For each reaction, identify the precipitate or lack thereof bacl2 naoh

[tex]\boxed{1.0237596\;{\text{atm}}}[/tex] is the final pressure of a 3.05 L system initially at 724 mm Hg ad 298 K that is compressed to a final volume of 2.60 L at 273 K.

Further Explanation:

An ideal gas is a hypothetical gas that is composed of a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is just a theoretical concept and practically no such gas exists. But gases tend to behave almost ideally at a higher temperature and lower pressure.

Ideal gas law is the equation of state for any hypothetical gas. The expression for the ideal gas equation is as follows:

[tex]\boxed{{\mathbf{PV = nRT}}}[/tex]                                                   ...... (1)

Here,

P is the pressure of the gas.

V is the volume of the gas.

T is the absolute temperature of the gas.

n is the number of moles of gas.

R is the universal gas constant.

Rearranging equation (1), we get:

[tex]\frac{{PV}}{T} = nR[/tex]                                                           ...... (2)

For a particular gas, the number of moles (n) and the universal as constant (R) both are constants.

If a specific gas with [tex]{P_1}[/tex], [tex]{V_1}[/tex] and [tex]{T_1}[/tex] is subjected to any change and the final parameters being [tex]{P_2}[/tex], [tex]{V_2}[/tex] and [tex]{T_2}[/tex]. So equation (2) becomes,

[tex]\frac{{{P_1}{V_1}}}{{{T_1}}} = \frac{{{P_2}{V_2}}}{{{T_2}}}[/tex]               ...... (3)

Here,

[tex]{P_1}[/tex] is the initial pressure of the gas.

[tex]{V_1}[/tex] is the initial volume of the gas.

[tex]{T_1}[/tex] is the initial temperature of the gas.

[tex]{P_2}[/tex] is the final pressure of the gas.

[tex]{V_2}[/tex] is the final volume of the gas.

[tex]{T_2}[/tex] is the final temperature of the gas.

Calculation of the final pressure [tex]\left( {{{\mathbf{P}}_{\mathbf{2}}}} \right)[/tex] of the gas

Rearranging equation (3), we get:

[tex]{P_2} = \frac{{{P_1}{V_1}{T_2}}}{{{T_1}{V_2}}}[/tex]                             ...... (4)

We have [tex]{P_1} = 724\;{\text{mm Hg}}[/tex]

[tex]{V_1} = 3.05\;{\text{L}}[/tex]

[tex]{T_1} = 298\;{\text{K}}[/tex]

[tex]{V_2} = {\text{2}}{\text{.60 L}}[/tex]

[tex]{T_2} = {\text{273 K}}[/tex]

Substitute these values in equation (4).

[tex]\begin{gathered}{P_2}=\frac{{\left( {724\;{\text{mm Hg}}} \right)\left( {3.05\;{\text{L}}} \right)\left( {273\;{\text{K}}} \right)}}{{\left( {298\,{\text{K}}} \right)\left( {2.60\;{\text{L}}} \right)}} \\= 778.05705\;{\text{mm Hg}} \\ \end{gathered}[/tex]

Conversion Factor:

[tex]1\;{\text{mm Hg}} = {\text{0}}{\text{.00131579 atm}}[/tex]

So the value of [tex]{P_2}[/tex] (in atm) is calculated as follows:

[tex]\begin{gathered}{P_2}=\left( {778.05707\;{\text{mm Hg}}}\right)\left( {\frac{{{\text{0}}{\text{.00131579 atm}}}}{{1\;{\text{mm Hg}}}}} \right) \\= 1.023759\;{\text{atm}}\\\end{gathered}[/tex]

So the final pressure of the gas is 1.023759 atm.

Learn more:  

1. Rate of chemical reaction: https://brainly.com/question/1569924

2. Chemical bonds in NaCl: https://brainly.com/question/5008811

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: ideal gas, pressure, volume, absolute temperature, equation of state, hypothetical, universal gas constant, moles of gas, initial, final, P, V, T, P1, P2, V1, V2, T1, T2.

The question cannot be answered as posed because a specific chemical reaction and balanced equation are needed to relate the masses of O2 and CO2.

