Answer: -4 1/2 , -1/2 , 1/4 , 2/3 , 2 1/3
Step-by-step explanation:
For this case we have the following numbers:
[tex]\frac {2} {3} = 0.6667[/tex]
[tex]-4 \frac {1} {2} = \frac {-8 + 1} {2} = \frac {-7} {2} = - 3.5[/tex]
[tex]\frac {1} {4} = 0.25[/tex]
[tex]- \frac {1} {2} = - 0.5\\2 \frac {1} {3} = \frac {3 * 2 + 1} {3} = \frac {7} {3} = 2.3333[/tex]
If we order from least to greatest we have:
[tex]-3.5; -0.5; 0.25; 0.6667; 2.3333[/tex]
Answer:
[tex]-4 \frac {1} {2}; -\frac {1} {2}; \frac {1} {4}; \frac {2} {3}; 2 \frac {1} {3}[/tex]
Which of the following functions shows an original investment of $200?
a. y=200(1.02)^x
b. y=5(200)^x
c. y=3(x)^200
d. y=2000(0.5)^x
Answer:
A shows an original investment of $200
Step-by-step explanation:
If you plug in x=0, you will get the value of the original investment
When you plug x=0 into A you get
[tex]y=200(1.02)^{0}[/tex]
This simplifies to
[tex]y=200(1)[/tex]
And finally to
[tex]y=200[/tex]
A diameter of a circle has endpoints P(-10,-2) and Q(4,6).
A. Find the center of the circle
B. Find the radius
C. Write an equation for the circle
Check the picture below.
[tex]\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ P(\stackrel{x_1}{-10}~,~\stackrel{y_1}{-2})\qquad Q(\stackrel{x_2}{4}~,~\stackrel{y_2}{6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{4-10}{2}~~,~~\cfrac{6-2}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{4}{2} \right)\implies \stackrel{\textit{center}}{(-3~,~2)} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{\textit{center}}{(\stackrel{x_1}{-3}~,~\stackrel{y_1}{2})}\qquad Q(\stackrel{x_2}{4}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{[4-(-3)]^2+[6-2]^2}\implies r=\sqrt{(4+3)^2+(6-2)^2} \\\\\\ r=\sqrt{49+16}\implies r=\sqrt{65} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{2}{ k})\qquad \qquad radius=\stackrel{\sqrt{65}}{ r} \\[2em] [x-(-3)]^2+[y-2]^2=(\sqrt{65})^2\implies (x+3)^2+(y-2)^2=65[/tex]
I don’t know what I’m doing please help!!
Answer:
(n -13)/(n -7)
Step-by-step explanation:
Simplify the fraction on the left, then add the two fractions.
[tex]\displaystyle\frac{n^2-10n+24}{n^2-13n+42}-\frac{9}{n-7}=\frac{(n-6)(n-4)}{(n-6)(n-7)}-\frac{9}{n-7}\\\\=\frac{n-4}{n-7}-\frac{9}{n-7}\\\\=\frac{n-4-9}{n-7}\\\\=\frac{n-13}{n-7}[/tex]
_____
Comment on the graph
The vertical asymptote tells you the simplified form has one zero in the denominator at x=7. That is, the denominator is x-7.
The x-intercept at 13 tells you that x-13 is a factor of the numerator.
The horizontal asymptote at y=1 tells you there is no vertical scaling, so the simplest form is ...
(n -13)/(n -7)
The hole at x=6 is a result of the factor (x-6) that is cancelled from the first fraction in the original expression. At that value of x, the fraction is undefined. So, the above solution should come with the restriction x ≠ 6.
Please help
must show work
There’s really no work to it tho unless you want to put the division. I did the first 5 since you only needed 5 of them. ( the r^# is the exponent numbers I don’t know how to make them look like exponents in my notes) Hope this helps <3
An art student wishes to create a clay sphere as part of a sculpture. If the clay’s density is approximately 88 pounds per cubic foot and the sphere’s radius is 2 feet, what is the weight of the sphere to the nearest pound? Use 3.14 for pi, and enter the number only.
