Give the name of the element that is a member of the alkali metal family whose most stable ion contains 2 electrons.

Explanation:

Molality is defined as the number of moles of solute per kg of solution. That is, molality depends on the mass.  

Whereas molarity is defined as the number of moles per liter of solution. That is, molarity depends on the volume of solution.

Also, when there is change in temperature then volume of solution changes but mass does not change.

Thus we can conclude that investigating changes in colligative properties involves the measurement of a solution's concentration in molality instead of molarity because mass does not change whereas volume does change.

Answer: Oxygen is the second most abundant gas in our atmosphere. ap

Explanation:

To find the density of a liquid with a mass of 22.00 grams and a volume of 10.0 ml, divide the mass by the volume to get a density of 2.20 g/ml.

To calculate the density of a liquid, you can use the formula:

Density = mass / volume

In this case, the mass of the liquid is 22.00 grams and the volume is 10.0 ml (which can also be written as 10.0 cm³ as 1 ml is equivalent to 1 cm³). Plugging these values into the formula gives us:

Density = 22.00 g / 10.0 ml = 2.20 g/ml

Therefore, the density of the liquid is 2.20 g/ml.

Answer:  High Reactivity

Explanation:  Alkali metals are the metals which are kept in the group 1 which is also known as S -Block elements.

The electronic configuration of the elements can be written as ns1 .

These are considered to be the most reactive elements of the whole periodic table because their outermost shell has only 1 vacant electron and thus are in need of only 1 electron to complete its duplet or either they can also lose that  one electron .

This the reason they can never be found pure in the nature .

Answer:

3 moles of HClO₄ is required to neutralize 1 mole Al(OH)₃.

Explanation:

The neutralization reaction between HClO₄and Al(OH)₃is as follows:

HClO₄ + Al(OH)₃ -> Al(ClO₄)₃ + H₂O

The balanced reaction is as follows:

3HClO₄ + Al(OH)₃ -> Al(ClO₄)₃ + 3H₂O

Based on the balanced molecular equation the molar ratio of HClO₄ : Al(OH)₃ is 3:1.  

So 3 moles of HClO₄ is required to neutralize 1 mole Al(OH)₃.  

When aqueous solutions of [tex]\rm NiBr_2\;and\;AgNO_3[/tex]  are mixed, a precipitate form.

A precipitation can occur when two solutions containing different salts are mixed, and a cation/anion pair in the resulting combined solution forms an insoluble salt; this salt then precipitates out of solution.

In the given combination,

[tex]\rm K_2SO_4\;and\;CrCl_3[/tex] : The reaction will result in Group 1A compounds which are soluble.

[tex]\rm NaI\;and\;KBr[/tex] : The reaction will result in Group 1A compounds which are soluble.

[tex]\rm Li_2CO_3\;and\;CSi[/tex] : carbonates with group 1A elements becomes soluble.

[tex]\rm NiBr_2\;and\;AgNO_3[/tex] : The product will be a halide with Ag which are insoluble in water, and thus precipitates out.

When aqueous solutions of [tex]\rm NiBr_2\;and\;AgNO_3[/tex]  are mixed, a precipitate form.

For more information about precipitate formation, refer to the link:

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To find the number of moles of MgCl₂ in 41.5 g, you divide the mass of the substance by its molar mass. The molar mass of MgCl₂ is 95.21 g/mol, resulting in 0.436 moles of MgCl₂.

To calculate the number of moles of MgCl₂ in 41.5 g, you need to know the molar mass of MgCl₂.

The molar mass is the sum of the mass of one mole of magnesium (Mg) ions and two moles of chloride (Cl) ions.

The molar mass of Mg is 24.305 g/mol and the molar mass of Cl is 35.45 g/mol.

Therefore, the molar mass of MgCl₂ is (1 × 24.305) + (2 × 35.45) = 95.21 g/mol.

Next, use the formula: Number of moles = Mass of substance (g) / Molar mass (g/mol)

Number of moles of MgCl₂ = 41.5 g / 95.21 g/mol = 0.436 moles of MgCl₂.

The mass of H2(g) collected is approximately calculated as 0.582 grams. This result is found by subtracting the water's vapor pressure from the total pressure, applying the ideal gas law to find the number of moles, and converting moles to grams.

To calculate the mass of H2(g) collected, we'll first need to calculate the pressure of the dry hydrogen gas. The pressure of a gas collected over water is a sum of the pressure of the dry gas and the vapor pressure of the water. Hence, the pressure of dry H2(g) is the total pressure minus the water vapor pressure, so 685 mmHg - 18.6 mmHg = 666.4 mmHg.

Next, we convert this pressure into atmospheres: 666.4 mmHg * (1 atm / 760 mmHg) = 0.877 atm (approximately). We'll also need to convert the temperature to Kelvin: 21ºC + 273 = 294 K.

