electric fields and magnetic fields both exhibit similar properties. where magnetic fields are natural electric fields are not but man made and can do the same things as a magnetic field.
For the parallel circuit in the previous part (with the switch closed), the current through the 20-ω resistor is _________ the current through 10-ω resistor. g
Less than
For the parallel circuit in the previous part (with the switch closed), the current through the 20-ω resistor is less than the current through 10-ω resistor.
Explanation;According to Ohm's Law, the current through a conductor is directly proportional to the potential difference at constant pressure and temperature.
Therefore; V α I
Mathematically; V = IR ; Where R is the resistance of a device or a conductor.
From the relationship; I = V/R ; which means current and resistance have inverse relationship such that an increase in resistance causes a decrease in electric current.
Therefore; the current through the 20-ω resistor is less than the current through 10-ω resistor.
In a parallel circuit, the current through a 20-ω resistor is half of the current through a 10-ω resistor. This is because in a parallel circuit, resistors with lower resistance will have more current flowing through them, which is a consequence of Ohm's Law.
Explanation:For a parallel circuit with a closed switch, the current through the resistors is influenced by their resistances.
According to Ohm's law, the current is inversely proportional to the resistance. Therefore, for the resistors of 20-ω and 10-ω, the current through the 20-ω resistor is half the current through the 10-ω resistor.
It is important to understand that in a parallel circuit, the voltage across each component is the same, and the total current in the circuit is the sum of the currents through each component. This implies that lower resistance components will draw more current from the circuit. The reason for this is represented mathematically in Ohm's law, which states that I = V/R.
Thus, when we speak about the 20-ω and 10-ω resistors, since they are assumed to have the same voltage across them, the current in the 20-ω resistor would be V/20, and the current in the 10-ω resistor would be V/10. This essentially means the current through the 20-ω resistor is half of the current through the 10-ω resistor given the same voltage.
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Kirchhoff's loop rule for circuit analysis is an expression of which of the following? Conservation of charge Conservation of energy Ampere's law Ohm's law Faraday's law
Final answer:
Kirchhoff's loop rule for circuit analysis expresses the conservation of energy, stating that the sum of all voltage gains and drops in a closed circuit loop must be zero. This rule, pivotal in analyzing complex electrical circuits, ensures that energy within the circuit is conserved, aligning with the principle that the total energy supplied equals the total energy used.
Explanation:
Kirchhoff's loop rule for circuit analysis is an expression of the conservation of energy. This rule, also known as Kirchhoff's second law or voltage law, asserts that the sum of all voltage drops and rises around any closed circuit loop must equal zero. It effectively ensures that energy is conserved within an electrical circuit, reflecting the principle that the total energy supplied in the circuit equals the total energy used.
Kirchhoff's rules, including both the loop rule and the junction rule (which reflects the conservation of charge), are fundamental in analyzing electrical circuits. They allow for the calculation of potential differences and currents within complex circuits, making them pivotal tools in circuit analysis. Kirchhoff's loop rule is a simplification of Faraday's law of induction and holds true under the assumption that there is no fluctuating magnetic field linking the closed loop.
This simplicity makes the loop rule a powerful tool for analyzing circuits in a wide variety of situations, regardless of the circuit's composition and structure. By applying these rules, currents in the circuit can be related through the junction rule, and a system of equations can be generated using the loop rule to solve for each current value, thus conserving energy throughout the circuit.
When a sound wave moves past a point in air, are there changes in the density of air at this point?
Answer:
Yes
Explanation:
When a sound wave moves through the air, a point in the air undergoes alternative changes in density called compressions and rarefactions.
A sound wave is a longitudinal waves, which means that the vibrations of the particles in the medium occur in a direction parallel to the direction of motion of the wave. Longitudinal waves creates two different regions in the medium:
- Compressions: these are regions where the density of the particles of the medium (in this case, air particles) are higher
- Rarefactions: these are regions where the density of the particles of the medium (in this case, air particles) are lower
A guitar string with a linear density of 2.0 g/m is stretched between supports that are 60cm apart. The string is observed to form a standing wave with three antinodes when driven at a frequency of 420 Hz. What are (a) the frequency of the fifth harmonic of this string and (b) the tension in the string?
