How do i solve
3(x+3)=18

Answers

Answer 1
Solve for x.
3(x+3)=18
Distribute the brackets.
3*x=3x
3*3=9
3x+9=18
Subtract 9 from both sides.
(3x+9)-9=(18)-9
3x=9
Divide both sides by 3.
(3x)/3=(9)/3
x=3

Hope this helps.
-Benjamin
Answer 2
Distribution
3 times X is 3x and 3 times 3 is 9
So
3x+9 =18
-9 -9
0. 9
3x=9

9/3 is 3
X=3

Related Questions


Latoya drove 585 miles in 9 hours.
At the same rate, how many miles would she drive in 5 hours?

Answers

585/9 = 65 miles per hour

65 x 5 = 325 miles

 she would drive 325 miles in 5 hours

Proportion
[tex]\frac{x}{5}=\frac{585}{9}\\\\ \frac{x}{5}=\frac{65}{1}\\\\ 1\times x=5\times 65\\\\ x=325[/tex] miles in 5 hours

What is the value of the number 7 in 43,782

Answers

The value number with be 700, tip if you need to find the value number I'll show a number example

572,962

What if the value number in 7?
Replace all the numbers behind the 7 into 0's
70,000

Hope that helps!

Jeremy created a small garden that measured 5 times 7.5 feet how many 10 feet rolls of fencing will he need to completely surround the garden?

Answers

Jeremy will need 3.75 rolls of fence to completely surround the garden but if you are rounding he will need 4.
3.75 but 4 if rounding

The difference between the square roots of a number is 30. What is the number?

Answers

If x is the number,

[tex] \sqrt{x} -(- \sqrt{x} )=30[/tex]

(The difference or distance between two numbers is the larger one minus the smaller one.)

[tex]2 \sqrt{x} =30 \\ \sqrt{x} =15 \\ (\sqrt(x))^2=15^2 \\ x=225[/tex]

Which of the following sets of numbers could be the side lengths of a right triangle?

3, 4, and 7
9, 40, and 42
8, 15, and 16
20, 21, and 29

Answers

I would say the answer is B 9, 40, and 42

the answer is  20,21,29 because  

20 times 20 is 400

21 times 21 is 441

and 29 times 29 is 841

the formula to ge tthe answer is a^2 + b^2 = c^2

20^2 + 21^2= 29^2

then plug the rest in

400+441= 841

100 kg of a fruit contained 90% water one week ago. How many kg of the fruit containing 80% water are there now?

Answers

90kg 

It is just a simple proportional problem. If you subtract 10%, then you subtrat 10 kg. 

Final answer:

The weight of the solids in the fruit remains constant at 10 kg. When the water content changes to 80%, the total weight of the fruit is 50 kg, since the solids make up 20% of the fruit's weight.

Explanation:

Initially, we have 100 kg of fruit with 90% water content. This means that there are 90 kg of water and 10 kg of solids (since water plus solids equals the total weight of the fruit).

After some time, the fruit dehydrates to where it now contains 80% water. However, the amount of solids in the fruit has not changed; it remains constant at 10 kg. To find the new total weight of the fruit with 80% water, we can set up the equation where 80% of the new weight is equal to the weight of the solids subtracted from the new total weight (since solids comprise the remaining 20% of the weight).

Let's denote the new total weight of the fruit as 'x'. According to the given information, 20% of x is the weight of the solids, which is 10 kg. Therefore, the equation is:

0.20x = 10 kg

Now we solve for 'x':

x = 10 kg / 0.20 x = 50 kg

The result is that there are 50 kg of the fruit with 80% water content now.

the three digit number 49x is divisible by 4 with no remainders. if the sum of the digits is divisible by 5 with no remainders, what is the number

Answers

(49x) / 4 , (4 + 9 + x) / 5

492 / 4 = 123
(4 + 9 + 2) / 5 = 15/5 = 3

ur number is 492

Find the missing number

Answers

To find a divisor, divide the dividend by the quotient.

9.03/2.1= 4.3

Final answer: 4.3

Find the Area.

Triangle: A= 1/2 bh.

Answers

area = 1/2 b*h

1/2 *10 *015 =

1/2 * 150 =75

 area = 75 square feet

A = 1/2bh = 1/2 (15)(10) = 150/2 = 75

answer
75 ft^2

A mother bottlenose ate about 278 pounds of food in one week. About how much food did she eat in a day?

Answers

About 40 pounds is the answe
The dolphin ate exactly 39.7142857143 so if you round to the ones it's 40, to the tenths 39.7, to the hundredths 39.71, to the thousandth 39.714 and so on

In a circle an arc 60 centimeters lon subtends an angle of 5 radians. What is the radius of the circle?

Answers

arc length = rθ    [r = radius of the circle, θ = central angle in radians]  ⇒

r = arc length/θ = 60/5 = 12 cm

From their location in the diagram, what are two possible values for m and n?

Answers

m=6/5 and n = sqrt(2), is rational (but not an integer) and n is irrational.

The case with n = sqrt(9)=3, is not a solution. The case with m=4pi neither.

The last case is m = 6/2=3, integer, so neither works.

So, it is the one with m=6/5 and sqrt(2)

Answer:

m= 6/5, n= √2

Step-by-step explanation:

This is just a simple version of the answer.

Miss Nelson works 154 hours each month he works eight months each year how many hours does Miss
Nelson work each year

Answers

154 hours x 8 months = 1232 hours over 8 months
154 times 8 equals 1232

What does 5 2/3 - 8 5/6 equal?

Answers

5 2/3 = 17/3 = 34/6

8 5/6 = 53/6

34/6 - 53/6 = -19/6 = -3 1/6


If x = y − 2, simplify the expression x + 6. A. x + 4 B. x − 8 C. y + 4 D. y − 8

Answers

Since x=y-2, we can plug that into x+4 to get (y-2)+6=y+4

This graph looks like a trigonometric function. Which trigonometric function would be best to use for this model: cosine, sine, or tangent? Why?

Type your response here:


a. It’s time to start making your model fit the path of the mass. Start with amplitude. What is the amplitude of the weight’s motion? How can you modify the base trigonometric function you identified in part b to fit this amplitude? Do this now.

Type your response here:


b. What is the period of the weight’s motion? How can you modify the trigonometric function you identified in part c to fit this period? Do this now.

Type your response here:



c. Check how your model looks compared with the mass by graphing your model with the Edmentum Graphing Tool. Looking at the graph, what is different between your model and the graph of the mass? What needs to change to make your model more accurate? Make this change to your model, and type in the new equation for your model.

Type your response here:

Answers

[tex]\displaystyle \boxed{y = \frac{6}{25}cos\:(1\frac{1}{2}\pi{x} - \frac{\pi}{2})} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{1}{3}} \hookrightarrow \frac{\frac{\pi}{2}}{1\frac{1}{2}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{3}} \hookrightarrow \frac{2}{1\frac{1}{2}\pi}\pi \\ Amplitude \hookrightarrow \frac{6}{25}[/tex]

OR

[tex]\displaystyle \boxed{y = \frac{6}{25}sin\:1\frac{1}{2}\pi{x}} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{3}} \hookrightarrow \frac{2}{1\frac{1}{2}\pi}\pi \\ Amplitude \hookrightarrow \frac{6}{25}[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the sine graph, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = \frac{6}{25}cos\:1\frac{1}{2}\pi{x},[/tex] in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph on the right] is approximately shifted [tex]\displaystyle \frac{1}{3}\:unit[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{1}{3}\:unit,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{1}{3}} = \frac{\frac{\pi}{2}}{1\frac{1}{2}\pi}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = \frac{6}{25}cos\:(1\frac{1}{2}\pi{x} - \frac{\pi}{2}).[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-2\frac{2}{3}, 0],[/tex]from there to [tex]\displaystyle [-1\frac{1}{3}, 0],[/tex]they are obviously [tex]\displaystyle 1\frac{1}{3}\:unit[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 1\frac{1}{3}.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 0,[/tex]in which each crest is extended six-twenty-fifths unit beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

**Now, it really does not matter which function you use because the result will always be the same, but IF the system only wants one function as an answer, then it would be the sine function sinse it intersects the origin. Other than that, it does not matter which one is chosen.

I am delighted to assist you at any time.

5 less than three times a number is 10

Answers

5•2=10
2 is less then 3

3x-5 =10

 add 5 to both sides

3x=15

 divide both sides by 3

x=5


check:

3(5)-5 = 15-5 = 10

which expression gives the distance between the points (4,6)and (7,-3)

Answers

The distance between any two points is:

d^2=(x2-x1)^2+(y2-y1)^2 so in this case:

d^2=(7-4)^2+(-3-6)^2

d^2=3^2+9^2

d^2=90

d=√90

d=3√10 units 

d≈9.49 units (to nearest hundredth of a unit)

Answer:

As shown in the image....

Step-by-step explanation:

This equation follows with the distance formula which is (x2-x1)+(y2-y1) squared.

what is 24 2/3 divided by 1 3/4

Answers

296/21 is the answer hope this helps 

Answer:

Step-by-step explanation:

First, you should convert the mixed fractions into an improper fraction.

74/3 divided by 7/4

As you should know, any fraction divided by another is that fraction times the reciprocal of the other fraction.

74/3*4/7

There fore leaving 296/21 as the answer.

When measuring board footage for some exotic woods, a carpenter must use 1.25 inches for thickness rather than 1 inch in her calculations. Write 1.25 in expanded form.

Answers

1+0.20+0.05

Hope this helps!

Answer: [tex]1.25=1+0.2+0.005[/tex]

Step-by-step explanation:

Given : When measuring board footage for some exotic woods, a carpenter must use 1.25 inches for thickness rather than 1 inch in her calculations.

To write : 1.25 in expanded form.

When we write a decimal number in expanded form, we are showing the place value of each digit.

Now, 1.25 can be written as :

[tex]1.25=1+0.2+0.005[/tex]

Hence, the expanded form of [tex]1.25=1+0.2+0.005[/tex]

Which expression shows the simplified form of (8r^-5) -3 ?

Answers

[tex](8r^{-5})^{-3}=8^{-3}r^{-5(-3)}= \cfrac{r^{15}}{8^3}= \cfrac{r^{15}}{512}[/tex]

Answer:

[tex]\frac{r^{15}}{512}[/tex]

Step-by-step explanation:

(8r^-5)^ -3

[tex](8r^{-5})^{-3)[/tex]

Apply exponential property

(ab^m) ^n = a^m b^mn

Multiply the outside exponent with the exponents insde

[tex](8r^{-5})^{-3)= 8^{-3}r^{-5*-3}=8^{-3}r^{15}[/tex]

Appy property a^-m = 1/a^m to make the exponent positive

[tex]8^{-3}r^{15}= \frac{r^{15}}{8^3} =\frac{r^{15}}{512}[/tex]

find the approximate length of the leg of a right triangle with one leg length 8 and hypotenuse length 19

Answers

So, teh exact value is sqrt( 19^2 - 8^2 ) = sqrt( 361-64) = sqrt(297).

There's people who can calculate this mentally, but I can't. Approximate by known squares: 15^2 = 225, 16^2 = 256, 17^2= 289, 18^2=324,

So, 18.

The approximate length of the leg of a right triangle is 17.

Use the concept of a triangle defined as:

A triangle is a three-sided polygon, which has three vertices and three angles which has a sum of 180 degrees.

And the Pythagoras theorem for a right-angled triangle:

(Hypotenuse)²= (Perpendicular)² + (Base)²

Given that,

One leg = 8 say it is the base of a triangle.

Hypotenuse = 19

Applying the Pythagorean theorem,

(19)²= (Perpendicular)² + (8)²

(Perpendicular)² = 297

Taking square root on both sides,

Perpendicular ≈ 17.2

Hence,

The required length of leg is approximately 17.

To learn more about triangles visit;

brainly.com/question/1058720

#SPJ5

Akshat spent 3 hours each day driving to and form work. He opened an office closer to home and now drives 80 minutes to and form work. What is the percent of decrease in his commute time?

Answers

3*60 = 180 minutes

80/180 = 0.44

1-0.44 = 0.56

 it was a 56% decrease in commute time

Which expression is equivalent to 100 n2 − 1? (10n)2 − (1)2 (10n2)2 − (1)2 (50n)2 − (1)2 (50n2)2 − (1)2

Answers

[tex]100n^2-1=10^2n^2-1=(10n)^2-1^2[/tex]

The correct answer is:

(10n)² − (1)²

Explanation:

If we evaluate this expression, we square everything in the first set of parentheses; this means we have 10²n² - 1², or 100n² - 1.

This is the expression we were trying to equal.

45/100 in simplest form

Answers

Hello there! How are you today?

First, let's take a look at our numbers.

45 / 100

Both of these numbers have a 0 and a 5, which means it is divisible by 5.
Let's divide both of them by 5.

45 / 5 = 9
100 / 5 = 20

We are now left with 9/20.

This is your simplified fraction since 9 and 20 do not have any common factors.

I hope this helps!

If the directrix of a parabola is the horizontal line y = 3, what is true of the parabola?
a)The focus is at (0, 3), and the equation for the parabola is y2 = 12x.
b)The focus is at (0, –3), and the equation for the parabola is x2 = –12y.
c)The focus is at (3, 0), and the equation for the parabola is x2 = 12y.
d)The focus is at (–3, 0), and the equation for the parabola is y2 = –12x.

Answers

The correct answer is b), or x² = -12y.

Explanation:
This equation may be written in standard form as
[tex]y=- \frac{1}{12} x^{2} [/tex]
The coefficient in front of x² is negative so the curve is downward.
The vertex has coordinates (0,0).
The vertex is equidistant from the directrix and the focus, so the focus is (0, -3).

Answer: on e2020 it’s b

Step-by-step explanation:

Dave is helping his grandmother make trail mix. His grandmother asks him to add cup of fruit for every cup of nuts.
To satisfy his grandmother’s request, Dave must mix cups of fruit for a single cup of nuts.

Answers

Dave is helping his grandmother make trail mix. His grandmother asks him to add cup of fruit for every cup of nuts.To satisfy his grandmother’s request, Dave must mix 3/5 4/5 1 1/5 1 2/3 cups of fruit for a single cup of nuts.

To satisfy his grandmother's request, Dave needs to mix [tex]\( \frac{1}{5} \)[/tex] cup of fruit for every [tex]\( \frac{1}{3} \)[/tex] cup of nuts.

To find out how many cups of fruit Dave needs to mix for a single cup of nuts, we need to find a common denominator for [tex]\( \frac{1}{5} \)[/tex]  and [tex]\( \frac{1}{3} \)[/tex], which is 15.

[tex]\[ \frac{1}{5} \times \frac{3}{3} = \frac{3}{15} \][/tex]

[tex]\[ \frac{1}{3} \times \frac{5}{5} = \frac{5}{15} \][/tex]

So, Dave needs to mix [tex]\( \frac{3}{15} \)[/tex] cup of fruit for every [tex]\( \frac{5}{15} \)[/tex] cup of nuts.

Therefore, to satisfy his grandmother's request, Dave must mix [tex]\( \frac{3}{15} \)[/tex] cup of fruit for a single cup of nuts.

The complete Question is given below:

dave is helping his grandmother make trail mix his grandmother asks him to add 1/5 cup of fruit for every 1/3 cup of nuts. To satisfy his grandmother's request, drave must mix ___ cups of fruit for a single cup of nuts

how to write 3x2+3y2+12x+18y-15 in general and standard format

Answers

see picture. The equation is already written in standard form.

Estimate the circumference of the circle to the nearest hundredth. Use 3.14 the diameter is 11

Answers

Recall the circumference formula:  
[tex]c= \pi D[/tex]  
Now, plug in pi as 3.14 and D as 11:  
[tex]3.14 * 11 = 34.54[/tex]  
Your answer is 34.54.
Final answer:

The circumference of a circle with a diameter of 11 using 3.14 for pi is estimated to be 34.54 to the nearest hundredth.

Explanation:

To estimate the circumference of a circle to the nearest hundredth, we use the formula C = πd, where C is the circumference and d is the diameter of the circle. Given that the diameter is 11 and we should use 3.14 for π, the calculation is C = 3.14 × 11. Performing the multiplication gives us a result of 34.54, which is the estimated circumference of the circle to the nearest hundredth.

Mrs. Chin paid a 20 percent tip on the bill for lunch. If the tip amount was $2.75, what was the bill for lunch before the tip was added to it?

Answers

2.75 x 100 / .20 = 13.75

double check

$13.75 x 0.25 = $2.75

so answer
The bill was $13.75 for lunch before the tip added
20/100 × x = $2.75
cross multiply,
20 × x = 2.75 × 100
20x = 275
x = 275/20
x = $13.75

lunch bill = $13.75
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