Answers
g=9.8ms-²
t=3s
V=- u +gt
V= 2.5+(9.8×3) = 2.5 + 29.4 = 31.9 ms-¹
Related Questions
Is the change in kinetic energy of your ball greater than, less than, or equal to the change in kinetic energy of your friend's ball?
Answers
Nylon is a “big” covalent molecule used to make backpacks. Which property of covalent compounds is most useful in making backpacks?
Answers
An electric field is established by applying a potential difference to the plates. it is found that a field of strength e0 will cause the droplet to be suspended motionless. write an expression for the droplet's charge q. let g be the acceleration due to gravity.
Answers
[tex]mg=qE[/tex]
From this equality we can deduce the charge of the droplet necessary for the particle to stay suspended:
[tex]q= mg/E[/tex]
where m is its mass and E is the electric field that is applied.
Final answer:
When a droplet is motionless in an electric field, it means the electrical force exactly balances gravity. Coulomb's law defines the electrical force as proportional to charge [tex](\( q \))[/tex] and the field strength [tex](\( E_0 \))[/tex]. Meanwhile, gravity exerts a force[tex]\( mg \)[/tex], where [tex]\( m \)[/tex] is the droplet's mass and [tex]\( g \)[/tex] is gravity's acceleration. Equilibrium occurs when these forces match:
[tex]\[ qE_0 = mg \][/tex]
Rearranging, we find the droplet's charge [tex]\( q \):[/tex]
[tex]\[ q = \frac{mg}{E_0} \][/tex]
This expression signifies the charge required for equilibrium in the given electric field.
Explanation:
To find the expression for the droplet's charge [tex](\( q \)),[/tex] we can use the equilibrium condition where the electric force [tex](\( F_{\text{electric}} \))[/tex] due to the electric field [tex](\( E_0 \))[/tex]balances the gravitational force [tex](\( F_{\text{gravity}} \))[/tex]acting on the droplet.
The electric force [tex](\( F_{\text{electric}} \))[/tex] exerted on the droplet with charge [tex]\( q \) i[/tex]n an electric field [tex]\( E_0 \)[/tex] is given by Coulomb's law:
[tex]\[ F_{\text{electric}} = qE_0 \][/tex]
The gravitational force [tex](\( F_{\text{gravity}} \))[/tex] acting on the droplet with mass [tex]\( m \)[/tex] in a gravitational field [tex]\( g \)[/tex] is given by:
[tex]\[ F_{\text{gravity}} = mg \][/tex]
At equilibrium, these forces balance each other:
[tex]\[ qE_0 = mg \][/tex]
Solving for [tex]\( q \):[/tex]
[tex]\[ q = \frac{mg}{E_0} \][/tex]
So, the expression for the droplet's charge [tex]\( q \)[/tex] is:
[tex]\[ q = \frac{mg}{E_0} \][/tex]
If the coefficient of kinetic friction is 0.500, what was the object's speed as you released it?
Answers
Look first for the time to fall 1.1 m = √ 2.2 / 9.8 = 0.475 s
Then, look for the speed at edge = 0.5 / 0.475 = 1.055 m/s
Afterwards, compute for energy lost = word done against friction = F . d = µmgd = 0.5 x 0.1 x9.8 x 1.1 = 0.539 J
Then, compute for original energy = 0.539 + 1/2 x m x v^2 = 0.539 + (0.5 x 0.1 x 1.055^2) = 0. 595 J
Original speed = √ 2 E / m = √ 1.19 / 0.1 = 3.45 m/s
A 150 n sled is being pulled up a 28 ° rough ramp at constant speed by a force of 100 n parallel to the ramp. with what acceleration will the crate slide down, if it is released at some point on the ramp?
Answers
we can use newton's second law for finding the value of acceleration
that is F=MxA
M the mass
A is the acceleration
F= P-Fk, Fk= -Mgcosθμ and P=Mgsinθ
μ is the coefficient of friction
The value of μ can be found with the above condition
(pulled up a 28 ° rough ramp at constant speed)
this implies the acceleration is equal to zero
100N - mgsin(28°) -mgcos(28°)μ = 0 , from where
μ= [100N - mgsin(28°)] / mgcos(28°)
μ=0.2
and then,
F=MxA= Mgsinθ -Mgcosθμ finally A=gsin28° -gcos28° x0.2 =2.6m/s²
θ = 28°, the angle of the slope.
