Give the charge and full ground-state electron configuration of the monatomic ion most likely to be formed by the element. rb
a. rb+: 1s22s22p63s23p64s23d104p65s2
b. rb+: 1s22s22p63s23p64s23d104p65s1
c. rb+: 1s22s22p63s23p64s23d104p5
d. rb+: 1s22s22p63s23p64s23d104p6
e. none of these

Answer:

D

Explanation:

Planet, Solar System Galaxy and Universe

Answer:

A whole number.

Explanation:

Hello,

Empirical formula is the smallest representation of a chemical formula and the molecular formula is the actual formula of a given compound. For instance, glucose has the following molecular formula:

[tex]C_6H_{12}O_6[/tex]

But its empirical formula is:

[tex]CH_2O[/tex]

So they are relation by the 6 as a whole number.

Best regards.

Answer:   Iodine

Explanation:  Cesium is the alkali metal which belongs to the group 1 of the periodic table.

Iodine is the Group 17 element which are known as the Halogens as they are the group of the most electronegative atoms.

Zinc belongs to the Transition metal d block .

Xenon belongs to the Group 18 of noble gases.

The electronic configuration will help us to determine which can gain electron to have a full outermost shell.

Cesium (Cs) = [Xe] 6s1

Zinc (Zn) = [Ar] 3d10 4s2

Iodine(I) =  [Kr] 4d10 5s2 5p5

Xenon (Xe) = Kr 4d10 5s2 5p6

Thus Iodine can easily gain one electron to have complete outermost shell.

Answer:

I would use calorimetry to determine the specific heat.

I would measure the mass of a sample of the substance.

I would heat the substance to a known temperature.

I would place the heated substance into a coffee-cup calorimeter containing a known mass of water with a known initial temperature. I would wait for the temperature to equilibrate, then calculate temperature change. I would use the temperature change of water to determine the amount of energy absorbed. I would use the amount of energy lost by substance, mass, and temperature change to calculate specific heat.

Explanation:

Answer on Edg 21'

Final answer:

To find the maximum permissible length for an 18-gauge extension cord for use with a power saw, one must calculate the voltage drop the cord can tolerate (5 V) and use the ohmic resistance per length unit of an 18-gauge wire to maintain at least 115 V for the saw's operation. This involves applying Ohm's Law and wire resistance specifications.

Explanation:

Finding the Maximum Permissible Length for an 18-Gauge Extension Cord:

To determine the maximum permissible length for an 18-gauge (1.0 mm diameter) copper wire extension cord for a power saw that draws 9.0 A and requires a minimum of 115 V to operate efficiently when the outlet supplies 120 V, we need to calculate the allowable voltage drop and then translate that into a length given the specific characteristics of the wire.

Voltage Drop Calculation:

The power saw can tolerate a voltage drop of 5 V (from 120 V to 115 V). Using Ohm's Law (V = IR), where V is the voltage, I is the current, and R is the resistance, we can determine the maximum resistance of the cord allowed to ensure the voltage at the saw does not drop below 115 V. First, we calculate the maximum allowable voltage drop per meter (or foot) of wire using the resistance per length unit for an 18-gauge copper wire.

Since an 18-gauge wire has specific resistance (often found in tables or the manufacturer's specifications), that value can be applied to determine how the calculated voltage drop correlates to a length. For example, if the resistance of an 18-gauge copper wire is 6.385 ohms per kilometer (0.006385 ohms per meter), and the power saw draws 9.0 A, the maximum permissible voltage drop of 5 V could be distributed across a specific length of wire without exceeding the minimum requirement of 115 V at the tool.

Conclusion:

Using the calculated resistance, the homeowner or electrician can then calculate the exact permissible length, ensuring the power saw operates within safe electrical parameters. It's essential to consult up-to-date tables for wire resistance to ensure accuracy.

Based on its products when it is dissolved in water, the substance that is a strong electrolyte is Sodium Nitrate.

An electrolyte refers to a substance that has ions. When Sodium Nitrate is dissolved in water, it leads to Hydrochloric acid being formed.

Hydrochloric acid is a strong acid which means that it is full of ions. Sodium Nitrate can therefore be said to be a strong electrolyte.

In conclusion, option C is correct.

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Given the Ka value for hydrazoic acid and the concentration of sodium azide, calculating the precise pH would typically involve understanding the dissociation degree or specific details about the ionization in the solution to apply the proper formulas. Without complete data, an exact pH calculation isn't directly attainable.