(a) 700 Hz
For standing waves on a string, the number of antinodes (n) corresponds to the order of the harmonic. So, three antinodes corresponds to the third harmonic. Also, the frequency of the nth-harmonic is the nth-integer multiple of the fundamental frequency, so we have:
[tex]f_3 = 3 f_1 = 420 Hz[/tex]
where [tex]f_1[/tex] is the fundamental frequency. Solving for f1, we find
[tex]f_1 = \frac{420 Hz}{3}=140 Hz[/tex]
And so now we can find the frequency of the 5th-harmonic:
[tex]f_5 = 5 f_1 = 5 (140 Hz)=700 Hz[/tex]
(b) 56.4 N
The fundamental frequency of a string is given by:
[tex]f_1 = \frac{1}{2L} \sqrt{\frac{T}{\mu}}[/tex]
where we have:
L = 60 cm = 0.60 m is the length of the string
[tex]\mu = 2.0 g/m = 0.002 kg/m[/tex] is the linear density
T = ? is the tension in the string
Solving the formula for T and using the fundamental frequency, f1=140 Hz, we find
[tex]T=\mu (2Lf_1)^2=(0.002 kg/m)(2(0.60 m)(140 Hz))^2=56.4 N[/tex]
The frequency of the fifth harmonic of the string is 700 Hz, and the tension in the string is 56.448 N.
Explanation:The question pertains to harmonic frequencies and tension in instruments, particularly a guitar string. Using the information given, we will apply the principles of standing waves on the string, wave speed derived from linear mass density and tension, and harmonic frequencies.
(a) If you're looking for the frequency of the fifth harmonic, note that the frequency of a particular harmonic is that harmonic number times the fundamental frequency. In this case, the string shows a standing wave with three antinodes, which refers to the third harmonic. So, the third harmonic frequency is 420 Hz; thus, the fundamental frequency is 420 Hz / 3 = 140 Hz. So, the frequency of the fifth harmonic is 5 times the fundamental frequency = 5*140 Hz = 700 Hz.
(b) To determine the tension in the string, you must first calculate the wave speed. The wave speed (Vw) can be derived from the formula for the frequency of a string, Vw=2Lf, where L is the length of the string in meters and f is the fundamental frequency. Here, L=0.6 m and f= 140 Hz, hence Vw = 2*(0.6m)*(140Hz) = 168 m/s. Given that wave speed is also calculated via the square root of tension (T) divided by linear mass density (μ), you can rearrange this formula to solve for T. This gives you T = (Vw)^2 * μ . The linear density is given as 2.0 g/m, but we need to convert it to kg/m to match the wave speed unit, so μ = 0.002 kg/m. Plugging in the values we find the tension: T = (168 m/s)^2 * 0.002 kg/m = 56.448 N.
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A horizontal force of magnitude 46.7 N pushes a block of mass 4.35 kg across a floor where the coefficient of kinetic friction is 0.635. (a) How much work is done by that applied force on the block-floor system when the block slides through a displacement of 2.96 m across the floor? (b) During that displacement, the thermal energy of the block increases by 35.0 J. What is the increase in thermal energy of the floor? (c) What is the increase in the kinetic energy of the block?
(a) 138.2 J
Since the applied force is parallel to the displacement of the block, the work done by the force is given by:
[tex]W=Fd[/tex]
where
F = 46.7 N is the magnitude of the force
d = 2.96 m is the displacement of the block
Substituting the numbers into the equation, we find
[tex]W=(46.7 N)(2.96 m)=138.2 J[/tex]
(b) 45.1 J
In order to calculate the total energy dissipated among the floor and the block as thermal energy, we have to calculate the work done by the frictional force, which is
[tex]W_f = F_f d = (-\mu mg)d[/tex]
where[tex]\mu=0.635[/tex] is the coefficient of friction
m = 4.35 kg is the mass of the block
g = 9.8 m/s^2
d = 2.96 m is the displacement
and the negative sign is due to the fact that the frictional force has opposite direction to the displacement.
Substituting, we find
[tex]W_f =-(0.635)(4.35 kg)(9.8 m/s^2)(2.96 m)=-80.1 J[/tex]
The magnitude of this work is equal to the sum of the thermal energy dissipated between the floor and the block:
[tex]W_f = E_{floor}+E_{block}[/tex]
And since we know
[tex]W_f = 80.1 J\\E_{floor}=35.0 J[/tex]
we find
[tex]E_{floor}=W_f-E_{block}=80.1 J-35.0 J=45.1 J[/tex]
(c) 58.1 J
According to the work-energy theorem, the increase in kinetic energy of the block must be equal to the work done by the applied force minus the work done by friction (which becomes wasted thermal energy):
[tex]\Delta K=W-W_f[/tex]
Substituting
[tex]W=138.2 J\\W_f = 80.1 J[/tex]
We find
[tex]\Delta K=138.2 J-80.1 J=58.1 J[/tex]
A double-slit diffraction pattern is formed on a distant screen. If the separation between the slits decreases, what happens to the distance between interference fringes? Assume the angles involved remain small.
