For an analysis of variance, the term “one-way” refers to

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Answer 1
In statistics, you have statistical tests called ANOVA or Analysis of Variance. There is One-Way ANOVA and Two-Way ANOVA. You can only use One-Way ANOVA when you are testing only one dependent variable against at least two independent variables. For example, you want to find the statistics of the adsorption capacity with respect to two of its factors: pH and temperature. In this test, you only get the variance once and it is based on the F table of distibution. The other name for this, is actually the F-test.

Related Questions

what is the answer ?

Answers

The system of inequalities is the following:

i) y ≤ –0.75x
ii)y ≤ 3x – 2

since [tex]0.75= \frac{75}{100}= \frac{3}{4} [/tex], we can write the system again as 

[tex]i) y \leq - \frac{3}{4}x [/tex]
[tex]ii) y \leq 3x-2[/tex]

Whenever we are asked to sketch the solution of a system of linear  inequalities, we:

1. Draw the lines
2. Color the regions of the inequalities.
3. The solution is the region colored twice.


A.

to draw the line [tex] y =- \frac{3}{4}x[/tex]

consider the points: (-4, 1) and (0, 0), or any 2 other points (x,y) for which [tex] y =- \frac{3}{4}x[/tex] hold.

since we have an "smaller or equal to" inequality, the line is a solid line (not dashed, or dotted).

In order to find out which region of the line to color, consider a point not on the line, for example P(1, 1), which is clearly in the upper region of the line.

For (x, y)=(1, 1) the inequality [tex]y \leq - \frac{3}{4}x[/tex], does not hold because 

[tex]1 \leq - \frac{3}{4}*1= -\frac{3}{4} [/tex] is not true,

this means that the solution is the region of the line not containing (1, 1), as shown in picture 1.


B.
similarly, to draw the solution of inequality ii) y ≤ 3x – 2, 

we first draw the line y=3x-2, using the points (0, -2) and (2, 4), or any other 2 points (x,y) for which y=3x-2 holds.

after we draw the line, we can check the point P(1, 7) which clearly is above the line y=3x-2.

for (x, y) = (1, 7), the inequality y ≤ 3x – 2 does not hold

because 7 is not ≤ 3*1-2=1, so the region we color is the one not containing P(1, 7), as shown in picture 2.


The solution of the system is the region colored with both colors, the solid lines included. Check picture 3.

the lines intersect at (0.533, -0.4) because:

–0.75x=3x-2
-0.75x-3x=-2
-3.75x=-2, that is x= -2/(-3.75)=0.533

for x=0.533, y=3x-2=3(0.533)-2=-0.4

Answer: Picture 3, the half-lines included. So the graph is in the 3rd and 4th Quadrants

Rs = 8y + 4 , ST = 4y + 8 , and RT = 36 , find the value of y

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I assume that you meant RS and ST are segments of RT.  If that is true then:

RS+ST=RT, using the values for these given...

8y+4+4y+8=36  combine like terms on left side

12y+12=36  subtract 12 from both sides

12y=24  divide both sides by 12

y=2

A local carpet company has been hired to carpet a planetarium which is in the shape of a circle. If the radius of the planetarium is six yards, and the cost of the carpet is $14 per square yard, find the total cost to carpet the planetarium.

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The cost of the carpet will be given by:
cost=[area of the carpet]*[price per yard]
area of the carpet will be given by:
area=πr^2
=π*6^2
=113.1 square yards
thus the cost of the carpet will be:
113.1*14
=$1,583.4

Simplify Negative 3 over 2 ÷ 9 over 6.

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1 because you can simply switch the numerator and the denominator when dividing.
3/2 divided by 9/6 is 3/2 X 6/9 = 18/18 which simplifies to 1.

Will someone please answer this??

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7.2 Feet Should be the correct answer

What is the answer to this question?

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9/12= 0.75

8.00 * 0.75 = 6.00

 the 9" costs $6.00

is 5.21 a rational number

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yes; since 9 over 10 is 0.9 as a decimal, 5 and then 21 over 100 is 5.21 as a decimal.

Which number is a prime number? 21,22,23,24

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23 is the prime number bc it isn't divisable by anything
A prime number is a number that has no factors, except for itself and one. 