To answer how many grams of CO2 are used when 7.0 g of O2 are produced, we assume the process is a typical combustion or respiration reaction, where CO2 is generated from O2, or vice versa. The balanced chemical equation for the combustion of carbon would typically be C + O2 → CO2. However, since we are given the mass of O2 produced, and not the mass of a carbon-containing fuel that reacts, we cannot proceed to calculate the mass of CO2 without additional information on the specific reaction involved, including the stoichiometry that defines the mass relationship between O2 and CO2. Therefore, we must have a balanced equation or a known reaction to relate the masses of O2 and CO2 produced in order to provide a specific answer.

https://brainly.com/question/30415532

#SPJ12

9.62 grams of [tex]\( \text{CO}_2 \)[/tex] are used when 7.0 grams of [tex]\( \text{O}_2 \)[/tex] are produced.

One common reaction where [tex]\( \text{O}_2 \)[/tex] is produced and [tex]\( \text{CO}_2 \)[/tex] is consumed is photosynthesis:

[tex]\[ 6 \text{CO}_2 + 6 \text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 + 6 \text{O}_2 \][/tex]

From this balanced equation, we see that 6 moles of [tex]\( \text{CO}_2 \)[/tex] produce 6 moles of [tex]\( \text{O}_2 \)[/tex]. This means that 1 mole of [tex]\( \text{CO}_2 \)[/tex] produces 1 mole of[tex]\( \text{O}_2 \).[/tex]

Step-by-Step Solution:

1. Determine the molar mass of [tex]\( \text{O}_2 \)[/tex]:

[tex]\[ \text{Molar mass of O}_2 = 2 \times 16.00 \text{ g/mol} = 32.00 \text{ g/mol} \][/tex]

2. Calculate the moles of \( \text{O}_2 \) produced:

[tex]\[ \text{Moles of O}_2 = \frac{7.0 \text{ g}}{32.00 \text{ g/mol}} = 0.21875 \text{ moles} \][/tex]

3. Use the stoichiometry from the balanced equation:

  From the balanced equation, the mole ratio between[tex]\( \text{CO}_2 \) and \( \text{O}_2 \) is 1:1.[/tex]

 Therefore, the moles of [tex]\( \text{CO}_2 \)[/tex] used is the same as the moles of [tex]\( \text{O}_2 \)[/tex]produced:

[tex]\[ \text{Moles of CO}_2 = 0.21875 \text{ moles} \][/tex]

4. Determine the molar mass of [tex]\( \text{CO}_2 \)[/tex] :

[tex]\[ \text{Molar mass of CO}_2 = 12.01 \text{ g/mol} + 2 \times 16.00 \text{ g/mol} = 44.01 \text{ g/mol} \][/tex]

5. Calculate the grams of \( \text{CO}_2 \) used:

[tex]\[ \text{Grams of CO}_2 = \text{Moles of CO}_2 \times \text{Molar mass of CO}_2 \][/tex]

[tex]\[ \text{Grams of CO}_2 = 0.21875 \text{ moles} \times 44.01 \text{ g/mol} = 9.62 \text{ g} \][/tex]

Final answer:

The molarity of the HNO3 solution is calculated by first determining the number of moles of borax used in the titration, then finding the equivalent moles of HNO3 based on the reaction stoichiometry, and finally dividing the moles of HNO3 by the volume of solution used in the titration.

Explanation:

Calculating the Molarity of HNO3:

To determine the molarity of the HNO3 solution, we need to follow a series of steps that involve the titration of borax with HNO3. First, we need to calculate the number of moles of borax using its molar mass. We know that the molar mass of borax is 381.372 g/mol and that 0.2619 g of borax was used in the titration. The number of moles of borax can be calculated as:

moles borax = (0.2619 g) / (381.372 g/mol)

Once we know the moles of borax, we can use the titration reaction to find the moles of HNO3 that react with the borax. Assuming a 1:1 reaction (which is typical for a neutralization reaction), the moles of HNO3 would be equal to the moles of borax. We then divide the number of moles of HNO3 by the volume of HNO3 used (in liters) to get the molarity:

molarity of HNO3 = moles of HNO3 / volume of HNO3 (in L)

Finally, we can fill in the known values and calculate the molarity of the HNO3 solution precisely.

Answer:

There needs to be a strong interaction between solvent and solute molecules. However, this interaction must be strong enough to disrupt the molecular interactions between the solute molecules.

Explanation:

It is called solute, the chemical compounds that dissolve in another substance. The solvent is the substance into which the solute will be dissolved to form a new product.

Chemical dissolution is the process of dispersing the solute in a solvent, giving rise to a homogeneous solution or mixture. For such a dissolution to occur, an extremely strong chemical bond between the solute and the solvent must occur. However, this bond must be strong enough to separate the bond between the solute molecules.

Answer: The number of neutrons in the given isotope are 27.

Explanation:

Atomic number is defined as the number of electrons or number of protons that are present in a neutral atom. It is represented as Z.