The question asks about the pH of a 0.35 M solution of sodium azide. Sodium azide (NaN3) dissociates in water to produce azide ions (N3-) and sodium ions (Na+). The azide ions then react with water to generate hydrazoic acid (HN3) and hydroxide ions (OH-), which affects the pH of the solution.

Given the Ka (acid dissociation constant) value for hydrazoic acid (HN3) is 1.9, and the concentration of sodium azide is 0.35 M, we can calculate the pH by first determining the pKa using the formula pKa = -log(Ka), then using the Henderson-Hasselbalch equation to find the pH, which is used for buffer solutions or weak acid/conjugate base systems.

However, since the concentration of sodium azide is directly given and it's a base forming solution, direct use of the pKa and Ka values without the concentrations of the conjugate pairs in a specific equation elucidating hydroxide ion concentration followed by pH calculation might be needed. Yet, a complete calculation would require the dissociation degree or further specific context about the system to accurately determine the pH, which isn't directly provided.

Final answer:

Ribosomal RNA (rRNA) is crucial for aligning mRNA and ribosomes during protein synthesis and catalyzing the formation of peptide bonds between amino acids. It is a key component of the ribosome, which directs the assembly of protein molecules. Transfer RNA (tRNA) assists by delivering the correct amino acids for incorporation into the protein.

Explanation:

Role of Ribosomal RNA (rRNA) during Translation

Ribosomal RNA (rRNA) plays a critical role during the process of translation, which is the synthesis of proteins in the cells. rRNA is a major component of ribosomes, which are the cellular structures where translation occurs. The rRNA ensures the correct alignment of mRNA and the ribosomes, which is essential for the decoding of the mRNA sequence into a polypeptide chain. Furthermore, rRNA has enzymatic activity and catalyzes the formation of peptide bonds between aligned amino acids, which is a pivotal step in the creation of a protein.

Transfer RNA (tRNA) also contributes to translation by carrying the appropriate amino acid to the ribosome, determined by its anticodon's base pairing with the corresponding codon on the mRNA. Each tRNA carries a specific amino acid that gets added to the growing polypeptide chain, thus translating the genetic code into a functional protein.

Final answer:

Ribosomal RNA (rRNA) is integral to protein synthesis during translation, aligning mRNA and ribosomes and catalyzing peptide bond formation. It works in conjunction with transfer RNA (tRNA), which brings amino acids to the ribosome.

Explanation:

The role of ribosomal RNA (rRNA) during translation is crucial to protein synthesis. rRNA constitutes a major part of ribosomes, which are the molecular machines that synthesize proteins. It ensures the proper alignment of mRNA and ribosomes, facilitating the reading of genetic information found on the mRNA. Moreover, rRNA has an enzymatic activity and catalyzes the formation of peptide bonds between aligned amino acids, incrementally building the polypeptide chain that will make up the protein.

Transfer RNA (tRNA) complements the process by carrying amino acids to the ribosome, matching them with the appropriate codons on the mRNA. The interactions between tRNA and mRNA are mediated by the rRNA, ensuring that each amino acid is correctly added in sequence to the growing polypeptide chain.

While rRNA and tRNA are essential for translation, they differ in their functions; rRNA primarily acts as a structural and catalytic component of the ribosome, whereas tRNA serves as a transport molecule that brings specific amino acids to the correct location.

The most significant resonance forms of silicon dioxide are those depicting silicon atoms tetrahedrally coordinated to four oxygen atoms with single Si-O bonds, forming a three-dimensional network. Silicon's lower tendency to form pi bonds compared to carbon leads to a covalent network solid structure, differing greatly from the molecular structure of CO2.

The question asks which resonance forms of silicon dioxide (SiO₂) contribute the most to the actual bonding in the substance. In the case of SiO₂, resonance forms with discrete silicon-oxygen double bonds are not favored due to silicon's tendency to form a three-dimensional network structure, where each silicon atom is tetrahedrally coordinated, forming four Si-O single bonds. This contrasts with carbon dioxide (CO₂), which forms strong double bonds due to carbon's ability to form π bonds effectively.

Silicon has an electron configuration of 3s²3p², which encourages sp³ hybridization and results in SiO₂ manifesting as a covalent network solid, where the SiO₄ tetrahedra share oxygen atoms in a continuous lattice. This structure is significantly different from that of molecular CO₂, which consists of discrete molecules held together by weak intermolecular forces. Therefore, the most representative forms of SiO₂ in terms of actual bonding would be those illustrating single Si-O bonds forming an extended network.