W = 150 N, the weight of the sled.
The normal reaction is
N = W cosθ = 150*cos(28) = 132.442 N
The component of the weight acting down the plane is
F = W sin θ = 150*sin(8) = 70.421 N
Case A; The sled is pulled up the slope.
Because the sled is in dynamic equilibrium, therefore
F + μN = 100
where μ = the kinetic coefficient of friction.
That is,
70.421 + 132.442μ = 100
μ = (100 - 70.421)/132.442 = 0.2233
Case B: The sled accelerates down the slope.
When the applied force of 100 N is removed, the sled accelerates down the slope due to its weight acting down the slope. The motion is opposed by kinetic friction.
That is,
Wsinθ - μWcosθ = ma
where
m = (150 N)/(9.8 m/s²) = 15.306 kg, the mass of the sled
a = the acceleration of the sled
Therefore
70.421 - 0.2233*132.442 = 15.306*a
a = 40.8467/15.306 = 2.669 m/s²
Answer:2.67 m/s² (nearest hundredth)
What is the connection between the liver (organ), UV radiation (sunlight), and bone tissue
Answers
The UV is needed by the skin to make previtamin D3. Previtamin D3 or cholecalciferol made from the skin will be changed in the liver into 25- hydroxyvitamin D3 and then sent to the kidney to be changed into 1,25- dihydroxyvitamin D3. The last change in the kidney will active the vitamin D. Vitamin D has a role in the calcium absorption which was will strengthen the bone tissue.
What are volume and density? How do they relate to each other?
Answers
______________________________
Density= It is the mass divided by the volume. Density is defined as the mass per unit volume.
Volume= the quantity of three-dimensional space enclosed by a closed surface, for example, the space that a substance (solid, liquid, gas, or plasma) or shape occupies or contains.
______________________________
Density expresses the proportional relationship between mass and volume of the substance. If the density of a particular substance is given in grams per milliliter, it indicates the number of grams present in 1 milliliter of that substance.
______________________________
A coin dropped from the top of a precipice takes 5.00 s to hit the ground. How high is the precipice?
A) 49.1 m
B) 245 m
C) 123 m
D) 25.5 m
Answers
∴ s = [tex] \frac{1}{2} a t^{2} [/tex]
∴ s = [tex] \frac{1}{2} [/tex]×9.8×5²
= 122.5m ~ 123m
in a 4 kilometer race, a runner completes the first kilometer in 5.9 minutes, the second kilometer in 6.2 minutes, the third kilometer in 6.3 minutes, and the final kilometer in 6 minutes. the average speed of the runner for the race is approximately
Answers
Then, divide the total amount by the number of data collected which is 4: 12.2/4= 3.05
The average speed of the runner of the race is approximately 3.05 km/min
Feel free to ask me any other questions you might have :)
Answer:
9.83 km/h
Explanation:
Given: in a 4 kilometer race, a runner completes the first kilometer in 5.9 minutes, the second kilometer in 6.2 minutes, the third kilometer in 6.3 minutes, and the final kilometer in 6 minutes.
To Find: the average speed of the runner for the race.