Answer:
the distance between interference fringes increases
Explanation:
For double-slit interference, the distance of the m-order maximum from the centre of the distant screen is
[tex]y=\frac{m \lambda D}{d}[/tex]
where [tex]\lambda[/tex] is the wavelength, D is the distance of the screen, and d the distance between the slits. The distance between two consecutive fringes (m and m+1) will be therefore
[tex]\Delta y = \frac{(m+1) \lambda D}{d}-\frac{m \lambda D}{d}=\frac{\lambda D}{d}[/tex]
and we see that it inversely proportional to the distance between the slits, d. Therefore, when the separation between the slits decreases, the distance between the interference fringes increases.
A bicyclist travels 60.0 kilometers in 3.5 hours. What's the cyclists average speed?
Speed = (distance covered) / (time to cover the distance)
Speed = (60 km) / (3.5 hr)
Speed = (60 / 3.5) (km/hr)
Speed = 17.14 km/hr
What type of device is a car engine?
A.A heat pump that uses heat to do work
B.A heat engine that uses work to move heat
C.A heat pump that uses work to move heat
D.A heat engine that uses heat to do work
B.A heat engine that uses work to move heat
Explanation;A heat engine involves a thermodynamic process that converts the heat supply in it into mechanical work.A heat engine makes use of the properties of thermodynamics to transform heat into work. Gasoline and diesel engines, jet engines, and steam turbines that generate electricity are all examples of heat enginewhen a physical change occurs what can not be affected as well?
A) size
B) shape
C) density
D) composition
A) Size
hope this helps
A( size like what the other person said
1. 412.9 g of dry ice sublimes at room temperature. a. What’s changing? --- sublimation b. What constant will you use? ----- 25.2 kJ c. What equation will you use? ------ Q=m(sublimation) d. Is energy being absorbed or released by the dry ice? ------- absorbed e. How much energy is being transferred? 2. Steam – specifically 72.9 g of steam – condenses. a. What’s changing? b. What constant will you use? c. What equation will you use? d. Is energy being absorbed or released by the steam? e. How much energy is being transferred? 3. A silver ring with a mass of 39.2 g is heated from 25.9 °C to 412.9 °C. a. What’s changing? b. What constant will you use? c. What equation will you use? d. Is energy being absorbed or released by the silver? e. How much energy is being transferred? 4. An ice cube with a mass of 156.3 g melts (starting at its freezing point) and then warms up to 56.232 °C. a. What’s changing? b. What constant will you use? c. What equation will you use? d. Is energy being absorbed or released by the ice cube? e. How much energy is being
1. 236 kJ
a. The phase (or state of matter) of the substance: from solid state to gas state (sublimation)
b. The enthalphy of sublimation, given by: [tex]\lambda=571 J/g[/tex]
c. The equation to use will be [tex]Q=m\lambda[/tex], where m is the mass of dry ice and [tex]\lambda[/tex] is the enthalpy of sublimation
d. The energy is being absorbed, because the heat is transferred from the environment to the dry ice: as a consequence, the bonds between the molecules of dry ice break and then move faster and faster, and so the substance turns from solid into gas directly.