21 is not a prime number, because in addition to having one and itself as factors, it has 7 and 3. ( 1 x 21 = 21.) ( 7 x 3 = 21.) 

22 is not a prime number. It's easy to tell because it is an even number. ( 1 x 22 = 22.) ( 2 x 11 = 22.)

24 is not a prime number. It's even, but also has more factors. ( 2 x 12 = 24.) ( 3 x 8 = 24.) (4 x 6 = 24.)

23, however, has no other factors but one and itself. ( 1 x 23 = 23.) So therefore, it is prime.

Your science quiz had 17 questions and you answered 13 of the questions correctly. What is your present score?

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dived 13 by 17

13/17 = 0.7647

  = 76.47%

 if you need to round the number it would be 76%, which is a 76 grade

Help.. :)

Which equation is not equivalent to the formula e = mc?
m equals e over c
c equals e over m
e = cm
m equals c over e
Please help THANKS!

Answers

m equals c over e is not equal to e=mc


Answer with Step-by-step explanation:

we are given a equation:

e=mc

We have to find which equation is not equivalent to the above formula.

e=mc

Dividing both sides by c,we get

m=e/c

i.e. m equals e over c

e=mc

Dividing both sides by m,we get

c=e/m

i.e. c equals e over m

e=mc=cmBut m is not equal to c over e

Hence, The equation which is not equivalent to e=mc is:

m equals c over e

The scores on an exam are normally distributed, with a mean of 74 and a standard deviation of 7. What percent of the scores are less than 81?

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Mean = 74
Standard deviation = 7

For 81%, the Z-score is
Z=(X-mean)/(standard deviation)
=(81-74)/7
=1

So look up table of normal distribution for
P(Z<1)=0.8413
=>
On average, 84% of scores are less than 81.

One custodian cleans a suite of offices in 3 hrs. When a second worker is asked to join the regular custodian, the job takes only 2 hours. How long does it take the second worker to do the same job alone?

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The regular custodian's cleaning rate is 1/3 suites per hour. The combined cleaning rate is 1/2 suites per hour. The combined cleaning rate is (rate 1) + (rate 2) = 1/2 rate 2 = 1/2 - 1/3 = 3/6 - 2/6 = 1/6 The second worker's rate is 1/6 suites per hour. Therefore, the second worker can do the same job alone in 6 hours.

Write as a single power: 4​^20​ + 4​^20​ + 4^​20​ + 4^​20

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Sorry, I misinterpreted the question before.\\\\ 4^20+4^20+4^20+4^20 \\\\ 4(4^20)\\\\ 4^21\\\\

If marc ABC = 184°, what is m∠ABC?

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the angle is 1/2 of the arc

184/2 = 92 degrees

It would be half of the intercepted arc which is

360-184 = 176

176/2 = 88 degrees

Evaluate the integral below, where e lies between the spheres x2 + y2 + z2 = 9 and x2 + y2 + z2 = 25 in the first octant.

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The student's question involves integrating a function in a region bounded by two spheres in the first octant, implying the use of spherical coordinates and integration over a sphere with a constant radius.

The question pertains to evaluating an integral within the region bounded by two spheres in the first octant. When dealing with spheres and integrals, the use of spherical coordinates is often beneficial. The question suggests using spheres with a constant radius and spherical coordinates (r, θ, φ), where a typical point in space is represented as (r sin(θ) cos(φ), r sin(θ) sin(φ), r cos(θ)). To integrate over the sphere, we consider the bounds given by the radii of the inner and outer spheres, (r = 3 and r = 5, respectively, since the square roots of 9 and 25 are 3 and 5), and the fact that it is within the first octant which further restricts the limits of θ and φ. The rest of the provided excerpts seem to be unrelated specifically to this problem but are examples of standard integrals and applications of integration in physics and potential theory.

The final answer after evaluating the integral is: [tex]\[\frac{49\pi}{3}\][/tex]. This is the value of the integral over the region between the spheres [tex]\( x^2 + y^2 + z^2 = 9 \) and \( x^2 + y^2 + z^2 = 25 \)[/tex] in the first octant.

