded to the nearest thousandth.

A) 0.357

B) 2.8

C) 0.3571

D) 0.28

The statement "The following sequence is arithmetic. 18, 11, 4, -3, -10, -17 is True.

To determine if a sequence is arithmetic, one must check if there is a common difference between consecutive terms. The common difference (d) can be found by subtracting any term in the sequence from the term immediately following it.

Let's calculate the common difference for the given sequence:

- For the first two terms: (11 - 18 = -7)

- For the next two terms: (4 - 11 = -7)

- For the following two terms: (-3 - 4 = -7)

- And for the last two terms provided: (-10 - (-3) = -10 + 3 = -7)

 Since the difference between each pair of consecutive terms is constant and equal to \(-7\), this confirms that the sequence is indeed arithmetic. Therefore, the statement is True.

Answer:

n ≥ 9

Step-by-step explanation:

The value of r in a solution of the expression 5 + r - 2 = 9 is,

⇒ r = -6

Given that,

A mathematical expression is,

⇒ 5 + r - 2 = 9

Now, simplify the expression by combining like terms as,

⇒ 5 + r - 2 = 9

⇒ 3 - r = 9

Add r on both sides,

⇒ 3 = 9 + r

Subtract 9 on both sides,

⇒ 3 - 9 = r

⇒ - 6 = r

Therefore, the solution of the expression is,

⇒ r = -6

To learn more about the mathematical expression visit:

brainly.com/question/1859113

#SPJ6

Using probability concept in mathematics, the total number of fish in the tank would be 60, this is solved by the equation

The student's question involves the concept of probability in mathematics. Given that the probability of finding a female golden platy is 30% and there are 18 female golden platys, we can formulate an equation to find the total number of fish. Let's say the total number of fish in the tank is X. Accordingly, we can write 30/100 * X = 18. Solving this equation would give X = 18 / (30/100), which simplifies to

golden platys in the tank.

https://brainly.com/question/32117953

#SPJ11

Final answer:

To make $2.50 using one dollar bills, quarters, and dimes, there are 7 different combinations.

Explanation:

To make $2.50 using one dollar bills, quarters, and dimes, we can use the concept of combinations. Let's break it down:

So, there are 7 different combinations to make $2.50 using one dollar bills, quarters, and dimes.

1.      To construct parallel lines, first, you must start with a line segment AB that well copies. Mark another point called C. Set the compass to the point A and adjust the compass to the width of the original line. Then without moving the compass, put it on point C and mark the end and label it D. Use a straightedge to connect the points and now you’ve copied a line segment.

2.      First, you click the line and make a line segment. Then make a separate point anywhere. Then you double-click perpendicular lines and click parallel lines. Click and drag the line segment onto the separate point.

3.      First, you start with a point on a line. Then you put your compass on the point and mark an arc on each side of the line and put points on them. Then you put the compass on one of the points and make an arc above the original point. Do the same for the other side. You should end up with 2 X’s on top and bottom of the original point. Then mark points on the Xs. Finally, use a straight edge to connect the two X’s which will make a bisecting line through the original.

4.      First, you make a line and click perpendicular lines and you will have a straight line cutting through the original.

Answer:

Step-by-step explanation:

A cheeseburger contains 290 calories and a small fries contains 230 calories.

Let X be the number of calories in a cheeseburger, and Y be the number of calories in a small fries.

From the given information, we can create two equations:

To solve this system of equations, we can use substitution or elimination. Let's use elimination:

Therefore, a cheeseburger contains 290 calories and a small fries contains 230 calories.

Answer:

C) A line perpendicular to a given line through a point not on a line.

Step-by-step explanation:

In the given construction we draw a perpendicular line from a point which is not on line.

Please see the attachment for construction and naming of point.

Thus, C is correct option. " a line perpendicular to a given line through a point not on a line".

If the discriminant of an equation is zero, then the correct statement amongst given statement is:

      a.    It has one real solution

We have three cases of discriminant--

The solution for the problem is:

d(S,P) = √(0-0)^2 + √(b-0)^2
d(S,P) = √b^2
d(S,P) = b

so we know that, SP = b

d(P, Q) = √(a-0)^2 + √(b-b)^2
d(P, Q) = √a^2
d(P, Q) = a
so
PQ = a 

SQ = c^2 = a^2 + b^2
SQ = √(a^2 + b^2)

Therefore, the answer is √(a^2 + b^2).

Proof of the congruence of the diagonals of a rectangle involves the distance formula stemming from the Pythagorean theorem and can be shown using specific coordinates. Comparing areas of squares uses the squares of the side lengths which simplifies to ratios.

The lengths of the diagonals of a rectangle can be found using the distance formula, which is derived from the Pythagorean theorem. To prove the diagonals are congruent, coordinates are assigned to the vertices of the rectangle and the distance formula is applied to both diagonals. If the rectangle is placed with one corner at the origin and sides along the axes, then this process is further simplified as one can use the differences in x-coordinates and y-coordinates directly.

If we have a rectangle with vertices at coordinates (0,0), (a,0), (a,b), and (0,b), the diagonal lengths can be found by using the distance formula: the diagonal between (0,0) and (a,b) would have a length of √(a² + b²), and the diagonal between (a,0) and (0,b) would also have a length of √(a² + b²), proving that they are congruent. Additionally, when comparing areas using ratios, one simply needs to compare the squares of the lengths of respective sides, as the area of a square is the square of its side length.

The value of y is:

           [tex]y=\dfrac{93-qa}{q-67}[/tex]

We are given a expression in terms of three unknowns q,a and y.

Now, we are asked to solve this expression for y.

i.e. we are asked to represent y in terms of other two unknowns.

We will first use the distributive property under multiplication in the left hand side of the equation.

i.e.

[tex]q\times a+q\times y=67y+93\\\\i.e.\\\\qa+qy=67y+93[/tex]

Now, we combine the terms of y at one side of the equation and the other terms to the other side.

i.e.

[tex]qy-67y=93-qa\\\\i.e.\\\\(q-67)y=93-qa\\\\i.e.\\\\y=\dfrac{93-qa}{q-67}[/tex]

Answer:

x - 6

Step-by-step explanation:

usatestprep

k-12