e. The amount of energy being transferred is
[tex]Q=m\lambda=(412.9 g)(571 J/g)=2.36\cdot 10^5 J=236 kJ[/tex]
2. 165 kJ
a. The phase (or state of matter) of the substance: from gas state to liquid state (condensation)
b. The latent heat of vaporisation of water, given by [tex]\lambda=2260 J/g[/tex]
c. The equation to use will be [tex]Q=m\lambda[/tex], where m is the mass of steam that condenses and [tex]\lambda[/tex] is the latent heat of vaporisation
d. The energy is being released, since the substance turns from a gas state (where molecules move faster) into liquid state (where molecules move slower), so the internal energy of the substance has decreased, therefore heat has been released
e. The amount of energy being transferred is
[tex]Q=m\lambda=(72.9 g)(2260 J/g)=1.65\cdot 10^5 J=165 kJ[/tex]
3. 3.64 kJ
a. Only the temperature of the substance (which is increasing)
b. The specific heat capacity of silver, which is [tex]C_s = 0.240 J/gC[/tex]
c. The equation to use will be [tex]Q=m C_s \Delta T[/tex], where m is the mass of silver, Cs is the specific heat capacity and [tex]\Delta T[/tex] the increase in temperature
d. The energy is being absorbed by the silver, since its temperature increases, this means that its molecules move faster so energy should be provided to the silver by the surroundings
e. The amount of energy being transferred is
[tex]Q=m C_s \Delta T=(39.2 g)(0.240 J/gC)(412.9^{\circ}C-25.9^{\circ}C)=3641=3.64 kJ[/tex]
4. 89 kJ
a. Both the phase of the substance (from solid to liquid) and then the temperature
b. The latent heat of fusion of ice: [tex]\lambda=334 J/g[/tex] and the specific heat capacity of water: [tex]C_s=4.186 J/gC[/tex]
c. The equation to use will be [tex]Q=m\lambda + m C_s \Delta T[/tex], where m is the mass of ice, [tex]\lambda[/tex] the latent heat of fusion of ice, Cs is the specific heat capacity of water and [tex]\Delta T[/tex] the increase in temperature
d. The energy is being absorbed by the ice, at first to break the bonds between the molecules of ice and to cause the melting of ice, and then to increase the temperature of the water
e. The amount of energy being transferred is
[tex]Q=m\lambda +m C_s \Delta T=(156.3 g)(334 J/g)+(156.3 g)(4.186 J/gC)(56.232^{\circ}C-0^{\circ}C)=8.9\cdot 10^4 J=89 kJ[/tex]
A 2.0-m-tall man is 5.0 m from the converging lens of a camera. His image appears on a detector that is 50 mm behind the lens. How tall is his image on the detector?
Answer:
20 cm
Explanation:
We can solve the problem by using the magnification equation:
[tex]M=\frac{h_i}{h_o}=-\frac{q}{p}[/tex]
where
[tex]h_i[/tex] is the size of the image
[tex]h_o = 2.0 m[/tex] is the height of the real object (the man)
[tex]q=50 mm =0.050 m[/tex] is the distance of the image from the lens
[tex]p = 5.0 m[/tex] is the distance of the object (the man) from the lens
Solving the formula for [tex]h_i[/tex], we find
[tex]h_i = -\frac{q}{p}h_o=-\frac{0.050 m}{5.0 m}(2.0 m)=-0.02 m = -20 cm[/tex]
And the negative sign means the image is inverted.
The height of the image on the detector is 100 mm.
Explanation:To determine the height of the image on the detector, we can use the lens equation:
1/f = 1/di - 1/do
Where f is the focal length of the lens, di is the image distance, and do is the object distance.
In this case, the focal length of the lens is 50 mm, the object distance is 5.0 m, and the image distance is 50 mm (since the detector is located 50 mm behind the lens).
Substituting these values into the equation, we can solve for di:
1/50 = 1/di - 1/5000
Simplifying, we get:
di = 100 mm
This means that the height of the image on the detector is 100 mm, since the image distance is equal to the height of the image.
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an airplane takes off from Dallas Texas to fly to new york city traveling ne for 2,760 km the Same plane returns that day to Dallas the airplane spent 2 hours on the trip to new york city and the return trip took 2 1/2 hours what is the airplanes speed for the round trip
1,104
1,227
1,300
1104 km/hour
ExplanationDistance between Dallas Texas to New York = 2760 km
Time the plane took from Dallas to New York = 2 hours
Time the plane took from New York back to Dallas = 2.5 hours
Formula to use
distance = speed x timeSpeed the plane took from Dallas to New York
2760 = 2 x speed
speed = 2760 / 2
= 1380 km/hour
Speed the plane took from New York to Dallas (ROUND TRIP)
2760 = 2.5 x speed
speed = 2760 / 2.5
= 1104 km/hour
Answer: The speed of airplane is 1227 km/hr
Explanation:
Average speed is defined as the ratio of total distance traveled to the total time taken.