To evaluate the given integral over the region between the spheres [tex]\( x^2 + y^2 + z^2 = 9 \)[/tex]and [tex]\( x^2 + y^2 + z^2 = 25 \)[/tex]  in the first octant, we can use spherical coordinates. In spherical coordinates, the volume element is given by [tex]\( r^2 \sin(\phi) \, dr \, d\theta \, d\phi \),[/tex] where r is the radial distance, [tex]\( \theta \)[/tex] is the azimuthal angle, and [tex]\( \phi \)[/tex] is the polar angle.

The limits for the integral are as follows:

[tex]- \( 3 \leq r \leq 5 \) (limits of the radii for the spheres)\\- \( 0 \leq \theta \leq \frac{\pi}{2} \) (first octant)\\- \( 0 \leq \phi \leq \frac{\pi}{2} \) (first octant)[/tex]

The integral to evaluate is not specified, so let's assume it's a simple function like \( f(x, y, z) = 1 \) for the sake of demonstration. The integral would then be:

[tex]\[\iiint_E 1 \, dV = \int_{0}^{\frac{\pi}{2}} \int_{0}^{\frac{\pi}{2}} \int_{3}^{5} r^2 \sin(\phi) \, dr \, d\theta \, d\phi\][/tex]

Now, let's evaluate this integral step by step:

[tex]\[\int_{0}^{\frac{\pi}{2}} \int_{0}^{\frac{\pi}{2}} \int_{3}^{5} r^2 \sin(\phi) \, dr \, d\theta \, d\phi\][/tex]

[tex]\[= \int_{0}^{\frac{\pi}{2}} \int_{0}^{\frac{\pi}{2}} \left[ \frac{1}{3} r^3 \sin(\phi) \right]_{3}^{5} \, d\theta \, d\phi\][/tex]

[tex]\[= \int_{0}^{\frac{\pi}{2}} \int_{0}^{\frac{\pi}{2}} \left( \frac{125}{3} - \frac{27}{3} \right) \sin(\phi) \, d\theta \, d\phi\][/tex]

[tex]\[= \int_{0}^{\frac{\pi}{2}} \int_{0}^{\frac{\pi}{2}} \frac{98}{3} \sin(\phi) \, d\theta \, d\phi\][/tex]

[tex]\[= \int_{0}^{\frac{\pi}{2}} \left[ \frac{98}{3} \theta \right]_{0}^{\frac{\pi}{2}} \, d\phi\][/tex]

[tex]\[= \int_{0}^{\frac{\pi}{2}} \frac{98}{3} \cdot \frac{\pi}{2} \, d\phi\][/tex]

[tex]\[= \frac{98\pi}{6}\][/tex]

[tex]\[= \frac{49\pi}{3}\][/tex]

So, the value of the integral over the specified region is[tex]\( \frac{49\pi}{3} \).[/tex]

A jeep and BMW enter a highway running east-west at the same exit heading in opposite directions. The jeep entered the highway 30 minutes before the BMW did, and traveled 7 mph slower than the BMW. After 2 hours from the time the BMW entered the highway, the cars were 306.5 miles apart. Find the speed of each car, assuming they were driven on cruise control.

Answers

recall you d = rt, distance = rate * time

when the BMW has been running for 2hrs, the Jeep has been running for 2.5hrs, because it started off the exit 30minutes(0.5hr) before the BMW.

if the rate of the BMW is say "r", then the rate of the Jeep is "r - 7", slower by 7mph.

now, we know after the Jeep was running for 2.5hrs and the BMW was running for 2hrs, they were both apart by 306.5miles, so, say if the Jeep travelled a distance of "d", then the BMW travelled the slack from the 306.5, or "306.5 - d".

[tex]\bf \begin{array}{lccclll} &distance&rate& \begin{array}{cllll} time\\ (hours)\\ \end{array}\\ &-----&-----&-----\\ Jeep&d&r-7&2.5\\ BMW&306.5-d&r&2 \end{array} \\\\\\ \begin{cases} \boxed{d}=(r-7)2.5\\ 306.5-d=2r\\ ----------\\ 306.5-\boxed{(r-7)2.5}=2r \end{cases}[/tex]

solve for "r" to get the rate of the BMW.

what about the Jeep's? well, the Jeep is just r - 7.

Answer:

3x+27+3.5x=397.5

6.5x=370.5

x=57 mph for jeep and travels 199.5 miles in 3.5 hours

x+9=66 mph for B and travels 198 miles in 3 hours

Step-by-step explanation:

speed of jeep=x, time is     >>>>>    t+0.5 in hours or 3.5 hours here

speed of B=x+9, time is  >>>>>>>>>>>> 3 hours

distance is >>>>>>>>>    speed time

Hope it Helps.