Solution:
In a 4 kilometer race,
time required to travel first kilometer = [tex]5.9[/tex] [tex]\text{minutes}[/tex]
time required to travel seoond kilometer = [tex]6.2[/tex] [tex]\text{minutes}[/tex]
time required to travel third kilometer = [tex]6.3[/tex] [tex]\text{minutes}[/tex]
time required to travel final kilometer = [tex]6[/tex] [tex]\text{minutes}[/tex]
we know that,
[tex]\text{Average speed}=\frac{\text{Total distance traveled}}{\text{Total time taken}}[/tex]
Total distance traveled = [tex]4[/tex] [tex]\text{kilometer}[/tex]
Total time taken = [tex](5.9+6.2+6.3+6)[/tex]
= [tex]24.4[/tex] [tex]\text{minutes}[/tex]
= [tex]\frac{24.4}{60}[/tex] [tex]\text{hours}[/tex]
putting values,
[tex]\text{Average speed}=\frac{4}{\frac{24.4}{60}}[/tex]
[tex]\text{Average speed}=\frac{4\times60}{24.4}[/tex]
=[tex]9.83[/tex] [tex]\text{km}/ \text{h}[/tex]
the average speed of the runner for the race is approximately [tex]9.83[/tex] [tex]\text{km}/ \text{h}[/tex]
Assume each tick mark represents 1 cm. Calculate the total displacement from 0 if an object moves 3 cm to the left, then 7 cm to the right, and then 6 cm to the left. The object moves cm to the left. What is the total distance the object travels? cm
Answers
The total displacement and total distance of the object that traveled should be -2cm and 16 cm.
Given that,
Each tick mark should be presented 1cm.If an object moves 3 cm to the left, then 7 cm to the right, and then 6 cm to the left.Here we assume a positive x-axis to the right-hand side.Based on the above information, the calculation is as follows:
The total displacement is
= 0 - 3 + 7 - 6
= -2 cm,
Thus, the object shifts 2 cm to the left-hand side.
Now
The total distance is
= 0 + 3 + 7 + 6
= 16 cm
Therefore we can conclude that the total displacement and total distance of the object that traveled should be -2cm and 16 cm.
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Answer:
The object moves ✔ 2 cm to the left.
What is the total distance the object travels? ✔ 16 cm.
A force of 250 N is applied to an object that accelerates at a rate of 10m/sec2. What is the mass of the object?
Answers
A source emits monochromatic light of wavelength 495 nm in air. when the light passes through a liquid, its wavelength reduces to 434 nm what is the liquid's index of refraction?
a. 1.14
b. 1.49
c. 2.03
d. 1.26
e. 1.33
Answers
n = c/v
where c = 3 x 10⁸ m/s, the speed of light in vacuum
v = the speed of light in the medium (the liquid).
The frequency of the light source is
f = (3 x 10⁸ m/s)/(495 x 10⁻⁹ m) = 6.0606 x 10¹⁴ Hz
Because the wavelength in the liquid is 434 nm = 434 x 10⁻⁹ m,
v = (6.0606 x 10¹⁴ 1/s)*(434 x 10⁻⁹ m) = 2.6303 x 10⁸ m/s
The refractive index is (3 x 10⁸)/(2.6303 x 10⁸) = 1.1406
Answer: a. 1.14
The liquid's index of refraction is approximately 1.88.
Explanation:To find the index of refraction for the liquid, we can use the formula:
n₁ / n₂ = λ₁ / λ₂
where n₁ and n₂ are the indices of refraction for air and the liquid, respectively, and λ₁ and λ₂ are the wavelengths of light in air and the liquid, respectively.
In this problem, we are given that the wavelength of light in air is 495 nm and the wavelength in the liquid is 434 nm. Plugging in these values, we get:
n₁ / n₂ = 495 nm / 434 nm
n₂ ≈ n₁ * (434 nm / 495 nm)
n₂ ≈ 1 * (434 nm / 495 nm)
n₂ ≈ 0.876
To convert the index of refraction to its decimal form, we add 1, giving us:
n₂ ≈ 0.876 + 1
n₂ ≈ 1.876
The liquid's index of refraction is approximately 1.876, which can be rounded to 1.88.
Two cars pass each other traveling at the same speed. one car has a constant velocity of 15.0 m/s, east. the other car has a constant acceleration of 1.00 m/s , west. how much time will have elapsed until the cars are 164 m apart?
Answers
The formula for calculating the distance at constant velocity is:
d = v * t
d = 15 t
The formula for distance at constant acceleration is:
d = v0 t + 0.5 a t^2
d = 15 t + 0.5 t^2
So after a sum distance of 164 m:
15 t + (15 t + 0.5 t^2) = 164
30 t + 0.5 t^2 = 164
t^2 + 60 t = 328
(t + 30)^2 = 328 + 30^2
t + 30 = ± 35.04
t = -65.04, 5.04
Since time cannot be negative, so the two cars are 164 m apart after about 5 seconds
What is the wavelength of an earthquake wave if it has a speed of 5 km/s and a frequency of 11 Hz?