Z = Atomic number = Number of electrons = Number of protons

Mass number is defined as the sum of number of protons and number of neutrons present in an atom. It is represented as A.

A = Mass number = Number of protons + Number of neutrons

Number of neutrons = Mass number - Atomic number

We are given an isotope having representation:  [tex]_{20}^{47}\textrm{Ca}[/tex]

Atomic number or number of protons = 20

Mass number = 47

So, number of neutrons = 47 - 20 = 27

Hence, the number of neutrons in the given isotope are 27.

Answer:

Igneous rock basalt.

Explanation:

The ocean crust is made mostly of igneous rock basalt, which comes from lava and the movement of tectonic plates.

Both a feather and an iron bar will impact the ground at the same time if released from the same height in a room without air resistance, demonstrating that gravity causes all objects to fall with the same acceleration, disregarding their mass.

If a feather and an iron bar are released from the same height in a room without any air resistance, both the feather and the iron bar will impact the ground at the same time. The correct answer is C) both. This outcome occurs because in the absence of air resistance, all objects fall at the same rate due to gravity. This phenomenon was famously demonstrated on the Moon by astronaut David R. Scott in 1971, where, despite the Moon's lower gravitational acceleration of 1.67 m/s² compared to Earth's 9.81 m/s², both a hammer and a feather were shown to fall at the same rate when dropped from the same height. This validates that acceleration due to gravity is constant and does not depend on the mass of the objects involved.

https://brainly.com/question/28228808

#SPJ3

Without the total voltage or detailed circuit configuration, it's not possible to determine the current through the 30.0 ω resistor. An example using Ohm's law has been provided for a hypothetical scenario.

To find the current through the 30.0 ω resistor, we would need to apply Ohm's law, which states that I = V/R, where I is the current, V is the voltage, and R is the resistance. However, the provided information is insufficient to determine the current, as we are not given the total voltage across the resistor or the configuration of the circuit (whether it is series, parallel, or a combination).

If the 30.0 ω resistor were the only resistance in the circuit and the voltage across it was provided, we could directly use Ohm's law to calculate the current. For example, if the voltage was 10 V, the current would simply be I = 10V / 30.0ω = 0.333 A.

Without additional information, such as the configuration of the circuit and the total voltage, we cannot accurately calculate the current. The problem might be missing details or might require knowledge about the rest of the circuit to solve.

https://brainly.com/question/30905506

#SPJ3

Answer is: Settling time.

Settling is the process by which substances (in this example with different shape) settle to the bottom of the fluid.

The two main variables in an experiment are the independent and dependent variable.

Dependent variable is the variable being tested and measured in a scientific experiment.

Dependent variables depend on the values of independent variables. The dependent variables represent the output or outcome whose variation is being studied.

The mass in grams of 6.5×10²⁰ molecules of aspirin (C₉H₈O₄) is 0.194 g

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole of C₉H₈O₄

1 mole of C₉H₈O₄ = (12×9) + (1×8) + (16×3)

= 180 g

Therefore, we can say that:

6.02×10²³ molecules = 180 g of C₉H₈O₄

6.02×10²³ molecules = 180 g of C₉H₈O₄

Therefore,

6.5×10²⁰ molecules = [tex]\frac{180 * 6.5*10^{20} }{6.02*10^{23}}\\\\[/tex]

6.5×10²⁰ molecules = 0.194 g

Thus, the mass of 6.5×10²⁰ molecules of aspirin (C₉H₈O₄) is 0.194 g

Learn more: https://brainly.com/question/8933381

The mass in grams of the aspirin is 0.194 g

From the question,

We are to determine the mass in grams of  6.5×10²⁰ molecules of aspirin (C₉H₈O₄)

First, we will determine the number of moles of aspirin present

Using the formula

[tex]Number\ of\ moles = \frac{Number\ of\ molecules}{Avogadro's\ constant}[/tex]

Avogadro's constant = 6.022 × 10²³ mol⁻¹

From the given information

Number of molecules of aspirin = 6.5×10²⁰ molecules

∴ Number of moles of aspirin present = [tex]\frac{6.5 \times 10^{20} }{6.022 \times 10^{23} }[/tex]

Number of moles of aspirin present = 0.0010793756 moles

Number of moles of aspirin present = 1.0793756 ×10⁻³ mole

Now, to determine the mass of aspirin present

From the formula

Mass = Number of moles × Molar mass

Molar mass of aspirin = 180.158 g/mol

∴ Mass of aspirin = 0.0010793756 × 180.158

Mass of aspirin = 0.194458 g

Mass of aspirin = 0.194 g

Hence, the mass in grams of the aspirin is 0.194 g

Learn more here: https://brainly.com/question/24800303

The perimeter of a square whose length is 12.0 m is 48 cm.