Answer:
2947 lb
Step-by-step explanation:
Find the volume of the sphere
v=4/3 ×pi×r³
r=2ft and pi=3.14
v=4/3 × 3.14×2³
v=33.49 ft³
Given that;
Density ⇒ 88 lb/ft³
Volume⇒33.49 ft³
Mass=?-------------------------------------find the mass
But we know density=mass/volume -----so mass=density × volume
Mass= 88×33.49 =2947.41 pounds
⇒2947 lb
If (3x+5)^2=ax^2+bx+c, what is the value of a+b+c?
Answer:
64
Step-by-step explanation:
The value of a+b+c is the value of the expression when x=1:
(3+5)^2 = 8^2 = 64
One number is 3 less than twice another. If their sum is 39 find the numbers
Which of the following systems of equations represents the word problem?
Answer:
The numbers are 14 and 25
Step-by-step explanation:
Let one of the numbers be x. The second number we are told is 3 less than twice x. The second number will thus be;
2x - 3
The sum of the numbers is thus;
x + (2x - 3) = 3x - 3
But the sum of the numbers is said to be 39, therefore;
3x - 3 = 39
3x = 42
x = 14
The second number is thus;
2(14) - 3 = 28 - 3 = 25
The set of equations representing the word problem is ( x + y = 39 ) and ( x = 2y - 3 )
The correct answer is option
a).( x + y = 39 ) and ( x = 2y - 3 )
To solve this problem, let's first understand the given information.
Let's denote x as the number of one type of fruit (let's say apples) and y as the number of another type of fruit (let's say oranges). The problem states two conditions:
1. The total number of fruits is 39.
2. The number of apples (x) is either three less than twice the number of oranges (y) or it's the same as three more than twice the number of oranges.
Let's represent these conditions mathematically:
1. x + y = 39 (Equation 1)
2. x = 2y - 3 or x = 2y + 3 (Equation 2)
Now, let's compare these equations with the options provided:
a) ( x + y = 39 ) and ( x = 2y - 3 )
b) ( x - y = 39 ) and ( x = 2y - 3 )
c) ( x + y = 39 ) and ( x = 3y - 2 )
d) ( x - y = 39 ) and ( x = 3y - 2 )
Comparing Equation 1 with the options, we see that options a) and c) match.
Comparing Equation 2 with the options, we see that options a) and b) match.
Therefore, the correct system of equations is option a):
(x + y = 39) and (x = 2y - 3).
1. The first equation represents the total number of fruits, which should be 39. We add the number of apples (x) and oranges (y) to get 39.
2. The second equation represents the relationship between the number of apples and oranges. The number of apples is three less than twice the number of oranges. So, we set up the equation x = 2y - 3.
Thus, the correct answer is option a)( x + y = 39 ) and ( x = 2y - 3 )
Complete question
One number is 3 less than twice another. If their sum is 39, find the numbers?
Which of the following systems of equations represents the word problem?
a) ( x + y = 39 ) and ( x = 2y - 3 )
b) ( x - y = 39 ) and ( x = 2y - 3 )
c) ( x + y = 39 ) and ( x = 3y - 2 )
d) ( x - y = 39 ) and ( x = 3y - 2 )
Find the length of the rectangle. The perimeter of the rectangle is 34 inches. The width of the rectangle is 7 inches. The length of the rectangle is L. A. 10 in. B. 20 in. C. 27 in. D. 70 in.
The answer is:
The correct option is:
A. 10 in.
Why?To calculate the length of the rectangle using its perimeter and one of its sides (width), we need to remember the formula to calculate the perimeter of a rectangle.