Answers
v = f × λ
where:
v is the speed = 5 km/s
f is the frequency = 11 Hz
λ is the wavelength (in metres)
We need to convert the speed into meters
5 km/s = 5000 m/s
Then substitute these values into the formula:
5000 = 11 × λ
λ = 5000 ÷ 11
λ = 454.5 meters
"for general projectile motion, when the projectile is at the highest point of its trajectory"
Answers
A particle of mass m=5.00 kilograms is at rest at t=0.00 seconds. a varying force f(t)=6.00t2−4.00t+3.00 is acting on the particle between t=0.00 seconds and t=5.00 seconds. find the speed v of the particle at t=5.00 seconds. express your answer in meters per second to three significant figures.
Answers
The speed of the particle at [tex]t = 5\,{\text{s}}[/tex] is [tex]\fbox{43\,{\text{m/s}}}[/tex].
Further explanation:
Applied force is directly proportional to the mass of the body and the acceleration of the body.
Given:
The function for force is [tex]F\left( t \right) = 6{t^2} - 4t + 3[/tex].
The limit of time is [tex]t = 0\,{\text{s}}[/tex] to [tex]t = 5\,{\text{s}}[/tex].
The mass of the particle is [tex]5\,{\text{Kg}}[/tex].
Concept used:
The rate of change of displacement of a body in unit time is called speed of the body. It is a scalar quantity.
Newton’s second law of motion states that the rate of change of momentum is equal to the applied force.
The expression for the Newton’s second law is given as.
[tex]F=ma[/tex]
Rearrange the expression for the acceleration of the body.
[tex]a=\dfrac{F}{m}[/tex] …… (1)
Here, a is the acceleration of the body, F is the force applied and m is the mass of the body.
The rate of change of speed of a body in unit time is called acceleration of the body.
The expression for the acceleration is given as.
[tex]a=\dfrac{{dv}}{{dt}}[/tex]
Substitute [tex]\dfrac{{dv}}{{dt}}[/tex] for [tex]a[/tex] in equation (1).
[tex]\dfrac{{dv}}{{dt}} = \dfrac{F}{m}[/tex]
On integrating the above expression we get.
[tex]v = \dfrac{1}{m}\int\limits_0^5 {Fdt}[/tex] …… (2)
Substitute [tex]6{t^2} - 4t + 3[/tex] for[tex]F\left(t\right)[/tex] and [tex]5\,{\text{Kg}}[/tex] for m in equation (2).
[tex]\begin{aligned} v&=\frac{1}{{\left( {5\,{\text{Kg}}} \right)}}\int\limits_0^5 {\left( {6{t^2} - 4t + 3} \right)dt}\\&=\frac{1}{{\left( {5\,{\text{Kg}}}\right)}}\left|{3{t^3}-2{t^2}+ 3t}\right|_0^5\\&=\frac{{215}}{{5\,}}\,{\text{m/s}}\\&=43\,{\text{m/s}}\\\end{aligned}[/tex]
Thus, the speed of the particle is [tex]\fbox{43\,{\text{m/s}}}[/tex].
Learn more:
1. Motion under force https://brainly.com/question/4033012.
2. Conservation of momentum https://brainly.com/question/9484203.
3. Motion under friction https://brainly.com/question/7031524.
Answer Details:
Grade: College
Subject: Physics
Chapter: Kinematics
Keywords:
Acceleration, force, weight, mass, motion, impact, nail, hammer, acceleration, duration of impact, Newton’s laws, speed, rate of change, time , 43m/s, 5Kg.
why is the scatterplot the most commonly used type of graph in science?
Answers
A coin completes 18 spins in 12 seconds. The centripetal acceleration of the edge of the coin is 2.2 m/s2. The radius of the coin is m.
