G 1470-kilogram truck moving with a speed of 24.0 m/s runs into the rear end of a 1110-kilogram stationary car. if the collision is completely inelastic, how much kinetic energy is lost in the collision?

Answers

Answer 1

Kinetic energy = Potential energy 

(1/2)mV^2 = mgh 

where 

m = mass of the car 
V = velocity of the car = 15 m/s (given) 
g = acceleration due to gravity = 9.8 m/sec^2 (constant) 
h = vertical distance travelled by car = d(sin 19) 
d = distance travelled by the car along the incline 

Substituting values, 

(1/2)(m)(529) = m(9.8)h 

and since "m" appears on both sides of the equation, it will simply cancel out, hence the above becomes 

(1/2)(529) = 9.8h 

h = 225/19.6 = 26,98 m 

Let 

d = distance that the car will coast up the hill before coming down 

h/d = sin 19 

and therefore, 

d = h/sin 19 

and substituting values, 

d = 26,98/sin 19 

d = 82,870 m --- after coasting up the hill for this distance, the car will start to roll down.

Related Questions

A baseball team is practicing throwing balls vertically upward to test their throwing arms. A player manages to throw a ball that reaches a maximum altitude of 10 m above the launch point, before falling back down. The acceleration due to gravity is 9.80 m/s 2 . (a) With what initial speed was the ball thrown? (b) How long did it take for the ball to reach its maximum altitude?

Answers

a) 14.0 m/s b) 1.43 s Ignoring air resistance, the ball falling from 10 meters will be exactly mirror the ball climbing 10 meters. Since the formula for how far an object travels under constant acceleration is d = 0.5 AT^2 all we need to do is substitute the known values and solve for T. So 10 m = 0.5 * 9.8 m/s^2 T^2 10 m = 4.9 m/s^2 T^2 2.040816327 s^2 = T^2 1.428571429 s = T So we now know the ball took 1.43 seconds to reach its maximum altitude. The initial speed the ball was thrown at will be the product of the time and gravitational acceleration. So 1.43 s * 9.80 m/s^2 = 14.0 m/s

A weightlifter is attempting a biceps curl with a 200 n barbell. the moment arm of the barbell about the elbow joint is 40 cm. the moment arm of the elbow flexor muscles is 4 cm. how much force must be produced by these muscles to hold the 200 n barbell in static equilibrium?

Answers

Final answer:

The biceps muscles need to produce a force of 2000 N to hold the 200 N barbell in static equilibrium.

Explanation:

To hold the 200 N barbell in static equilibrium, the biceps muscles need to produce a force equal to the weight of the barbell. The moment arm of the barbell about the elbow joint is 40 cm, so the torque exerted by the barbell is calculated as:

Torque = Force x Moment Arm

Torque = 200 N x 40 cm = 8000 N·cm

The moment arm of the elbow flexor muscles is 4 cm. To maintain static equilibrium, the torque exerted by the biceps muscles must be equal and opposite to the torque exerted by the barbell:

Torque biceps = Torque barbell

Force biceps x Moment Arm biceps = Force barbell x Moment Arm barbell

Force biceps x 4 cm = 200 N x 40 cm

Force biceps = (200 N x 40 cm) / 4 cm

Force biceps = 2000 N

A hypothetical spherical planet consists entirely of iron. what is the period of a satellite that orbits this planet just above its surface?

Answers

Newton states: F=G*M*m/ r^2, where M= ρ* (4/3)*pi*r^3 is mass of iron planet, r is radius of the planet; 
 the same gravity force F=m*w^2*r is the centripetal force for the orbiting satellite, where angular speed w=2pi/T, T is period; 
 thus F=F; G*M*m/ r^2 = m*w^2*r; or; 
G*(ρ* (4/3)*pi*r^3)/ r^2 = (2pi/T)^2*r; or; 
G*ρ/3 = pi/T^2, hence T= √(3pi/(G*ρ)) = 
= √(3pi/(6.6742E-11 *7860)) =4238.62s = 70h 38’;

The orbital period of a satellite orbiting just above the surface of a hypothetical iron planet is approximately 84.5 minutes. This calculation uses Kepler's third law and the known density of iron. The result is derived after integrating the gravitational constant and mass into the formula.

Orbital Period of a Satellite Around an Iron Planet

To determine the period of a satellite orbiting just above the surface of a hypothetical spherical planet made entirely of iron, we can use Kepler's third law in conjunction with some known information about iron and orbital mechanics.

The formula we use here is:

T = 2π √(r³ / GM)

where:

T is the orbital period.r is the radius of the planet.G is the gravitational constant, 6.67430 × 10-11 m³ kg-1 [tex]s^{-2[/tex].M is the mass of the planet.