[tex]Perimeter_{rectangle}=2width+2length[/tex]
Now, we are given the following information:
[tex]Perimeter=34in\\Width=7in[/tex]
Then, substituting and calculating, we have:
[tex]Perimeter_{rectangle}=2width+2length[/tex]
[tex]34in=2*7in+2length[/tex]
[tex]34in-14in=2length\\\\2length=20in\\\\length=\frac{20in}{2}=10in[/tex]
Hence, we have that the length of the rectangle is equal to 10 inches.
So, the correct option is:
A. 10 in.
Have a nice day!
Answer:
The correct answer is option A. 10 in
Step-by-step explanation:
Points to remember
Perimeter of rectangle = 2(Length + width)
It is given that, Perimeter = 34 inches
Width = 7 inches
To find the length of rectangle
Perimeter = 2(Length + width)
34 = 2(Length + 7)
17 = Length + 7
Length = 17 - 7 = 10 inches
Therefore the length of rectangle = 10 inches
The correct answer is option A. 10 in
g(n)=25−49(n−1) complete the recursive formula?
My answer:
g(1)=25
g(n)=g(n-1)+?
What is ?
Answer:
• g(1) = 25
• g(n) = g(n-1) -49
Step-by-step explanation:
You can get a clue by filling in n=2 in the explicit formula:
g(2) = 25 -49(2-1) = 25 -49 = g(1) -49
The explicit formula is of the form for an arithmetic sequence:
g(n) = g(1) +d(n-1) . . . . where g(1) is the first term and d is the common difference
Of course, this translates to the recursive formula ...
• g(1) = g(1)
• g(n) = g(n-1) +d
Here you have g(1) = 25, and d = -49. Filling these into the recursive form, you get ...
• g(1) = 25
• g(n) = g(n-1) -49
Answer:
• g(1) = 25
• g(n) = g(n-1) -49
Step-by-step explanation:
You can get a clue by filling in n=2 in the explicit formula:
g(2) = 25 -49(2-1) = 25 -49 = g(1) -49
The explicit formula is of the form for an arithmetic sequence:
g(n) = g(1) +d(n-1) . . . . where g(1) is the first term and d is the common difference
Of course, this translates to the recursive formula ...
• g(1) = g(1)
• g(n) = g(n-1) +d
Here you have g(1) = 25, and d = -49. Filling these into the recursive form, you get ...
• g(1) = 25
• g(n) = g(n-1) -49
The Eco Pulse survey from the marketing communications firm Shelton Group asked individuals to indicate things they do that make them feel guilty (Los Angeles Times, August 15, 2012). Based on the survey results, there is a .39 probability that a randomly selected person will feel guilty about wasting food and a .27 probability that a randomly selected person will feel guilty about leaving lights on when not in a room. Moreover, there is a .12 probability that a randomly selected person will feel guilty for both of these reasons.a. What is the probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room or both (to 2 decimals)?
The probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room or both is .54
Further explanationProbability is the likeliness of the occurrence of an event.
Let :
P(A) = Probability of feeling guilty about wasting food = .39
P(B) = Probability of feeling guilty about leaving lights on = .27
P(A∩B) = Probability of feeling guilty for both of these reasons = .12
The probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room or both is :
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = .39 + .27 - .12
P(A∪B) = .54Learn moreDifferent Birthdays: https://brainly.com/question/7567074
Dependent or Independent Events: https://brainly.com/question/12029535
Answer detailsGrade: High School
Subject: Mathematics
Chapter: Probability
Keywords: Person, Probability, Outcomes, Random, Event, Room, Wasting, Food
Find the value of f(9) and g(–9) if f(x) = –7x – 9 and g(x) = 6x3 – 23x.
f(9) = –16
g(–9) = –760
f(9) = –54
g(–9) = 16764
f(9) = –72
g(–9) = –4167
f(9) = 63
g(–9) = 54
Answer:
Your answer should be A
Step-by-step explanation:
For this case we have the following functions:
[tex]f (x) = - 7x-9\\g (x) = 6x ^ 3-23x[/tex]
We must find [tex]f (9)[/tex] and [tex]g (-9):[/tex]
Substituting we have:
[tex]f (9) = - 7 (9) -9\\f (9) = - 63-9\\f (9) = - 72[/tex]
On the other hand:
[tex]g (-9) = 6 (-9) ^ 3-23 (-9)\\g (-9) = 6 (-729) -23 (-9)\\g (-9) = - 4374 + 207\\g (-9) = - 4167[/tex]
Answer:
Option C
Which answer is right?????