Answers
Answer:
2.5 cm
Explanation:
Number of spins in 12 seconds = 18
Number of spins in 1 second = 18 / 12 = 1.5
Number of spins in one second is called frequency.
f = 1.5 rps
ac = 2.2 m/s^2
Let r be the radius of coin
Centripetal acceleration, ac = r x w^2
2.2 = r x ( 2 x 3.14 x 1.5) ^2
2.2 = r x 88.7364
r = 0.025 m = 2.5 cm
Answer: 0.025 m or 2.5m
Explanation:
The number of spins given in 12 seconds = 18
So the number of spins in 1 second will be
= 18 / 12 = 1.5rps
The above result is the frequency because it is the number of spins in one second
Let f be frequency
f = 1.5 rps
Using centripetal acceleration given
Ca = 2.2 m/s^2
m is the radius of the given coin
Using the formula
Centripetal acceleration, = m x w^2
Knowing that w = 2πf
2.2 = m x ( 2 x 3.14 x 1.5) ^2
2.2 = m x 88.7364
m = 0.025 m
15. To use your left hand to determine the direction of the voltage developed in a moving conductor in a stationary magnetic field, you must point your A. forefinger in the direction of the motion. B. forefinger in the direction of the lines of force. C. thumb in the direction of the electromagnetic force. D. thumb in the direction of the magnetic flux.
Answers
Correct answer choice is:
B. forefinger in the direction of the lines of force.
Explanation:
The direction of the force - and consequently the transfer of the wire - can be defined by applying Fleming’s left-hand rule.
The forefinger tends to the direction of the magnetic field. The middle finger points in the course of the current. The thumb supplies the direction of force or movement working on the conductor. Fleming's Left Hand Rule is applied in electronic engines which are utilized in coolers, appliances, printers, etc.
A person's height and weight will change gradually, while other things, such as getting a driver's license, may occur suddenly and mark the beginning of a new phase in life. This difference is an example of the theme of development known as:
Answers
Answer:
Continuity vs. Stages
Explanation:
Continuity is the gradual changes that a person may experiment throught their life, good examples are the ones given in the question, height and weght increasing or changing over time, but stages start whenever something happens that changes the way of life of the person, for example graduating college and going into the labor force, or getting married.
Explain how new discoveries influence contemporary psychological perspectives
Answers
Answer:
New discoveries can either provide evidence to support or refute contemporary psychological perspectives, or they can lead to the development of new theories and perspectives.Explanation:
Which are the components of a typical refracting telescope? hints?
Answers
The components of a typical refracting telescope are basically convex object and convex eyepiece. The correct option is 1.
A typical refracting telescope is made up of a series of convex lenses. The objective lens is a convex lens positioned at the front of the telescope that collects and focuses light from distant objects. At the focus point, it creates an inverted actual picture.
The eyepiece, which is located at the telescope's back end, is likewise a convex lens. Its goal is to amplify the picture created by the objective lens so that the viewer may see a bigger, upright, magnified image.
In a standard refracting telescope, the correct combination is a convex objective lens and a convex eyepiece.
Thus, the correct option is 1.
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Your question seems incomplete, the probable complete question is:
Which are the components of a typical refracting telescope?
1.convex object and convex eyepiece
2. concave object and convex eyepiece
3. convex object and concave eyepiece
How many revolutions does the object make during the first 3.9 s?
Answers
The area which is located under the curve gives us the angle in radians; we divide this by 2π to get units in revs (revolutions).
So for 0 ≤ t ≤ 2,
number of revs = 20rad/s * 2s * 1rev/2π rads = 6.37 revs
So for 2 ≤ t ≤ 3.9,
number of revs = 10rad/s * 1.9s * 1rev/2πrads = 3.02 revs
Therefore the total is about:
6.37 revs + 3.02 revs = 9.39 revs ≈ 9.4 revs
To answer how many revolutions an object makes in 3.9 seconds, we require knowledge of the object's constant angular velocity or angular acceleration. With the angular velocity, the total radians rotated can be found and divided by 2π to get the number of revolutions.
Explanation:The question "How many revolutions does the object make during the first 3.9 s?" involves calculating the number of complete rotations or revolutions an object makes over a given period of time. In physics, this is often related to concepts of rotational motion, including angular velocity and angular acceleration. However, to calculate the number of revolutions over a certain time, we need to know either the constant angular velocity of the object, the angular acceleration, or another related quantity that would allow us to determine how the angle changes over time.