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Answer:

they have the same valance electrons

Explanation:

Crucible tongs are mandatory to handle hot crucibles to avoid skin burns and accidents during experimental procedures. Crucible tongs work with the crucible; their shape was designed to firmly hold it to avoid spills.

Touching the magnesium metal can actually contaminate it and bring with it impurities which may not be removed by heating. So this leads to error in weighing.

There are two reasons not to touch the crucible tong with bare hands:

1. The crucible tong is used during firing so it is extremely hot and may burn your hands

2. Any impurities in your hand may contaminate the tong hence leading to error just like the case for the magnesium metal

The structure of methyl acrylate is

The balanced equation for the reaction between aluminum and nitric acid is: 2Al(s) + 6HNO3(aq) → 2Al(NO3)3(aq) + 3H2(g). This represents the formation of aluminum nitrate and hydrogen gas from aluminum and nitric acid.

The chemical reaction where aluminum metal reacts with nitric acid to produce aluminum nitrate and hydrogen gas can be written and balanced as follows:

2Al(s) + 6HNO3(aq) → 2Al(NO3)3(aq) + 3H2(g)

Here, Al stands for Aluminum, H for Hydrogen, N for Nitrogen, and O for Oxygen. The symbols (s), (aq), and (g) designate the physical states solid, aqueous (in water), and gas, respectively. Nitric acid, HNO3, reacts with aluminum, Al, to form aluminum nitrate, Al(NO3)3, and hydrogen gas, H2.

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Final answer:

To find the mass of barium in a 620 mg tablet of barium sulfate, multiply the tablet's mass by the percentage of barium (58.8%). The calculation yields approximately 364.56 mg of barium in the tablet.

Explanation:

The question is asking to calculate the mass of barium present in a 620 mg tablet of barium sulfate, a compound known for its use in medical imaging. Given that barium sulfate is 58.8% barium by mass, we can calculate the mass of barium in the tablet by multiplying the total mass of the tablet by the percentage of barium.

To find the amount of barium, we use the following calculation:

Mass of barium = (mass of barium sulfate tablet) x (percentage of barium) / 100%

Mass of barium = (620 mg) x (58.8%) / 100

Mass of barium = 620 mg x 0.588

Mass of barium ≈ 364.56 mg

Therefore, a 620 mg tablet of barium sulfate contains approximately 364.56 mg of barium.

Final answer:

To calculate the enthalpy change for burning 18.0 g of methyl alcohol, use stoichiometry and the balanced chemical equation for the combustion of methyl alcohol. Convert the mass of methyl alcohol to moles and then use the mole ratio from the balanced equation to determine the moles of products. Finally, multiply the moles of products by the enthalpy change per mole to find the enthalpy change in kilojoules.

Explanation:

The enthalpy change for burning 18.0 g of methyl alcohol can be calculated using stoichiometry. First, convert the mass of methyl alcohol to moles by dividing by its molar mass. Then, use the balanced chemical equation for the combustion of methyl alcohol to determine the ratio of moles of methyl alcohol to moles of products. Finally, multiply the moles of methyl alcohol by the enthalpy change per mole to find the enthalpy change in kilojoules.

For example, the balanced equation for the combustion of methyl alcohol is: 2CH3OH + 3O2 -> 2CO2 + 4H2O

The enthalpy change for this reaction is -726 kJ per mole of methyl alcohol. Therefore, to find the enthalpy change for burning 18.0 g of methyl alcohol, you would follow these steps:

Isoelectronic pairs consist of atoms and ions with identical electron configurations. Examples include the pairs N³, 0²-, F¯, Ne, Na+, Mg²+, and Al³+ (1s²2s²2p6) and P³-, S²-, Cl-, Ar, K+, Ca²+, and Sc³+ ([Ne]3s²3p6). Understanding atomic structure and electron distribution is key to understanding chemical bonding and molecular formation.

Isoelectronic pairs are atoms and ions that have the same electron configuration. For example, N³, 0²-, F¯, Ne, Na+, Mg²+, and Al³+ (1s²2s²2p6) are all isoelectronic because they share the same configuration. Another isoelectronic series is P³-, S²-, Cl-, Ar, K+, Ca²+, and Sc³+ ([Ne]3s²3p6).

Methods to understand and predict how atoms will combine to form molecules is through the electron-pair geometry and molecular structure. For instance, carbon (atomic number 6) has six electrons, filling the 1s and 2s orbitals, with the remaining two occupying the 2p subshell. According to Hund's rule, the lowest-energy configuration for an atom with electrons within a set of degenerate orbitals is that having the maximum number of unpaired electrons.

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