To calculate the average speed of the airplane, we use the equation:
[tex]\text{Average speed}=\frac{\text{Total distance traveled}}{\text{Total time taken}}[/tex]
We are given:
Total distance traveled = (2760 + 2760) km = 5520 km (Round trip)
Total time taken = (2 + 2.5) hr = 4.5 hr
Putting values in above equation, we get:
[tex]\text{Average speed of airplane}=\frac{5520km}{4.5hr}=1227km/hr[/tex]
Hence, the speed of airplane is 1227 km/hr
How do gamma rays differ from visible light
The difference between visible light and gamma rays is their frequency, energy and wavelength. All electromagnetic waves travel at the same speed, which is called the speed of light. ... Visible light has much lower energy and longer wavelengths than gamma radiation.
A ball is thrown upward with an initial velocity of 12.1 m/s. How long will it take to reach a velocity of -24.5 m/s?
= 3.73 seconds
Explanation;Using the equation;
v = u + at
where v is the final velocity, u is the initial velocity and a is the acceleration due to gravity (-g) and t is the time taken.
Therefore;
v = u - gt
Thus;
v = 24.5 m/s, u = 12.1 m/s, a = -g = 9.8 m/s²
-24.5 m/s = 12.1 - 9.8 × t
36.6 = 9.8 t
t = 36.6/9.8
= 3.73 seconds
What are beats? A. periodic fluctuations in the velocity of sound waves B. periodic fluctuations in the wavelength of sound waves C. periodic fluctuations in the intensity of sound waves D. periodic fluctuations in the frequency of sound waves
The answer is
C. periodic fluctuations in the intensity if sound waves.
Answer:
D. periodic fluctuations in the frequency of sound waves
Explanation:
Beat is referred to the phenomena that occurs when to sound waves interfer with each other and they have different frequencies.
This difference is what creates a beating, wich in sound waves manifest as high and low sounds, this as a result of the oscilating frequency .
Which shows the correct reflected ray? Question options: A B C D
I think the answer is D because the law of reflection is the angle of incidence is equal to the angle of reflection.
Answer:
D
Explanation:
The law of reflection states that:
- The incident ray and the reflected ray lie on the same plane
- The angle of reflection is equal to the angle of incidence
The angle of incidence is the angle between the direction of the incident ray and the normal to the surface, while the angle of reflection is the angle between the direction of the reflected ray and the normal to the surface.
From the figure, we see that the only situation where the angle of reflection is equal to the angle of incidence is ray D.
The law of reflection states that the angle of reflection is equal to the angle of incidence, with these angles measured relative to a line perpendicular to the reflecting surface. Mirrors adhere precisely to this law, reflecting light at specific angles. Your choice, D, is correct if it shows the reflected light ray making the same angle with the normal as the incident light ray.
Explanation:You are correct in thinking that the answer is D. The law of reflection stipulates that the angle of incidence (the angle at which incoming light hits a surface) is equal to the angle of reflection (the angle at which light is reflected). These angles are always measured relative to a line perpendicular to the surface, called the normal. In your case, the correct answer would be an option where the reflected ray is at the same angle to the normal as the incident ray. If D shows that, then D is indeed the correct answer.
Mirrors, having smooth surfaces, adhere to this law of reflection perfectly, reflecting light at specific angles. Rough surfaces, on the other hand, diffuse light, causing it to scatter in many directions. This is why we can see clearly in mirrors but not on rough surfaces.
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A. 25%
B. 20%
C. 10%
D. 80%
please show work :)
Substitute your values into the formula:
W = Work done = 288
[tex]Q_{in}[/tex] = 360
Solve to find e:
e = 288 ÷ 360 = 0.8
Convert e to a percentage by multiplying by 100.
0.8 × 100 = 80
D. 80%Which of these stars has the hottest core?A)a blue main-sequnce star. B)a red supergiant. C)a red main-sequence star.
Answer:
C. red main-sequence star
Explanation:
Which of these stars has the hottest core?A)a blue main-sequence star. B)a red supergiant. C)a red main-sequence star.
Stars are basically exploding gases usually hydrogen and helium gases, held together by gravity. The closest to us is the sun. which contains gases
a blue main-sequence star temperature is between 10,000 Kelvin to 40000kelvin
red main-sequence star. can about 10million kelvin
while
B)a red supergiant is 3500-4500 K
Blue stars are generally the hottest, so a blue main-sequence star likely has the hottest core. The star's color provides insight into its core temperature.