Answer:
See the attachment
Step-by-step explanation:
The point of the dashed line y=x in the problem statement graph is that the inverse function is a reflection of the function across that line. (y and x are interchanged) The graph of selection C has the appropriate pair of curves.
The fraction 4/5 is equivalent to what percent
4/5 is equivalent to the percentage 80%.
Answer:
The correct answer is given by,
The fraction 4/5 is equivalent to 80%
Step-by-step explanation:
Points to remember
To convert fraction into percentage we have to multiply fraction with 100
x/y ⇒ 100x/y%
To find the equivalent percentage
Here fraction is 4/5
4/5 is equivalent to (4/5) * 100 = 400/5 = 80%
Therefore the correct answer is,
The fraction 4/5 is equivalent to 80%
Suppose that the weights of 5400 registered female Labrador retrievers in the United States are distributed normally with a mean of 62.5 lb and a standard deviation of 2.5 lb.
Approximately how many of the Labrador retrievers weigh less than 65 lb?
Enter your answer in the box.
Answer:
[tex]N= 4543[/tex] Labrador retrievers
Step-by-step explanation:
We know that the mean [tex]\mu[/tex] is:
[tex]\mu = 62.5[/tex]
and the standard deviation [tex]\sigma[/tex] is:
[tex]\sigma=2.5[/tex]
The probability that a randomly selected Labrador retriever weighs less than 65 pounds is:
[tex]P(X<65)[/tex]
We calculate the Z-score for X =65
[tex]Z = \frac{X-\mu}{\sigma}\\\\Z =\frac{65-62.5}{65}=1[/tex]
So
[tex]P(X<65) = P(Z<1)[/tex]
Looking in the table for the standard normal distribution we have to:
[tex]P(Z<1) =0.8413[/tex].
Finally the amount N of Labrador retrievers that weigh less than 65 pounds is:
[tex]N = P(X<65) *5400[/tex]
[tex]N = 0.8413*5400[/tex]
[tex]N= 4543[/tex] Labrador retrievers
Use the shell method to write and evaluate the definite integral that represents the volume of the solid generated by revolving the plane region about the y-axis. y = x5/2 y = 32 x = 0
The volume of the solid generated by revolving the plane region about the y-axis is approximately 35,929.77 cubic units.
Here,
To use the shell method to find the volume of the solid generated by revolving the plane region bounded by the curves [tex]y = x^{(5/2)}, y = 32[/tex],
and x = 0 about the y-axis, we need to integrate the circumference of cylindrical shells along the y-axis.
The volume V can be expressed as the integral of the circumference of the cylindrical shells from y = 0 to y = 32:
V = ∫[0 to 32] 2π * x * h(y) dy
where h(y) represents the height (or thickness) of each shell, and x is the distance from the y-axis to the curve [tex]y = x^{(5/2)[/tex].
To find h(y), we need to express x in terms of y by rearranging the equation [tex]y = x^{(5/2)[/tex]:
[tex]x = y^{(2/5)[/tex]
Now, we can express the volume integral:
V = ∫[0 to 32] 2π * [tex]y^{(2/5)[/tex] * (32 - y) dy
Now, we'll evaluate the integral:
V = 2π ∫[0 to 32] ([tex]32y^{(2/5)} - y^{(7/5)[/tex]) dy
Integrate each term separately:
[tex]V = 2\pi [(32 * (5/7) * y^{(7/5)}) - (5/12) * y^{(12/5)}] | [0 to 32]\\V = 2\pi [(32 * (5/7) * (32)^{(7/5)}) - (5/12) * (32)^{(12/5)}] - [0][/tex]
Now, evaluate the expression:
[tex]V = 2\pi [(32 * (5/7) * 2^7) - (5/12) * 2^{12}][/tex]
V = 2π [(32 * 1280/7) - (5/12) * 4096]
V = 2π [81920/7 - 341.33]
V ≈ 2π * 81920/7 - 2π * 341.33
V ≈ 36608π - 678.13
The volume of the solid generated by revolving the plane region about the y-axis is approximately 35,929.77 cubic units.