First, we need to calculate the radius of the iron planet. Iron has a density of about 7874 kg/m³. If we assume the planet has a volume V, the mass M can be related to the density ρ and radius r by:

V = 4/3 π r³

M = V × ρ or M = (4/3) π r³ ρ

Next, we substitute this mass into the orbital period formula:

T = 2π √[r³ / G (4/3 π r³ ρ)]

Simplifying, we get:

T = 2π √[3/(4πG ρ)]

Plugging in the values:

ρ = 7874 kg/m³

T = 2π √[3/(4π × 6.67430 × 10-11 m³ kg-1 s-2 × 7874 kg/m³)]

After performing the calculation:

T ≈ 5069.9 seconds ≈ 84.5 minutes

Thus, the orbital period of a satellite just above the surface of an iron planet is approximately 84.5 minutes.

Suppose the ring rotates once every 3.80 s . if a rider's mass is 59.0 kg , with how much force does the ring push on her at the top of the ride?

Answers

F=ma so, do 3.80s x 59 KG which will give you your answer, hope this helps <3

A balloon at an amusement park has 1,500 g of gas. By what amount will the mass of the balloon decrease if all the gas inside it escapes?

- 750 g

- 1,500 g

-2,000 g

- 3,000 g

SOMEONE PLEASE HELP ME IT WILL BE SOOOO APPRECAITED!

Answers

The answer is best explained in the diagram below.

Let m =  the mass of the balloon material (g).

At state 1, the total mass of the balloon is the mass of the balloon material and the mass of gas.
The total mass in state 1 is
m₁ =(m + 1500) g

At state 2, 1500 g of gas has escaped. Only the mass of the balloon material remains.
The total mass in state 2 is
m₂ = m g.

The decrease in mass of the balloon is
m₁ - m₂ = (m + 1500) - m = 1500 g

Answer: 1,500 g


Answer:

Answer 1,500 g

because if it has 1,500 g and it loses ALL of the gas...

then it will lose 1,500 g

Hope this Helps!

The desert and tundra are alike because they both have
A) extreme daily temperature changes.
B) large seasonal variation.
C) limited available water.
D) sandy soils.

Answers

a) extreme daily temperature changes



if im wrong plz let me know
Your answer is A extreme weather changes they both have weather that is life treating if under the wrong circumstance.

Your answer is A.

Roberto was testing how light interacted with a material he had just developed. The initial speed of light was 3.0 × 108 m/s. The final speed of light after it changed direction was 1.7 × 108 m/s. What type of interaction took place?

Answers

The answer to the question would be Refraction.

as we know the two possible answers are refraction and reflection. The questions shows a decrease in speed thus being refraction as a ray in a reflection would not lose its speed. Hope this helps!

Analyzing the question, we can classify the effect of refraction as the speed is reduced when entering the middle.

What is the concept of refraction?

Refraction of light is a phenomenon that occurs in electromagnetic waves that are transmitted through some translucent or transparent medium. When light penetrates refractive media, that is, those capable of refracting light, its speed decreases.

the type of interaction that happend is refraction as the speed is reduced when entering the middle.

See more about refraction at brainly.com/question/14760207

The speed of an aircraft is sometimes expressed as a mach number: mach 1 means that the speed is equal to the speed of sound. if you wish to determine the speed of an aircraft going mach 2.2, for example, in meters per second or miles per hour, what additional information do you need?

Answers

The speed of sound needs to be given, in the proper form. This will allow for the proper conversion (namely, a multiplication by the Mach rate) to find the actual speed that the aircraft is traveling, compared to how fast sound travels.

"where are the majority of transform faults located?"

Answers

The majority of the transform faults in the ocean are located on the ocean floor. They offset oceanic ridges. However, not all transform faults are on the oceanic crust- some are found on continental margins. Transform faults are boundaries between plates of the Earth's crust.

The molecules that make up a plastic two-liter bottle A) are in constant, rapid, random motion. B) have a volume of more than two liters if melted. C) expand to take the shape of wherever the bottle is placed. D) are closer together than the molecules of soda that they contain.

Answers

the answer would be D because they arent in constant motion, also they are made to HOLD two liters so it wouldnt be able to fill two liters with volume, finally the size of the bottle doesnt change when you place it somewhere so D is the only one that makes sense and is actually true.
hope this helps

The molecules that make up a plastic two-liter bottle are closer together than the molecules of soda that they contain.

What is solid?

One of the four common states of matter is solid. Solids have tightly bonded molecules that can only vibrate. This means that solids have a fixed shape that only modifies under the application of force. This contrasts with the random movement of gases and liquids, known as flow.

Melting is the process by which a solid turns into a liquid. When liquids are frozen, they solidify. Dry ice is one of the few materials that can transform directly from a solid to a gas. Sublimation is the term used for this.

Numerous types of forces can exist between the atoms in a solid. For instance, ionic sodium and chlorine are bound together by ionic bonds to form the crystal structure of sodium chloride (common salt).

Learn more about solid here:

https://brainly.com/question/17061172

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