Explanation:The temperature of a star is typically indicated by its color, which can be used to infer information about its core. In general, blue stars are the hottest and red stars are the coolest. Therefore, of the options given, a blue main-sequence star likely has the hottest core. It's interesting to note that a star's core temperature can alter its life cycle stages, hence why we classify stars into different categories like main-sequence, supergiant and so on.
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Three point charges lie in a straight line along the y-axis. a charge of q1 = -9.10 µc is at y = 6.30 m, and a charge of q2 = -7.90 µc is at y = -4.50 m. the net electric force on the third point charge is zero. where is this charge located?
Answer:
Electric field E = kQ/r^2
Distance between charges = 6.30 - (-4.40) = 10.70m
Say the neutral point, P, is a distance d from q1. This means it is a distance (10.70 - d) from q2.
Field from q1 at P = k(-9.50x^10^-6) / d^2
Field from q2 at P = k(-8.40x^10^-6) / (10.70-d)^2
These fields are in opposite directions and are equal magnitudes if the resultant field = 0
k(-9.50x^10^-6) / d^2 = k(-8.40x^10^-6) / (10.70-d)^2
9.50 / d^2 =8.40 / (10.70-d)^2
d^2 / (10.70-d)^2 = 9.50/8.40 = 1.131
d/(10.70-d) = sqrt(1.1331) = 1.063
d = 1.063 ((10.70-d)
= 10.63 - 1.063d
2.063d = 10.63
d = 5.15m
The y coordinate where field is zero is 6.30 - 5.15 = 1.15m
Explanation:
A plane is flying east at 135 m/s. The wind accelerates it at 2.18 m/s2 directly northeast. After 18.0 s, what is the direction of the displacement of the plane?
the plane was flying at 2,691. 33 m at 5.32°
Many household cleaners, particularly toilet cleaners and some drain cleaners have acid in them. This is the equation representing hydrochloric acid plus bleach. NaClO + 2 HCl →Cl2 + H2O + NaCl If you mix bleach with acidic cleanser, a very noxious gas that can cause respiratory problems will be released. Your sense of smell can detect this gas in air at concentrations as low as 0.08 parts per million and at that level, it is basically an irritant. Levels as low as 15 parts per million can cause severe throat irritation while levels of 50 parts per million or above are very dangerous. What is this gas?
Answer:
chlorine gas
Explanation:
Answer:
The gas is chlorine gas.
Explanation:
[tex]NaClO + 2 HCl \rightarrow Cl_2 + H_2O + NaCl[/tex]
Chlorine gas is a toxic gas and very reactive inside the human body. Also an irritant to eyes and skin. Exposure to high concentration leads to lung damage or death.
Where as the byproduct formed are water and sodium chloride which an aqueous solution of sodium chloride harmless to humans.
Please help on this one?
I believe A. I'm so sorry if it's wrong! but it's the most best answer to me since it makes sense to me.
The law of repulsion by Coulomb agrees with: Newton's law of universal gravitation Newton's laws of motion the findings of Gilbert the direct-square law
Explanation:
The law of repulsion is given by Coulomb. The mathematical form of Coulomb law is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]...............(1)
Where
F is the force
k is the electrostatic constant
[tex]q_1\ and\ q_2[/tex] are electric charges
r is the distance between charges
The Newton's law of universal gravitation is given by :
[tex]F=\dfrac{Gm_1m_2}{r^2}[/tex]..............(2)
G is the universal gravitational constant
From equation (1) and (2) it is clear that both law obeys inverse square law and both are of same type. So, the law of repulsion by Coulomb agrees with the Newton's law of universal gravitation.
The Law of Coulomb agrees with the inverse-square law and Newton's law of universal gravitation. It doesn't directly correspond with Newton's laws of motion or the findings of Gilbert on magnetism.
Explanation:The Law of Coulomb is closely related to and agrees with the inverse-square law, which states that a specified physical quantity or intensity is inversely proportional to the square of the distance from the source of that physical property. This rule is also employed in Newton's law of universal gravitation.
However, the Law of Coulomb does not directly correspond or agree with Newton's laws of motion or the findings of Gilbert. Newton's laws of motion govern the relationship between the motion of an object and the forces acting upon it, while Gilbert's findings primarily concern magnetism.
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A beam of red light and a beam of blue light have exactly the same energy. Which beam contains the greater number of photons?