For example, if we know the angular velocity (ω) in radians per second (rad/s), we can calculate the number of revolutions by integrating the angular velocity over the given time period (3.9 s) or multiplying it by time if the angular velocity is constant. Since one revolution is equivalent to 2π radians, we can determine the total number of revolutions by dividing the total angle rotated (in radians) by 2π.
Compare the orderliness of the particles. In general, which state has the most orderly arrangement?
Answers
We have that the state with the orderly arrangement is
The Solid state
It is important to note that there are three states
Solid Liquid GaseousGenerally,The crystalline solid is the most well orderly arranged particle bond as it made up of a crystal lattice that has its particles well arranged.
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Use this excerpt from the text to answer the question. "Some people insist the United States is more properly called a republic rather than a democracy." The people who support this statement argue that the United States is a republic because in its government,
Answers
what is beach nourishment
Answers
The cold virus causes disease when it enters the _____ of the human body.
Answers
The cold virus causes disease when it enters the mucous membranes of the human body such as the nasal cavity.
The cold virus causes disease when it enters the mucous membranes of the human body, particularly the nasal cavity. The most common groups of cold viruses include rhinoviruses, coronaviruses, and adenoviruses. These viruses are transmitted through direct contact such as shaking hands, and droplet transmission which occurs when an infected person coughs or sneezes. The rhinoviruses in particular thrive in cooler temperatures found in the nasal passages, leading to symptoms such as runny nose, congestion, and sneezing.
Symptoms of a cold are a result of the body's inflammatory response to the viral infection. This response generates the typical signs of a cold, but the condition is usually self-limiting and resolves on its own within 1-2 weeks.
Two masses m1 = 5.40 kg and m2 which has a mass 80.0% that of m1, are attached to a cord of negligible mass which passes over a frictionless pulley also of negligible mass. If m1 and m2 start from rest, after they have each traveled a distance h = 2.00 m, use energy content to determine the following.
(a) speed v of the masses
Answers
To determine the speed of the masses after traveling a distance of 2.00 m, we can use the principle of conservation of energy.
Explanation:To determine the speed of the masses after traveling a distance of 2.00 m, we can use the principle of conservation of energy. The initial potential energy of the system is equal to the final kinetic energy. The potential energy is given by m1gh, where g is the acceleration due to gravity and h is the distance traveled. The kinetic energy is given by (1/2)m1v^2 + (1/2)m2v^2, where v is the speed of the masses.
Given that m2 has a mass of 80.0% of m1, m2 = 0.80 * m1. Plugging this information into the equation and solving for v, we get:
v = √(2gh / (m1 + m2))
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An airport has runways only 198 m long. a small plane must reach a ground speed of 39 m/s before it can become airborne. what average acceleration must the plane's engines provide if it is to take off safely from its airport? answer in units of m/s 2 .
Answers
v=39 m/s
u=0
t=?
a=?
v²=u²+2as
(39)²=(0)²+2(a)(198)
1521=396a
1521/396=a
3.84 m/s^2 = a
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Borace drew a diagram to compare the processes of scientific investigation and technological design.
Which belongs in the area labeled W?
Conduct an experiment
Design a solution
Analyze the results
Build a prototype
Answers
Answer:
Conduct an experiment
Explanation:
Borace drew a diagram to compare the processes of scientific investigation and technological design, then the area labeled W belongs to the Conduct an experiment, therefore the correct answer is option A.
What are the stages of technological design?There are mainly five stages of the technological design
Identifying the issue that needs to be solved is the first step in every problem-solving process.
The second stage is to imagine; during this phase, a designer would generate several concepts and conduct research on potential creations. They must pick a handful of their greatest concepts and then narrow it down to the best.
The chosen product from the imaging stage is planned in the third stage.
Testing, evaluating, and modifying the product are the fourth stage.
Thus, If Borace drew a diagram to compare the processes of scientific investigation and technological design, then the area labeled W belongs to the Conduct an experiment, therefore the correct answer is option A.
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