To know more about integral:
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Final answer:
The shell method is used to evaluate the volume of a solid created by revolving a region around the y-axis using a vertical shell element, integrating from x=0 to the x value corresponding to y=32.
Explanation:
To use the shell method to find the volume of the solid generated by revolving the given plane region about the y-axis, we consider a vertical element or 'shell' at a certain x-value with thickness dx. Given the equations [tex]x^{5/2}[/tex], y = 32, and x = 0, these will be the bounds for our region.
The volume of each infinitesimal shell with radius x and height [tex](32 - x^{5/2})[/tex], when revolved around the y-axis, is [tex]2πx(32 -x^{5/2})dx[/tex]. To find the total volume, we integrate this expression from x=0 to where y is 32, which corresponds to the x value where [tex]x^{5/2} = 32[/tex].
Using the substitution [tex]x^{5/2}[/tex] to solve for dx, we get the integral in terms of y, which simplifies the computation. Finally, we evaluate the definite integral to find the volume of the solid of revolution.
There are two spinners. The first spinner has three equal sectors labeled 1, 2, and 3. The second spinner has four equal sectors labeled 3, 4, 5, and 6. Spinners are spun once. How many outcomes do not show an even number on the first spinner and show a 6 on the second spinner?
Answer:
2 outcomes
Step-by-step explanation:
Let's list count all the possible outcomes:
(1,3) (1,4) (1,5) (1,6)
(2,3) (2,4) (2,5) (2,6)
(3,3) (3,4) (3,5) (3,6)
As expected, there are 12 (3x4) possible outcomes.
How many outcomes do not show an even number (so showing 1 or 3) on the first spinner and show a 6 on the second spinner?
There are two cases where 6 is on the second spinner and NOT an even number on the first spinner: (1,6) and (3,6)
A dead body was found within a closed room of a house where the temperature was a constant 70° F. At the time of discovery the core temperature of the body was determined to be 80° F. One hour later a second measurement showed that the core temperature of the body was 75° F. Assume that the time of death corresponds to t = 0 and that the core temperature at that time was 98.6° F. Determine how many hours elapsed before the body was found. [Hint: Let t1 > 0 denote the time that the body was discovered.] (Round your answer to one decimal place.)
Answer:
1.6 hours
Step-by-step explanation:
I started off with T(t)=70+Ce^kt
then since the initial temp was 98.6 I did T(0)=98.6=70+C so C=28.6
Then T(1) = 80 = 28.6e^k + 70
k = ln (10/28.6)
Then plugged that into
T(t)=85=28.6e^ln(10/28.6)t + 70
and got t=.61
The answer says it is about 1.6 hours.