The higher the frequency, the more energy the photon has. Of course, a beam of light has many photons. This means that really intense red light (lots of photons, with slightly lower energy)
The nuclear particle consisting of one down quark and two up quarks has what kind of charge?
Answer:
+e
Explanation:
The charge of an up quark is:
[tex]q_u = +\frac{2}{3}e[/tex]
The charge of a down quark, instead, is:
[tex]q_d = -\frac{1}{3}e[/tex]
In this problem, we have a particle consisting of 1 down quark and 2 up quarks, Therefore, the net charge of the particle will be
[tex]q=1(q_d)+2(q_u)=1(-\frac{1}{3}e)+2(\frac{2}{3}e)=-\frac{1}{3}e+\frac{4}{3}e=\frac{3}{3}e=+e[/tex]
So, the particle has a charge of +e.
According to recent Kepler mission results, how common are planets around other stars?
After 9 years of spectacular findings, NASA shut down the Kepler space telescope at the end of last October (2018).
From 2009 to 2018, the Kepler mission found more than 2,600 planets in other "solar systems" ... in orbit around other stars besides our Sun. AND, at the time the mission ended, (5 months before the night I'm writing this), there were still more than 2,000 sets of data still to be analyzed.
The results suggest that having a family of planets is really not an unusual thing for a star. Indeed, the rare, unusual stars may be the few that don't have planets orbiting them.
Planets around other stars are probably so common that they are the rule, and not the exception to the rule.
Study the image below. What interaction causes the water to spread as they pass through the rock opening?
absorption
diffraction
reflection
refraction
diffraction ;-)
When water passes through small hole this type of phenomena happens.
diffraction interaction causes the water to spread as they pass through the rock opening. Hence option B is correct.
What is diffraction ?Diffraction is the interference or bending of waves via an aperture into the area that is geometrically in the shadow of the aperture or obstruction. Effectively, the wave's secondary source is the diffracting element or aperture. The term "diffraction" was created by Italian scientist Francesco Maria Grimaldi, who also made the first precise measurements of the phenomena in 1660.
On the registration plate, an infinite number of spots (three are illustrated) along length d project phase contributions from the wavefront, resulting in a continually changing intensity theta.
The Huygens-Fresnel principle, which views each point in a propagating wavefront as a collection of unique spherical wavelets, describes the diffraction phenomena in classical physics. When a wave from a certain direction, the distinctive bending pattern is most obvious.
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What medium do seismic waves travel through?
Answer:
They travel along the surface of the Earth and through the earth.
When the temperature of 2.35 m^3 of a liquid is increased by 48.5 degrees Celsius, it expands by 0.0920 m^3. What is its coefficient of volume expansion? (The answer is ________ •10^-4 C^-1. Just fill in the blank.)
Answer:
[tex]8.1\cdot 10^{-4} C^{-1}[/tex]
Explanation:
The volumetric expansion of the liquid is given by
[tex]\Delta V=\alpha V_0 \Delta T[/tex]
where
[tex]\alpha[/tex] is the coefficient of volume expansion
[tex]V_0[/tex] is the initial volume
[tex]\Delta T[/tex] is the change in temperature
For the liquid in this problem,
[tex]V_0 = 2.35 m^3\\\Delta T=48.5^{\circ}C\\\Delta V=0.0920 m^3[/tex]
So we can solve the equation to find [tex]\alpha[/tex]:
[tex]\alpha=\frac{\Delta V}{V_0 \Delta T}=\frac{(0.0920 m^3)}{(2.35 m^3)(48.5^{\circ}C)}=8.1\cdot 10^{-4} C^{-1}[/tex]
Why is alternating current more effective at long–distance travel than direct current?
The power lines are made out of conductors.
Transformers increase or decrease voltage as needed.
The AC generator is more efficient.
AC has lower voltage than DC.
If you are using PLATO, which I'm sure you are cause I've had the same question, the answer it the following:
Transformers increase and decrease voltage as needed.
The alternating current more effective at long–distance travel than direct current because transformers increase and decrease voltage as needed.
What is alternating current?Alternating current is an electric current which periodically reverses direction and changes its magnitude continuously with time.
The voltage difference developed through transmission lines is very high,. This reduces the current and minimizes the energy lost through transmission. So, alternating current is chosen over direct current for transmitting electricity. It is much cheaper to change the voltage of an alternating current.
Thus, the alternating current more effective at long–distance travel than direct current because transformers increase and decrease voltage as needed
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