How do you write 11/ 4 as a percentage?

Answers

Answer 1
The answer is %225 First, we must convert the given fraction into a decimal number. So use a calculator or long division to convert the given fraction to a decimal number. In this case, 


Now just multiply the equivalent decimal by 100 to convert it into a percent. So . Take note that we're simply moving the decimal point two spots to the right.


So the given fraction  is equivalent to 275%

Related Questions

(01.02) given that f(x) = 2x + 5 and g(x) = x − 7, solve for f(g(x)) when x = −3. (1 point) −15 −8 10 25

Answers

hello : 
 f(x) = 2x + 5 and g(x) = x − 7
f(g(-3))=f (-3-7) =f(-10) = 2(-10)+5 = -20+5 = -15

If cot= 2/3 what is the value of Csc

Answers

So cot= inverse tan
Tan= opposite over adjacent. So 3/2
This means the hypotenuse is square root of 13
Csc is inverse sin
Sin = opposite \ Hypotenuse
Sin = 3/Square root of 13
Csc = square root of 13/ 3

Mrs marks has 3/4 pound of cheese to use making sandwiches she uses about 1/32 pound of cheese on each sandwich how many sandwiches can she make with the cheese she has?

Answers

3/4 = 24/32 and if each sandwich uses 1/32 cheese then she can make 24 sandwiches
(3/4) / (1/32) ...when dividing fractions, flip what u r dividing by, then multiply
3/4 * 32/1 = 24....so she can make 24 sandwiches

Plane A leaves Tulsa at 2:00 p.m., averaging 300 mph and flying in a northerly direction. Plane B leaves Tulsa at 2:30 p.m., averaging 225 mph and flying due east. At 5:00 p.m., how far apart will the planes be?

Answers

Answer 1061

Step-by-step explanation:

Answer:

At 5:00 p.m. the planes will be [tex]1061.323[/tex] miles apart.

Step-by-step explanation:

To solve this problem, I add a picture of the situation.

We know that speed is distance over time  ⇒

[tex]Speed=\frac{distance}{time}[/tex] (I)

The first step to solve this exercise is to graph the situation. We can draw a right triangle which vertices will be ''Tulsa'', and the planes ''A'' and ''B'' at 5:00 p.m.

In order to know the measures of the sides, we are going to calculate them using the equation (I)

Plane A leaves Tulsa at 2:00 p.m.

Therefore, at 5:00 p.m. it will have flown 3 hours ⇒

[tex]300\frac{mi}{h}=\frac{distance}{3h}[/tex] ⇒

[tex]distance=(300\frac{mi}{h}).(3h)[/tex]

[tex]distance=900mi[/tex]

At 5:00 p.m. the distance from the plane A to Tulsa is 900 mi

Plane B leaves Tulsa at 2:30 p.m.

Therefore, at 5:00 p.m. it will have flown 2.5 hours ⇒

[tex]225\frac{mi}{h}=\frac{distance}{2.5h}[/tex]

[tex]distance=(225\frac{mi}{h}).(2.5h)[/tex]

[tex]distance=562.5mi[/tex]

At 5:00 p.m. the distance from the plane B to Tulsa is 562.5 mi

Finally, we can find the distance between the plane A and the plane B using the Pythagorean theorem :

[tex](900mi)^{2}+(562.5mi)^{2}=(Distance_{A-B})^{2}[/tex]

[tex]810000mi^{2}+316406.25mi^{2}=(Distance_{A-B})^{2}[/tex]

[tex](Distance_{A-B})^{2}=1126406.25mi^{2}[/tex]

[tex]Distance_{A-B}=\sqrt{1126406.25mi^{2}}[/tex]

[tex]Distance_{A-B}=1061.322877mi[/tex] ≅ [tex]1061.323mi[/tex]

At 5:00 p.m. the planes will be 1061.323 miles apart.

NEED HELP ASAP!!!!!!!

Solve the equation.

e² = 0.36

Enter your answer in the box.

e = ±

Answers

square root of 36 = +/-6   so  square root of 0.36 is +/0.6

Answer:

0.6

Step-by-step explanation:

took the test

Suppose y varies directly with x. Write a direct variation equation that relates x and y. Then find the value of y when x = 7.

y=15 when x=6

Answers

[tex]\bf \qquad \qquad \textit{direct proportional variation}\\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array}\\\\ ----------------------------\\\\ \textit{we also know that } \begin{cases} y=15\\ x=6 \end{cases}\implies 15=k6\implies \cfrac{15}{6}=k \\\\\\ therefore\qquad \boxed{y=\cfrac{15}{6}x}\\\\ ----------------------------\\\\ \textit{what's \underline{y} when x=7?}\qquad y=\cfrac{15}{6}\cdot 7[/tex]
Final answer:

To write a direct variation equation, we use the form y = kx, where k is the constant of variation. We can find the value of k by substituting the given values into the equation. Once we have the value of k, we can write the direct variation equation that relates x and y. Finally, we can find the value of y for a given value of x by substituting it into the equation.

Explanation:

To write a direct variation equation, we use the form y = kx, where k is the constant of variation. We are given that y = 15 when x = 6. To find k, we can substitute these values into the equation:

15 = k * 6

To find the value of k, we divide both sides by 6:

k = 15/6 = 2.5

Now we can write the direct variation equation that relates x and y:

y = 2.5x

To find the value of y when x = 7, we substitute x = 7 into the equation:

y = 2.5 * 7 = 17.5

Learn more about Direct Variation here:

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Complete the steps to the factor the tens. 30x40=( n x 10) x ( n x 10)=( n x n) x (10 x10)= n x 100 = n

Answers

the corrent answer is 20 please mark the brainliest if this helps

Find a point on the y-axis that is equidistant from the points (4, −4) and (1, 1).

Answers

hello : 
a point on the y-axis is : P( 0, y)
PA = PB  or  PA² = PB².... A(4 , -4)    B(1,1)
(4-0)²+(-4-y)² = (1-0)² + (1-y)²
16 +y² +8y +16 = 1 + 1 -2y +y²
10y = -30
y = -3

Evaluate these questions
3a+2a=



c+d there is a line under this one
ad

Answers

Get photo math it would help you out with all of your math problems
Greetings!

1)
For this question we can combine the terms together as they are like:
[tex]3a+2a[/tex]
Combine like terms.
[tex]=5a[/tex]


Hope this helps.
-Benjamin


What is the answer for this problem

Answers

9 + 15 / 5 x 13 =
9 + 3 x 13 =
9 + 39 = 48
15/5=3
3x13=39
39+9=48

Parallelogram JKLM is shown on the coordinate plane below:

If parallelogram JKLM is rotated 270° clockwise around the origin, what are the coordinates of the endpoints of the side congruent to side JM in the image parallelogram?

Answers

Given that rotating 90 degrees clockwise around the origin switches the x andy values and makes the new y value negative, we can, for example, switch (2, 1) to (1, -2). 180 degrees clockwise simply makes both values negative (-2, -1), and 270 degrees clockwise switches them and makes the new y value negative  (-1, 2), we can plug those in to our JM endpoints to turn (-5, 1) into (-1, -5) and (-6, 2) into (-2, -6)

Answer-

The coordinates of the endpoints of the side congruent to side JM will be,

(-2, -6) and (1, -5).

Solution-

When rotating a point 270° clockwise or 90° counter-clockwise around the origin, we apply the rule (x, y) → (-y, x).

The co-ordinates of the original parallelogram are,

J = (-6, 2)

M = (-5, -1)

L = (-3, 3)

K = (-4, 6)

After the rotation, the new co-ordinates will be,

J = (-2, -6)

M = (1, -5)

L = (-3, -3)

K = (-6, 4)

∴ The coordinates of the endpoints of the side congruent to side JM will be,

(-2, -6) and (1, -5).

What is the area of a circle with radius 14 units, to the nearest hundredth?

Answers

Take the radius and find the diameter. Then multiply the diameter by 'pi.'
14×2=28
28×pi=88

what do you add 15/4 to make 4

Answers

the answer would be 1/4 or [tex] \frac{1}{4} [/tex] i hope this answer helps!

A jet travels 500 miles in 2 hours. At this rate, how far could the jet fly in 8 hours? What is the rate of speed of the jet? PLEASEEE HELP

Answers

The jet could fly 2,000 miles in 8 hours and the rate of speed is 250miles per hour.

One month, Ruby worked 8 hours more than Isaac, and Svetlana worked 4 times as many hours as Ruby. Together they worked 112 hours. Find the number of hours each person worked.  

Answers

R=8+I
S=4R

R+I+S=112
R+R-8+4R=112
6R=120
R=20

So therefore, Ruby worked 20 hours, Svetlana worked 80 hours, and Isaac worked 12 hours.

Point M is the midpoint of segment JK. Find JK when JM=6x-7 and MK=2x+3.

Answers

if M is the midpoint of JK then JM+MK=JK and JM=MK
so
6x-7=2x+3
minus 2x both sides
4x-7=3
add 7 both sides
4x=10
divide both sides by 4
[tex]x=\frac{10}{4}[/tex]
[tex]x=\frac{5}{2}[/tex]

sub back

JM=6x-7
[tex]JM=6(\frac{5}{2})-7[/tex]
[tex]JM=\frac{30}{2}-7[/tex]
[tex]JM=15-7[/tex]
JM=8

JM=MK=8
JM+MK=8+8=16=JK

[tex]x=\frac{5}{2}[/tex] and JM=8=MK and JK=16

The value of JK will be 16.

It is given that M is the midpoint of segment JK.

We have to find out the value of JK.

What will be the value of x , if 4x + 12 = 8x + 4 ?

The value of x will be 2.

As M is the midpoint of JK.

JK = MK + JM

So,

MK = JM

2x + 3 = 6x - 7

4x = 10

x =2.5

So ,

MK = 2x + 3 = 8

JM = 6x - 7 = 8

Hence ,

JK = MK + JM = 8 + 8

JK = 16

Thus , value of JK will be 16.

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If a measurement follows a normal (bell-shaped) frequency curve, then percent of the population will have a z-score below .36.

Answers

Refer to the standard table for the normal distribution shown below.

From the normal distribution tables, when z < 0.36, obtain
P(z < 0.36) = 0.6406 ≈ 64 percent

Answer: 64% (nearest integer)

Gretchen and Ezia received equal scores on a test made up of multiple choice questions and an essay. Gretchen got 18 multiple choice questions correct and received 19 points for her essay. Ezia got 15 multiple choice questions correct and received 31 points for her essay.

How many points was each multiple choice question worth?
Enter your answer in the box.

Answers

I think its 91.

NOT Guaranteed this is the Answer. Best of luck to you.
I think its 91. hope this helps


How can I evaluate this question?

Answers

[tex]\bf \left(x^2-\cfrac{2}{\sqrt{x}}+1 \right)(\sqrt[3]{x}+3x-4)\quad \begin{cases} \frac{2}{\sqrt{x}}\implies \frac{2}{x^{\frac{1}{2}}}\implies 2x^{-\frac{1}{2}}\\\\ \sqrt[3]{x}\implies x^{\frac{1}{3}} \end{cases} \\\\\\ (x^2-2x^{-\frac{1}{2}}+1)(x^{\frac{1}{3}}+3x-4)[/tex]

[tex]\bf \\\\\\ \begin{cases} x^2\cdot x^{\frac{1}{3}}+3x^3-4x^2\\\\ -2x^{-\frac{1}{2}}\cdot x^{\frac{1}{3}}-2x^{-\frac{1}{2}}\cdot 3x+2x^{-\frac{1}{2}}\cdot 4\\\\ +x^{\frac{1}{3}}+3x-4 \end{cases} \\\\\\ \begin{cases} x^{2+\frac{1}{3}}+3x^3-4x^2\\\\ -2x^{-\frac{1}{2}+\frac{1}{3}}-6x^{-\frac{1}{2}+1}+8x^{-\frac{1}{2}}\\\\ +x^{\frac{1}{3}}+3x-4 \end{cases}[/tex]

[tex]\bf x^{\frac{7}{3}}+3x^3-4x^2-2x^{-\frac{1}{6}}-6x^{\frac{1}{2}}+8x^{-\frac{1}{2}}+x^{\frac{1}{3}}+3x-4 \\\\\\ \sqrt[3]{x^7}+3x^3-4x^2-\cfrac{2}{x^{\frac{1}{6}}}-6\sqrt{x}+\cfrac{8}{x^{\frac{1}{2}}}+\sqrt[3]{x}+3x-4 \\\\\\ x^2\sqrt[3]{x}+3x^3-4x^2-\cfrac{2}{\sqrt[6]{x}}-6\sqrt{x}+\cfrac{8}{\sqrt{x}}+\sqrt[3]{x}+3x-4[/tex]

what numbers are divisible by 7?
a.75 b.35 c.20 d.30

Answers

35 is the answer
Thanks (;
35 is the only number divisible by 7.

Algebra problem below!


The sum of two consecutive even integers is -50

What are the numbers?

Answers

Thank you for your question!

The formula is:

x + (x + 2) = -50

Solving:

2x + 2 = -50
2x = -52
x = -26

Finding the second number:
-26 + 2 = -24

-24,-26

Hope this helps!

The 1st integer = xthe 2nd integer = x - 2 x + x + 2 = -502x + 2 = -502x = -52  x = -26 The first integer = x = -24The second integer = x - 2 = -24 - 2 = -26  The integers are -24 and -26.

1. Find the perimeter and area of a rectangle with a length of 3.2 m and a width of 1.5 m.
A) p=4.7 m; A=2.25 m^2
B) p=4.7 m; A=4.8^2
C) p=9.4 m; A=2.4 m^2
D) p=9.4 m; A= 4.8^2

2. Find the area of a triangle with a base of 27 feet and a height of 14 feet.
A) 41 ft^2
B) 82 ft^2
C) 189 ft^2
D) 378 ft^2

Answers

1. D) p=9.4 m; A= 4.8 m^2 2. C) 189 ft^2 1. Find the perimeter and area of a rectangle with a length of 3.2 m and a width of 1.5 m. The perimeter of a rectangle is simply twice the sum of it's length and width, so 2(3.2m + 1.5 m) = 2*4.7 = 9.4 m The area of a rectangle is the product of its length and width, so 3.2 m * 1.5 m = 4.8 m^2 Of the available choices, D matches with p=9.4 m; A= 4.8 m^2 2. Find the area of a triangle with a base of 27 feet and a height of 14 feet. The area of a triangle is 1/2 base times height, so 0.5 * 27 ft * 14 ft = 189 ft^2 Of the available choices, C matches with 189 ft^2

The distributive property is used to help simplify math experssions. True False

Answers

true is the answer
hope it helped

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

TRUE

This is because when you distribute 1 thing between 2 (or more) things, it (in a way) simplifies the problem...


For Example:

solve for x

f(x) = 5*(x - 4)


The only way to solve a question like this would be to distribute the 5 to the x and to the 4...

So...

The answer is: TRUE

Staci has seven more cats then Taylor. Write an expression that illustrates how many cats Staci has. Use x to represent the number of cats Taylor has./4899345/032a37eb?utm_source=registration

Answers

x = number of cats Taylor has

Staci has seven more than this so:
x + 7 = number of cats Staci has

Which trigonometric ratios are correct for triangle ABC? Check all that apply

Answers

Consider an angle M with measure m≠90°, in a right triangle.

Let

OPP denote the length of the side opposite to M,
ADJ denote the length of the side adjacent to M, and 
HYP denote the hypotenuse.

then: 

Sin(M) = OPP/HYP
Cos(M)= ADJ/HYPP
Tan(M)=OPP/ADJ


Back to our problem, 

using the Pythagorean we can find the length of AB: 

[tex]|AB|^2+|AC|^2=|BC|^2\\\\|AB|^2+9^2=18^2\\\\|AB|^2=18^2-9^2\\\\|AB|^2=(18-9)(18+9)=9 \cdot 27=9 \cdot 9 \cdot3\\\\|AB|=9 \sqrt{3} [/tex]

[tex]Sin(C)= \frac{OPP}{HYP}=\frac{9 \sqrt{3} }{18}= \frac{ \sqrt{3} }{2}[/tex]
[tex]Cos(B)= \frac{ADJ}{HYP}= \frac{9 \sqrt{3}}{18}= \frac{ \sqrt{3}}{2} [/tex]
[tex]Tan(C)= \frac{OPP}{ADJ}= \frac{9 \sqrt{3} }{9}= \sqrt{3} [/tex]
[tex]Sin(B)= \frac{OPP}{HYP}= \frac{9}{18}= \frac{1}{2} [/tex]
[tex]Tan(B)= \frac{OPP}{ADJ}= \frac{9}{9 \sqrt{3}}= \frac{1}{ \sqrt{3} }= \frac{ \sqrt{3}}{3} [/tex]


Answer: 1, 3, 4



Determine the solution of the system. Show your work.
Y = 5x – 9
Y = 2x + 6

Answers

Both define y, so they are equivalent.

5x-9=2x+6
3x-9=6
3x=15
x=5

Then plug in x into any of the equations
y=2(5)+6
y=10+6
y=16

Final answer: (5,16)

The solution is (x, y) = (5, 16). My "work" is to make use of a graphing calculator.



_____

You can subtract the second equation from the first. This gives

... 0 = 3x -15

Then, divide by 3 and add 5.

... 0 = x - 5

... 5 = x


Substitute this value into either equation to find y.

... y = 2x +6

... y = 2·5 +6

... y = 16


The strategy to subtract the second equation from the first is based on the observation that both equations give expressions for y, and the x-coefficient in the first equation is the larger of the two x-coefficients. Thus, the subtraction we chose will eliminate y and give an x-term with a positive coefficient.

$250 is discounted into $212.50 what is the percent decrease

Answers

450 all together I think
15%
250 - 15% = 212.50

40% of a 12,000 acre forest is being logged how many acres will be logged

Answers

12000 x 0.40 = 4800

12000 - 4800 = 7200

7200 acres are being logged

hope this helps
40% = 0.40

0.40 (12,000) = 4,800

answer

4,800 acre is 40% of a 12,000 acre

Suppose that (y) varies with (x). Write an equation for the inverse variation.

y=4 when x=7

A: y= x/28

B: y=3x

C: x= y/3

D: y= 28/x

Answers

y = k/x, where k is the constant
if x = 7 and y = 4
 4=k/7


k = 4*7 = 28
 

y = 28/x

 answer is D

Can u solve 6x-21=5x+17+x

Answers

6x - 21 = 5x + 17 + x

6x - 21 = 6x + 17
6x - 6x = 21 + 17

0 = 38, untrue

cannot be solved

hope this helps
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