The time that has elapsed before the body was found is 1.5 hour
The given parameters;
when time, t = 0, temperature = 98.6 ⁰Fwhen time, t = 1, temperature = 75⁰when time, t = t, temperature = 80⁰Apply the Newton's method of cooling equation;
[tex]T(t) = T_{s} + (T_{o} - T_{s})e^{kt}\\\\T(t) = 70 + (98.6 - 70)e^{kt}\\\\T(t) = 70 + 28.6e^{kt}[/tex]
At the time of discovery, we have the following equation,
[tex]T_{t} = 70 + 28.6e^{kt}\\\\80 = 70 + 28.6e^{kt}\\\\10 = 28.6k^{kt}[/tex]
1 hour later, t + 1, we have the second equation;
[tex]75 = 70 + 28.6e^{kt} \\\\5 = 28.6e^{k(t+ 1)} \\\\5 = 28.6e^{kt + k} ---- (2)[/tex]
divide equation 1 by equation 2;
[tex]\frac{10}{5} = \frac{28.6e^{kt}}{28.6 e^{kt + k}} \\\\2 = e^{kt - kt - k}\\\\2 = e^{-k}\\\\-k = ln(2)\\\\k = -0.693[/tex]
The time when he dead body was discovered is calculated as;
[tex]10 = 28.6e^{kt}\\\\10= 28.6e^{-0.693t}\\\\e^{-0.693t} = \frac{10}{28.6} \\\\-0.693 t = ln(\frac{10}{28.6} )\\\\-0.693t = -1.05\\\\t = \frac{1.05}{0.693} \\\\t = 1.515 \ \\\\t \approx 1.5 \ hr[/tex]
Thus, the time that has elapsed before the body was found is 1.5 hour
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Use substitution to solve each system of equations. y = 4x + 22 4x – 6y = –32
(–5, 2)
(2, –5)
(–8, 1)
(4, 7)
Answer:
The answer is (-5,2)
Step-by-step explanation:
So we have 2 equations and we need to solve them by substitution.
1) y = 4x + 22
2) 4x – 6y = –32
Since we already have y isolated in equation #1, we'll use that value in equation #2:
4x - 6(4x + 22) = -32
4x - 24x - 132 = -32
-20x = 100
x = -5
Then we put that value of x in the first equation:
y = 4 (-5) + 22 = -20 + 22 = 2
The answer is then (-5,2)
Answer:
(-5, 2)
Step-by-step explanation:
We have the equations:
[tex]y=4x+22[/tex] and [tex]4x-6y=-32[/tex]
Using the substitution method, with y = 4x + 22 and replace it in the equation 4x - 6y = -32
4x - 6(4x + 22) = -32
4x -24x -132 = -32
-20x = -32 + 132
x = 100/-20= -5
Substituting the value of x in the first equations of the systems to clear x.
y = 4x + 22
y = 4(-5) + 22
y= -20 + 22 = 2
What is the value of the expression |a + b| + |c| when a = –3, b = 7, and c = 1
The answer is 5 hope this helps
Answer:
5
Step-by-step explanation:
abs(a + b) + abs(c)
abs(-3 + 7) + abs(1)
abs(4) + abs(1)
4 + 1
5
select the graph of the solution set that would represent the following expression. (x-2)=5(x+1)
Answer:
Find the attached
Step-by-step explanation:
We have been given the following expression;
(x-2)=5(x+1)
We are required to determine the graph of the solution set. To do this we formulate the following set of equations;
y = x - 2
y = 5(x+1)
We then graph these two equations on the same cartesian plane. The solution will be the point where these two graphs intersect.
Find the attachment below;
Answer:
{-1.75}
Step-by-step explanation:
The given equation is
[tex]x-2=5(x+1)[/tex]
Let as assume f(x) be left hand side and g(x) be the right hand side.
[tex]f(x)=x-2[/tex]
[tex]g(x)=5(x+1)[/tex]
The solution set of given equation is the intersection point of f(x) and g(x).
Table of values are:
For f(x) For g(x)
x f(x) x g(x)
0 -2 0 5
2 0 -1 0
Plot these corresponding ordered pairs on a coordinate plan and connect them by straight lines
From the below graph it is clear that the intersection point of f(x) and g(x) is (-1.75,-3.75).
Therefore, the solution set of given equation is {-1.75}.
Prove that for all whole values of n the value of the expression:
n(n–1)–(n+3)(n+2) is divisible by 6.
Explanation:
Multiply it out.
n^2 -n -(n^2 +5n+6)
= -6n -6
= -6(n +1)
For any integer value of n, this is divisible by 6. (The quotient is -(n+1).)
What is the third quartile of this data set?