Answer on: june 11, 2021

Is this statemate true or false?
All parallelograms are special kinds of squares.

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This is false.
By definition, all squares must have four right angles. Not all parallelograms meet this requirement,

A potter use 4/5 of a pound of clay to make a bowl.How many bowls can the potter make from 12 pounds.

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12/1 / 4/5=

12/1 * 5/4 =

60/4 = 15

 they can make 15 bowls

Rewrite with only sin x and cos x. cos 3x

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[tex]\cos (3x)=4\cos^3 x-3\cos x[/tex]

Please, show me how to solve this. Find the limit as x approaches −8 for the function ​f(x)=5x+12.

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ahemm... cheap answer is just   [tex]\bf \lim\limits_{x\to -8}~5x+12\implies 5(-8)+12\implies -28[/tex]

A certain recipe requires 458 cups of flour and 659 cups of sugar. a) If 3/8 of the recipe is to be made, how much sugar is needed?

If the above ingredients are required for one batch, find the amount of flour needed for a double batch.

Answers

a) To make 3/8 of the recipe calculate 3/8 of each ingredient.

This is how to do it:

Flour: 458 cups * 3/8 = 3* 458 / 8 cups = 3*229/4 cups = 687/4 cups = 171.75 cups = 171 and 3/4 cups

Sugar: 659 cups * 3/8 = 3*659 / 8 = 1977 / 8 cups = 247.125 cups = 247 and 1/8 cup.

For a double batch multiply all the ingredients by 2:

Flour: [687 /4] * 2 = 687/2 = 343.5 cups = 343 and 1/2 cups

Sugar: [1977/8]*2 = 1977/4 = 494.25 cups = 494 and 1/4 cups.

Zooey predicts the movie will be 90 minutes long. If the movie actually is 102 minutes long, what is Zooey's percent error? Round your answer to the nearest tenth of a percent.

Answers

102 - 90 = 12
12 / 102 = 0.1176 = 11.76 rounds to 11.8% <==
%error=100(prediction-actual)/actual

%error=100(90-102)/102

%error≈ -11.8%

Now the negative sign indicates that she underestimated the length of he movie by 11.8%, but technically the percent error is an absolute value so it is just 11.8% error.

Triangle XYZ is reflected across the line x = 3. What is the reflection image of X?

Answers

The image of x is the point (7,5).
Draw the line x= 3 and treat it like a mirror.

When you reflect the points of the triangle just count how many units each point is from the mirror (x=3)
Count the same number of points in the opposite direction (away from the mirror) and you will arrive at the coordinates for the points

Answer:

It's (7,5)

Step-by-step explanation:

Owners of a recreation area are filling a small pond with water. They are adding water at a rate of 35 liters per minute. There are 700 liters in the pond to start. Let W represent the total amount of water in the pond (in liters), and let T represent the total number of minutes that water has been added. Write an equation relating W to T . Then use this equation to find the total amount of water after 19 minutes.

Answers

W=700+35T. Then replace T with 19 which will be W=700+35(19) which equals to 1365 total amount of water in liters.

An equation relating W to T is,

W = 700 + 35T

And, Total amount of water after 19 minutes is, 1365 liters

We have to given that,

Owners of a recreation area are filling a small pond with water. They are adding water at a rate of 35 liters per minute.

There are 700 liters in the pond to start.

Now, Let W represent the total amount of water in the pond (in liters), and let T represent the total number of minutes that water has been added.

Hence, an equation relating W to T is,

W = 700 + 35T

So, For T = 19 minutes,

W = 700 + 35  x 19

W = 700 + 665

W = 1365

Therefore, Total amount of water after 19 minutes is, 1365 liters

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Let f(x) = -20x2 + 14x + 12 and g(x) =5x-6 Find f/g and state its domain a. 5x - 6; all real numbers except x =6/5 b. 5x - 6; all real numbers c. –4x – 2; all real numbers except x =6/5 d. –4x – 2; all real numbers

Answers

Final answer:

To find f/g, divide each term in f(x) by g(x). Resulting in f(x)/g(x) = -4x - 2 with the domain being all real numbers except x = 6/5. Hence, the correct answer is c. -4x - 2; all real numbers except x = 6/5.