For example;

For example;

In this case;

We are given one side of a square as 12.0 cm

But Perimeter of a square is given by; 4 × s

Thus; Perimeter = 4 × 12 units

                           = 48 units

Keywords; Perimeter, Area

Level: Middle school

Subject; Mathematics

Topic: Area and Perimeter

Final answer:

The perimeter of the square with a side length of 12.0 m is 48.0 m.

Explanation:

The perimeter of a square is the sum of all its sides.

Since all the sides of a square are equal, we can find the perimeter by multiplying the length of one side by 4.

For the given square with a side length of 12.0 m, the perimeter would be:

Perimeter = 12.0 m x 4

= 48.0 m

The mass of 3.00 moles of magnesium chloride (MgCl₂) is 95.211 gram/mol.

This is determined by multiplying the number of moles by the molar mass of MgCl₂, which is 95.21 g/mol.

Steps for Problem Solving:

Therefore, the mass of 3.00 moles of magnesium chloride (MgCl₂) is 24.305+ 2*35.453= 95.211 gram/mol.

Correct question is: What is the mass of 3.00 moles of magnesium chloride, MgCl₂? Express your answer with the appropriate units.

A tributary is a smaller stream or river that flows into a larger one, contributing to its volume and influencing its navigability, ecosystem, and flooding potential.

The definition of a tributary is a stream or river that flows into a larger stream, river, or lake. These smaller watercourses contribute to the flow of the larger one, which is often referred to as the mainstem or parent river. Tributaries do not flow directly into the sea. They provide additional water volume to their parent river, which can then affect the river's ability to navigate, its ecosystem, and potential for flooding. For example, the Missouri River is a tributary of the Mississippi River because it flows into it.

equal moles of C8H18 and O2 are reacted to give equal no. of moles of CO2.

mole ratio of C8H18 =(1/2) x 8 = 4 moles

mole ratio of O2 = (1/25) x 4 = 0.16 moles

so, limiting reagent is O2

the no. of moles of CO2 formed = 16 x 0.16 = 2.56 moles

weight of CO2 formed (theoretical weight) = 2.56 x 44 = 112.64

Percentage yield =(practical yiel/theoretical yield) x 100 = (28.16/112.64) x100 = 25%

Answer: The percent yield of carbon-dioxide gas is 25%.

Explanation:

[tex]2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O[/tex]

1) According to reaction 25 moles of oxygen gas reacts with 2 moles of [tex]C_8H_{18}[/tex], then 4 moles of oxygen will react with [tex]\frac{2}{25}\times 4[/tex] moles of [tex]C_8H_{18}[/tex] that is 0.32 moles.

Oxygen with 4 moles is limiting reagent in this reaction.

2) According to reaction 25 moles of oxygen gas gives 16 moles of carbon-dioxide gas, then 4 moles of oxygen gas will give [tex]\frac{16}{25}\times 4[/tex] moles of carbon-dioxide gas that is 2.56 moles.

Theoretical mass of [tex]CO_2=\text{number of moles}\times \text{molecular mass of }CO_2}=2.56mol\times 44g/mol=112.64 g[/tex]

Experimental mass of [tex]CO_2[/tex] = 28.16 g

[tex]Percent yield=\frac{|\text{Experimental mass}}{\text{Theoretical mass}}=\frac{28.16\times 100}{112.64}=25\%[/tex]

Hence, the percent yield of carbon-dioxide gas is 25%.

To dissolve 1.00 g of barium sulfate, we would need 1 L of water.

In order to calculate the amount of water needed to dissolve 1.00 g of barium sulfate, we need to use the molar mass of barium sulfate and the concept of molarity.

The molar mass of barium sulfate (BaSO4) is 233.43 g/mol. We can use this to convert the mass of barium sulfate to moles.

Once we know the number of moles of barium sulfate, we can use the molar ratio between barium sulfate and water to calculate the volume of water needed. The balanced equation for the dissolution of barium sulfate in water is:

BaSO4 (s) + H2O (l) → Ba2+ (aq) + SO42- (aq)

Based on this equation, 1 mole of barium sulfate dissolves to give 1 mole of water. Therefore, to dissolve 1.00 g of barium sulfate, we would need 1 L of water.

https://brainly.com/question/5383482

#SPJ12