Then, we can use the ideal gas law, PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant (0.0821 L*atm/K*mol), and T is temperature. Solving for n, n = PV / RT, we substitute the known values to get n = (0.877 atm * 7.80 L) / (0.0821 L*atm/K*mol * 294 K) = 0.291 mol.

Last, we turn moles of H2 into grams. As the molar mass of H2(g) is approximately 2 g/mol, the mass of H2(g) collected is 0.291 mol * 2 g/mol = 0.582 grams.

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Answer: Option (D) is the correct answer.

Explanation:

When there is minimum use of energy and we are still able to preserve resources then it means we are cutting the demand for energy.

Therefore, when we are treating water with chlorine then it means without any electricity or energy we are cleaning the water. But at the same time chlorinated water is harmful to use unless chlorine is dissolved in limiting quantity.

Whereas energy efficient appliances will use the electricity efficiently.

Landfill will require the use of machines or man power therefore, energy will be used.

On the other hand, when rules are framed against the use of chlorofluorocarbons then there will be lesser depletion of ozone layer. Hence, use of energy will be minimum.

Thus, we can conclude that legislation against the use of chlorofluorocarbons has helped preserve resources while cutting the demand for energy.

I think it’s “cathode rays are negatively-charged particles.”

Explanation:

Answer:  Carbonyl is the functional group.

Explanation:  Aldehyde is a functional group containing the group -CHO .

Amide is the functional group which contains the group -CONH2.

Carboxyl is the functional group which contains the group -COOH.

And Hydroxyl is the functional group which contains the group -OH.

The balanced thermochemical equation for the decomposition of methanol (CH3OH(g)) to form CH4(g) and O2(g) is CH3OH(g) -> CH4(g) + O2(g) + 252.8 kJ/mol of O2 formed.

The balanced thermochemical equation for the decomposition of methanol (CH3OH(g)) to form CH4(g) and O2(g) can be written as:

CH3OH(g) -> CH4(g) + O2(g) + 252.8 kJ/mol of O2 formed.

To determine the pH of a solution which has 0.06 m in sodium benzoate (nac7h5o2) and 0.09 m in benzoic acid (hc7h5o2), we use the ICE table and the acid dissociation constant of hc7h5o2 to determine the concentration of the hydrogen ion present at equilibrium. We do as follows:

HC7H5O2 = H+ + C7H5O2-
NaC7H5O2 = Na+ + C7H5O2-

Therefore, the only source of hydrogen ion would be the acid. We use the ICE table,
                   HC7H5O2           H+        C7H5O2-
I                     0.09                  0              0.06
C                      -x                    +x               +x
------------------------------------------------------------------
E                 0.09-x                x              0.06+ x

Ka = 6.28x10^(-5) = (0.06 + x) (x) / 0.09 -x 
x = 9.40x10^-5 M = [H+]

pH = - log [H+] 
pH = -log  9.40x10^-5 M
pH = 4.03

Therefore, the pH of the resulting solution would be 4.03.

An acid.

An acidic compound.

*Acids increase concentrations of H+ ions.

The balanced nuclear equation for the beta decay of carbon-11 is ⁶₁₁C → ⁶₁₂N + ⁰⁻₁e, which indicates carbon-11 transforming into nitrogen-11 and emitting a beta particle (electron).

The beta decay of carbon-11 is a type of radioactive decay where a beta particle (an electron) is emitted from an atomic nucleus. Writing a balanced nuclear equation for this process involves showing the original nucleus, the emitted beta particle, and the resulting daughter nucleus. In beta decay, a neutron in the nucleus is transformed into a proton and an electron. The electron is ejected from the nucleus as the beta particle, and the atomic number of the nucleus increases by one while the mass number remains the same.

The balanced nuclear equation for the beta decay of carbon-11 is:

⁶₁₁C → ⁶₁₂N + ⁰⁻₁e

Here, carbon-11 (⁶₁₁C), with 6 protons and 5 neutrons, decays to nitrogen-11 (⁶₁₂N), which has 7 protons and 4 neutrons, by emitting a beta particle (⁰⁻₁e, also represented as β-). This process increases the atomic number by one, from carbon (6) to nitrogen (7), while the mass number remains 11.

Final answer:

The balanced nuclear equation for the beta decay of carbon-11 is 11C → 11B + β + γ. The daughter isotope in this decay is boron-11 (11B).

Explanation:

The balanced nuclear equation for the beta decay of carbon-11 is:

11C → 11B + β + γ

The daughter isotope in this decay is boron-11 (11B).

Answer:

A

Explanation:

The answer is A, fat because of the hydrogen compounds and the carbon center compounds.