20, 21, 24, 25, 28, 29, 35, 37, 42
Answer:
36
Step-by-step explanation:
⇒The question is on third quartile
⇒To find the third quartile we calculate the median of the upper half of the data
Arrange the data in an increasing order
20, 21, 24, 25, 28, 29, 35, 37, 42
Locate the median, the center value
20, 21, 24, 25, 28, 29, 35, 37, 42
The values 20, 21, 24, 25 ------------lower half used in finding first quartile Q1
The value 28 is the median
The vlaues 29, 35, 37, 42...............upper half used in finding 3rd quartile Q3
Finding third quartile Q3= median of the upper half
upper half= 29,35,37,42
median =( 35+37)/2 = 36
graph the solution set for this inequality -6x-3y<-18
Answer:
it is 27 because of my cacculations
Step-by-step explanation:
you would fist subtract your numbers and thne get rid of the 5
Answer:
27
Hope It Helps
A common tangent is
segment CD
segment ST
segment RU
a tangential line to a circle is one that "touches" the circle but doesn't go inside, and keeps on going, in this case that'd be CD.
The correct answer would be: segment CD
Adrian, Ben and Charlie share some sweets in the ratio of 8:5:10.
Charlie got 24 more sweets than Adrian.
Work out the total number of sweets.
Answer:
252 candies
Step-by-step explanation:
Let A = 8x
Let B = 5x
Let C = 10x
10x = 8x + 24 Subtract 8x from both sides
10x - 8x = 24 Do the subtraction
2x = 24 Divide by 2
2x/2 = 24/2 Do the division
x = 12
So Adrian has 8*12 = 96 candies.
Ben has 5 * 12 = 60 candies
Charlie has 10*12 = 120 candies
Total = 276 candies
The total number of sweets shared by Adrian, Ben, and Charlie is 276,
To solve how many sweets were shared by Adrian, Ben, and Charlie, with the given ratio of 8:5:10 and knowing Charlie got 24 more sweets than Adrian, we can set up a ratio problem. Let the ratio part be 'x', so Adrian has 8x sweets, Ben has 5x sweets, and Charlie has 10x sweets. As Charlie got 24 more sweets than Adrian, we can write the equation 10x = 8x + 24. Solving this equation for 'x' gives us x = 12. Thus, Adrian has 96 sweets (8 x 12), Ben has 60 sweets (5 x 12), and Charlie has 120 sweets (10 x 12). Adding these together gives us a total of 276 sweets.
A street that is 165 m long is covered in snow. City workers are using a snowplow to clear the street. The snowplow has tires that are 1.7 m in diameter. How many times does a tire have to turn in traveling the length of the street? Use the value 3.14 for π. Round your answer to the nearest tenth. Do not round any intermediate steps.
namely, how many go-around or revolutions does a tire have to make for those 165 meters.
[tex]\bf \textit{circuference of a circle}\\\\ C=\pi d~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=1.7 \end{cases}\implies C=1.7\pi \impliedby \textit{one revolution} \\\\\\ \textit{how many times does }1.7\pi \textit{ go into 165?}\qquad \stackrel{\pi =3.14}{\cfrac{165}{1.7\pi }\qquad \implies \qquad 30.9}[/tex]
The number of times the tire will have to turn in travelling the length of the street is 30.9 times.
To determine the number of times the tire will have to turn in travelling the length of the street, we will first calculate the circumference of the tire.
Since the tire is circular, the circumference of the tire can be calculated from the formula for calculating the circumference of a circle.
The circumference of a circle is given by
C = πd
Where C is the circumference and d is the diameter
From the question d = 1.7m and π = 3.14
∴ C = 3.14 × 1.7
C = 5.338 m
Therefore, the circumference of the tire is 5.338 m
Now, for the number of times the tire will have to turn in travelling the length of the street, we will divide the length of the street by the circumference of the tire.
Number of times the tire will have to turn = Length of the street ÷ Circumference of the tire
Number of times the tire will have to turn = 165 m ÷ 5.338 m
Number of times the tire will have to turn = 30.91045 times
Number of times the tire will have to turn ≅ 30.9 times
Hence, the number of times the tire will have to turn in travelling the length of the street is 30.9 times
Learn more here: https://brainly.com/question/16663653
suppose that 10 is less than square rooot of n which is less than 11 what is the possible value for n
Answer:
The correct answer is that a possible value for n could be all numbers from 101 to 120.
Step-by-step explanation:
Ok, to solve this problem:
You have that: [tex]10 <\sqrt{n} <11[/tex]
Then, applying the properties of inequations, the power is raised by 2 on both sides of the inequation:
[tex](10)^{2} <(\sqrt{n} )^{2} <(11)^{2}[/tex]
[tex]100<n<121[/tex]
Then, a possible value for n could be all numbers from 101 to 120.
Model each problem as an equation, and then match to its solution.
Answer:
Part 1) The larger integer is 11
Part 2) The denominator is 5
Part 3) The positive integer is 4
The graph in the attached figure
Step-by-step explanation:
Part 1)
Let
x----> the smaller positive integer
y-----> the larger positive integer
we know that
[tex]x^{2} +y^{2} =185[/tex] -----> equation A
[tex]x=y-3[/tex] -----> equation B
substitute equation B in equation A and solve for y
[tex](y-3)^{2} +y^{2} =185\\ \\y^{2} -6y+9+y^{2}=185\\ \\2y^{2}-6y-176=0[/tex]
using a graphing calculator-----> solve the quadratic equation
The solution is y=11
[tex]x=11-3=8[/tex]
Part 2)
Let
x----> the numerator of the fraction
y-----> the denominator of the fraction
we know that
[tex]x=2y+1[/tex] ----> equation A
[tex]\frac{x+4}{y+4}=\frac{5}{3}[/tex] ----> equation B
substitute equation A in equation B and solve for y
[tex]\frac{2y+1+4}{y+4}=\frac{5}{3}[/tex]
[tex]\frac{2y+5}{y+4}=\frac{5}{3}\\ \\6y+15=5y+20\\ \\6y-5y=20-15\\ \\y=5[/tex]
[tex]x=2(5)+1=11[/tex]
Part 3)
Let
x----> the positive integer
we know that
[tex]x-\frac{1}{x}=\frac{15}{4}[/tex]
solve for x
[tex]x-\frac{1}{x}=\frac{15}{4}\\ \\4x^{2}-4=15x\\ \\4x^{2}-15x-4=0[/tex]
using a graphing calculator-----> solve the quadratic equation
The solution is x=4
Plz help ASAP!! Explain your answer! I will mark at brainliest!!! And don’t copy anybody else’s answer
Answer:
No, it is not a square
Step-by-step explanation:
If one wall is 19", that would mean the wall perpendicular to this wall is also 19" (in fact all of the walls would be 19"!) If this was a square, then the diagonal we draw at 20.62" would serve as the hypotenuse of a right triangle. One wall would serve as a leg, and another wall as another leg. If this is a square, then the Pythagorean's Theorem would be satisfied when we plug in the 2 wall measures for a and b, and the diagonal for c:
[tex]19^2+19^2=20.62^2[/tex]
We need to see if this is a true statement. If the left side equals the right side, then the 2 legs of the right triangle are the same length, and the room, then is a square.
361 + 361 = 425.1844
Is this true? Does 722 = 425.1844? Definitely not. That means that the room is not a square.
Solve the equation of exponential decay.
Suppose a country's exports declined 2.7% from 2010 to 2011. In 2010 the country exported $1.035 trillion. Assuming this continued what would the exports be in 2013
Answer:
$953.4 billion
Step-by-step explanation:
Each year, exports are (1-0.027) = 0.973 of what they were the year before. After 3 years, the export value is multiplied by 0.973^3. So, in 2013, the value of exports would be ...
($1035 billion)(0.973^3) ≈ $953.4 billion