Explanation:

To find the function f/g, we divide the function f(x) by g(x). Given f(x) = -20x2 + 14x + 12 and g(x) = 5x - 6, we divide these to get:

f(x)/g(x) = (-20x2 + 14x + 12) / (5x - 6)

Dividing each term in f(x) by g(x):

f(x)/g(x) = -4x - 2

The domain of this function would be all real numbers except where g(x) = 0, since we cannot divide by zero. g(x) = 0 when x = 6/5. Thus, the domain is all real numbers except x = 6/5.

The correct answer to the student's question is therefore c. -4x - 2; all real numbers except x = 6/5.

If (f + g)(x) = 3x2 + 2x – 1 and g(x) = 2x – 2, what is f(x)?

Answers

F(x)= 3x^2+1

I'm taking that 3x2 equals 3x^2

Write the equation in spherical coordinates. 3x + 2y + 3z = 1

Answers

[tex]\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\cos\varphi\end{cases}[/tex]

[tex]3x+2y+3z=1[/tex]
[tex]\implies3\rho\cos\theta\sin\varphi+2\rho\sin\theta\sin\varphi+3\rho\cos\varphi=1[/tex]
[tex]\implies\rho=\dfrac1{(3\cos\theta+2\sin\theta)\sin\varphi+3\cos\varphi}[/tex]

Five individuals, including a and b, take seats around a circular table in a completely random fashion. suppose the seats are numbered 1, . . . , 5. let x = a's seat number and y = b's seat number. if a sends a written message around the table to b in the direction in which they are closest, how many individuals (including a and
b.would you expect to handle the message?

Answers

Will use A and B in place of a and b for clarity.
Let x=number of individuals away from A, including A & B

Without loss of generality, assume A is seated in seat #1.

Then B is seated at 2,3,4,5 with equal probability.
Half of the time B is seated at 2 or 5, each of which is next to A, therefore x=2
The other half of the time B is seated at 3 or 4, each of which is separated from A by one seat, then x=3.

The expected number of individuals
E[X]=sum (x*P(x))
=2*(1/2)+3(1/2)
=2.5

So the expected number of individuals to handle the message is 2.5.

The number of  individuals you would expect to handle the message is 2.5.

Joint probability distribution

Let Z represent the number of individuals that handle the message

Table for the possible joint value of X and Y

Z                       Y

                         1          2          3            4         5  

X         1             -          2           3            3         2

          2           2         -           2            3         3

          3           3         2           -             2         3

           4           3         3           2            -          2

           5            2         3           3           2          -

Each cell contain=1/4×1/5=1/20

Hence:

Number of individual=10×2×1/20+10×3×1/20

Number of individual=20×0.05+30×0.05

Number of individual=2.5

Therefore the number of  individuals you would expect to handle the message is 2.5.

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what does it mean to say that's data point has a residual of 0

Answers

The point lies directly on the regression line (Apex)

Answer:

The correct answer is “the point lies directly on the regression line”

Step-by-step explanation:

When you do a regression analysis, then you get a line of regression that best fits it. The data points usually tend to fall in the regression line, but they do not precisely fall there but around it. A residual is the vertical distance between a data point and the regression line. Every single one of the data points had one residual. If one of this residual is equal to zero, then it means that the regression line truly passes through the point.  

Making use of the fact hat eq. (6.20) is an exact differential expression, show that what is the result of application of this equation to an ideal gas

Answers

Since there is no figure attached, I will describe the derivation of the ideal gas law. The combined gas law has no official founder; it is simply the incorporation of the three laws that was discovered. The combined gas law is a gas law that combines Gay-Lussac’s Law, Boyle’s Law and Charle’s Law.  Boyle’s law states that pressure is inversely proportional with volume at constant temperature. Charle’s law states that volume is directly proportional with temperature at constant pressure. And Gay-Lussac’s law shows that pressure is directly proportional with temperature at constant volume. The combination of these laws known now as combined gas law gives the ratio between the product of pressure-volume and the temperature of the system is constant. Which gives PV/T=k(constant). When comparing a substance under different conditions, the combined gas law becomes P1V1/T1 = P2V2/T2.
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