Graph the equation on the coordinate plane.

How would I graph it?

y=12x

The most accurate statement is 2 ≤ x ≤ 12 or x is between 2 and 12, inclusive.

The statement that best describes the domain of the function represented in the graph is 2 ≤ x ≤ 12 or x is between 2 and 12, inclusive.

The domain of a function refers to all the possible input values (in this case, the quantity of blue paint) for which the function produces an output (the quantity of red paint).

Looking at the graph, we can see that the line segment starts at a blue paint quantity of 2 and ends at a blue paint quantity of 12.

Since the endpoints are included in the line segment, we know that the function is defined for all blue paint quantities between 2 and 12, inclusive.

Therefore, the most accurate statement is 2 ≤ x ≤ 12 or x is between 2 and 12, inclusive.

The possible values for the product [tex]\( a \cdot b \)[/tex] are between -14 and 14, inclusive.

Here's the step-by-step calculation:

1. To find the minimum possible value, we multiply the smallest values of ( a ) and ( b ):

[tex]\( a = -5 \) and \( b = -7 \)[/tex]

[tex]\( a \cdot b = (-5) \cdot (-7) = 35 \)[/tex]

2. To find the maximum possible value, we multiply the largest values of ( a ) and ( b ):

[tex]\( a = 2 \) and \( b = 1 \)[/tex]

 [tex]\( a \cdot b = 2 \cdot 1 = 2 \)[/tex]

So, the possible values for the product[tex]\( a \cdot b \)[/tex]  are between -14 and 14.

The range of values for( a ) is from -5 to 2, and for ( b ) is from -7 to 1. To find the extreme values of the product [tex]\( a \cdot b \),[/tex]  we multiply the smallest and largest values of ( a ) and ( b ).

For the minimum value, we take ( a = -5 ) and ( b = -7 ), which gives us [tex]( a \cdot b = 35 \).[/tex]

For the maximum value, we take ( a = 2 ) and ( b = 1 ), which gives us [tex]\( a \cdot b = 2 \).[/tex]

Therefore, the product[tex]\( a \cdot b \)[/tex] ranges from -14 to 14, inclusively.

complete question

If the value of "a" lies between −5 and 2 and the value of "b" lies between −7 and 1, what are the possible values for the product a· b?

Final answer:

In Zoe's class, 1/10 of the students have pets that are rodents, while 7/10 have pets that are not rodents.

Explanation:

To calculate the fraction of students in Zoe's class who have pets that are rodents, you multiply the fraction of students who have pets by the fraction of those pet owners who have rodents:

4/5 × 1/8 = 4/40 or simplified, 1/10.

This means 1/10 of Zoe's class have rodents as pets.

Now, to find out the fraction of students with pets that are not rodents, subtract the fraction of students with rodents from the total fraction of students with pets:

4/5 - 1/10 = 32/40 - 4/40 = 28/40, which simplifies to 7/10.

So, 7/10 of Zoe's class have pets that are not rodents.

Answer:

"6 times the  difference of 12 and 4"

Step-by-step explanation:

Given: [tex]6\times (12-4)[/tex]

To write the given expression in words.

"6 times the difference of 12 and 4"

Because difference of 12 and 4 is 12-4

6 times of a number(n) is 6n

Therefore,

[tex]6\times (12-4)[/tex] as phrase "6 times the  difference of 12 and 4"

Hence, The phrase of the given expression is "6 times the  difference of 12 and 4"

To find the sum of 5 consecutive integers, use the formula (n + n+1 + n+2 + n+3 + n+4), where n is the first integer. The consecutive integers are 99, 100, 101, 102, and 103.

To find the sum of 5 consecutive integers, we can use the formula (n + n+1 + n+2 + n+3 + n+4), where n is the first integer. In this case, the sum is 505, so we have the equation: n + (n+1) + (n+2) + (n+3) + (n+4) = 505. Simplifying this, we get: 5n + 10 = 505. Subtracting 10 from both sides gives 5n = 495. Dividing both sides by 5, we find that n = 99.

Therefore, the 5 consecutive integers are 99, 100, 101, 102, and 103.

Answer:

23 is the required answer.

Step-by-step explanation:

We are given a fraction of the form [tex]2\frac{5}{9}[/tex].

It is a mixed fraction.

We convert it into improper fraction.

The improper fraction is of the form [tex]\frac{(9\times2)+5}{9} = \frac{23}{9}[/tex].

This fraction can also be written as 23 multiplied [tex]\frac{1}{9}[/tex] times.

It is clear that the above fraction have 23 parts of ninth.

It would take 3 seconds for the ball to hit the ground

Given the initial velocity r = 48 feet per second feet per second, for the football to hit the ground, the height h will be 0.

Now, substitute the values, we have;

0 = 48t - 16t²

collect the like terms and rearrange to a quadratic equation, we get that;

16t² - 48t = 0

Now, we have to factor out the common term from the equation which is 16t, we have then that;

16t(t - 3) = 0

t- 3 = 0

collect the like terms, we get;

t = 3 seconds

Answer:

is b

Step-by-step explanation: i did the test