five friends went to a local restaurant and all had the buffet at $6.75 each. the following is the restaurant bill. does it seem reasonable 5($6.75) =&67.50

Heart will beat 140 times in 2 minutes.
Heart beats at a rate of 70 beats per minute.

(How it's done down below)

In 0 minutes heart beats 700 times

hence in 1 minute it will beat 700/10=70 times

and heart will beat 140 times in 140/70=2 minutes

Heartbeats at a rate of 70 beats per minute.

hence in 1 minute it will beat 700 ÷ 10=70 times

The slope of the line that passes through (8, 10) and (1, 1) is 9/7.

To find the slope of a line that passes through two given points, (x1, y1) and (x2, y2), we use the formula:

m = (y2 - y1) / (x2 - x1)

Using the given points (8, 10) and (1, 1), we substitute the coordinates into the formula:

m = (1 - 10) / (1 - 8) = -9 / -7 = 9/7

Therefore, the slope of the line that passes through (8, 10) and (1, 1) is 9/7.

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The slope of the line that passes through the points (8, 10) and (1, 1) is calculated using the slope formula and it comes out to be 9/7, which is an improper fraction.

To find the slope of a line passing through two points, you use the slope formula:

Slope (m) = (change in y) / (change in x) = (y2 - y1) / (x2 - x1)

For the points (8, 10) and (1, 1), we calculate the slope as follows:

m = (1 - 10) / (1 - 8)

m = (-9) / (-7)

m = 9/7

Therefore, the slope of the line that passes through (8, 10) and (1, 1) is 9/7, which is an improper fraction.

Answer:

We can use the associative property of addition to group the numbers for addition.

Step-by-step explanation:

We are given the following information in the question:

We have to add [tex]4 + 2 + 5[/tex] in two different ways.

Associative property of addition

Working:

[tex]4 + 2 + 5[/tex]

[tex](4+2)+5 = 4+(2+5)\\6 + 5 = 4 + 7\\13 =13[/tex]

The associative property allows for different groupings of numbers when adding without affecting the sum, such as (4 + 2) + 5 and 4 + (2 + 5), both resulting in 11.

In mathematics, especially when dealing with arithmetic operations like addition, we have the flexibility to group numbers in different ways due to the associative property of addition. This property tells us that the way in which numbers are grouped does not affect the sum. Here's how you can group and add the numbers 4, 2, and 5 in two different ways:

Both methods give us the same result, which is 11, demonstrating the associative property in action.

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Answer:

The average monthly expenses is $ 1,149.75

Step-by-step explanation:

Given,

The monthly rent of the condominium = $ 725,

Also, monthly fee for maintenance work = $ 125,

And, Their annual expenses are insurance $468, lost interest, $129; and utility bills, $3,000,

⇒ The total annual expenses in insurance, lost interest and utility bill = $ 468 + $ 129 + $ 3,000

= $ 3597,

⇒ The monthly expenses in insurance, lost interest and utility bills = [tex]\frac{3597}{12}[/tex]

= $ 299.75,

Hence, the average monthly expenses = monthly rent of the condominium + monthly fee for maintenance work + monthly expenses in insurance, lost interest and utility bills

= $ 725 + $ 125 + $ 299.75

= $ 1,149.75

Final answer:

The code provided guides the user through entering five weights using a Scanner object, stores them in a double array, and then prints them all on one line separated by spaces.

Explanation:

To address the question of prompting the user to enter five people's weights and storing them in an array of doubles in Java, we need to provide a short piece of code executing this task.

The code will look something like this:

import java.util.Scanner;
class Main {
 public static void main(String[] args) {
   Scanner scanner = new Scanner(System.in);
   double[] weights = new double[5];

   for(int i = 0; i < weights.length; i++) {
     System.out.println("Enter weight " + (i+1) + ": ");
     weights[i] = scanner.nextDouble();
   }

   System.out.println("The entered weights are:");
   for(double weight : weights) {
     System.out.print(weight + " ");
   }
 }
}

This code initializes a Scanner to take user input, creates an array of doubles to store the weights, and uses a for loop to iterate over the array, prompting the user to enter a weight for each element. It then prints out each weight followed by a space.

Answer:

  $300

Step-by-step explanation:

Write an equation for the the sale price in terms of the original price. Then solve for the original price.

  sale price = (original price) - (percent off) × (original price)

Factoring out the (original price), we have ...

  sale price = (original price) × (1 - percent off)

We can find the original price by dividing this equation by (1 - percent off).

  (sale price)/(1 -percent off) = original price

Putting in the numbers, we get ...

  $225/(1 -25%) = original price

  $225/(1 - 25/100) = $225/(1 -0.25) = $225/0.75 = original price = $300

This math problem can be solved by setting up a system of linear equations. Designate the number of $27 tickets as x and the number of $40 tickets as y. You then form two equations, one for the total number of tickets (x + y = 5000) and one for the total revenue (27x + 40y = 158400). Solve these equations to determine how many of each ticket should be sold.

The subject of this question is a problem in algebra, specifically a system of linear equations. Let's denote the number of $27 tickets as x and the number of $40 tickets as y. The total number of tickets sold will be 5000. So, we have our first equation: x + y = 5000. The total revenue is $158,400. The revenue from $27 tickets will be $27x and the revenue from $40 tickets will be $40y. So, we have our second equation: 27x + 40y = 158400. Now, we have a system of linear equations which can be solved to find the number of each ticket type that should be sold. Solve these equations to get the desired quantity of ticket type for generating the required total revenue.

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V = speed of light = 3 x 108 m/s

d = distance = 384000 x 103 m = 3.84 x 108 m

time taken = t = d/V = 3.84 x 108 /(3 x 108 ) = 1.28 sec

Answer: 15(6x - 1)

Step-by-step explanation: Jamar had a great start, by figuring out the factors of both 90 and 15; of which he picked 15.

What he got wrong was failing to do same to the value 15 exactly what he did to 90x.

To put it right, here is how to go about it:

90x - 15

Factor of both 90 and 15 is 15

Therefore:

15 (6x - 1)

This is correct. You can as well expand the result to check.

The correct factorization will be:  15(6x - 1)

Given,

90x-15

Here,

Jamar had a great start, by figuring out the factors of both 90 and 15; of which he picked 15.

What he got wrong was failing to do same to the value 15 exactly what he did to 90x.

To make it correct:

90x - 15

Factor of both 90 and 15 is 15

Therefore:

15 (6x - 1)

Hence the correct factorization is achieved .

Know more about factorization,

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Answer:

D: $8.95

Step-by-step explanation:

step 1

Calculate what 15% of the normal price is.

15% as a decimal is 0.15. Multiply this by $9.99.

0.15⋅$9.99 = $1.4985

step 2

Subtract $9.99 by $1.4985 and round the difference to the nearest cent.

$9.99 − $1.4985 = $8.4915 ≈ $8.49

step 3

Match your solution to the correct answer choice.

Answer choice D is the only answer choice that matches your solution. Select answer choice D and move on to the next question.

Answer:

A

Step-by-step explanation: